Here is the correct computation of the question given.
Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.
Men aged 20-29: 117 122 129 118 131 123
Men aged 60-69: 130 153 141 125 164 139
Group of answer choices
a)
Men aged 20-29: 4.8%
Men aged 60-69: 10.6%
There is substantially more variation in blood pressures of the men aged 60-69.
b)
Men aged 20-29: 4.4%
Men aged 60-69: 8.3%
There is substantially more variation in blood pressures of the men aged 60-69.
c)
Men aged 20-29: 4.6%
Men aged 60-69: 10.2 %
There is substantially more variation in blood pressures of the men aged 60-69.
d)
Men aged 20-29: 7.6%
Men aged 60-69: 4.7%
There is more variation in blood pressures of the men aged 20-29.
Answer:
(c)
Men aged 20-29: 4.6%
Men aged 60-69: 10.2 %
There is substantially more variation in blood pressures of the men aged 60-69.
Step-by-step explanation:
From the given question:
The coefficient of variation can be determined by the relation:
[tex]coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100[/tex]
We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69
To start with;
The coefficient of men age 20 -29
Let's first find the mean and standard deviation before we can do that ;
SO .
Mean = [tex]\dfrac{\sum \limits^{n}_{i-1}x_i}{n}[/tex]
Mean = [tex]\frac{117+122+129+118+131+123}{6}[/tex]
Mean = [tex]\dfrac{740}{6}[/tex]
Mean = 123.33
Standard deviation [tex]= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }[/tex]
Standard deviation =[tex]\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }[/tex]
Standard deviation = [tex]\sqrt{\dfrac{161.3334}{5}}[/tex]
Standard deviation = [tex]\sqrt{32.2667}[/tex]
Standard deviation = 5.68
The [tex]coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100[/tex]
[tex]coefficient \ of \ variation = \dfrac{5.68}{123.33}*100[/tex]
Coefficient of variation = 4.6% for men age 20 -29
For men age 60-69 now;
Mean = [tex]\dfrac{\sum \limits^{n}_{i-1}x_i}{n}[/tex]
Mean = [tex]\frac{ 130 + 153 + 141 + 125 + 164 + 139}{6}[/tex]
Mean = [tex]\dfrac{852}{6}[/tex]
Mean = 142
Standard deviation [tex]= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }[/tex]
Standard deviation =[tex]\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }[/tex]
Standard deviation = [tex]\sqrt{\dfrac{1048}{5}}[/tex]
Standard deviation = [tex]\sqrt{209.6}[/tex]
Standard deviation = 14.48
The [tex]coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100[/tex]
[tex]coefficient \ of \ variation = \dfrac{14.48}{142}*100[/tex]
Coefficient of variation = 10.2% for men age 60 - 69
Thus; Option C is correct.
Men aged 20-29: 4.6%
Men aged 60-69: 10.2 %
There is substantially more variation in blood pressures of the men aged 60-69.
what’s the correct answer for this?
Answer:
A.
Step-by-step explanation:
98%
The probability of not winning the raffle is 100% - 2% = 98%
f(x)=2x-6 g(x)=3x+9, find (f+g)
Answer:
(f+g)(x) = 5x +3
Step-by-step explanation:
(f+g)(x) = f(x) +g(x)
= (2x -6) +(3x +9)
= 2x +3x -6 +9
(f+g)(x) = 5x +3
Directions:
Write and solve a proportion to answer the question.
1/5 is 40% of what number?
Answer:
20/40
Step-by-step explanation:
1/5=40/100*x
x=1/5*100/40
x=20/40 or 10/20 or 0.5
Y is directly proportional to (x+2)2 when x=8 y = 250 find y when x=4
Answer: 150
Step-by-step explanation: K is constant
250= K (8+2)2
250= K (10)2
250= K (20)
250= K20
divide both sides by 20
250/20= K
12.5= K
THEREFORE
Y= K (4+2)2
Y= 12.5 (6)2
Y= 12.5 × 12
Y= 150
At x = 4 the value of the variable y will be 90 as per the proportionality given.
What is proportionality?The property of having suitable proportions in terms of size, number, degree, harshness, etc.: If a defensive action against an unfair attack results in destruction that contravenes the proportionality criterion, it may even go far beyond a justifiable defense.
Given, Y is directly proportional to (x+2)2 when x=8 y = 250
Since Y ∝ (x + 2)²
Y = k (x + 2)²
Where k is constant
For x = 8 y = 250
Substituting the values
250 = k(8 + 2)²
k = 2.5
Thus for x= 4
y = 2.5 (4 + 2)²
y = 90
therefore, According to the proportionality, the variable y will have a value of 90 at x = 4.
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A sports-equipment factory produces sports balls. On Monday, they produced 1,080 balls altogether. All of the balls they produced were either volleyballs or soccer balls. They produced 7 times as many volleyballs as soccer balls. How many soccer balls did the factory produce on Monday?
Answer: 135 soccer balls
Step-by-step explanation:
In this equation, let x represent the number of soccer balls, and 7x represent the number of volley balls.
7x + x = 1,080
8x = 1,080
Now divide 1,080 by 8 to get the number of soccer balls.
1,080 / 8 = 135
In case you’re wondering how to find the number of volley balls, just multiply 135 by 7
135 * 7 = 945
What is the value of X?
Answer:
the answer to the problem is 35.
Answer:
he horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate. Also called "Abscissa"
Step-by-step explanation:
Given the data shown below, which of the following is the best prediction for
the number of years it will take for the population to reach 200,000?
Year
Population
11,920
2
16,800
3
23,300
4
33,000
5
45,750
6
64,000
O A. 9.41
O B. 12.45
O C. 15.82
O D. 18.14
Answer:
The best prediction for the number of years it will take for the population to reach 200,000 is 9.41
Step-by-step explanation:
Year Population
1 11,920
2 16,800
3 23,300
4 33,000
5 45,750
6 64,000
[tex]y_1 =A _0 e ^{kt _1}\\y_2 = A_0 e^{k t_2}\\(t_1,y_1)=(1,11920)\\(t_2,y_2)=(2,16800)[/tex]
Substitute the values
[tex]11920=A _0 e ^{k} ---1\\16800 = A_0 e^{2k} ---2[/tex]
Divide 1 and 2
[tex]\frac{11920}{16800}=\frac{e^k}{e^{2k}}\\\frac{11920}{16800}=e^{k-2k}\\ln(\frac{11920}{16800})=-k\\k=-1 ln(\frac{11920}{16800})\\k=0.3432\\A_0=y_1 e^{-k t_1}\\A_0=11920 e^{-0.3432}\\A_0=8457.5238[/tex]
The exponential function that passes through the points (1, 11920) and (2, 16800) is[tex]y=8457.5238 e^{0.3432t}[/tex]
Now we are supposed to find the best prediction for the number of years it will take for the population to reach 200,000
[tex]200000=8457.5238 e^{0.3432t}[/tex]
[tex]\frac{200000}{8457.5238}=e^{0.3432t}[/tex]
[tex]ln(\frac{200000}{8457.5238})=0.3432t[/tex]
t = 9.41
Hence the best prediction for the number of years it will take for the population to reach 200,000 is 9.41
At a carnival, an individual can win a prize by choosing a rubber duck from a pond with "Win" written on the underside of the duck. There are a total of eight ducks with "Win" written on the underside of the duck, and there are 17 ducks with "Lose" written on the underside of the duck. After each pick, if a prize is won, the duck is replaced in the pond. If a prize is not won, then the duck is again placed back into the pond. If an individual makes four picks, what is the probability the individual will win a prize exactly one time?
Step-by-step explanation:
The probability of success = 8/(8 + 17) = 8/25 = 0.32.
Let X be the random variable denoting the number of successes (number of times the individual won a prize) in four picks.
Hence, X ~ Bin(4, 0.32).
Thus, P(X = 1) = [tex]4C_1=(0.32)(1-0.68)^{4-1}=4C_1(0.32)(0.68)^3[/tex]
The probability the individual will win a prize exactly one time is
C(4, 1)(0.32)¹ (0.68)³ if the total of eight ducks with “Win” written on the underside of the duck.
What is probability?It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
There are a total of eight ducks with “Win” written on the underside of the duck, and there are 17 ducks with “Lose” written on the underside of the duck.
The probability of success
P = 8/(8 + 17)
P = 8/25
P = 0.32
Let's suppose the X is the random variable denoting the number of the individual won a prize in four picks.
So,
X ~ Bin(4, 0.32).
Thus, P(X = 1) = C(4, 1)(0.32)(1 0.32)⁴⁻¹
= C(4, 1)(0.32)¹ (0.68)³
Thus, the probability the individual will win a prize exactly one time is
C(4, 1)(0.32)¹ (0.68)³ if the total of eight ducks with “Win” written on the underside of the duck.
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What’s the correct answer for this question?
Answer:
A.
Step-by-step explanation:
Circle with centre (0,2) will have the equation
(x)²+(y-2)² = r²
Finding r² by distance formula using P(-7,2)
r² = (-7-0)²+(2-2)²
r² = (-7)²
r² = 49
So substituting in the equation
x²+(y-2)² = 49
What’s the correct answer for this?
Answer:
36
Step-by-step explanation:
Diameter AB bisects the chord
MO = NO
5x+3=6x
3 = 6x-5x
x = 3
Now
MN = 5x+3+6x
MN = 5(3)+3+6(3)
MN = 15+3+18
MN = 36
If 25 new born babies are randomly selected, what is the probability that the 25 babies are born that their mean weigh less than 3100g?
Answer:
Step-by-step explanation:
Given that
n = 25
mean = 3100
standard deviation = 500
[tex]\bar x = \frac{500}{\sqrt{25} }[/tex]
= 500 / 5
= 100
N ( μ = 3500, (500)² / 25)
N = (3500,(100)² )
b) P ( x < 3100)
c) Z score
[tex]z = \frac{x - u _{\bar x}}{\sigma \_ {\bar x}}[/tex]
[tex]u_{\bar x}= 3500[/tex]
[tex]\sigma _{\bar x}= 100[/tex]
[tex]z = \frac{3100-3500}{100} \\\\= -4[/tex]
d)
probability=
P ( x < 3100) = P < -4 = 0
Answer:
a) The parameters for the sampling distribution include
Mean = μₓ = 3500 g
Standard deviation = σₓ = 100 g
Required probability = P(x < 3100)
b) The image of the probability density curve is presented in the attached image.
c) The z-score for 3100 g in the sampling distribution = -4.00
d) The probability that the 25 babies that are born that their mean weigh less than 3100 g = 0.00003
Step-by-step explanation:
Complete Question
Suppose we know the birth weights of babies is normally distributed, with mean of 3500 g and standard deviation 500g.
If 25 new born babies are randomly selected, what is the probability that the 25 babies are born that their mean weigh less than 3100g?
a) What are the parameters?
b) Draw a probability density curve for the problem.
c) What is the z-score of the weight?
d) What is the required probability?
Solution
The Central limit theorem explains that for a random sample of adequate size obtained from a normal distribution with independent variables, the mean of the sampling distribution is approximately equal to the population mean and the sampling distribution is approximately of the nature of the population distribution (normal) with the standard deviation of the sampling distribution given as
Standard deviation of the sampling distribution = [(Population Standard deviation)/√n]
σₓ = (σ/√n)
Mean of Sampling distribution = Population mean
μₓ = μ = 3500 g
σₓ = (σ/√n) = (500/√25) = 100 g
a) The parameters for the sampling distribution include
Mean = μₓ = 3500 g
Standard deviation = σₓ = 100 g
Required probability = P(x < 3100)
b) The image of the probability density curve is presented in the attached image.
c and d) To obtain the required probability, we need the z-score for 3100 g, so we standardize 3100g
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (3100 - 3500)/100 = - 4.00
To determine the required probability 45mg/L, P(x < 3100) = P(z < -4.00)
We'll use data from the normal probability table for these probabilities
P(x < 3100) = P(z < -4.00) = 0.00003
Hence, the probability that the 25 babies that are born that their mean weigh less than 3100 g = 0.00003
Hope this Helps!!!!
The sum of a number and its reciprocal is 41/20. Find the number. smaller value larger value
Step-by-step explanation:
Let the number is x. Its reciprocal will be 1/x. According to given condition, we get :
[tex]x+\dfrac{1}{x}=\dfrac{41}{20}\\\\\dfrac{x^2+1}{x}=\dfrac{41}{20}\\\\20x^2+20=41x\\\\20x^2-41x+20=0[/tex]
It is a quadratic equation. The values of x are :
[tex]20x^2-25x - 16x+ 20 =0\\\\5x(4x - 5) -4( 4x - 5) = 0\\\\(5x-4)(4x-5)=0\\\\5x-4=0\ \text{and}\ (4x-5)=0\\\\x=\dfrac{4}{5}\ \text{and}\ x=\dfrac{5}{4}[/tex]
The smaller number is 4/5 and the larger number is 5/4.
Terry, Edin and Gordon are hygiene inspectors. Three takeaways, kebab, fish and chips and pizza. It is decided to share the work so that all inspectors will visit one takeaway each, chosen at random. List all the possible different ways they could share the work. (TK-EF-GP,
Answer: There are 6 different ways in which they can share the work.
Step-by-step explanation:
Suppose that Terry selects first the place where he goes, in the selection he has 3 options at random to chose.
Then Edin selects, Edin has two options (because one is already taken)
Then Gordon selects, he has only one options.
The number of combinations is equal to the product of the number of options for each selection, this is:
Combinations = 3*2*1 = 6
There are 6 different ways in which they can share the work.
Keep getting this wrong please help!!!
Answer:
14.13 in³
Step-by-step explanation:
Volume of a ball (sphere) is:
V = ⁴/₃ π r³
Circumference of a ball (circle) is:
C = 2π r
Use the circumference to find the radius.
9.42 in = 2π r
r = 1.50 in
Use the radius to find the volume:
V = ⁴/₃ π (1.50 in)³
V = 14.13 in³
I keep gettin this wrong please help!!!
Answer:
Slow = 30
Fast = 50
Step-by-step explanation:
So make variables for the speed.
Slow wanderer = x
Faster wanderer = x + 20
The time it took was 2.5 hours.
2.5x + 2.5x + 50 = 200
5x + 50 = 200
x = 30
An old saying in golf is "You drive for show and you putt for dough." The point is that good putting is more important than long driving for shooting low scores and hence winning money. To see if this is the case, data from a random sample of 69 of the nearly 1000 players on the PGA Tour's world money list are examined. The average number of putts per hole and the player's total winnings for the previous season are recorded. A least-squares regression line was fitted to the data. The following results were obtained from statistical software. the p-value for the test in question 3 is 0.0087. p-value for the test in question 3 is 0.0087. a correct interpretation of this result is that:____________
Answer:
With this P-value, we have statistical evidence to support the claim that there is a relationship between the average number of putts per hole and the player's total winnings.
Step-by-step explanation:
In this case, the hypothesis test has the following hypothesis:
Null hypothesis: there is no relationship between the average number of putts per hole and the player's total winnings.
Alternative hypothesis: there is relationship between the average number of putts per hole and the player's total winnings.
Then, a P-value of 0.0087 is, without doubt, a strong evidence that the null hypothesis is false.
With this P-value, we have statistical evidence to support the claim that there is a relationship between the average number of putts per hole and the player's total winnings.
A standard card deck has 52 cards consisting of 26 black and 26 red cards. Three cards are dealt from a shuffled deck, without replacement. Complete parts a through c below. a. Determine whether the following statement is true or false. The probability of being dealt three black cards is one half times one half times one half equals one eighth . If true, explain why. If false, show how to get the correct probability.
Answer:
6 / 51
Step-by-step explanation:
It is false.
Reason:
The probability of picking a black card at first is:
26 / 52 = 1/2
There are now 25 black cards and 51 cards in total.
The probability of picking another black card, if there's no replacement is now:
25 / 51
Now, there are 24 black cards and 50 cards left in total.
The probability of picking a black card without replacement now becomes:
24 / 50 = 12 / 25
Hence, the probability of picking three black cards without replacement is:
1/2 * 25/51 * 12 / 25 = 300 / 2550
In simplest form, it is 6 / 51
expand and simplify (4+√2)(6-√2)
Answer:
[tex]22+2\sqrt{2}[/tex]
Step-by-step explanation:
[tex](4+\sqrt{2} )(6-\sqrt{2} )[/tex]
[tex]4(6)-4\sqrt{2} +6\sqrt{2} -2[/tex]
[tex]24+2\sqrt{2} -2[/tex]
[tex]22+2\sqrt{2}[/tex]
A force of 8 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching it from its natural length to 14 in. beyond its natural length? W = ft-lb
Answer:
The work done in stretching it from its natural length to 14 in. beyond its natural length is W=8.17 ft-lb.
Step-by-step explanation:
We know that a force of 8 lb is required to hold a spring stretched 8 in. beyond its natural length.
This let us calculate the spring constant k as:
[tex]F=kx\\\\k=F/x=(8 \;lb)/(8\;in)=1\;lb/in[/tex]
We know that work is, in an scalar form, the product of force and distance.
The force F is equal to the spring constant multiplied by the distance from the natural length.
Then, as the force changes with the distance from the natural length, we have to calculate integrating:
[tex]W=\int_0^{14}F\,dx=\int_0^{14}kx\,dx\\\\\\W=\dfrac{1}{2}kx^2\left|^{14}_0=\dfrac{1}{2}(1\,lb/in)(14 \,in)^2-\dfrac{1}{2}(1\,lb/in)(0 \,in)^2[/tex]
[tex]W=98lb\cdot in-0lb-in\\\\W=98(lb\cdot in)\cdot \dfrac{1 \,ft}{12\,in}=8.17\;lb\cdot ft[/tex]
Question 20 (5 points)
In a jet engine, what purpose does the afterburner serve?
A,) It reheats the gas from the fuel and releases it more rapidly.
B.) It burns fuel once the plane reaches its maximum altitude.
C.) After the plane lands, it burns off excess fuel that wasn't used in flight.
D.) It provides a way to slow the plane down by cooling the exhaust gas.
It reheats the gas from the fuel and releases it more rapidly.
The answer is option A.
How long can a jet fly on an afterburner?In full afterburner at low altitudes, the F-16 can burn in excess of 64,000 pounds an hour. At full throttle, a U.S.-variant F-16 with maximum external fuel stores has about 20 minutes until it's on emergency reserves (which would only last an extra minute or so at full afterburner).
Does afterburner increase thermal efficiency?Since the exhaust gas already has a reduced oxygen content, owing to the previous combustion, and since the fuel is not burning in a highly compressed air column, the afterburner is generally inefficient in comparison to the main combustion process.
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The required return on equity is:
A) It has nothing to do with market risk premium
B) generally less than post-tax debt costs.
C) A debt/capital ratio of 0.5 is smaller than WACC.
D) is directly related to the risk of the company's assets.
E) It is generally the reciprocal of inflation.
Answer:
D) is directly related to the risk of the company's assets.
Step-by-step explanation:
Equity which may be defined as what the difference between what your business worth minus what you owe in it.
It can also be put in a way as the remaining value of an owners interest in a particular company after all debt might have been cleared.
Equity= assets - liability
So equity has a lot to do in the risk management of a business or a particular company.
What’s the correct answer for this question?
Answer:
D.
Step-by-step explanation:
For independent events
P(A and B) = P(A) × P(B)
FINDING P(B)
P(B) = P(A and B) /P(A)
P(B) = 0.6/0.8
P(B) = 0.75
How many edges dose the following shape have?
What is this answer?
Answer:
1
Step-by-step explanation:
coz 1 x 1 x 1=1
I am just confused can someone help please...
Two models R1 and R2 are given for revenue (in billions of dollars per year) for a large corporation. The model R1 gives projected annual revenues from 2008 through 2015, with t = 8 corresponding to 2008, and R2 gives projected revenues if there is a decrease in the rate of growth of corporate sales over the period. Approximate the total reduction in revenue if corporate sales are actually closer to the model R2. (Round your answer to three decimal places.) R1 = 7.21 + 0.55t R2 = 7.21 + 0.44t
Answer:
7.0422 is the correct answer to the given question .
Step-by-step explanation:
Given
R1 = 7.21 + 0.55t
R2 = 7.21 + 0.44t
Decrease in the revenue can be determined by the formula
[tex]= Reduction\ in\ R1\ -\ Reduction\ in\ R2[/tex]
[tex]= (7.21 + 0.55t ) - (7.21 + 0.44t)[/tex]
=0.11 t
Now overall Reduction can be determined by the interval from t=8 to t=15
Consider c=0.11 t
[tex]\frac{dc}{dt}[/tex]=0.11
Now integrated the equation from t=8 to t=15 to determine total reduction in revenue
[tex]=\int_{8}^{15}\sqrt{1+0.11^2}\ dL[/tex]
[tex]=7.0422[/tex]
The accompanying data set consists of observations on shower-flow rate (L/min) for a sample of n = 129 houses: 4.6 12.1 7.1 7.0 4.0 9.2 6.7 6.9 11.5 5.1 11.2 10.5 14.3 8.0 8.8 6.4 5.1 5.6 9.6 7.5 7.5 6.2 5.8 2.7 3.4 10.4 9.8 6.6 3.7 6.4 8.3 6.5 7.6 9.3 9.2 7.3 5.0 6.3 13.2 6.2 5.4 4.8 7.5 6.0 6.9 10.8 7.5 6.6 5.0 3.3 7.6 3.9 11.9 2.2 15.0 7.2 6.1 15.3 18.1 7.2 5.4 5.5 4.3 9.0 12.7 11.3 7.4 5.0 3.5 8.2 8.4 7.3 10.3 11.9 6.0 5.6 9.5 9.3 10.4 9.7 5.1 6.7 10.2 6.2 8.4 7.0 4.8 5.6 10.5 14.6 10.8 15.5 7.5 6.4 3.4 5.5 6.6 5.9 15.0 9.6 7.8 7.0 6.9 4.1 3.6 11.9 3.7 5.7 6.8 11.3 9.3 9.6 10.4 9.3 6.9 9.8 9.1 10.6 4.5 6.2 8.3 3.1 4.9 5.0 6.0 8.2 6.3 3.8 6.0 (a) Construct a stem-and-leaf display of the data. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
Answer:
Step-by-step explanation:
For n=129 and with leaf unit = 0.1, the stem and leaf chart of the given data on Shower-flow rate (L/min) is as follows:
2 28
Stem leaves
3----------1344567789
4----------01356889
5----------00001114455666789
6----------0000122223344456667789999
7----------00012233455555668
8----------02233448
9----------012233335666788
10----------2344455688
11--------- 2335999
12---------- 17
13-------- 9
14--------36
15---------- 0035
16---------None
17---------None
18 ----------3
* From steam and leaf chart we note that minimum Shower flow rate is 2.2 whereas maximum is 18.3 L/mim. Further typical or representative rate is 7.0 L/min.
* The display of data on steam and leaf chart shows that data is positively skewed means concentration of data on left side or lower value side is high as compared to other side.
* Distribution is not symmetric rather very clear positive skew ness is observed through steam and leaf chart. Even distribution is Unimodal.
* From steam and leaf chart is indicative to conclude that the highest observation 18.3 is outlier.
What is the completely factored form of polynomial 5X cubed +20 X squared plus 2X +8
Step-by-step explanation:
5x3 + 20x2 + 2x + 8
5x2 (x + 4) + 2(x + 4)
(5x2 + 2) (x + 4)
factorise fully 24x+16
Answer:
8(3x + 2)
Step-by-step explanation:
→To factorize this expression, you must take out the GCF (Greatest Common Factor). The GCF is the biggest number that you can take out of all the terms in the expression, meaning the number has to be able to be divide by 24x and 16.
→The GCF is 8:
8(3x + 2)
Answer:
8(3x+2)
Step-by-step explanation:
24x+16
8*3*x + 8*2
Factor out an 8
8(3x+2)
Find the angle of least positive measure that is coterminal with 541 degrees
Answer: 181 degrees.
Step-by-step explanation:
If we have an angle A, between, then the angle B is coterminal to A if:
B = A + n*360°
where n can be any whole number (if n = 0, we have B = A)
Then, if we take our angle as A = 541°
we can take n = -1 and get:
B = 541° - 1*360° = 181°
Now, if we subtract again 360°, we will end with an angle of negative measure, so 181° is the least positive measure angle that is coterminal with 541°
