when 3000 grams of water is cooled from 80.0 c to 10.0 c, how much energy is released

Answers

Answer 1

Answer:

877800 Joules of energy is released

Explanation:

mass m = 3000 g

initial temperature = 80 c

Final temperature = 10 c

Change in temperature ΔT = 80 - 10 = 70 c

Heat H = ?

The relationship between these parameters is given by;

H = mcΔT

Where c = specific heat capacity = 4.18 J/gc

H = 3000 * 4.18 * 70 = 877800 Joules


Related Questions

Which step of mitosis involves the nucleus spitting and nuclear membranes forming around each new nucleus??

Answers

Answer:

telophase

Explanation:

How many lbs are in 5 kilograms

Answers

Answer:

There are approximately 11.0231 pounds in a kilogram

Which statement describes the effect of sorting and recombining genes in sexual reproduction?

Group of answer choices

offspring receive only recessive genes

offspring receive only dominant genes

offspring receive the same set of genes

offspring receive a unique combination of genes

Answers

The fourth option I think

how should the following italicized statement be taken??? elements can be broken further into simpler substances.
a. true
b. false​.

Answers

Answer:

false

Explanation:

Elements cannot be broken down into a simpler substance.

I think it’s false. Hope that helps!

When aqueous solutions of AgNO3 and KI are mixed, AgI precipitates. The balanced net ionic equation is ________. When aqueous solutions of AgNO3 and KI are mixed, AgI precipitates. The balanced net ionic equation is ________. AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq) Ag+ (aq) + I- (aq) → AgI (s) AgNO3 (aq) + KI (aq) → AgI (aq) + KNO3 (s) Ag+ (aq) + NO3 - (aq) → AgNO3 (aq) Ag+ (aq) + NO3 - (aq) → AgNO3 (s)

Answers

Answer:

Ag⁺ (aq) + I¯ (aq) —> AgI (s)

Explanation:

We'll begin by writing the dissociation equation for aqueous AgNO₃ and KI.

Aqueous AgNO₃ and KI will dissociate in solution as follow:

AgNO₃ (aq) —> Ag⁺(aq) + NO₃¯ (aq)

KI (aq) —> K⁺(aq) + I¯(aq)

Aqueous AgNO₃ and KI will react as follow:

AgNO₃ (aq) + KI (aq) —>

Ag⁺(aq) + NO₃¯ (aq) + K⁺ (aq) + I¯(aq) —> AgI (s) + K⁺ (aq) + NO₃¯ (aq)

Cancel out the spectator ions (i.e ions that appears on both sides of the equation) to obtain the net ionic equation. The spectator ions are K⁺ and NO₃¯.

Thus, the net ionic equation is:

Ag⁺ (aq) + I¯ (aq) —> AgI (s)

The net ionic equation of aqueous solutions of [tex]AgNO_3[/tex] and [tex]KI[/tex] to form [tex]AgI[/tex] precipitates is: B. [tex]Ag^{+}_{(aq)} + I^{-}_{(aq)}[/tex] -----> [tex]AgI_{(s)}[/tex]

A balanced chemical equation can be defined as a chemical equation wherein the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

This ultimately implies that, both the charge on each atom and sum of the masses of the chemical compounds or elements in a chemical equation are properly balanced.

An ion can be defined as an atom or molecules (group of atoms) that has lost or gained one or more of its valence electrons, thereby, making it have a net positive or negative electrical charge.

First of all, we would write the dissociation equation for aqueous solutions of [tex]AgNO_3[/tex] and [tex]KI[/tex]:

For [tex]AgNO_3[/tex]:

[tex]AgNO_3_{(aq)}[/tex] -----> [tex]Ag^{+}_{(aq)} + NO_{3}^{-}_{(aq)}[/tex]

For [tex]KI[/tex]:

[tex]KI_{(aq)}[/tex] -----> [tex]K^{+}_{(aq)} + I^{-}_{(aq)}[/tex]

Next, we would write a chemical equation for the reaction of aqueous solutions of [tex]AgNO_3[/tex] and [tex]KI[/tex]:

[tex]AgNO_3_{(aq)} + KI_{(aq)}[/tex]  -----> [tex]Ag^{+}_{(aq)} + NO_{3}^{-}_{(aq)}[/tex] [tex]+ \;K^{+}_{(aq)} + I^{-}_{(aq)}[/tex] ----->[tex]AgI_{(s)} + K^{+}_{(aq)} + NO_{3}^{-}_{(aq)}[/tex]

Note: Spectator ions refers to the ions that exist as a reactant and a product in a chemical equation because they are unchanged by the chemical reaction.

In this chemical reaction, the spectator ions are:

[tex]K^+[/tex][tex]NO_{3}^{-}[/tex]

Finally, in order to obtain the net ionic equation, we would cancel out the two (2) spectator ions:

[tex]Ag^{+}_{(aq)} + I^{-}_{(aq)}[/tex] -----> [tex]AgI_{(s)}[/tex]

Read more: https://brainly.com/question/13750908

A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbon dioxide gas and water vapor. Calculate the moles of octane needed to produce 1.4mol of water. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits. 1.8mol

Answers

Answer:

0.2 moles of octane

Explanation:

The equation of the reaction is;

C8H18(g) + 25/2 O2(g) ------> 8CO2(g) + 9H2O(l)

From the equation;

1 mole of octane yields 9 moles of water

x moles of octane yields 1.4 moles of water

x= 1.4 × 1/9

x= 0.16 moles of octane

For many years, experiments showed that light had wave-like properties. For this reason, scientists described light

as a wave. More recently, experiments produced data that could not be explained by the wave theory of light. The

idea of particle properties was introduced

Why did the theory of light change over time?

O The theory was too old and needed to be updated

New scientists did not agree with the older theory

O The scientific question changed, so the theory had to change.

O Repeated experimentation introduced new discoveries.

Answers

Answer:

Repeated experimentation introduced new discoveries.

Explanation:

Science is not a static body of  knowledge, scientific theories change as new evidence emerges from repeated experiments.

For many years, the wave theory of light was generally held by almost all scientists.

Further experiments such as photoelectric effect and Compton effect lent credence to the the particle theory of light, hence the answer

Answer:

D

Explanation:

Repeated experimentation introduced new discoveries.

helpppp me asap please help me asap please

If theoretical mass of CH3OH produced in the reaction below was 85.3grams, and the actual mass produced during the experiment was 80.1 gA. Calculate the percent yield of this reaction. B. Give one reason why the numbers are different. COfg) + 2 H2(g) -> CH;OH(I)​

Answers

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HELP FAST PLZ!!!!! Which phase change allows a substance to transform from a liquid to a
gas?
melting
Ofreezing
O ionization
condensation
deionization
O
evaporation
sublimation

Answers

Answer:evaporation

Explanation:

Answer:

Pretty sure its evaporation, if its not I'm very sorry.

Research Hypatia's achievements in the world

of science.

What is she most known for?

Write down three interesting facts about her

life.

Answers

Answer:

See explanation

Explanation:

Hypatia is popular for her work in mathematics. She also did some work in the area of astronomy. Her well know work in mathematics is her ideas about conic sections.

She was born the Theon of Alexandria and she was a professional mathematician in her life time.

She was the greatest mathematician of her time and she was telling leader of the Neoplatonist school of philosophy in Alexandria. By so doing, she conquered the culture of sexism in her time.

She was trained by her father in mathematics and eventually replaced him. She was the last major mathematician in the Alexandrian tradition.

Quickly please! Which is a group of tissues that work together to carry out a common function?

cell
organ
organelle
organ system

Answers

Answer:

organ system

Explanation:

Answer:

B) organ

Explanation:

Calculate the pH of a 0.46 M solution of NH 4Cl. ( K b for NH 3 = 1.8 × 10 –5)
a.
9.59
b.
4.41
c.
4.80
d.
0.34
e.
9.20

Answers

pH of the solution = 4.8

Further explanation  

NH₄Cl is a salt of a weak base and a strong acid so that it will be partially hydrolyzed

Reaction:

NH₄Cl -----> NH₄⁺ + Cl⁻

NH₄ will be hydrolyzed in water

NH₄⁺ + H₂O ------> NH₃ + H₃O⁺ (H⁺)

This solution releases H⁺ ions so they are acidic

Formula

[tex]\tt [H^+]=\sqrt{\dfrac{Kw}{Kb}.M }[/tex]

Kw = The water equilibrium constant  = 10⁻¹⁴

Kb = the ionization constant of a base = 1.8.10⁻⁵

M = 0.46

[tex]\tt [H^+]=\sqrt{\dfrac{10^{-14}}{1.8.10^{-5}}\times 0.46 }[/tex]

[H+]=√2.55 x 10⁻¹⁰ = 1.599 x 10⁻⁵

pH = - log [H+]

pH = 5-log 1.599 = 4.796≈ 4.8

How many valence electrons must a lithium atom lose to obtain a complete valence shell?
A. one
B. two
C. three
D. four

Answers

Answer:

C. three

Explanation:

Liz and Michelle are testing which ball will bounce the highest. They test 4 different balls. Each ball is dropped five times from the same height. The height of the bounce is measured. At the end of the experiment, the data for each ball was averaged to obtain an average bounce height.

Is this a well designed experiment?

A) No, it does not give any data.

B) No, they should have used more types of balls.

C) Yes, they tested more than one thing at a time.

D) Yes, they averaged the measurements and had multiple trials.

Answers

Answer:

D

Explanation:,

In designing an experiment there must be multiple trials. Multiple trials eliminate errors when the results are averaged.

This gives better results than when single measurements are used to determine results of experiments. The result of this experiment can be regarded as being reliable because it was well designed.

Does Sodium Chloride, have the same properties as sodium and chlorine

Answers

The answer is:
No they have different properties

5. What would be the temperature change if 12.5 g of water absorbed 35 J of heat?

Answers

Explanation:

its 399929939932929292

pentane or 2,2,3- trimethylhexane has the higher boiling point. why?​

Answers

Answer:

2,2,3- trimethylhexane because it has more carbon atoms than pentane.

Explanation:

Hello.

In this case, since the physical properties of organic compounds are intensified as the number of carbon atoms start increasing on it, the larger the amount of carbon atom, the higher the boiling point since more energy is required to allow the liquid-phase molecules to transcend to the vapor-phase.

In such a way, since pentane has five carbon atoms and 2,2,3- trimethylhexane has nine carbon atoms, 2,2,3- trimethylhexane has the highest boiling point.

Best regards.

The escape velocity from Earth’s surface is 1.12*10^4 meters per second. At this speed, how many kilometers would a rocket travel in 3 minutes

Answers

Answer:

2016 Km.

Explanation:

The following data were obtained from the question:

Speed (S) = 1.12×10⁴ m/s

Time (t) = 3 mins

Distance (d) =.?

Next, we shall convert 3 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

3 mins = 3 min × 60 s / 1 min

3 mins = 180 s

Next, we shall determine the distance travelled by the rocket. This is illustrated below:

Speed (S) = 1.12×10⁴ m/s

Time (t) = 180 s

Distance (d) =.?

Speed (S) = distance (d) /time (t)

S = d/t

1.12×10⁴ = d/ 180

Cross multiply

d = 1.12×10⁴ × 180

d = 2016000 m

Finally, we shall convert 2016000 m to Km. This can be obtained as shown below:

1000 m = 1 Km

Therefore,

2016000 m = 2016000 m × 1 Km / 1000 m

2016000 m = 2016 Km

Therefore, the rocket will travel 2016 Km in 3 mins

Find ΔHrxn for the following reaction:

2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)

Answers

Answer:

ΔH°rxn = -827.5 kJ

Explanation:

Let's consider the following balanced equation.

2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)

We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]

ΔH°rxn = -827.5 kJ

The standard enthalpy of the reaction is -827.5 kJ/mol

The standard enthalpy of reaction [tex]\mathbf{\Delta H^0_{rxn}}[/tex] is the enthalpy change that happens in a system whenever one mole of the matter is converted through a chemical process under normal conditions.

The given reaction can be expressed as:

2PbS(s) + 3O₂(g) → 2PbO(s) + 2SO₂(g)

The standard enthalpy can be represented by the equation:

[tex]\mathbf{\Delta H^0_{rxn} = \sum \Delta _f ^0(products) - \sum \Delta _f^0(reactants)}[/tex]

At standard conditions, the standard enthalpies of formation of the given species are:

ΔH°f(PbO(s)) = 219 kJ/molΔH°f(SO₂(g)) = -296.83 kJ/molΔH°f(PbS(s))  = 100.4 kJ/molΔH°f(O₂(g)) = 0 kJ/mol

 

[tex]\mathbf{ \Delta H^0_{rxn} = \Big[2 mol \times \Delta H^0_f(PbO(s)) + 2 mol \times \Delta H^0_ f(SO_2(g) )\Big] - \Big[2 mol \times \Delta H^0_f (PbS(s))} + \mathbf{ 3 mol \times \Delta H^0_f(O_2(g) )\Big] }}[/tex]

 

[tex]\mathbf{\Delta H^0rxn = [2 mol \times (-217.32 kJ/mol) + 2 mol \times (-296.83)] - [2 mol \times (-100.4)} \\ \mathbf{+ 3 mol \times 0 kJ/mol]}}[/tex]

[tex]\mathbf{\Delta H^0rxn = -827.5 \ kJ/mol}}[/tex]

Therefore, we can conclude that the standard enthalpy of the reaction is -827.5 kJ/mol

Learn more about standard enthalpy of the reaction here:

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What two types of elements make up an Ionic bond ?

Answers

Answer:

Metals and Non-metals

Explanation:

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

Answers

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

[tex]2SO_2 + O_2 \to 2SO_3[/tex]

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction [tex]2SO_2 + O_2 \to 2SO_3[/tex] = 0.8325;

If we want to find:

[tex]SO_2 + \dfrac{1}{2}O_2 \to SO_3[/tex]

Then:

[tex]K_c = (0.8325)^{1/2}[/tex]

[tex]\mathbf{K_c = 0.912}[/tex]

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

1. Which statement is true about oxygen,
sulfur, and selenium? scap.8.0
^ They belong to the same group.
© They belong to the same period.
The mass number doubles between each
element.
0 The atomic number increases by eight
between each clement,

Answers

Answer:

they belong to same grop

A negatively charged rod is placed near two neutral metal spheres, as shown below. Which statement describes the charging method shown? The spheres are charged through friction. The spheres develop the same charge. Electrons move from the rod to Sphere A. Electrons move from Sphere A to Sphere B.

Answers

Answer:

D. Electrons move from Sphere A to Sphere B.

Explanation:

The statement that best describes the charging method is "Electrons move from Sphere A to Sphere B". This is further explained below.

What is Charge?

A charge is simply defined as the property of a unit of matter that expresses how many more or fewer electrons it has than protons.

In conclusion, For a negatively charged rod placed near two neutral metal spheres, electrons move from Sphere A to Sphere B.

Read more about Charge

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Which element forms a cation?
A. gold
B. phosphorus
C. fluorine
D. nitrogen

Answers

Answer:

gold

Explanation:

Cations are positively charged, so the element that loses electrons to have the same amount of electrons as a noble gas atom is gold.

What is the relationship between the specific rotation of (2S ,3S)-dibromopentane and (2R, 3R)-dibromopentane?
A) It is different in magnitude and opposite in sign
B) it is equal in magnitude and have the same sign
C) it is zero
D) it is equal in magnitude but opposite in sign
E) It is not possible to predict the specific rotation

Answers

Answer:

D) it is equal in magnitude but opposite in sign

Explanation:

The compounds (2S ,3S)-dibromopentane and (2R, 3R)-dibromopentane are a pair of enantiomers.

Enantiomers are stereoisomers that that are mirror images of each other and rotate plane polarized light. The magnitude of rotation of plane polarized light is known as specific rotation of the compound measured in degrees.

Enantiomers have the same magnitude of specific rotation but opposite in sign. This is  because one enantiomer rotates plane polarized light to the left while the other rotates plane polarized light to the right.

The amount of UVA radiation hitting a surface at sea level in a lightly clouded day is about 70W/m2. About half of that can be absorbed by the skin. A typical carbon- carbon bond requires 348 kJ/mol to break. A person lies on the beach for about 1 hour without sunscreen (i.e. fully exposed to UVA radiation). Estimate the number of C-C bonds broken in this person’s back (about 0.18 m2) over that period. Assume that the average wavelength of UVA is 335 nm.

Answers

Answer:

Explanation:

energy of solar radiation = 70 W / m²

energy absorbed in 1 hour by an area of .18 m²

= 70 x .5 x .18 x 60 x 60 J

= 22.68 x 10³ J

bond energy of i mole bond = 348 x 10³ J

bond energy of 6.02 x 10²³ bonds = 348 x 10³  J

bond energy of one bond = 57.8 x 10⁻²⁰ J  

No of bonds broken by energy 22.68 x 10³

= 22.68 x 10³  / 57.8 x 10⁻²⁰

= .3923 x 10²³

= 39.23 x 10²⁰ .

2. Determine the possible traits of the calves of : Da red (RR) bull is mated with a red (RR) cow 1 a red * (RR) bullis mated with a white (WW) Cow 2 Da roan * (RW) is mated with a red(RR)Cow 3 3. Illustrate your answers using a Punnett square. 4. Write your answers on the paper.​

Answers

1st square - all 4 red babies
2nd square - all 4 roan babies
3rd square - 2 red, 2 roan babies

When 2.16g of H2 reacts with excess O2 by the following equation, 258 kJ of heat are released. What is the change of enthalpy associated with the reaction of 1.00 mol of hydrogen gas? 2H2+O2⟶2H2O

Answers

Answer:

-241 kJ/mol

Explanation:

Let's consider the reaction of hydrogen with excess oxygen to form water.

2 H₂ + O₂ ⟶ 2 H₂O

When 2.16g of hydrogen reacts with excess oxygen, 258 kJ of heat are released, that is, Q = -258 kJ. Considering that the molar mass of hydrogen is 2.02 g/mol, the change of enthalpy associated with the reaction of 1.00 mol of hydrogen gas is:

ΔH° = -258 kJ/2.16 g × (2.02 g/1.00 mol) = -241 kJ/mol

In an sp2 hybridized atom, we saw that there was one unhybridized 2p orbital. How many unhybridized 2p orbitals remain on an atom that has sp3 hybrid orbitals?
A. One.B. Two.C. Three.D. None.

Answers

Answer:

None

Explanation:

We must recall that the number of hybrid orbitals formed must be equal to the number of atomic orbitals that were combined. Hence, if we have an sp3 hybridized orbital, there are four hybrid orbitals formed.

Since there are four hybrid orbitals formed from the three p and one s orbital that combined, there is no unhybridized orbital left.

The number of unhybridized 2p orbitals that remains on an atom that has sp3 hybrid orbital is : ( D ) None

The hybridization of an s orbital with three p orbitals will yield four sp3 hybrid orbitals, which means that there will be no unhybridized 2p orbitals left.

This is because during the hybridization, the number of hybrid orbitals yielded must be equal to the combined number of atomic orbitals that yielded the Hybrid orbitals.

Hence we can conclude that the number of unhybridized 2p orbitals that remain on an atom that has sp3 hybrid orbital is zero ( None )

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What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters

Answers

Answer:

[tex]\boxed {\tt 1.0 \ g/mL}[/tex]

Explanation:

Density can be found by dividing the mass by the volume.

[tex]d=\frac{m}{v}[/tex]

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

[tex]m= 50.0\ g \\v=50.0 \ mL[/tex]

Substitute the values into the formula.

[tex]d=\frac{50.0 \ g}{50.0 \ mL}[/tex]

Divide.

[tex]d= 1.0 \ g/mL[/tex]

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

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