In the following chapter, enzyme catalysis reactions will be extensively reviewed. The first step in these reactions involves the binding of a reactant molecule (referred to as a substrate) to a binding site on the enzyme. If this binding is extremely efficient (that is, equilibrium strongly favors the enzyme–substrate complex over separate enzyme and substrate) and the formation of product rapid, then the rate of catalysis could be diffusion limited. Estimate the expected rate constant for a diffusion controlled reaction using typical values for an enzyme ( and Å) and a small molecular substrate ( and Å).

Answer:

i have the same question

Explanation:

Answer: In a compound with molecular formula [tex]X_2Y_3[/tex] ,the valency of Y and X are 2 and 3 respectively.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

The given compound is [tex]X_2Y_3[/tex] where X and Y combine and their oxidation states or valencies are exchanged and written in simplest whole number ratios. Thus the oxidation state or valency of X is 3 and that of Y is 2.

The valency of X is 3 and the valency of Y is 2.

The valency is more simply defined as the combining power of an element. We can see the valency of an element from the subscript of the other atom in the compound. This will now serve as our guide in decoding the valencies of X and Y.

Hence, the valency of X is 3 and the valency of Y is 2.

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Answer:

Hi..? All three elements are in group 1 thus they have 1 valence electron which is easy to lose due to shielding.As Pottasium is larger than the rest,Pottasium's valence electron is at a greater distance from the attractive nucleus and is so removed more easily than Sodium's and Lithium's valence electrons.As it is removed more easily it requires less energy and can be said to be more reactive

Answer:

Explanation:

1 mole atoms - 6,02 * [tex]10^{23}[/tex]

4 moles atoms - x

x = 4 * 6,02 * [tex]10^{23}[/tex] * 6

x = 24 * 6,02 * [tex]10^{23}[/tex]

x = 144,48 atoms ≅ 144 atoms

Answer:

3, H⁺ acceptor

Explanation:

Let's consider Bronsted-Lowry acid-base theory.

According to this theory, an acid is a substance that donates H⁺ ions. For example, HCl is an acid.

HCl + H₂O = Cl⁻ + H₃O⁺

Cl⁻ is the conjugate base of HCl.

According to this theory, a base is a substance that accepts H⁺ ions. For example, NH₃ is a base.

NH₃ + H₂O = NH₄⁺ + OH⁻

NH₄⁺ is the conjugate acid of NH₃.

According to one acid-base theory, a base is an H+ acceptor.

The acid-base theory, also called the Brønsted-Lowry theory, is a theory developed by Johannes N. Brønsted and Thomas M. Lowry.

In conclusion, according to one acid-base theory, a base is an H+ acceptor.

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Answer:

Synthesis

Explanation:

Because the reactants aren't compounds, it has to be a synthesis reaction, in which Cu and O combine to make copper oxide.

Answer:

Synthesis

Explanation:

d

Answer: The solution to the problem expressed to he correct number of significant figures is 1.69

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule applied for multiplication and division is :

The least precise number determines the number of significant figures in the answer.

As 12.0 has 3 significant digits and 7.11 also has 3 significant digits, the answer would also contain 3 significant digits.

For [tex]\frac{12.0}{7.11}=1.69[/tex]

Thus the solution to the problem expressed to he correct number of significant figures is 1.69

Answer:

1.69

Explanation:

12.0 ÷ 7.11 = 1.687

The rule of significant figures for division is that the quotient must have the same number of significant figures as the number that has the fewest significant figures.

Both 12.0 and 7.11 have three significant figures. Because of this, we know that we must round our quotient to three significant figures as well. 1.687 rounded to the nearest tenth is 1.69. So our answer is 1.69.

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Answer:

0.5472 moles of H₂O are produced

0.1992 moles of C₈H₁₈ were left

Explanation:

The reaction of octane (C₈H₁₈) with oxygen (O₂) is:

C₈H₁₈ + 25/2 O₂ → 8CO₂ + 9H₂O

Where 1 mole of octane reacts with 25/2 moles of oxygen to produce 8 moles of carbon dioxide and 9 moles of water

For a complete reaction of 0.760moles of oxygen there are needed:

0.760 mol O₂ ₓ (1 mole C₈H₁₈ / 25/2 moles O₂) = 0.0608 moles of C₈H₁₈

As you have 0.260 moles, the moles of octane that were left are:

0.260 mol - 0.0608 mol = 0.1992 moles of C₈H₁₈

Now, if 0.760 moles of O₂ react, the moles of water that are produced are:

0.760 mol O₂ ₓ (9 moles H₂O / 25/2 moles O₂) = 0.5472 moles of H₂O

The characteristics of a strong acid is that it has a weaker bond to hydrogen. That is option D.

A strong acid is defined as the type of acid that completely dissociates in an aqueous solution during a chemical reaction.

Typical examples of strong acid include the following:

The characteristics of strong acids over weak acids is that they bond weakly with hydrogens.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The step wise mechanism  is shown on the second uploaded image

Explanation:

Answer:

HClO₃

Explanation:

Empirical formula of a chemical compound is defined as the simplest ratio of atoms presents in the compound (In whole numbers).

For the H₂Cl₂O₆ the empirical formula could be obtained dividing in 2 the formula. That is:

HClO₃ → This is the simplest ratio of atoms presents in the compound, that is, the empirical formula

Answer:

the final state of the hydrogen atom = 3

Explanation:

From the given information;

Let first calculate the amount of energy by the ground state atom during the atoms absorbs  photon light  by using the formula:

[tex]E_{absorbs} = \dfrac{hc}{\lambda}[/tex]

where;

h = planck's constant = [tex]6.626*10^{-34 }\ \ Js[/tex]

c = speed of light = [tex]3.0*10^8 \ \ m/s[/tex]

λ = wavelength = 92.57 nm = 92.57 × 10⁻⁹ m

[tex]E_{absorbs} = \dfrac{6.626*10^{-34 }\ \ Js * 3.0*10^8 \ \ m/s}{92.57*10^{-9} \ \ m}[/tex]

[tex]E_{absorbs} = 2.15 *10^{-18} \ J[/tex]

The energy emitted by the hydrogen atom is calculated by using the same formula from above ; but here , the wavelength λ = 954.3 nm = 954.3 × 10⁻⁹ m

[tex]E_{absorbs} = \dfrac{6.626*10^{-34 }\ \ Js * 3.0*10^8 \ \ m/s}{954.3*10^{-9} \ \ m}[/tex]

[tex]E_{absorbs} = 2.08 *10^{-19} \ J[/tex]

The change in the energy absorbed is:

[tex]\Delta E= 2.15 *10^{-18} \ J - 2.08 *10^{-19} \ J[/tex]

[tex]\Delta E= 1.94 *10^{-18} \ J[/tex]

The final state of the atom can be determined by using the relation:

[tex]\Delta E = R_H [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}][/tex]

where;

[tex]R_H[/tex] = Rydberg constant = 2.18 × 10⁻¹⁸ J

[tex]\dfrac{\Delta E}{R_H} = [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}] \\ \\ \\ \dfrac{1.94*10^{-18} \ J}{2.18*10^{-18} \ J } = [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}] \\ \\ \\ 0.889 = [\dfrac{1}{1^2}-\dfrac{1}{n^2_f}] \\ \\ \\ 1 - 0.889 = \dfrac{1}{n^2_f} \\ \\ \\ 0.111= \dfrac{1}{n^2_f} \\ \\ \\ {n^2_f} = \dfrac{1}{0.111} \\ \\ \\ {n^2_f} = 9 \\ \\ \\ {n_f} = \sqrt{9} \\ \\ \\ \mathbf{n_f = 3}[/tex]

Thus; the final state of the hydrogen atom = 3

[tex]E_a_b_s_o_r_b_e_d = (6.626 * 10^-^3^4 J.s) * (3.00 * 10^8 m/s) / (92.57 *10^-^9 m)[/tex]We can use the fact that the energy of the photon is given by the equation: to determine the final position of the hydrogen atom.

E = hc / λ

Where:

E is the energy of the photon,

h is Planck's constant [tex](6.626 * 10^-^3^4 J.s)[/tex],

c is the speed of light in a vacuum [tex](3.00 * 10^8 m/s)[/tex], and

λ is the wavelength of the photon.

Let's first determine the energy of the absorbed photon:

[tex]E_a_b_s_o_r_b_e_d = hc /[/tex]λ[tex]_a_b_s_o_r_b_e_d[/tex]

[tex]E_a_b_s_o_r_b_e_d = (6.626 * 10^-^3^4 J.s) * (3.00 * 10^8 m/s) / (92.57 *10^-^9 m)[/tex]

The energy of the photon released will then be determined by:

[tex]E_e_m_i_t_t_e_d = hc[/tex] / λ[tex]_e_m_i_t_t_e_d[/tex]

E[tex]_e_m_i_t_t_e_d[/tex] = [tex](6.626 * 10^-^3^4 J.s) * (3.00 * 10^8 m/s) / (945.3 *10^-^9 m)[/tex]

The energy difference between the absorbed and released photons must now be determined:

ΔE = [tex]E_e_m_i_t_t_e_d - E_a_b_s_o_r_b_e_d[/tex]

The energy levels of hydrogen are given by the equation:

ΔE = -13.6 eV *[tex](1 / n^2_f_i_n_a_l - 1 / n^2_i_n_i_t_i_a_l)[/tex]

Where

[tex]n_f_i_n_a_l[/tex] and [tex]n_i_n_i_t_i_a_l[/tex] are the principal quantum numbers of the final and initial states, respectively, and -13.6 eV is the ionization energy of hydrogen.

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Answer:

b. 186 g

Explanation:

Step 1: Write the balanced equation.

4 NH₃(g) + 6 NO(g) → 5 N₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 145 g of N₂

The molar mass of nitrogen is 28.01 g/mol.

[tex]145g \times \frac{1mol}{28.01 g} =5.18 mol[/tex]

Step 3: Calculate the moles of NO required to produce 5.18 moles of N₂

The molar ratio of NO to N₂ is 6:5.

[tex]5.18molN_2 \times \frac{6molNO}{5molN_2} = 6.22molNO[/tex]

Step 4: Calculate the mass corresponding to 6.22 moles of NO

The molar mass of NO is 30.01 g/mol.

[tex]6.22mol \times \frac{30.01g}{mol} =186 g[/tex]

The mass of NO required to produce 145 g of N₂ is 186 g.

The correct answer to the question is Option B. 186 g

We'll begin by calculating the mass of NO that reacted and the mass of N₂ produced from the balanced equation.

4NH₃ + 6NO —> 5N₂ + 6H₂O

Molar mass of NO = 14 + 16 = 30 g/mol

Mass of NO from the balanced equation = 6 × 30 = 180 g

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 5 × 28 = 140 g

From the balanced equation above,

140 g of N₂ were produce by 180 g of NO

Finally, we shall determine the mass of NO required to produce 145 g of N₂

From the balanced equation above,

140 g of N₂ were produce by 180 g of NO

Therefore,

145 g of N₂ will be produce by = (145 × 180) / 140 = 186 g of NO

Thus, 186 g of NO is required for the reaction.

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Answer:

Compound A: Propylbenzene

Compound B: Cumene

Explanation:

On this case, we have two clues:

1) The mass spectrometry info

2) The formation of benzoic acid

If we have the formation of benzoic acid with a strong oxidant ([tex]H_2CrO_4[/tex]). It means that we have an alky group bonded to benzene. Therefore we have to add three carbons to a benzene ring in order to obtain the mass of the compound (120).

The next question is how these three additional carbons are bonded to the benzene. For this, we have to check the mass info. For compound A we have a fragmentation moeity on 91 therefore we have a loss of an ethyl group. Therefore compound A have a linear structure for the aditional three carbons.

For compound B we have a fragmentation moeity on 105 this means a loss of 15 units of mass therefore we loss a methyl group. This indicates that we have a non linear structure fo the three additional carbons.

See figures 1 and 2.

I hope it helps!

Answer:

The amount of  ampicillin stock is  [tex]V_3 = 7.5 mL[/tex]

The amount of deionized  is 22.5 \ mL

Explanation:

From the question we are told that

   The volume of stock solution of ampicillin in de-ionized water is [tex]V_0 = 100 mL[/tex]

   The concentration (in mg ) of ampicillin in de-ionized is [tex]C_0 = 100 mg/mL[/tex]

    The volume of ampicillin in deionized water to produce is [tex]V_2 = 30ml[/tex]

The concentration (in mg )  of ampicillin in de-ionized water to produce is [tex]C_2 = 25 mg/mL[/tex]

The chemical process can be mathematically represented as

            [tex]V_3 100 = 30 * 25[/tex]

=>          [tex]V_3 = \frac{30*25}{100}[/tex]

             [tex]V_3 = 7.5 mL[/tex]

The amount of  ampicillin stock is  [tex]V_3 = 7.5 mL[/tex] and amount of 25 mL  (30 - 7.5 = 22.5 mL ) of deionized water

Answer:

The correct answer is 0.10.

Explanation:

Based on the given question, in a buffer solution of 1 liter, the molarity of acetic acid is 1.420 M and the molarity of sodium acetate is 0.67. The pKa value of acetic acid given is 4.74, now the pH of buffer is,  

pH of buffer = pKa + log ([CH3COONa]/[CH3COOH])

= 4.74 + log (0.67/1.420)

= 4.74 + (-0.326)

= 4.41  

Now 0.10100 mol of HCl is added, the HCl reacts with sodium acetate to give,  

CH3COONa + HCl = CH3COOH + NaCl

Now the concentration of CH3COONa becomes = 0.67-0.101 = 0.57 M, and the new concentration of CH3COOH becomes = 1.420 + 0.101 = 1.52 M

Now the new pH will be,  

= pKa + log (0.57/1.52)

= 4.74 + (-0.426)

= 4.31

The pH change is 4.41-4.31 = 0.10  

Answer:

128

Explanation:

Step 1: Write the balanced equation

H₂(g) + I₂(g) ⇌ 2 HI(g)

Step 2: Make an ICE chart

         H₂(g) + I₂(g) ⇌ 2 HI(g)

I         3.75     2.15         0

C         -x         -x         +2x

E      3.75-x   2.15-x      2x

Step 3: Find the value of x

Since the concentration of I₂ at equilibrium is 0.0800 M,

2.15M-x = 0.0800 M

x = 2.07 M

Step 4: Calculate the concentrations at equilibrium

[H₂] = 3.75-x = 3.75-2.07 = 1.68 M

[I₂] = 0.0800 M

[HI] = 2x = 2(2.07) = 4.14 M

Step 5: Calculate the equilibrium constant Kc

[tex]Kc= \frac{[HI]^{2} }{[H_2]\times [I_2]} = \frac{4.14^{2} }{1.68\times 0.0800} = 128[/tex]

Answer:

If the cap is left off, some of the dissolved CO2 can escape as gas from the bottle, making the pop go flat faster (less dissolved CO2 in pop). If the cap is placed tightly, the gaseous CO2 cannot readily escape the bottle thus your pop won't go flat

Explanation:

If the cap is left off, some of the dissolved CO2 can escape as gas from the bottle, making the pop go flat faster. If the cap is placed tightly, the gaseous CO2 cannot readily escape the bottle thus your pop won't go flat.

Just some fun related concept:

A similar concept comes into play for the reason behind why pop tastes better in fridge then just keeping at normal temperature. This is because gases tend to have high solubility at cold temperatures thus CO2 is more readily dissolved in fridge than outside room temperature which is why it tastes great!

Here is the correct question.

Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons.

NF3

SBr2

CCl4

Answer:

Explanation:

The objective here is to draw the molecule three molecules by placing atoms on the grids and connecting them with their respective bonds, therefore including all the lone pairs of electrons.

See the attachment below for the diagrams.

The first compound is know as Nitrogentrifluoride. A non-flammable greenhouse gas. It is majorly used for he production of semi conductors. It has a trigonal planar structure.

SBr2: Sulfur dibromide is a yellowish liquid toxic gas. It results as a reaction between SCl_2 and HBr. Its has a Bent Structure.

CCl_4 : carbon tetrachloride has the presence of a colourless liquid with a sweet smell. Carbon tetrachloride is used for different domestic uses such as: cleaning surfaces, fumigating, cleaning metals etc. It has a tetrahedral structure.

Answer:

59.8287

Explanation:

I put that answer in and it is correct.

Answer:

Lengths. of. Naphthalene. Figure 3.20 shows that there are two equivalent ... all the carbon–carbon bonds of benzene are identical and are intermediate in length ... A typical carbon–carbon single bond has a length of 1.54 Å, and a double ... of how resonance can be used to explain or predict experimental observations.Explanation:

Answer:

E = 16 J

Explanation:

We have,

You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg

It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

Plugging all the values,

[tex]E=\dfrac{1}{2}\times 8\times 2^2 \\\\E=16\ J[/tex]

So, the maximum kinetic energy on his fastest day is 16 J.

Answer:2,4-dichlorohexane

Explanation:

Hope it helps

Answer:

Charge is balanced in oxidation half-reactions by adding electrons as products; in reduction half-reactions, charge is balanced by adding electrons as reactants.

Hope it helps :] !!!!!!!!!

Answer:

[tex]C_2=9.066x10^{-4}M[/tex]

Explanation:

Hello,

In this case, the first step is to compute the molarity of the first solution, for which we consider the molar mass of iron (III) nitrate that is 241.86 g/mol to compute the moles in 100.00 mL (0.1 L) of solution:

[tex]M=\frac{0.5482g*\frac{1mol}{241.86 g} }{0.1L}=0.0227 M[/tex]

Which is actually the concentration of iron (III) ions. Therefore, for 10.00 mL of such solution, the concentration until a dilution to 250.0 mL results being:

[tex]C_2=\frac{C_1V_1}{V_2} =\frac{0.0227M*10.00mL}{250.0mL} \\\\C_2=9.066x10^{-4}M[/tex]

Best regards.

Answer:

The correct answer is 1.89130 × 10⁻² g per ml.

Explanation:

Based on the given information, the volume of the water sample is 46 ml, the temperature given is 21 degree C. Weight of the compound mineral X is 0.87 grams obtained post evaporating, washing, and drying of the sample. Yes, on the basis of the given information, one can find the solubility of compound X in water at 21 degree C.  

As 46 ml of water comprise 0.87 grams of the mineral compound X. Therefore, 1 ml of the water sample will comprise,  

= 0.87/46 g of X

= 1.89130 × 10⁻² grams

Hence, the solubility of the compound X in the sample of water is 1.89130 × 10⁻² gram per ml.  

Answer:

mass of Mg=0.016g

Explanation:

P(Mg)=1.7g/cm³

P(Fe)=7.9g/cm³

m(Fe)=819g

P(Fe)=m(Fe)/v(Fe)

7.9=819/v(Fe)

v(Fe)=0.0096cm³

since v(Mg)=v(Fe)

=0.0096cm³

P(Mg)=m(Mg) /v(Mg)

1.7=m(Mg)/0.0096

m(Mg) = 0.016g

The mass of the Mg block has been found to be 176.24 grams.

The density can be defined as the mass per unit volume. The density can be expressed as:

Density = [tex]\rm \dfrac{Mass}{Volume}[/tex]

The volume of the object will be:

Volume = [tex]\rm \dfrac{Mass}{Density}[/tex]

The density of Mg block = 1.7 g/[tex]\rm cm^3[/tex]

The density of Fe block = 7.9 g/[tex]\rm cm^3[/tex].

Since the volume of both blocks has been the same.

[tex]\rm \dfrac{Mass\;of\;Mg\;block}{Density\;of\;Mg\;block}\;=\;\dfrac{Mass\;of\;Fe\;block}{Density\;of\;Fe\;block}[/tex]

The given mass of Fe block = 819 g.

Substitute the values:

[tex]\rm \dfrac{Mass\;of\;Mg\;block}{1.7\;g/cm^3}\;=\;\dfrac{819\;g}{7.9\;g/cm^3}[/tex]

Mass of Mg block = 176.24 g.

The mass of the Mg block has been found to be 176.24 grams.

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Answer:

principle quantum number :)

Explanation:

I took the test and got it right

Quantum numbers are defined as the set of four numbers with the help of which we can get complete information about the electrons in an atom. The energy level of an electron is given by Principal quantum number. The correct option is B.

The Principal quantum number represents the main energy level or shell in which the electron is present. It also determines the average distance of the orbital or electron from the nucleus. It is denoted by the letter 'n' and can have any whole number values like 1, 2, 3, 4,....

The value of principal quantum number usually stand for different energy shells K, L, M, N .... the value of 'n' can be any integer with a positive value which is equal to or greater than 1.

The value of 'n' denotes the innermost electron shell of an atom which indicates the lowest energy state of an electron. It cannot be a negative value.

Thus the correct option is B.

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Answer:

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

1.83 moles K (6.022 x 10^23 atoms / mole ) = 1.10 x 10^24 atoms K

Explanation:

1.83 moles K (6.022 x 10^23 atoms / mole ) = 1.10 x 10^24 atoms

Answer:

The chemical bond between atoms in metallic elements

Explanation:

Metallic bond is a bond that exist between metallic elements. It does not occur between metals and non metals.