what is the difference between a relation and function? Classify each of the following as a function, or not a function. State the domain and range
{(1,7),(1,14),(1,21)}

The relation is/isn't a function
Domain _ _ _
Range _ _ _
Leave Unused Fields Blank

Answers

Answer 1

Answer:

A relation is a subset of cartesian product of two non empty sets whereas A function is a type of relation in which every element of first set has one and only image in the second set.

In a relation an element of the first set can have many images in the second set whereas in a function the first element can have only one image in the second set.

The given relation is not a function as the element 1 is related to 3 different elements in the second set.

Domain={1}

Range={7,14,21}


Related Questions

Suppose you are standing in a parking lot near a building, and the winter air temperature is 0 degrees Celsius. At that temperature, sound travels about 331 meters per second. If you sound a horn and it takes 0.7 seconds to hear the echo, how far away is the building?

Answers

The building is 231.7 m far away.Distance can refer to a physical length or an estimate based on other factors in physics or common use.

What is distance?

Distance is a numerical representation of the space between two objects or locations. |AB| is a symbol for the distance between two points A and B.

Given data;

Speed of sound  = 331 meters per second

Time = 0.7 sec

The distance from the building is;

d=v×t

d=331 m/sec × 0.7 sec

d=231.7 m

Hence the building is 231.7 m far away.

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Group of 5 people can do a piece of work in 6hrs- Calculate the time a group of 8 people working half the rate of first group could take​

Answers

The time taken by a group of 8 people working half the rate of the first group is 7.5 hours.

What is a fraction?

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

A Group of 5 people can do a piece of work in 6hrs.

5 people, at a rate of 1, and the time taken is 6 hours

Work done is 30

8 people, at a rate of 1/2, and the time taken is x hours

8(1/2)x = 30

x = 60/8 = 7.5 hours

Thus, the time taken by a group of 8 people working half the rate of the first group is 7.5 hours.

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En una tienda se fabrican dos tipos de mesas, de 3 y 4 patas. En total se tienen 89 mesas para vender. Se sabe que el quíntuple de las mesas de 3 patas más la cantidad de mesas de 4 patas es igual a 277. ¿ Cuántas mesas de 3 patas se tienen para vender?

Answers

En una tienda se fabrican

La cantidad de mesas de 3 patas que tiene para la venta la tienda que las

fabrica es: 47

¿Qué es un sistema de ecuaciones?

Es un arreglo de ecuaciones que se caracteriza por tener el mismo número de incógnitas que de ecuaciones.

Existen diferentes métodos para su resolución:

Sustitución: se despeja de una ecuación una variable, quedando en función de otra para luego sustituirla en otra ecuación y así obtener

Igualación: se despeja la misma variable en dos de las ecuaciones y se igualan los resultados.

Eliminación: se resta o suman dos ecuaciones para que quede un resultado en función una variable y así despejarla.

Gráfico: se grafican las rectas y el punto de intersección es la solución del sistema.

¿Cuántas mesas de 3 patas se tienen para vender?

Definir;

x: mesas de 3 patas

y: mesas de 4 patas

Ecuaciones

x + y = 89

5x + y = 277

Aplicar método de eliminación;

Restar 1 - 2;

x + y = 89

-5x - y = -277

-4x + 0 = -188

Despejar x;

x = 188/4

x = 47

Sustituir;

47 + y = 89

Despejar y;

y = 89 - 47

y = 42

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144% of what number is 54?

Answers

Answer:

37.5

Step-by-step explanation:

37.5×144/100=54 the number is 37.5

Triangle P R Q is shown. Angle R P Q is 39 degrees. The length of P R is 6, the length of R Q is p, and the length of P Q is 8.
Law of cosines: a2 = b2 + c2 – 2bccos(A)

Which equation correctly uses the law of cosines to solve for the missing side length of TrianglePQR?

62 = p2 + 82 – 2(p)(8)cos(39°)
p2 = 62 + 82 – 2(6)(8)cos(39°)
82 = 62 + p2 – 2(6)(p)cos(39°)
p2 = 62 + 62 – 2(6)(6)cos(39°)

Answers

According to law of cosines the length of RQ can be written as [tex]p^{2} =6^{2} +8^{2} -2*6*8cos(39)[/tex].

Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.

A length of the triangle can be written as according to law of cosines if sides are given and one angle is [tex]a^{2} =b^{2} +c^{2} -2bccos(A)[/tex]

We have to just put the values in the above equation.

as [tex]p^{2} =6^{2} +8^{2} -2*6*8cos(39)[/tex].

p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.

Hence the side can be written as according to law of cosines if the angle is 39 degrees is  as [tex]p^{2} =6^{2} +8^{2} -2*6*8cos(39)[/tex].

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Answer: OPTION B

Step-by-step explanation:

edge22

answer this 14+20-48
t​

Answers

34-48t would be the answer if the t is connected to the 48

10. A Chemical balance needs to weigh 237 grams using weights of 50 grams , 20 grams , 10 grams and 1 gram . How many of each weight is needed ? ​

Answers

Answer:

237 grams

50 * 4

= 200

4 weight of 50 g

1 weight of 20g

1 weight of 10g

7 weight of 1g

math questionawdAawdadaDaWD

Answers

Substitute 5 in the place of X

[tex]f(x) = \frac{1}{8} \times 4 ^{x} \\ f(5) = \frac{1}{8} \times 4 ^{5} \\ f(5) = \frac{1}{8} \times 1024 \\ f(5) = 0.125 \times 1024 \\ f(5) = 128[/tex]

The asnwer is D

PLEASE GIVE BRAINLIEST

Immediate help needed please.
Can you answer and explain please

Answers

The possible values of k are k < - 1.868 or k > 0.535 in which the inequality is true.

What is a quadratic equation?

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]

We have a quadratic equation:

(k - 1)x² + (4k)x + k -3 = 0

Here,

a = k - 1

b = 4k

c = k - 3

As we know for distinct real roots:

D > 0

[tex]\rm {b^2-4ac}} > 0[/tex]

(4k)² - 4(k-1)(k-3) > 0

[tex]\rm 16k^2-4\left(k-1\right)\left(k-3\right) > 0[/tex]

[tex]\rm 12k^2+16k-12 > 0[/tex]

[tex]\rm 3k^2+4k-3 > 0[/tex]

[tex]\rm 3\left(k+\dfrac{2}{3}\right)^2-\dfrac{13}{3} > 0[/tex]

[tex]\rm 3\left(k+\dfrac{2}{3}\right)^2 > \dfrac{13}{3}[/tex]

[tex]\rm \left(k+\dfrac{2}{3}\right)^2 > \dfrac{13}{9}[/tex]

[tex]\rm k < \dfrac{-\sqrt{13}-2}{3}\quad \mathrm{or}\quad \:k > \dfrac{\sqrt{13}-2}{3}[/tex]

or

[tex]\rm k < -1.868 \quad \mathrm{or}\quad \:k > 0.535[/tex]

Thus, the possible values of k are k < - 1.868 or k > 0.535 in which the inequality is true.

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3(2x - 3) = 4(2x + 4)​

Answers

Answer:

Step-by-step explanation:

Open the brackets

3 x 2x = 6x

3x -3 = -9

4 x 2x= 8x

4 x 4= 16

6x - 9 = 8x + 16

Move same to same side

-16 -9 = 8x - 6x

-25 = 2x

x -25/2

x = -12.5

Answer:

x = -25/2 or -12.5

Step-by-step explanation:

3*(2x - 3) = 4*(2x + 4)​

6x - 9 = 8x + 16

6x - 8x = 16 + 9

-2x = 25

x = -25/2 or -12.5

------------------------

check

3 * (2 * (-12.5) - 3) = 4 * (2 * (-12.5) + 4)

3 * (25 - 3) = 4 * (12.5 + 4)

3 * 22 = 4 * 16.5

66 = 66

the answer is good

A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula
represents the volume of the pyramid?
A. V = 1/12 s ^3
B. V=1/6 s ^3
C. V=1/3s ^3
D. V=3s³
E. V=6s³

Answers

Answer:

The volume of the pyramid with a base area of s² and the heights iss

The formula for calculating the volume of a square based pyramid is expressed as:

Volume = 1/3* Base area* Height

Since it is a square-based pyramid, the base area is calculated as:

Base Area = s ^ 2

If the height of the pyramid is equal to of the length of a side on the base, hence h = s

Substituting the base area and the height into the formula for the volume, this will give;

V = BH / 3

V = (s ^ 2 * s)/3

V = (s ^ 3)/3

V = 1/3 * s ^ 3

Hence the volume of the pyramid with a base area of s ^ 2 and the height s is 1/3 * s ^ 3

Find the area.
O 121.12 ft²
O 53.1 ft²
O 152.3 ft²
O212 ft²
7 ft
8 ft

Answers

The area of the geometry will be 53.1 square feet. Then the correct option is B.

What is Geometry?

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

The figure is the combination of the triangle and semicircle.

Then the area will be

Area = area of triangle + area of semicircle

Area of triangle = 1/2 x 8 x 7

Area of triangle = 28 square ft

Area of semicircle = (π / 8)  x 8²

Area of semicircle = 25.13 square ft

Then the area of the geometry will be

Area = 28 + 25.13

Area = 53.1 square feet

Then the correct option is B.

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What is the length of CD? In this diagram, AABC~ AEDC.

Answers

The length of CD will be option C. 3

From given diagram, triangle ABC and EDC meet at a common vertex C.

So, triangle ABC and EDC both are congruent to each other.

Applying the similarity property of congruence, ratio of the congruent triangles' corresponding sides will be equal.

Therefore,

AB/ED = AC/EC = BC/CD

AC/EC = BC/CD

18/6 = (12 - x)/x

Simplifying the expression,

We get

18x = 6(12 - x)

Multiplicating the terms in right hand side,

18x = 72 - 6x

Solving 6x on both sides,

we get

18x + 6x = 72 - 6x + 6x

24x = 72

Dividing both the sides by 24, we get

24x/24 = 72/24

x = 3

Hence, the length of CD is 3.

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Someone answer this, thank you!

Answers

Step-by-step explanation:

1) the equation of the line represented is

y=0.5x+3 (slope-interception form), the slope is 0.5, the intercept is 3.

x-2y+6=0 (common form);

2) x-intersection is at -6, y-intersection is at 3.

In the year 2000, a house was valued at $60 000.
In 2010, the same house was valued at $80 000.
Work out the value of the house in 2010 as a percentage of it value in 2000

Answers

The percentage by which the cost is increasing will be 75%.

What is the percentage?

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

The percentage of the 8th graders who want to go to the water slides is found from;

In the year 2000, a house was valued at $60 000.

In 2010, the same house was valued at $80 000.

The percentage value is found as;

[tex]\% = \frac{60000}{80000} \times 100 \\\\ \% =75 \%[/tex]

Hence the percentage by which the cost is increasing will be 75%.

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if cp=rs 400, loss=10% find sp

Answers

Answer:

cp = rs 400

loss = 10%

Then SP = 400 - 10% of 400

= 400 - 40

= 360

Therefore SP = Rs. 360

Solve x^2 - 10x = 30x

Answers

[tex]x^2-10x=30x\\x^2-40x=0\\x(x-40)=0\\x=0 \vee x=40[/tex]

Gertrude has a life insurance policy that will pay her family $97,000 per year I she dies. If interest rates are at 1.4% when the insurance company has to pay, what is the amount of the lump sum that the insurance company must put into a bank account? A. $692,857,142.90 B. $6,928,571.43 c. $692,857.14 D. $69,285,714.29​

Answers

The amount of the lump sum that the insurance company must put into a bank account is $6,928,571.43 option (B) is correct.

What is the percentage?

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

Gertrude has a life insurance policy that will pay her family $97,000 per year.

If interest rates are at 1.4% when the insurance company has to pay

r = 1.4%

or

r = 0.014

The amount of the lump sum that the insurance company must put into a bank account:

= 97,000/0.014

= 6928571.429 ≈ $6,928,571.43

Thus, the amount of the lump sum that the insurance company must put into a bank account is $6,928,571.43 option (B) is correct.

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What are the roots of x In-10x2 + 12x-9=0? OA. 61√6 -1 10 31√6 10 OB. O C. 31√24 10131/24 OD. ti√24 OE. 1, 2:√6 51 10 What are the roots of x In - 10x2 + 12x - 9 = 0 ? OA . 61√6 -1 10 31√6 10 OB . O C. 31√24 10131/24 OD . ti√24 OE . 1 , 2 : √6 51 10​

Answers

Answer:

9=0

Step-by-step explanation:

9=0

The roots of x in the equation -10x² + 12x - 9 = 0 are:

x = (3/5) + (3/5)√(6)i

x = (3/5) - (3/5)√(6)i

What is a quadratic equation?

For variable x : ax² + bx + c = 0, where a≠0 is a standard quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution since it is a second-order polynomial equation, which is guaranteed by the algebraic basic theorem.

To find the roots of x in the equation -10x² + 12x - 9 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation in standard form (ax² + bx + c).

In this case, a = -10, b = 12, and c = -9. Substituting these values into the quadratic formula, we get:

x = (-12 ± √(12² - 4(-10)(-9))) / 2(-10)

x = (-12 ± √(144 - 360)) / (-20)

x = (-12 ± √(-216)) / (-20)

Substituting this into the expression for x, we get:

x = (-12 ± 6√(6)i) / (-20)

Simplifying the expression further, we get:

x = (3/5) ± (3/5)√(6)i

Therefore, the roots of x in the equation -10x² + 12x - 9 = 0 are:

x = (3/5) + (3/5)√(6)i

x = (3/5) - (3/5)√(6)i

These roots are complex conjugates of each other.

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Please help me!!! I will give brainliest to the correct answer.

Answers

2(10+2)=3(y+3)2(12)=3y+924=3y+93y=15y=5

[tex]\mathsf {2(10 + 2) = 3(y + 3)}[/tex]

[tex]\mathsf {24 = 3y + 9}[/tex]

[tex]\mathsf {3y = 15}[/tex]

[tex]\textsf {y = 5}[/tex]

[tex]\textsf {The value of y will be 5. }[/tex]

Identify parallel and perpendicular lines

Answers

Parallel lines are those on a plane that do not intersect while perpendicular lines are those that intersect at an angle of 90°.

How are parallel and perpendicular lines different?

Parallel lines will never intersect with each other and will maintain the same distance from each other for as long as they are on the same plane.

Perpendicular lines on the other hand will intersect each other and will do so at a 90° angle. An example of such a line is the steps on a ladder which intersect the beam at a 90° angle.

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Which numbers below are odd?
A. 4271
B. 7966
C. 787
D. 288
E. 8113
F. 985

Answers

Answer:
A. 4271
C. 787
E. 8113
F. 985

(They all end in an odd number.)

Solve the following system of equations. -7x+5y=-11; -4x+3y= -7

Answers

Answer:

X = (-2) Y = (-5)

- 7x + 5y= (-11) -------(1)

-4x + 3y,= (-7) ----------(2)

Solving by using elimination method

Multiplying eq 1 with 3 and eq 2 with 5

3( -7x + 5y) = 3(-11)

5(- 4x + 3y) = 5(-7)

-21x + 15y = (-33)

-20x + 15y,= (-35)

Subtracting both the eq.

-x = 2

x = (-2)

Putting this value in eq. 1

- 7x + 5y= (-11)

-7(-2)+ 5y= (-11)

14 + 5y = (-11)

5y = (-11) - 14

5y= (-25)

y = (-5)

Drag each sign and value to the correct location on the image. Each sign and value can be used more than once, but not all signs and values will be used. The vertices of an ellipse are at (-5, -2) and (-5, 14), and the point (0, 6) lies on the ellipse. Drag the missing terms and signs to their correct places in the standard form of the equation of this ellipse.

Answers

The complete equation of the ellipse is [tex]\frac{(x + 5)^2}{5^2} + \frac{(y - 6)^2}{8^2} = 1[/tex]

How to complete the vertex equation?

The complete question is in the attachment

The given parameters are:

Vertex = (-5,-2) and (-5,14)Point = (-0,6)

The vertex is represented as (h, k ± a).

So, we have:

h = -5

k + a = 14

k - a = -2

Add the last two equations

2k = 12

Divide by 2

k = 6

Substitute k = 6 in k + a = 14

6 + a = 14

Solve for a

a = 8

The ellipse equation is represented as:

[tex]\frac{(x - h)^2}{b^2} + \frac{(y - k)^2}{a^2} = 1[/tex]

So, we have:

[tex]\frac{(x + 5)^2}{b^2} + \frac{(y - 6)^2}{8^2} = 1[/tex]

The ellipse passes through the point (0,6).

So, we have:

[tex]\frac{(0 + 5)^2}{b^2} + \frac{(6 - 6)^2}{8^2} = 1[/tex]

This gives

[tex]\frac{5^2}{b^2} + \frac{0}{8^2} = 1[/tex]

Evaluate the quotient

[tex]\frac{5^2}{b^2} = 1[/tex]

Cross multiply

[tex]b^2 = 5^2[/tex]

Take the square root of both sides

b = 5

Substitute b = 5 in [tex]\frac{(x + 5)^2}{b^2} + \frac{(y - 6)^2}{8^2} = 1[/tex]

[tex]\frac{(x + 5)^2}{5^2} + \frac{(y - 6)^2}{8^2} = 1[/tex]

Hence, the complete equation of the ellipse is [tex]\frac{(x + 5)^2}{5^2} + \frac{(y - 6)^2}{8^2} = 1[/tex]

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Kmele had paid his credit card on time for three years, but last month he missed the due date. He then noticed that the amount owed increased by $35. This most likely happened because he was charged.
A. a late fee
B. a higher interest rate
C. a minimum-payment fee
D. an overdraft-fee

Answers

Answer:

It's most likely he was charged a late fee

How to 24-[5408÷48{×41+701]-240}-240÷16​

Answers

do in oder of pemdas....

Which expression is equivalent to...​

Answers

Answer: the fourth one

Step-by-step explanation:

Answer:

D.) 8x¹²y³

Step-by-step explanation:

When an expression is raised to a power, you have to raise everything in the expression to the power when simplifying. This includes the coefficients and variables. When a variable already raised to a power is raised to another power, the powers are multiplied.

Therefore,

2³ = 8

(x⁴)³ = x⁴*³ = x¹²

(y)³ = y³

Combined, the final answer is 8x¹²y³.

David rolls a fair dice 30 times. How many times would David expect to roll a number greater than 3?

Answers

Answer:

15

Step-by-step explanation:

so if its a 6 faced dice then there is a 3/6 numbers greater than 3. which simplifies to 1/2. 30(1/2)= 15

Simplify this problem!!!

Answers

Answer:

C

Step-by-step explanation:

HOPE THAT HELPSBDNQBDB

The answer is c hope that helps you

Solve the following system of equations:
4x − 2y − z = −5
x − 3y + 2z = 3
3x + y − 2z = −5
(0, 1, 3)
(0, −1, 3)
(0, 1, −3)
(0, −1, −3)​

Answers

Answer: (0, 1, 3)

Step-by-step explanation:

Adding the second and third equations, we get [tex]4x-2y=-2[/tex]Multiplying both sides of the first equation by 2, we get that [tex]8x-4y-2z=-10[/tex]. Adding this to the second equation, we get that [tex]9x-7y=-7[/tex].

If we multiply both sides of the equation [tex]4x-2y=-2[/tex] by 7, we get [tex]28x-14y=-14[/tex].

If we multiply both sides of the equation [tex]9x-7y=-7[/tex] by 2, we get [tex]18x-14y=-14[/tex].

Subtracting the equation [tex]28x-14y=-14[/tex] from the equation [tex]18x-14y=-14[/tex], we get that [tex]-10x=0 \longrightarrow x=0[/tex].

This means that [tex]4(0)-2y=-2 \longrightarrow y=1[/tex]

And thus, [tex]4(0)-2(1)-z=-5 \longrightarrow -2-z=-5 \longrightarrow z=3[/tex].

So, the solution is (0, 1, 3).

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