Chemistry High School

how can one establish whether a liquid sample extracted from a plant is pure
​

Answers

Answer 1
The most accurate means of determining the purity of a substance is through the use of analytical methods. These methods, widely used in different industries, mostly involve chemical analysis, which can pinpoint the presence, identity and amount of impurities in the sample. The most simple chemical methods include gravimetry and titration. There are also the more advanced light-based or spectroscopic methods, such as UV-VIS spectroscopy, nuclear magnetic resonance and infrared spectroscopy. Chromatographic methods, such as gas chromatography and liquid chromatography, can also be used. Other methods used in testing the purity include mass spectroscopy, capillary electrophoresis, optical rotation and particle size analysis.

-basically nerdy talk for using machines controlling chemicals or other atoms to pinpoint any impurities

Related Questions

How many grams of Ag2S2O3 form
when 125.0 g AgBr reacts completely
according to the reaction below?

2AgBr + Na2S2O3 → Ag2S₂O3 + 2NaBr

Answers

Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

Reaction stoichiometry

In first place, the balanced reaction is:

2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgBr: 2 moles Na₂S₂O₃: 1 moleAg₂S₂O₃: 1 mole NaBr: 2 moles

The molar mass of the compounds is:

AgBr: 187.77 g/moleNa₂S₂O₃: 158 g/moleAg₂S₂O₃: 327.74 g/moleNaBr: 102.9 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgBr: 2 moles ×187.77 g/mole= 375.54 gramsNa₂S₂O₃: 1 mole ×158 g/mole= 158 gramsAg₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 gramsNaBr: 2 moles ×102.9 g/mole= 205.8 grams

Mass of Ag₂S₂O₃ formed

The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

[tex]mass of Ag_{2} S_{2} O_{3} =\frac{125 grams of AgBrx327.74 grams of Ag_{2} S_{2} O_{3}}{375.54 grams of AgBr}[/tex]

mass of Ag₂S₂O₃= 109.09 grams

Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.

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A calorimeter absorbs 2,508 J of energy from the snack shown in the data below. How much energy does the snack provide per
gram (J/g) according to the experiment?

Answers

The energy provided by the snack is obtained as 1254 J/g.

What is the energy of the snack?

The calorimeter is used to measure the energy content of food. The food is burnt in the calorimeter in order to determine the amount of energy that it contains. The mass of the food burnt is converted to energy.

Mass of food burnt = 3.52 g - 1.52 g = 2 g

The energy that is provided by the snack in J/g = 2,508 J/ 2 g

= 1254 J/g

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What is the answer to “An element is:”

Answers

Answer:

Option A

A pure chemical substance consisting of one type of atom.

Explanation: An element is a pure substance and is made of only one type of atom; it cannot be broken down into a simpler substance.

An element is defined as  a pure chemical substance consisting of one type of atom.

What is an element?

It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.There are 118 elements known to exist either naturally or artificially.

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Calculate how many grams would be required to prepare 600. 0 ml of 0. 150 m of naf? molar mass of naf is 41. 9 g/mo

Answers

Considering the definition of molarity and molar mass, the mass of NaF required is 3.771 grams.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liters}[/tex].

Definition of molar mass

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Mass of NaF required

In this case, you know:

molarity= 0.15 M= 0.15 [tex]\frac{moles}{L}[/tex]number of moles= ?volume= 600 mL= 0.6 L

Replacing in the definition of molarity:

[tex]0.15\frac{moles}{L} =\frac{number of moles}{0.6 L}[/tex]

Solving:

0.15 [tex]\frac{moles}{L}[/tex] × 0.6 L= number of moles

0.09 moles= number of moles

The molar mass of NaF is 41. 9 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 41.9 grams, 0.09 moles of the compound contains how much mass?

[tex]mass=\frac{0.09 molesx41.9 grams}{1 mole}[/tex]

mass= 3.771 grams

Finally, the mass of NaF required is 3.771 grams.

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molar mass:

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molarity:

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