Jack has a rectangular piece of land, the area of which is represented by a1 = 9.5l. His brother has a different rectangular piece of land, the area of which is represented by a2 = l(14 − l). Let a represent the area in square meters and l represent the length in meters of the pieces of land. The two equations plotted on a graph meet at a point as shown in the image.
The area of the brothers’ pieces of land will be the same when the length is ______ meters.

Answer:

Domain = x ≥ 0

Range = y ≥ 20

Step-by-step explanation:

The equation in slope-intercept form would look like this:

y = 4x + 20

The slope is $4 because that is the money that can be made depending on the week. Because he received a random $20 at the beginning, this is just an additional income.

                     ---------------------------------------------------------------------------

In this scenario, the domain (x-values) represent the number of weeks. The range (y-values) represent the total money made.

So the domain is asking, what is the lowest/highest amount of weeks he can save for? We know the number of weeks cannot be negative because he can't save for negative weeks. However, he could save for zero weeks. He can be saving for theoretically infinite weeks. Therefore, the domain is x ≥ 0.

The range is asking, how much money can he save? Since he starts out with a baseline of $20, this is the lowest amount of money he can have. If he were to save for an infinite amount of weeks, he could make an infinite amount of money. Therefore the range is y ≥ 20.

Answer:

x² - 4 = 0

x² = 4

x =± √4

x = +2 or x = -2.

Answer:

2 and -2 (±2)

Step-by-step explanation:

Step 1: Move -4 to the other side of the equal sign; we get x² = 4.

Step 2: A lot of people miss the negative answer! The square root of 4 is equal to both positive 2 and negative 2.

The vertex of the graph is at (-2, 3).

This means the equation is of the form [tex]f(x)=a|x+2|+3[/tex].

Substituting in the coordinates of one of the other points on the graph that is not the vertex, such as (-1, -1),

[tex]-1=a|-1+2|+3\\\\-1=a+3\\\\a=-4[/tex]

So, the equation is [tex]\boxed{f(x)=-4|x+2|+3}[/tex]

Answer: A. 6, 18, 54, 162

Step-by-step explanation:

Each term is 3 times the last, meaning the common ratio is 3.

Answer:

$4

Step-by-step explanation:

Company $0.50

Store. $ 4.50

Price up $ X

4.50

- 0.50

------------

4.00

X= $4.00

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

[tex]\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}[/tex]

Hence the correct match are -

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It looks like you're talking about the indefinite integral

[tex]\displaystyle \int t^2 e^{-10t} \, dt[/tex]

Integrate by parts:

[tex]\displaystyle u\,dv = uv - \int v\,du[/tex]

Let

[tex]u = t^2 \implies du = 2t \, dt[/tex]

[tex]dv = e^{-10t} \, dt \implies v = -\dfrac1{10} e^{-10t}[/tex]

Then

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \int t e^{-10t} \, dt[/tex]

Integrate by parts again, this time with

[tex]u = t \implies du = dt[/tex]

[tex]dv = e^{-10t} \, dt \implies v = -\dfrac1{10} e^{-10t}[/tex]

Then

[tex]\displaystyle \int t e^{-10t} \, dt = -\frac1{10} t e^{-10t} + \frac1{10} \int e^{-10t} \, dt[/tex]

Putting everything together, we get

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \int t e^{-10t} \, dt[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} + \frac15 \left(-\frac1{10} t e^{-10t} + \frac1{10} \int e^{-10t} \, dt\right)[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} + \frac1{50} \int e^{-10t} \, dt[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} + \frac1{50} \left(-\frac1{10} e^{-10t}\right) + C[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = -\frac1{10} t^2 e^{-10t} - \frac1{50} t e^{-10t} - \frac1{500} e^{-10t} + C[/tex]

[tex]\displaystyle \int t^2 e^{-10t} \, dt = \boxed{-\frac{e^{-10t}}{500} \left(50t^2 + 10t + 1\right) + C}[/tex]

Answer:

Slope: 10

Y-intercept: +9

Step-by-step explanation:

An equation written in slope-intercept form is y=mx+b. "m" is your slope and b is your y-intercept.

Answer:

20

Step-by-step explanation:

492/99x100=21.43

nearest tenth percentage is 20

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

Correct Expression :

[tex]\qquad \tt \rightarrow \: |10| + | - 6| [/tex]

[tex]\qquad \tt \rightarrow \: distance = 16\:\: units\degree[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Using distance formula -} [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{( - 6 - 10) {}^{2} + (4 - 4) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{( - 16) {}^{2} + 0} [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{256} [/tex]

[tex]\qquad \tt \rightarrow \: 16 \: \: units[/tex]

For short it can be expressed as :

[tex]\qquad \tt \rightarrow \: |10| + | - 6| = 10 + 6 = 16[/tex]

[ y - coordinate of both the points are same ]

Correct option - D

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

We have an odd number of consecutive integers, therefore the middle one is equal to the average of all of them. And since the average is equal to the sum of the numbers divided by their number, the middle integer in this problem is equal to 369 divided by 9, which is equal to 41.

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Answer:

You cannot solve this problem with only one given equation

Step-by-step explanation:

You need at least 2 equations to solve for two variables.

a) Corresponding angles of similar figures are congruent, so [tex]\angle B \cong \boxed{\angle Z}[/tex]

b) Scale factor = (image)/(preimage). Since we are looking for ABCD to WZYX, this means that WZYX is the image and ABCD is the preimage. Thus, the scale factor is [tex]\frac{25}{10}=\boxed{5/2}[/tex]

c) Since the scale factor is 5/2,

[tex]\frac{20}{t}=\frac{5}[2}\\\\40=5t\\ \\ t=\boxed{8}[/tex]

Answer:

Step-by-step explanation:

The initial vale is when x = 0

-  That is 75,

The growth factor is 2%.

The converse of the statement will be : if x^2 = 100 then x = -10, which is not true.

In order to write a converse of a conditional statement "p then q",  will be "q then p" the hypothesis and conclusion interchanges.

Then the converse of the statement will be :

if x^2 = 100 then x = -10,

which is not true.

Since , x = +10, then x^2 = 100

Therefore, if x^2 = 100 then x = -10, which is not true.

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The sample size required is 2938.645

Probability is the likeliness of an event to happen.

It is given that

p = .37

∈ = 0.025

∝ = 1 - 0.995 = 0.005

∝[tex]\rm z_{\alpha/2} = z_{0.005/2} = 2.807[/tex]  (From z table)

Sample size n is given by

[tex]\rm n = (\dfrac{z_{\alpha/2}}{\epsilon})^2 p (1-p)\\\\n = (\dfrac{2.807}{.025})^2 *0.37*(1-0.37)\\\\n = 2938.645\\[/tex]

Therefore the sample size required is 2938.645

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Answer:

The Answer is [B]

Step-by-step explanation:
i actually dont have one

Answer:

∠MOP ≅ ∠NOQ

Step-by-step explanation:

Vertical Angle Theorem

When two straight lines intersect, they form two pairs of angles.  The vertically opposite (non-adjacent) angles are congruent.

Therefore:

∠MON ≅ POQ  and  ∠MOP ≅ ∠NOQ

A function assigns the values. The value of f(-3) and f(3) + f(-3) is 8 and -8, respectively.

A function assigns the value of each element of one set to the other specific element of another set.

Given the function f(x)=-x²-4x+5, therefore, the value of f(x) when the value of x is -3 is,

f(-3) = -(-3)² - 4(-3) + 5

f(-3) = -9 + 12 + 5

f(-3) = 8

Now, the value of f(x) when the value of x is 3 is,

f(3) = -(3)²-4(3)+5

f(3) = - 9 - 12 + 5

f(3) = -16

further, the value of f(3) + f(-3) is,

f(3) + f(-3) = -16 + 8

f(3) + f(-3) = -8

Hence, the value of f(-3) and f(3) + f(-3) is 8 and -8, respectively.

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Answer:

2 and 1/4 cups

Step-by-step explanation:

4 cups-5 cups

5 cups-?

(5×5)÷4=6 cups and 1/4

6 and 1/4-4=2 cups and 1/4

The pair of equations (c) y = (1 / 6) x + 8 and y = 6x + 4 are not parallel

A linear equation is represented as:

y = mx + b

Where m is the slope of the line

Two lines are said to be parallel if their slopes are the same

i.e. y = mx + b and y = mx + c

Using the above as a guide, the option (c) represents lines that are not parallel, because they do not have the same slope

Hence, y = (1 / 6) x + 8 and y = 6x + 4 are not parallel

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Answer:

9.05

Step-by-step explanation:

make gallons into quarts

quar prefix in many languages means 4

1 gallon is 4 quarts

3 gallons is 4 times 3 -> 12 quarts

just by seeing 108 and 12 the answer will be around 9

108.90 ÷ 12 = 9.05

Multiply by 9/25 to make the coefficient of the variable 1 the answer is 9/25.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have a given linear equation.

After solving the linear equation we get:

[tex]\rm \dfrac{25}{9}x = 25[/tex]

To make the coefficient of the variable 1

Multiply by 9/25 on both sides.

[tex]\rm \dfrac{9}{25}\times\dfrac{25}{9}x = 25\times \dfrac{9}{25}[/tex]

x = 9

Thus, multiply by 9/25 to make the coefficient of the variable 1 the answer is 9/25.

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Answer: the answer is 9/25

Step-by-step explanation: Multiplying both sides of the equation by 9/25 isolates x

Given that [tex]f(x) = x[/tex] and [tex]g(x) = 2x^3[/tex], we have

[tex]f(g(x)) = f(2x^3) = 2x^3[/tex]

and

[tex]g(f(x)) = g(x) = 2x^3[/tex]

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. The length of the tree is 23.66 meters.

The tangent or tanθ in a right-angle triangle is the ratio of its perpendicular to its base. it is given as,

[tex]\rm Tangent(\theta) = \dfrac{Perpendicular}{Base}[/tex]

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

Let the height of the tree be represented by x.

The length of the shadow when the angle of elevation is 45°.

Length of shadow = x/ Tan(45°)

The length of the shadow when the angle of elevation is 60°.

Length of shadow = x/ Tan(60°)

Now, since the difference between shadows is 10 meters. Therefore, we can write,

x/ Tan(45°) - x/ Tan(60°) = 10m

x[1/ Tan(45°) - 1/ Tan(60°) ] = 10 m

x (0.42265) = 10 m

x = 23.66 m

Hence, the length of the tree is 23.66 meters.

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Since the product of variables in inverse proportion is constant, the equation is [tex]\boxed{xy=-1300}[/tex]