Answer:
68.5% seats filled
76% points earned
Step-by-step explanation:
General outlineIdentify the whole and the partChange ratio into a percentageRatiosPercentages are formed when one finds a ratio of two related quantities, usually comparing the first partial quantity to the amount that "should" be there.
[tex]\text{ratio}=\dfrac {\text{the "part"}}{\text{the whole}}[/tex]
For instance, if you have a pie, and you eat half of the pie, you're in effect imagining the original pie (the whole pie) cut into two equal pieces, and you ate one of them (the "part" of a pie that you ate). To find the ratio of pie that you ate compared to the whole pie, we compare the part and the whole:
[tex]\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}[/tex]
[tex]\text{ratio}=\dfrac {1}{2}[/tex]
If you had instead eaten three-quarters of the pie, you're in effect imagining the original pie cut into 4 equal pieces, and you ate 3 of them.
[tex]\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}[/tex]
[tex]\text{ratio}=\dfrac {3}{4}[/tex]
There can be cases where the "part" is bigger than the whole. Suppose that you are baking pies and we want to find the ratio of the pies baked to the number that were needed, the number of pies you baked is the "part", and the number of pies needed is the whole. This could be thought of as the ratio of project completion.
If we need to bake 100 pies, and so far you have only baked 75, then our ratio is:
[tex]\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}[/tex]
[tex]\text{ratio}=\dfrac {75}{100}[/tex]
But, suppose you keep baking pies and later you have accidentally made more than the 100 total pies.... you've actually made 125 pies. Even though it's the bigger number, the number of pies you baked is still the "part" (even though it's bigger), and the number of pies needed is the whole.
[tex]\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}[/tex]
[tex]\text{ratio}=\dfrac {125}{100}[/tex]
PercentagesTo find a percentage from a ratio, there are two small steps:
Divide the two numbersMultiply that result by 100 to convert to a percentageGoing back to the pies:
When you ate half of the pie, your ratio of pie eaten was [tex]\frac{1}{2}[/tex]
Dividing the two numbers, the result is [tex]0.5[/tex]
Multiplying by 100 gives 50. So, the percentage of pie that you ate (if you ate half of the pie) is 50%
When you ate three-quarters of the pie, the ratio was [tex]\frac{3}{4}[/tex]
Dividing the two numbers, the result is 0.75
Multiplying by 100 gives 75. So, the percentage of pie that you ate (if you ate three-quarters of the pie) is 75%.
When you were making pies, and 100 pies were needed, but so far you'd only baked 75 pies, the ratio was [tex]\frac{75}{100}[/tex]
Dividing the two numbers, the result is 0.75
Multiplying by 100 gives 75. So, the percentage of the project that you've completed at that point is 75%.
Later, when you had made 125 pies, but only 100 pies were needed, the ratio was [tex]\frac{125}{100}[/tex]
Dividing the two numbers, the result is 1.25
Multiplying by 100 gives 125%. So, the percentage of pies you've made to complete the project at that point is 125%.... the number of pies that you've made is more than what you needed, so the baking project is more than 100% complete.
The questions1. 27400 spectators n a 40000 seat stadium percentage.
Here, it seems that the question is asking what percentage of the stadium is full, so the whole is the 40000 seats available, and the "part" is the 27400 spectators that have come to fill those seats.
[tex]\text{ratio}=\dfrac {\text{the number of spectators filling seats}}{\text{the total number of seats in the stadium}}[/tex]
[tex]\text{ratio}=\dfrac {27400}{40000}[/tex]
Dividing gives 0.685. Multiplying by 100 gives 68.5. So, 68.5% of the seats have been filled.
2. an archer scores 95 points out of a possible 125 points percentage
Here, it seems that the question is asking what percentage of the points possible were earned, so the whole is the 125 points possible, and the "part" is the 95 points that were earned.
[tex]\text{ratio}=\dfrac {\text{the number of points earned}}{\text{the total number of points possible}}[/tex]
[tex]\text{ratio}=\dfrac {95}{125}[/tex]
Dividing gives 0.76. Multiplying by 100 gives 76. So, 76% of points possible were earned.
Placement Assessment
A certain drug is made from only two ingredients: compound A and compound B. There are 7 milliliters of compound A used for every 4 milliliters of compound
B. If a chemist wants to make 946 milliliters of the drug, how many milliliters of compound A are needed?
milliliters of compound A
X
Time Remaining: 22:11:23 I Question 17
?
Libbi
Est
Answer:
[tex]7 469.8.56[/tex]
nossa nem sei como é bom saber se fala com a mãe e o pai do mundo e vc não tem mais nada pra comer e não tem como fazer a gente vai ficar muito tempo sem fazer a mãe dela não e vc como tá o trabalho rede de nada em casa e é só pra mim né não é fácil de fazer a mãe dela e a mãe dele tá bem né não é fácil de fazer o que vc quer que Deus quiser vai dar pra mim né e não tem como fazer d id da x não vou poder é o que eu te abençoe e ilumine e ilumine todos os dias entre?01029)
WHAT DOES THIS MEAN???
"If you take Nia out for mexican food, have an air freshener on standby."
Answer: Beans cause Nia to Fart!
Step-by-step explanation:
Mexican food usually contains beans, which beans are a known catalyst of flatulence. Beans induce farts and Nia does so! Farts usually stink, so an air freshener is needed.
Please help! thank youuuu
Use polynomial long division to divide. Determine whether the divisor evenly divides into the dividend.
(8x-5)/(2x+1)
Answer:
The solution is 4 - 9/(2x + 1)
No, the divisor does not evenly divide into the dividend
Step-by-step explanation:
Please see the attached image
what is the length of the squares side?
Answer:
side ≈ 4.24= [tex]\frac{6}{\sqrt{2} }[/tex]
Step-by-step explanation:
sides a = b
[tex]6^{2} =a^{2} +a^{2}[/tex]
[tex]6^{2} =2a^{2}[/tex]
[tex]a^{2}= \frac{6^{2} }{2} =\frac{36}{2} =18[/tex]
[tex]a=\sqrt{18} =4.24=\sqrt{(9)(2)} =\frac{6}{\sqrt{2} }[/tex]
Hope this helps
Solve based off of the screenshot provided below.
Answer:
48 cm²
Explanation:
The figure can be cut into 1 rectangle and 1 triangle.
Area of the figure:
⇒ area of rectangle + area of triangle
⇒ Length × Width + 1/2 × Base × Height
⇒ 6 × 4 + 1/2 × 6 × 8
⇒ 24 + 24
⇒ 48
Therefore, area of figure is 48 cm².
Answer:
48 cm squared
Step-by-step explanation:
The given figure is composed of a rectangle (L=6 cm and W = 4 cm) and a right angled triangle { Base = (12- 4) = 8 cm, height = 6 cm. }
Area of the two figures is to be calculated separately and then added to get the required result.
Area of the rectangle = l × w
= 6 × 4
= 24 cm²
Area of the right triangle = ½ × base × height
= ½ × 8 × 6
= 24 cm²
Hence, area of the given figure = 24 + 24
= 48 cm squared.
What key features do the functions f(x) = 4-x and g of x equals negative one times the square root of the x minus 4 end root have in common? Both f(x) and g(x) include domain values of [–4, ∞) and range values of (–∞, ∞), and both functions have an x-intercept in common. Both f(x) and g(x) include domain values of [4, ∞), and both functions decrease over the interval (4, ∞). Both f(x) and g(x) include domain values of [4, ∞) and range values of [0, ∞), and both functions have a y-intercept in common. Both f(x) and g(x) include domain values of [–4, ∞) and range values of (–∞, ∞), and both functions are negative for the entire domain.
The statement about both functions that is true is:
Both f(x) and g(x) include domain values of [4, ∞), and both functions decrease over the interval (4, ∞). What is the domain and range for the function of y = f(x)?The domain of a function is the set of values of input for which the function is valid.
The range is the dependent variable of a set of values for which the function is defined.
Given that:
f(x) = 4 - x
The slope (m) of the function = -1x-intercept = (4,0)y-intercept = (0,4)Domain = [4,∞)For function g(x) = -1 ×[tex]\mathbf{\sqrt{x-4}}[/tex]
The domain = x ≥ 4 and the solution set is [4,∞)The range g(x) = ≤ 0 and the solution set is [-∞, 0)The function g(x) does not have a y-intercept.Therefore, from the given options, the statement about both functions that is true is:
Both f(x) and g(x) include domain values of [4, ∞), and both functions decrease over the interval (4, ∞).Learn more about the domain of a function here:
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Answer:
Both f(x) and g(x) include domain values of [4, ∞), and both functions decrease over the interval (4, ∞).
Step-by-step explanation:
I got it right on the test.
Evaluate:
10
Σ¹0 4(1)n-1 = [?]
Round to the nearest hundredth.
Enter
Answer:
Step-by-step explanation:
we are essentially calculating:
4(1/4)^0 + 4(1/4)^1 + 4(1/4)^2 + ... + 4(1/4)^9
Formula: [tex]\frac{a(1-r^n)}{1-r}[/tex]
4(1-(1/4)^10)/ (1-1/4) approximates to 5.33
Somebody help me solve;
(1)A fair die is being rolled.
a) Find the probability that at least 5 rolls are needed to obtain the first
one.
b) Find the probability that it will take fewer than seven rolls to obtain the
second one if the first one occurs on the third roll.
if the third place value of a number is 64 , What base is the number in ?
A) 2
B) 4
C) 8
D) 16
Answer:
B
Step-by-step explanation:
4, 16, 64 should be the correct order
A standard number cube with the numbers 1 through 6 is rolled. Find the probability of rolling a number greater than 2
Find the midpoint between the given points: (2,-1), (10,-9)
Answer: (6, -5)
Step-by-step explanation: I used the midpoint formula and this is what I got. I hope this helps!
The formula:
(xm, xy) = (x1 + x2/2, y1 + y2/2)
As part of a weight loss plan, Levi’s average Calories consumed per day, denoted by c, subject to a maximum of 15 calories, is measured to calculate the amount of weight he will lose. If he is losing weight consistently, what is the domain of the function?
a. c < 0
b. c > 0
c. 0 ≤ c ≤ 15
d. 0 < c ≤ 15
Using it's concept, it is found that the domain of the function is given as follows:
d. 0 < c ≤ 15
What is the domain of a function?The domain is the set that contains all possible input values for the function.
He is losing weight consistently, hence c > 0, and the maximum amount is of 15 calories, hence c ≤ 15 and the domain is given by:
d. 0 < c ≤ 15
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A polynomial function has a root of -6 with multiplicity 3 and a root of 2 with multiplicity 4. If the function has a negative
leading coefficient and is of odd degree, which could be the graph of the function?
Answer:
Using the formula multiplicity, we find that the equation of the function will be [tex]f(x)=-(x+6)^{3} (x-2)^{4}[/tex]. The graph is in the attachment.
Step-by-step explanation:
Concept: Given that for -6, multiplicity is 3 and for 2 multiplicity is 4.
So, the equation of multiplicity is represented as:
[tex]f(x)=a(x-root)^{mutliplicity}[/tex]
This gives the following function
[tex]f(x)=a(x+6)^{3} (x-2)^{4}[/tex]
The equation has a negative leading coefficient.
This means that, the value of a is less than 0 i.e. a < 0
Assume any value of a (say a = -1), the equation becomes
[tex]f(x)=-(x+6)^{3} (x-2)^{4}[/tex]
The graph is in the attachment.
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Answer:
C
Step-by-step explanation:
trust bro
y=2x+40 and y=4x+20 when will these be equal
Answer:
When x = 10, they will both be y = 60
(10, 60)
Step-by-step explanation:
2(10) + 40 = 60
4(10) + 20 = 60
Answer:
x = 10
Step-by-step explanation:
2 (10) +40 = 60
4(10) +20 = 60
Which values are part of the solution set? Check all that apply. x = 3 x = –5 x = negative one-half x = –4.5 x = –4
The values that are part of the solution are x = -5 and x = -4.5
Number linesNumber lines are lines that are used to represent the solution to inequalities.
From the given number line with he solution x > -4, this shows that all the solutions must be values that are greater than -4.
The values that are part of the solution are x = -5 and x = -4.5
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Express 5.5° as a fraction. .
Answer:
11/200
Step-by-step explanation:
Convert the percentage to a fraction by placing the expression over
100
Percentage means 'out of 100
5.5
100
Convert the decimal number to a fraction by shifting the decimal point in both the numerator and denominator. Since there is
1
number to the right of the decimal point, move the decimal point
1
place to the right.
55
1000
Cancel the common factor of
55
and
1000
11/200
Hi people! Can you help me figure this out? I'll mark brainliest!
D. 12.5
The equation to find the average rate of change is
[tex] \frac{y2 - y1 }{x2 - x1} [/tex]
To find the average rate of change between points (0,20) and (8,120) you need to plug it into the equation so it'll be
[tex] \frac{120 - 20}{8 - 0} [/tex]
this simplifies to
[tex] \frac{100}{8} [/tex]
which is 12.5
Multiply (Make sure to show work on a separate sheet of paper)
Please use the equation writer that is on top. Look for this sign √ and click on it. That will allow you to write an exponent.
(2x−4)(x−6)
Answer:
[tex]2x^{2}[/tex] - 16x + 14
Step-by-step explanation:
(2x - 4)(x - 6)
= (2x + −4)(x + −6)
= (2x)(x) + (2x)(−6) + (−4)(x) + (−4)(−6)
= [tex]2x^{2}[/tex] − 12x − 4x + 24
= [tex]2x^{2}[/tex] - 16x + 14
Please answer both questions I will give u brainliest if ur right
first one b 315, second d
Step-by-step explanation:
18*=3*+315
7*+4*=a*
The graph of a rational function f is shown below.
Assume that all asymptotes and intercepts are shown and that the graph has no "holes".
Use the graph to complete the following.
We have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.
What is a graph?A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.
The y-intercept of a function is determined by the intersection of its graph with the y-axis. The value of y on the y-axis at which the considered function crosses it is called the y-intercept.
Assume the following equation: y = f (x)
We have x =0- 2 and y+2 = 0,The x and y intercept of the given function is -2 and +2.
The vertical asymptote is none. The horizontal asymptote is 2.
Hence,we have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.
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(04.01, 04.02 HC)
Eric plays basketball and volleyball for a total of 95 minutes every day. He plays basketball for 25 minutes longer than he plays volleyball.
Part A: Write a pair of linear equations to show the relationship between the number of minutes Eric plays basketball (x) and the number of minutes he plays volleyball (y) every day. (5 points)
Part B: How much time does Eric spend playing volleyball every day? Show your work. (3 points)
Part C: Is it possible for Eric to have spent 35 minutes playing basketball if he plays for a total of exactly 95 minutes and plays basketball for 25 minutes longer than he plays volleyball? Explain your reasoning. (2 points)
Eric spend 60 minutes for basketball and 35 minutes for volleyball.
What is Linear Equation?An equation that has the highest degree of 1 is known as a linear equation. This means that no variable in a linear equation has an exponent more than 1. The graph of a linear equation always forms a straight line.
Here, let Eric plays basketball for x minutes.
and volleyball for y minutes.
Total time spend on playing basketball and volleyball everyday = 95 minutes.
Duration of Basketball 25 minutes more than volleyball
Now, according to question,
x + y = 95 ..........(i)
x - 25 = y ...........(ii)
On solving equation (i) and (ii), we get
x + x - 25 = 95
2x = 95 + 25
2x = 120
x = 120 / 2
x = 60
put value of x in equation (ii), we get
60 - 25 = y
y = 35
Yes, it is possible and clearly described in above calculation.
Thus, Eric spend 60 minutes for basketball and 35 minutes for volleyball.
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Let f(x) = -5x^6√x + -7/x³√x. What would f’(x) be? If anyone could show me step-by-step, I would greatly appreciate it! I’ve worked out this problem 4 times already and I can’t seem to get the right answer.
Answer:
[tex]f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}[/tex]
or
[tex]f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}[/tex]
Step-by-step explanation:
Rather than solving this question in a more complex method by directly using the product rule and quotient rule, it can first be considered to perform some algebraic manipulation (index laws) to simplify the expression before taking the derivative.
[tex]\begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^6\ \sqrt{x}\ +\ \frac{-7}{x^3\ \sqrt{x}}\\\\f\left(x\right)\ =\ -5x^6\cdot x^{\frac{1}{2}}\ +\ \frac{-7}{x^3\cdot x^{\frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{6\ +\ \frac{1}{2}}\ +\ \frac{-7}{x^{3\ +\ \frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ +\ \frac{-7}{x^{\frac{7}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\end{array}[/tex]
Now, the derivative of the function can be calculated simply by only using the power rule, which yields
[tex]\begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\\\\f^{\prime}\left(x\right)\ =\ \left(-5\right)\left(\frac{13}{2}\right)\left(x^{\frac{13}{2}\ -\ 1}\right)\ -\ \left(7\right)\left(-\frac{7}{2}\right)\left(x^{-\frac{7}{2}\ -\ 1}\right)\\\\f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}\\\\f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}\end{array}\\\end{large}[/tex]
How do I find dy/dx of the following?
Answer:
[tex]\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}[/tex]
Step-by-step explanation:
[tex]y \ = \ x^{3} \ - \ \displaystyle\frac{1}{\sqrt{x}} \ + \ \displaystyle\frac{3}{x^{4}} \\ \\ y \ = \ x^{3} \ - \ x^{-\frac{1}{2}} \ + \ 3x^{-4} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{3 \ - \ 1} \ - \ \left(-\displaystyle\frac{1}{2}\right)x^{-\frac{1}{2} \ - \ 1} \ + \ \left(-4 \ \times \ 3\right)x^{-4-1}[/tex]
[tex]\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2}x^{-\frac{3}{2}} \ - \ 12x^{-5} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}[/tex]
convert 0.390 as a fraction
Answer:
390/1000
This is the answer and hope it helps
find the missing values in this sequence; -6;...;3...;15.
Answer:
Maybe 9 and 12 ?
Step-by-step explanation:
-6 + 9 = 3
then 3 + 9 = 12
then 12 + 3 = 15
each term is the sum of the two that are before it
About 5% of hourly paid workers in a region earn the prevailing minimum wage or less. A grocery chain offers discount rates to companies that have at least employees who earn the prevailing minimum wage or less. Complete parts (a) through (c) below. Company B has 540 employees. What is the probability that Company B will get the discount?
The probabilities for various binomial distribution have been determined.
The complete question is
About 5% of hourly paid workers in a region earn the prevailing minimum wage or less. A grocery chain offers discount rates to companies that have at least 30 employees who earn the prevailing minimum wage or less. Complete parts (a) through (c) below.
(a) Company A has 285 employees. What is the probability that Company A will get the discount? (Round to four decimal places as needed.)
(b) Company B has 502 employees. What is the probability that Company B will get the discount? (Round to four decimal places as needed.)
(c) Company C has 1033 employees. What is the probability that Company C will get the discount? (Round to four decimal places as needed.)
What is Probability ?Probability is a stream in mathematics that study the likeliness of an event to happen .
On the basis of the given data
(a) Let X is a random variable that denotes the number of employees that earn less than prevailing average.
Here X has binomial distribution with
n=285 and p=0.05.
As np and n(1-p) are greater than 5 so using normal approximation X has normal distribution with parameters
μ= np-285 * 0.05
= 14.25
standard deviation is given by
[tex]\sigma=\sqrt{np(1-p)}=\sqrt{285* 0.05* 0.95}\\\\=3.6793[/tex]
Applying continuity correction.
The z-score for X = 30-0.5 = 29.5 is
[tex]z=\dfrac{29.5-14.25}{3.6793}\\\\=4.14[/tex]
The probability that Company A will get the discount is given by
[tex]P(X\geq 30)=P(z > 4.14)=0.0000[/tex]
(b) Let X is a random variable that denotes the number of employees that earn less than prevailing average.Here X has binomial distribution with
n=502 and p=0.05.
[tex]\rm \mu=np=502* 0.05=25.1[/tex]
standard deviation
[tex]\rm \sigma=\sqrt{np(1-p)}=\sqrt{502\cdot 0.05\cdot 0.95}=4.8831[/tex]
Applying continuity correction.
The z-score for X = 30-0.5 = 29.5 is
[tex]\rm z=\dfrac{29.5-25.1}{4.8831}=0.90[/tex]
The probability that Company B will get the discount is
[tex]P(X\geq 30)=P(z > 0.90)=0.1841[/tex]
(c)Let X is a random variable that denotes the number of employees that earn less than prevailing average.Here X has binomial distribution with
n=1033 and p=0.05.
[tex]\mu=np=1033\cdot 0.05=51.65[/tex]
standard deviation
[tex]\rm \sigma=\sqrt{np(1-p)}=\sqrt{1033*0.05* 0.95}=7.0048[/tex]
Applying continuity correction.
The z-score for X = 30-0.5 = 29.5 is
[tex]\rm z=\dfrac{29.5-51.65}{7.0048}=-3.16[/tex]
The probability that Company C will get the discount is
[tex]\rm P(X\geq 30)=P(z > -3.16)=0.9992[/tex]
Therefore the probabilities for various binomial distribution have been determined.
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The sum of the first n terms of a geometric series is 364? The sum of their reciprocals 364/243. If the first term is 1, find n and common ratio
If the geometric series has first term [tex]a[/tex] and common ratio [tex]r[/tex], then its [tex]N[/tex]-th partial sum is
[tex]\displaystyle S_N = \sum_{n=1}^N ar^{n-1} = a + ar + ar^2 + \cdots + ar^{N-1}[/tex]
Multiply both sides by [tex]r[/tex], then subtract [tex]rS_N[/tex] from [tex]S_N[/tex] to eliminate all the middle terms and solve for [tex]S_N[/tex] :
[tex]rS_N = ar + ar^2 + ar^3 + \cdots + ar^N[/tex]
[tex]\implies (1 - r) S_N = a - ar^N[/tex]
[tex]\implies S_N = \dfrac{a(1-r^N)}{1-r}[/tex]
The [tex]N[/tex]-th partial sum for the series of reciprocal terms (denoted by [tex]S'_N[/tex]) can be computed similarly:
[tex]\displaystyle S'_N = \sum_{n=1}^N \frac1{ar^{N-1}} = \frac1a + \frac1{ar} + \frac1{ar^2} + \cdots + \frac1{ar^{N-1}}[/tex]
[tex]\dfrac{S'_N}r = \dfrac1{ar} + \dfrac1{ar^2} + \dfrac1{ar^3} + \cdots + \dfrac1{ar^N}[/tex]
[tex]\implies \left(1 - \dfrac1r\right) S'_N = \dfrac1a - \dfrac1{ar^N}[/tex]
[tex]\implies S'_N = \dfrac{1 - \frac1{r^N}}{a\left(1 - \frac1r\right)} = \dfrac{r^N - 1}{a(r^N - r^{N-1})} = \dfrac{1 - r^N}{a r^{N-1} (1 - r)}[/tex]
We're given that [tex]a=1[/tex], and the sum of the first [tex]n[/tex] terms of the series is
[tex]S_n = \dfrac{1-r^n}{1-r} = 364[/tex]
and the sum of their reciprocals is
[tex]S'_n = \dfrac{1 - r^n}{r^{n-1}(1 - r)} = \dfrac{364}{243}[/tex]
By substitution,
[tex]\dfrac{1 - r^n}{r^{n-1}(1-r)} = \dfrac{364}{r^{n-1}} = \dfrac{364}{243} \implies r^{n-1} = 243[/tex]
Manipulating the [tex]S_n[/tex] equation gives
[tex]\dfrac{1 - r^n}{1-r} = 364 \implies r (364 - r^{n-1}) = 363[/tex]
so that substituting again yields
[tex]r (364 - 243) = 363 \implies 121r = 363 \implies \boxed{r=3}[/tex]
and it follows that
[tex]r^{n-1} = 243 \implies 3^{n-1} = 3^5 \implies n-1 = 5 \implies \boxed{n=6}[/tex]
Shashi has a rectangular garden. The length of the garden is 4 feet less than twice the width. The area of the garden is 448 square feet. What is the length of the garden?
Answer:
28 feet
Step-by-step explanation:
Area of a rectangle is :
A = L × W
We are given A and a expression for L, so let's substitute :
448 = (2W-4) × W
Now we expand the left side :
2W²-4w = 448
Subtract 448 from both sides :
2W²-4W-448 = 0
Divide everything by 2 :
W²-2W-224 = 0
Now we factorise :
Find 2 numbers that multiply to give -224 and add to give -2 :
-16 and 14
Rewrite -2W with -16W and +14W :
W² - 16W + 14W -224 = 0
W(W-16) +14(W-16) = 0
(W+14)(W-16) = 0
W = -14 , W = 16
Only take positive value since this is lengths :
W = 16
Now we substitute W into the expression to find L :
L = (2W -4)
L = 2(16) - 4
L = 32 - 4
L = 28
Units will be feet since it is a length
Hope this helped and have a good day
If x=0,what is the value of (8x)^0
[tex] {8x}^{0} \\( {8 \times 0})^{0} \\ {0}^{0} \\ it \: is \: undefined[/tex]
PLEASE GIVE BRAINLIEST
Camacho is buying a monster truck. The price of the truck is x dollars, and he also has to pay a 13%, percent monster truck tax. Which of the following expressions could represent how much Camacho pays in total for the truck?
The total price of the truck =$x + $ 0.13x
We have given that,
Camacho is buying a monster truck. The price of the truck is x dollars, and he also has to pay a 13%, percent monster truck tax.
We have to determine the expressions that could represent how much Camacho pays in total for the truck.
We will consider the price of the truck to be $x
What is the tax?And the amount of tax in the percentage would be 13%
13/100 = $ 0.13x (this is the actual amount of the tax)
Now we will calculate the total price of the truck =$x + $ 0.13x
= $ x(1 + 0.13)
If there is any confusion please leave a comment below.
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https://brainly.in/question/7196254
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