Question 4(Multiple Choice Worth 4 points)
Which of the following is a rational number?
√1. √2. √3, √5
O√1
O √2
O√3
√√5

Trigonometry functions is often employed in taking the measurement of the level or the pitch of a sound wave or musical note.

The change of amplitude of a sound wave's amplitude is linked to the change in pressure that occurs due to the wave measured at a given location.

Frequency tells the number of waves that  pass a fixed location in a specific time frame.

Sound engineers uses the basic laws of trigonometry via sine and cosine graphs.

Note that all sounds can be broken down into a lot of sine waves, as sine waves comes together to form sounds.

Therefore, Trigonometry functions is often employed in taking the measurement of the level or the pitch of a sound wave or musical note.

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Note that the sign of f on the interval -5/9 < x < 2/3 is negative. (Option B)

To determine the sign of f(x) on the interval -5/9 < x < 2/3, we need to evaluate f(x) at a test point within this interval and determine if it is positive or negative.

Since we know that f(x) has zeros at x = -4, x = -5/9, and x = 2/3, we can use these points as our reference to choose test points.

Specifically, since the zeros at x = -5/9 and x = 2/3 are not included in the interval -5/9 < x < 2/3, we can choose any test point within this interval, such as x = 0.

Evaluating f(x) at x = 0, we get:

f(0) = (3(0) - 2)(0 + 4)(9(0) + 5)

= (-2)(4)(5)

= -40

Since f(0) is negative, we can conclude that f(x) is negative on the interval -5/9 < x < 2/3.

Therefore, the sign of f on the interval -5/9 < x < 2/3 is negative

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Full Question:

f(x) = (3x - 2) (x+4) (9x +5) has zeros at x = -4, x = -5/9, and x = 2/3, that is the sign of f on the interval -5/9 < x < 2/3?

The speed of the wind and the speed of the dragon in still air are respectively;  142.5 mph and 7.5 mph

The dragon flew 300 miles with the wind in two hours.

After flying against the wind for two hours, he had made 270 miles of the return trip.

Let s be the speed in still air

Let w be the speed of the wind

Thus;

(s - w) = effective speed against the wind

and

(s + w) = effective speed with the wind

We know that;

distance = time * effective speed

Thus;

2(s + w) = 300

2(s - w) = 270

This can be simplified to get;

s + w = 150   -----(1)

s - w = 135   -----(2)

Add both equations to get;

2s = 285

s = 285/2

s = 142.5 mph.

Then, plane speed in still air is;

142.5 + w = 150

w = 150 - 142.5

w = 7.5 mph is the speed of the wind

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Answer:

List method: {7,9,11,13,15,17,19}

Set method: {X:N where N is odd, N>5 and N<21}

The odd numbers greater than 5 and less than 21 are {7, 9,11,13,15,17,19}.

Odd numbers are the numbers that cannot be divided by 2 evenly. It cannot be divided into two separate integers evenly.

Odd numbers are opposite to even numbers this means that even numbers are numbers that can be divided by 2.

When we say numbers greater than 5 and less than 21 this means 5< x < 21

The odd numbers greater than 5 and less than 21 are ;

{7, 9,11,13,15,17,19}. These odd numbers are greater than 5 and less than 21.

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Answer:

The length of the side BC is 6 units.

Step-by-step explanation:

Rectangle ABCD

Coordinates of Point A,B,C,D

[tex]A = ( 5 , 5)B = (7, 5)C = (7 , -1)D = (5 , -1)[/tex]

As we are asked to find the length of side BC, we'll apply the Distance formula on side BC

BC = [tex]\sqrt{(7_ {-} 7)^{2} +(-1 {-} 5)^{2}}[/tex]

     = [tex]\sqrt{(0)^{2} +(-6)^{2}}[/tex]

     = [tex]\sqrt{ 36}[/tex]

     = [tex]6[/tex]

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Answ x=59

Step-by-step explanation:

Answer:

The first type of solid shapes to be discovered are known as Platonic solids, which include the cube, the tetrahedron, the octahedron, the dodecahedron, and the icosahedron

By the power and chain rules, taking derivatives on both sides with respect to [tex]t[/tex] gives

[tex]4x^3 \dfrac{dx}{dt} + 4y^3 \dfrac{dy}{dt} = 4\dfrac{dy}{dt}[/tex]

or

[tex]4x^3 \dfrac{dx}{dt} + (4y^3-4) \dfrac{dy}{dt} = 0[/tex]

The graph is: On a coordinate plane, a cubic function has a point of inflection at x = 5 and crosses the x-axis at x = 5

A cubic function in mathematics is one with the formula f(x)=ax3+bx2+cx+d, where aneq 0 and the coefficients a, b, c, and d are complex numbers, and the variable x has real values. In other words, it is a real function as well as a polynomial function of degree three.

The function we have is:

y = ∛(x - 5)

So cubic root is given

Here we notice that when x = 0, we have:

y = ∛-5, this is the y-intercept

And when x = 5 we have:

y = ∛0 = 0 which is the x-intercept, and also the inflection point because here we have the change of sign.

Hence option which describes graph best is On a coordinate plane, a cubic function has a point of inflection at x = 5 and crosses the x-axis at x = 5

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Answer:A

Step-by-step explanation: Edge 2022

Answer:

answer is B. 100°

Step-by-step explanation:

if correct please I need brainlist

Answer:

100°

Step-by-step explanation:

Opposite angles of a quadrilateral inscribed in a circle are supplementary, i.e., they add up to 180°.

The 80° angle and angle x are opposite each other, so:
x + 80° = 180°

x = 180° - 80°

  x = 100°

Answer:

y=−6x−36

Step-by-step explanation:

ez math

The answer for each of the differentiation are; f'(-6) = 432;  f⁻¹(y) = ∛((y + 5)/4); df⁻¹/dy = 1/432

1) f(x) = 4x³ - 5

We will differentiate it to get;

f'(x) = df/dx = 12x²

f'(-6) = 12(-6)²

f'(-6) = 432

2) We are given the formula;

x = f⁻¹(y)

Thus;

y = 4x³ - 5

4x³ = y + 5

x³ = (y + 5)/4

x = ∛((y + 5)/4)

f⁻¹(y) = ∛((y + 5)/4)

c)  f⁻¹(y) = ∛((y + 5)/4)

df⁻¹/dy = -1/12y²

At f(-6), we have;

df⁻¹/dy = 1/432

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Answer:

Let x = number of half-page advertisements

Let y = number of full-page advertisements

[tex]\begin{cases} 42x + 86y = 1192\\ x + y = 20\end{cases}[/tex]

8 full-page advertisements

12 half-page advertisements

Step-by-step explanation:

Definition of variables

Let x = number of half-page advertisements

Let y = number of full-page advertisements

Given information:

Using the given information, we can write a system of equations:

Equation 1:  42x + 86y = 1192

Equation 2:   x + y = 20

To solve the system of equations, rearrange Equation 2 to make x the subject:

⇒ x = 20 - y

then substitute this into Equation 1 and solve for y:

⇒ 42(20 - y) + 86y = 1192

⇒ 840 - 42y + 86y = 1192

⇒ 840 + 44y = 1192

⇒ 44y = 352

⇒ y = 8

Substitute the found value of y into Equation 2 and solve for x:

⇒ x + 8 = 20

⇒ x = 12

Therefore, Kathryn purchased:

An equation of Hamid’s revenue by multiplying the book price by the number of copies sold is  x = ny.

The process of equating one thing with another.

Let Hamid’s revenue is $x and the price of book is $y.

If he sold n number of copies.

Then, the general equation will be x = n * y.

Therefore, an equation of Hamid's revenue will be x = ny.

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Answer:

Step-by-step explanation:

From the picture we observe:

1. The shape is 3 quarters of circle as one quarter is excluded (note the right angle);

2. The radius of the circle is 2 units.

Use area formula of circle to find the area of given shape:

Answer:

a = 4pi

Step-by-step explanation:

The formula of finding a area of a circle is "a = piR^2.

Replace the R with the radius which is 2 for this circle.

Answer:

y = csc(x)+2

Step-by-step explanation:

This is the graph of y = csc(x), shown in the attached image, shifted up 2 units.

The function  (f-g) (x) is represented as 5^2x - 3 - x .

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

f(x)=5^2x-2

g(x)=x+1

Then, the function

(f-g) (x) = 5^2x-2  - (x+1)

Distribute the negative;

(f-g) (x) = 5^2x-2  - x - 1

(f-g) (x) = 5^2x - 3  - x

Hence, the function  (f-g) (x) is represented as 5^2x - 3 - x .

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The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for [tex]m^{2} +1[/tex] is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and [tex]\sqrt{t-1}[/tex] for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at [tex]m^{2} +1[/tex] when m belongs to [tex]\sqrt{7} and \sqrt{10}[/tex] the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

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The equation of the red graphed function is: g(x) = 1 - x².

Given the graph shown in the attachment below, the graphed function heads downwards, and the x - axis is intercepted at ( 1, 0 ) and (-1,0).

Thus, the x-intercepts, which is the zeros of the function, are: 1 and -1.

So, g(x) = (x + 1)(x -1)

Expand:

g(x) = 1 - x²

The equation of the red graph is: g(x) = 1 - x².

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Answer:

Step-by-step explanation:

Answer:

A. 24

Step-by-step explanation:

Least common multiple of 8 and 12 = 24

8× 1 = 8 12×1 = 12

8×2 = 16 12×2=24

8×3 = 24

L.C.M (8,12) = 24

The greatest multiple that occurs in both the multiples of 8 and 12, is 24.

Hence, the least common multiple here is 24.

Answer:

1. 8

2. 3

Step-by-step explanation:

[tex]f(g(3)) \\= f(2(3)-3))\\=f(3)\\=3^2-1\\= 9-1\\=8\\\\g(f(-2))\\= g((-2)^2-1)\\=g(4-1)\\=g(3)\\=2*3-3\\=3[/tex]

Answer:

A relation is a subset of cartesian product of two non empty sets whereas A function is a type of relation in which every element of first set has one and only image in the second set.

In a relation an element of the first set can have many images in the second set whereas in a function the first element can have only one image in the second set.

The given relation is not a function as the element 1 is related to 3 different elements in the second set.

Domain={1}

Range={7,14,21}

The true statements are

-one zero with multiplicity 3

-one zero with multiplicity 4

-one zero with multiplicity 5

-one zero with multiplicity 1 and one zero with multiplicity 2

-one zero with multiplicity 1 and one zero with multiplicity 3

-one zero with multiplicity 2 and two zeros with multiplicity 1

-one zero with multiplicity 2 and three zeros with multiplicity 1

-Two zeros with multiplicity 2

-Two zero with multiplicity 2 and two zeros with multiplicity 1

-Two zero with multiplicity 2 and three zeros with multiplicity 1

-Two zero with multiplicity 1

-Three zeros with multiplicity 1

-Four zeros with multiplicity 1

-Five zeros with multiplicity 1

The function is given as:

f(x)

And it has a degree of 3

This means that

Using the above highlight as a guide, the true statements are (a), (d),and (l)

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Answer: 3

Step-by-step explanation:

The sine of an angle is equal to the cosine of its complement, so

[tex]4x+10=2x+16\\\\2x+10=16\\\\2x=6\\ \\ x=3[/tex]

The area of triangle is 24 sq. units

Area of rectangle is product of its length to its breadth.

i.e., Area of rectangle = length* breadth

let A(6, -3), B(3, -6), C( -1, -2) and D( 2, 1)

Using distance formula

AB = √(3-6)²+ (-6 +3)²

AB= √9 + 9

AB= √18

AB= 3√2

now,

BC=  √(-1-3)²+ (-2 +6)²

BC = √16 +16

BC = √32

BC =4 √2

Now, Area of rectangle

= AB* BC

=  3√2 *4 √2

= 12*2

= 24 square units

Hence, area of rectangle is 24 sq. units

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The total number of cups in the package is 2300.

Percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.

Here,

Let the total number of cups in the package be x.

Number of green cup = 690

Weightage of green cup in total = 30%

Now,

30% of x = 690

30/100 X x = 690

x = 690 X 100/30

x = 23 X 100

x = 2300

Thus, the total number of cups in the package is 2300.

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Answer:

the original amount was 62

Step-by-step explanation:

You can use the part over whole formula like this:

[tex]\frac{part}{whole} = ( \frac{6.2}{?} * \frac{10}{100})\\ ? = 62[/tex]

why?

because we know that 10% = 10/100, we can easily find out the answer by cross multiplying

? * 10 (let's use x, instead of ?)

=10x

6.2 * 100

= 620

Now we have an equation that looks like this: 10x = 620

By using the inverse operation tool (dividing each side by 10 to isolate x) we have:

x (or ?) = 62

Answer:

[tex]y = \sin( \frac{2\pi}{3} x) [/tex]

Step-by-step explanation:

The equation of a sine function is y = a sin(bx), where a = amplitude (aka height) and b equals period (aka time). I'm assuming there isn't any information other than the graph shown, so let's assume that our amplitude is 1 and our period is 2pi/3. Plugging these values into the equation, we get:

[tex]y = (1) \sin(( \frac{2\pi}{3})x ) = \sin(\frac{2{\pi} }{3}x )[/tex]

Answer:

D

Step-by-step explanation: