Answer:
a. 3.72 [atm]
Explanation:
For a gas at constant temperature, (with no change in number of molecules of the gas), we can apply Boyle's Law: [tex]P_1V_1=P_2V_2[/tex]
[tex](1.556[atm])(268.5[mL])=P_2(112.4[mL])[/tex]
[tex]\dfrac{(1.556[atm])(268.5[mL\!\!\!\!\!\!\!\!{--}])}{112.4[mL \!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})}{112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}[/tex]
[tex]3.716957[atm]=P_2[/tex]
It seems like the answer should have 4 significant figures since all of the other quantities have 4 significant figures, but the closest answer choice of those provided is a. 3.72
Identify 3 chemicals that produce a potentially dangerous reaction with hydrochloric acid.
A car's tires are inflated to 2.11 atm at 25c. after driving to the grocery store, the tires are at 2.25 atm. what is the temperature of the air in the tire after the drive?
Answer:
T₂ = 26.7 °C
Explanation:
Because you are dealing with pressure and temperature, you can use Gay-Lussac's Law to find the final answer. The equation looks like this:
P₁ / T₁ = P₂ / T₂
In this form, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You have been given the values for all of the variables but "T₂". Therefore, by plugging these values into the equation, you can simplify to find "T₂".
P₁ = 2.11 atm T₁ = 25 °C
P₂ = 2.25 atm T₂ = ?
P₁ / T₁ = P₂ / T₂ <--- Gay-Lussac's Law equation
(2.11 atm) / (25 °C) = (2.25 atm) / T₂ <--- Plug variables into equation
0.0844 = (2.25 atm) / T₂ <--- Divide 2.11 by 25
(0.0844) x T₂ = 2.25 atm <--- Multiply both sides by T₂
T₂ = 26.7 <--- Divide both sides by 0.0844
Ammonia gas occupies a volume of 450. mL at a pressure of 720. mm Hg. What volume will it occupy at standard pressure?
Show your work Please!!!!
Calculate the molecular mass of Al2(SO4)3(Molecular mass of Al=27, S=32, O=16) Pls fast
Al₂(SO₄)₃
= 2.Al+3.S+12.O
= 2.27 + 3.32+12.16
= 54+96+192
=342 g/mol
The 9.6 g object displaced
3.2 mL of water.
What is its density in g/mL?
density=[?] g/mL
Answer: 3
Explanation:
Density is mass/volume divide the mass 9.6 by the volume of 3.2
[tex]\frac{9.6}{3.2} =3[/tex]
The density of the object displaced in water is equal to 3 g/ml.
What is the density?The density of a substance can be described as the substance's mass per unit of its volume. The symbol is generally used to represent density ρ and the letter D can be used.
The mathematical formula of the density of a material can be represented as shown below:
Density = Mass/volume
ρ = m/V
The density of a material varies with pressure as well as temperature. There is a small variation in the density of the solids and liquids but much larger for gases. Increasing the pressure of the substance decreases the volume and thus increases its density.
As the object displaced water of volume of 3.2 ml.
Therefore, the volume of the object, V = 3.2 ml
The mass of the object, m = 9.6 g
The density of the object placed in water can be calculated as:
Density of object = 9.6/3.2 = 3 g/ml
Therefore, the density of the object is 3 g/ml.
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Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.
It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.
Concept :To boil water at 95°C, decrease the atmospheric pressure.
At 105°C, the water will be boiling quickly than normal at 100°C.
The best way is add alcohol .
The common way is that decrease the atmospheric pressure .
This will work as per Boyles law ,and boiling point can be decreased.
but it has few restrictions
You can't decrease pressure simply at normal conditionsFor decreasing pressure you have to go hill tops .Hence there is a spare way
Add alcoholGeneral alcohols like ethanol,butanol can decrease the boiling point of water
A thermodynamically-controlled process describes a reaction that ________.
A thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.
What is a thermodynamically-controlled process?A thermodynamically-controlled process is a reaction in which the ratio of the product formed is determined by the relative stability of the products.
Thermodynamic control ensures that the most stable or more stable of two products is formed.
Therefore, a thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.
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What is the answer to this question? I need help!!
Answer:
[tex]\fbox {C}[/tex]
Explanation:
By repeating the experiment with new amounts of each reactant, this conflict can be resolved as we can see the effect of a reactant on the final amount of product formed.
7.0 mol Mn reacts with 5.0 mol
O2 according to the equation below:
2Mn + O₂ → 2MnO
How many moles of MnO form from
5.0 mol Mn?
? ] mol MnO
Round your answer to the tenths place.
Answer:
5.0 mol
Explanation:
From the coefficients of the equation, we know that for every 2 moles of Mn consumed, 2 moles of MnO are produced.
Thus, the number of moles of Mn consumed is equal to the number of moles of MnO produced, and thus the answer is 5.0 mol.
The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.
What is a limiting reagent?In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.
In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.
Thus, the moles of oxygen consumed by 7 moles of Mn is:
2 moles Mn = 1 mole O₂
7 moles Mn = 3.5 moles O₂
The available moles of O₂ = 5 mol.
The remaining moles of O₂ = 5-3.5 moles
The remaining moles of O₂ = 1.5 moles
The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.
The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂
1 mole O₂ = 2 moles MnO
1.5 moles O₂ = 2 * 1.5 moles MnO
1.5 moles O₂ = 3 moles MnO
Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.
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For the function F(x) = 1, which of these could be a value of F(x) when x is
close to zero?
Answer:
A. -10,000
Explanation:
When x approaches zero, the graph tells us that F(x) either becomes extremely large or extremely small. The best answer is therefore A: -10,000. Best, because we aren't given the exact value of x, but clearly the other results require that x be greater than 1 or less than -1, which is far from zero.
Specialized periodicals in which scientists publish the results of their works are called
Specialized periodicals in which scientists publish the results of their works are called scientific journals.
In educational publishing, a scientific journal is a periodical book intended to similarly the progress of technology, typically by way of reporting new studies.
Journal articles may include original research, re-analyses of studies, opinions of literature in a selected place, proposals of new but untested theories, or opinion pieces.
These scientific journals include the following.
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What does a particular point on a line of a phase diagram represent?
A. The pressure created by the kinetic energy of molecules at a
particular temperature
B. The maximum temperature a substance can exist at without
bonds breaking
OC. The melting point or boiling point of a substance at a specific
pressure
OD. The conditions in which temperature and pressure have equal
effects on a substance
Answer:
The point at which the lines intersect represents the triple point.
How many moles of propane
react when 294 g of CO2 form?
C3H8 +502 3CO2 + 4H₂O
?] mol C3H8
Identify the reaction type for each unrelated, radical reaction as either initiation, propagation, or termination. Reaction A. A chlorine chlorine bond splits into two chlorine radicals. What type of reaction is reaction A
A is the initial reaction when a chlorine bond splits into two chlorine radicals.
What are radicals?In chemistry, a radical is an atom, molecule, or ion that has an unpaired valence electron.
The question is based on Radical Chain Reaction. And these reactions have three different phases: Initiation, Propagation and Termination.
Reaction A- Initiation
Reaction B- Termination
Reaction C- propagation
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Consider the compound calcium nitrate, Ca(NO3)2. Which statements are true about this compound? Check all that apply. There are two atoms of oxygen. There are six atoms of oxygen. There are two nitrogen atoms. There are two calcium atoms.
Calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.
Ca(NO₃)₂
Calcium nitrate is a compound consisting of calcium, nitrogen and oxygen compoundsIt is an inorganic compoundIt is water-absorbent and absorbs moisture from airCalcium nitrate has two forms, hydrous and anhydrousBoth forms are colourless and odourlessThe reaction to form Calcium nitrate is Ca + 2NO₃ -----> Ca(NO₃)₂The number of oxygen atoms is: 2x3 = 6The number of nitrogen atoms is: 2x1= 1There is 1 calcium atomThus, calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.
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Answer:
B)There are six atoms of oxygen.
C)There are two nitrogen atoms.
Explanation:
edge 2023
the screenshts below
Answer:
yes so for example one
Explanation:
yeah so
Which of the following shows the combustion of a hydrocarbon?
OA. NaOH + HCI → NaCl + H₂O
OB. CO₂ + H₂O → H₂CO3
OC. 2C₂H₂ +502 + 4CO2 + 2H₂O
OD. C₂H4 + Cl₂ ⇒ C₂H4Cl₂
Answer:
C
Explanation:
with combustion you must know that your products must be carbon dioxide and water. I think you copied your question incorrectly.
The scientists who have contributed to our current body of knowledge were
from what part of the world?
A. All areas of the world
B. Mostly Europe
C. Mostly the Middle East
D. Only the United States
SEMIT
Answer:
A.
Explanation:
Well, Nicola Tesla was from Croatia.
Albert Einstein was from Germany.
Thomas Edison was from the U.S.
So I think all over.
the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?
The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
Position of 18o-labeled methanol in the products
The 18O label will appear at position b in the product as indicated in the image.
This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).
While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.
Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
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Given the balanced equation representing a
reaction:
2NO+ O₂ → 2NO₂ + energy
1. The mole ratio of NO to NO₂ is
(1) 1 to 1
(2) 2 to 1
(3) 3 to 2
(4) 5 to 2
Answer: it would be a 1 to 1 ratio
Explanation: originally it would be 2 to 2 but you have to reduce
A sealed container can hold
0.325 L of gas at 1.00 atm
and 293 K. How many moles of gas
can the container hold?
0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
V=5 L
P = 1.05 atm
T = 296 K
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]n= \frac{1.05 atm\; X \;5 L}{ 0.08206 L.atm / mol K X 296 K}[/tex]
Moles = 0.216 moles
Hence, 0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
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Answer:
0.014
Explanation:
Use the formula PV=nRT; there are calculators for it online as well.
7.0 mol Mn reacts with 5.0 mol
O2 according to the equation below:
2Mn + O₂ → 2MnO
How many moles of MnO form from
5.0 mol Mn?
[?] mol MnO
Round your answer to the tenths place.
5 moles of MnO form from 5.0 mol Mn. Details about stoichiometry can be found below.
How to calculate number of moles?The number of moles of a substance can be calculated stoichiometrically as follows:
According to this question, the following chemical equation is given as follows:
2Mn + O₂ → 2MnO
2 moles of Mn forms 2 moles of MnO
Hence, 5 moles of Mn will form 5 × 2/2 = 5 moles of MnO.
Therefore, 5 moles of MnO form from 5.0 mol Mn.
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Answer: 10.0
Explanation: i took the test
Ethanoic acid reacts with ethanol to form an ester and water. How many moles of ethanoic acid are required to produce 0.5 mol of the ester? (A) 0.05 (B) 0.5 (C) 1 (D) 2
0.5 moles of ethanoic acid are required to produce 0.5 mol of the ester , Option B is the right answer.
What is esterification reaction ?The reaction in which a carboxylic acid combine with an alcohol to form ester and water is called esterification reaction.
It is given in the question that
Ethanoic acid reacts with ethanol to form an ester and water
C₂H₅OH + CH₃COOH → CH₃COOH + H₂O
The moles of ethanoic acid required to produce 0.5 mole of ester.
In the following reaction it can be seen that the mole fraction of ethanoic acid to ester is 1: 1
Therefore 0.5 mole of ethanoic acid will be required to produce 0.5 mol of ester.
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A solution is 0.225M Na2SO4. What is the molarity of the sodium ion in solution
The molarity of the sodium ion in the solution is 0.450 M.
How do we determine the molarity of sodium ions in a solution?The molarity of the sodium ion in a solution can be determined by the dissociation of the given solution Na2SO4(sodium sulfate).
The dissociation of Na2SO4 is computed as follows:
1 mole of Na2SO4 dissociates to give 2 moles of sodium cations and 1 mole of sulfate anion.i.e.
[tex]\mathbf{Na_2SO_4 \to 2Na^{+} + SO_4^{2-}}[/tex]
The molarity for sodium-ion [Na+] is:
= 2 × 0.225 M
= 0.450 M
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What is the mass of a 7.426-mole sample of sodium hydroxide (NaOH molar mass = 40.0 g/mol)?
Select one:
5.360 g
40.00 g
179.1g
297.0 g
[tex](40.0)(7.426)=\boxed{297.0 \text{ g (to 4 sf)}}[/tex]
Please answer step by step.
3 moles of NaOH reacts with 1 mole of phosphoric acid.
What is the moles ratio of the NaOH and Phosphoric acid reaction?The moles ratio of the reaction between NaOH and Phosphoric acid is given by the equation of the reaction below:
[tex]3\:NaOH + H_{3}PO_{4} \rightarrow Na_{3}PO_{4} + 3\:H_{2}O \\ [/tex]
Based on the equation of the reaction, 3 moles of NaOH reacts with 1 mole of phosphoric acid.
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Which would be a good use for an organic substance? Check all that apply. A. Electrical conductors B. Waterproof coatings C. Fuels such as gasoline D. Microchips E. Plastic storage containers
Answer:
B. waterproof coatingExplanation:
please mark me brainlistMr. Auric Goldfinger, criminal mastermind, intends to smuggle several tons of gold across international borders by disguising it as lumps of iron ore. He commands his engineer minions to form the gold into little spheres with a diameter of exactly
8 cm and paint them black.
However, his chief engineer points out that customs officials will surely notice the unusual weight of the "iron ore" if the balls are made of solid gold (density
). She suggests forming the gold into hollow balls instead , so that the fake "iron ore" has the same density as real iron ore
One of the balls of fake "iron ore," sliced in half.
Calculate the required thickness of the walls of each hollow lump of "iron ore." Be sure your answer has a unit symbol, if necessary, and round it to 2
significant digits.
The thickness of the walls of each hollow lump of iron ore is: 0.295cm. This is determined using the knowledge of the Volume of a Hollow Sphere.
What is the Volume of a Hollow Sphere?
The formula for the Volume of a Hollow Sphere is give as:
Volume of a Hollow = 4/3 R³ – 4/3 r³
Step 1 - Find the apparent volume of 8cm diameter sphere including the wall the the hollow inside
V = 4/3 r³
V = (4/3) (8)³
V = (4/3) * (22/7) * 512
V = 2145.52cm³
Step 2 - Determine the mass of Gold required for the sphere to achieve the density of iron ore if the apparent volume is as given in Step 1 above.
Recall that Mass = Density * Volume
Mass = 5.15 * 2145.52
Mass = 11049.45
Step 3 - Find volume of gold based on mass calculated in Step 2 above
Recall that :
Volume = Mass/Density
Thus,
V = 11049.4/19.3
Thus, Volume = 572.51cm³
Step 4 - Find the width of the wall of a hollow sphere for the volume realized in step 3
Recall the initial formula:
Volume of a Hollow = 4/3 R³ – 4/3 r³
Thus, 572.51 = (4/3) (8³ - (8 - t)³)
572.51 = (4/3) *(22.7) *(8³ - (8 - t)³)
572.51 = (88/21) *(8³ - (8 - t)³)
Multiply both sides by 21 and we have
88 (512 - (8 - t)³) = 12,022.71
Simplify further
(8 - t)³ = 357.38
t = 0.9035cm
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The exothermic reaction between solid aluminium powder and solid manganese (IV) oxide, produces solid manganese and
another product. How many moles of aluminium powder are needed to produce 203.7 grams of manganese?
The number of moles of aluminum powder needed to produce 203.7 grams of manganese is 5 moles.
How to calculate the number of moles of Aluminium powder?Heat, Mn, and Al2O3 are produced when aluminum powder and manganese dioxide are heated.
[tex]3MnO_{2} + 4Al - > 3Mn + 2Al_{2} O_{3} + Heat[/tex]
The balanced chemical equation in this situation indicates that there are 3 moles of manganese and 4 moles of aluminum involved in the reaction, which results in a 3:4 mole ratio.
You may make use of this mole ratio by calculating how many moles of aluminum are required to react with the 203.7g of Manganese. So,
Firstly, the mass of Aluminium has to be taken out
Let the mass be considered x.
So, the number of moles of Aluminium = x/27
Number of moles of Manganese = 203.7/54
Hence, the mass x will be,
[tex]x = 4 *203.7 * 27 / 3 * 54[/tex]
[tex]x = 135.8g[/tex]
Hence, the number of moles of Aluminium is = 135.8/27 = 5 moles.
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Name 20 chemical changes in our daily environment
Answer:
chemical reactions In our daily environment are
1) Cooking food
2) Photosynthesis
3) rusting
4) painting
5) respiration
6) combustion
7) Electrochemistry (including chemical batteries)
8)Digestion
9)Soap and detergent reactions
10)Acid-base reactions
11) fermentation
12) oxidation
13 ) burning of paper
14) riping of fruits
15) frying egg
16) souring of milk
17) baking
18) heating sugar
19) burning wood
20) rising bread
