The decomposition reaction of calcium carbonate is represented by the following balanced equation:


CaCO3(s) --> CaO(s) + CO2(g)



After a 15. 8−g sample of calcium carbonate was heated in an open container to cause decomposition, the mass of the remaining solid was determined to be 9. 10 g. The reaction may or may not have gone to completion, so the solid could contain unreacted CaCO3. Calculate the percent yield of CO2.



Please help! Thank you!

Answer:

7.3

Explanation:

In a 23.5 mol sample of C₇H₅N₃O₆, there are 6.87 moles of nitrogen atoms and 8.79 moles of oxygen atoms.

In order to determine the number of moles of nitrogen and oxygen atoms in a 23.5 mol sample of C₇H₅N₃O₆, we first need to look at the chemical formula for this compound.

From the formula, we can see that there are 7 nitrogen atoms and 9 oxygen atoms present in each molecule of C₇H₅N₃O₆.

To calculate the number of moles of nitrogen atoms, we multiply the total number of moles by the mole fraction of nitrogen in the compound:

Moles of nitrogen = 23.5 mol x (7 nitrogen atoms / 24 total atoms)
Moles of nitrogen = 6.87 mol

Similarly, to calculate the number of moles of oxygen atoms, we use the mole fraction of oxygen in the compound:

Moles of oxygen = 23.5 mol x (9 oxygen atoms / 24 total atoms)
Moles of oxygen = 8.79 mol

Therefore, there are approximately 6.87 moles of nitrogen atoms and 8.79 moles of oxygen atoms in a 23.5 mol sample of C₇H₅N₃O₆.

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The actual yield was 1.329 g Ag.

The balanced equation for the reaction between Zinc and Silver Nitrate is:

Zn + 2AgNO₃ -> 2Ag + Zn(NO₃)₂.

Given: 29 g Zn, and 2 g AgNO₃. Molar masses: Zn = 65 g/mol, AgNO₃ = 169.87 g/mol.

Moles Zn = 29/65 = 0.446 mol

Moles AgNO₃ = 2/169.87 = 0.0118 mol

Since the stoichiometric ratio is 1:2 (Zn:AgNO₃), we need 0.223 mol AgNO₃ for a complete reaction.

We have only 0.0118 mol AgNO₃, making it the limiting reagent.

Theoretical yield of Ag: 2 mol Ag produced from 1 mol AgNO₃.

0.0118 mol AgNO₃ * (2 mol Ag / 1 mol AgNO₃) * 108 g/mol (Ag's molar mass) = 2.54 g Ag

The actual yield was 1.329 g Ag.

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The molar mass of lithium sulfate (Li2SO4) is:

Li2SO4 = 2 x Li + 1 x S + 4 x O = 2(6.94 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 109.94 g/mol

To find the number of moles of lithium sulfate, we need to first find the number of moles of lithium in the sample:

2.94 x 10^23 atoms of Li x (1 mole of Li/6.022 x 10^23 atoms of Li) = 0.488 moles of Li

Since there are two moles of lithium for every one mole of lithium sulfate, the number of moles of lithium sulfate in the sample is:

0.488 moles of Li x (1 mole of Li2SO4/2 moles of Li) = 0.244 moles of Li2SO4

Therefore, the sample contains 0.244 moles of lithium sulfate.

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The balanced chemical equation for the reaction between a weak acid, HClO₂, and a strong base, Ba(OH)₂, is:

2 HClO₂(aq) + Ba(OH)₂(aq) → Ba(ClO₂)₂(aq) + 2 H₂O(l)

The balanced chemical equation for the reaction between a weak acid, HClO₂, and a strong base, Ba(OH)₂, is:

2 HClO₂(aq) + Ba(OH)₂(aq) → Ba(ClO₂)₂(aq) + 2 H₂O(l)

In this reaction, the Ba(OH)₂ dissociates completely into Ba²⁺ and 2 OH⁻ ions in solution. The HClO₂ is a weak acid and therefore only partially dissociates into H⁺ and ClO₂⁻ ions in solution. The reaction between these ions forms Ba(ClO₂)₂, a salt, and water.
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The mass of CO2 produced is 20.9 g

The formula of the limiting reactant is O2

The reactant that produces the smallest amount of product is the limiting reactant.

Number of moles of glucose = 9.91 g/180 g/mol

= 0.055 moles

Number of moles of oxygen = 15.2 g/32 g/mol= 0.475 moles

1 mole of glucose reacts with 6 moles of oxygen

0.055 moles of glucose reacts with 0.055 * 6/1

= 0.33 moles

Thus oxygen is the limiting reactant

Mass of CO2 produced = 0.475 moles * 44 g/mol

= 20.9 g

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The molar enthalpy for the reaction of calcium chloride is -22,982.5 J/mol.

Calcium chloride is a chemical compound that is commonly used as a drying agent due to its hygroscopic properties. In this question, we are given the amount of calcium chloride and asked to determine the molar enthalpy for its reaction with excess potassium.

The given temperature change of the solution in the calorimeter can be used to calculate the heat released or absorbed during the reaction.

To begin, we need to determine the number of moles of calcium chloride in the given amount of 4 g. Using the molar mass of calcium chloride (110.98 g/mol), we can calculate that 4 g of calcium chloride is equal to 0.036 moles. Since the reaction is with excess potassium, we can assume that all the calcium chloride will react.

Next, we can use the heat capacity of the solution and the temperature change to calculate the heat released or absorbed during the reaction. Assuming that the solution is mainly water, we can use the specific heat capacity of water (4.18 J/g°C) to calculate the heat absorbed by the solution.

The mass of the solution is the sum of the mass of calcium chloride and the mass of water, which is 4 g + 7.5 g = 11.5 g. The temperature change is 32 °C - 15 °C = 17 °C. Therefore, the heat absorbed by the solution is:

Q = m x c x ΔT = 11.5 g x 4.18 J/g°C x 17 °C = 827.37 J

Since the reaction is exothermic (heat is released), the molar enthalpy can be calculated using the following equation:

ΔH = -Q/n

where n is the number of moles of calcium chloride. Plugging in the values, we get:

ΔH = -827.37 J/0.036 mol = -22,982.5 J/mol

Therefore, the molar enthalpy for the reaction of calcium chloride is -22,982.5 J/mol.

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According to the question Given Name: 2-methylbutane IUPAC Name: 2-methylbutane Structure: [tex]CH_3CH_2CH(CH_3)CH_3.[/tex]

Structure is the arrangement or organization of parts or elements in a material, system, or entity. It is essential in understanding how something is composed and how it functions. Examples of structures include the skeletal system of the human body, the structure of a computer program, the structure of a book, or the structure of a business. Structures can be physical or abstract, and are usually determined by the purpose of the material, system, or entity. For example, a bridge is a physical structure designed to support the movement of people, goods, and vehicles across a body of water. A book is an example of an abstract structure, with a specific beginning, middle, and end. The structure of a business might include the organizational hierarchy, the roles and responsibilities of each employee, and the different departments. Knowing the structure of something can help people understand how it works and how to interact with it.

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Answer:

They forge heavy elements in their cores, explode as supernovas, and expel these elements into space.

Explanation:

To find the density of ammonia (NH3) at 646 torr and 10°C, we need to use the Ideal gas law equation:

PV = nRT

Where R is the gas constant, n is the number of moles, P is pressure, V is volume, and T is temperature in Kelvin.

We must first change the pressure from torr to atm:

646 torr = 0.852 atm

The temperature is then changed from Celsius to Kelvin:

10°C + 273.15 = 283.15 K

Now, we can rearrange the ideal gas law equation to solve for density (d):

d = (PM) / (RT)

M is the ammonia's molar mass.

With the supplied values and constants, we obtain:

d = (0.852 atm)(17.04 g/mol) / ((0.0821 atm*L)/(mol*K))(283.15 K)

d = 0.736 g/L

Therefore, the density of ammonia at 646 torr and 10°C is 0.736 g/L.

What do you mean by density of ammonia?

The density of ammonia refers to the mass of ammonia gas per unit volume. The standard temperature and pressure (STP), which is defined as a temperature of 0 degrees Celsius (273.15 Kelvin) and a pressure of 1 atmosphere (101.325 kilopascals or 760 millimeters of mercury), is used to measure the density of ammonia, a colorless gas that is lighter than air.

At STP, the density of ammonia gas is approximately 0.771 grams per liter (g/L) or 0.771 kilograms per cubic meter (kg/m3). However, the density of ammonia can vary depending on the temperature, pressure, and other factors such as the presence of impurities or moisture.

The density of ammonia is an important property in many applications, particularly in the chemical industry. It is used to calculate the amount of ammonia needed for a particular reaction or process, and can also be used to determine the mass or volume of ammonia gas in a storage tank or container.

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When working with a heat source, one should always assume that glassware and metal objects are hot. Option A is correct.

Working with a heat source requires special precautions to ensure safety in the laboratory. Heat sources such as Bunsen burners, hot plates, and ovens can generate high temperatures that can cause burns or fires if not handled properly. One important safety rule when working with a heat source is to assume that glassware and metal objects are hot.

This means that one should avoid touching or handling these objects without protective equipment, even if they appear to be cool or inactive. This is because they may still be hot from exposure to the heat source and can cause burns or injuries. Other safety measures when working with a heat source include using appropriate personal protective equipment, such as heat-resistant gloves and safety goggles, and ensuring good ventilation in the laboratory to prevent exposure to fumes or volatile chemicals. Option A is correct.

What should you do when working with a heat source?

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The discrepancy gap between customer expectations and perceptions towards service quality of front office staff/night auditor is commonly referred to as the "service gap."

This gap arises when customers have certain expectations regarding the level of service they will receive, but their actual perceptions of the service fall short of those expectations.

The service gap can be caused by a variety of factors, including inadequate training of front office staff, poor communication between staff and customers, inconsistencies in service delivery, and failure to meet customer needs and preferences.

To reduce the service gap, it is important for organizations to have a clear understanding of customer expectations and to ensure that their service delivery meets or exceeds those expectations.

This may involve implementing better training programs for front office staff, improving communication with customers, and implementing systems for monitoring and measuring customer satisfaction.

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The combustion of 5 pounds of glyceryl trioleate would release 137,181 kJ of energy in the form of heat, which is equivalent to 137.181 nutritional calories.

The balanced thermochemical equation for the metabolism of glyceryl trioleate is:

To get rid of 5 pounds of glyceryl trioleate by combustion, we need to calculate the number of moles of the fat, which is:

Then, we can calculate the amount of energy released by combustion:

To convert this to nutritional calories, we divide by 1,000:

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175.17 grams of CaCO₃ are produced when 98.2 grams of CaO are reacted with an excess of CO₂ according to the given equation.

To solve this problem, we need to use stoichiometry which deals with the quantitative relationships between reactants and products in chemical reactions.

The balanced chemical equation for the reaction is:

CaO + CO₂ → CaCO₃

This equation tells us that for every 1 mole of CaO and 1 mole of CO₂ that react, we get 1 mole of CaCO₃.

We are given the mass of CaO that is used in the reaction. To calculate the mass of CaCO₃ that is produced, we need to use stoichiometry and the molar mass of CaCO₃.

The molar mass of CaCO₃ is the sum of the atomic masses of one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O). Using the values from the periodic table, we can calculate the molar mass of CaCO₃ as:

molar mass of CaCO₃ = 1 × atomic mass of Ca + 1 × atomic mass of C + 3 × atomic mass of O

                                    = 1 × 40.08 g/mol + 1 × 12.01 g/mol + 3 × 16.00 g/mol

                                    = 100.09 g/mol

To calculate the number of moles of CaO that reacted, we can use the following equation:

n = m/M

where n is the number of moles of CaO, m is the mass of CaO, and M is the molar mass of CaO.

Using the given values, we get:

n = 98.2 g / 56.08 g/mol = 1.749 mol

This is the number of moles of CaO that reacted in the reaction.

Since the reaction is 1:1, meaning that one mole of CaO reacts with one mole of CO₂ to produce one mole of CaCO₃, we know that the number of moles of CaCO₃ produced is also 1.749 mol.

Finally, to calculate the mass of CaCO₃ produced, we can use the following equation:

m = n × M

where m is the mass of CaCO₃ produced, n is the number of moles of CaCO₃ produced, and M is the molar mass of CaCO₃.

Using the given values, we get:

m = 1.749 mol × 100.09 g/mol = 175.17 g

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This indicates that the system's energy drops while the energy of the environment grows. As a result, the ultimate temperature is projected to be greater than the beginning temperature of 28 degrees Celsius.

The process sends heat into the environment since it is exothermic. The heat produced by the reaction is transferred to the surrounding environment, raising the temperature.

This is due to the fundamental rule of thermodynamics, which states that energy cannot be created or destroyed, but only moved from one form to another. In this case, the energy released by the reaction is transferred to the surrounding environment as heat energy, causing the temperature to rise.

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Polonium is a rare and radioactive element that belongs to the group of chalcogens. The coordination number of polonium in a simple cubic lattice is 8.

It is known to crystallize in the simple cubic lattice structure, which is one of the three basic types of crystal lattice structures. In this structure, each polonium atom is located at the corner of a cube, sharing its electrons equally with its neighboring atoms.

The coordination number of an atom in a crystal lattice is the number of nearest neighbor atoms to which it is bonded. In the case of polonium, since each atom is located at the corner of a cube, it is in contact with eight other atoms, which are located at the corners of the adjacent cubes.

The knowledge of the crystal structure and coordination number of polonium is important for understanding its physical and chemical properties, and can also have implications in the fields of materials science, nuclear physics, and medical applications.

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Materials that slow down or impede the transmission of heat through them are called insulators. So the correct answer is the option: a.

They can be used for a multitude of purposes, from keeping cold drinks icy to keeping buildings warm in the winter, thanks to this ability. Insulators function by either using materials with low thermal conductivity or by creating air pockets between the materials. This slows the rate of heat flow by reducing the transmission of heat energy from one side to the other. Insulators are valuable in electrical applications because they can stop electrical current from passing through them. Option: a is correct.

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--The complete Question is, These are materials that heat passes slowly or not at all

a. Insulators

b. Fuel

c. Sun

d. Conductors

e. Heat --

The rate of appearance of [tex]NO_{2}[/tex] is 8.4 x [tex]10^{-7}[/tex] m/s and the rate of appearance of [tex]O_{2}[/tex] is 2.1 x [tex]10^{-7}[/tex] m/s.

Given the reaction: 2[tex]N_{2}O_{5}[/tex](g) → 4[tex]NO_{2}[/tex](g) + [tex]O_{2}[/tex](g)

The rate of decomposition of [tex]N_{2}O_{5}[/tex] is 4.2 x [tex]10^{-7}[/tex] m/s.

a) To find the rate of appearance of [tex]NO_{2}[/tex], we will look at the stoichiometric coefficients in the balanced reaction. For every 2 moles of [tex]N_{2}O_{5}[/tex] decomposed, 4 moles of [tex]NO_{2}[/tex] are produced. So, the ratio is 4:2, which simplifies to 2:1.

Rate of appearance of [tex]NO_{2}[/tex] = (Rate of decomposition of [tex]N_{2}O_{5}[/tex]) x (2/1)
Rate of appearance of [tex]NO_{2}[/tex] = (4.2 x [tex]10^{-7}[/tex] m/s) x 2
Rate of appearance of [tex]NO_{2}[/tex] = 8.4 x [tex]10^{-7}[/tex] m/s

b) For the rate of appearance of [tex]O_{2}[/tex], we will again look at the stoichiometric coefficients. For every 2 moles of [tex]N_{2}O_{5}[/tex] decomposed, 1 mole of [tex]O_{2}[/tex] is produced. The ratio is 1:2.

Rate of appearance of [tex]O_{2}[/tex] = (Rate of decomposition of [tex]N_{2}O_{5}[/tex] ) x (1/2)
Rate of appearance of [tex]O_{2}[/tex] = (4.2 x [tex]10^{-7}[/tex] m/s) x 1/2
Rate of appearance of [tex]O_{2}[/tex] = 2.1 x [tex]10^{-7}[/tex] m/s

Thus, the rate of appearance of [tex]NO_{2}[/tex] is 8.4 x [tex]10^{-7}[/tex] m/s and the rate of appearance of [tex]O_{2}[/tex] is 2.1 x [tex]10^{-7}[/tex] m/s.

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When you measure current, you are measuring the number of: c. Electrons that pass a point in one second.

When measuring current, you are measuring the number of electrons that pass a point in one second.

Current is defined as the flow of electric charge, which is typically the flow of electrons through a conducting material. The unit of current is the ampere (A), which is defined as the flow of one coulomb of charge per second.

In a circuit, current flows from the negative terminal of the battery (where electrons are pushed out) to the positive terminal (where electrons are absorbed). The amount of current in a circuit is determined by the voltage applied (potential difference) and the resistance of the circuit, according to Ohm's Law (I = V/R).

Therefore, measuring current is a way of quantifying the amount of electric charge that is flowing through a circuit per unit time, and it is directly related to the movement of electrons in the circuit.

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The types of chemical bonds present in a material determine the arrangement of atoms or molecules at the microscopic level, which in turn determines the properties of the material at the macroscopic level.

For example, materials with ionic bonds tend to have high melting and boiling points due to the strong electrostatic attraction between positively and negatively charged ions. Covalently bonded materials tend to have lower melting and boiling points due to the weaker intermolecular forces between molecules.

Metallic bonding leads to high electrical and thermal conductivity due to the delocalization of electrons within the metal lattice. These different bond types and resulting material properties are important in understanding the behavior and applications of different materials.

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4666.7 m of sulphur dioxide are formed when 12.5g of iron sulphide ore (pyrite) reacts with oxygen according to the equation at stp.

According to given data,   12.5 g of iron sulphide ore (Pyrite ) reacts with oxygen according to the equation at STP.

We have to find the volume of sulphur dioxide

Mass of iron sulphide = 12.5 g

molar mass of iron sulphide = 120 g/mol

so number of moles of iron sulphide = 12.5/120 = 0.104167 mol

chemical equation of reaction of iron sulphide with oxygen is given as

4FeS₂ + 11O₂ ⇒2Fe₂O₃ + 8SO₂

here  4 mol of FeS₂ gives 8 mole of sulphur dioxide.

⇒1 mol of FeS₂ = 8/4 mol = 2 mol of sulphur dioxide.

⇒0.104167 of FeS₂ = 2 × 0.104167 = 0.208334 mol of Sulphur dioxide.

at STP 1 mol = 22.4 L

so the mass of sulphur dioxide

= 0.208334 × 22.4 L

= 4.6666816 L

= 4666.6816 ml

≈ 4666.7 ml

Therefore the volume of sulphur dioxide is 4666.7 ml.

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The balanced net ionic equation for the given reaction is:

H+ (aq) + OH- (aq) → H₂O (l)

This reaction represents the neutralization of an acid and a base, where the H+ ions from the acid (in this case, H+ from H₃PO₄) react with the OH- ions from the base (in this case, NaOH) to form water (H₂O).

The balanced equation provided in the question involves additional ions, but since those ions are present on both the reactant and product sides of the equation, they do not participate in the net ionic reaction.

The net ionic equation only shows the ions that actually participate in the reaction and undergo a change in oxidation state.

In the given reaction, the calcium ion (Ca₂+) and the phosphate ion (PO₃-) do not undergo any change in oxidation state and remain in their original form in both the reactants and products. Therefore, they cancel out in the net ionic equation.

Overall, the net ionic equation represents a simple acid-base neutralization reaction that results in the formation of water.

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The ionization energy of the ground-state Li atom can be calculated using the given spectral lines and theyhko l.

Here are the steps:

1. Identify the transition wavelengths: 610.36 nm (transition 1), 460.29 nm (transition 2), 413.23 nm (transition 3), and 670.78 nm (transition 4).
2. Convert wavelengths to frequencies using the formula: frequency = speed of light / wavelength. Use c = 3 x 10^8 m/s and convert wavelengths to meters.
3. Calculate the energy of each transition using the formula: energy = h * frequency, where h is Planck's constant (6.626 x 10^-34 Js).
4. Determine the difference in energy between each transition and the transition from the 2P to 2S term (transition 4).
5. The ionization energy corresponds to the smallest energy difference between the transitions and the ground-state transition (transition 4).

By following these steps, you can calculate the ionization energy of the ground-state Li atom.

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The volume of the gold sample containing 1.77x10¹⁹ electrons is approximately 2.51 × 10⁻¹⁸ cm³. This was determined by calculating the mass of the sample first, which was 1.2212 grams, and then using the density of gold to determine the volume.

Assuming that the gold sample is electrically neutral, the number of electrons is equal to the number of protons, which is also the atomic number of gold. Therefore, we can determine the mass of the sample using the atomic weight of gold (196.97 g/mol) and Avogadro's number (6.022 × 10²³ particles/mol):

1.77 × 10¹⁹ electrons x (1 atom Au / 79 electrons) x (196.97 g / 1 mol) x (1 mol / 6.022 × 10²³ atoms) = 4.85 × 10⁻¹⁷ g

Next, we can use the density of gold (19.3 g/cm³) to calculate the volume of the sample:

4.85 × 10 g x (1 cm³ / 19.3 g) = 2.51 × 10⁻¹⁸ cm³

Therefore, the volume of the sample of gold is 2.51 × 10⁻¹⁸ cm³.

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The heat released in the formation of 1.99 grams of sodium hydroxide is -9.60 kJ.

The given equation shows that the formation of 2 moles of NaOH releases 215.76 kJ of heat. Therefore, the formation of 1 mole of NaOH releases 107.88 kJ of heat. To calculate the heat released in the formation of 1.99 grams of NaOH, we need to first convert the given mass into moles. The molar mass of NaOH is 40 g/mol, so 1.99 grams of NaOH is equal to 0.04975 moles.

Now we can use the following formula to calculate the heat released:

Therefore, the heat released in the formation of 1.99 grams of NaOH is -5.37 kJ. However, since the reaction gives off heat, the answer should be reported as a positive value. Therefore, the final answer is 9.60 kJ.

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The root mean square velocity for N2 gas at 11.8 degrees Celsius is approximately 84.15 m/s.

Here's a step-by-step explanation:

1. Convert the given temperature from Celsius to Kelvin: 11.8 degrees Celsius + 273.15 = 284.95 K.

2. Recall the root mean square velocity (v_rms) formula for a gas:
v_rms = √(3RT/M), where R is the gas constant, T is the temperature in Kelvin, and M is the molar mass of the gas in kg/mol.

3. Identify the molar mass (M) of N2 gas. Nitrogen has an atomic mass of 14.0067, and since it's a diatomic molecule (N2), we have to multiply that by 2: 14.0067 * 2 = 28.0134 g/mol. Convert this to kg/mol: 28.0134 / 1000 = 0.0280134 kg/mol.

4. Substitute the given values into the formula:
v_rms = √(3 * 8.3145 J K^-1 mol^-1 * 284.95 K / 0.0280134 kg/mol).

5. Solve for v_rms:
v_rms = √(3 * 8.3145 * 284.95 / 0.0280134) ≈ √(7082.04098) ≈ 84.15 m/s.

So, the root mean square velocity for N2 gas at 11.8 degrees Celsius is approximately 84.15 m/s.

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A few errors about hydrogen peroxide's breakdown can be found throughout the discourse. Instead of being destroyed, the product is transformed into water and oxygen.

Catalase enzymes are found in both plants and animals, and they catalyse the conversion of hydrogen peroxide into water and oxygen. Water and oxygen are naturally formed from hydrogen peroxide, although the process is extremely slow.

Time how long it takes a disc of filter paper to rise a specified distance in a test tube containing hydrogen peroxide solution as one method of determining the rate.

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Ethyl 4-aminobenzoate is likely to dissolve in 3 M HCl as it is a base and can react with the acid to form a salt, which is soluble in water.

The three aromatic compounds are ethyl 4-aminobenzoate, 2-nitrotoluene, and 1,3,5-trimethylbenzene. When these solids are placed in 3 M HCl, only the compound with basic properties (ethyl 4-aminobenzoate) is likely to dissolve. This is because HCl is a strong acid that dissociates completely in water to produce H+ ions.

When HCl is added to a basic compound like ethyl 4-aminobenzoate, the H+ ions react with the lone pair of electrons on the nitrogen atom of the amine group, neutralizing the basicity of the compound and producing a water-soluble salt. On the other hand, the other two compounds, which are not basic, will not react with HCl and will not dissolve in the acidic solution. Therefore, ethyl 4-aminobenzoate is the most likely compound to dissolve in 3 M HCl.

The complete question is
If a solid mixture of the three aromatic compounds shown below is placed in 3 m hcl, which is likely to dissolve?

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The correct matches are:

1.A chemical bond between atoms with similar electronegativities - covalent bond

2. a measure of the ability of an atom to attract electrons within a chemical bond - Electronegativity

3. a bond between atoms of greatly differing electronegativities - Ionic bond

4. the bond formed in metals, holding metals together - Metallic bond

A covalent bond is a bond formed by sharing electrons between two atoms that occur in the bond. It generally forms between atoms with similar electronegativity values.

An ionic bond is a bond formed between two oppositely charged ions of her and held by strong electrostatic attraction. It forms between atoms that have vastly different electronegativities.

Electronegativity is the tendency of an atom in a covalent bond to attract a shared pair of electrons.

A metallic bond is a bond formed by electrostatic attraction between a positively charged metal ion and a conduction electron.

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Answer:

Sharing bond: Covalent

Tendency to attract electrons: Electronegativity

Stable electron configurations: Inert gas

Transferred electrons bond: Ionic

Fructose-1-phosphate is an intermediate in fructose metabolism and is produced by fructokinase. While fructose-1-phosphate can be converted to glucose in the liver via the enzyme fructose-1,6-bisphosphatase, this reaction requires energy and is irreversible.

The potential disadvantage of the synthesis of fructose-1-phosphate is that it traps fructose in the liver cell, which can lead to the formation of advanced glycation end products (AGEs) that are associated with various diseases. However, the conversion of fructose-1-phosphate to glucose would require an enzyme that is specific to  reaction, which may not have evolved in same way as the galactose-1-phosphate to glucose-1-phosphate reaction. It is also possible that  evolutionary advantage of being able to metabolize fructose outweighs the potential disadvantage of the formation of AGEs.

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