What’s the equation of the trig graph?

Answer:

Among them 4/5 Is correct answer.

Answer:

3/4

Step-by-step explanation:

..,...............

The difference in overall loss or gain between sell at the current day's high price or low price is found tp be the difference in overall gain as $280.10

The third option is correct.

High price value: 115 shares * $105.19 per share = $12,084.85

Low price value: 115 shares * $103.25 per share = $11,858.75

High price value: 30 shares * $145.18 per share = $4,355.40

Low price value: 30 shares * $143.28 per share = $4,298.40

The overall value at high price:

$12,084.85 + $4,355.40

= $16,440.25

The overall value at low price:

$11,858.75 + $4,298.40

= $16,157.15

In conclusion, the difference in overall gain or loss:

$16,440.25 - $16,157.15 = $280.10

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Answer:

(a) x² + 6x + 8 = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± sqrt(b² - 4ac)) / 2a

where a = 1, b = 6, and c = 8

Substituting the values, we get:

x = (-6 ± sqrt(6² - 4(1)(8))) / 2(1)

x = (-6 ± sqrt(36 - 32)) / 2

x = (-6 ± sqrt(4)) / 2

x = (-6 ± 2) / 2

x = -4 or -2

Therefore, the solutions are x = -4 or x = -2.

(b) x² + 7x + 12 = 0

We can factorize this quadratic equation as:

x² + 7x + 12 = (x + 3)(x + 4)

Therefore, the solutions are x = -3 or x = -4.

(c) y² + 7y + 10 = 0

We can factorize this quadratic equation as:

y² + 7y + 10 = (y + 2)(y + 5)

Therefore, the solutions are y = -2 or y = -5.

(d) y² + 3y - 4 = 0

We can factorize this quadratic equation as:

y² + 3y - 4 = (y + 4)(y - 1)

Therefore, the solutions are y = -4 or y = 1.

(e) x² - 2x - 8 = 0

We can factorize this quadratic equation as:

x² - 2x - 8 = (x - 4)(x + 2)

Therefore, the solutions are x = 4 or x = -2.

(f) m² - 7m + 12 = 0

We can factorize this quadratic equation as:

m² - 7m + 12 = (m - 3)(m - 4)

Therefore, the solutions are m = 3 or m = 4.

(g) y² - 10y + 25 = 0

We can factorize this quadratic equation as:

y² - 10y + 25 = (y - 5)²

Therefore, the only solution is y = 5.

(h) y² - 4y - 45 = 0

We can factorize this quadratic equation as:

y² - 4y - 45 = (y - 9)(y + 5)

Therefore, the solutions are y = 9 or y = -5.

(k) x² + 9x + 18 = 0

We can factorize this quadratic equation as:

x² +9x + 18 = (x + 3)(x + 6)

Therefore, the solutions are x = -3 or x = -6.

(m) y² - 13y + 22 = 0

We can factorize this quadratic equation as:

y² - 13y + 22 = (y - 2)(y - 11)

Therefore, the solutions are y = 2 or y = 11.

(n) x² + x - 12 = 0

We can factorize this quadratic equation as:

x² + x - 12 = (x + 4)(x - 3)

Therefore, the solutions are x = -4 or x = 3.

(p) x² - 11x + 18 = 0

We can factorize this quadratic equation as:

x² - 11x + 18 = (x - 2)(x - 9)

Therefore, the solutions are x = 2 or x = 9.

(q) y² - 14y + 48 = 0

We can factorize this quadratic equation as:

y² - 14y + 48 = (y - 6)(y - 8)

Therefore, the solutions are y = 6 or y = 8.

(s) m² - m - 56 = 0

We can factorize this quadratic equation as:

m² - m - 56 = (m- 8)(m + 7)

Therefore, the solutions are m = 8 or m = -7.

(t) y² + 22y + 96 = 0

We can factorize this quadratic equation as:

y² + 22y + 96 = (y + 12)(y + 8)

Therefore, the solutions are y = -12 or y = -8.

(v) x² - 38x + 72 = 0

We can factorize this quadratic equation as:

x² - 38x + 72 = (x - 2)(x - 36)

Therefore, the solutions are x = 2 or x = 36.

(w) x² + 14x - 51 = 0

We can factorize this quadratic equation as:

x² + 14x - 51 = (x + 17)(x - 3)

Therefore, the solutions are x = -17 or x = 3.

(y) g² - 12g - 64 = 0

We can factorize this quadratic equation as:

g² - 12g - 64 = (g - 8)(g - 4)

Therefore, the solutions are g = 8 or g = 4.

(z) y² + 22y + 121 = 0

We can factorize this quadratic equation as:

y² + 22y + 121 = (y+ 11)²

Therefore, the only solution is y = -11.

(1) y² + 10y + 24 = 0

We can factorize this quadratic equation as:

y² + 10y + 24 = (y + 4)(y + 6)

Therefore, the solutions are y = -4 or y = -6.

(1) x² - x - 56 = 0

We can factorize this quadratic equation as:

x² - x - 56 = (x - 8)(x + 7)

Therefore, the solutions are x = 8 or x = -7.

(1) x² + 23x + 22 = 0

We can factorize this quadratic equation as:

x² + 23x + 22 = (x + 1)(x + 22)

Therefore, the solutions are x = -1 or x = -22.

(0) m² - 6m - 27 = 0

We can factorize this quadratic equation as:

m² - 6m - 27 = (m - 9)(m + 3)

Therefore, the solutions are m = 9 or m = -3.

(r) x² - 15x + 56 = 0

We can factorize this quadratic equation as:

x² - 15x + 56 = (x - 7)(x - 8)

Therefore, the solutions are x = 7 or x = 8.

(u) k² - 18k - 88 = 0

We can factorize this quadratic equation as:

k² - 18k - 88 = (k - 2)(k - 16)

Therefore, the solutions are k = 2 or k = 16.

(x) y² + 32y + 240 = 0

We can factorize this quadratic equation as:

y² + 32y + 240 = (y + 12)(y + 20)

Therefore, the solutions are y = -12 or y = -20.

Hope this helps!

The polynomial f(x) with real coefficients and the given zeros is:

f(x) = x^3 - (12 + i)x^2 + (x - 3 - 2i)x + 27x + (27 + 3i)

To form a polynomial with degree 5 and the given zeros, we can start by writing the factors corresponding to each zero.

The zero 3 gives us the factor (x - 3).

The zero -i gives us the factor (x + i) since complex zeros always come in conjugate pairs.

The zero 9+i gives us the factor (x - (9+i)).

Now, we can multiply these factors together to obtain the polynomial:

f(x) = (x - 3)(x + i)(x - (9+i))

Next, we simplify the expression:

f(x) = (x - 3)(x + i)(x - 9 - i)

Expanding the product, we have:

f(x) = (x^2 + xi - 3x - 3i)(x - 9 - i)

Multiplying further:

f(x) = (x^3 - 9x^2 - ix^2 + xi - 3x^2 + 27x + 3ix - 3xi - 27i - 3x + 27 + 3i)

Combining like terms:

f(x) = x^3 - (9 + i)x^2 - 3x^2 + (x - 3 - 3i)x + 27x + (27 + 3i)

Simplifying:

f(x) = x^3 - (12 + i)x^2 + (x - 3 - 2i)x + 27x + (27 + 3i)

The polynomial f(x) with real coefficients and the given zeros is:

f(x) = x^3 - (12 + i)x^2 + (x - 3 - 2i)x + 27x + (27 + 3i)

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The total surface area of the cylindrical brass pipe, including the internal surface area, is approximately 34183.08 cm².

The formula for the surface area of a cylinder includes the curved surface area (CSA) and the two circular base areas.

1. Outer Surface Area:

The curved surface area (CSA) of a cylinder is given by the formula: CSA = 2πrh, where r is the radius and h is the height.

Given:

Outer diameter = 10 cm

Outer radius (R) = 10 cm / 2 = 5 cm

Height (h) = 600 cm

Outer CSA = 2π(5)(600) = 6000π cm²

The circular base areas can be calculated using the formula: Base area = πr², where r is the radius.

Outer base area = π(5)² = 25π cm²

Therefore, the total outer surface area is the sum of the curved surface area and the two circular base areas:

Total outer surface area = Outer CSA + 2 * Outer base area = 6000π + 2 * 25π = 6050π cm²

2. Inner Surface Area:

The inner radius (r) is given as 4 cm. We can use the same formulas to calculate the inner surface area.

Inner CSA = 2π(4)(600) = 4800π cm²

Inner base area = π(4)² = 16π cm²

Total inner surface area = Inner CSA + 2 * Inner base area = 4800π + 2 * 16π = 4832π cm²

Total surface area = Total outer surface area + Total inner surface area = 6050π + 4832π = 10882π cm²

To find the numerical value, we can use the approximation π ≈ 3.14:

Total surface area ≈ 10882 * 3.14 = 34183.08 cm²

Therefore, the total surface area of the cylindrical brass pipe, including the internal surface area, is approximately 34183.08 cm².

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Answer:

18.2 grams

Step-by-step explanation:

Since the base diameter of the cylindrical container is d=11 cm, so its radius r is:

[tex]r=\frac{d}{2}=\frac{11}{2}=5.5[/tex]

Then, the volume V of the cylindrical container with radius r=5.5 cm and height h=12 cm is:

[tex]V=\pi r^{2}h=\pi \times 5.5^{2}\times 12=363\pi[/tex]

Since the water sample contains 0.016g of trace element for every cubic centimeter of water, so amount of trace element collected by the container of volume [tex]V=363\pi[/tex] cubic centimeters is:

[tex]0.016 g/cm^{3}\times 363\pi~cm^{3}=18.2g[/tex]

The yield on 1-year T-bonds one year from now, based on the pure expectations Theory, is approximately 0.0349 or 3.49%. the yield on 2-year T-bonds one year from now, based on the pure expectations theory, is approximately 0.0443 or 4.43%.the yield on 1-year T-bonds two years from now, based on the pure expectations theory, is 5%.

The pure expectations theory, which suggests that the yield on a bond for a particular period is determined by the market's expectation of future interest rates. The theory assumes that investors are indifferent between investing in shorter-term bonds and rolling over their investments or investing in longer-term bonds.

A.) To calculate the yield on 1-year T-bonds one year from now, we need to find the geometric average of the current yield on 1-year T-bonds and the expected yield on 1-year T-bonds two years from now. Let's assume the current yield on 1-year T-bonds is 3% and the expected yield on 1-year T-bonds two years from now is 4%.

Using the geometric average formula, we can calculate the yield as follows:

Yield = sqrt((1 + Current Yield) * (1 + Expected Yield)) - 1

     = sqrt((1 + 0.03) * (1 + 0.04)) - 1

     = sqrt(1.03 * 1.04) - 1

     ≈ sqrt(1.0712) - 1

     ≈ 0.0349

Therefore, the yield on 1-year T-bonds one year from now, based on the pure expectations theory, is approximately 0.0349 or 3.49%.

B.) To calculate the yield on 2-year T-bonds one year from now, we need to find the geometric average of the current yield on 2-year T-bonds and the expected yield on 2-year T-bonds two years from now. Let's assume the current yield on 2-year T-bonds is 4% and the expected yield on 2-year T-bonds two years from now is 5%.

Using the geometric average formula, we can calculate the yield as follows:

Yield = sqrt((1 + Current Yield) * (1 + Expected Yield)) - 1

     = sqrt((1 + 0.04) * (1 + 0.05)) - 1

     = sqrt(1.04 * 1.05) - 1

     ≈ sqrt(1.092) - 1

     ≈ 0.0443

Therefore, the yield on 2-year T-bonds one year from now, based on the pure expectations theory, is approximately 0.0443 or 4.43%.

C.) To calculate the yield on 1-year T-bonds two years from now, we need to find the expected yield on 1-year T-bonds two years from now. Let's assume the expected yield on 1-year T-bonds two years from now is 5%.

The yield on 1-year T-bonds two years from now, based on the pure expectations theory, is equal to the expected yield, which is 5%.

Therefore, the yield on 1-year T-bonds two years from now, based on the pure expectations theory, is 5%.

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The integral of xe^(7x) dx is equal to (1/7) xe^(7x) - (1/49) e^(7x) + C, where C is the constant of integration.

The integral of x cos(8x) dx is equal to (1/8) x sin(8x) + (1/64) * cos(8x) + C, where C is the constant of integration.

We have,

To solve the given integrals using integration by parts, we follow the formula:

∫u dv = uv - ∫v du

Let's solve each integral step by step:

∫xe^(7x) dx ; u = x, dv = e^(7x) dx

Taking the derivatives and integrals:

du = dx

v = ∫e^(7x) dx = (1/7) * e^(7x)

Applying the integration by parts formula:

∫xe^(7x) dx = uv - ∫v du

= x * (1/7) * e^(7x) - ∫(1/7) * e^(7x) dx

= (1/7) * xe^(7x) - (1/49) * e^(7x) + C

And,

∫x cos(8x) dx ; u = x, dv = cos(8x) dx

Taking the derivatives and integrals:

du = dx

v = ∫cos(8x) dx = (1/8) * sin(8x)

Applying the integration by parts formula:

∫x cos(8x) dx = uv - ∫v du

= x * (1/8) * sin(8x) - ∫(1/8) * sin(8x) dx

= (1/8) * x * sin(8x) + (1/64) * cos(8x) + C

Therefore,

The integral of xe^(7x) dx is equal to (1/7) xe^(7x) - (1/49) e^(7x) + C, where C is the constant of integration.

The integral of x cos(8x) dx is equal to (1/8) x sin(8x) + (1/64) * cos(8x) + C, where C is the constant of integration.

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The function whose graph is given include the following: D. y = cosx + 1.

In Mathematics and Geometry, the standard form of a cosine function can be represented or modeled by the following mathematical equation (formula):

y = acos(x - h) + k

Where:

By critically observing the graph of the given cosine function, we can reasonably infer and logically deduce that the parent cosine function y = cosx was vertically shifted (translated) upward by 1 unit, in order to produce the transformed cosine function as follows;

y = cosx

g(x) = y + 1

g(x) = cosx + 1

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Approximately 1.33 quarts of whipping cream should be mixed with 4 quarts of half and half to obtain a light cream with a 18% butterfat content.

Let's denote the number of quarts of whipping cream that needs to be mixed as "x". We know that the whipping cream has a butterfat percentage of 36% and the half and half has a butterfat percentage of 12%. We want to determine the quantity of whipping cream needed to create a mixture with a butterfat percentage of 18%.

To solve this problem, we can use the concept of weighted averages. The amount of butterfat contributed by the whipping cream is 0.36x, and the amount contributed by the half and half is 0.12 * 4 = 0.48.

The total amount of butterfat in the resulting mixture is 0.18 * (x + 4) since we are aiming for an 18% butterfat content in the final mixture.

Setting up an equation based on the butterfat content, we have:

0.36x + 0.48 = 0.18(x + 4)

Simplifying the equation:

0.36x + 0.48 = 0.18x + 0.72

0.36x - 0.18x = 0.72 - 0.48

0.18x = 0.24

x = 0.24 / 0.18

x = 1.33...

Therefore, approximately 1.33 quarts of whipping cream should be mixed with 4 quarts of half and half to obtain a light cream with a 18% butterfat content.

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Answer:

I assume you mean what they are called, if not please clarify

<1 and <5 = corresponding angles

<3 and < 6 = alternate interior angles

<4 and <6 =  consecutive interior angles

Step-by-step explanation:

Consequently, there are 5 elements in A B'.

Given the following definitions:

U = {1, 2, 3, 4, 5, 6, 7}A = {1, 2, 4, 5}B = {1, 3, 5, 7}

The complement of a set B is the set of all elements that belong to the universal set U but not to B.

A’ = {x | x ∈ U and x ∉ A} = {3, 6, 7}B’ = {x | x ∈ U and x ∉ B} = {2, 4, 6}

The union of sets A and B is the set of all elements that belong to set A or set B, or both.

A ∪ B = {x | x ∈ A or x ∈ B}

= {1, 2, 3, 4, 5, 7}A ∪ B'

= {x | x ∈ A or x ∈ B’}

= {1, 2, 4, 5, 6}

Therefore, the number of elements in A ∪ B' is 5.

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Answer:

161.67 square feet

Step-by-step explanation:

The explanation is attached below.

Area of rectangle = length * width

=> Area of ABIJ = (7 * 6)ft^2 = 42 ft^2

=> Area of IJHG = (5 * 7)ft^2 = 35 ft^2
=> Area of HGCD = (7.81 * 7)ft^2 = 54.67 ft^2

=> Area of triangle = (EIH) = JFG = 1/2 * Base * height

EIH = 1/2 * 6 * 5 = 15 ft^2

JFG = 1/2 * 6 * 5 = 15 ft^2

Total area = (42 + 35 + 54.67 + 15 + 15)ft^2 = 161.67 ft^2

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Answer: 7

Step-by-step explanation:

We can use the Pythagorean theorem (a^2+b^2=c^2) so 25^2=625, and 24^2=576

576+b^2=625 b^2=49 b - (a)=7

Answer:

(x - 1/8) * 1/4 = 1/16

x - 1/8 = 1/16

x = 1/16 + 1/8

x = 3/8

Answer:  C  200 times larger

Step-by-step explanation:

If you want to compare Edmond to Tulsa

Edmond = 1.6 x 10^3

Tulsa  = 3.3 x 10^5

10 to the power of anything means 1 and what ever that power is, that's how many 0's you put on.

Ex. 10^3 = 1000

10^5 = 100000

So Edmond = 1.6 x 1000

Tulsa = 3.3 x 100000

If you multply by 10's 100's etc.  the amount of 0's you have is how many you will move your decimal point

So Edmond = 1600

Tulsa = 330000

You can see that when comparing edmond to tulsa it got a lot larger.  200 times larger.

Answer:There are several ways to calculate this.

The easiest way would be to determine the distance the bird flew.

40km/h x 4h = 160km

30km/h x 2,5h= 75km

Then add up the total distance: 160km + 75km = 235km

Next add up the total time: 4h + 2,5h = 6,5h

So in total the bird flew 235km in 6,5h. Now just divide both numbers by 6,5 as what you want to know is how far the bird got during an average hour.

Step-by-step explanation:

The volume of the solid figures are:

1. 480 cm³

2. 1000 m³

3. 141.43 cm³

4. 60.48 cm³

5. 16971.43 mm³

1. The volume of a cuboid is given by the formula:

V = l * w * h

where l is the length, w is the width and h is the height

We have:

l = 12 cm

w = 5 cm

h = 8 cm

V = 12 * 5 * 8

V = 480 cm³

2. The volume of a cube is given by the formula:

V = l³

where l is the side length

We have:

l = 10m

V = 10³

V = 1000 m³

3. The volume of a cylinder is given by the formula:

V = πr²h

where r is the radius and h is the height

We have:

r = 3 cm

h = 5 cm

V = 22/7 * 3² * 5

V = 141.43 cm³

4. This is also a cuboid.

We have:

l = 4.5 cm

w = 3.2 cm

h = 4.2 cm

V = 4.5 * 3.2 * 4.2

V = 60.48 cm³

5. This is also a cylinder.

We have:

r = 30/2 = 15 mm

h = 24 mm

V = 22/7 * 15² * 24

V = 16971.43 mm³

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1. The surface area of the rectangular prism is 872 square inches.

2. The surface area of the cylinder is 378o.56 square millimeters.

The rectangular prism has three pairs of equal faces: the top and bottom faces, the front and back faces, and the left and right faces.

The formula for the surface area of a rectangular prism is:

Surface Area = 2(length × width) + 2(length × height) + 2(width × height)

Surface Area = 2(8 in × 12 in) + 2(8 in × 17 in) + 2(12 in × 17 in)

Surface Area = 192 in² + 272 in² + 408 in²

Surface Area = 872 in².

The surface area of a cylinder consists of two circular bases and the curved surface area.

The formula for the surface area of a cylinder is: 2π(radius × height) + 2π(radius²).

Surface Area = 2π(14 mm × 29 mm) + 2π(14 mm)²

Surface Area = 2π(406 mm²) + 2π(196 mm²)

Surface Area = 812π mm² + 392π mm²

Surface Area = 1204π mm²

As π = 3.14:

Surface Area = 1204 × 3.14 mm²

Surface Area = 3780.56 mm²

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The graph that represents the function y= tanx is Option A.

The graph of y =tan (x) is a periodic function that has vertical asymptotes at x = (n + 1/2)π, where n is an integer.

It oscillates between positive and   negative infinity, creating a wave-  like pattern.

It has a repeating pattern of sharp peaks and valleys, exhibiting both positive and negative slopes.

Thus, option A is the correct answer.

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Here's a table of values for the equation y = 8x - 4:

The table below show the input and output values of the equation.

x y

0 -4

1 4

2 12

3 20

4 28

5 36

6 44

7 52

8 60

9 68

10 76

These values represent the corresponding values of y when you substitute different values of x into the equation y = 8x - 4.

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a. Using plantwide allocation based on direct labor-hours at a rate of $3 per labor-hour:

Strawberry: $1,744 per 1,000 gallons

Vanilla: $1,534 per 1,000 gallons

Chocolate: $1,889 per 1,000 gallons

b. Allocation rates:

Department SV: $3.60 per machine-hour

Department C: $1.50 per labor-hour

c. Using department allocation rates:

Strawberry: $1,780 per 1,000 gallons

Vanilla: $1,573 per 1,000 gallons

Chocolate: $1,886 per 1,000 gallons

a. To compute the total cost of 1,000 gallons of each flavor using plantwide allocation, we need to allocate overhead based on direct labor-hours at a rate of $3 per labor-hour.

Strawberry:

Direct labor cost: $757 per 1,000 gallons

Labor-hours: 60 per 1,000 gallons

Overhead allocation: $3 per labor-hour * 60 labor-hours = $180

Raw materials cost: $807 per 1,000 gallons

Total cost of 1,000 gallons of strawberry flavor:

Direct labor cost + Overhead allocation + Raw materials cost = $757 + $180 + $807 = $1,744

Vanilla:

Direct labor cost: $832 per 1,000 gallons

Labor-hours: 65 per 1,000 gallons

Overhead allocation: $3 per labor-hour * 65 labor-hours = $195

Raw materials cost: $507 per 1,000 gallons

Total cost of 1,000 gallons of vanilla flavor:

Direct labor cost + Overhead allocation + Raw materials cost = $832 + $195 + $507 = $1,534

Chocolate:

Direct labor cost: $1,132 per 1,000 gallons

Labor-hours: 50 per 1,000 gallons

Overhead allocation: $3 per labor-hour * 50 labor-hours = $150

Raw materials cost: $607 per 1,000 gallons

Total cost of 1,000 gallons of chocolate flavor:

Direct labor cost + Overhead allocation + Raw materials cost = $1,132 + $150 + $607 = $1,889

b. To compute the allocation rate for each department, we will divide the overhead cost by the corresponding allocation base.

Allocation rate for Department SV:

Overhead: $90,972

Machine-hours: 25,270

Allocation rate = Overhead / Machine-hours = $90,972 / 25,270 = $3.60 per machine-hour

Allocation rate for Department C:

Overhead: $27,750

Labor-hours: 18,500

Allocation rate = Overhead / Labor-hours = $27,750 / 18,500 = $1.50 per labor-hour

c. To compute the cost of 1,000 gallons of each flavor using the department allocation rates, we will multiply the allocation rate by the corresponding allocation base for each flavor.

Strawberry:

Machine-hours: 60 per 1,000 gallons

Allocation rate for Department SV: $3.60 per machine-hour

Overhead allocation: $3.60 per machine-hour * 60 machine-hours = $216

Direct labor cost: $757 per 1,000 gallons

Raw materials cost: $807 per 1,000 gallons

Total cost of 1,000 gallons of strawberry flavor:

Direct labor cost + Overhead allocation + Raw materials cost = $757 + $216 + $807 = $1,780

Vanilla:

Machine-hours: 65 per 1,000 gallons

Allocation rate for Department SV: $3.60 per machine-hour

Overhead allocation: $3.60 per machine-hour * 65 machine-hours = $234

Direct labor cost: $832 per 1,000 gallons

Raw materials cost: $507 per 1,000 gallons

Total cost of 1,000 gallons of vanilla flavor:

Direct labor cost + Overhead allocation + Raw materials cost = $832 + $234 + $507 = $1,573

Chocolate:

Labor-hours: 157 per 1,000 gallons

Allocation rate for Department C: $1.50 per labor-hour

Overhead allocation: $1.50 per labor-hour * 157 labor-hours = $235

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The correct labels for the axes to describe the total cost Leandra will pay to rent the car for one week is represented in option (B).

Explanation:  

In the given scenario, we are given that Leandra is renting a car for one week. The total cost to rent the car includes a weekly rate plus an additional charge per mile driven.

We can make the following points to obtain the correct labels for the axes to describe the total cost Leandra will pay to rent the car for one week

Let, x = Number of miles driven y = Total costLeandra is renting a car for one week.

Hence, we have the following given information:Total cost is a function of number of miles driven. Thus, the dependent variable is y, the Total cost.Weekly rate is a fixed cost and additional charge per mile driven is variable cost.

Hence, independent variable is x, the number of miles driven. Thus, x represents the number of miles driven and y represents the total cost to rent the car for one week.

The graph should show the number of miles driven on the x-axis and the corresponding total cost on the y-axis.The correct labels for the axes to describe the total cost Leandra will pay to rent the car for one week is represented in option (B) which is given as follows:

x-axis represents the number of miles driven in the car during one week, and y-axis represents the total cost Leandra will pay to rent the car for one week.

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note the full question maybe:

Which graph correctly labels the axes for the total cost (y-axis) Leandra will pay to rent a car for one week based on the number of miles driven (x-axis)?

[tex](\sin \theta)^2+\left(\dfrac{9}{10}\right)^2=1\\\\(\sin \theta)^2+\dfrac{81}{100}=1\\\\(\sin \theta)^2=\dfrac{19}{100}\\\\\sin\theta=\sqrt{\dfrac{19}{100}}=\dfrac{\sqrt{19}}{10}[/tex]

Mean: also known as the average is a measure of central tendency in a dataset. It is calculated by summing up all the values in the dataset and dividing the sum by the total number of values.

Standard deviation: The standard deviation is a measure of the dispersion of data around the mean in a dataset.t quantifies the average amount by which each data point in the dataset varies from the mean. A higher standard deviation indicates greater variability or dispersion of the data points, while a lower standard deviation suggests that the data points are closer to the mean. The standard deviation is typically represented by the symbol σ (sigma).

Z-Score: The z-score (also known as the standard score) is a statistical measurement that indicates how many standard deviations an individual data point is from the mean of a distribution. It allows you to compare and understand the relative position of a particular data point within a dataset.

The formula to calculate it is:  Z = (x - μ) / σ where:

Z = Z-score

x = data point

μ = mean

σ =  standard deviation

To calculate the z-score for Luis's exam grade, we can use the formula:

z = (x - μ) / σ

Where:

x = Luis's exam grade (84)

μ = Mean (81)

σ = Standard deviation (2.5)

Substituting the given values into the formula, we have:

z = (84 - 81) / 2.5

z = 3 / 2.5

z = 1.20

Rounding to two decimal places, the z-score for Luis's exam grade is 1.20.

Answer:

B) [tex]A=0.5(f\cdot g)(x)[/tex]

Step-by-step explanation:

[tex]\displaystyle A=\frac{1}{2}bh\\\\A=\frac{1}{2}(2x)(x^2+3)\\\\A=\frac{1}{2}g(x)f(x)\\\\A=\frac{1}{2}(f\cdot g)(x)[/tex]

Answer:

Option 2 is the correct answer.

Step-by-step explanation:

The equation that can be used to represent the area of the triangle is:

A(x) = 0.5 * (f ⋅ g)(x)

Let's break it down step by step:

Step 1: Understanding the equation components

f(x) represents the height of the triangle, given as x² + 3.

g(x) represents the base of the triangle, given as 2x.

(f ⋅ g)(x) represents the product of f(x) and g(x), or the multiplication of their respective values at a specific x.

Step 2: Evaluating the equation

To find the area of the triangle when x = 2, we substitute x = 2 into the equation.

A(2) = 0.5 * (f ⋅ g)(2)

Now, let's substitute the functions f(x) and g(x) with their corresponding values at x = 2.

f(2) = 2² + 3 = 4 + 3 = 7

g(2) = 2(2) = 4

Substituting these values into the equation:

A(2) = 0.5 * (7 ⋅ 4)

= 0.5 * 28

= 14

Therefore, when x = 2, the area of the triangle is 14.

Step 3: Interpretation and Conclusion

The equation A(x) = 0.5 * (f ⋅ g)(x) correctly represents the area of the triangle. It takes into account the height function f(x) = x² + 3 and the base function g(x) = 2x, multiplied together and multiplied by 0.5 (or divided by 2), which is a common factor in the formula for the area of a triangle.

Hence, the equation A(x) = 0.5 * (f ⋅ g)(x) can be used to represent the area of the triangle for any given value of x.

To find the range of a data set, we subtract the minimum value from the maximum value.

Given the data set: 47, 38, 72, 56, 40, 64, 30, 80, 66, 51

The minimum value is 30, and the maximum value is 80.

Range = Maximum value - Minimum value

= 80 - 30

= 50

Therefore, the range for the data set is 50.

To find the interquartile range (IQR), we need to determine the values of the first quartile (Q1) and the third quartile (Q3) and then calculate the difference between them.

First, we need to order the data set in ascending order:

30, 38, 40, 47, 51, 56, 64, 66, 72, 80

To find Q1, we take the average of the values at the 25th and 26th positions (since it falls between 38 and 40):

Q1 = (38 + 40) / 2

= 78 / 2

= 39

To find Q3, we take the average of the values at the 75th and 76th positions (since it falls between 66 and 72):

Q3 = (66 + 72) / 2

= 138 / 2

= 69

Now, we can calculate the interquartile range (IQR):

IQR = Q3 - Q1

= 69 - 39

= 30

Therefore, the interquartile range (IQR) for the given data set is 30.