Answers
Answer:
x = 20
Step-by-step explanation:
x° + 2x° + (x+10)° = 90°
3x° + x° + 10° = 90°
4x° + 10° = 90°
4x° = 90°-10°
4x° = 80°
x = 80/4
x = 20
Answer:
20°
Step-by-step explanation:
The sum of all three angles combined is 90°. You can see this by the square at the corner. This means that you have to add all of the angles together and set it equal to 90° to solve for x.
x° + 2x° + (x + 10)° = 90°
3x° + (x + 10)° = 90°
4x° + 10° = 90°
4x° = 80°
x = 20°
Related Questions
The owner of Limp Pines Resort wanted to know the average age of its clients. A random sample of 25 tourists is taken. It shows a mean age of 46 years with a standard deviation of 5 years. The width of a 95 percent CI for the true mean client age is approximately: _________
Answers
Given Information:
Sample size = n = 25
Mean age of client = 46 years
Standard deviation of age of client = 5 years
Confidence level = 95%
Required Information:
Width of the confidence interval = ?
Answer:
[tex]$ \text {width of CI } = \pm 2.064 $\\\\[/tex]
Step-by-step explanation:
The width for the true mean client age is given by
[tex]$ \text {width of CI } =\pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $[/tex]
Where n is the sample size, s is the standard deviation of age of client, and [tex]t_{\alpha/2}[/tex] is the t-score corresponding to 95% confidence level.
The t-score corresponding to 95% confidence level is
Significance level = 1 - 0.95 = 0.05/2 = 0.025
Degree of freedom = n - 1 = 25 - 1 = 24
From the t-table at α = 0.025 and DF = 24
t-score = 2.064
[tex]$ \text {width of CI } = \pm (2.064)(\frac{5}{\sqrt{25} } ) $\\\\[/tex]
[tex]$ \text {width of CI } =\pm (2.064)(\frac{5}{5 } ) $\\\\[/tex]
[tex]$ \text {width of CI } = \pm (2.064)(1) $\\\\[/tex]
[tex]$ \text {width of CI } = \pm 2.064 $\\\\[/tex]
Therefore, width of the 95% confidence Interval for the true mean client age is approximately ±2.064.
Bonus:
The corresponding 95% confidence interval is given by
[tex]$ \text {Confidence Interval } = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $[/tex]
Where x_bar is the mean client age
[tex]$ \text {Confidence Interval } = 46 \pm 2.064 $[/tex]
[tex]$ \text {Confidence Interval } = (43.936, 48.064) $[/tex]
[tex]$ \text {Confidence Interval } = (44, 48) $[/tex]
Which means that we are 95% sure that the true mean client age is within the range of (44, 48) years.
What’s the correct answer for this question?
Answers
Answer:
0.37
Step-by-step explanation:
As shown in table,
The probability of the fruit is orange is P(A) = 0.3
The probability of the fruit is organic is P(B)
The probability of the fruit is orange and organic is P(A⋂B) = 0.11
=> The probability that a randomly selected orange is organic is calculated by applying the conditional probability formula:
P(B|A) =P(A⋂B)/P(A) = 0.11/0.3 = 0.37
=> Option D is correct
Hope this helps!
Question one answer: S²=3V/H
What is the opposite operation of squaring? Using this opposite operation, rewrite the equation from question 1 so s is by itself on one side of the equation.
Step by step answer
Answers
Answer:
[tex]\ S=\sqrt{\dfrac{3V}{H}}}[/tex]
Step-by-step explanation:
The opposite operation of squaring is taking the square root.
[tex]\ S=\sqrt{\dfrac{3V}{H}}}[/tex]
We know that the denominator of a fractional power is the index of the corresponding root:
[tex]\displaystyle x^\frac{1}{n}=\sqrt[n]{x}[/tex]
For n=2, we don't usually write the index in the root symbol:
[tex]x^{\frac{1}{2}}=\sqrt{x}[/tex]
In the case of this problem, ...
[tex](S^2)^{\frac{1}{2}}=\left(\dfrac{3V}{H}\right)^{\frac{1}{2}}\\\\S=\sqrt{\dfrac{3V}{H}}[/tex]
A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) At what rate is his distance from second base decreasing when he is halfway to first base? (Round your answer to one decimal place.) ft/s (b) At what rate is his distance from third base increasing at the same moment? (Round your answer to one decimal place.)
Answers
Answer:
Step-by-step explanation:
Given that :
the side of the square = 90ft
The speed of the runner = 31 ft/sec
By the time the runner is halfway to the first base; the distance covered by the runner in time(t) is (31 t) ft and the distance half the base = 90/2 = 45 ft
Thus; 31 t = 45
t = 45/31
From the second base ; the distance is given as:
P² = (90)² + (90 - 31t )²
P = [tex]\sqrt{(90)^2 + (90 - 31t )^2}[/tex]
By differentiation with time;
[tex]\dfrac{dP}{dt} =\dfrac{1}{ 2 \sqrt{90^2 +(90-31t)^2} } *(0+ 2 (90-31t)(0-31))[/tex]
[tex]\dfrac{dP}{dt} =\dfrac{1}{ 2 \sqrt{90^2 +(90-31t)^2} } * 2 (-31)(90-31t)[/tex]
At t = 45/31
[tex]\dfrac{dP}{dt} =\dfrac{1}{ 2 \sqrt{90^2 +45^2} } * 2 (-31)(45)[/tex]
[tex]\dfrac{dP}{dt} =\dfrac{-35*45}{100.623}[/tex]
= - 13.86 ft/sec
Hence, we can conclude that as soon as the runner is halfway to the first base, the distance to the second base is therefore decreasing by 13.86 ft/sec
b) The distance from third base can be expressed by the relation:
q² = (31t)² + (90)²
[tex]q = \sqrt{(31t)^2+(90)^2}[/tex]
By differentiation with respect to time:
[tex]\dfrac{dq}{dt} = \dfrac{1}{2\sqrt{90^2 + (31)t^2} } *(0+31^2 + 2t)[/tex]
At t = 45/31
[tex]\dfrac{dq}{dt} = \dfrac{1}{2\sqrt{90^2 + 45^2} } *(0+31^2 + \frac{45}{31})[/tex]
[tex]= \dfrac{31*45}{100.623}[/tex]
[tex]= 13.86 \ ft/sec[/tex]
Thus, the rate at which the runner's distance is from the third base is increasing at the same moment of 13.86 ft/sec. So therefore; he is moving away from the third base at the same speed to the first base)
a) The distance from second base is decreasing when the batter is halfway to first base at a rate of 13.9 feet per second.
b) The distance from third base is increasing when the batter is halfway to first base at a rate of 13.9 feet per second.
a) As the batter runs towards the first base, both the distance from second base and the length of the line segment PQ decrease in time. The distance from the second base is determined by Pythagorean theorem:
[tex]QS^{2} = QP^{2}+PS^{2}[/tex] (1)
By differential calculus we derive an expression for the rate of change of the distance from second base ([tex]\dot QS[/tex]), in feet per second:
[tex]2\cdot QS \cdot \dot{QS} = 2\cdot QP\cdot \dot{QP} + 2\cdot PS\cdot \dot {PS}[/tex]
[tex]\dot{QS} = \frac{QP\cdot \dot QP + PS\cdot \dot{PS}}{QS}[/tex]
[tex]\dot {QS} = \frac{QP\cdot \dot {QP}+PS\cdot \dot {PS}}{\sqrt{QP^{2}+PS^{2}}}[/tex] (2)
If we know that [tex]QP = 0.5L[/tex], [tex]PS = L[/tex], [tex]L = 90\,ft[/tex], [tex]\dot {QP} = -31\,\frac{ft}{s}[/tex] and [tex]\dot {PS} = 0\,\frac{ft}{s}[/tex], then the rate of change of the distance from second base is:
[tex]\dot {QS} = \frac{(45\,ft)\cdot \left(-31\,\frac{ft}{s} \right)}{\sqrt{(45\,ft)^{2}+(90\,ft)^{2}}}[/tex]
[tex]\dot {QS} \approx -13.864\,\frac{ft}{s}[/tex]
The distance from second base is decreasing when the batter is halfway to first base at a rate of 13.9 feet per second.
b) As the batter runs towards the first base, both the distance from third base increases and the distance from home increase in time. The distance from the third base is determined by Pythagorean theorem:
[tex]QT^{2} = HT^{2}+QH^{2}[/tex] (3)
By differential calculus we derive an expression for the rate of change of the distance from third base ([tex]\dot QT[/tex]), in feet per second:
[tex]2\cdot QT\cdot \dot{QT} = 2\cdot HT\cdot \dot {HT} + 2\cdot QH\cdot \dot {QH}[/tex]
[tex]\dot {QT} = \frac{HT\cdot \dot {HT}+QH\cdot \dot {QH}}{QT}[/tex]
[tex]\dot {QT} = \frac{HT\cdot \dot {HT}+QH\cdot \dot {QH}}{\sqrt{HT^{2}+QH^{2}}}[/tex]
If we know that [tex]HT = 90\,ft[/tex], [tex]QH = 45\,ft[/tex], [tex]L = 90\,ft[/tex], [tex]\dot{HT} = 0\,\frac{ft}{s}[/tex] and [tex]\dot {QH} = 31\,\frac{ft}{s}[/tex], then the rate of change of the distance from third base is:
[tex]\dot{QT} = \frac{(45\,ft)\cdot \left(31\,\frac{ft}{s} \right)}{\sqrt{(90\,ft)^{2}+(45\,ft)^{2}}}[/tex]
[tex]\dot{QT} \approx 13.864\,\frac{ft}{s}[/tex]
The distance from third base is increasing when the batter is halfway to first base at a rate of 13.9 feet per second.
We kindly invite to check this question on rates of change: https://brainly.com/question/13103052
A boxplot of weights (in grams) for 578 chicks is given. The right hand axis marks the five number summary. Use this plot to decide if the following statement is true or false. A chick weighing 300 grams is an outlier. [Note: use the Upper Fence criterion].a) trueb) false
Answers
Answer:
the anwser is in the text
Step-by-step explanation:
what are the cubic units? Pleaseee
Answers
Answer: pls mark me brainiest
Step-by-step explanation:
I am very sure that the answer is V≈351.86
Answer:
112π
Step-by-step explanation:
Cubic units are units when talking in the 3rd dimension
The volume of a cylinder is πr² x h
find the area of the base first.
since we can write it in terms of π, don't worry about decimals.
The radius is 4.
plug it in, the base's area is 16π. Multiply that by the height, 7.
16(7)π
112π is the volume
The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces. If a random sample of sixty-five 16-ounce beverage cans are selected, what is the probability that the mean of this sample is less than 16.1 ounces of beverage? Answer: (round to 4 decimal places)
Answers
Answer:
The probability that the mean of this sample is less than 16.1 ounces of beverage is 0.0537.
Step-by-step explanation:
We are given that the average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces.
A random sample of sixty-five 16-ounce beverage cans are selected
Let [tex]\bar X[/tex] = sample mean amount of a beverage
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean amount of a beverage = 16.18 ounces
[tex]\sigma[/tex] = standard deviation = 0.4 ounces
n = sample of 16-ounce beverage cans = 65
Now, the probability that the mean of this sample is less than 16.1 ounces of beverage is given by = P([tex]\bar X[/tex] < 16.1 ounces)
P([tex]\bar X[/tex] < 16.1 ounces) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\frac{16.1-16.18}{\frac{0.4}{\sqrt{65} } }[/tex] ) = P(Z < -1.61) = 1 - P(Z [tex]\leq[/tex] 1.61)
= 1 - 0.9463 = 0.0537
The above probability is calculated by looking at the value of x = 1.61 in the z table which has an area of 0.9591.
The city of Ventura would like to build a seawall to protect the city from the threat of tsunamis. Each additional inches of height further protects the city and the 100 residents are each willing to pay $10 per inch of seawall height, regardless of how many inches are provided. The cost of building a wall that is i inches high is given by c(i) = 6i^2. What is the Pareto Optimal height for the seawall?
Answers
Answer:
The Pareto Optimal height is [tex]i = 100 \ inch[/tex]
Step-by-step explanation:
The Pareto Optimal height is a height of the seawall at which an increase in wall height will exceed the amount the resident are willing to pay and a decrease will affect the protection of the city
The number of residents is [tex]n = 100[/tex]
The amount each are willing to pay is [tex]z=[/tex]$10 per inch
The cost of building a wall that is i inches high is given by [tex]c(i) = 6i^2.[/tex]
The total amount the residents are willing to pay is
[tex]n = 100 * 10[/tex] = $1000
The maximum cost is mathematically represented as
[tex]\frac{dc(i)}{di} = 10i[/tex]
which implies that
1000 = 10i
Hence the Pareto Optimal height is
=> [tex]i = \frac{1000}{10}[/tex]
[tex]i = 100 \ inch[/tex]
What’s the correct answer for this?
Answers
Answer:
x = 19
Step-by-step explanation:
In the attached file
Harriet spins this 6 colour spinner and flips a coin.
What is the probability of getting grey and tails?
Answers
Answer: 9%
Step-by-step explanation:
In probabilities; when two or more conditions must be met, the "and" operator is used. The probability of grey and tails is 1/12
From the attached spinner, we have:
[tex]Grey = 1[/tex]
[tex]n =6[/tex] --- partitions
So, the probability of landing on grey is:
[tex]P(Grey) = \frac{Grey}{n}[/tex]
This gives:
[tex]P(Grey) = \frac{1}{6}[/tex]
In a coin, we have:
[tex]Tail = 1[/tex]
[tex]n =2[/tex] --- faces
So, the probability of tail is:
[tex]P(Tail) = \frac{Tail}{n}[/tex]
[tex]P(Tail) = \frac{1}{2}[/tex]
The probability of grey and tail is:
[tex]Pr = P(Grey) \times P(Tail)[/tex]
[tex]Pr = \frac{1}{6} \times \frac{1}{2}[/tex]
[tex]Pr = \frac{1}{12}[/tex]
Hence, the probability of getting grey and tail is 1/12
Read more on probability at:
https://brainly.com/question/13957582
Simplify the given expression. Cite a property from Theorem 6.2.2 for each step. (A − (A ∩ B)) ∩ (B − (A ∩ B)) Let A and B be any sets. Then (A − (A ∩ B)) ∩ (B − (A ∩ B)) = = (A ∩ (A ∩ B)c) ∩ (B ∩ (A ∩ B)c) = A ∩ ((A ∩ B)c ∩ (B ∩ (A ∩ B)c)) = A ∩ (((A ∩ B)c ∩ B) ∩ (A ∩ B)c) = A ∩ ((B ∩ (A ∩ B)c) ∩ (A ∩ B)c) = A ∩ (B ∩ ((A ∩ B)c ∩ (A ∩ B)c)) = A ∩ (B ∩ (A ∩ B)c) = (A ∩ B) ∩ (A ∩ B)c = ∅
Answers
Answer:
Step-by-step explanation:
Consider the sets A and B
(A − (A ∩ B)) ∩ (B − (A ∩ B))
= (A ∩ (A ∩ B)c) ∩ (B ∩ (A ∩ B)c) by the set difference law
= (A ∩ (Ac ∩ B)c) ∩ (B ∩ (Ac ∩ B)c) by De Morgan's law
= {(A ∩ Ac) ∪ (A ∩ Bc)} ∩ {(B ∩ Ac) ∪ (B ∩ Bc)} by the distributive law
= {∅ ∪ (A ∩ Bc)} ∩ {(B ∩ Ac) ∪ ∅} by complementation
= {A ∩ Bc} ∩ {B ∩ Ac} by identity law
= (A ∩ Ac) ∩ (B ∩ Ac) by the associative law
= ∅ ∩ ∅ by complementation
= ∅ by the universal bound law
Therefore, (A − (A ∩ B)) ∩ (B − (A ∩ B)) = ∅
Answer:
Considere los conjuntos A y B
(A − (A ∩ B)) ∩ (B − (A ∩ B))
= (A ∩ (A ∩ B)c) ∩ (B ∩ (A ∩ B)c) por la ley de diferencia establecida
= (A ∩ (Ac ∩ B)c) ∩ (B ∩ (Ac ∩ B)c) por la ley de De Morgan
= {(A ∩ Ac) ∪ (A ∩ Bc)} ∩ {(B ∩ Ac) ∪ (B ∩ Bc)} por la ley distributiva
= {∅ ∪ (A ∩ Bc)} ∩ {(B ∩ Ac) ∪ ∅} complementando
= {A ∩ Bc} ∩ {B ∩ Ac} por ley de identidad
= (A ∩ Ac) ∩ (B ∩ Ac) por la ley asociativa
= ∅ ∩ ∅ complementando
= ∅ por la ley universal consolidada
Step-by-step explanation:
) Tara earns twice as much per hour as Kayte.
Kayte earns $3 more per hour than Austin. As
a group, they earn $41 per hour. What is
Austin's hourly wage?
Answers
Answer:
Austin's hourly wage is $8.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
Tara's hourly wage is x.
Kayte's hourly wage is y.
Austin's hourly wage is z.
Tara earns twice as much per hour as Kayte.
This means that [tex]x = 2y[/tex]
Kayte earns $3 more per hour than Austin.
This means that [tex]y = z + 3[/tex]
As a group, they earn $41 per hour.
This means that [tex]x + y + z = 41[/tex]
What is Austin's hourly wage?
This is z.
[tex]x + y + z = 41[/tex]
[tex]y = z + 3[/tex] and [tex]x = 2y[/tex], so [tex]x = 2(z + 3) = 2z + 6[/tex]
[tex]x + y + z = 41[/tex]
[tex]2z + 6 + z + 3 + z = 41[/tex]
[tex]4z + 9 = 41[/tex]
[tex]4z = 32[/tex]
[tex]z = \frac{32}{4}[/tex]
[tex]z = 8[/tex]
Austin's hourly wage is $8.
Answer:
Austin's hourly wage is $8.
Step-by-step explanation:
We can write this problem as a system of linear equations.
We define T: Tara's hourly wage, A: Austin's hourly wage and K: Kayte's hourly wage.
Then, if Tara earns twice as much per hour as Kayte, we have:
[tex]T=2K[/tex]
If Kayte earns $3 more per hour than Austin, we have:
[tex]K=A+3[/tex]
And if they earn $41 per hour as a group, we know:
[tex]T+K+A=41[/tex]
We can use all equations to replace in the third one, as:
[tex]T+K+A=41\\\\(2K)+K+A=41\\\\3K+A=41\\\\3(A+3)+A=41\\\\3A+9+A=41\\\\4A=41-9=32\\\\A=32/4=8[/tex]
Austin's hourly wage is $8.
The segments are tangents to the circle. Find the perimeter of JLNQ.
The perimeter of the polygon is
Answers
Answer:
36 Units.
Step-by-step explanation:
In the diagram attached, K, M, P and R are points of tangency.
Theorem: Tangents to a circle from the same point are equal.
By the theorem above,
LK=LM=6 Units
NM=NP=2 Units
QP=QR=7 Units
JR=JK=3 Units
Therefore:
JL=JK+KL=3+6=9 Units
LN=LM+LN=6+2=8 Units
NQ=NP+PQ=2+7=9 Units
QJ=QR+RJ=7+3=10 Units
Therefore, the perimeter of the polygon JLNQ =9+8+9+10
=36 Units.
Note: The second diagram shows the theorem already applied.
Some people say Mauna Kea is a taller mountain than Mt. Everest, because its total under sea and above sea level height is
a0 meters.
Answers
Answer:
Mauna Kea has from the base that is to say the deepest 10 km of height that is to say 10,000 m which is equivalent to being higher than Mount Everest.jj
Step-by-step explanation:
The main reason why we could say that Mauna Kea is the highest mountain, even surpassing Mount Everest, is because of its altitude if we compare them we see the difference; for example Mauna Kea from its base that is to say from the deepest the ocean measures 10,000 m of altitude, on the other hand the Mount Everest has an altitude of 8848 meters (29,029 ft) above sea level, that is to say from its base it measures 8848 m altitude.
A group of hikers buy 8 bags of trail mix. Each bag contains 3 1/2 cups of trail mix. The trail mix is shared evenly among 12 hikers. How many cups of trail mix will each hiker receive?
Each hiker will receive cups of trail mix.
Answers
Answer:
Each hiker will get 2 1/3 cups
Step-by-step explanation:
8 bags multiplied by 3.5
28 cups overall
The 28 cups is shared between 12 hikers
28/12=2 1/3 cups
Find the roots of the polynomial function f(x)=x^3+2x^2+x
Answers
Answer:
0 and -1
Step-by-step explanation:
Hello,
[tex]x^3+2x^2+x = x(x^2+2x+1)=x(x+1)^2[/tex]
so the roots are
0 and -1 (to get x+1=0 )
do not hesitate if you need further explanation
hope this helps
Answer:
It's actually X = 0, X = - 1, with multiplicity 2, Option D, on Edge2020
Step-by-step explanation:
I just did it on edge :)
Emma and Max want to buy a house together.
Emma earns £18,500 and Max earns £22,500. They have £6000 savings.
They want to buy a house that is being sold for £130,000.
They will pay the deposit with their savings and take out a mortgage to pay for the rest.
Emma and Max can borrow 3 times their combined incomes as a mortgage.
They will need to pay 5% of the selling price of the value as a deposit.
How much can they borrow as a mortgage?
Answers
Answer:
£123,000
Step-by-step explanation:
Their combined income is ...
£18,500 +22,500 = £41,000
They can borrow 3 times this amount, or ...
3 × £41,000 = £123,000
__
Comment on this transaction
The required deposit is 5% of 130,000 = 6,500, which is more than their savings. After this down payment is made, the remaining value is £123,500, which exceeds their borrowing power. It appears that Emma and Max need to find a house with a lower price.
Each contestant in the Hunger Games must be trained to compete. Suppose that the time it takes to train a contestant has mean 5 days and standard deviation 4 days, independent of the time it takes other contestants to train. If the Hunger Games has 100 contestants to train, approx imate the probability that it will take less than 450 days to train all the contestants. Leave your answer in terms of the standard normal distribution phi(a).
Answers
Answer:
11.51% probability that it will take less than 450 days to train all the contestants.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the sum of n variables, the mean is [tex]\mu*n[/tex] and the standard deviation is [tex]s = \sigma\sqrt{n}[/tex]
In this question:
[tex]n = 100, \mu = 100*5 = 500, s = 4\sqrt{100} = 40[/tex]
Approximate the probability that it will take less than 450 days to train all the contestants.
This is the pvalue of Z when X = 450.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{450 - 500}{40}[/tex]
[tex]Z = -1.2[/tex]
[tex]Z = -1.2[/tex] has a pvalue of 0.1151
11.51% probability that it will take less than 450 days to train all the contestants.
In choosing what music to play at a charity fund raising event, Cory needs to have an equal number of piano sonatas from J. S. Bach, Haydn, and Wagner. If he is setting up a schedule of the 9 piano sonatas to be played, and he has 5 J. S. Bach, 52 Haydn, and 5 Wagner piano sonatas from which to choose, how many different schedules are possible
Answers
Answer:
2,210,000 different schedules
Step-by-step explanation:
Cory needs to have an equal number of piano sonatas from J. S. Bach, Haydn, and Wagner.
Since he is setting up a schedule of 9 piano sonatas to be played, he needs:
3 out of 5 J. S. Bach piano sonatas3 out of 52 Haydn piano sonatas3 out of 5 Wagner piano sonatasWe then calculate how many different schedules are possible using combination.
Number of possible Schedules
[tex]=$ ^5C_3$ \times ^{52}C_3$ \times ^5C_3\\=10 \times 22100 \times 10\\$=2210000 ways[/tex]
There are 2,210,000 different possible schedules.
and simplify this too
Answers
Answer:
-5x^4
Step-by-step explanation:
Cube root of -125 is -5
Cube root of n^12 is n^4
Answer:
3 x (-125n^12)^1/2
Step-by-step explanation:
HELP PLEASE WILL MARK AS BRAINLIST
Answers
Answer:
If x + 5x = 90, 6x = 90 so x = 15, 5x = 75.
Answer: x= 15, 5x=75
Step-by-step explanation:
x=15
x+5x=90
Add similar elements
6x=90
6x/6=90/6
x=15
5x=75
x=15
5x=15x5
15x5=75
James grows corn on 1/4 of his land. If he has 65 acres of land, how much of the
land is used for growing corn?
acres
Answers
Answer:
16.25 acres
Step-by-step explanation:
If corn is 1/4 of the land and we have 65 acres, we merely multiply 1/4 to 65.
You get 16.25 acres.
Answer:
16.25acres
Step-by-step explanation:
65/4=16.25 or 16 and 1/4
How much will a person pay for 11.6 pounds of bananas at a price of 1.51 per pound?
Answers
Answer:
17.52
Step-by-step explanation:
literally 11.6 x 1.51 and then round to hundredth place
How to do arithmetic sequence with fractions I’m so confused
Answers
Answer:
Step-by-step explanation:
first you have to see itis an arithmetic or geometric sequence.
then find common difference(for A.P) or common ratio (for G.P)
c.d .=an-an-1
c.r. =an/an-1
1.G.P.
2. A.P
3.G.P
3,5,25/3,125/9,...
c.r.=5/3
or (25/3)/5=25/(3*5)=5/3
or 125/9÷25/3=125/9×3/25=(125×3)/(9×25)=5/3
Any help would be greatly appreciated
Answers
Step-by-step explanation:
4y + 6 = 16
you can find y (meters)
then replace y value in every side of this shape
then plus all line you will receive the perimeter
Jo and Dee are fairies. Jo is 888 centimeters tall. Dee is 777 centimeters taller than Jo.
How tall is Dee?
Answers
Answer:
15 cm
Step-by-step explanation:
7 cm taller than 8 cm is 15 cm tall.
Dee is 15 cm tall.
Answer:
Dee's height is
[tex]1665cm[/tex]
Step-by-step explanation:
[tex]jo = 888cm \\ dee = 777cm \: \: \: taller \: \: \: than \: \: jo \\ [/tex]
So
[tex]dee = 888 + 777 \\ = 1665cm[/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
Two dice are rolled. E is the event that the sum is even, F is the event of rolling at least one six, and G is the event that the sum is eight. List the outcomes for the following events:
a. E ∩ F {(2, 2), (4, 4), (6, 6)} {(6, 2), (6, 4), (6, 6), (2, 6), (4, 6)} {(2, 6), (4, 6), (6, 6)} ∅
b. Ec ∩ G {(6, 2), (6, 4), (6, 6), (2, 6), (4, 6)} {(2, 6), (4, 6), (6, 6)} {(2, 2), (4, 4), (6, 6)} ∅
Answers
Answer:
(a)[tex]E \cap F ={(2, 6),(4, 6),(6, 2),(6, 4),(6, 6)}[/tex]
(b) [tex]E^c \cap G =\{ \}[/tex]
Step-by-step explanation:
The sample space of two dice rolled is given below:
[tex]\{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5,6)\\(6, 1), (6, 2), (6, 3), (6, 4), (6,5), (6,6)\}[/tex]
For Event E (The sum is even), the outcomes are:
[tex](1, 1), (1, 3), (1, 5),(2, 2), (2, 4), (2, 6)\\(3, 1), (3, 3), (3, 5), (4, 2), (4, 4), (4, 6)\\(5, 1),(5, 3), (5, 5), (6, 2), (6, 4), (6,6)[/tex]
For Event F (Rolling at least one six), the outcomes are:
[tex](1, 6), (2, 6), (3, 6), (4, 6),(5,6),(6, 1), (6, 2), (6, 3), (6, 4), (6,5), (6,6)[/tex]
For Event G (The sum is eight), the outcomes are:
[tex](2, 6), (3, 5),(4, 4), (5, 3),(6, 2)[/tex]
(a)[tex]E \cap F[/tex]
Therefore:
[tex]E \cap F ={(2, 6),(4, 6),(6, 2),(6, 4),(6, 6)}[/tex]
(b)[tex]E^c \cap G[/tex]
E is the event that the sum is even
Therefore: [tex]E^c$ is the event that the sum is odd.[/tex]
Since G is the event that the sum is eight( which is even), the intersection of the complement of E and G will be empty.
Therefore:
[tex]E^c \cap G =\{ \}[/tex]
Champagne is best when the bubbles are concentrated in the wine. A group of scientists compared gentle and splashing pouring methods for champagne by measuring the amount of bubbles in each glass of champagne poured two different ways at three different temperatures. The following data present the pattern of results obtained in the study.
Chane of temperature
40 46 52
Gentle pour n=10 n=10 n=10
M=7 M=3 M=2
SS=64 SS=57 SS=47
Splashing pour n=10 n=10 n=10
M=5 M=1 M=0
SS=56 SS=54 SS=46
Required:
a. Use a two-factor ANOVA with α= 0.05 to evaluate the mean differences.
b. Briefly explain how temperature and pouring influence the bubbles in champagne according to this pattern of results.
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Answer:
??????
Step-by-step explanation:
PLEEEASE HELPPPPPPP!! substitution
Answers
Answer:
X=80
Y=9
Z=7
Step-by-step explanation:
What is f(-2)?
-3
-1
1
3
Answers
Answer:
option b
Step-by-step explanation:
b i did it on edge
