james brewer purchased 100 shares of stock for $73 a share. james also paid a $60 commission. what was the total purchase price for this transaction?

Using two triangle concepts, it is found that the solution for y is of y = 70º.

Hence:

Then:

x + y + 70 = 180

x + 190 - 3x + 70 = 180.

2x = 80.

x = 40.

Hence:

y = 190 - 3x = 190 - 3(40) = 70º.

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Answer:

B. 70

Explanation:

A total of 182 pairs of jeans and shorts were sold and the number of shorts sold was 28 fewer than twice the number of jeans. This can be expressed with j being the number of jeans as:

j2 - 28 = number of shorts

As the number of shorts is 28 lower than twice the number of jeans, this means it can not be C or D, as these numbers are larger than 182 when doubled. The process of elimination can be done with the remaining using our equation.

51(2) - 28 = 102 - 28 = 74
70(2) - 28 = 140 - 28 = 112

Now that we have the number of shorts sold by using the equation, we can add them with what number was used as their number of jeans.

74 + 51 = 125
112 + 70 = 182

So the number of jeans sold is B. 70.

Based on the calculations, Celine would earn a total of $65.00 assuming she delivered 10 packages.

A function can be defined as a mathematical expression which is used to define and represent the relationship that exists between two or more variable.

Given the following function:

y = 20.00 + 0.45(x)

In this exercise, you're required to determine Celine's weekly earnings based on the number of packages she delivered. However, the number of packages delivered by Celine wasn't shown, thus, we would assume a value for the purpose of an explanation:

Assuming x = 10 packages.

Substituting the value of x into the function, we have:

y = 20.00 + 0.45(10)

y = 20.00 + 45

y = $65.00.

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Answer:

A. (6x + 7)(6x - 7)

Step-by-step explanation:

use difference of squares, which says a^2 - b^2 =(a+b)(a-b)

take the square roots of the two numbers, 6x and 7, and use them as a and b

Answer:

(h, k )

Step-by-step explanation:

given the standard form of an absolute function

f(x) = a| x - h | + k , then

vertex = (h, k )

The standard form of an absolute value function is f(x) = a|x - h| + k, where (h,k) is the vertex of the absolute value function.

The correct option is (h,k).

The term "function" refers to a relationship between a set of inputs and outputs. Just one output is connected to each input in a function, which connects inputs in that manner. Every function has a domain, co-domain, and range.

In general, the standard form of an absolute value function is given as:

f(x) = a |x - h| + k

where:

a is a non-negative constant that determines the shape and direction of the V-shaped graph of the absolute value function

h is the horizontal shift of the graph of the function from the origin (if h > 0, the graph shifts to the right; if h < 0, the graph shifts to the left)

k is the vertical shift of the graph of the function from the origin (if k > 0, the graph shifts up; if k < 0, the graph shifts down)

The vertex of the absolute value function is the point where the graph changes direction, that is, the point where the graph changes from sloping downwards to sloping upwards or vice versa.

Since the vertex is the point of the absolute value function where the graph changes direction, it lies at the center of the V-shaped graph. Thus, the vertex is located at the point (h,k).

Therefore, in the standard form f(x) = a |x - h| + k, (h,k) represents the coordinates of the vertex of the absolute value function.

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Answer:

Vans - 7

Cars - 15

Step-by-step explanation:

$200 * 7 = $1400

$100 * 15 = $1500

$1400 + $1500 = $2900

The solutions to the system of equation f(x) and g(x) are [tex]\frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex] and

[tex]\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]

Quadratic equations are equations that has a leading degree of 2. Given the following functions:

f(x)=2x^(2)-3x-10

g(x)=-3x^(2)+20

To solve, we will use the quadratic formula as shown below;

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

For the quadratic equation f(x)=2x^(2)-3x-10

a = 2

b = -3

c = -10

Substitute

[tex]x=\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(-10)}}{2(2)}\\x=\frac{3\pm\sqrt{89}}{4}\\x= \frac{3+\sqrt{89}}{4} \ or \ \frac{3-\sqrt{89}}{4}[/tex]

For the quadratic equation -3x² + 20

a =-3

b = 0

c = 20

[tex]x=\frac{0\pm \sqrt{(0)^2-4(-3)(20)}}{2(-3)}\\x=\frac{\pm4\sqrt{15}}{-6}\\x=\frac{2\sqrt{15}}{3} \ or \ \frac{-2\sqrt{15}}{3}\\[/tex]

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Step-by-step explanation:

thr standard form for a quadratic equation is:

ax²+bx+c

in this example, a=1, b=(-1), c=(-42)

Answer:

12 km

Step-by-step explanation:

Let the total distance to be traveled = x

[tex]\sf \dfrac{4}{5} \ of \ the \ journey = 48\\\\[/tex]

        [tex]\sf \dfrac{4}{5}*x = 48\\\\[/tex]

             [tex]x = 48*\dfrac{5}{4}[/tex]

                = 12 * 5

            x = 60 Km

Distance still to traveled = 60 - 48 = 12Km

Answer:

18502.8229198

Answer:

18502.82292

Step-by-step explanation:

calculator

The management, organisation, and technology factors contributed to this problem are listed below.

The  problem in the airways was that corporation didn't know its customers, the airline hasn't been able to take use of its market opportunity in recent years.

Airways was unable to evaluate and keep track of its marketing efforts.

The technology factor that contributed were:

The Organisation factors that contributed were

The Management factors that contributed were

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Answer:

4.1968

Explanation:

Given that:

angle: 25°

opposite: x

adjacent: 9

So, use the tan rule:

opposite/adjacent = tan(x)

x/9 = tan(25)

x = 9tan(25)

x = 4.1968

Option A

Answer:

Hey there : y= 3x - 3

Answer:

y = [tex]\frac{3}{2}[/tex] x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line

Answer:

I believe the answer would be option D

Step-by-step explanation:

the distance formula is

[tex] \sqrt{(x - x1)^{2} + (y - y1)^{2} } [/tex]

So, substituting the values of the coordinates, you will get the answer of D

Answer: Option (4)

Step-by-step explanation:

We know that the radius of the circle is 3.

Using the distance formula, the distance from the given point to the center is

[tex]\sqrt{(\sqrt{6}-0)^{2}+(2-0)^{2}} = \sqrt{10} \neq 3[/tex]

Answer:d

Step-by-step explanation:

Answer:

============================

[tex]\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}[/tex]

Bring both fractions into common denominator:

[tex]\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}[/tex]

Simplify:

[tex]\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]

[tex]\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]

[tex]\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =[/tex]

[tex]\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =[/tex]

[tex]\dfrac{4\sqrt{14} }{7-4} =[/tex]

[tex]\dfrac{4}{3} \sqrt{14} }[/tex]

Compare the result with given expression to get:

The equation that represents this number sentence is 1/5n - 3 = 28

Let the unknown number be "n". One-fifth of a number is expressed as 1/5n

Three less than one-fifth of a number is expressed as 1/5n - 3

Finally, if three less than one-fifth of a number is equal to 28, then the final expression will be 1/5n - 3 = 28

The equation that represents this number sentence is 1/5n - 3 = 28

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Answer:

The answer is C. -2x -4

Step-by-step explanation:

Your given information.

-3 - 3x - 1 + x

Combine and simplify common numbers/variables.

(-3x + x) + (-3 - 1)

-2x - 4

Answer:

4x² + x - 7

Step-by-step explanation:

Given f(x) = -3 and g(x) = 4x² + x - 4, solve for (f + g)(x).

Step 1: Replace the function designators with the actual functions in f(x) and g(x); that gives us 4x² + x - 4 - 3.

Step 2: Simplify; that gives us the answer 4x² + x - 7.

Answer:

625 × 48 = 30,000

[tex]\sqrt[4]{30000} = 10 \sqrt[4]{3} [/tex]

answer = third option

When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet  , Minimum at (2,4)

Therefore Option C and D is the correct answer.

The equation for a quadratic function is given by

y = a(x-h)² +k²

where (h,k) is the extreme value(vertex).

Here the equation given is

y = x²-4x +8

y = x²-4x+4+4

y = (x-2)² +4

Here the value of a = 1 , h = 2 and k = 4

The extreme value is at (2,4)

Therefore When the bird is 2 feet away from the first fence post, it reaches its minimum height of 4 feet  , Minimum at (2,4)

Therefore Option C and D is the correct answer.

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Answer:

distance between -5 to 0 = 5 units

The value of y when x is equal to zero will be 330.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

The given function is;

y = 330 + 25x

We have to find the value of y when x is equal to zero.

So,

Put x = 0

y = 330 + 25x

y = 330 + 25(0)

y = 330

Hence, the value of y when x is equal to zero will be 330.

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[tex]\large\sf{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large \sf{=\frac{\left(\sqrt{1+sin\theta}\right)^{2}+\left(\sqrt{1-sin\theta}\right)^{2}}{\sqrt{(1-sin\theta)(1+sin\theta)}}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{=\frac{1-sin\theta+1+sin\theta}{\sqrt{1^{2}-sin^{2}\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large \sf{=\frac{2}{\sqrt{cos^{2}\theta}}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{= \frac{2}{cos\theta}}[/tex]

[tex]\\[/tex]

[tex]\large\sf{= 2sec\theta}[/tex]

[tex]\\[/tex]

[tex]\large\sf{=RHS}[/tex]

Therefore,

[tex]\large\sf\red{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}=2sec\theta}[/tex]

The coordinates of the point that is 4/5 of the way from T to S is (2,10)

The given parameters are:

T = (6,-2)

S = (1,13)

Location = 4/5

The location 4/5 means

Ratio, m : n = 4 : 1

The coordinate is then calculated as:

[tex](x,y) = \frac{1}{m +n} * (mx_2 + nx_1,my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{4 +1} * (4 * 1 + 1 * 6 , 4 * 13 + 1 * -2)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (10 , 50)[/tex]

This gives

(x,y) =  (2,10)

Hence, the coordinates of the point that is 4/5 of the way from T to S is (2,10)

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Answer:

25

Step-by-step explanation:

This is an equilateral triangle so all of its angle measures, and side lengths likewise, are equal.

To find x we can use the following equation:

3x - 5 = 2x + 20 export like terms to the same side of the equation

3x - 2x = 20 + 5 (notice how terms change from "+" to "-" and vice versa)

add/subtract like terms

x = 25

Answer:

x=1, y=1. (1, 1).

Step-by-step explanation:

y=-5x+6

y=3x-2

------------

-5x+6=3x-2

-5x-3x+6=-2

-8x+6=-2

-8x=-2-6

-8x=-8

8x=8

x=8/8=1

y=3(1)-2=3-2=1

Answer:

92

Step-by-step explanation:

46 + 46 = 92

Answer:

38 is the correct solution