The question was incomplete. Below you will find the missing parts of the question.
The company actually loses money on their first few products as it costs them more to make them, but once they hit ? they break even again. The worst case scenerio is that they produce ? items, as they will have a profit of ? dollars. The first root tells us that the profit will be 0 when ? products are sold.
Answer: The company actually loses money on their first few products as it costs them more to make them, but once they hit 150 they break even again. The worst case scenerio is that they produce 75 items, as they will have a profit of 10000 dollars. The first root tells us that the profit will be 0 when 0 products are sold.
Because the roots are x = 0 and 150, the vertex is (75, 10000).
So, the function is y = [tex]-\frac{10000}{5625}(x-75)^{2} +10000[/tex]
When, y = 0,
[tex]0=-\frac{10000}{5625} (x-75)^{2} +10000[/tex]
⇒ [tex]\frac{10000}{5625} (x-75)^{2}=10000[/tex]
⇒ [tex](x-75)^{2} = 10000(\frac{5625}{10000})[/tex]
⇒ [tex](x-75)^{2} = 5625[/tex]
⇒ [tex]x-75=75[/tex]
⇒ x = 150
When y=0, then x =150, their income was in balance.
When x = 75, then y=10000, they will have a profit of 10000 dollars.
The first root tells us that the profit will be 0 when 0 products are sold.
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X-y=5 and x^2y=5x+6
By applying algebraic handling on the two equations, we find the following three solution pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
How to solve a system of equations
In this question we have a system formed by a linear equation and a non-linear equation, both with no trascendent elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three solution pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
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Which expression can be used to an identity with [(sin)(sec)]^2 + 1?
Answer:
A
Step-by-step explanation:
sin*sec=tan
tan^2+1=sec^2 by an identity
Which of the following options is a 3rd degree polynomial with exactly 1 real
root?
A. F(x)=x²-9x² +27x-27
B. F(x)=x+3x² +9x+27
C. F(x)= x +9x² +27x+27
D. F(x)=x+3x² -9x-27
Give the “best” big-oh notation to describe the complexity of the algorithm that prints all bit strings of length n.
It is correct to state that a bit can be in one of 2 states, either 1 or 0.
What is a bit?A bit is is a single binary digit. A bit can either be "1" or "0".
What is the explanation to the above answer?We stated that It is correct to indicate that a bit can be in one of 2 states, either 1 or 0. This indicates that 2ⁿ strings must be created in total. The string must then be processed twice.
The first time, for generation andThe second for reading.Hence, Our time is now O(2ⁿ⁺¹) = O(2ⁿ)
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urgent help needed algebra 2
The missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.
What is unit conversion?It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
We have:
[tex]\rm F = \dfrac{9}{5}C + 32[/tex]
Make subject C and solve:
[tex]\rm \dfrac{5}{9}(F-32) = \dfrac{5}{9}\times\dfrac{9}{5}C[/tex]
[tex]\rm \dfrac{5}{9}(F-32) = C[/tex]
Plug F = 41
[tex]\rm \dfrac{5}{9}(41-32) = C[/tex]
[tex]\rm \dfrac{5}{9}(9) = C[/tex]
41 degrees F = 5 degrees C
Thus, the missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.
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e total cost, in dollars, for a company to produce r headsets per day is modeled by the function C,
where C(r) = (-5)2 + 35 for 5 < r ≤ 25. The company sells each headset for $20. On one day, the
company produced 15 headsets. According to the model, what will be the profit on the sale of these
headsets? (Profit equals total sales minus total cost.)
O $215
O $225
O $240
O $300
‐10+35=25 and 25 × 20=300
Given: ∠E and ∠F are supplementary and ∠F and ∠G are supplementary.
Prove: ∠E≅∠G
1) ∠E and ∠F are supplementary and ∠F and ∠G are supplementary (given)
2) m∠E+m∠F=180 degrees, m∠F+m∠G=180 degrees (supplementary angles have measures that add to 180 degrees)
3) m∠E=m∠G (subtraction property of equality)
4) ∠E≅∠G (angles with equal measure are congruent)
When you raise (almost) anything to the power zero, you get 1.
Answer:
z^0= 1
(2v+2)^0 = 1
3^0 = 1
0^0= 0
Step-by-step explanation:
When you raise (almost) anything to the power zero, you get 1 and when you raise 0 to any number except 0 is 0
1. Which of the following numbers is
rational?
A. 0.78
B. 0.303003000
C. √6
D. 0.3841697
Answer:
A. 0.78
Step-by-step explanation:
A rational number is a number that you can express as [tex]\frac{x}{y}[/tex] where [tex]y\neq 0[/tex].
How many yards are in 1 mile 60 feet?
Answer:
1780
Step-by-step explanation:
multiply the length value by 1760
and then divide the length value by 3
There are 230 calories in a 48 gram packet of M&M's. How many calories are in a 33.6 gram bag?
Answer:
161 calories
Step-by-step explanation:
1) Divide 230 by 48
4.791666666666667
2) multiply 4.791666666666667 by 33.6
161
Done! Your answer is 161 calories in a 33.6 gram bag. Or just 161.
Hope this helps!
Help will give br brainlesssssss
Answer:
i think the answer is the second one D and A
TIME REMAINING
09:44
On a coordinate plane, a solid straight line has a positive slope and goes through (negative 3, negative 5) and (0, negative 4). Everything to the right of the line is shaded.
Which linear inequality is represented by the graph?
y ≥ One-thirdx – 4
y ≤ One-thirdx – 4
y ≤ One-thirdx + 4
y ≥ One-thirdx + 4
Since everything to the right of the line is shaded, the linear inequality which represents the graph is equal to: A. y ≥ 1/3x - 4.
How to determine the linear inequality?In order to determine the linear inequality which represents the graph, we would find the slope of the given points.
Mathematically, the slope of a straight line can be calculated by using this formula;
[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]
Substituting the given points into the formula, we have;
[tex]Slope = \frac{-4\;-\;(-5)}{0\;-\;(-3)}\\\\Slope = \frac{1}{3}[/tex]
Slope = 1/3.
From the standard equation, we have:
y - y₁ = m(x - x₁)
y - (-5) = 1/3(x - (-3))
y + 5 = 1/3x + 1
y = 1/3x + 1 - 5
y = 1/3x - 4
y ≥ 1/3x - 4.
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6. Using the discriminant, determine the value of k that will give 1 solution (i.e. discriminant equals zero) y = kx²-4x + 4
Answer:
k = 1
Step-by-step explanation:
Discriminant
[tex]b^2-4ac\quad\textsf{when }\:ax^2+bx+c=0[/tex]
[tex]\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}[/tex]
[tex]\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}[/tex]
[tex]\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}[/tex]
As we need to determine the value of k that will give one solution, set the discriminant to zero.
Given equation:
[tex]y=kx^2-4x+4[/tex]
Therefore:
a = kb = -4c = 4Substitute these values into the discriminant and solve for k:
[tex]\begin{aligned}b^2-4ac & = 0\\\implies (-4)^2-4(k)(4) & = 0\\16-16k & = 0\\16k & = 16\\\implies k & = 1\end{aligned}[/tex]
If the odds against an event are 3:5, then the probability that the event will fail to occur is
Answer:
3/8
Step-by-step explanation:
probability = wanted outcomes / total outcomes
odds = wanted outcomes / unwanted outcomes
Odds of 3:5 losing means 3 losing outcomes and 5 winning outcomes.
The total outcomes is 8
The probability of losing which is the probability that the event will fail to occur is 3/8.
What is the explicit formula for this sequence?
60, 30, 15, 7.5, ...
A. an = 60.
(9)
OB. an= = (1.60
OC. an = 60.
• (+)-
OD. an=3.2(n-1)
60(n-1)
(n-1)
i beilive this is unknown
Help pls ???????????
The second derivative of the first function is s"(x) = = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³.
The second derivative of the second function is; k''(t) = (36t² - 6)e^(-3t²)
How to find the second derivative?1) We are given the function;
s(x) = 4/(1 + 2e^(-0.2x)
First derivative is;
ds/dx = [8e^(x/5)]/5(e^(x/5) + 2)²
Second Derivative is;
d²s/dx² = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³
At x = 0;
d²s/dx² = -[8e^(0/5) - 2]e^(0/5)/25(e^(0/5) + 2)³
d²s/dx² = 8/675
B) We are given the function;
k(t) = e^(-3t²)
The first derivative is;
dk/dt = -6te^(-3t²)
The second derivative is;
k''(t) = (36t² - 6)e^(-3t²)
At t = 1, we have;
k''(t) = (36(1)² - 6)e^(-3(1²))
k"(t) = 1.494
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Solve: 4 + 3x = 2(3x-7) +9
A. There are infinitely many solutions
B. x = 3
C. x = -3
D. x = 2/3
Answer:
B. x = 3
Step-by-step explanation:
Simplifying
4 + 3x = 2(3x + -7) + 9
Reorder the terms:
4 + 3x = 2(-7 + 3x) + 9
4 + 3x = (-7 * 2 + 3x * 2) + 9
4 + 3x = (-14 + 6x) + 9
Reorder the terms:
4 + 3x = -14 + 9 + 6x
Combine like terms: -14 + 9 = -5
4 + 3x = -5 + 6x
Solving
4 + 3x = -5 + 6x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-6x' to each side of the equation.
4 + 3x + -6x = -5 + 6x + -6x
Combine like terms: 3x + -6x = -3x
4 + -3x = -5 + 6x + -6x
Combine like terms: 6x + -6x = 0
4 + -3x = -5 + 0
4 + -3x = -5
Add '-4' to each side of the equation.
4 + -4 + -3x = -5 + -4
Combine like terms: 4 + -4 = 0
0 + -3x = -5 + -4
-3x = -5 + -4
Combine like terms: -5 + -4 = -9
-3x = -9
Divide each side by '-3'.
x = 3
Simplifying
x = 3
Name the corresponding part if polygon WXYZ ≅ polygon PQRS.
Question: QP =
The corresponding part of PQ is WX
How to determine the corresponding parts?The congruent statement is given as:
polygon WXYZ ≅ polygon PQRS.
This means that the corresponding points are:
W and P, X and Q, Y and R, Z and S
When two points Q and P are joined together, we have:
polygon WX ≅ polygon PQ
Hence, the corresponding part of PQ is WX
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Solve by completing the square:
x2 + 3x – 9 = 0
Answer:
[tex]x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]
Step-by-step explanation:
Given equation:
[tex]x^2+3x-9=0[/tex]
Completing the square
Move the constant to the right side by adding 9 to both sides:
[tex]\implies x^2+3x=9[/tex]
Add the square of half the coefficient of x to both sides:
[tex]\implies x^2+3x+\left(\dfrac{3}{2}\right)^2=9+\left(\dfrac{3}{2}\right)^2[/tex]
[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{45}{4}[/tex]
Factor the trinomial on the left side:
[tex]\implies \left(x+\dfrac{3}{2}\right)^2=\dfrac{45}{4}[/tex]
Square root both sides:
[tex]\implies x+\dfrac{3}{2}=\pm\sqrt{\dfrac{45}{4}}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{45}}{\sqrt{4}}}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9 \cdot 5}}{2}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9} \sqrt{5}}{2}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{3\sqrt{5}}{2}[/tex]
Subtract 3/2 from both sides:
[tex]\implies x=\pm\dfrac{3\sqrt{5}}{2}-\dfrac{3}{2}[/tex]
[tex]\implies x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]
Juliette buys a rosemary plant that is 12 cm and grows 1 cm per week (w). Kimberly starts one from seed but the package says it will grow 2 cm per week. How many weeks will it take for Kimberly’s plant to equal the height of Juliette’s?
The weather report says the temperature is 20°c and will drop 5°c per hour for the next 6 hours. Daryl plans to be gone at least 6 hours, and he has a plant outside. If he wants the plant to remain in temperatures above -10° should Daryl move the plant to a warmer location before leaving
The inequality equation will be -5x + 20 < -10.
What is inequality?Inequality is defined as an equation that does not contain an equal sign.
The weather report says the temperature is 20°c and will drop 5°c per hour for the next 6 hours.
Daryl plans to be gone at least 6 hours, and he has a plant outside.
If he wants the plant to remain in temperatures above -10° should Daryl move the plant to a warmer location before leaving will be
The inequality equation will be
-5x + 20 < -10
where x is the number of hours.
Then we have
-10 < -5x + 20
5x > 30
x > 6 hours
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What are the solutions to the following system?
Which expression is equivalent to...
Please answer all three of the questions <3
Answer:
1) D because the answer to 8.42*10^3=8420
and 8420 lies between 8400 and 8500
2) C because when you take the absolute value of -2.3 and -3.2, they become positive numbers => 2.3 < 3.2
3)D because 6 < 6.3 < 6.6
Hope it helps!
Find the equation of the line that is perpendicular to y=-2x-9 and contains the points (8,-4)
The slope of the given line is -2, and since perpendicular lines have negative reciprocal slopes, the slope of the line we want to find is 1/2.
Substituting into point-slope form,
[tex]y+4=\frac{1}{2}(x-8)\\\\y+4=\frac{1}{2}x-4\\\\\boxed{y=\frac{1}{2}x-8}[/tex]
Answer:
Equation of line perpendicular to y= -2x-9 is y=x/2-8 .
Step-by-step explanation:
The slope of a line gives the measure of its steepness and direction. The slope of a curve at a point is equal to the slope of the straight line that is tangent to the curve at that point.
The general equation of a line is y = mx + c, where m is the slope of the line and c is the y-intercept. It is the most common form of the equation of a straight line that is used in geometry.
The product of slopes of two perpendicular lines gives (-1).
m1m2=(-1)
(-2)m2=(-1)
m2=1/2
y=m2x+c
Point (8,-4) satisfies the given equation :
(-4)=1/2 x 8 + c
c = (-8)
Line perpendicular to y= -2x-9 will be -
y=x/2-8
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Please help meeeeeeeeee
Answer:
a, b, d
Step-by-step explanation:
its one of those
Answer:
A, the first one
Which of the following is the midpoint between (6, 3) and (-2, -5)
Answer:
( 2, -1)
Step-by-step explanation:
(X1 + X2)/2 , (Y1 + Y2)/2
(6-2)/2 , (3-5)/2
4/2 , -2/2
2 , -1
Answer:
(2, -1)
Step-by-step explanation:
(x1, y1)=(6, 3)
(x2, y2)=(-2, -5)
[(6+(-2))/2, (3+(-5))/2]
=(4/2, -2/2)
=(2, -1)
please answer me please
Step-by-step explanation:
please mark me as brainlest
Please answer! I will give you the brainliest :)
Answer:
K
Step-by-step explanation:
(1*500 * 5) + (10 * 3*500)
