A box in the shape of a rectangular prism has a width that is 5 inches greater than the height and a length that is 2 inches greater than the width. Write a polynomial expression in standard form for the volume of the box. Explain the meaning of any variables used.

as the following pic you can see the answer.

#diameter is 8 so radius is 4

Answer:

400

Step-by-step explanation:

4/5×500

=400 6s would be riled

Answer: [tex]3 \pm \sqrt{7}[/tex]

Step-by-step explanation:

[tex]1) \text{ } x^{2}-6x+2=0\\\\2) \text{ } x^{2}-6x=-2\\\\3) \text{ } x^{2}-6x+\left(\frac{-6}{2} \right)^{2}=-2+\left(\frac{-6}{2} \right)^{2}=7\\\\4) \text{ } (x-3)^{2}=7\\\\5) \text{ } x-3 =\pm \sqrt{7} \longrightarrow \boxed{3 \pm \sqrt{7}}[/tex]

Answer:

5

Step-by-step explanation:

Look at one of the coordinates to find k. For this example I'll look at the y-intercepts (0, 3) (for g(x)) and (0, -2) (for f(x))

g(0) = 3

g(0) = f(0) + k

3 = -2 + k

5 = k

Damek can form 14 three-digit numbers from the given situation. Hence, only 14 possibilities.

There are five number cards on the table.

2- digit 1 card

1- digit 0 card

2- digit 2 card

There is a possibility of putting 1 or 2 in the hundredth place.

If 1 is put in the hundredth place then there are 3 possibilities for tenth place 1,0,2

If 1 is put there then there is a possibility of 2 numbers 0,2 in ones place

If 2 is put then there is a possibility of 3 numbers 0,1,2 in ones place

If 0 is put then there is a possibility of 2 numbers 1,2 in ones place.

So, there are 7=(2+3+2) possibilities that the hundredth place is filled by 1.

Similarly, there will be 7 possibilities that the hundredth place is filled by 2.

Hence, there are 14 possibilities as required by the problem.

So, the possibilities of 3-digit numbers are (given the number cannot start with 0) 14.

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Answer:

5. 8π 6. 18π 7. 8.6π 8. 11/4π

Step-by-step explanation:

8. 2 3/4

2*4+3 = 11/4

Step-by-step explanation:

the perimeter of a rectangle is

2×length + 2×width

so, here

2×95 + 2×72 = 190 + 144 = 334 m

so, yes, the answer 2. 334 is correct.

The solution is Option B.

The total number of posts is the total perimeter of the rectangular field and the value of N = 334 posts

What is the Perimeter of a Rectangle?

The perimeter P of a rectangle is given by the formula, P=2 ( L + W) , where L is the length and W is the width of the rectangle.

Perimeter P = 2 ( Length + Width )

Given data ,

Let the number of posts be = N

Fencing posts have to be fixed at 1-metre intervals

The perimeter of the rectangular field = number of posts

Now , the equation will be

The length of the rectangular field = 95 m

The width of the rectangular field = 72 m

Perimeter P of the rectangle = 2 ( Length + Width )

Substituting the values in the equation , we get

Perimeter of the rectangle P = 2 ( 95 + 72 )

On simplifying the equation , we get

Perimeter of the rectangle P = 2 ( 167 )

Perimeter of the rectangle P = 334 m

Now , the number of posts = perimeter of the rectangular

So , the number of posts N = 334 posts

Therefore , the value of N is 334

Hence , the number of posts is 334 posts

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The simplest form of the square root of 48 is 4√3

Given the following rational function √48

The correct prime factorization is given as;

√48 = √3×16

√48  = √16 × √3

Since the square root of 16 is 4, hence;

√48 = 4√3

Hence the simplest form of the square root of 48 is 4√3

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Answer:

The answer is B

Step-by-step explanation:

By proportion , 3 : 2.91 = 2: x . then you write it in fraction

Answer:

Standard Deviation is s = 2.9

Step-by-step explanation:

Count = [tex]N[/tex] = 5

Mean = [tex]x^-[/tex] = 9

Variance = [tex]s^2[/tex] = 8.5

SD Formula = [tex]s = \sqrt \frac{1}{N - 1} (x_{i} - x^-)^2[/tex]

Variance Formula[tex]s^2 = \frac{(x_{i} - x^-)^2}{N- 1}[/tex]

Step 1: Calculate the variance

[tex]= \frac{(7-9)^2 + (5-9)^2 + (10-9)^2 + (11-9)^2 + (12 -9)^2 }{5-1}[/tex]

[tex]=\frac{34}{4} = 8.5[/tex]

Step 2: Apply square root/SD formula

[tex]=\sqrt{8.5} = 2.9[/tex]

Answer:

B is the correct answer

Step-by-Step:

Answer:

multiply 1/2 by each element in the matrix

Step-by-step explanation:

6. 32

39 15

Answer:

B

Step-by-step explanation:

The vertical asymptotes are the red dashed lines. They are x = -4 and x = 0. Think of them as electric fences that the graph cannot touch or cross. The curve can only get closer and closer.

This question has already been posted, so all credit goes to jimthompson5910.

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Answer:

The factors of the given equation are:

(11x−8)(11x+2)

Step-by-step explanation:

Since both terms are perfect squares,

Factorize using the difference of squares formula,

[tex]a^{2} -b^{2}[/tex][tex]=(a+b)(a-b)[/tex]

where a=11x−3 and b=5.

=> (11x-3+5)(11x-3-5)

=> (11x+2)(11x−8)

=>[tex](11x-3)^{2}-25[/tex]

Use the binomial theorem [tex](a-b)^{2}=a^{2} +b^{2} -2ab[/tex] to expand[tex](11x-3)^{2}-25[/tex]

=> [tex](11x^{2})+(3)^{2}- 2(11x)(3)-25[/tex]

=>[tex]121x^{2} + 9 - 66x -25[/tex]

=> [tex]121x^{2} -16+ 66x[/tex]

By the splitting method,

=> (11x−8)(11x+2)

The factors of the equation are (11x−8)(11x+2).

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Answer:

286+390+468÷3= answer

Step-by-step explanation:

[tex] = \sum \limits_{n = 1}^{7} ( - 2. {6}^{n - 1} )[/tex]

[tex] = \sum \limits_ {n = 1}^{n_{ \text{max}}} (a_1. {r}^{n - 1} )[/tex]

[tex] \: [/tex]

[tex]a_1 = - 2[/tex]

[tex]n = 7[/tex]

[tex]r = 6 \to r >1[/tex]

[tex] \: [/tex]

• Find S7.

[tex]s_n = a_1.( \frac{ {r}^{n} - 1}{r - n} )[/tex]

[tex]s_7 = - 2.( \frac{ {6}^{7} - 1 }{6 - 1} )[/tex]

[tex]s_7 = - 2.( \frac{279.936 - 1}{5} )[/tex]

[tex]s_7 = - 2.( \frac{279.935}{5} )[/tex]

[tex]s_7 = - 2 \: . \: 55.987[/tex]

[tex]s_7 = - 111.974[/tex]

The answer is B.

Answer:

-5x=-23

Or

X=23/5

Step-by-step explanation:

Answer:

2.4

Step-by-step explanation:

We must do the inverse of every operation:

15 + 12 = 27

27/5 = 5.4

5.4 - 3 = 2.4

Answer:

There are no solutions

Step-by-step explanation:

If y is greater or equal to 3x+1 it can not be less than 3x-3 since 3x-3 is 4 less than 3x+1. Therefore, there can not be any solutions for the system of inequalities.

Statement A is needed to complete this syllogism. its diagonals are perpendicular. Therefore, if a quadrilateral has 4 congruent sides then its diagonals are perpendicular.

A logical structure for a formal argument that includes a major, minor, and conclusion.

This syllogism cannot be concluded without Statement A. The diagonals of it are parallel. As a result, a quadrilateral's diagonals are perpendicular if it has four congruent sides.

If a quadrilateral has 4 congruent sides, then it is a rhombus. If it is a rhombus, then its diagonals are perpendicular.

Therefore, if a quadrilateral has 4 congruent sides then its diagonals are perpendicular.

Hence option A is correct.

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Answer:

a quadrilateral has 4 congruent sides

Step-by-step explanation:

Syllogisms are connected by a shared statement that connects a hypothesis to a different conclusion.

[tex]( {4x}^{2} - 7x - 2) - (3x - 8) \\ \\ {4x}^{2} - 7x - 2 - 3x + 8 \\ \\ {4x}^{2} - 10x + 4.[/tex]

Answer:

x = 115

z = 27

Step-by-step explanation:

x + 65 = 180 (same side interior angles)

x = 115

x = 3z +34 (alternate interior angles)

115 = 3z + 34

3z = 81

z = 27

Answer:

x = 15

Step-by-step explanation:

the opposite angles of a cyclic quadrilateral sum to 180° , then

6x + 20 + 3x + 25 = 180 , that is

9x + 45 = 180 ( subtract 45 from both sides )

9x = 135 ( divide both sides by 9 )

x = 15

Answer:

1-3

2-2

3-1

Step-by-step explanation:

Answer:

19-73 19-73 and the other half way back home from the

to ghana 5hjgf and to the 8

Answer:

a. y = 2(x + 3)² - 17

b. y = 4(x + 6)² - 154

Step-by-step explanation:

a. y = 2x² + 12x + 1

y = 2[(x² + 6x)] + 1

y = 2[(x + 3)² - 9] + 1

y = 2(x + 3)² - 18 + 1

y = 2(x + 3)² - 17

b. y = 4x² + 48x - 10

y = 4[(x² + 12x)] - 10

y = 4[(x + 6)² - 36)] - 10

y = 4(x + 6)² - 144 - 10

y = 4(x + 6)² - 154

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: x² + y² = 64[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Standard equation of circle is :

[tex]\qquad \tt \rightarrow \: (x - h) {}^{2} + (y - k) {}^{2} = {r}^{2} [/tex]

Since the circle is centered at origin, h = k = 0

[tex]\qquad \tt \rightarrow \: (x - 0) {}^{2} + (y - 0) {}^{2} = {8}^{2} [/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + {y}^{2} = 64 [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

There are multiple ways to prove congruence between two triangles:

Keep in mind that the order of the letters matters.

Given triangle JLM, we know that

This is only one of the ways to prove congruence with these two triangles.

Answer:

-2

Step-by-step explanation:

just a guess but it's right