Help solve these two problems im having trouble trying to start these problems?​

Answer:

The acceleration of a small piece of ice is 10.40 m/s².

Explanation:

The electric force is given by:

[tex]F = Eq[/tex]

Where:    

E is the electric field = 1.07x10⁵ N/C

q is the charge = 1.05x10⁻¹¹ C          

The electric force is equal to Newton's second law:

[tex] Eq = ma [/tex]

Where:            

m is the mass = 1.08x10⁻⁴ g = 1.08x10⁻⁷ kg

a is the acceleration

Hence, the acceleration is:

[tex] a = \frac{Eq}{m} = \frac{1.07 \cdot 10^{5} N/C*1.05 \cdot 10^{-11} C}{1.08 \cdot 10^{-7} kg} = 10.40 m/s^{2} [/tex]

Therefore, the acceleration of a small piece of ice is 10.40 m/s².

I hope it helps you!                    

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Note: The question is in complete. The complete question is given below:

Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference frame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h.  Which conclusion is best supported by the information?

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Rhea is standing still after kicking the ball, and Sean is running away from Rhea.

Both soccer players are standing still after the ball is kicked.

Both soccer players are running while the ball is in motion.

Explanation:

A reference frame is a position from which something is observed.

Since from the reference frame of Rhea, the ball is moving at a speed of 13 km/h after he kicks the ball at a speed of 13km/h whereas from the frame of reference of Sean, the ball is moving at a speed of 22km/h, there is a difference in the speed of the ball as seen from Rhea's and Sean's frame of reference of about 9 km/h. This difference can only be due to relative motion between the ball and Rhea.

Therefore, the best conclusion supported by the given information is that Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Answer:

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Note: The question is in complete. The complete question is given below:

Rhea kicks a soccer ball at 13 km/h to Sean. After kicking the ball, the speed of the soccer ball from Rhea's reference frame is 13 km/h. The speed of the soccer ball from Sean's reference frame is 22 km/h.  Which conclusion is best supported by the information?

Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Rhea is standing still after kicking the ball, and Sean is running away from Rhea.

Both soccer players are standing still after the ball is kicked.

Both soccer players are running while the ball is in motion.

Explanation:

A reference frame is a position from which something is observed.

Since from the reference frame of Rhea, the ball is moving at a speed of 13 km/h after he kicks the ball at a speed of 13km/h whereas from the frame of reference of Sean, the ball is moving at a speed of 22km/h, there is a difference in the speed of the ball as seen from Rhea's and Sean's frame of reference of about 9 km/h. This difference can only be due to relative motion between the ball and Rhea.

Therefore, the best conclusion supported by the given information is that Sean is standing still, and Rhea is running toward Sean while kicking the ball.

Answer:

D

Explanation:

Answer:

The answer is C. Strong Nuclear

Explanation:

I took this test and it was correct!

Answer:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

Explanation:Hope this helps :)

By definition, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

First of all, an atom is the smallest constituent unit of ordinary matter that has the properties of a chemical element.

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.

In other words, every atom consists of a nucleus in which neutrons and protons meet and energy levels where electrons are located.

This is, the atomic nucleus is the central part of the atom that is made up of protons and neutrons, while the orbitals or peripheral region is an area where electrons are found.

In summary, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

Learn more:

Answer:

hi

Explanation:

hiijjjjjjjjjjjjjjj

Answer:

No

Explanation:

It was made in the 17th century

The answer is A I Hope this answer helps you (i got the question right)

Answer:

A. As speed increases, kinetic energy increases exponentially.

Explanation:

The amount of kinetic energy an object has depends on the speed. Kinetic energy is also known as "motion energy." This being said, if speed is increasing, decreasing, or staying constant, the kinetic energy of the object will too.

Answer:

What do you mean ma´am/sir?

Explanation:

Answer:

This answer was wrong

Explanation:

I took the test and I missed this question.  So it is not answer B: pass a literacy test.  

It will need an A. pass a vision and hearing test

Learn more about the insurance here: https://brainly.com/question/989103?referrer=searchResults

Taking into account the definition of wavelength, frecuency and propagation speed, the frequency is 5 Hz.

Wavelength (λ) is the distance between two consecutive points that are in the same state of vibration (the state of vibration is called phase). It is expressed in units of length (m).

Frequency (f) is the number of waves per unit of time and is normally expressed in Hertz (Hz) which is the number of waves per second.

The velocity of propagation is the speed with which the wave propagates in the medium. Relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f * λ

In this case, you know:

Replacing in the previous expression:

50 m/s= f× 10 cm

Solving;

f= 50 m/s÷ 10 cm

f= 5 Hz

Finally, the frequency is 5 Hz.

Learn more:

Answer:

a- More heat is required for the constant-pressure process than for the constant-volume

Explanation:

we have to solve using the thermodynamic first law. this is the heat applied to the system

dQ = dU + dW

definition of terms:

dU = change in internal energy

dW = work done

we have it that

change in internal energy dU is directly proportional to work done dW

but when we are in constant volume process, work done of the gas is zero

therefore

dQ of constant pressure is > than that of constant volume

so constant pressure process requires more heat

The process that requires more heat is the constant-pressure process than the constant-volume process.

According to the first law of thermodynamics, the heat that's applied to the system will be the addition of the change in internal energy and the work done.

In a constant-volume process, the work done on the gas is equal to zero. More heat will be required for the constant-pressure process than for the constant-volume process.

Also, it should be noted that the change in the thermal energy of the gas will be the same for the constant-pressure process and the constant-volume process.

Read related link on:

https://brainly.com/question/16951562

Answer:

A) v3 = -[6.29 × 10^(6)]j^ - [7.06 × 10^(6)]i^

B) K_total = 373.08 × 10^(-15) J

Explanation:

We are given;

Mass of unstable atomic nucleus; M = 1.83 × 10^(-26) kg

Mass of first particle; m1 = 5.03 × 10^(-27) kg

Speed of first particle in y-direction; v1 = (6 × 10^(6) m/s) j^

Mass of second particle; m2 = 8.47 × 10^(-27) kg

Speed of second particle in x - direction; v2 = (4 × 10^(6) m/s) i^

Now, we don't have the mass of the third particle but since we are told the unstable atomic nucleus disintegrates into 3 particles, thus;

M = m1 + m2 + m3

1.83 × 10^(-26) = (5.03 × 10^(-27)) + (8.47 × 10^(-27)) + m3

m3 = (1.83 × 10^(-26)) - (13.5 × 10^(-27))

m3 = 4.8 × 10^(-27) kg

A) Applying law of conservation of momentum, we have;

MV = (m1 × v1) + (m2 × v2) + (m3 × v3)

Now, the unstable atomic nucleus was at rest before disintegration, thus V = 0 m/s.

Thus, we now have;

0 = (m1 × v1) + (m2 × v2) + (m3 × v3)

We want to find the velocity of the third particle v3. Let's make it the subject of the formula;

v3 = [(m1 × v1) + (m2 × v2)]/(-m3)

Plugging in the relevant values, we have;

v3 = [(5.03 × 10^(-27) × 6 × 10^(6))j^ + (8.47 × 10^(-27) × 4 × 10^(6))i^]/(-4.8 × 10^(-27))

v3 = [(30.18 × 10^(-21))j^ + (33.88 × 10^(-21))i^]/(-4.8 × 10^(-27))

v3 = -[6.29 × 10^(6)]j^ - [7.06 × 10^(6)]i^

B) Formula for kinetic energy is;

K = ½mv²

Now,total kinetic energy is;

K_total = K1 + K2 + K3

K1 = ½ × 5.03 × 10^(-27) × (6 × 10^(6))²

K1 = 90.54 × 10^(-15) J

K2 = ½ × 8.47 × 10^(-27) × (4 × 10^(6))²

K2 = 67.76 × 10^(-15)

To find K3, let's first find the magnitude of v3 because it's still in vector form.

Thus;

v3 = √[(-6.29 × 10^(6))² + (-7.06 × 10^(6))²]

v3 = 9.46 × 10^(6) m/s

K3 = ½ × 4.8 × 10^(-27) × (9.46 × 10^(6))²

K3 = 214.78 × 10^(-15) J

K_total = (90.54 × 10^(-15)) + (67.76 × 10^(-15)) + (214.78 × 10^(-15))

K_total = 373.08 × 10^(-15) J

Complete Question

The complete question is shown on the first uploaded image

Answer:

The expression for the velocity of the sixth ball is

 [tex]v_2 = \frac{u_1 sin\theta }{sin \phi cos\theta + cos \phi sin\theta}[/tex]

Explanation:

From the question we are told that

     The mass of the 8 ball is  [tex]m_1 =  0.5 \  kg[/tex]

      The initial velocity of the 8 ball is  [tex]u_1  =  3.7 \  m/s[/tex]

      The initial velocity of the 6 ball is  [tex]u_2  =  0  \  m/s[/tex]

         The mass of the 6 ball is  [tex]m_2 =  0.5 \  kg[/tex]

Generally from the law of momentum conservation is  

     [tex]m_1 *u_1 + m_2 * u_2 = m_1 * v_1 +m_2 *v_2[/tex]

Now along the y  axis

      [tex]u_1 =u_y_1 =  0 \  m/ s[/tex]

      [tex]u_2 =u_y_2=  0 \  m/ s[/tex]

      [tex]v_1 =v_y_1=  v_1 sin \theta  \  m/ s[/tex]

      [tex]v_2 =v_y_2=  v_2 sin \phi  \  m/ s[/tex]

So

  [tex]m_1 *0 + m_2 * 0 = m_1 * (v_1 sin \theta) +m_2 *(v_2 sin \phi )[/tex]

=>  [tex]v_1 = \frac{v_2 sin \phi }{ sin \theta}[/tex]

Now along the x  axis

      [tex]u_1 =u_x_1 =  u_1 \  m/ s[/tex]

       [tex]u_2 =u_2_2=   0 \  m/ s[/tex]

        [tex]v_1 =v_x_1=  v_1 cos \theta  \  m/ s[/tex]

        [tex]v_2 =v_x_2=  v_2 cos \phi  \  m/ s[/tex]

So

        [tex]m_1 *u_1 + m_2 * 0 = m_1 *(v_1 cos \theta) +m_2 *(v_2 cos \phi)[/tex]

=>[tex]m_1 *u_1  = m_1 *(v_1 cos \theta) +m_2 *(v_2 cos \phi)[/tex]    

substituting for [tex]v_1[/tex] in the above equation

=>[tex]m_1 *u_1  = m_1 *([ \frac{v_2 sin \phi }{ sin \theta}] cos \theta) +m_2 *(v_2 cos \phi)[/tex]      

=>[tex]m_1 *u_1  = m_1 *([ \frac{v_2 sin \phi }{ sin \theta}] cos \theta) +m_2 *(v_2 cos \phi)[/tex]

 given that  [tex]m_1 = m_2 = m[/tex]

=>[tex]m *u_1  = m *([ \frac{v_2 sin \phi }{ sin \theta}] cos \theta) +m *(v_2 cos \phi)[/tex]

=>[tex]m *u_1  = m [([ \frac{v_2 sin \phi }{ sin \theta}] cos \theta) + (v_2 cos \phi)][/tex]

=>[tex]u_1  = ([ \frac{v_2 sin \phi }{ sin \theta}] cos \theta) + (v_2 cos \phi)[/tex]

=>[tex]u_1  = v_2 sin\phi cot \theta + v_2 cos\phi [/tex]

[tex]v_2 = \frac{u_1  }{sin\phi cot\theta + cos\phi }[/tex]

converting [tex]cot \phi[/tex] back  to  [tex]\frac{cos \theta}{sin\theta }[/tex]

So

    [tex]v_2 = \frac{u_1  }{sin\phi [\frac{cos \theta}{sin\theta }] + cos\phi }[/tex]

multiply through by  [tex]\frac{sin \theta}{sin \theta }[/tex]

   [tex] \frac{sin \theta}{sin \theta } *v_2 = \frac{sin \theta}{sin \theta } * \frac{u_1  }{sin\phi [\frac{cos \theta}{sin\theta }] + cos\phi }[/tex]

=>  [tex]v_2 = \frac{u_1 sin\theta }{sin \phi cos\theta + cos \phi sin\theta}[/tex]

Answer:

Maybe.

Explanation:

Answer:

In the absence of thrust, the lunar lander moves downward toward the surface of the moon. At this point, the only force acting on the lunar lander is gravity, which is directed toward the center of the moon. Because the net force is in the downward direction, the lunar lander moves downward.

Explanation: plato

Answer: In the absence of thrust, the lunar lander moves downward toward the surface of the moon. At this point, the only force acting on the lunar lander is gravity, which is directed toward the center of the moon. Because the net force is in the downward direction, the lunar lander moves downward.

Explanation: edmentum sample answer

Answer:

10 mls2

Explanation:

speed =distance /time

Answer:

leather

Explanation:

plz mark as brainliest......hope it helps

Answer:

a. leather

Explanation:

Hello friend!!!!

a. leather is the correct option because jute, wool and cotton are all natural fibres whereas leather is a synthetic fibre.

Hope this helps

plz mark as brainliest!!!!!!

Answer:

Yes

Explanation:

The variables change in and experiment.

Answer:

If you are carefully enough to control everything, then everything that could change the result of your experiment won't happen.

Explanation:

Answer:

I am confused of your question. Do you want final velocity? To get final velocity, use (initial V)+(Gravity*Time)

Explanation:

Answer:

B. g*t

Explanation:

Answer:

The correct answer is A. A government that wants to increase its GDP would most likely increase the money supply to make it easier to borrow money.

Explanation:

If the government wanted to increase its GDP, the most appropriate way to do so would be to increase the money supply both through issuance and through a reduction in bank reserve requirements, thereby increasing the circulating money in the hands of society.

This, in turn, would make citizens reinvest that money, increasing economic production and, therefore, the national GDP.

Answer: A. Increase the money supply to make it easier to borrow money

Explanation: I just took the test on Ap ex

Answer: a tendency to do nothing or to remain unchanged.

Explanation:

For example, if you roll a ball, it will continue rolling unless friction or something else stops it by force.

Answer:

the property of matter by which it retains its state of rest or its velocity along a straight line so long as it is not acted upon by an external force. an analogous property of a force: electric inertia.

or a tendency to do nothing or to remain unchanged.

Answer:

a) Δf = 0.7 n , e)   f = (15.1 ± 0.7) 10³ Hz

Explanation:

This is an error about the uncertainty or error in the calculated quantities.

Let's work all the magnitudes is the SI system

The frequency of oscillation is

        f = n / 2π L² √( E /ρ)

where n is an integer

Let's calculate the magnitude of the oscillation

       f = n / 2π (0.2335)² √ (210 10⁹/7800)

       f = n /0.34257 √ (26.923 10⁶)

       f = n /0.34257    5.1887 10³

       f = 15.1464 10³ n

a) We are asked for the uncertainty of the frequency (Df)

       Δf = | df / dL | ΔL + df /dE ΔE + df /dρ Δρ

in this case no  error is indicated in Young's modulus and density, so we will consider them exact

       ΔE = Δρ = 0

       Δf = df /dL  ΔL

       df = n / 2π   √E /ρ   | -2 / L³ | ΔL

       df = n / 2π 5.1887 10³ | 2 / 0.2335³) 0.005 10⁻³

       df = n 0.649

Absolute deviations must be given with a single significant figure

        Δf = 0.7 n

b, c) The uncertainty with the width and thickness of the canteliver is associated with the density

In your expression there is no specific dependency so the uncertainty should be zero

The exact equation for the natural nodes is

          f = n / 2π L² √ (E e /ρA)

where A is the area of ​​the cantilever and its thickness,

In this case, they must perform the derivatives, calculate and approximate a significant figure

        Δf = | df / dL | ΔL + df /de  Δe + df /dA  ΔA

        Δf = 0.7 n + n 2π L² √(E/ρ A) | ½  1/√e | Δe

               + n / 2π L² √(Ee /ρ) | 3/2 1√A23  |

the area is

        A = b h

        A = 24.9  3.3  10⁻⁶

        A = 82.17 10⁻⁶ m²

        DA = dA /db ΔB + dA /dh Δh

        dA = h Δb + b Δh

        dA = 3.3 10⁻³ 0.005 10⁻³ + 24.9 10⁻³ 0.005 10⁻³

        dA = (3.3 + 24.9) 0.005 10⁻⁶

        dA = 1.4 10⁻⁷ m²

let's calculate each term

         A ’= n / 2π L² √a (E/ρ A) | ½ 1 /√ e | Δe

         A ’= n/ 2π L² √ (E /ρ)      | ½ 1 / (√e/√ A) |Δe

        A ’= 15.1464 10³ n ½ 1 / [√ (24.9 10⁻³)/ √ (81.17 10⁻⁶)] 0.005 10⁻³

        A '= 0.0266  n

        A ’= 2.66 10⁻² n

       A ’’ = n / 2π L² √ (E e /ρ) | 3/2  1 /√A³ |

       A ’’ = n / 2π L² √(E /ρ) √ e | 3/2  1 /√ A³ | ΔA

       A ’’ = n 15.1464 10³ 3/2 √ (24.9 10⁻³) /√ (82.17 10⁻⁶) 3 1.4 10⁻⁷

       A ’’ = n 15.1464 1.5 1.5779 / 744.85 1.4 10⁴

       A ’’ = 6,738 10²

we write the equation of uncertainty

     Δf = n (0.649 + 2.66 10⁻² + 6.738 10²)

The uncertainty due to thickness is

    Δf = 3 10⁻² n

The uncertainty regarding the area, note that this magnitude should be measured with much greater precision, specifically the height since the errors of the width are very small

     Δf = 7 10² n

 d)    Δf = 7 10² n

e) the natural frequency n = 1

       f = (15.1 ± 0.7) 10³ Hz

Answer:

5694000 min

Explanation:

Let's suppose the average American watches 4 hours of TV every day. First, we will calculate how many minutes they watch per day. We will use the conversion factor 1 h = 60 min.

(4 h/day) × (60 min/1 h) = 240 min/day

They watch 240 minutes of TV per day. Now, let's calculate how many minutes they watch per year. We will use the conversion factor 1 year = 365 day.

240 min/day × (365 day/year) = 87600 min/year

They watch 87600 min/year. Finally, let's calculate how many minutes they spend watching TV in 65 years.

87600 min/year × 65 year = 5694000 min

Answer:

Community A

Explanation:

Community A most likely use hydroelectric power for generating most of their electricity.

Hydroelectric power utilizes the energy from water to produce electricity.

A water body is dammed, then channeled for driving a turbine which in turn generates electricity by induction.

Answer:

a) The work done by gravity on the coin as it falls is 17.653 joules.

b) The kinetic energy of the coin at a speed of 60 meters per second is 10.8 joules.

c) The work lost due to air resistance is 6.853 joules.

d) The average force exerted on the coin due to air resistance as it fell is 0.023 newtons.

Explanation:

a) We must remind that situation with Earth-coin system must be represented by Principle of Energy Conservation and Work Energy Theorem. According to this latter, work done by gravity equals to the change in gravitational potential energy:

[tex]\Delta U_{g} = m\cdot g \cdot \Delta z[/tex] (Eq. 1)

Where:

[tex]\Delta U_{g}[/tex] - Change in gravitational potential energy, measured in joules.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational accelerations, measured in meters per square second.

[tex]\Delta z[/tex] - Height of the skyscraper, measured in meters.

If we know that [tex]m = 0.006\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta z = 300\,m[/tex], the work done gravity on the coin is:

[tex]\Delta U_{g} = (0.006\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (300\,m)[/tex]

[tex]\Delta U_{g} = 17.653\,J[/tex]

The work done by gravity on the coin as it falls is 17.653 joules.

b) By definition of translation kinetic energy, we get the following model:

[tex]K = \frac{1}{2}\cdot m\cdot v^{2}[/tex]

Where:

[tex]K[/tex] - Kinetic energy of the coin right before hitting the street, measured in joules.

[tex]v[/tex] - Speed of the coin, measured in meters per second.

If we get that [tex]m = 0.006\,kg[/tex] and [tex]v = 60\,\frac{m}{s}[/tex], the kinetic energy at this speed is:

[tex]K = \frac{1}{2}\cdot (0.006\,kg)\cdot \left(60\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 10.8\,J[/tex]

The kinetic energy of the coin at a speed of 60 meters per second is 10.8 joules.

c) The work lost due to air resistance is obtained derived from Principle of Energy Conservation and Work-Energy Theorem:

[tex]W_{lost} = \Delta U_{g}-K[/tex] (Eq. 2)

Where [tex]W_{lost}[/tex] is the work lost due to air resistance, measured in joules.

If we know that [tex]\Delta U_{g} = 17.653\,J[/tex] and [tex]K = 10.8\,J[/tex], the work lost due to air resistance is:

[tex]W_{lost} = 17.653\,J-10.8\,J[/tex]

[tex]W_{lost} = 6.853\,J[/tex]

The work lost due to air resistance is 6.853 joules.

d) The average force exerted on the coin due to air resistance can be determined by applying definition of work, as air resistance force was antiparallel to the displacement of the coin. That is:

[tex]W_{lost} = F\cdot \Delta z[/tex]

[tex]F = \frac{W_{lost}}{\Delta z}[/tex] (Eq. 3)

Where [tex]F[/tex] is the average force exerted on the coin due to air resistance, measured in newtons.

If we know that [tex]W_{lost} = 6.853\,J[/tex] and [tex]\Delta z = 300\,m[/tex], then the average force exerted on the coin is:

[tex]F = \frac{6.853\,J}{300\,m}[/tex]

[tex]F = 0.023\,N[/tex]

The average force exerted on the coin due to air resistance as it fell is 0.023 newtons.

Answer:

 a = - 9.8 j ^   m/s²

Explanation:

This is a projectile launch problem, they give us the initial velocity in the two components

         v₀ₓ = 17.1 m / s

         [tex]v_{oy}[/tex] = 14.7 m / s

They indicate that the only acceleration that exists is the acceleration of gravity, which acts in the direction towards the center of the Earth, in general in a coordinate system it coincides with the direction of the y axis.

           a = - g j ^

           a = - 9.8 j ^  m /s²

Answer:

Function

Explanation:

This question defines a function. It is any consequence that is made up of positive structures which has a way of affecting the society in a positive way. And it also has a way of impacting structural continuity in the society. The functionalism idea has the postulation that all cultural or social phenomena is of positive function and cannot be ignored

Answer:

function

Explanation:

answer EDGE2020

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 500 N

distance = 4 m

We have

workdone = 500 × 4

We have the final answer as

Hope this helps you