Answer:
Explanation:
Given that:
distance (z) = 7.86 m
mass of the person = 81.7 kg
Acceleration (a) = 0.729 m/s²
By using Newton's second law along the vertical axis:
[tex]T - mg = ma\\ \\ T = ma + mg \\ \\ T = m(a+g) \\ \\[/tex]
T = 81.7 (0.729 +9.8)
T = 860.22 N
The work done now is:
[tex]W_T = T\times z \\ \\[/tex]
[tex]W_T = 860.22 \times 7.86[/tex]
[tex]\mathbf{W_T =6761.3292\ N}[/tex]
In which direction does the magnetic field in the center of the coil point?
A. Left
B. Down
C. Right
D. Up
The direction of the magnetic field in the center of the coil point towards the up. So, the correct option is D.
What is right-hand grip rule ?Right-hand grip rule states that, if you are holding a current carrying conductor with your right hand, such that the curled fingers point towards the direction of current flowing through the conductor, then the thumb will point towards the direction of the magnetic field.
Here,
From the current carrying conductor given,
The current is flowing through the conductor in a direction from left to right or it can be said as, the current is flowing in a clockwise direction.
So, we can apply the right-hand grip rule in this conductor.
According to the right-hand grip rule, stretch the thumb of the right hand and point it towards the direction of flow of current in the conductor. Then the remaining curled fingers will be pointed upwards in the conductor.
Hence,
The direction of the magnetic field in the center of the coil point towards the up.
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Proton traveling across a capacitor A proton enters with a velocity v between the plates of a capacitor as shown in the figure. What is the direction of the magnetic field needed so that the proton continues its trajectory, undeflected? Explain each step of your reasoning.
Answer:
Please see the direction of force in the attachment
Explanation:
As the particle enters the capacitor, it experiences electric. In order to move in the same direction as the electron was moving before entering the capacitor, the force due to the electric field of capacitor must be balanced by the magnetic field.
The direction of particle is shown in the attachment.
As we know,
Force = q (v *B)
determine the total voltage in the circuit below the ammeter is reading 4 A
Answer:
6 V.
Explanation:
We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:
Resistor 1 (R₁) = 3 Ω
Resistor 2 (R₂) = 3 Ω
Equivalent Resistance (R) =?
Since the two resistor are in parallel connection, the equivalent resistance can be obtained as:
R = (R₁ × R₂) / (R₁ + R₂)
R = (3 × 3) / (3 + 3)
R = 9/6
R = 1.5 Ω
Finally, we shall determine the total voltage in the circuit. This can be obtained as follow:
Current (I) = 4 A
Equivalent Resistance (R) = 1.5 Ω
Total voltage (V) =?
V = IR
V = 4 × 1.5
V = 6 V
Thus, the total voltage in the circuit is 6 V
the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67
Answer:
[tex]\theta_c = 36.78^o[/tex]
Explanation:
The relationship between the refractive index and the critical angle is given as follows:
[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]
where,
η = refractive index = 1.67
θc = critical angle =?
Therefore,
[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]
[tex]\theta_c = 36.78^o[/tex]
A racing car on a straight accelerates from 100mph to 316 mph in three seconds what is the acceleration?
Answer:
72mph/sec
Explanation:
The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:
216mph / 3sec = 72mph/sec, our final answer
Hope it made sense. I would appreciate Brainliest, but no worries.
In the nitrogen cycle, plants take in nitrates and convert them into
HELP PLEASEE
when a person receives an electric shock from wires , is he most affected by a spark, corona, arc or humus solution?
Answer:
Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.
Explanation:
A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen spectral line with a wavelength of 656 nm is seen 60.0 cm to one side of the center. Then, the hydrogen lamp is replaced with an unknown lamp. A spectral line is seen on the screen 36.4 cm away from the center. What is the wavelength of this spectral line
Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ
sin θ = y / L
we substitute
[tex]d \ \frac{y}{L}[/tex] = m λ
with the initial data we look for the distance between the lines
d = [tex]\frac{m \lambda \ L}{y}[/tex]
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Why are objects that fall near Earth's surface rarely in free fall?
O Gravity does not act on objects near Earth's surface.
O Air exerts forces on falling objects near Earth's surface.
O The objects do not reach terminal velocity.
O The objects can be pushed upward by gravity.
Answer:
Air exerts forces on falling objects near earth's surface
Explanation:
Falling objects are typically subject to air resistance which prevents the force of gravity on the object
Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have the frequency 440 Hz and the note E should be at 659 Hz. The tuner can determine this by listening to the beats between the third harmonic of the A and the second harmonic of the E. A tuner first tunes the A string very precisely by matching it to a 440 Hz tuning fork. She then strikes the A and E strings simultaneously and listens for beats between the harmonics. What beat frequency indicates that the E string is properly tuned
Answer:
The beat frequency = 2.0 Hz
Explanation:
From the given information
The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.
i.e.
[tex]f_{3A} = 3f_A[/tex]
where;
[tex]f_A =[/tex] note A fundamental freq.
replacing 440 Hz for [tex]f_A[/tex]
[tex]f_{#a} = 3 (440 \ Hz)[/tex]
[tex]f_{3A} = 1320 Hz[/tex]
However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.
i.e.
[tex]f_{2E} = 2f_E[/tex]
[tex]f_E =[/tex] note E fundamental freq.
replacing 659 Hz for [tex]f_E[/tex]
[tex]f_{2E} = 2(659)[/tex]
[tex]f_{2E} = 1318 \ Hz[/tex]
Finally, the beat frequency when the E string is properly tuned is:
[tex]\Delta f = f_{3A}-f_{2E}[/tex]
[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]
[tex]\Delta f = 2.0 \ Hz[/tex]
Thus, the beat frequency = 2.0 Hz
An object has a mass of 50 kg on Earth. What would be the mass of that object in the Moon
It would be 50 kg.
Mass doesn't change.
Weight can.
Philosophy: The Big Picture Unit 8
Would an existentialist argue that the study of philosophy was a good use of a life?
A. Yes, if society valued the results of the study.
B. Yes, but only if the individual found it meaningful.
C. No, a life should be spent minimizing the role of anxiety.
D. No, there is no way that philosophy could create a meaningful life.
A car on a roller coaster loaded with passengers has a mass of 2.0 x 10^3 kg. At the lowest point of the the track, the radius of curvature is 24 m and the roller coaster car has a tangential speed of 17 m/s
We have that the is mathematically given as
Fn=36000N
ForceQuestion Parameters:
mass of 2.0 x 10^3 kg
the radius of curvature is 24 m and
the roller coaster car has a tangential speed of 17 m/s
Generally the equation for the Force is mathematically given as
F=ma
Fn-fg=mv^2/r
Fn=m(v^2/r+g)
Therefore
Fn=2000(12^2/18+9.8)
Fn=36000N
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Determine the activity of the sample of cerium when the sample was 80 seconds old
Answer is in a photo. I can only upload it to a file hosting service. link below!
bit.[tex]^{}[/tex]ly/3a8Nt8n
What is the mass of a jet that accelerates at 4 m/s2 after a 4,000 N force from the engines?
Answer:
1000kg
Explanation:
F=MA
Rearrange the formula: M=F/A
plug in values for F (force), and A (acceleration).
M=4000/4
M=1000kg
i think.
not sure tho.
The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
What is Newton's second law of motion?Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.
Rearranging the formula to solve for mass, we get:
m = F / a
Substituting the given values, we get:
[tex]m = 4000 N / 4 m/s^2[/tex]
m = 1000 kg
Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
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As you know a cube with each side 4 m in length has a volume of 64m3. Each side of the cube is now doubled in length. What is the ration if the new volume to the old volume
Answer:
The ratio of the new volume to the old volume is 8 to 1.
Explanation:
Let's first list what we know:
A cube has sides with lengths of 4 mThe volume of the cube is 64 [tex]m^3[/tex]The new cube has sides double the length of the old cubeSince the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.
The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.
Now, let's solve for the volume of the new cube:
[tex]V = s^3[/tex]
[tex]V = 8^3[/tex]
[tex]V = 512[/tex]
The volume of the new cube is 512 [tex]m^3[/tex].
The ratio of the new volume to the old volume is 512 : 64.
Let's simplify the ratio:
512 : 64
8 : 1
The ratio of the new volume to the old volume is 8 to 1.
P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)
Calculate the work done to push a 200-N object 5-meters
A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 5.80 ft from the mirror on the left wall and 13.7 ft from the mirror on the right wall.
Answer:
Explanation:
When the person stands 5.80 ft from the mirror of the wall.
a) The first image is found by multiplying the distance of the left mirror to the person.
i.e.
2 × 5.80 = 11.6 ft
b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.
i.e.
(2 × 13.7 ) + 11.6
= 39 ft
c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.
(2 × 5.80) + 39
= 50.6 ft
What is meant by the terms critical mass and supercritical?
Answer:
Critical mass is the minimum mass of fissionable material required to sustain a nuclear fission reaction, and a supercritical mass, which will provide more than enough neutrons to sustain a fission reaction at the time of detonation.
Explanation:
What is the gravitational potential energy of a 4 kg bowling ball 1 m above the ground?
Answer:
40 J
Explanation:
Gpe= mgh
=4*10*1
=40
Families attempting to rebound from crises are advised to discontinue family rituals and leisure activities, as they may regenerate negative family stress and threaten resilience.
A. False
B. True
A ball is rolling down a hill. Wich action would slow the ball down?
The weight of an object is the force pulling the object:
a. upward
b. to the side.
c. in all directions
d. downward
Give the relationship between the number of valence electrons in an atom's
valence electron shell and the position of the element on the Periodic Table
Answer:
they're reactions
Explanation:
The relationship between the valence electrons and position is: the number of valence electrons determines the position
What is valence electron?This is the number of electrons in the outermost shell of an atom.
NOTE: The outermost shell is called valence shell
Position in Periodic tableThis is where an element is located in the periodic table
Relationship between valence electrons and positionThe position of an element in the periodic table is determined by the number of valence electrons.
For example
Sodium, Na (atomic number of 11) has the following electronic configuration
1st shell = 2 electrons2nd shell = 8 electrons 3rd (valence) shell = 1 electronSince the valence electron is 1, thus, sodium is located in group 1 of the periodic table.
Thus, we can see that the position of an element in the periodic table is related to the valence electron(s) in the atomic shell of the element.
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the ice and steam point on a thermometer are found to be 96ml apart. what temperature is recorded when the length of mercury thread is 33.6ml above the ice point
Answer:
33.6 / 96 is the fraction of the temperature between ice and freezing
33.6 / 96 = .35
So C = .35 * 100 = 35 deg C where the ice point would be 0 deg C
You can convert C to F
F = 9 / 5 * C + 32 = 9/5 * 35 + 32 = 95 deg F
if the root mean square speed of a gas particle is 200 m/s at a temperature of 400k, at what approximate temperature will urms when kelvin temperature equals 350 m/s
Answer:
The correct solution is "1230 K".
Explanation:
The given values are:
[tex](V_{rms})_1= 200 \ m/sec[/tex]
[tex](V_{rms})_2= 350 \ m/sec[/tex]
[tex]T_1=400 \ K[/tex]
As we know,
⇒ [tex]V_{rms} \propto \sqrt{T}[/tex]
or,
⇒ [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]
On substituting the values, we get
⇒ [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]
⇒ [tex]T_2=1230 \ K[/tex]
1 kg block slides down a frictionless inclined plane that makes an angle of 300 with respect to the ground. The total length of the plane is 2 m, but midway down it collides with a second block, weighing 0.5 kg. The two blocks stick together and travel as one unit the rest of the way down the ramp. What is the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane
Answer:
the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
Explanation:
Given that the data in the question;
angle of inclination with respect to the ground [tex]\theta[/tex] = 30°
length of plane d = 2m
m₁ = 1 kg
m₂ = 0.5 kg
now, velocity of the first block at midpoint;
[tex]\frac{1}{2}[/tex]mv² = mgsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
[tex]\frac{1}{2}[/tex]v² = gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]
v² = gsin[tex]\theta[/tex]d
v = √( gsin[tex]\theta[/tex]d)
g is 9.8 m/s
so we substitute
v = √( 9.8 × sin30° × 2)
v = √( 19.6 )
v = 3.13 m/s
Now, velocity just after collision of the blocks will be;
(m₁ + m₂)v₂ = m₁v
v₂ = m₁v / (m₁ + m₂)
we substitute
v₂ = (1 × 3.13) / (1 + 0.5)
v₂ = 3.13 / 1.5
v₂ = 2.0866 m/s
now, final kinetic energy will be;
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + Initial Kinetic energy
[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + [tex]\frac{1}{2}[/tex]mv₂²
we substitute
[tex]KE_f[/tex] = [(1 + 0.5)9.8 × sin30 × [tex]\frac{2}{2}[/tex]] + [[tex]\frac{1}{2}[/tex] × 1.5 × 2.0866 ]
[tex]KE_f[/tex] = 7.35 + 3.2654
[tex]KE_f[/tex] = 10.62 J
Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J
what happens to a neutron that is not attached to a proton?
gravitational potential is the energy due to an object's:
a. motion
b. spring stretch or compression
c. position in a gravity field
d. chemical bonds.
position in a gravitation field (c)
Answer:
The answer is C. position in a gravity field
A 1.50x103-kilogram car is traveling east at 30 meters per second.
The brakes are applied and the car is brought to rest in 9.00 seconds.
A. Calculate the magnitude of the total impulse applied to the car to
bring it to rest. [Show all work, including the equation and
substitution with units.]
B. State the direction of the impulse applied to the car. [East or
West?]
PLEASE HELP!!!!
Answer:
[tex]39000\ \text{kg m/s}[/tex]
West
Explanation:
m = Mass of car = [tex]1.3\times 10^{3}\ \text{kg}[/tex]
t = Time = 9 seconds
u = Initial velocity = 30 m/s
v = Final velocity = 0
Impulse is given by
[tex]J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}[/tex]
The magnitude of the total impulse applied to the car to bring it to rest is [tex]39000\ \text{kg m/s}[/tex].
The direction is towards west as the sign is negative.
