Which of the following best describes the set of complex numbers?
OA. The set of all numbers of the form a+bi, where a and bare any
real numbers and i equals -1
B. The set of all numbers of the form abi, where a and bare any real
numbers and i equals 1
C. The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1
OD. The set of all numbers of the form abi, where a and b are any real
numbers and / equals -1

Answer:

Last one/D 9^9/5/5^9/10

Step-by-step explanation:

Answer:

43

Step-by-step explanation:

31+12=43

Therefore adding 43 to -31 should give the answer 12.

Hii!

____________________________________________________________

Answer:

43

Step-by-step explanation:

We can find an answer to this question by setting up an equation.

-31+x=12

x is the unknown amount we should add to -31 to obtain 12.

Now, to solve it for the variable, x, we need to add 31 to both sides.

Upon doing this we obtain.

x=43

∴, 43 should be added to -31 to get 12

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Hope that this helped! Best wishes.

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Answer:

a) 5 pounds

b) 365 dollars

Your question translates to computing [tex]3^{2020} \pmod {13}[/tex].

Recall Euler's theorem: if [tex]\gcd(a,n)=1[/tex] (that is, [tex]a[/tex] and [tex]n[/tex] are relatively prime), then [tex]a^{\varphi(n)}\equiv1\pmod n[/tex], where [tex]\varphi(n)[/tex] denotes Euler's totient function, which counts the number of positive integers relatively prime to [tex]n[/tex].

Since 13 is prime, we have [tex]\phi(13)=12[/tex]. Then by Euler's theorem,

[tex]3^{12} \equiv 1 \pmod{13}[/tex]

Now, observe that 2020 = 168×12 + 4, so that

[tex]3^{2020} \equiv 3^{168\times12+4} \equiv \left(3^{12}\right)^{168} \times 3^4 \equiv 1^{168} \times 3^4 \equiv 3^4 \pmod{13}[/tex]

and since 3⁴ = 81 = 6×13 + 3, we end up with

[tex]3^{2020} \equiv 81 \equiv 3 \pmod{13}[/tex]

so the remainder upon dividing 3²⁰²⁰ by 13 is 3.

Ivanna's score was at the 36th percentile, will be 99.64 and Aldo's score was at the 19th percentile, will be 99.81.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Last year, over 10,000 students took an entrance exam at a certain state university.

Let the maximum score be 100.

Ivanna's score was at the 36th percentile, will be

⇒ [(10,000 – 36) / 10,000] x 100

⇒ 99.64

Aldo's score was at the 19th percentile, will be

⇒ [(10,000 – 19) / 10,000] x 100

⇒ 99.81

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Answer:

h(t)= 5r2-1

That the answer for the question

The slope of the line that passes through (1, -3) and (0, 2) is: B. m = -5.

Slope (m) = rise / run = change in y / change in x.

Given the points, (1, -3) and (0, 2):

Slope (m) = (-3 - 2)/(1 - 0)

Slope (m) = -5/1

Slope (m) = -5

Therefore, the slope of the line is: B. m = -5.

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Answer:

y^-1= x +8

Step-by-step explanation:

this may be helpful for you

Answer:

survey (A)

A questionnaire (or someone asking questions) is considered to be a survey. It is "surveying" someone's opinion on data.

hope this helps!!

Answer:

4/11 of an inch (about .4 of an inch)

Step-by-step explanation:

[tex]l \times 33 \times 5.75 = 69[/tex]

[tex]189.75l = 69[/tex]

[tex]l = \frac{69}{189.75} = \frac{4}{11} = .3636[/tex]

So the length of the popcorn box is 4/11 of an inch, or about .4 of an inch.

Answer:

-0.875

Step-by-step explanation:

So you have the points -4.25 and 2.50. To find the midpoint you simply add the two and then divide by 2. This results in (-4.25 + 2.50) / 2 = -0.875

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: x = 32°[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Diagonals of a Rhombus bisect each other at 90°

[tex]\qquad \tt \rightarrow \: x + 58 + 90 = 180[/tex]

[ Sum of interior angles of a triangle ]

[tex]\qquad \tt \rightarrow \: x + 148 = 180[/tex]

[tex]\qquad \tt \rightarrow \: x = 180 - 148[/tex]

[tex]\qquad \tt \rightarrow \: x = 32 \degree[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The diagonals of the rhombus intersect at right angle. Then the value of x will be 32°.

It is a polygon with four sides. The total interior angle is 360 degrees. In a rhombus, opposite sides are parallel and equal.

Figure ABCD is a rhombus.

Its diagonals intersect at right angle.

Let the another angle be x. Then we have

x + 58° + 90° = 180°

        x + 148° = 180°

                   x = 32°

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Answer:

28.125

Step-by-step explanation:

22.5×1.25=28.125

Answer:

28 1/8

Step-by-step explanation:

1.25 x 22.5 = 28.125

Answer:

2nd one is the correct

The following expressions (1+cosβ)(1−cosβ)sinβ is equivalent to sin³β

In a Right angled triangle , trigonometric ratios can be used to determine the value of angles and sides of the triangle.

The trigonometric expression given in the question is

(1+cosβ)(1−cosβ)sinβ

(a+b)(a-b) = a² - b²

( 1 - cos²β)sinβ

By the trigonometric Identity

1-cos²β = sin² β

 sin² β x sin β

sin³β

Therefore Option B is the correct answer.

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They will earn If they work every week If the year is $22100.

We have given that,

you currently make 425

We have to determine what is the gross they will earn If they work a week If the year.

We know that

A worker currently makes $425 per week

1year=52 weeks

So by proportion find the amount that the worker will earn in one year

[tex]\frac{425}{x}\times \frac{\$}{weeks}[/tex]

[tex]=\frac{x}{52}\times \frac{\$}{weeks}[/tex]

[tex]x=52\times 425[/tex]

x=22,100

Therefore, The answer is $22100.

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Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is one subtracted by the p-value of Z when X = 66.5.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{66.5 - 50}{5}[/tex]

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

0.0005 = 0.05%

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Answer:

usually at the login screen it gives you an option to reset your password if you forgot, it will appear in blue as "forgot password?" or "trouble logging in?"

Step-by-step explanation:

The size of the colony after 10 days is  852.

The growth rate of the colony can be represented with an exponential equation with the form:

FV = P(1 + r)^n

Where:

55(1.73)^5 = 852

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Answer: 2, 4, 6, 8

Step-by-step explanation:

Just plug x into the equation for each one.

x = -3

[tex]y=\frac{2(-3)}{3} +4\\y=\frac{-6}{3} +4\\y=2[/tex]

With this one, you can see it is a linear equation and for every increase of 3 on x, y in increased by 2.

x   -6   -3   0   3   6

y   0   2    4   6   8

Answer:

12x^7+15x^6

Step-by-step explanation:

Change 3x^3-2 to 3x

(x^4)(3x)(4x^2+5x)

Multiply your single terms

(3x^5)(4x^2+5x)

Then distribute

12x^7+15x^6

Answer:

a)  81π  in³

b)  27  in³

c)  divide the volume of the slice of cake by the volume of the whole cake

d)  10.6%

e)  see explanation

Step-by-step explanation:

The cake can be modeled as a cylinder with:

[tex]\sf Radius=\dfrac{1}{2}diameter \implies r=4.5\:in[/tex]

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

[tex]\begin{aligned}\sf \implies \textsf{Volume of the cake} & =\pi (4.5)^2(4)\\ & = \sf \pi (20.25)(4)\\ & = \sf81 \pi \:\: in^3\end{aligned}[/tex]

[tex]\begin{aligned}\textsf{Circumference of the cake} & = \sf \pi d\\& = \sf 9 \pi \:\:in\end{aligned}[/tex]

If each slice of cake has an arc length of 3 in, then the volume of each slice is 3/9π of the entire volume of the cake.

[tex]\begin{aligned}\implies \textsf{Volume of slice of cake} & = \sf \dfrac{3}{9 \pi} \times \textsf{volume of cake}\\\\& = \sf \dfrac{3}{9 \pi} \times 81 \pi\\\\& = \sf \dfrac{243 \pi}{9 \pi}\\\\& = \sf 27\:\:in^3\end{aligned}[/tex]

The volume of each slice of cake is 27 in³.

The volume of the whole cake is 81π in³.

To calculate the probability that the first slice of cake will have the marble, divide the volume of a slice by the volume of the whole cake:

[tex]\begin{aligned}\implies \sf Probability & = \sf \dfrac{27}{81 \pi}\\\\& = \sf 0.1061032954...\\\\ & = \sf 10.6\% \:\:(1\:d.p.)\end{aligned}[/tex]

Probability is approximately 10.6%  (see above for calculation)

If the four slices of cake are cut and passed out before anyone eats or looks for the marble, the probability of getting the marble is the same for everyone. If one slice of cake is cut and checked for the marble before the next slice is cut, the probability will increase as the volume of the entire cake decreases, until the marble is found.  So it depends upon how the cake is cut and distributed as to whether Hattie's strategy makes sense.

Answer:

7.1%

Step-by-step explanation:

Those that did not complete the race either gave up or were disqualified. This means that 18 + 3 = 22 people did not complete the race. The percentage is 22/310 × 100% = 7.1%

When h = 0 ,  [f(x + h) - f(x)]/h  = 2x +2 for the given expression.

The missing expression is  f(x) = x² + 2x.

f(x+h)-f(x)/h is called the formula of difference quotient.

When h---> 0 ,

the expression f'(x) = (f(x-h) - f(x)) / h is the equation for tangent to the line

Here the the expression is

f(x) = x² + 2x

Determining f(x + h) by substituting x = x + h on both sides of the given f(x).

Then f(x + h) = (x + h)² + 2(x + h)

= x² + 2xh + h² + 2x + 2h

the difference f(x + h) - f(x).

f(x + h) - f(x) = [x²  + 2xh + h²  + 2x + 2h] - [x² + 2x]

= 2xh + h² + 2h

Divide the difference from h as in the formula of difference coefficient

[f(x + h) - f(x)]/h = (2xh + h² + 2h) / h

= 2x + h + 2

So, when h = 0 ,  [f(x + h) - f(x)]/h  = 2x +2

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Answer:

  x = π/12, 5π/12

Step-by-step explanation:

We can work this problem a couple of ways. We can convert it to single trig function, shifted horizontally. Or we can convert it to a double-angle equation.

__

We recall the sum of angles formula is ...

  sin(x+y) = sin(x)cos(y) +cos(x)sin(y)

Using this, we can rewrite the left side of the equation using some angle offset y, and some scale factor k.

  k·sin(x +y) = k·sin(y)·cos(x) +k·cos(y)·sin(x) = 2cos(x) +2sin(x)

finding the shift

Equating coefficients of cos(x) and sin(x), we can solve for k and y:

  k·sin(y) = 2

  k·cos(y) = 2

The ratio of these equations is ...

  (k·sin(y))/(k·cos(y)) = 2/2

  tan(y) = 1   ⇒   y = π/4

  k = 2/sin(π/4) = 2√2

shifted equation

So, our original equation becomes ...

  2√2·sin(x +π/4) = √6

Dividing by √2 and using the inverse sine function, we have ...

  x +π/4 = arcsin((√3)/2) = π/2 ±π/6

  x = π/4 ±π/6

  x = π/12, 5π/12

__

If we square both sides of the original equation, we get ...

  (2sin(x) +2cos(x))² = (√6)²

  4sin²(x) +8sin(x)cos(x) +4cos²(x) = 6

  2sin(x)cos(x) = (6 -4)/4 = 1/2 . .  . . use sin² +cos² = 1, subtract 4, divide by 4

Using the trig identity 2sin(x)cos(x) = sin(2x), we can find ...

  2x = arcsin(1/2) = π/2 ±π/3 +2kπ . . . . k = an integer;

  x = π/4 ±π/6 +kπ . . . . for integer k

  x = {π/12, 5π/12, 13π/12, 17π/12}

We know that squaring the equation can introduce extraneous solutions, so we need to try these out. For x in the third quadrant, the sine and cosine values are both negative, so the only useful solutions here are ...

  x = π/12, 5π/12

_____

Additional comment

Based on the above, we now know that any trig expression of the form ...

  a·sin(x) +b·cos(x)

can be rewritten to the form ...

  (√(a² +b²))·sin(x +arctan(b/a)) . . . . . a scaled and shifted sine function

The arctangent will have to take the signs of 'a' and 'b' into account in order to get the angle quadrant right.

Answer:

5/17

Step-by-step explanation:

If we do the multiplication first, we get:

[tex]\frac{4-(12\div-12)}{13+(-8\div-2)}[/tex]

If we do the division next, we get:

[tex]\frac{4+1}{13+4} = 5/17[/tex]

Answer:

Multiply with 2 to the original sides