Find the equation of the line that passes through the point (6,14) and is parallel to the equation below.
y =
1 - 4
OA.
y = r - 18
OB.
y = - + 20
y = ģx + 10
OC.
OD
y =
- 52 + 8
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Find The Equation Of The Line That Passes Through The Point (6,14) And Is Parallel To The Equation Below.y

Answers

Answer 1

Answer:

y = 2x/3 + 10 ; C

Step-by-step explanation:

To write the equation of a straight line, we have the general form as;

y = mx + b

where m is the slope and b is the y intercept

Mathematically from the equation given, the slope value is 2/3

When two lines are parallel to each other , the value of their slopes are the same

What this mean is that the value of the slope of the second line is 2/3

So we have the second line as;

y = 2x/3 + b

To get the value of b, we use the given point where the line passes through

The given point according to the question is the point (6,14)

so using this coordinates, we have

14 = 2/3(6) + b

14 = 4 + b

b = 14-4

b = 10

So the equation of the new line is;

y= 2/3x + 10


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Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given 2 sides of a triangle then the third side x is in the range

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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step by step explanation:




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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

B

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

9514 1404 393

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Step-by-step explanation:

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bit.[tex]^{}[/tex]ly/3tZxaCQ

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Step-by-step explanation:

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Step-by-step explanation:

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