Given the reaction: 2Na(s) + 2H20(1) 2Na+(aq) + 2OH(aq) + H2(g)
This reaction goes to completion because one of the products formed is
1.
an insoluble base
2.
a soluble base
3
a precipitate
4.
a gas

Answer:

The correct answer is 1.5 balloons.

Explanation:

Based on the given question, the radius of the spherical balloons is 170 cm. Therefore, the volume of each balloon will be,  

= 4/3 × π × (170)³ cm³

= 20.5176 × 10⁶ cm³  

= 20.5176 m³

The density of air at 100 degree C s 0.946 Kg m⁻³

The mass of air in each balloon can be calculated by using the formula,  

Mass = density × volume

Mass = 0.946 Kg m⁻³ × 20.5176 m³

Mass = 19.410 Kg

The heat energy, that is, required to bring the air from 25 degree C to 100 degree C will be,  

= 19.410 × 10³ g × (100 -25) degree C × 1.009 J/g degree C

= 14.68 × 10⁵ J

The concentration of butane given is 1.00 Kg or 1000 g

The molecular weight of butane is 58.12 g per mole

The moles or n can be calculated by using the formula,  

n = mass / mol.wt

n = 1000 g/58.12 g/mol = 17.20 mol

The formation of enthalpy of butane at 25 degree C is 125.7 × 10³ J/mol. The evolution of heat energy that take place at the time of burning 17.20 moles of butane is,  

= 125.7 × 10³ J/mol × 17.20 mol

= 2.16 × 10⁶ J

The number of balloons that can be inflated with hot air is,  

= 2.16 × 10⁶ J / 14.68 × 10⁵ J per each balloon

= 1.5 balloons

Hence, maximum of 1.5 balloons can be inflated.  

Answer:

2nd option

Explanation:

Molarity is the number of moles of the solute (NaCl) in 1 litre of the solution (NaCl solution).

Given: concentration= 232g/ L

what we are trying to achieve is __mol/ L.

So in 1 litre, we have 232g of NaCl.

To convert mass to mole, we divide it by the Mr.

Given that the Mr is 58g/mol,

number of moles

= 232 ÷58

= 4

Thus, 1 litre has 4 moles of NaCl.

Therefore, the molarity is 4.0 mol/L.

Answer:

The metal will feel hot.

Explanation:

Metals are known for their high thermal conductivity. If one part of the metal feels hot, the other will as well.

_______________________________________________________

This piece of metal has been exposed to the sun, and will feel hot after a certain amount of time. By the statement above, the unexposed part will feel hot as well.

Hope that helps!

Answer:

6.941 grams

Explanation:

The molecular formula for Lithium is Li. The Si base unit for amount of substance is mole. 1 mole is equal to 1 moles Lithium, or 6.941 grams

Answer:

9.647989999999998

Explanation:

Answer:

C₇H₁₁N

Explanation:

To find the chemical formula, first, let's evaluate the given conditions.

1. Is a primary amine:

This means that the amine is connected to a carbon, like NH₂-R

2. The degree of unsaturation of the five-membered carbon ring is equal to three:

One of the degrees of unsaturation is for the five-membered carbon ring, the other two are for pi-bonds. This means that the five-membered carbon ring has 2 pi-bonds inside.

3. There are seven carbon atoms:

Five of these seven carbons are for the carbon ring and the other two are bonded to the primary amine.

From all of the above, we have that the chemical formula is:

C₅H₅-C₂H₄-NH₂ = C₇H₁₁N  

I hope it helps you!

Answer:

The correct answer is

C. 6 Protons

Explanation:

Carbon is a nonmetallic element that is available in  both organic and inorganic compounds.

    Carbon belongs to group 14 elements in the periodic table,carbon is a chemical element with the symbol C and atomic number 6, it can  form long chains with its own atoms, a feature called catenation.

Two allotropes of carbon available are diamonds and graphites, which have different crystalline structures

The physical properties of carbon vary widely with the allotropic form.

examples are.

Answer:

CaCN₂

Explanation:

A compound of calcium, carbon and nitrogen CaₐCₓNₙ in oxygen will burning producing:

CaₐCₓNₙ + O₂ → aCaO + xCO₂ + nNO₂

Moles of the oxides CaO, CO₂, NO₂ are:

CaO: 3.106g ₓ (1 mole / 56.08g) = 0.0554 moles of CaO = moles of Ca

CO₂: 2.439g ₓ (1mole / 44g) = 0.0554 moles CO₂ = moles C

NO₂: 5.097g ₓ (1mole / 46g) = 0.111 moles NO₂ = moles N

Empirical formula is the chemical formula that represents the simplest ratio of elements in a compound.

Having as basis 0.0554 moles (The lower number of moles):

0.0554 moles Ca / 0.0554 = 1 Ca

0.0554 moles C / 0.0554 = 1 C

0.111 moles N / 0.0554 = 2N

Thus, the compound CaₐCₓNₙ  has as empirical formula:

Ca₁C₁N₂ = CaCN₂

Answer:

a) First-order.

b) 0.013 min⁻¹

c) 53.3 min.

d) 0.0142M

Explanation:

Hello,

In this case, on the attached document, we can notice the corresponding plot for each possible order of reaction. Thus, we should remember that in zeroth-order we plot the concentration of the reactant (SO2Cl2 ) versus the time, in first-order the natural logarithm of the concentration of the reactant (SO2Cl2 ) versus the time and in second-order reactions the inverse of the concentration of the reactant (SO2Cl2 ) versus the time.

a) In such a way, we realize the best fit is exhibited by the first-order model which shows a straight line (R=1) which has a slope of -0.0013 and an intercept of -2.3025 (natural logarithm of 0.1 which corresponds to the initial concentration). Therefore, the reaction has a first-order kinetics.

b) Since the slope is -0.0013 (take two random values), the rate constant is 0.013 min⁻¹:

[tex]m=\frac{ln(0.0768)-ln(0.0876)}{200min-100min} =-0.0013min^{-1}[/tex]

c) Half life for first-order kinetics is computed by:

[tex]t_{1/2}=\frac{ln(2)}{k}=\frac{ln(2)}{0.013min^{-1}} =53.3min[/tex]

d) Here, we compute the concentration via the integrated rate law once 1500 minutes have passed:

[tex]C=C_0exp(-kt)=0.1Mexp(-0.013min^{-1}*1500min)\\\\C=0.0142M[/tex]

Best regards.

Answer:

D.

Explanation:

Water is polar, for one thing. Polar mixes with polar, nonpolar mixes wih nonpolar. This leaves D.

Answer:

[tex]K=3.2[/tex]

Explanation:

Hello,

In this case, for the given equilibrium, we write the law of mass action:

[tex]K=\frac{[PCl_3][Cl_2]}{[PCl_5]}[/tex]

Next, in terms of the change [tex]x[/tex] due to the reaction extent (ICE procedure):

[tex]K=\frac{x*x}{1M-x}[/tex]

Clearly, the initial concentration phosphorous pentachloride is 1 M (one mole per litre), therefore, since the equilibrium concentration is 0.2 M (same volume) we can compute [tex]x[/tex]:

[tex]x=1M-0.2M=0.8M[/tex]

Thus, we compute the equilibrium constant:

[tex]K=\frac{0.8*0.8}{0.2} \\\\K=3.2[/tex]

Regards.

Explanation:

First off, the + 1 charge means that the metal has lost an electron.

To identify the metal, we have to know the total number of electrons in the 3d sub shell.

Total number of electrons = 1 + 10 = 11

This metal belongs to the fourth period in the periodic table (that's where transition metals begin to occur).

This means that the 11th metal in this period is the metal. That happends to be Copper.

Answer:

Hey mate,

Here is your answer. Hope it helps you

Explanation:

Primary alcohols are those alcohols where the carbon atom of the hydroxyl group(OH) is attached to only one single alkyl group. Some of the examples of these primary alcohols include Methanol (, propanol, ethanol, etc. The complexity of this alkyl chain is unrelated to the classification of any alcohol considered as primary. The existence of only one linkage among –OH group and an alkyl group and the thing that qualifies any alcohol as a primary.

Answer:

Calcium

Explanation:

Since the element reacts with oxygen to form an oxide with the formula MO, the charge on the element is +2.

Also, since the oxide MO when dissolved in water is basic, the metal is an alkali earth metal.

From the above conditions;

The metal is not arsenic because arsenic is a metalloid has the  following oxides As₂O₃ and As₃O₅ and are respectively amphoteric and acidic in nature

The metal is not germanium because is a metalloid and even though germanium oxide has the formula GeO₂, it is amphoteric.

The metal is not chlorine because chlorine is a non-metal

The metal is definitely calcium because calcium oxide has the formula CaO and calcium is an alkaline earth metal.

The metal is not selenium because selenium is anon-meal and its oxide has the formula Se0₂ and is acidic

Answer:

The +3 oxidation state is characteristic of the actinides.

All actinides are radioactive.

Cerium (Ce) rnakes 100th in abundance (by mass %).

The actinides are silvery and chemically reactive.

In the periodic table,the The +3 oxidation state is characteristic of the actinides. All actinides are radioactive.The actinides are silvery and chemically reactive.

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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Answer:

See explanation below

Explanation:

You are missing certain data. I found one, in the attached picture. All you have to do is replace your data in this procedure to get an accurate answer.

According to the picture attached, we have 2.4 g of HBr and 1.9 g of NaOH. This mix produces 0.411 g of water. To get the %yield of water, we first need to see how many theorical grams of water are formed. With this we can calculate the %yield.

The overall reaction is:

HBr + NaOH --------> NaBr + H₂O

We have a mole ratio of 1:1 so, let's see which is the limiting reactant between the acid and the base, using the reported molar mass for each (MM HBr = 80.9119 g/mol; MM NaOH = 39.997 g/mol)

moles HBr = 2.4 / 80.9119 = 0.02966 moles

moles NaOH = 1.9 / 39.997 = 0.0475 moles

So, we can clearly see that the moles of NaOH are in excess, so the HBr is the limiting reactant.

As we have a mole ratio of 1:1 with each compound here, and that the HBr is the limiting reactant we can say that:

moles HBr = moles H₂O = 0.02966 moles of water

Now, using the molar mass of water, let's calculate the theorical yield of water: (MM water = 18.01528 g/mol

m H₂O = 0.02966 * 18.01528 = 0.534 g

We have the theorical yield, let's calculate the % yield:

% = 0.411 / 0.534 * 100

% = 76.92%

Answer:

- The precipitate that forms from the reaction of Ammonium Sulfide and Copper (II) Nitrate is the insoluble Copper (II) Sulfide (CuS).

- Overall ionic equation

2NH₄⁺ + S²⁻ + Cu²⁺ + 2NO₃⁻ → 2NH₄⁺ + 2NO₃⁻ + CuS (s)

- Net Ionic equation

S²⁻ + Cu²⁺ → CuS (s)

Or better written as

Cu²⁺ + S²⁻ → CuS (s)

Spectator ions include 2NH₄⁺ and 2NO₃⁻.

Explanation:

Ammonium Sulfide - (NH₄)₂S

Copper (II) Nitrate - Cu(NO₃)₂

The overall equation for this reaction is a double displacement reaction and the balance form is represented by

(NH₄)₂S (aq) + Cu(NO₃)₂ (aq) → 2NH₄NO₃ (aq) + CuS (s)

Copper (II) Sulfide (CuS) is the insoluble precipitate formed from this reaction.

Note that the compounds in aqueous form are the ones that can allow the existence in ionic form, the insoluble solid compound stays in that form without ionizing, hence, the overall ionic equation is

2NH₄⁺ + S²⁻ + Cu²⁺ + 2NO₃⁻ → 2NH₄⁺ + 2NO₃⁻ + CuS (s)

Then, the ions that occur on both sides of the overall ionic equation, are called spectator ions and they include 2NH₄⁺ and 2NO₃⁻.

These spectator ions can then cancel out, leaving us with the net ionic equation

S²⁻ + Cu²⁺ → CuS (s)

Hope this Helps!!!

Answer:

1. Moles of oxalic acid in 100 g sample = 0.0055moles

2. Percentage oxalic acid in 100g sample = 0.5%

Explanation:

Check attachment below for explanation and correct chart arrangement

The correct answer is B. A homogeneous mixture has the same properties for every part of the mixture, so the quality of the material is consistent.

Explanation:

In a homogenous mixture, all the components are equally integrated; this means the final result in the case of a material is a material that looks uniform and also has the same properties in every part of section. This homogeneity and consistency are especially important if you are testing the properties of the material or using it for a specific application because if you use a homogenous mixture the quality and properties will be consistent and thus you can obtain consistent results.

Answer:

Explanation:

Consider the given reaction,

A+B +C

[tex]rate=k[A]^m[B]^m[/tex]

Reaction is first order with respect to reactant B.

The pseudo order rate is

[tex]rate=k_1 [B]^m,\\\\where k_1 =k[A]^m[/tex]

Pseudo order reaction is the reaction in which the reactant concentration remains constant; its concentration is very high so it does not involve in the rate of the reaction. Here, the concentration of  A is sufficiently high so this reaction becomes the pseudo first order reaction.

The reaction is first order with respect to [B] with rate constant k1 .

Using the given table, concentration of  B is decreasing the rate also decreasing

Therefore, order of the reaction with respect to A  is 1.

The order of the reaction in reactant A is 1, means the value of m for given rate should be 1.

Pseudo order reactions are those reactions in which two reactants are present but the concentration of one of the reactant is present in excess quantity and it seems like first order reaction.

Given chemical reaction is: A + B +C

According to the question, given reaction is first order with respect to the reactant B and rate law will be represented as:

Rate = k[A]m[B]m

Also given that reactant A is present in high concentration in the reaction, so the rate of pseudo order reaction is:

Rate = k1[B]n, where

k1 = k[A]m

According to the given table with respect to concentration of reactant B and rate k1, it is clear that rate of the reaction decreases as the concentration of reactant B decreses. So, to get the required result order of the reaction or value of m with respect to the reactant A should be 1.

Hence option (B) is correct i.e. 1.

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Answer:

210. g

Explanation:

SiO2 molar mass=60.09 g/mol

3.50 mol * 60.09 g/mol = 210. g

Answer:

THE SPECIFIC HEAT CAPACITY OF THE ALUMINIUM CAN IS 0.03747 J/g K

Explanation:

Heat liberated (Q) = MCΔT

Heat = 106.8 J

M = mass = 10 g

ΔT = 12°C= 12 + 273 K = 285 K

C = specific heat capacity = unknown

At a rise in 12 °C temperature, the aluminium can possesses a specific heat capacity of =

C = Q / MΔT

C = 106.8 J / 10 g * 285 K

C = 106.8 J / 2850 g K

C = 0.03747 J/g K

The specific heat capacity of the aluminum can weighing 10 g and absorbs 106.8 J of heat after been warmed to 12°C is 0.03747 J/ g K

Answer:

The specific heat of the aluminium can is 0.89 J/g°C

Explanation:

Step 1: Data given

Mass of the aluminium can = 10.0 grams

The amount of energy absorbed = 106.8 J

The temperature rises 12.0 °C

Step 2: Calculate the specific heat of the aluminium can

Q = m*c* ΔT

⇒with Q = the heat absorbed = 106.8 J

⇒with m = the mass of the aluminium can = 10.0 grams

⇒with c = the specific heat of the aluminium can = TO BE DETERMINED

⇒with ΔT = the rise of the temperature = 1.0°C

106.8 J = 10.0 grams * C * 12.0 °C

C = 106.8 J / (10.0 grams * 12.0 °C)

C = 0.89 J/g°C

The specific heat of the aluminium can is 0.89 J/g°C

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

[tex]moles=\frac{0.0016 grams*1 mole}{78 grams}[/tex]

moles=2.05*10⁻⁵

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

[tex]mass of CaF_{2}=\frac{1000 mL*1g}{1mL}[/tex]

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

[tex]moles=\frac{1000 grams*1 mole}{78 grams}[/tex]

moles=12.82

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Answer:

chemical cells that produce an electrical current

Explanation:

lead acid battery is a type of chemical cell, that discharges to produce electrical current.

lead acid battery uses  lead peroxide for the conversion of the chemical energy into electrical power when it is discharging. It is also rechargeable, that is, it can convert electrical energy back to chemical energy during charging.

Thus, a discharging lead acid battery is best described as a chemical cells that produce an electrical current

Answer:

The correct option is;

2.) Chemical cells that produce an electric current

Explanation:

A discharging lead-acid battery is an electrochemical cell that produces electrical energy through the chemical reaction taking place at the battery electrodes which have lead as the anode and lead oxide as the cathode which result in the flow of an electric current, thereby converting chemical energy of the lead, lead oxide and aqueous sulfuric acid system into electrical energy, therefore, it is a chemical cell that produces an electric current.

The hydrometer is an instrument used to determine the density of liquids, and looks like a large glass float filled at the bottom with grains of lead or mercury.

Because the mass of the hydrometer is known and thus the mass of the displaced liquid, the density can be determined using the volume.

There is a scale on the handle, the density can be read here. The deeper the hydrometer sinks, the lower its density.

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Answer:

matter, dense, equal

Explanation:

According to Rutherford's nuclear theory, the core of an atom (nucleus) contains most of the matter of an atom and is dense, so the majority of the mass of a fluorine atom cannot be due to its nine electrons. According to Rutherford's nuclear theory, most of the volume of an atom is empty space, so the volume of a hydrogen atom cannot be mostly due to the proton. According to Rutherford's nuclear theory, the number of negatively charged particles outside the nucleus is equal the number of positively charged particles within the nucleus, so a nitrogen atom has 7 protons and 7 electrons, while a phosphorous atom cannot have 15 protons and 150 electrons.

Answer:

12.54mL

Explanation:

Step 1:

Data obtained from the question:

Mass of Zn = 2.95g

Density of Zn = 7.14 g/mL

Volume of water = 12.13mL

Final volume reading of cylinder =..?

Step 2:

Determination of the volume of Zn. The volume of Zn can be obtained as follow:

Density = Mass /volume

7.14 = 2.95/volume

Cross multiply

7.14 x Volume = 2.95

Divide both side by 7.14

Volume = 2.95/7.14

Volume of Zn = 0.41mL

Step 3:

Determination of the final volume reading of the cylinder.

The final reading of the cylinder will be the addition of the volume of water and the volume of Zn as shown below:

Final volume of cylinder = volume of water + volume of Zn.

Volume of water = 12.13mL

Volume of Zn = 0.41mL

Final volume =..?

Final volume of cylinder = 12.13 + 0.41

Final volume of cylinder = 12.54mL

Therefore, the final volume reading of the cylinder is 12.54mL

The final volume reading of the graduated cylinder is 12.54 mL.

A 2.95 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder. The volume of the piece of zinc is:

[tex]2.95 g \times \frac{1mL}{7.14 g} = 0.413 mL[/tex]

The final volume reading of the graduated cylinder will be equal to the sum of the volumes of the piece of zinc and the water.

[tex]V = V(H_2O)+V(Zn) = 12.13 mL + 0.413 mL = 12.54 mL[/tex]

The final volume reading of the graduated cylinder is 12.54 mL.

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Answer:

a) CO is the limiting reactant.

b) [tex]n_{H_2}^{excess}=749.9592molH_2[/tex]

c) [tex]n_{CH_3OH}=0.0204molCH_3OH[/tex]

Explanation:

Hello,

In this case, the balanced chemical reaction:

[tex]CO + 2H_2 \rightarrow CH_3OH[/tex]

So we proceed as follows:

a) We first compute the moles of CO by using its density (0.00114 g/mL) and molar mass (28 g/mol):

[tex]n_{CO}=500mLCO*\frac{0.00114gCO}{1mLCO}*\frac{1molCO}{28gCO}=0.0204molCO[/tex]

Next, with the given 750 moles of hydrogen, we can compute the moles of carbon monoxide that are consumed by such amount of hydrogen by using their 1:2 molar ratio:

[tex]n_{CO}^{consumed\ by\ H_2}=750molH_2*\frac{1molCO}{2molH_2}=375molCO[/tex]

Thus, we see a clear excess of hydrogen, for that reason the carbon monoxide is the limiting reactant.

b) In this case, we first compute the moles of CO that are not consumed:

[tex]n_{CO}^{unchanged}=375mol-0.0204mol=374.9796molCO[/tex]

Next, we use the 1:2 molar ratio again to compute the unchanged moles of hydrogen which is the excess reactant:

[tex]n_{H_2}^{excess}=375.9796molCO*\frac{2molH_2}{1molCO} =749.9592molH_2[/tex]

c) Finally, we use the reacting moles of carbon monoxide to compute the formed moles of methanol by using the 1:1 molar ratio:

[tex]n_{CH_3OH}=0.0204molCO*\frac{1molCH_3OH}{1molCO} =0.0204molCH_3OH[/tex]

Best regards.

Answer:

Explanation:

Si tomamos en cuenta el peso molecular del agua, que es equivalente a:

1 Átomo de H₂O

O = 16 gr/mol

H = 1 gr/mol

H₂O = 18 gr/mol

Teóricamente sabemos que en 1 mol de H2O habrá 18 gr.

Para obtener los moles presentes en 1 mg de H₂O, (como 1 gr = 1000 mg), decimos:

1 mol H2O …………………………..  18000 mg

       X          ……………………………   1 mg

X = 1 / 18000 = 5,56 X 10⁻⁵ moles de H20

Y para obtener la cantidad de moléculas presentes, de acuerdo a los moles, multiplicamos por el número de Avogadro (6,023 X 10²³ moléculas /mol)

Moléculas de H₂O = 5,56x 10⁻⁵ mol x 6,023 x 10²³

Moléculas de H₂O = 3,34488 x10¹⁹ moléculas de H₂O

En el copo de nieve habrá 3,34488 x 10¹⁹ moléculas de H₂O.

Espero que te sirva =)

5,43 X 10²² particles of water (H20) are in a collection of snowflakes with a mass of 0.005 g.

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

One mole of any substance is equal to 6.023 × 10²³ units of that substance such as atoms, molecules, or ions. The number 6.023 × 10²³ is called as Avogadro's number or Avogadro's constant.

The mole concept can be used to convert between mass and number of particles.

1 atom of H₂O

O = 16 g/mol

H = 1 gr/mol

H₂O = 18 gr/mol

1 mol H₂O …………………………..  18000 mg

?      X          ……………………………   1 mg

X = 1 / 18000

= 5,43 X 10²² moles de H20

Thus, 5,43 X 10²² particles of water (H20) are in a collection of snowflakes with a mass of 0.005 g.

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Answer:

63.45g of I₂ can be produced

Explanation:

IF₅ reacts with IF to produce IF₇ and I₂. The reaction is:

IF₅ + 2 IF → IF₇ + I₂

Moles of 10.0g of IF₅ (221.89g/mol):

10.0g IF₅ × (1mol / 221.89g) = 0.0451 moles of IF₅

Using PV / RT = n, it is possible to find moles of 11.20L of IF, thus:

1atm×11.20L / 0.082atmL/molK × 273K = 0.500 moles of IF.

At STP, pressure is 1atm, temperature is 273K and gas constant R is 0.082atmL/molK

For a complete reaction of IF₅ you need:

0.0451 moles of IF₅ × (2 moles IF / 1 mole IF₅) = 0.902 moles of IF. As you have just 0.500 moles of IF, the IF is the limiting reactant.

2 moles of IF produce 1 mole of I₂. 0.500 moles of IF produce:

0.500mol IF ₓ ( 1 mol I₂ / 2 mol IF) = 0.250 mol I₂

As molar mass of I₂ is 253.81g/mol, mass of 0.250 mol I₂ are:

0.250mol I₂ ₓ (253.81g / mol) =

Answer:

The concentration of the resulting solution in parts per million is 177.97

Explanation:

Parts per million (ppm), is a unit of measure for concentration that refers to the number of units of the substance per million units of the set.

The concentration in parts per million expressed in mass / mass is calculated by dividing the mass of the solute (ms) by the mass of the solution (md, sum of the mass of the solute and the mass of the solvent), both expressed in the same unit and multiplied by 10⁶ (1 million).

[tex]ppm=\frac{ms}{md} *10^{6}[/tex]

So, being:

Replacing:

[tex]ppm=\frac{0.089 grams}{500.089 grams}*10^{6}[/tex]

ppm= 177.97

The concentration of the resulting solution in parts per million is 177.97