Answer:
4 pi ( = 12.566 in^2 )
Step-by-step explanation:
TOTAL area = pi r^2 = pi (6)^2 = 36 pi in^2
divide into 9 pieces 36 pi / 9 = 4 pi in ^2
One lucky day, you meet a leprechaun who promises to give you fantastic wealth, but hands you only a penny before disappearing. You head home and place the
penny under your pillow. The next morning, to your surprise, you find two pennies under your pillow. The following morning, you find four pennies, and the morning after
that, eight pennies.
Suppose that you could keep making a single stack of the pennies. After how many days would the stack be long enough to reach a star that is about 3x10¹3 km
away? (Assume that 1 penny = 1.5 mm)
The number of days would the stack be long enough to reach a star that is about 3 × 10¹³ km away is 64 days
How to find the number of days the penny would stack?Since from the question, we see that the number of pennies double with each day. It forms a geoemetric progression with
first term a = L and common ratio , r = 2.Since the number of pennies after n days equals N = 2ⁿ
Let
L = length of 1 penny = 1.5 mm = 1.5 × 10⁻³ mSo, after n days, the length of the stack of pennies is the geoemetric progression D = 2ⁿ × L
Number of days pennies would stack to reach starMaking n subject of the formula, we have
n = ㏒(D/L)/㏒2
Since D = the distance of the star = 3 × 10¹³ km = 3 × 10¹⁶ m, and L = length of 1 penny = 1.5 mm = 1.5 × 10⁻³ mSubstituting the values of the variables into the equation, we have
n = ㏒(D/L)/㏒2
n = ㏒(3 × 10¹⁶ m/1.5 × 10⁻³ m)/㏒2
n = ㏒(3/1.5 × 10¹⁹)/㏒2
n = ㏒(2 × 10¹⁹)/㏒2
n = ㏒2 + ㏒10¹⁹/㏒2
n = (19㏒10 + ㏒2)/㏒2
n = (19 + 0.3010)/0.3010
n = 19.3010/0.3010
n = 64.1
n ≅ 64 days
So, the number of days would the stack be long enough to reach a star that is about 3 × 10¹³ km away is 64 days
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Match each box plot to the data set it represents.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
{20,18,8,18,10,8,4}
{12,14,16,20,4,8,10}
{12,16,4,20,8,6,8}
An expression can either be an equation or an inequality.
The correct classification of the terms are:
Expression; 4x+20
Inequality: 4x+20>40
Equation: 4x+20=40
We have given that,
{20,18,8,18,10,8,4}
{12,14,16,20,4,8,10}
{12,16,4,20,8,6,8}
How to determine the correct classification?To determine the correct classification, we make use of the following highlights
When an expression has the =, then the expression is an equation.
When an expression has any of the following signs>, <, >=, <= or != , then the expression is an inequality.
When the expression is neither an equation nor an inequality, then it is just an expression.
Hence, the correct classifications are:
Expression; 4x+20
Inequality: 4x+20>40
Equation: 4x+20=40
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Help anyone? Simple problem
Answer:x>7
Step-by-step explanation:
Its saying a nuber greater than 7 and 3 plus 8 would be 11
Smallest to greatest 4/9, 4.9, 49%
Answer:
4/9, 49%, 4,9
Step-by-step explanation:
4/9=0,444444
49%=0,49
4,9=4,9
This question was confusing 15 for whoever answers
Answer:
Refer to the attached image. I'm not clear on one point. Yes, it is confusing.
Step-by-step explanation:
See attached image.
On a coordinate plane, 2 parallelograms are shown. Parallelogram 1 has points (0, 2), (2, 6), (6, 4), and (4, 0). Parallelogram 2 has points (2, 0), (4, negative 6), (2, negative 8), and (0, negative 2). How do the areas of the parallelograms compare? The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2. The area of parallelogram 1 is 2 square units greater than the area of parallelogram 2. The area of parallelogram 1 is equal to the area of parallelogram 2. The area of parallelogram 1 is 2 square units less than the area of parallelogram 2
The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2
How to compare the areas?The coordinates are given as:
Parallelogram 1: (0, 2), (2, 6), (6, 4), and (4, 0).
Parallelogram 2: (2, 0), (4, -6), (2, -8), and (0, -2)
Next, calculate the base and the height
For parallelogram 1, we have:
Base = (0, 2) and (2, 6)
Height = (6, 4), and (4, 0).
So, we have:
[tex]Base = \sqrt{(0 - 2)^2 + (2 -6)^2} = \sqrt{20}[/tex]
[tex]Height = \sqrt{(6 - 4)^2 + (4 -0)^2} = \sqrt{20}[/tex]
The area is:
Area = Base * Height
Area = √20 * √20
Area = 20
For parallelogram 2, we have:
Base = (0, -2) and (4, -6)
Height = (4, -6) and (2, -8)
So, we have:
[tex]Base = \sqrt{(0 -4)^2 + (-2 +6)^2} = \sqrt{32}[/tex]
[tex]Height = \sqrt{(4 - 2)^2 + (-6 +8)^2} = \sqrt{8}[/tex]
The area is:
Area = Base * Height
Area = √32 * √8
Area = 16
By comparing both areas, we have:
20 is greater than 16 by 4
This means that the area of parallelogram 1 is greater by 4 units
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if 13n-6 = 98 what is the value of n
Answer:
n = 8
Step-by-step explanation:
13n-6 = 98
Solution:
13n = 98+613n = 104n = 104/13n = 8Hence the value of n is 8.
13n - 6 = 98
13n = 98 + 6
13n = 104
n = 104/13
n = 8
Simplify completely.
3 189x5y7
√/7x²y²
3
Answer:
[tex]\large \boxed{\sf 3x\sqrt[3]{y^5}}[/tex]
Explanation:
[tex]\rightarrow \dfrac{\sqrt[3]{\sf 189x^5y^7}}{\sqrt[3]{\sf 7x^2y^2}}[/tex]
applying radical rule[tex]\rightarrow \sf \sqrt[3]{\dfrac{\sf 189x^5y^7}{\sf 7x^2y^2}}[/tex]
simplify[tex]\rightarrow \sqrt[3]{\sf 27x^3y^5}[/tex]
put cubic root[tex]\rightarrow \sqrt[3]{\sf 27} \sqrt[3]{\sf {x^3} }\sqrt[3]{\sf y^5}}[/tex]
simplify[tex]\rightarrow \sf 3x\sqrt[3]{y^5}[/tex]
An equilateral triangle has the height BO= 80 cm. Considering, height BO splits the base (segment) AC into two equal segments of size x/2, find X.
Answer:
Given - an equilateral triangle
An equilateral triangle means all sides equal and all angle equal to 60°
In triangle BOA
sin 60° = OB/ AB
√3/2. = 80/AB
AB = 160√3/3
X = 160√3/3
simplify the equation ( 3(3) × 3 (4) ) ÷ 3 (2)
Answer:
(3(3) × 3(4) ) ÷ 3(2)
(9 × 12) ÷ 6
108 ÷ 6
18
The table gives the average monthly precipitation, in inches, in Seattle, Washington, from January through July, where January is month 1 and July is month 7. How would you describe the relationship between the variables in the data? Select all that apply.
There is a linear association between the month and average monthly precipitation.
There is a nonlinear association between the month and average monthly precipitation.
As the number of months increases, the average monthly precipitation, in inches, increases.
As the number of months increases, the average monthly precipitation, in inches, decreases.
The relationship between the variables in the data will be as the number of months increases, the average monthly precipitation, in inches, decreases. Then the correct option is D.
What is a function?A statement, principle, or policy that creates the link between two variables is known as a function.
The table gives the average monthly precipitation, in inches, in Seattle, Washington, from January through July, where January is month 1 and July is month 7.
Month 1 2 3 4 5 6 7
Average monthly precipitation 5.2 3.9 3.3 2.0 1.6 1.4 0.6
Then the relationship between the variables in the data will be as the number of months increases, the average monthly precipitation, in inches, decreases.
Then the correct option is D.
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The graph of the function f(x) = (x-3)(x + 1) is shown.
-10-8-6
q
10-
Which describes all of the values for which the graph is
positive and decreasing?
all real values of x where x < -1
all real values of x where x < 1
all real values of x where 1
O all real values of x where x > 3
Answer:
x < -1
Step-by-step explanation:
Draw a parabola (the graph) passing trough two x-intercepts -1 and 3 and open up.
complete the square to rewrite y=x^2+8x+3 in vertex form and then identify the minimum y-value of the function
The vertex-form of the quadratic equation is given by y = (x + 4)² - 13, and the minimum value of y is of -13.
What is the equation of a parabola given it’s vertex?The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient. If a > 0, k is the minimum value of y, and if a < 0, it is the maximum value.
In this problem, the equation is:
y = x² + 8x + 3.
Completing the squares, the function is:
y = (x + 4)² - 13
13 is subtracted as (x + 4)² = x² + 8x + 16, hence for the equations to be equal 13 has to be subtracted. k = -13 is also the minimum value of y.
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The minimum y-value of the function for the parabolic equation is -13.
What is the vertex of a parabolic equation in quadratic form?The vertex for an up-down facing parabola of the form y = ax² + bx + c is [tex]\mathbf{x_v= -\dfrac{b}{2a}}[/tex]
From the given equation:
y = x² + 8x + 3
The parameters for the parabola are:
a = 1, b = 8, c = 3
[tex]\mathbf{x_v= -\dfrac{8}{2\times 1}}[/tex]
[tex]\mathbf{x_v= -4}[/tex]
If we replace the value of [tex]\mathbf{x_v= -4}[/tex] to find the minimum value of [tex]\mathbf{y_v}[/tex] value, we have:
[tex]\mathbf{y_v = -13}[/tex]
Thus, the parabola vertex is (-4,-13). If a< 0, the vertex is a maximum value and If a>0, the vertex is a minimum value.
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In a market survey, 100 traders sell fruits, 40 sell apples, 46 oranges, 50 mangoes. 14 apples and oranges. 15 apples and mangoes, and 10 sell the three fruits. Each of the 100 traders sells at least one of the three fruits. Find the number that sell oranges and mangoes only.
The number of traders that sell oranges and mangoes only are 17.
How to determine the common differenceSince there are three sets, use the formula
n (A∪O∪M) = n(A) + n(O) + n(M) - n(A∩O) -n(O∩M) - n(A∩M) + n(A∩O∩M)
A represents apple traders = 40
O represents orange traders = 46
M represents mangoes traders = 50
A∪O∪M = total traders = 100
A∩O = 14
O∩M = ?
A∩M = 15
A∩O∩M = 10
Substitute values into the formula
100 = 40 + 46 + 50 - 14 - 15 - O∩M + 10
100 = 146 - 29 - O∩M
100 = 117 - O∩M
Make O∩M subject of formula
- O∩M = 100 -117
O∩M = 17 traders
Therefore, the number of traders that sell oranges and mangoes only are 17.
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Fraction
Puja Limbu did 8 out of 10 math problems and Raju lama did 11 out of 15 similar maths problems.Express the number of problems solved by each of them in fractions and identify who did better performance.
Using percentages, we have that Puja Limbu did 80% of the problems and Raju Lama did 73.3%, hence Puja Limbu had the better performance.
What is a percentage?The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:
[tex]P = \frac{a}{b} \times 100\%[/tex]
The percentage for Puja Limbu is:
[tex]P = \frac{8}{10} \times 100\% = 80\%[/tex]
The percentage for Raju Lama is:
[tex]P = \frac{11}{15} \times 100\% = 73.3\%[/tex]
80% > 73.3%, hence Puja Limbu had the better performance.
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What is the range of the given data set?
Answer:
6
Step-by-step explanation:
21 - 15 = 6
please help, performance task: trigonometric identities
The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
How to solve the trigonometric equations?Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)
The equation can be split as follows:
y = 1 - cos(x)
y = 2 - 2sin²(x)
Next, we plot the graph of the above equations (see graph 1)
Under the domain interval (-π, π), the curves of the equations intersect at:
(-π/3, 0.5) and (π/3, 0.5)
Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)
Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)
The equation can be split as follows:
y = 4cos⁴(x) - 5cos²(x) + 1
y = o
Next, we plot the graph of the above equations (see graph 2)
Under the domain interval [0, 2π), the curves of the equations intersect at:
(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)
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HELP! WILL GIVE BRAINLIEST AND 100 POINTS!
A study showed that low-intensity vibration therapy reduces pain levels in patients with fibromyalgia. During each session in the study, vibration pads were placed on the pain site indicated by the patient. Pain reduction was measured through self-reporting after each session.
Another study is being designed to examine whether low-intensity vibration therapy also reduces pain in patients suffering from ruptured disks in the lumbar region of the back. Three hundred male patients are subjects in the new study.
Part A: What is an appropriate design for the new study? Include treatments used, method of treatment assignment, and variables that should be measured. (4 points)
Part B: If the study consisted of 150 male and 150 female patients instead of 300 male patients, would you change the study design? If so, how would you modify your design ? If not, why not? (4 points)
Part C: Could your design be double-blind? Explain. (2 points)
Answer:
Part A: The appropriate design for the study includes;
Treatment used; Chamomile oil treatment
Method of treatment; Application of the chamomile oil to the cervical region of patients experiencing pain due to pinched nerves
Treatment assignment; Treatment should be assigned to patients with pinched nerves
Variables that should be measured; Reduction or relief of pain as reported by the patients
Part B; The study should be administered equally to both male and female as the symptoms can be experienced by both male and female
Part C; The design could be double blind by replacing the chamomile administered by placebo, thereby preventing bias from both researcher and participants in the results of the research.
Step-by-step explanation:
Please help asap
What is the domain and range of T
Answer:
Domain = {-3, -2}Range = {-4, -3, 4}Step-by-step explanation:
The domain is the set of x-values, and the range is the set of y-values.
(5x-1) -(2-8x) for x = 0.75
What number were both the numerator and denominator multiplied by to arrive at the equivalent fraction? What number were both the numerator and denominator multiplied by to arrive at the equivalent fraction ?
Answer:
Both the numerator and denominator should be multiplied by the same number to arrive at the equivalent fraction.
Step-by-step explanation:
Equivalent fractions = two or more than two fractions are said to be equal if both results the same fraction after simplification.
For example, consider the fraction 1/3
Multiplying numerator and denominator with 2, we get 1/3 × 2/2 = 2/6
Multiplying numerator and denominator with 3, we get 1/3 × 3/3 = 3/9
Multiplying numerator and denominator with 4, we get 1/3 × 4/4 = 4/12
Therefore, we can conclude that,
1/3 = 2/6 = 3/9 = 4/12 these are equivalent fractions.
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Answer: 2 and 6/8
Step-by-step explanation:
If you receive a 25% DISCOUNT off an item costing $22.00, how much money do you save?
Answer:
The amount of money you saved by receiving a discount of 25% is $5.5
Step-by-step explanation:
Discount is the reduction in the price of goods or services offered by shopkeepers at the marked price. Selling price is the actual price at which an article is sold after any reduction or discounts in the cost price.
discount is always calculated on the cost price of the article
formula to calculate the discount and discount %
Discount = List Price - Selling Price
Discount (%) = (Discount/cost price) × 100
here, in the question discount % is given = 25%
cost price of the item = $22
therefore using the above mentioned discount percentage formula:
25 = (Discount/22)×100
25/100 = Discount/ 22
0.25 × 22 = Discount
$5.5 = Discount
thus ,
the amount of many you saved by receiving a discount of 25% is $5.5
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We have two fractions, 1/6 3/8 and we want to rewrite them so that they have a common denominator (and whole number numerators). What numbers could we use for the denominator? Choose 2 answers:
Answer:
See below
Step-by-step explanation:
The denominator has to be divisible by 6 and 8
you could choose 24 48 72 96 etc
I'm gonna need so help
Answer:
-4 and -6 are the answers
Z varies directly as x and y, z=6 when x=2 and y=6 find the value of z when x=3 and y=8
Answer:
12
Step-by-step explanation:
Direct Variation. I think it's gonna be like this.
SInce Z is not inversely to y , its varies directly to both.
Then it's,
Z=kxy, where k is constant.
subst. Z=6,x=2 and y=6.
6=k×2×6
6=k×12=12k
6=12k=½
the formula connecting them is
Z=½xy
Z=½×3×8
Z= 1×3×8÷2
Z=24÷2
Z=12.
That's my solution.
which of the following are NOT classified as a trapezoid? Select all that apply
a) rhombuses
b) parallelograms
c) rectangles
d) squares
e) quadrilaterals
Answer:
[tex]\boxed {a, b, c, d}[/tex]
Step-by-step explanation:
Rhombuses, parallelograms, rectangles, and squares cannot be classified as trapezoids as they have 2 pairs of parallel sides each. But quadrilaterals can be classified as trapezoids if they have a pair of parallel sides and a pair of non-parallel sides.
a) rhombuses
b) parallelograms
c) rectangles
d) squares
Which of the following is an example of a quadratic equation?
A. y = 216+6
B. x²-64 = 0
C. y = 4x+6
D. x+10 = 33
Answer: B
Step-by-step explanation:
A quadratic equation has degree 2.
PLEASE HELP ME WITH THIS
Answer:
Vertex
Vertex are the end points of parabola where it opens up
locus are the group of points
latus rectum is the line parallel to it .
Question 4 (Essay Worth 10 points)
(05.06; 05.07 MC)
A prism and two nets are shown below:
Image of a right triangular prism and 2 nets. The triangle bases have base 4, height 3, and diagonal side 5. The length of the prism from the bases is 8.6. Net A has 3 rectangles in a row. The middle one has sides AC and CD. This middle one has triangle ABC on top and identical triangle below. Net B is the same except that the triangle base ABC is on top of the last rectangle which has sides AC and CD. Units are in inches.
Part A: Which is the correct net for the prism? Explain your answer. (2 points)
Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points)
Part C: What is the surface area of the prism? Show your work. (4 points)
Answer:
115.2 in^2
Step-by-step explanation:
total surface area Stot = 113.2 in2
lateral surface area Slat = 103.2 in2
top surface area Stop = 6 in2
bottom surface area Sbot = 6 in2
how many spherical balls of diameter 15cm can be covered by 40 square metres of material
Answer:
It's very simple: divide the 40 m² area by area of 1 one sphere
[tex] \frac{40 \: m {}^{2} }{3.41 \times 15m {}^{2} } = 565[/tex]
