Answer:
34k+B plus 9 :)
Explanation:
The current is suddenly turned off. How long does it take for the potential difference between points a and b to reach one-half of its initial value
Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From the question we are told that
The original voltage is [tex]V_o[/tex]
The new voltage is [tex]V =\frac{V_o}{2}[/tex]
The capacitance is [tex]C = 150\ nF = 150 *10^{-9} \ F[/tex]
The first resistance is [tex]R_i = 26 \Omega[/tex]
The second resistance is [tex]R_E = 200 \Omega[/tex]
Generally the equivalent resistance is
[tex]R_e = R_1 + R_E[/tex]
=> [tex]R_e = 26 +200 [/tex]
=> [tex]R_e = 226 \ \Omega [/tex]
Generally the time constant is mathematically represented as
[tex]\tau = RC[/tex]
=> [tex]\tau = 226 * 150 *10^{-9}[/tex]
=> [tex]\tau = 3.39 *10^{-5} \ s [/tex]
Generally the voltage is mathematically represented as
[tex]V = V_o e^{-\frac{t}{\tau} }[/tex]
=> [tex]\frac{V_o}{2} = V_o e^{-\frac{t}{\tau} }[/tex]
=> [tex]0.5 = e^{-\frac{t}{\tau} }[/tex]
=> [tex]ln(0.5) = {-\frac{t}{ 3.39 *10^{-5} } }[/tex]
=> [tex]ln(0.5) * 3.39 *10^{-5} = -t [/tex]
=> [tex]t = 2.35*10^{-5} \ s [/tex]
Donald Duck Matthews wanted to show up all his friends with his newfound dancing skills he left his house to go to dressers house 20 m north from where he was he's so dresser his moves went off to the next place and next stop was 10 m west at choirboys house luckily he saw Eddie there too. After showing off his skills agai he was satisfied, but he still had to show one last person up. His brother who was 15 m South. After making it there he showed hos moves and smiled. what was Ducks displacement?
A. 12 m SW
B. 11 m NW
C. 45 m NW
D. 45 m NE
The final displacement of the duck would be 11.18 meters in NW, therefore the correct answer is option B.
What is displacementDisplacement describes this shift in location.
As given in the problem Donald Duck Matthews wanted to show up all his friends with the newfound dancing skills he left his house to go to dressers house 20 m north from where he was he's so dresser his moves went off to the next place and next stop was 10 m west at choirboys house luckily he saw Eddie there too.
After showing off his skills again he was satisfied, but he still had to show one last person up. His brother was 15 m South.
His final position would be 5 meters north and 10 meters west.
The displacement of the Duck = √( 10² + 5²)
= 11.18 meters in NW
Thus, the final displacement of the duck would be 11.18 meters in NW.
To learn more about displacement here, refer to the link;
brainly.com/question/10919017
#SPJ2
1. A car travels 36 miles North and then 45 miles East. How far does it
displace?
2. Jason walks 100 meters South and 500 meters West. How far does he
displace from his starting point?
3. If a person riding a back rides 60 meters West then 40 meters North, how far
have they displaced?
4. What is the displacement of a car that travels 700 miles North and then 500
miles East?
5. If a car travels from it's driveway to a town 300 miles North, then returns to
its driveway, how far has it displaced?
6. Does a car displace if it travels 200 miles North and then 100 miles South? If
so, how far?
7. If a car travels South for 650 km and then East for 650 km, how far has it
displaced?
8. Does a racecar displace around a circular track from the start to the end of
the race?
Needs y’all’s help answering these 8 questions please
Answer:
Explanation:
Displacement is the shortest distance or path between two points.
1) Displacement = √(36² + 45²) = 57.63 miles
2) Displacement = √(100² + 500²) = 509.9 meters
3) Displacement = √(60² + 40²) = 72.11 miles
4) Displacement = √(700² + 500²) = 860.23 miles
5) Displacement = 300 - 300 = 0 miles
6) Displacement = 200 + 100 = 300 miles
7) Displacement = √(650² + 650²) = 919.24 miles
8) Yes, since a distance is moved in a direction
How many strings of length 10 over the alphabet (a, b, c, d] have at least one b somewhere in the string?
a) 310
b) 410 - 310
c) 10.4
d) 10.39
Complete Question
The complete question is shown on the first uploaded image
Answer:
The correct option is B
Explanation:
The number of alphabet is n= 4 (a , b , c , d )
Generally the total number of string of length 10 over the 4 alphabets is
[tex]N = 4^{10}[/tex]
Gnerally the number of string of length 10 that does not include b is
[tex]T = 3^{10}[/tex]
Generally the number of strings of length 10 over the 4 alphabets that have at least one alphabet b somewhere in the string is
[tex]G = N - T[/tex]
=> [tex]G = 4^{10} - 3^{10}[/tex]
Determine the acceleration that results when a 12 N net force is applied to a 3 kg object.
a. 4 m/s 2
b. 6 m/s 2
c. 12 m/s 2
d. 36 m/s 2
Answer:
4m/s^2 ( A)
Explanation:
The solution is in the attached file
According to American Heart Association, your target heart rate is__________.
Group of answer choices
A .all of the above
B. 85% - 95% of your max heart rate
C. 20%-30% of your max heart rate
D. 50%-85% of your max heart rate
Answer:
B
Explanation:
A normal heart rate is from 85-95% the other heart rate is not normal because your heart is beating more than normal
4. A teacher throws the stapler at her students 23 m in 1.2 seconds. What speed must the teacher throw the
stapler and what will be the staplers highest point during its flight?
dy = - 42gt2
dx = Vyt
Answer:
dy
Explanation:
My guess of guts.
okay bye
In an illustration, lines of force are drawn around a magnet to illustrate the magnetic
O field.
O induction.
O poles.
O force.
Need help now
Answer: A. Field
Explanation: Magnetic Field is the correct answer.
Answer:
A
Explanation:
A cat chases a mouse for a distance of 9.0 m over 16 s before getting tired. What is the cats average speed?
Answer:
The answer is 0.56 m/sExplanation:
The speed of the cat can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{9}{16} = \\ = 0.5625[/tex]
We have the final answer as
0.56 m/sHope this helps you
1. A diver running 4 m/s dives out horizontally from the edge of a vertical cliff and lands 32 meters
from the cliff. How long was the diver in the air before they hit the water?
a. 125 seconds
c. 36 seconds
b. 8 seconds
d. 128 seconds
Wind eroding the rocks on a moutain is an example of the atmosphere interacting with the cryosphere
true or false
Answer:
False
Explanation:
The cryosphere is all the part of the earth where water is in solid form. Where wind interacts with rocks, it is an example of atmosphere - geosphere interaction.
Rocks are part of the geosphere The geosphere is the part of the earth made up of solid rocks. Wind erosion occurs when wind wears down part of the geosphere.Metals that have shine and luster?
Answer:
luster
Explanation:
ionic bonds form when electrons?
Answer:
when the electron transferred permanently to another atom
The drawing shows two identical airplanes at an air show. The airplanes are flying at the same speed. Airplane W is flying 50 m higher than airplane X. Which statement best describes the energy of the two airplanes?
Answer:
Airplane X has more gravitational potential energy than Airplane W
Explanation:
Gravitational potential energy is defined as "the energy acquired by an object due to its positional change in presence of gravitational force."
That being said, gravitational potential energy depends on the height of an object above the ground. It also depends on the mass of the object and even further, the amount of gravitational force that is applied.
And if we take a look at the question again, we'd agree that the two airplanes are flying at different heights, this means their gravitational potential energy will be different. And as such, Airplane X has more gravitational potential energy than Airplane W
how can water be boiled in a paper cup?
Answer:
if you place a glass of boiling water in a paper cup filled with hot pads
Explanation:
am I thinking too deeply into this or does it make sense
A block of a plastic material floats in water with 35.6% of its volume under water. What is the density of the block in kg/m3
Answer:
The density is [tex]\rho_{block} = 356 \ kg/m^3 [/tex]
Explanation:
From the question we are told that
The proportion of the plastic under water is p = 0.356
Generally at equilibrium the buoyant force is equal to the weight of the block i.e
[tex]B = mg[/tex]
Generally the Buoyant force is mathematically represented as
[tex]B = \rho * V * g[/tex]
Here [tex]\rho[/tex] density of the water with value
[tex]\rho = 1000 kg/m^3[/tex] ,
V is the volume of water displaced by the block which is [tex] p * V_{block [/tex] ,
So
[tex]1000 * 0.356 V_{block} * g = m * g[/tex]
Here m is the mass of the block which is mathematically represented as
[tex]m = \rho_{block} * V_{block}[/tex]
So
[tex]1000 * 0.356 V_{block} * g = \rho_{block} * V_{block}* g[/tex]
[tex]1000 * 0.356 V_{block} = \rho_{block} * V_{block}* g[/tex]
=> [tex]\rho_{block} = 1000 * 0.356[/tex]
=> [tex]\rho_{block} = 356 \ kg/m^3 [/tex]
In the absence of a gravitational field, you could determine the mass of an object (of unknown composition) by:
A) applying a known force and measuring it's acceleration.
B) measuring the volume.
C) weighing it.
Answer:
A) By applying a known force, and measuring it's acceleration.
Explanation:
This is actually something that astronauts do in space as a mathmatical exercise when calculating the mass of an object since F = m × a.
Once the force, and acceleration are applied, the only unknown is the mass which can be solved by dividing force over acceleration. This is because inertial mass is equal to gravitational mass.
How do compounds differ from mixtures such as lemonade
Answer:
A mixture is a combination of two or more substances in any proportion. This is different from a compound, which consists of substances in fixed proportions. ... The lemonade pictured above is a mixture because it doesn't have fixed proportions of ingredients.
Explanation:
I'm imagining a scene in a future Pirates of the Carribean movie. The Black Pearl tried to surf a wave to get over a sandbar and didn't quite make it. The stern (back end) of the ship is stuck on the sand bar and is a sitting duck for the Royal Navy ships following her. The Black Pearl has 2 cannons pointed forward (bowchasers) and 3 cannon pointing backward (sternchasers). Which cannons should Captain Jack Sparrow fire to move his ship forward off the sand bar?
To the left (port)
To the right (starboard)
To the back (the sternchasers)
To the front (the bowchasers)
Answer:
3 in the back so it can shove it off the sand bar
Explanation:
help me get the answer in Physical Science.
Answer:
lithium
Explanation:
I took physical science 2 years ago and passed with an A
A motorcyclist goes around an un-banked (i.e., flat) circular turn of radius 31m, at a constant speed of 110km/hr (convert this to m/s). What is the minimum coefficient of static friction needed to keep the tires from slipping? Explain why the answer is (or is not) plausible.
Answer:
[tex]\mu_{s} = 3.071[/tex]
This result represents an absurd, not plausible, as coefficient of frictions from materials have values between 0 and 1.
Explanation:
From Second Newton's Law we understand that centripetal acceleration experimented by motocyclist is due to force derived from static friction. And normal force of the ground on motocyclist equals weight of motocyclist due to the flatness of circular turn. The equations of equilibrium of the motocyclist is:
[tex]\Sigma F_{x} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (Eq. 1)
[tex]\Sigma F_{y} = N-m\cdot g = 0[/tex] (Eq. 2)
Where:
[tex]\mu_{s}[/tex] - Static coefficient of friction, dimensionless.
[tex]N[/tex] - Normal force, measured in newtons.
[tex]m[/tex] - Mass of the motocyclist, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v[/tex] - Speed of the motorcyclist, measured in meters per second.
[tex]R[/tex] - Radius of the circular turn, measured in meters.
The static coefficient of friction is cleared in (Eq. 1):
[tex]\mu_{s} = \frac{m\cdot v^{2}}{N\cdot R}[/tex]
From (Eq. 2) we get that normai force is:
[tex]N = m\cdot g[/tex]
And we expand the resulting expression in (Eq. 1):
[tex]\mu_{s} = \frac{m\cdot v^{2}}{m\cdot g\cdot R}[/tex]
[tex]\mu_{s} = \frac{v^{2}}{g\cdot R}[/tex] (Eq. 3)
If we know that [tex]v = 30.556\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 31\,m[/tex], the expected static coefficient of friction is:
[tex]\mu_{s} = \frac{\left(30.556\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (31\,m)}[/tex]
[tex]\mu_{s} = 3.071[/tex]
This result represents an absurd, not plausible, as coefficient of frictions from materials have values between 0 and 1.
Electric Charge andStatic ElectricityIt was known as early as 600BCEthat objects could become charged by rubbing fur on various substances such as amber. Charged objects could be used to attract light objects such as hair. In the 1700s, it was determined that charge came in two varieties that could cancel each other out. Charles-Augustin de Coulomb established a quantitativerelation in 1783 that describes how charged objects interact via the electric force. The electric force:
Answer:
Explanation:
In 1785, Coulomb investigated quantitatively, the force exerted between point charges.
The Coulomb's Law states that: "The force of attraction or repulsion between two, point charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them. "
If q₁ and q₂ are two, point charges and r is the distance between them, then the electric force of attraction or repulsion F between them, according to Coulomb’s law will be:
F ∝ q₁q₂ ________________________ eqn (1)
F ∝ 1/r² ________________________ eqn (2)
Combining eqn (1) and eqn (2), we get:
F ∝ (q₁ q₂)/r²
F = (kq₁q₂)/r²
where,
k = constant of proportionality = 9 x 10⁹ N.m² / C²
4. Tires on the road show how friction produces
a. lubrication
b. heat
c. gravity
d. force
help :(
I think it is D. Force
Answer:
Explanation:
Do you mean tire tracks?
If you do then the tracks show that there must have been a lot of heat involved. When the tires skid, the friction produced must be awfully hot to stop and 800 kg vehical (which is pretty small). The tire tracks that you see are bits of melted rubber taken from the tire.
Force is involved, but heat is the better answer.
gravity is necessary for friction to take place. If you were out in space, you could not get enough friction to leave tire tracks. (Force is awfully small).
Lubrication is there to give you a 4th choice. The exact opposite is what takes place. Lubrication reduces friction.
A daring stunt woman sitting on a tree limb
wishes to drop vertically onto a horse gallop-
ing under the tree. The constant speed of the
horse is 6.8 m/s, and the woman is initially
1.91 m above the level of the saddle.
How long is she in the air? The acceleration
of gravity is 9.8 m/s.
Answer in units of s.
Answer:
she is in the air for approximately 0.62 seconds
Explanation:
We want to find the time for a free fall under the acceleration of gravity, covering a distance of 1.91 m, and considering that the woman doesn't impart initial velocity in the vertical direction. So we use the kinematic equation:
[tex]d=v_i\,t+ \frac{g}{2} \,t^21.91 = 0 +4.9\, t^2\\t^2=1.91/4.9\\t=\sqrt{1.91/4.9} \\t\approx 0.624\,\,sec[/tex]
Then she is in the air for approximately 0.62 seconds
A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 98 m and acquired a velocity of The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to:
29 m/s2
31 m/s2
33 m/s2
30 m/s2
32 m/s2
Explanation:
The question is incomplete. Here is the complete question.
A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 98 m and acquired a velocity of 30m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to...
Given
initial velocity of rocket u = 0m/s
final velocity of rocket = 30m/s
Height reached by the rocket = 98m
Required
upward acceleration of the rocket
Using the equation of motion below to get the acceleration a:
[tex]v^2 = u^2+2as\\30^2 = 0^2 + 2(a)(98)\\900 = 196a\\a = \frac{900}{196}\\a = 4.59m/s^2[/tex]
Hence upward acceleration of the rocket during the burn phase is closest to 5m/s²
Note that the velocity used in calculation was assumed.
dimensional formula of stress is same as
Dimensional formula of stress is same as pressure.
Two students measured the length of the same stick, each using a different 30 cm ruler. One student reported a length of 22 cm, and the other reported a length of 8 cm. The most likely explanation for the difference in the reported values is that one —
A. *student improperly read the ruler
B. ruler was metal and the other ruler was plastic
C. student viewed the ruler from a different angle
D. ruler was constructed with nonstandard cm marks
Answer:
C. student viewed the ruler from a different angle
Explanation:
It is the problem of viewing the scale from different sides or angles. If we assume the actual length of the stick to be 22 cm. Then the first student measured the length by reading the values from 1 cm towards 22 cm on the scale. While, the second student measured the length of the stick by reading the values from the other side or the other angle of the scale, that is, from 30 cm mark towards 1 cm. And in that case the the length of the 22 cm long stick will appear as:
30 cm - 22 cm = 8 cm
Therefore, the second student read 8 cm on scale. So, the correct option is:
C. student viewed the ruler from a different angle
Consider the trajectories of a projectile that experiences drag due to air resistance. Maximum range is achieved by launching the projectile at ________.
a. An angle less than 45 degrees.
b. An angles of 45 degrees.
c. An angle greater than 45 degrees.
d. An angle that depends on the launch speed
Answer:
Maximum range is achieved by launching the projectile at an angles of 45 degrees.
so the answer is B
Explanation:
What is the range of a projectile?
this can be defined as the maximum horizontal distance covered by a projectile
R=v^2sin(2θ)/2g
Why is 45 degrees maximum range?
"The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range puts 2θ = 90 degrees and, therefore, θ = 45 degrees."
Hence a projectile, travels the farthest when it is launched at an angle of 45 degrees
The velocity of a body travelling in a circular path can be measured with an uncertainty estimated at 4%. The Radius R of the circular path can be measured within 2%. What is the uncertainty associated with the determination of normal acceleration, a, from a = v^2/R Would it make much difference if the radius could be measured within 1%?
Answer:
a) uncertainty percentage = 10%
b) if R could be measured within 1%, uncertainty percentage is 9%,
it wouldn't make much difference
Explanation:
Given that;
velocity v = 4%
radius R = 2%
using calculation on errors / uncertainties in mumber,
To find error/uncertainty in aₙ
aₙ = V² / R
= V₂ × 1/R
V × V × 1/R
let U + V be x and relative error ΔV/V = 4% = 0.04
also, let R be Y and error (relative) ΔR/R = 2% = 0.02
so aₙ = V²/R = x² / y --------------------- let this be equ 1
Δaₙ/aₙ = ΔV/V + ΔR/R + ΔV/V {V×V×1/R}
Δaₙ/aₙ = 0.4 + 0.02 + 0.4
Δaₙ/aₙ = 0.1
so 0.1 × 100 = 10%
therefore uncertainty percentage = 10%
if R could be measured within 1%
Δaₙ/aₙ = (0.04 × 2) + 0.01
= 0.08 + 0.01
= 0.09
so 0.09 × 100
= 9%
therefore if R could be measured within 1%, uncertainty percentage is 9%,
it wouldn't make much difference
A 126 N force is applied at an angle of 25.00 to a 8.50 kg block pressed against a rough vertical wall and the block slides down the wall at constant velocity. Calculate the coefficient of kinetic friction between the block and the wall.
Answer:
μk = 0.58
Explanation:
If the block is sliding down at constant speed, this means that no net force is acting upon it in the vertical direction.As the block is pressed on the wall, this means that it doesnt accelerate in the horizontal direction either, so no net force acts upon it in this direction also.In this direction, we have only two forces acting, equal and opposite each other, one is the normal force (exerted by the wall) and the other is the horizontal component of the applied force.If the applied force forms an angle of 25º with the wall (which is vertical), this means that we can get its projection along the horizontal direction, using simple trigonometry , as follows:[tex]F_{apph} = F_{app} * sin\theta = 126 N * sin 25 = 53.3 N[/tex]
⇒ [tex]F_{n} = - F_{apph} = -53.3 N[/tex]
In the vertical direction, we have three forces acting on the block: the weight pointing downward, the kinetic friction force (as we know that the block is sliding), and the vertical component of the applied force, in the same direction as the friction one.As we have already said, the sum of these forces must be 0.[tex]F_{g} + F_{appv} + F_{ff} = 0 (1)[/tex] where Fg is the weight of the block, Fappv is the vertical component of the applied force, and Fff is the kinetic friction force.Replacing these forces by their mathematical expressions, we have:[tex]F_{g} = m_{b} * g = 8.5 Kg * (-9.8 m/s2) = -83.3 N[/tex]
[tex]F_{appv} = F_{app}* cos\theta = 126 N * cos 25 = 114.2 N[/tex]
[tex]F_{ff} = \mu_{k}* F_{n} =\mu_{k} * (-53.3 N)[/tex]
Replacing in (1), and solving for μk, we finally get:μk = 0.58
