Answer:
because they can create noise
Explanation:
sounds is through music or songs but vibration is just quick vibrate music, not quite sure , it's just my instinct, lol
The solubility of limestone, CaCO3, at 25˚C is 0.00067 g/100 mL. Write the chemical equation for the solubility equilibrium of this sparingly soluble salt in water. Then compute the molar solubility and the solubility product constant Ksp for CaCO3 at 25˚C.
Answer:
4.5 × 10⁻⁹
Explanation:
Step 1: Write the reaction for the solution of CaCO₃
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Step 2: Convert the solubility of CaCO₃ from g/L to mol/L
We will use the following conversion factors:
The molar mass of CaCO₃ is 100.09 g/mol.1 L= 1000 mL.There are 0.00067 g of CaCO₃ per 100 mL of solution.[tex]\frac{0.00067 gCaCO_3}{100mLSol} \times \frac{1molCaCO_3}{100.09gCaCO_3} \times \frac{1000mLSol}{1LSol} = 6.7 \times 10^{-5} M[/tex]
Step 3: Calculate the solubility product constant (Ksp)
To relate Ksp and the molar solubility (S), we need to make an ICE chart.
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +S +S
E S S
The solubility product constant is:
Ksp = [Ca²⁺].[CO₃²⁻] = S² = (6.7 × 10⁻⁵)² = 4.5 × 10⁻⁹
3. A certain Chemical Industry company has a quality control job opening. The job is open for any major with basic knowledge of chemistry. You decided to apply. In the interview the HR personnel gives you a sealed folder from a certain lot to test your laboratory experience, as well as your quantitative and volumetric analysis skills. The chemical contained in the sample is benzoic acid (C-H602) and it is known to be a monoprotic acid. In order to get the job, you need to determine if the sample's purity is acceptable based on their standards. Inside the folder you found a vial with a solid sample labeled BA-I, a periodic table, and the following data: 1.250 g of the sample required 20.15 mL of 0.500 M concentration of NaOH to reach the end point. The lot can be denied if the purity is below 99.5 % purity.
1) What is the purity in the sample?
2) Is it the purity acceptable?
3) Would you repeat the titration experiment?
Answer:
1) 97.6%
2) No the purity is not acceptable because the standard is 99.5% purity.
3) Yes I will repeat the titration experiment to confirm my result.
Explanation:
Equation of the reaction;
C7H6O2(aq) + NaOH(aq) ---------> C7H5ONa(aq) + H2O(aq)
From the information provided;
Number of moles of NaOH reacted = concentration × volume = 20.15/1000 × 0.500 = 0.01 moles
From the reaction equation;
1 mole of C7H6O2 reacts with 1 mole of NaOH
Hence 0.01 moles of C7H6O2 will react with 0.01 moles of NaOH
Mass of C7H6O2 reacted = number of moles of C7H6O2 × molar mass of C7H6O2
Molar mass of C7H6O2 = 122.12 g/mol
Mass of C7H6O2 reacted = 0.01 moles × 122.12 g/mol = 1.22 g
Percentage by mass of pure C7H6O2 in the impure sample = 1.22/1.250 × 100 = 97.6 %
Sodium is located above potassium in Group 1 of the periodic table. If a potassium ion has a charge of +1, what is the charge on a sodium ion?
A. -1
B 0
C. +1
D +2
Answer:
C
Explanation:
It will be the same. That's what moving down a column means. The properties are going to be quite similar.
A geochemist has determined by measurements that there are moles of tin in a sample of cassiterite. How many moles of oxygen are in the sample
The question is incomplete, the complete question is:
This is the chemical formula for cassiterite (tin ore): SnO2 A geochemist has determined by measurements that there are 13. moles of tin in a sample of cassiterite. How many moles of oxygen are in the sample? Round your answer to 2 significant digits.
Answer:
Explanation:
In SnO2, there are two moles of oxygen for each mole of tin.
Hence, if there are 13 moles of tin, then we should have 13 * 2 moles of oxygen. This gives us 26 moles of oxygen.
Hence there are 26 moles of oxygen.
20 POINTS PLEASE ANSWER ASAP!!!!
Why is calcium (Ca) in group 2, period 4 on the periodic table?
A Calcium, like all group 2 elements, is nonreactive and a gas at room temperature.
B Calcium, like all period 4 elements, is nonreactive and a gas at room temperature,
C Calcium, like all group 2 elements, is reactive and a solid at room temperature.
D. Calcium, like all period 4 elements, is reactive and a solid at room temperature.
Calcium (Ca) is in group 2 and period 4 on the periodic table be because Calcium has 2 valence electrons and 4 electron shell. Thus, calcium is a metal like all other group 2 element.
The correct answer to the question is Option C. Calcium, like all group 2 elements, is reactive and a solid at room temperature.
Calcium is a group 2 element majorly because it has 2 valence electrons. It is also in period 4 because it has 4 electron shells.
Being a group 2 element, calcium is a solid at room temperature and also reactive. All elements in the group 2 are metals.
There are other elements in period 4 which are not solid. For example krypton is an element in period 4 and it is a gas and not reactive.
From the above information, we can conclude that the correct answer to the question is:
Option C. Calcium, like all group 2 elements, is reactive and a solid at room temperature.
See attached image
Learn more: https://brainly.com/question/5979466
What is the mass in grams of 2.5 moles of Al?
Answer:
One mole of Al weighs 27g.
2.5 moles of Al weigh 67.5g.
What is the main function of the muscular system A. digestion B. breathing C.movement D. Eliminating
Answer:
C, Movement
Explanation:
the mass number of Fe is 56 . how many neutron are there in a single Fe atom
Answer:
30 neutrons
Explanation:
Since the mass of the iron nuclide is 56 , there must be 56−26=30 neutrons, 30 massive, neutral particles in this iron nucleus.
1. What step dogs every scientific experiment begin with?
A hypothesis
B. procedures
C conclusion
D. question/problem
Which are characteristics of all living things?
Order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.
What is the best way to organize desert several several million different types of organisms on earth
Answer:
The desert should be divided into different types based on its properties. The organisms living in specific type of desert should be named accordingly.
Explanation:
There are usually five major types of desert in the world. Tropical, rainy, semi arid desert, coastal desert and dry desert. There are many different types of organisms living in these deserts. The biodiversity has made it difficult for the humans to analyse and identify the millions of different types. The best way is to organize and name the organisms that live in specific types of deserts.
A. In a separatory funnel containing ethyl acetate and 10% aqueous sodium bicarbonate (NaHCO3), which layer would contain the brominated aromatic compound?
Answer:
ethyl acetate layer
Explanation:
This question tests your knowledge of the principle of solvent extraction.
In solvent extraction, there is always an organic layer and an aqueous layer. The ethyl acetate is the organic layer while the sodium bicarbonate is the aqueous layer.
A brominated aromatic compound will be extracted into the organic layer (ethyl acetate layer).
The water bottle contains 575 grams of water at 80°C. The water eventually cools to
40°C. How many calories of heat could be transferred to the student's back?
Answer:
–23000 Calories.
NOTE : The negative sign indicates that heat has been loss to the student back.
Explanation:
The following data were obtained from the question:
Mass (M) of water = 575 g
Initial temperature (T1) = 80 °C
Final temperature (T2) = 40 °C
Heat (Q) transferred =.?
Next, we shall determine the change in temperature (ΔT).
This is illustrated below:
Initial temperature (T1) = 80 °C
Final temperature (T2) = 40 °C
Change in temperature (ΔT) =?
Change in temperature (ΔT) = T2 – T1
Change in temperature (ΔT) = 40 – 80
Change in temperature (ΔT) = –40°C
Finally, we shall determine the heat transferred. This can be obtained as follow:
Mass (M) of water = 575 g
Change in temperature (ΔT) = –40°C
Specific heat capacity (C) of water = 1 Cal/g°C
Heat (Q) transferred =.?
Q = MCΔT
Q = 575 × 1 × –40
Q = –23000 Calories
NOTE : The negative sign indicates that heat has been loss to the student back.
BaCl2+Na3PO4-->NaCl+Ba3 (PO4)2If 3.54g of Ba3 (PO4)2are produce by the reaction given how many grams of the starting material BCl2 were used?a) 3.680 gb) 1.23 gc) 3.68 gd) 4.16 g
Answer:
1.23 g
Explanation:
Given that the mass of barium phosphate formed= 3.54 g
Molar mass of Ba3 (PO4)2 = 602 g/moles
Number of moles of Ba3 (PO4)2= 3.54g/602 g/moles = 0.0059 moles
Since 1 mole of BaCl2 forms 1 mole of Ba3 (PO4)2
Hence, 0.0059 moles of BaCl2 yields 0.0059 moles of Ba3 (PO4)2
Hence mass of BaCl2 reacted= mass × molar mass= 1.23 g
A 100.00-mL water sample was adjusted to pH 10 and titrated to the calmagite endpoint with 10.87 mL of 0.0125 M EDTA solution. Then the pH of another 100.00-mL water sample was adjusted to pH 12 and titrated with EDTA to the calcon endpoint. In this second titration, 2.63 mL of titrant was required. Calculate the concentration of Mg2 and Ca2 in the water. Express your answers in mg/L of CaCO3 and MgCO3, respectively.
Answer:
The mass of Ca²⁺ present in the water sample = 13.23 mg/L.
The mass for the Mg²⁺ in the water sample = 25.06 mg/L.
Explanation:
We are given the following set of values which are going to aid in solving this particular question/problem. Thus, the parameters or data or information is given below:
First part:
Total volume of the water sample = 100.00-mL water sample, volume of the EDTA solution = 10.87 mL, the concentration of the EDTA solution = 0.0125 M, the adjusted pH of the water sample with = 10.
Second part:
Total volume of the water sample = 100.00-mL water sample, volume of the EDTA solution = 2.63 mL and the adjusted pH of the water sample with = 12.
Thus, the first thing to do now is to determine the number of moles of the EDTA solution in Ca²⁺ titration which is; 0.0125 x 0.00263 = 3.30 x 10⁻⁵ moles.
The mass of Ca²⁺ present in the water sample = [3.30 x 10⁻⁵ moles × 40.08 ] ÷ 100 mL. = 13.23 mg/L
In 100mL, the number of moles of Mg²⁺ = (total number of moles of EDTA solution used ) - ( number of moles of the EDTA solution in Ca²⁺ titration).
Also, The number of moles of Mg²⁺ = ( 0.0125 x 0.01087) - (3.30 x 10⁻⁵ moles.) = 1.031 x 10⁻⁴ moles.
The mass for the Mg²⁺ in the water sample = 1.031 x 10⁻⁴ moles x 24.305/0.1 = 25.06 mg/L.
You are given an unknown mixture containing NaCl and NaHCO3. When you carry out the heating exactly as described in part A, only NaHCO3 decomposes. From the loss in mass, you can calculate the amount of NaHCO3 present in the mixture and its mass percent composition.
Here is your data. Incorporate it in your written procedure.
Experimental data Unknown (NaCl + NaHCO3)
Mass of crucible + cover 72.428 g
Mass of crucible + cover + mixture 74.80 g
Mass of crucible + cover + residue (1st heating) 74.25 g
Mass of crucible + cover + residue (2nd heating) 74.24 g
Mass of crucible + cover + residue (3rd heating) 74.24
From the data above, carry out your calculation for finding the mass of mixture, and mass of final solid remaining in the crucible. Using the knowledge that only loss of mass due to CO2 and H2O can be linked to the original mass of NaHCO3, calculate the mass of NaHCO3 and percent of NaHCO3 in the mixture.
Answer:
1.52g NaHCO3 were in the original mixture.
Mass percent: 64.1%
Explanation:
When NaHCO3 heats it descomposition occurs as follows:
2 NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g).
The loss in mass is because of the evaporization of CO2 and H2O. As both are in the same porportion, its molar mass is the sum of both compounds (44g/mol + 18g/mol = 62g/mol)
Loss in mass: 74.80g - 74.24g = 0.56g.
In moles:
0.56g * (1mol / 62g) = 0.00903 moles of gas.
As 1 mole of the gases comes from 2 moles of NaHCO3:
Moles NaHCO3:
0.00903 moles of gas * (2 moles NaHCO3 / 1 mole gas) = 0.018 moles NaHCO3.
In grams (Molar mass NaHCO3: 84g/mol):
0.018 moles NaHCO3 * (84g / mol) = 1.52g NaHCO3 were in the original mixture.
The mass of the mixture was:
74.80g - 72.428g = 2.372g
That means mass percent of NaHCO3 is:
(1.52g / 2.372g) * 100 = 64.1%
Identify the following reaction as an endothermic reaction, exothermic reaction, or both endothermic and exothermic:
Dissolving NH4Cl in water to make a cold pack.
Answer:
Endothermic reaction
Explanation:
Endothermic reactions are defined as the type of chemical reaction in which the system absorbs the energy from the surroundings and the temperature of the surrounding decreases while in Exothermic reactions, heat is released by the system to the surroundings and it makes the surrounding warm.
The given example is an "endothermic reaction" because the reaction between NH4Cl and water is making the surrounding cool (cold pack) due to the release of heat.
Hence, the correct answer is "endothermic reaction".
The three dots in the Lewis dot diagram for boron indicates that it. Please help
Answer:
valence electrons
Explanation:
it is outermost shell of electrons
The three dots in the Lewis dot diagram for boron indicates that it has three valence electrons.
The three dots in the Lewis dot diagram for boron indicates that it
can bond with three other atoms. NO. It can bond with less than 3 atoms by forming double or triple bonds.can only form triple covalent bonds. NO. It can also form single and double covalent bonds.has three valence electrons. YES. It has 3 electrons in the outermost electron shell.scores a 3 on Pauling's electronegativity scale. NO. The electronegativity of boron is 2.04.The three dots in the Lewis dot diagram for boron indicates that it has three valence electrons.
You can learn more about the Lewis dot structure here: https://brainly.com/question/20300458
Suppose the reaction Ca3(PO4)2 + 3H2SO4 → 3CaSO4 + 2H3PO4 is carried out starting with 149 g of Ca3(PO4)2 and 86.9 g of H2SO4. How much phosphoric acid will be produced?
Answer:
57.9 grams .
Explanation:
Ca₃(PO₄)₂ + 3H₂SO₄ → 3CaSO₄ + 2H₃PO₄
1 mole 3 moles 2 moles
149 g of Ca₃(PO₄)₂ = 149 / 310 = .48 moles
86.9 g of H₂SO₄ = 86.9 / 98 = .8867 moles
Here H₂SO₄ is the limiting reagent .
.8867 / 3 = .2955
.2955 moles of Ca₃(PO₄)₂ reacts with .8867 mole of H₂SO₄ to give
2 x .2955 moles of H₃PO₄
H₃PO₄ produced = 2 x .2955 moles
= .591 moles
= .591 x 98 = 57.9 grams .
Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20 J/K when mixed with 100g of pure Au
Answer:
[tex]m_{Ag}=2,265.9g[/tex]
Explanation:
Hello!
In this case, since the definition of entropy in a random mixture is:
[tex]\Delta S=-n_TR\Sigma[x_i*ln(x_i)][/tex]
For this silver-gold mixture we write:
[tex]\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )][/tex]
By knowing the moles of gold:
[tex]n_{Au}=100g*\frac{1mol}{197g} =0.508mol[/tex]
It is possible to write the aforementioned formula in terms of the variable [tex]x[/tex] representing the moles of silver:
[tex]20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )][/tex]
Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:
[tex]x=n_{Ag}=21.0molAg[/tex]
So the mass is:
[tex]m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g[/tex]
Best regards!
Which of the following best describes the structure of a carbohydrate?
a
Carbon ring(s)
b
Single or double helix
c
Hydrocarbon(s)
d
Globular or fibrous
Answer:
A
Explanation:
B- is dna related
C i dunno
and d is about protein so that leaves A
Nicotinic acid, HC6H4NO2, is a B vitamin. It is also a weak acid with Ka = 1.4 × 10-5. Calculate [H+] and the pH of a 0.041 M solution of HC6H4NO2.
Answer:
[H+] = 7.576x10⁻⁴M
pH = 3.12
Explanation:
Based on the equilibrium of the nicotinic acid in water:
HC6H4NO2(aq) + H2O(l) ⇄ C6H4NO2-(aq) + H3O+(aq)
Ka = [C6H4NO2-] [H3O+] / [HC6H4NO2]
As both C6H4NO2-(aq) and H3O+(aq) comes from the same equilibrium, we can approximate their concentration as X and replace:
Ka = [C6H4NO2-] [H3O+] / [HC6H4NO2]
1.4x10⁻⁵ = [X] [X] / [0.041M]
5.47x10⁻⁷ = X²
7.576x10⁻⁴M = X = [H+]And as pH is defined as -log [H⁺]
pH = 3.12Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is:
Al(s) + 3/2 Br2(l)AlBr3(s)
We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.
1) 2 AlBr3(s) 2 Al(s) + 3 Br2(l)
2) 2 Al(s) + 3 Br2(l) 2 AlBr3(s)
3) AlBr3(s) Al(s) + 3/2 Br2(l)
Answer:
Explanation:
Al(s) + 3/2 Br₂(l) = AlBr₃(s)
K = [ AlBr₃] / [ Al] [ Br₂]³/²
K² = [ AlBr₃]² / [ Al ] ² [ Br₂]³
2 AlBr₃ = 2 Al(s) + 3 Br₂(l) =
K₁ = [ Al ] ² [ Br₂]³ / [ AlBr₃]²
K₁ = ( 1 / K² ) = K⁻²
2 ) 2 Al(s) + 3 Br₂(l) = 2 AlBr₃(s)
K₂ = [ AlBr₃ ]² / [ Al ]² [ Br₂ ]³
K₂ = K²
3 )
AlBr₃(s) = Al(s) + 3/2 Br₂(l)
K₃ = [ Al ] [ Br₂ ] ³/² / [ AlBr₃ ]
= ( 1 / K ) = K⁻¹
Which of the following is one way creativity can help scientists?
By ensuring they follow the scientific method
By increasing the amount of time it takes to complete scientific experiments
By making sure they only try things that have already been proven
By leading them to ask more questions about the natural world
Answer:
Creativity can help scientists by leading them to ask more questions about the natural world.
Explanation:
Beacause they use creativity to make up questions about the natural world.
How many atoms of Carbon are found on the PRODUCTS side?
Which condition produces an anion?
A. more neutrons than electrons
B. more protons than electrons
C. more electrons than neutrons
D. more electrons than protons
Calculate the wavelength of light (in nm) of the spectral line of Hydrogen where an electron falls from the 6th Bohr orbit to the 3rd Bohr orbit.
a) 540 nm
b) 2000 nm
c) 1090 nm
d) 1050 nm
Answer:
The wavelength of light (in nm) of the spectral line of Hydrogen where an electron falls from the 6th Bohr orbit to the 3rd Bohr orbit is 1090nm
Explanation:
We know that , the wavelength of the light is calculated by Rydberg's formula-
[tex]\frac{1}{\pi} =R^2(\frac{1}{n^2_1} -\frac{1}{n^2_2})[/tex] [tex][n_2>n_1][/tex]
Here , R = Rydberg's constant [tex](1.097\times 10^7 m^-^1)[/tex]
Z = atomic number (for hydrogen , Z= 1)
[tex]n_2 =6 , n_1=3[/tex]
[tex]\pi =[/tex] wavelength of light
Now , putting the values in the Rydberg's formula ,
[tex]\frac{1}{\pi} =1.097\times10^7m^-^1(\frac{1}{3^2} -\frac{1}{6^2} )[/tex]
=[tex]1.097\times 10^7m^-^1 (\frac{4-1}{36} )[/tex]
=[tex]1.097\times 10^7m^-^1(\frac{3}{36} )[/tex]
=[tex]1.097\times 10^7m^-^1(\frac{1}{12} )[/tex]
[tex]\frac{1}{\pi}[/tex] = [tex]0.0914167\times 10^7m^-^1[/tex]
[tex]\pi=\frac{1}{0.0914167\times10^7m^-^1}[/tex]
[tex]\pi=10.9389\times10^-^7\\\pi=1093.89\times10^-^9m[/tex]
=1090nm
Hence , the wavelength of the light is 1090nm,, that is option D is correct.
the two stages of cellular respiration.
Which belongs in the area marked X?
Energy is released.
Oxygen is used up.
Glucose is broken down.
Carbon dioxide is used up.
Answer:
Oxygen is used up
Explanation:
Have an amazing day! And here is the attachment If you don't believe me. Brainliest would be nice.
All organelles that only plant cells have
Answer:
Cell wall, chloroplast, and vacuoles
Explanation:
The chemical formula for sumuric acid is H Son. In one molecule of sulfuric acid, there are____
A. two atoms of hellum
B. two atoms of oxygen
C. four atoms of oxygen
D. four atoms of sulfur oxide
Answer:
I want to say option C: four atoms of oxygen. Sorry if I'm wrong
