Place the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of change on the interval (0,3)

Answer:

g(x), f(x) and h(x)

Step-by-step explanation:

Given

Interval: (0,3)

See attachment for functions f(x), g(x) and h(x)

Required

Order from fastest to slowest decreasing average rate of change

The average rate of change is calculated as:

[tex]Rate = \frac{f(b) - f(a)}{b - a}[/tex]

In this case:

[tex](a,b) = (0,3)[/tex]

i.e.

[tex]a = 0\\b=3[/tex]

For f(x)

[tex]f(x) = 16(\frac{1}{2})^x[/tex]

[tex]Rate = \frac{f(b) - f(a)}{b - a}[/tex]

[tex]Rate = \frac{f(3) - f(0)}{3 - 0}[/tex]

[tex]Rate = \frac{f(3) - f(0)}{3}[/tex]

Calculate f(3) and f(0)

[tex]f(x) = 16(\frac{1}{2})^x[/tex]

[tex]f(3) = 16(\frac{1}{2})^3 = 16 * \frac{1}{8} = 2[/tex]

[tex]f(0) = 16(\frac{1}{2})^0 = 16 * 1 = 16[/tex]

So:

[tex]Rate = \frac{f(3) - f(0)}{3}[/tex]

[tex]Rate = \frac{2 - 16}{3}[/tex]

[tex]Rate = -\frac{14}{3}[/tex]

For g(x)

[tex]Rate = \frac{g(b) - g(a)}{b - a}[/tex]

[tex]Rate = \frac{g(3) - g(0)}{3 - 0}[/tex]

[tex]Rate = \frac{g(3) - g(0)}{3}[/tex]

From the table of g(x)

[tex]g(3) = 1[/tex]

[tex]g(1) = 27[/tex]

So:

[tex]Rate = \frac{1 - 27}{3}[/tex]

[tex]Rate = -\frac{26}{3}[/tex]

For h(x)

[tex]Rate = \frac{h(b) - h(a)}{b - a}[/tex]

[tex]Rate = \frac{h(3) - h(0)}{3 - 0}[/tex]

[tex]Rate = \frac{h(3) - h(0)}{3}[/tex]

From the graph of h(x)

[tex]h(3) = -3[/tex]

[tex]h(0) = 4[/tex]

So:

[tex]Rate = \frac{-3 - 4}{3}[/tex]

[tex]Rate = -\frac{7}{3}[/tex]

So, the calculated rates of change are:

[tex]f(x) = -\frac{14}{3}[/tex] [tex]= -4.67[/tex]

[tex]g(x) = -\frac{26}{3}[/tex] [tex]=-8.67[/tex]

[tex]h(x) = -\frac{7}{3}[/tex] [tex]=-2.33[/tex]

By comparison:

From the fastest decreasing to slowest, the order is: g(x), f(x) and h(x)

Answer: IN THIS ORDER!!   g(x), f(x), h(x).

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