Answers
Answer:
A. 30cm³
Explanation:
Based on the chemical reaction:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
1 mol of calcium carbonate reacts with 2 moles of HCl to produce 1 mol of CO₂
To solve this question we must convert the mass of each reactant to moles. With the moles we can find limiting reactant and the moles of CO₂ produced. Using PV = nRT we can find the volume of the gas:
Moles CaCO₃ -Molar mass: 100.09g/mol-
1.00g * (1mol / 100.09g) = 9.991x10⁻³ moles
Moles HCl:
50cm³ = 0.0500dm³ * (0.05 mol / dm³) = 2.5x10⁻³ moles
For a complete reaction of 2.5x10⁻³ moles HCl there are necessaries:
2.5x10⁻³ moles HCl * (1mol CaCO₃ / 2mol HCl) = 1.25x10⁻³ moles CaCO₃. As there are 9.991x10⁻³ moles, HCl is limiting reactant.
The moles produced of CO₂ are:
2.5x10⁻³ moles HCl * (1mol CO₂ / 2mol HCl) = 1.25x10⁻³ moles CO₂
Using PV = nRT
Where P is pressure = 1atm assuming STP
V volume in L
n moles = 1.25x10⁻³ moles CO₂
R gas constant = 0.082atmL/molK
T = 273.15K at STP
V = nRT / P
1.25x10⁻³ moles * 0.082atmL/molK*273.15K / 1atm = V
0.028L = V
28cm³ = V
As 28cm³ ≈ 30cm³
Right option is:
A. 30cm³Related Questions
What is the formula of compound formed from a calcium ion and As? Express your answer as a chemical formula
Answers
Answer:
its chemical formula is Ca3N2
Explanation:
hope it will help
The pH of an acidic solution is 5.59. What is [H+]?
Answers
Answer:
[H⁺] = 2.57x10⁻⁶ M
Explanation:
This problem can be solved using the definition of pH:
pH = -log[H⁺]
Now we isolate [H⁺] in the equation:
-pH = log[H⁺]
[tex]10^{-pH}[/tex]=[H⁺]
As we are given the pH by the problem, we can now proceed to calculate the [H⁺]:
[H⁺] = [tex]10^{-5.59}[/tex]
[H⁺] = 2.57x10⁻⁶ M
Thus, when the pH of a solution is 5,59; the molar concentration of H⁺ species is 2.57x10⁻⁶.
How many moles of solute are present in 2 L of a 25M potassium nitrate (KNO3) solution?
0.5 moles
50 moles
25 moles
2 moles
Answers
50 moles
The formula used in this question is-
Mole= Molarity*Volume(in Litre)
So after putting the value
= (25)*(2)
=50 moles
What is molarity?
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.
Learn more about Molarity here
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When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..
Answers
The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of
sodium azide, NaN3.
2 NaNz (s) 2 Na (s) + 3 N2 (g)
If an air bag has a volume of 53.4 L and is to be filled with nitrogen gas at a pressure of 1.07 atm and a
temperature of 23.7°C, how many moles of NaNz must decompose? You may assume the Ny behaves as
an ideal gas.
Answers
Answer:
1.57 mol NaN₃
Explanation:
2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)First we use PV=nRT to calculate the number of N₂ moles that need to be produced:
P = 1.07 atmV = 53.4 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 KInputing the data:
1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86And solving for n:
n = 2.35 mol N₂Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:
2.35 mol N₂ * [tex]\frac{2molNaN_3}{3molN_2}[/tex] = 1.57 mol NaN₃2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent yield if 5.40 g of "hydrogen gas" are collected?
Answers
Answer:
1040%
Explanation:
To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:
Percent yield = Actual yield (5.40g) / Theoretical yield * 100
Moles Fe -Molar mass: 55.845g/mol-:
10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.
For a complete reaction of these moles there are necessaries:
0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.
As there are 14.8 moles of the acid, Fe is limiting reasctant.
The moles of H2 produced are:
0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2
The mass is:
0.277 moles H2 * (2.016g/mol) = 0.558g H2
Percent yield is:
5.40g / 0.558g * 100 = 1040%
It is possible the experiment wasn't performed correctly
How tightly particles are packed determines what state it takes.
True or False
Answers
Answer:
True
Explanation:
tighter the molecules the slower it moves and the harder it gets
solid has very tight particles packed together
gas has its particles spread out
How many moles of C2H2 are required to produce 0.60 mol of H2O?
Express your answer to two significant figures and include the appropriate units.
Answers
Answer:
0.60 moles
Explanation:
From the reaction:
[tex]2C_2H_2 + 5O_2 \to 4CO_2+2H_2O[/tex]
From above, Only 2 moles of CH2CH2 are required to produce 2 moles of water (H_2O).
As such, 0.6 moles of H2O will require:
x (CH2CH2) × 2 moles of (H_2O) = 0.6 moles (CH2CH2) × 2 mole of (H_2O)
x mole of (CH2CH2) = 0.60 moles
∴
0.6 moles of H2O will require 0.60 moles of CH2CH2
Why is Potassium called an alkali metal?
Answers
Answer:
Explanation: potassium (Na) has one electron in outer shell
And it donates it easily and can even reduce
Hydrogen gas from water. An alkaline solution containing
Hydroxide ions (OH-) is then formed
Answer:
Because
Explanation:
Potassium is called Alkali metal because Potassium forms oxides which dissolve in water to form Alkali
If an ultraviolet photon has a wavelength of 77.8 nm calculate the energy of one mole ultraviolet photon.
Answers
Answer:
Explanation:
E = (hc)/(λ)
E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /
(77.8x10^(-9)m)
E = 2.55 x 10^(-11) J
What's the wavelength in meters of an electron traveling at 9.5 x 10^7 m/s? The mass of an electron is 9.11 x 10^-28 g.
Select one:
a. 7.66 x 10-15 m
b.7.66 x 10-12 m
c. 3.47 x 1027 m
d. 3.47 x 1030 m
Answers
Answer:
where:
• A is the wavelength in m.
• h = 6.626 x 10-34Js is Planck's
constant.
• m is the mass of the particle, such as the electron, in kg. The particle must have a mass for this relation to work.
• v is the forward velocity of the particle, in m/s.
Hence, the wavelength is:
6.626 x 10-34J.s
(9.1094 × 10 −³¹kg) (5 × 10³m/s)
We know that 1 J 1 kg. m²/s². So:
6.626 × 10-³4 g · m² / ø
9.1094 x 10 - 31) (5 x 105 m/s)
= 1.455 x 10-9 m
=
= 1.455 nm
1
Select the correct answer.
How long is the term of a federal judge in a constitutional court?
OA.
two years
OB
four years
Ос.
six years
OD.
lifetime
Answers
Answer:
Judges and justices serve no fixed term — they serve until their death, retirement, or conviction by the Senate. By design, this insulates them from the temporary passions of the public, and allows them to apply the law with only justice in mind, and not electoral or political concerns.
Observe the map what do the grey scar like represent?
Answers
Answer:
mid ocean ridge
Explanation:
How are a tundra and a desert different?
A desert has a low level of precipitation and a tundra has a high level of precipitation.
A desert is wet year-round and a tundra is dry.
A tundra has a lower levels of humidity.
A tundra has lower average temperatures year-round.
i am giving brainlyest!!!!!!!
Answers
Answer:
A tundra has a lower average temperatures year-round.
The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.
Answers
Answer:
0.0542 M
Explanation:
Let;
CA = concentration of Ce4+ solution = 0.1741 M
VA = volume of Ce4+ solution = 18.68 mL
CB = concentration of H3AsO3 = ?
VB = volume of H3AsO3 = 30.00 mL
NA = Number of moles of Ce4+ solution = 2
NB = Number of moles of H3AsO3 = 1
From;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB = CAVANB/VBNA
CB = 0.1741 * 18.68 * 1/30.00 * 2
CB = 0.0542 M
pls help i will mark as brainliest
Answers
Answer:
ano po ito?? isa po ba itong story
How many grams of Mg(NO3), are necessary to
make 1500 mL of a 0.50 M solution?
Answers
Answer:
1.1 × 10² g
Explanation:
Step 1: Given data
Concentration of the solution (C): 0.50 M (0.50 mol/L)Volume of solution (V): 1500 mL (1.500 L)Step 2: Calculate the moles of Mg(NO₃)₂ (solute)
Molarity is equal to the moles of solute (n) divided by the liters of solution.
C = n/V
n = C × V
n = 0.50 mol/L × 1.500 L = 0.75 mol
Step 3: Calculate the mass corresponding to 0.75 moles of Mg(NO₃)₂
The molar mass of Mg(NO₃)₂ is 148.3 g/mol.
0.75 mol × 148.3 g/mol = 1.1 × 10² g
Which process takes place in the conversion of iron into steel?
Answers
Iron is changed into steel by blowing oxygen through the molten metal from the Blast Furnace. This oxidises the impurities in the molten metal. Carbon is a major impurity in Blast Furnace metal.
Arrange in terms of increasing atomic radius. From smallest to largest.
S, F, Sr, Na, Ga
Answers
Answer:
F<S<Na<Ga<Sr
Explanation:
Atomic radius increased from the right of the periodic table to left, and from the top to the down
The symbol for free energy is
a. DG.
b. DS.
c. DT.
d. DH.
Answers
please help does anyone know this// science!
Answers
Answer:
its A
Explanation:
The only one that makes sense
Which of the following statements about C3 carbon fixation is true? a. C3 carbon fixation is an adaptation for plants exposed to high light intensity. b. C3 carbon fixation occurs in more plants than C4 carbon fixation. c. C3 carbon fixation is more common in areas of high temperatures than C4 carbon fixation. d. C3 carbon fixation occurs in the inner cells of a leaf rather than the entire leaf.
Answers
Answer: The answer is B
Explanation:
RiP BoZo. shout out to faze gabi staright up bopped potato girl.
Answer:
B
:D
Explanation:
Consider the following exothermic process at equilibrium:
CO(g)+H2O(g)⇌CO2(g)+H2(g)
Which of the following changes would increase the amount of H2(g) present in the equilibrium mixture?
Consider the following exothermic process at equilibrium:
Which of the following changes would increase the amount of present in the equilibrium mixture?
decrease the temperature
increase [CO2]
increase [CO]
increase the volume of the container in which the reaction occurs.
more than one of the above
(Answer is not increase [CO])
Answers
For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
How is equilibrium affected by changes?When a perturbation is done on a system at equilibrium, it shifts its equilibrium position to counteract the perturbation.
Let's consider the following exothermic process at equilibrium.
CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)
Which of the following changes would increase the amount of H₂(g) present in the equilibrium mixture?
decrease the temperature. NO. For an exothermic reaction, a decrease in the temperature will shift the equilibrium towards the reactants.increase [CO₂]. NO. This would shift the equilibrium towards the reactants.increase [CO]. YES. This would shift the equilibrium towards the products.increase the volume of the container in which the reaction occurs. NO. This wouldn't affect the equilibrium since the number of gaseous moles is the same on both sides.more than one of the above. NO.For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.
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The gas phase decomposition of nitrogen dioxide at 383 °C
NO2(g)NO(g) + ½ O2(g)
is second order in NO2 with a rate constant of 0.540 M-1 s-1.
If the initial concentration of NO2 is 0.477 M, the concentration of NO2 will be
M after 12.4 seconds have passed.
Answers
Answer:
[tex][NO_2]=0.112M[/tex]
Explanation:
Hello there!
In this case, since the second-order integrated law is given by the following equation:
[tex]\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt[/tex]
Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:
[tex]\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}[/tex]
[tex][NO_2]=\frac{1}{8.933M^{-1}} =0.112M[/tex]
Best regards!
Human blood contains a buffer of carbonic acid (H_2 CO_3) and bicarbonate anion (HC〖O_3〗^-) in order to maintain blood pH between 7.35 and 7.45, as a value higher than 7.8 or lower than 6.8 can lead to death. In this buffer, hydronium and bicarbonate anion are in equilibrium with carbonic acid. Furthermore, the carbonic acid in the first equilibrium can decompose into CO_2 gas and water, resulting in a second equilibrium system between carbonic acid and water. Because CO_2 is an important component of the blood buffer, its regulation in the body, as well as that of O_2 , is extremely important. The effect of this can be important when the human body is subjected to strenuous condition.
Carbonic acid buffer:
H_2 CO_3 (aq)+ H_2 O(l) ↔H_3 O^+ (aq)+HC〖O_3〗^- (aq)
1. Write the equilibrium constant expression K_c for the carbonic acid buffer in the blood.
Answers
Kc = [H3O+][HCO3-] / [H2CO3]
Remember that Kc is products over reactants. Also, you do not include liquid water in a Kc expression, since liquid water has no concentration.
How many milliliters of 0.2560 M KCl solution will contain 20.00 g of KCl?
Answer is 1048 mL solution but how do I get to the answer?
Answers
Answer:
1048 mL
Explanation:
Step 1: Given data
Concentration of the solution: 0.2560 MMass of KCl (solute): 20.00 gStep 2: Calculate the moles corresponding to 20.00 g of KCl
The molar mass of KCl is 74.55 g/mol.
20.00 g × 1 mol/74.55 g = 0.2683 mol
Step 3: Calculate the volume of the solution
Molarity is equal to moles of solute divided by liters of solution.
M = moles of solute / volume of solution
volume of solution = moles of solute / M
volume of solution = 0.2683 mol / (0.2560 mol/L)
volume of solution = 1.048 L = 1048 mL
which is an example of a sale laboratory procedure
Answers
A sample of hydrogen has an initial temperature of 122.0 °F. When the temperature is lowered to -23.0 °F, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen?
Answers
Answer: The initial volume of gas was [tex]282cm^3[/tex]
Explanation:
Charles's Law: This law states that volume is directly proportional to temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas =?
[tex]V_2[/tex] = final volume of gas = [tex]212cm^3[/tex]
[tex]T_1[/tex] = initial temperature of gas = [tex]122.0^0F=323.15K[/tex]
[tex](32^0C=273.15K)[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-23.0^0F=242.59K[/tex]
[tex]\frac{V_1}{323.15}=\frac{212}{242.59}[/tex]
[tex]V_2=282cm^3[/tex]
Therefore, the initial volume of gas was [tex]282cm^3[/tex]
C. 2.86 g
D. 1.22 g
13. At what Kelvin temperature will 25.2 mol of Xe occupy a volume of 645 L at a pressure of 732 torr?
A. 361 K
B. 291 K
C. 402 K
D. 300 K
Answers
gloves worn when working with liquid oxygen must be able to resist.
Answers
Answer:
What is your question?
Explanation:
Can you give more context to ur question?
