Which graph best matches a person walking away at a constant speed

Answer:

2Cr³⁺(aq) + 3S²⁻(aq) ----> Cr₂S₃(s)

Explanation:

When aqueous solutions of chromium(III) chloride and ammonium sulfide are  mixed together, chromium (III) chloride and ammonium sulfide undergoes a double displacement reaction to produce chromium (iii) sulphide as a precipitate and ammonium chloride which remains in solution.

The general equation of the reaction is given below:

2CrCl₃(aq) + 3(NH₄)₂S(aq) ----> Cr₂S₃(s) + 6NH₄Cl(aq)

The net equation of the reaction is given below:

2Cr³⁺(aq) + 3S²⁻(aq) ----> Cr₂S₃(s)

Answer:

From these two values, i.e. mass and volume, density of the copper cylinder can be calculated.

Formula of density is :

Density = Mass / volume.

Now we have mass: 53.76g and volume 6cm³

Density = 53.76 / 6

Density= 8.96 g/cm³

Answer:

Thus, at convergent boundaries, continental crust is created and oceanic crust is destroyed. Two plates sliding past each other forms a transform plate boundary. Natural or human-made structures that cross a transform boundary are offset—split into pieces and carried in opposite directions.

Explanation:

Answer:

Explanation:

From the given information;

the molecular molarity of the acid and  base are as follows:

For acid : 5 mL × 0.20 M = 0.1 mmol

For base: 5 mL × 0.20 M = 0.1 mmol

However;

0.05 m  × 1.0 M = 0.05 mmol of acid HCl

Similarly, When the acid undergoes reaction with the base; the amount of acid and base left are as follows:

Amount of acid left:

0.1 + 0.05 = 0.15 mmol

Amount of base left:

0.1 - 0.05 = 0.05 mmol

The formula for calculating the Buffer pH is:

[tex]pH = pka + log(\dfrac{Base}{Acid} )[/tex]

Recall that for Acetic, the acid dissociation constant = 4.74

Then:

[tex]pH =4.74+ log(\dfrac{0.05}{0.15} )[/tex]

[tex]pH =4.74+ log(0.333)[/tex]

pH = 4.74 -  0.4775

pH = 4.26

Therefore, the decrease in pH is about 0.48 units

Answer:

WCl₂, WCl₄, WCl₅, WCl₆

Explanation:

Molar Mass of Tungsten = 184 g/mol

Mass of Chlorine = 35.5 g/mol

In the first compound;

Percentage of tungsten = 72.17 %

Upon solving;

72.17 % = 184

100 % = Total mass

Total mass of compound = 254.95g

Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.

The Formular is WCl₂

In the second compound;

Percentage of tungsten = 56.45 %

Upon solving;

56.45 % = 184

100 % = Total mass

Total mass of compound = 325.95 g

Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.

The Formular is WCl₄

In the third compound;

Percentage of tungsten = 50.91 %

Upon solving;

50.91 % = 184

100 % = Total mass

Total mass of compound = 361.42 g

Mass of chlorine =  361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.

The Formular is WCl₅

In the fourth compound;

Percentage of tungsten = 46.39 %

Upon solving;

46.39 % = 184

100 % = Total mass

Total mass of compound = 396.64 g

Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.

The Formular is WCl₆

Answer: Wax

Explanation:

Density is defined as the mass contained per unit volume.

[tex]Density=\frac{mass}{Volume}[/tex]

Usually solids are more denser than liquid, as molecules in solid are more strongly packed and thus have more mass per unit volume.

Liquids on the other hand contain molecules which are less tightly bound and thus thus contain less mass per unit volume as compared to solid.

Example: Solid wax is more denser than liquid wax.

Answer:

Fe^2+(aq) = 4.51 × 10^-11 M

Fe3+(aq) = 1.79 × 10^5 M.

Explanation:

So, the first thing to do is to to write out the chemical reaction showing the ionic reaction of the chemical species present in the chemical reaction;

4Fe^2+ (aq) + O2(g) + 4H^+ <---------------------------> 4Fe^3+(aq) + 2H2O(l).

The next thing to do is to determine or calculate for G° and the equilibrium constant,kc. Thus, the value of G° = 4(-4.6) + 2(-237.18) - {4(-78.87)} = -177.28 kJ/mol.

Therefore, the equilibrium constant = e^-∆G°/RT = 1.19 × 10^31.

Therefore the value for Fe^2+ and Fe^3+ can be determine as;

NB=> Recall that [Fe^3+]/[Fe^2+] = kc [(Po2) (H^+)^4]^1/4.

Also, 1/ 55850 = 1.79 × 10^-5 M.

[Fe^2+] + [Fe^3+] = 1.79 × 10^-5. -------(1).

Therefore, [Fe^3+]/[Fe^2+] = kc [(Po2) (H^+)^4]^1/4. = [Fe^3+]/[Fe^2+] = [ 1.19 × 10^31 × 0.2095 × (10^2)^2] ^1/4 = 3.97 × 10^5.

Therefore, [Fe^3+]/[Fe^2+] = 3.97 × 10^5.

[Fe^3+] = 3.97 × 10^5[Fe^2+].

Hence, using the equation (1) above we can determine the value of the species.

[Fe^2+] + [Fe^3+] = 1.79 × 10^-5

[Fe^2+] + [Fe^2+] = 1.79 × 10^-5.

[Fe^2+] + 3.97 × 10^5[Fe^2+] = 1.79 × 10^-5.

[Fe^2+] = 4.51 × 10^-11 M.

Therefore, we will have [Fe^3+]/[Fe^2+] = 3.97 × 10^5.

Thus, [Fe^3+] = [Fe^2+] × 3.97 × 10^5. = 1.79 × 10^5 M.

Answer:

112.92 s.

Explanation:

Let M₁ be the molar mass of N₂O

Let t₁ be the time taken for N₂O to effuse.

Let M₂ be the molar mass of I₂

Let t₂ be the time taken for I₂ to effuse.

Molar mass (M₁) of N₂O = (14×2) + 16 = 28 + 16 = 44 g/mol

Time (t₁) of effusion of N₂O = 47 s

Molar mass (M₂) of I₂ = 127 × 2 = 254 g/mol

Time (t₂ ) of effusion of I₂ =?

The time take for the same amount of I₂ to effuse can be obtained as follow:

t₂/t₁ = √(M₂/M₁)

t₂/47 = √(254 / 44)

Cross multiply

t₂ = 47 × √(254 / 44)

t₂ = 112.92 s

Therefore, it will take 112.92 s for the same amount of I₂ to effuse.

Answer:

the answer is B

Explanation:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges

Answer:

a. 0.183 mol C

b. 0.366 mol H

Explanation:

Assuming total combustion, all of the carbon in the unknown compound turned into carbon dioxide, CO₂.

So first we calculate the CO₂ moles produced, using its molecular weight:

This means in the unknown compound there were 0.183 moles of carbon, C.

Conversely, all of the hydrogen in the unknown compound turned into water, H₂O.

Calculating the H₂O moles:

We multiply the water moles by two, as there are 2 H moles per H₂O mol:

The question is incomplete, the complete question is;

Compare Homogeneous and Heterogeneous Equilibria Question Which type of equilibrium is more likely to omit substances from the equilibrium constant expression? Select the correct answer below: O homogeneous equilibria O heterogeneous equilibria O a and b are equally likely O there is no correlation

Answer:

heterogeneous equilibria

Explanation:

In a heterogeneous equilibria, there are species of different phases present in the equilibrium expression. Some of these heterogeneous substances may be pure solids.

Remember that the solids and pure liquids are eliminated from the final equilibrium expression.

Thus, when writing equilibria involving heterogeneous substances, solids and pure liquids do not appear in the final equilibrium expressions.

Answer:

Mark as brainleist answer and thanks this answer

Answer: the last one

Explanation: if a cell has too little water, it will begin to function incorrectly, and if a cell has too much water it will burst.

Answer: The size actually does not matter. But planets with smaller mass will have less gravity decreasing their weight. Other for larger mass planets, more mass is more gravity which is also more weight.

Explanation:

Answer:

C) F

Explanation:

Valence electrons are the electrons present in the outermost shell of an atom and have the highest energy level of an atom whereas electrons at ground state or lower orbitals have less potential energy.

This is so because orbitals nearby nucleus are strongly bonded with the atomic nucleus and have less energy than an outermost shell.

So, the potential energy states of an atom depend on the number of orbitals. In the given options fluorine with atomic number 9 has less number of orbitals that is 2 orbitals and valence electrons will be present in second orbitals, so fluorine will have the lowest average potential energy states.

Hence, the correct option is "C) F".

Explanation:

no of moles = no of atoms ÷ avogadro's number

= (9.8×10^24) ÷ (6.02×10^23)

Answer:

0.41g/L

Explanation:

To find the concentration of the albumin in the mixture we need to find the mass in grams and the volume in liters of the solution:

Mass of albumin:

0.20x10⁻³L * (6.0g / L) = 1.2x10⁻³g of albumin

Volume of the solution:

0.20mL + 2.72mL = 2.92mL = 2.92x10⁻³L

Thus, concentration of albumin is:

1.2x10⁻³g of albumin / 2.92x10⁻³L =

Answer:

see explanation

Explanation:

When caffeine is purified, the impurities are removed,  these impurities are responsible for the greater mass of pure caffeine compared to the mass of the pure sample.

The percent recovery of caffeine is frequently low because some caffeine is often left behind in the solvent during the process of recrystallization.

Secondly, since caffeine is a sublime substance, some caffeine may be lost o sublimation leading to a low percent recovery of pure caffeine.

Answer:

s = 22.352 m/s

Explanation:

Given data:

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

Solution:

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

miles to meter:

25 mi × 1609 m/ 1 mi = 40233.6 m

Formula:

s =  d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s

Answer:

Explanation:

It will take 3 sodium ions to neutralize 1 phosphorus ion. That's because you need 3 plus's to satisfy the - charge on phosphorous. So the chemical formula is Na3P reflecting this fact.

Answer:

CaSO₄ (calcium suflate) is the precipitate formed

Explanation:

We can think the reactants:

BeSO₄ → Beryllium sulfate

Ca(OH)₂ → Calcium hydroxide

The reaction is:

Be₂SO₄  +  Ca(OH)₂  →  CaSO₄ ↓  +  Be(OH)₂

We call it as a double-replacement reaction because two ions exchange places from 2 compounds to form two new compounds.

Sulfates can always make precipitate with the elements from group 2, Ca, Ba and Mg.  

Hydroxides from group 2 are solubles, so we complete states:

BeSO₄ (aq)  +  Ca(OH)₂ (aq)  →  CaSO₄ ↓ (s)  +  Be(OH)₂ (aq)

Answer:

left to right across a period when it decreases and when it increases top to bottom in a group,

hope i helped

Answer:

43.75 ml

Explanation:

Given that the equation of the reaction is;

2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)

Concentration of acid CA= 0.05 M

Concentration of base CB = 0.02 M

Volume of acid VA = 35.00ml

Volume of base VB= ???

Number of moles of acid NA= 2

Number of moles of base NB=1

From

CAVA/CBVB= NA/NB

Making VB the subject of the formula;

VB= CAVANB/CBNA

VB= 0.05 × 35 × 1/ 0.02 × 2

VB=1.75 /0.04

VB= 43.75 ml

Answer:

Neon

Explanation:

All noble gases have 8 valence electrons except helium.

Noble gases include Helium, neon, argon, krypton, xenon, redon.

Electronic configuration of neon:

Ne₁₀ = [He] 2s² 2p⁶

All other options are incorrect because,

Electronic configuration of Fluorine:

F₉ = [He] 2s² 2p⁵

Fluorine have seven valence electrons.

Electronic configuration of oxygen:

O₈ = [He] 2s² 2p⁴

Oxygen have six valence electrons.

Electronic configuration of sodium:

Na₁₁ = [Ne] 3s¹

sodium have one valence electron.

Answer:

When the following redox equation is balanced with smallest whole number coefficients, the coefficient for the iodide ion will be __6__.

Explanation:

From the redox equation, we can see that NO₃⁻ is reduced to NO (from oxidation state +5 to +2), whereas I⁻ is oxidized to I₂ (from oxidation state -1 to 0). The half reactions are balanced with H⁺ (acidic solution), as follows:

Reduction :        2 x (NO₃⁻(aq) + 3 e-  + 4 H⁺ → NO(g) + 2 H₂O)

Oxidation :                                   3 x (2 I⁻(aq) → I₂(s) + 2 e-)

                       ----------------------------------------------------------------------

Total equation: 6 I⁻(aq) + 2 NO₃⁻(aq)+ 8 H⁺ → 3 I₂(s) + 2 NO(g) + 4 H₂O

That is the redox equation with the smallest whole number coefficients.

Accordin to this, the coefficient for the iodide ion (I⁻) is: 6.

The given redox equation is balanced with the smallest whole-number coefficients, the coefficient for the iodide ion will be 6.

Redox reaction is the reaction in which oxidation and reduction both occur simultaneously.

From the redox equation, we can see that NO₃⁻ is reduced to NO (from oxidation state +5 to +2), whereas I⁻ is oxidized to I₂ (from oxidation state -1 to 0).

The half reactions are balanced with H⁺ (acidic solution), as follows: Reduction : 2 x (NO₃⁻(aq) + 3 e- + 4 H⁺ → NO(g) + 2 H₂O)

Oxidation : 3 x (2 I⁻(aq) → I₂(s) + 2 e-) ----------------------------------------------------------------------Total equation: 6 I⁻(aq) + 2 NO₃⁻(aq)+ 8 H⁺ → 3 I₂(s) + 2 NO(g) + 4 H₂O

That is the redox equation with the smallest whole number coefficients.

According to this, the coefficient for the iodide ion (I⁻) is: 6.

Find more information about redox reaction here:

brainly.com/question/13978139

Answer:

It was formed from slow cooling.

the angle of the Sun’s rays

Explanation:

Answer:

D. It was formed from slow cooling.

Answer:

Strong electrolytes-2,4

Weak electrolyte-1,5

Non electrolyte- 3,6

Explanation:

The statements were labeled according to whether they define strong electrolytes, weak electrolytes or non electrolytes.

Strong electrolytes are completely dissociated in solution and form highly ionic solutions.

Weak electrolytes have medium conductivity and do not completely dissociate in solution.

Non electrolytes do not dissociate in solution and their solution does not conduct electricity.

1. Weak electrolyte solution: it contains a partially dissociated solute.

2. Strong electrolyte solution: it has the highest conductivity.

3. Non-electrolyte solution: it contains a complete solute.

4. Strong electrolyte solution: it contains a completely dissociated solute.

5. Weak electrolyte solution: it has a medium level of conductivity.

6. Non-electrolyte solution: it has little or no conductivity.

A solution can be defined as a homogenous mixture that contains two or more substances.

In Chemistry, there are three (3) main types of solution and these include:

1. Weak electrolyte solution: this is a type of solution in which only a small amount of dissolved solute exists as ions because it partially dissociates into its constituent anions and cations.

2. Strong electrolyte solution: this is a type of solution that contains only ions but no molecules of the electrolyte because it completely dissociates or ionizes in a solution.

3. Non-electrolyte solution: this is a type of solution that do not dissociates or ionizes in a solution.

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