Find the principal needed now to get the given amount; that is, find the present value. To get $4000 after 2 1/4 years at 9% compounded daily The present value of $4000 is $? (Round to the nearest cent as needed.)
Step-by-step explanation:
Compounding formula
FV = PV ( 1 + i )^n FV = Future value (4000) PV = present value
i = decimal interest per PERIOD = .09/365
n = periods = 2 1/4 yrs * 365 days/yr = 821.25 periods
4000 = PV ( 1 + .09/365)^821.25
Solve for PV = $ 3266.83
SOMEONE, PLEASE HELP! ASAP, WILL GIVE 30 POINTS!
Using the equations given, only equation 2 has a proportional relationship.
What is a proportional and non-proportional relationship?Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other.
The difference between proportional and non-proportional linear relationships is that, although both have constant rates of change the proportional relationship has constant output to input ratios, and the non-proportional relationship does not.
In this problem, to determine the proportional relationship, we can also check for both values of x and y.
1. y = -0.75x + 5
When x = 1
y = -0.75(1) + 5
y = 4.25
when x = 2
y = -0.75(2) + 5
y = 3.5
The relationship is not proportional since as one variable increase, the other decreases.
2. y = 4x - 1
When x = 1
y = 4(1) - 1
y = 4 - 1
y = 3
when x = 2
y = 4(2) - 1
y = 8 - 1
y = 7
This relationship is proportional since the variables increases or decreases with one another.
3. y = (3/4)x
When x = 1
y = (3/4)(1)
y = 3/4
when x = 2
y = (3/4)(2)
y = 2/3
This relationship is not proportional
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For her geography project, Karen built a clay model of a
volcano in the shape of a cone. Her model has a diameter
of 12 inches and a height of 8 inches. Find the volume of
clay in her model to the nearest tenth. Use 3.14 for pi
Answer:
301.4 in^3
Step-by-step explanation:
Divide 12 by 2 to get the radius
12/2=6
Square 6 and multiply by 3.14 according to the area of a circle formula πr^2.
6^2=36 36*3.14=113.04
We now have the area of the base.
Multiply it by the height and divide by three to follow the formula for the volume of a cone, 1/3bh.
113.04*8=904.32. 904.32/3= 301.44, or 301.4 after rounding.
I-Ready
What is the distance between point P and point Q?
a) Find the value of 8 1/3 b) Find the value of 8 2/3 c) Find the value of 16 3/4
Answer:
a) 27. b) 27.3333 c) 40.75
I need some assistance with this ? Please
Answer:
I am sorry this is just so new for me like what even is an "imaginary" solution, i am in 6th grade wth
Natasha is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 20 inches × 15 1 4 inches. She needs to cut another rectangle that is 10 1 2 inches by 10 1 4 inches. How many total square inches of construction paper does Natasha need for her project? Mixed number
The distance between Town P and Town Q is 237.5 Km. At 11.30 a.m a van travels from
Town P to Town Q at an average speed of 35 km/h. At the same time, a car travels from
Town Q to Town P along the same route at an average speed of 60 km/h.
a)At what time will the vehicles meet on the way?
b) How far will each vehicle have travelled when they meet?
Answer:
So when the two vehicles meet, the van has travelled 87.5 km and the car has travelled 150 km.
Step-by-step explanation:
(a) Let's call the time it takes for the two vehicles to meet "t". We know that the distance between the two towns is 237.5 km, and the combined speed of the two vehicles is 35 km/h + 60 km/h = 95 km/h. Using the formula distance = speed × time:
237.5 = 95t
Solving for t:
t = 237.5/95
t ≈ 2.5 hours
So the two vehicles will meet on the way 2.5 hours after 11.30 a.m., which is at 2.00 p.m.
(b) To find how far each vehicle has traveled when they meet, we can use the formula distance = speed × time again. The van travels at 35 km/h for 2.5 hours, so it travels:
distance = speed × time = 35 km/h × 2.5 hours = 87.5 km
The car travels at 60 km/h for 2.5 hours, so it travels:
distance = speed × time = 60 km/h × 2.5 hours = 150 km
So when the two vehicles meet, the van has traveled 87.5 km and the car has traveled 150 km.
Find the slope of the line represented
by the data below.
x 2 4 6 8
-3 39
3
9 15
y|-3
Simplify completely.
Slope = [?
Hint: The slope of a line is the
Change in y
Change in x
A recursive rule for a geometric sequence is a1=
4
9
;an=3an−1.
What is the explicit rule for this sequence?
ANSWER:
4
9
(3n−1) just took the test
The explicit rule for the geometric sequence with a recursive rule of a1=4/9 and an=3an-1 is: an = (4/9) * (3)^(n-1)
What is the explicit rule for this sequence?To find the explicit rule for a geometric sequence, we use the formula:
an = a1 * r^(n-1)
where a1 is the first term, r is the common ratio, and n is the term number.
Given the recursive rule for this geometric sequence as a1=4/9 and an=3an-1, we can find the common ratio:
an = 3an-1
an/an-1 = 3/1
r = 3
Now we can use the formula to find the explicit rule:
an = a1 * r^(n-1)
an = (4/9) * (3)^(n-1)
Therefore, the explicit rule is: an = (4/9) * (3)^(n-1)
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help please
The half-life of Radium-226 is 1590 years. If a sample contains 500 mg, how many mg will remain after 1000 years? -----------
after 1000 years, there will be approximately 218.7 mg of Radium-226 remaining in the sample. use formula for radioactive decay to solve
what is radioactive decay ?
Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation, such as alpha particles, beta particles, and gamma rays. The decay occurs in order to achieve a more stable configuration of the nucleus.
In the given question,
The formula for radioactive decay is:
N(t) = N0 * (1/2)ᵃ⁾ᵇ
where:
N(t) is the amount of radioactive material at time t
N0 is the initial amount of radioactive material
t is the time elapsed since the initial measurement
T is the half-life of the radioactive material
We can use this formula to solve the problem as follows:
N0 = 500 mg (the initial amount)
T = 1590 years (the half-life)
t = 1000 years (the time elapsed)
N(t) = 500 * (1/2)¹⁰⁰⁰⁾ ¹⁵⁹⁰
N(t) = 500 * 0.4374
N(t) = 218.7 mg
Therefore, after 1000 years, there will be approximately 218.7 mg of Radium-226 remaining in the sample.
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pleaseeeee i need helppp in this
The resulting matrix formed by performing R2 -> 4R1 + R2 on M is given as follows:
[tex]M = \left[\begin{array}{ccc}-4&3&1\\-18&9&8\end{array}\right][/tex]
How to do the row operation?The matrix in the context of this problem is defined as follows:
[tex]M = \left[\begin{array}{ccc}-4&3&1\\-2&-3&r\end{array}\right][/tex]
The rows of the matrix are given as follows:
R1: -4, 3 and 1.R2: -2, -3 and 4.Hence the row 2 of the resulting matrix has the elements given as follows:
Column 1: 4 x -4 - 2 = -18.Column 2: 4 x 3 - 3 = 9.Column 3: 4 x 1 + 4 = 8.More can be learned about operations with matrices at brainly.com/question/16901354
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Construct a 90 % confidence interval of the population proportion using the given information.
x = 105 n =150
The 90% confidence interval based on the data provided will be (0.6152, 0.7848)
How to calculate the confidence intervalIt should be noted that standard error = ✓[(p * q) / n]
p = population proportion
q = 1 - p
n = sample size
sample proportion = x / n = 105 / 150 = 0.7
standard error = ✓(p * q) / n] = sqrt[(0.7 * 0.3) / 150] = 0.0516
margin of error = 1.645 * 0.0516 = 0.0848
Confidence interval = sample proportion ± margin of error
= 0.7 ± 0.0848
= (0.6152, 0.7848)
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What is the value of X? (Thx for any help!)
Answer:
x=109 y=100
Step-by-step explanation:
Answer:
x=100
y=109
Step-by-step explanation:
For any quadrilateral (4-sided shape) inscribed in a circle (all 4 vertices of the quadrilateral are on the edge of the circle), there is a special relationship between certain pairs of angles within the quadrilateral.
Specifically, opposite angles (angles across from each other) must sum (add) to 180 degrees.
The angle measuring 80 degrees is opposite the angle measuring x degrees, so x + 80 = 180, implying x = 100.
In this case, the angle measuring 71 degrees is opposite the angle measuring y degrees. So, 71 + y = 180, which implies y = 109.
Which of the following pairs consists of equivalent fractions? 3/9 and 5/15 ,12/20 and 20/25,5/6 and 6/5,6/12 and3/4
Answer:
[tex]The[/tex] [tex]Answer[/tex] [tex]Is:[/tex] [tex]\frac{3}{9}[/tex] [tex]&[/tex]& [tex]\frac{5}{15}[/tex]
Step-by-step explanation:
Divide by 4 , 2nd fraction Divide by 5:
3/4 ≠ 4/5
5/6 ≠ 6/5 We can already see it.
Divide by 3. . .
2/4 ≠ 3/4
Divide by 3 , 2nd fraction Divide by 5:
1/3 = 1/3 [tex]Perfect![/tex]
The answer is, [tex]\frac{3}{9}[/tex] & [tex]\frac{5}{15}[/tex]
A sample of 500 high schools in a state results in an average number of students per grade level of 178.6 students, with a margin of error of ±45.2. If there are 3250 high schools in the state, what is the estimated number of students per grade level?
between
and
students
The estimated number of students per grade level in the state is between 66,700 and 112,800 students, with an estimated total of 580,450 students.
The anticipated number of students in line with grade level within the state is between:
(178.6 - 45.2) x 500 = 66,700 students
and
(178.6 + 45.2) x 500 = 112,800 students.
This is the range of values that we can be 95% confident includes the actual average number of students according to grade degree within the state, based on the sample of 500 high schools and the margin of mistakes of ±45.2.
To estimate the whole number of students according to grade level in the state, we can multiply the anticipated average with the aid of the total number of high schools:
3250 x 178.6 = 580,450 students
Consequently, the estimated number of students per grade level in the state is between 66,700 and 112,800 students, with an estimated total of 580,450 students.
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Suppose a normal distribution has a mean of 34 and a standard deviation of
2. What is the probability that a data value is between 30 and 36? Round your
answer to the nearest tenth of a percent.
Answer:
it’s 86.6%
Step-by-step explanation:
could be wrong
Find the surface area of the triangular prism. A triangular prism. The base is a right triangle with base and height 4 millimeters, and the third side 5.7 millimeters. The height of the prism is 3 millimeters.
The surface area of the triangular prism is approximately 44.29 square millimeters.
What is surface area?
Surface area is the total area that the surface of a three-dimensional object covers. It is a measure of the amount of space that the surface of an object occupies. Surface area is usually measured in square units such as square meters, square centimeters, square inches, or square feet.
What is the area?
The total space occupied by a flat (2-D) surface or the shape of an object is defined as its area.
The area of a plane figure is the space enclosed by its boundary.
According to the given information:
To find the surface area of a triangular prism, we need to add up the area of all the faces. A triangular prism has three rectangular faces and two triangular faces.
Let's start by finding the area of the triangular faces. The base of the triangular prism is a right triangle with base 4 millimeters, height 4 millimeters, and hypotenuse 5.7 millimeters. We can use the Pythagorean theorem to find the missing side:
[tex]a^2 + b^2 = c^2\\4^2 + 4^2 = 5.7^2[/tex]
16 + 16 = 32.49
32 = 32.49 - 0.49
32 = 32
So the missing side has length [tex]\sqrt{(5.7^2 - 4^2)} =3.69 millimeters.[/tex] This is the base of each triangular face.
The height of the triangular prism is 3 millimeters, so the height of each triangular face is also 3 millimeters.
The area of each triangular face is:
(1/2) × base × height
= (1/2) × 3.69 × 3
≈ 5.54 square millimeters
So the total area of the two triangular faces is:
2 × 5.54= 11.08 square millimeters
Now let's find the area of each rectangular face. The length of each rectangular face is the same as the base of the triangular face, which is 3.69 millimeters. The width of each rectangular face is the height of the triangular prism, which is 3 millimeters.
The area of each rectangular face is:
length × width
= 3.69 × 3
≈ 11.07 square millimeters
So the total area of the three rectangular faces is:
3 × 11.07
= 33.21 square millimeters
To find the surface area of the triangular prism, we add up the area of all five faces:
11.08 + 33.21
= 44.29 square millimeters
Therefore, the surface area of the triangular prism is approximately 44.29 square millimeters.
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PLEASE SOMEONE !! 15 POINTS!!!
Answer:
The answer is -5
Step-by-step explanation:
Each number moves down 5 as it moves to the right 1. Right is positive, and down is negative. -5 divided by 1 is -5.
y=7x-3 what slope and y intercept
Answer:
Slope = 14.000/2.000 = 7.000 x-intercept = 3/7 = 0.42857 y-intercept = -3/1 = -3.00000
y intercept = -3
slope = 7/1
need help with this geometry problem
The shaded area of the circle is around 65.44 square meters in size.
How to find area?To find the area of the shaded region, subtract the area of sector FGH from the area of sector FEGH.
The area of sector FEGH is:
A1 = (1/2) r² θ₁
where r = radius of the larger circle and θ₁ = angle subtended by the arc EH.
Since EH = 30 m and the radius of the larger circle = 18 m (half of 10 + 8):
θ₁ = (EH arc length) / r = 30/18π radians
So,
A₁ = (1/2) (18)² (30/18π) = 270/π m²
The area of sector FGH is:
A₂ = (1/2) r² θ₂
where θ₂ = angle subtended by the arc GH.
Since GH is 8 m and the radius of the larger circle is 18 m:
θ2 = (GH arc length) / r = 8/18π radians
So,
A₂ = (1/2) (18)² (8/18π) = 64/π m²
Therefore, the area of the shaded region is:
A = A₁ - A₂ = (270/π) - (64/π) = 206/π ≈ 65.44 m²
Hence, the area of the shaded region is approximately 65.44 square meters.
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Solve for the missing angle measurements for angles a, b, c, and d
Note that the angle measurements are given as follows:
A = 145° (Sum of angles on a straight line.
B = 35° Opposite angles
C = 145° Opposite angels
D) = 35° supplementary angels.
What is the explanation of the above statements?a) Note that Sum of angles on a straight line=180° and are therefore supplementary
b) All opposite angle are equal, since ∠b is opposite to 35°, then ∠b = 35°
c) 145° is also opposite to ∠c
d) when two angles are supplementary, it means that they sum up to 180°
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Full Question:
Solve for the missing angle measurements for angles a, b, c, and d
See the attached imge
A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took
13.5
m
2
13.5 m
2
13, point, 5, start text, space, m, end text, squared of material to build the cube.
What is the volume inside the giant sugar cube?
Give an exact answer (do not round).
The volume of the inside of the giant sugar cube would be = 3.375cm³
How to calculate the volume of a cube using the given surface area?To calculate the volume of a cube, the side length should first be determined from the surface area given.
But the formula for surface area of a cube = 6a²
That is;
surface area = 13.5cm²
a = ?
13.5 = 6(a)²
13.5/6 = a²
a = √13.5/6
= √2.25
= 1.5cm
Therefore the volume of the cube = a³
= 1.5³
= 3.375cm³
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Complete question:
A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took 13.5m² of material to build the cube. What is the volume inside the giant sugar cube? Give an exact answer (do not round).
Solve for x. Round to the nearest tenth, if necessary.
Answer:
160
Step-by-step explanation:
The cosine is equal to the adjacent side divided by the hypotenuse (adj/hyp)
Adjacent = 80
Hypotenuse = x
therefore, cos(60) = 80/x
1/2 = 80/x
x = 80 x 2 = 160
Suppose that the functions q and r are defined as follows.
Answer:
Step-by-step explanation:
Given:
q(x) = -3x+4
r(x) = -4x
(r₀q)(4) => r(q(4)) solve for q(4) first
q(4) = -3(4)+4 > substitute 4 in for x
q(4) = -12 +4
q(4) = -8 > now substitute this into r(q(4))
r(-8) = -4(-8) > substitute -8 in for x
r(-8) = 32
(r₀q)(4) = 32
(q₀r)(4) => q(r(4)) solve for r(4) first
r(4) = -4(4) > substitute 4 for x
r(4) =-16 > substitute this into q(x)
q(-16) = -3(-16)+4
q(-16) = 48 +4
q(-16) = 52
(q₀r)(4) = 52
Enter your answer by filling in the boxes.
The correct statement regarding the end behavior of the function is given as follows:
As x -> -∞, f(x) -> +∞.As x -> +∞, f(x) -> +∞.What is the end behavior of a function?The end behavior of a function refers to how the function behaves as the input variable approaches positive or negative infinity.
The function in this problem is given as follows:
f(x) = 2(x - 4)² + 3.
We have the square of a number, which is always positive, hence the function goes to positive infinity when the input goes to negative infinity/positive infinity.
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Before a basketball game, a referee noticed the ball had been deflated. She dropped it from 6 feet and measured the first bounce at 36 inches and the second bounce at 18 inches.
a) write an exponential equation to model the height of the ball.
b)How high was the ball on the fifth bounce?
Therefore , the solution of the given problem of equation comes out to be the ball is 2.25 inches tall after the fifth bounce.
What is an equation?In order to demonstrate consistency between two opposing statements, variable words are frequently used in sophisticated algorithms. Equations are academic phrases that are used to demonstrate the equality of different academic figures. Consider expression the details as y + 7 offers. In this case, elevating produces b + 7 when partnered with building y + 7.
Here,
a)
We are aware that the ball was dropped from a height of 6 feet, or 72 inches, and that it bounced twice, the first time for 36 inches and the second time for 18 inches. We can thus write:
=> a = 72 (the initial height)
=> B = (height of previous bounce minus height of each subsequent bounce) = 18/36 = 1/2
As a result, the following exponential equation can be used to predict the ball's height:
=> y = 72*(1/2)ˣ
b) We enter x = 5 into the equation we derived in part a) to determine the height of the ball on the fifth bounce:
=> y = 72*(1/2)⁵
=> y = 72*(1/32)
=> 2.25 inches for y.
As a result, the ball is 2.25 inches tall after the fifth bounce.
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Please if you know the answer put the steps on thank you.
Answer:
1. # of people who predicted they would pass = 30
2. # of people who predicted they would fail = 20
3. # of people who predicted they would pass and actually passed = 27
4. # of people who predicted they would pass and actually failed = 3
5. # of people who predicted they would fail and actually passed = 11
6. # of people who predicted they would fail and actually failed = 9
Step-by-step explanation:
1. # of people who predicted they would
The total number of people who took the test is 50.The number of people who predicted they would pass is 30.The number of people who predicted they would fail is 20 (since 50 - 30 = 20)Let x be the number of people who predicted fail and actually passed the test. Since three times as many people who passed predicted pass than predicted fail, we know that 3x is the number of people who predicted pass and actually passed the test. Therefore, the total number of people who passed the test is x + 3x = 4x, and we know that 36 people passed the test, so 4x = 36, and x = 9.Since x is the number of people who predicted fail and actually passed the test, then the number of people who predicted fail and actually failed the test is 20 - x = 20 - 9 = 11.The number of people who predicted pass and actually passed the test is 3x = 3(9) = 27.The number of people who predicted pass and actually failed the test is 30 - 27 = 3.I also filled in the frequency table by extracting it from Brainly and drawing on it to show how the math works and fits in the table.
Suppose that the readings on the thermometers are normally distributed with a mean of 0∘ and a standard deviation of 1.00∘C.
If 12% of the thermometers are rejected because they have readings that are too high, but all other thermometers are acceptable, find the reading that separates the rejected thermometers from the others.
The reading that separates the rejected thermometers from the others is given as follows:
1.175 ºC.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution of the data-set, depending if the obtained z-score is positive(above the mean) or negative(below the mean).The z-score table is used to obtain the p-value of the z-score, and it represents the percentile of the measure X in the distribution.The mean and the standard deviation for this problem are given as follows:
[tex]\mu = 0, \sigma = 1[/tex]
The 12% higher of temperatures are rejected, hence the 88th percentile is the value of interest, which is X when Z = 1.175.
Hence:
1.175 = X/1
X = 1.175 ºC.
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Twenty middle-aged men with glucose readings between 90 milligrams per deciliter and 120 milligrams per deciliter of blood were selected randomly from the population of similar male patients at a large local hospital. Ten of the 20 men were assigned randomly to group A and received a placebo. The other 10 men were assigned to group B and received a new glucose drug. After two months, posttreatment glucose readings were taken for all 20 men and were compared with pretreatment readings. The reduction in glucose level (Pretreatment reading − Posttreatment reading) for each man in the study is shown here.
Group A (placebo) reduction (in milligrams per deciliter): 12, 8, 17, 7, 20, 2, 5, 9, 12, 6
Group B (glucose drug) reduction (in milligrams per deciliter): 29, 31, 13, 19, 21, 5, 24, 12, 8, 21
Create and interpret a 98% confidence interval for the difference in the placebo and the new drug. (10 points)
A: The data provides convincing evidence, at α=0.02 level, that the glucose drug is effective in reducing mean glucose level.
B: The 98% confidence interval for the difference in mean reduction of glucose level between placebo and drug groups is 3.5 to 13.7 mg/dL, supporting the effectiveness of the glucose drug
A: To test whether the glucose drug is effective in producing a reduction in mean glucose level, we will use a two-sample t-test with equal variances assuming normality of the differences.
Let μA be the true mean reduction in glucose level for the placebo group and μB be the true mean reduction in glucose level for the glucose drug group. The null hypothesis is H0: μA - μB = 0, and the alternative hypothesis is Ha: μA - μB < 0
Using the given data, the sample mean reduction for the placebo group is 9.7 mg/dL and for the glucose drug group is 18.3 mg/dL. The pooled sample standard deviation is 8.064 mg/dL, and the t-statistic is calculated to be:
t = (xB - xA) / (sP × √(1/nA + 1/nB))
= (18.3 - 9.7) / (8.064 × √(1/10 + 1/10))
= 2.551
where xA and xB are the sample means, sP is the pooled sample standard deviation, and nA and nB are the sample sizes.
B: To create a 98% confidence interval for the difference in the placebo and the new drug, we will use the formula:
CI = (xB - xA) ± tα/2,sP × √(1/nA + 1/nB)
where xA and xB are the sample means, sP is the pooled sample standard deviation, nA and nB are the sample sizes, and tα/2,sP is the t-value corresponding to a 98% confidence level with 18 degrees of freedom.
Using the values from Part A, we have:
CI = (18.3 - 9.7) ± 2.101 × 8.064 × √(1/10 + 1/10)
= 8.6 ± 5.103
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The correct question is:
Twenty middle-aged men with glucose readings between 90 milligrams per deciliter and 120 milligrams per deciliter of blood were selected randomly from the population of similar male patients at a large local hospital. Ten of the 20 men were assigned randomly to group A and received a placebo. The other 10 men were assigned to group B and received a new glucose drug. After two months, posttreatment glucose readings were taken for all 20 men and were compared with pretreatment readings. The reduction in glucose level (Pretreatment reading − Posttreatment reading) for each man in the study is shown here.
Group A (placebo) reduction (in milligrams per deciliter): 12, 8, 17, 7, 20, 2, 5, 9, 12, 6
Group B (glucose drug) reduction (in milligrams per deciliter): 29, 31, 13, 19, 21, 5, 24, 12, 8, 21
Part A: Do the data provide convincing evidence, at the α = 0.02 level, that the glucose drug is effective in producing a reduction in mean glucose level?
Part B: Create and interpret a 98% confidence interval for the difference in the placebo and the new drug.
