(WILL MARK BRAINLIAST)( 1 answer question.. look the photo)

As the cars come closer together, the amount of potential energy in the system:


-Increases

-Decreases

-Stays the same

Answer:

The coefficient of rolling friction will be "0.011".

Explanation:

The given values are:

Initial speed,

[tex]v_i = 4.0 \ m/s[/tex]

then,

[tex]v_f=\frac{4.0}{2}[/tex]

    [tex]=2.0 \ m/s[/tex]

Distance,

s = 18.2 m

The acceleration of a bicycle will be:

⇒ [tex]a=\frac{v_f^2-v_i^2}{2s}[/tex]

On substituting the given values, we get

⇒    [tex]=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}[/tex]

⇒    [tex]=\frac{4-8}{37}[/tex]

⇒    [tex]=\frac{-4}{37}[/tex]

⇒    [tex]=0.108 \ m/s^2[/tex]

As we know,

⇒  [tex]f=ma[/tex]

and,

⇒  [tex]\mu_rmg=ma[/tex]

⇒       [tex]\mu_r=\frac{a}{g}[/tex]

On substituting the values, we get

⇒       [tex]=\frac{0.108}{9.8}[/tex]

⇒       [tex]=0.011[/tex]

Answer:

27: 85

28:75%

Explanation:

27:68=80

?=100 hence (68×100)÷80

=85

28:18/24× 100

=75%

Answer:

3.2 m

Explanation:

From the question given above, the following data were obtained:

Coefficient of friction (μ) = 0.1

Initial velocity (u) = 0 m/s

Mass (m) = 6 Kg

Acceleration (a) = 0.4 m/s²

Time (t) = 4 s

Distance (s) =.?

The distance travelled can be obtained as illustrated below:

s = ut + ½at²

s = (0×4) + (½ × 0.4 × 4²)

s = 0 + (0.2 × 16)

s = 0 + 3.2

s = 3.2 m

Thus, the box will travel 3.2 m in 4 s.

Answer:

Richter scale Magnitude

Richter scale. Magnitude is a measure of the amount of energy released during an earthquake, and you've probably heard news reports about earthquake magnitudes measured using the Richter scale. Something like, "A magnitude 7.3 earthquake struck Japan today.

Explanation:

Hope I helped!

Answer:

1.6e20

Explanation:

Answer:

Ur answer is 12 sir!

Explanation:

HAve a good day sir

Answer:

--------------------------------

Explanation:

Answer:

25 m/s

Explanation:

From the question,

Average speed = Total distance /total time.

S' = D/T........................... Equation 1

D = 40+60 = 100 Km = 100000 m.

T = t₁+t₂

t₁ = (40×3600/72) s = 2000 s

t₂ = 60000/30 = 2000 s

T = 2000+2000 = 4000 s.

SUbstitute the values of T and D into equation 1

S' = 100000/4000

S' = 25 m/s

sorry bro but i don't know his i am also bad

Explanation:

but maybe you can you the formula of volatage as well as

Explanation:

3d7eei4rueiuxx7ex5x775xe

Answer:

I. Friction force exerted on the body is less than 100N

Explanation:

For  a body to be static, the moving force must be equal to the frictional force. Since the frictional force is a force of opposition. It tends to oppose the moving force acting on an object.

Hence if the moving force is greater than the force of friction, the Force of fiction will not be able to overcome the moving hence the body will tend to move.

Therefore, for a body to move, Fm > Ff or Ff < Ff

Fm is the moving force

Ff is the force of friction

Given

Fm = 100N

For the 100N body to move the frictional force must be less than 100N

Answer:

a) v = 18.86 m / s, b)  h = 8.85 m

Explanation:

a) For this exercise we can use the conservation of energy relations.

Starting point. Like the compressed spring

          Em₀ = K_e + U = ½ k x² + m g x

the zero of the datum is placed at the point of the uncompressed spring

Final point. With the spring if compress

           Em_f = K = ½ m v²

how energy is conserved

          Em₀ = Em_f

          ½ k x² + m g x = ½ m v²

           v² = [tex]\frac{k}{m}[/tex]  x² + 2gx

let's reduce the magnitudes to the SI system

          m = 500 g = 0.500 kg

          x = -45 cm = -0.45 m

the negative sign is because the distance in below zero of the reference frame

let's calculate

           v² = [tex]\frac{900}{0.500}[/tex]  0.45² + 2 9.8 (- 0.45)

           v = √355.68

           v = 18.86 m / s

b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops

           Em_f = U = m g h

           Em₀ = Em_f

            ½ k x²2 + m g x = m g h

            h = ½  [tex]\frac{k}{g}[/tex]   x² + x

let's calculate

           h = [tex]\frac{1}{2} \ \frac{900}{9.8 } \ 0.45^2[/tex] - 0.45

           h = 8.85 m

measured from the point where the spring is uncompressed

Answer:

In its most general sense, a picture is a visual representation of something, especially in the form of a painting, drawing, photograph, or the like. A picture can also refer to a mental image, among other senses.

Answer:

hi..bro

make pinky sis answer as brinlist ok

have a good day

Explanation:

The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).

hope my ans helps

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Stay safe

Answer:

hinit = 17.5 m

Explanation:

       [tex]E_{o} = U_{o} = m*g*h_{init} (1)[/tex]

       [tex]E_{f} = U_{f} + K_{f} = m*g* h_{2} + \frac{1}{2} *m*v_{f} ^{2} (2)[/tex]

       [tex]F_{c} = m*\frac{v_{f} ^{2}}{R} (3)[/tex]

       [tex]F_{c} = m*\frac{v_{f} ^{2}}{R} = m*g (4)[/tex]

       [tex]v_{f}^{2} = R*g (5)[/tex]  

      [tex]h_{init} = h_{2} + \frac{1}{2} R = 10m + 7.5 m = 17.5 m (6)[/tex]

The spring constant of the given spring is= -533.33

The potential energy of the spring= 6 Joule

A push or pull that causes object to change its state of rest or motion.

For spring;

K is the spring constant.

         ⇒Force = -kx

         ⇒80N=0.15m ×-k

          ⇒K=-80/0.15

          ⇒K= -533.333

So the spring constant is 533.333

Potential Energy=1/2kx²

                            ⇒0.5×533.33 ×0.15×0.15

                            ⇒5.95.99 N

Learn more about force here: http://brainly.com/question/25239010

#SPJ2

Answer:

The correct answer for this would be D.

Explanation:

Are tight coils of DNA

Answer:

D all of the above

Explanation:

electricity moves easily through all of them and none of them prevent the flow of electricity

Answer:

The horizontal distance traveled by the projectile is 15.23 m.

Explanation:

Given;

angle of projection, θ = 25⁰

initial velocity of the projectile, u = 15 m/s

time of flight, t = 1.12 s

The the travelling path of the object is calculated as the range of the projectile

[tex]R = u_x t\\\\R = (15\ Cos \ 25^0) \times 1.12\\\\R = 13.595 \times 1.12\\\\R = 15.23 \ m[/tex]

Therefore, the horizontal distance traveled by the projectile is 15.23 m.

Answer:

[tex]l1 < l2[/tex];  [tex]l1[/tex] is less than [tex]l2[/tex]

Explanation:

Firstly, we take a look at the concept of moment of inertia, This concept comes from the fact that it resists change in motion. A body that has a higher value of moment of inertia requires more force ( torque) to change its position as compared to a body with lesser value of moment of inertia.

Now taking a look at the situation in  the question, both the magnets are placed in similar magnetic field, so having the same amount of force, hence torque acts on both magnets.

Since magnet 1 takes less time to rotate compared to magnate 2, hence magnet 1's moment of inertia should be less than that of magnet 2.

Therefore, [tex]l1 < l2[/tex];  [tex]l1[/tex] is less than [tex]l2[/tex]

Answer: iDc im in 3grade

Explanation:sorry

Answer:

The correct answer is "12 rad/s"

Explanation:

The given values are,

Mass of rod,

M = 140 g

i.e.,

   = 0.14 kg

Length,

L = 57 cm

i.e.,

  = 0.57 m

Mass of beads,

M = 30 g

i.e.,

   = 0.03 kg

Angular speed,

r = 11 cm

i.e.,

 = 0.11 m

Now,

The inertia of rods will be:

=  [tex]\frac{1}{12}ML ^2[/tex]

On substituting the values, we get

=  [tex]\frac{1}{12}\times 0.14\times (0.57)^2[/tex]

=  [tex]0.0037905 \ kg-m^2[/tex]

The inertia of beads will be:

=  [tex]mr^2[/tex]

On substituting the values, we get

=  [tex]0.03\times (0.11)^2[/tex]

=  [tex]0.000726 \ kg-m^2[/tex]

The total inertia will be:

=  [tex]Inertia \ of \ rods+Inertia \ of \ beads[/tex]

=  [tex]0.0037905 + 0.000726[/tex]

=  [tex]0.0045165 \ kg-m^2[/tex]

now,

The angular speed of the system will be:

⇒ [tex]L_1w_1=L_2w_2[/tex]

On substituting the values in the above equation, we get

⇒ [tex]0.0045165\times 23 = (0.0037905 + (0.03\times 0.285^2)\times 2 )\times w_2[/tex]

⇒ [tex]0.1038795 = 0.0037905 + (0.00243675\times 2 )\times w_2[/tex]

⇒             [tex]w_2 = 12 \ rad/s[/tex]

Answer:

The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.

Explanation:

Given;

potential difference between the plates, V = 10 V

length of each square side of the plates, L = 20 cm = 0.2 m

area of the plates, A = 0.2 x 0.2 = 0.04 m²

separation of the plates, d = 3 cm = 0.03 m

The work done in bringing the plates together is calculated as;

W = ¹/₂qV

[tex]W = \frac{1}{2} (\frac{\epsilon_0 A }{d}V) \times V\\\\W = \frac{\epsilon_0 A V^2}{2d}\\\\W = \frac{8.85 \times 10^{-12} \ \times \ 0.04\ \times \ 10^2}{2(0.03)} \\\\W = 5.9 \times 10^{-10} \ J[/tex]

Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.

Answer:

It is A. Light blue

_____________

Hope this helps!

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