Does gravity increase or decrease with greater distance?

Answer:

Explanation:

When the person stands 5.80 ft from the mirror of the wall.

a) The first image is found by multiplying the distance of the left mirror to the person.

i.e.

2 × 5.80 = 11.6 ft

b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.

i.e.

(2 × 13.7 ) + 11.6

= 39 ft

c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.

(2 × 5.80) + 39

= 50.6 ft

Answer:

C. An external downward field is created or an external downward field is removed

Explanation:

As we can see that from the attached figure that the induced current would be counter clockwise. So the field occur because of induced current i.e. out of page. This represent that the current is induced in order to rise the flux out of the direction of the page

Therefore because of the external field, the field out of page & flux would be reducing or the external upward field is eliminated

So option C is correct

Answer:

72mph/sec

Explanation:

The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:

216mph / 3sec = 72mph/sec, our final answer

Hope it made sense. I would appreciate Brainliest, but no worries.

(a) The length of the pendulum is 3.96 m.

(b) The amplitude is 7.89 m.

(c) The frequency is 0.25 Hz.

(d) The maximum velocity is 12.38 m/s.

(e) The total energy is 9.67 J.

(f) The maximum height is 3.94 m.

The length of the pendulum at the given parameters is determined using the following formula.

[tex]T = 2\pi \sqrt{\frac{l}{gcos(\theta)} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{gcos(\theta)} }\\\\\frac{T^2}{4\pi ^2 } =\frac{l}{gcos(\theta)}\\\\l = \frac{gcos(\theta)T^2}{4\pi^2} \\\\l = \frac{(9.8)cos(5)\times (4)^2}{4\pi^2} \\\\l = 3.96 \ m[/tex]

The amplitude of the pendulum is calculated as follows;

mgLcosθ = ¹/₂FA

mgLcosθ = ¹/₂(mg)A

Lcosθ = ¹/₂A

A = 2Lcosθ

A = 2 x 3.96 x cos(5)

A = 7.89 m

[tex]\omega = \sqrt{\frac{g}{l} } \\\\\omega = \sqrt{\frac{9.8}{3.96} } \\\\\omega = 1.57 \ rad/s[/tex]

ω = 2πf

f = ω/2π

f = (1.57) / (2π)

f = 0.25 Hz

The maximum velocity is calculated as follows;

v = Aω

v = 7.89 x 1.57

v = 12.38 m/s

E = mgLcosθ

E = 0.25 x 9.8 x 3.96 x cos(5)

E = 9.67 J

h = Lcosθ

h = 3.96 x cos(5)

h = 3.94 m

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Answer:  H

the lights travel through the mirr to create a bigger wider light.

hope this helps (:

Answer:

sugar free

Explanation:

she should most likely take anything sugar free and avoid any bread, bread can increase your blood level as well, my mother had pre diabetes and what she did was eat salads and drink vegetable smoothies until your sugar goes down. splitting an entrée won't do anything, you technically get the same amount of sugar so at the point just eat the whole meal.

Answer:

Neither the source or wall is moving so the sound takes 3 sec to get to the wall and 3 sec to return

D = 3 * v = 330 m/s * 3 sec = 990 m

Answer:

41.7 Hz

Explanation:

Wavelength= velocity/frequency

or

frequency= velocity/Wavelength

f=500/12

f=41.6666

f=41.7 Hz

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Answer:

well its burning its callories so thats it technically

Explanation:

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bit.[tex]^{}[/tex]ly/3a8Nt8n

We have that the  is mathematically given as

Fn=36000N

Question Parameters:

mass of 2.0 x 10^3 kg

the radius of curvature is 24 m and

the roller coaster car has a tangential speed of 17 m/s

Generally the equation for the Force   is mathematically given as

F=ma

Fn-fg=mv^2/r

Fn=m(v^2/r+g)

Therefore

Fn=2000(12^2/18+9.8)

Fn=36000N

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Answer:

The beat frequency = 2.0 Hz

Explanation:

From the given information

The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.

i.e.

[tex]f_{3A} = 3f_A[/tex]

where;

[tex]f_A =[/tex] note A fundamental freq.

replacing 440 Hz for [tex]f_A[/tex]

[tex]f_{#a} = 3 (440 \ Hz)[/tex]

[tex]f_{3A} = 1320 Hz[/tex]

However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.

i.e.

[tex]f_{2E} = 2f_E[/tex]

[tex]f_E =[/tex]  note E fundamental freq.

replacing 659 Hz for [tex]f_E[/tex]

[tex]f_{2E} = 2(659)[/tex]

[tex]f_{2E} = 1318 \ Hz[/tex]

Finally, the beat frequency when the E string is properly tuned is:

[tex]\Delta f = f_{3A}-f_{2E}[/tex]

[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]

[tex]\Delta f = 2.0 \ Hz[/tex]

Thus, the beat frequency = 2.0 Hz

Answer:

Newton's third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects. However much you push your fork in the food, that much a dent it will cause.

Explanation:

Answer:

¡I hope it helps you! :) .................

Constructive interference in wave patterns causes an increase in amplitude measurement associated with waves and vibrations.

When two waves move in the same direction and are in phase with each other, their amplitudes are summed to produce the resultant wave.

The waves are considered to have suffered constructive interference in this case. Upward displacement occurs when waves experience constructive interference.

The medium's upward displacement is higher than the displacement of the two interfering pulses.

Hence option D is correct.

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position in a gravitation field (c)

Answer:

The answer is C. position in a gravity field

Answer:

D. A light wave can travel without a medium.

Explanation:

Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

On the other hand, mechanical waves such as sound are highly dependent on matter for their propagation and transmission.

This ultimately implies that, the properties which makes a light wave different from all mechanical waves is that, a light wave can travel without a medium of propagation.

Answer:

40 J

Explanation:

Gpe= mgh

=4*10*1

=40

Answer:

Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.

Explanation:

any pics? so i can see the question ⁉️

Answer:

λ = 396.7 nm

Explanation:

For this exercise we use the diffraction ratio of a grating

           d sin θ = m λ

in general the networks works in the first order m = 1

we can use trigonometry, remembering that in diffraction experiments the angles are small

           tan θ = y / L

           tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ

           sin θ = y / L

we substitute

          [tex]d \ \frac{y}{L}[/tex] = m λ

with the initial data we look for the distance between the lines

           d = [tex]\frac{m \lambda \ L}{y}[/tex]

           d = 1 656 10⁻⁹ 1.00 / 0.600

            d = 1.09 10⁻⁶ m

for the unknown lamp we look for the wavelength

           λ = d y / L m

           λ = 1.09 10⁻⁶ 0.364 / 1.00 1

           λ = 3.9676 10⁻⁷ m

           λ = 3.967 10⁻⁷ m

we reduce nm

           λ = 396.7 nm

Answer:

the average speed of the particles in terms of the speed of light is 0.81c

Explanation:

Given the data in the question;

[tex]t_p[/tex] = 256.2 ps = 256.2 × 10⁻¹² s

speed of light c = 2.99 × 10⁸ m/s

d = 10.7 cm = 0.107 m

we know that; Average speed v = d/t ------- let this be equation 1

Also, given that 256.2 ps is the lifetime of particle X frame, proper time will be;

t = Y[tex]t_p[/tex] = [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) --------- let this be equation 2

Next, we input equation 2 into equation 1'

v = d / [ [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] )  ]

v = d/[tex]t_p[/tex][ √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]

v[tex]t_p[/tex]/d = √( 1 - [tex]\frac{v^2}{c^2}[/tex] )

we square both sides

( v[tex]t_p[/tex]/d )² = (√( 1 - [tex]\frac{v^2}{c^2}[/tex] ) )²

v²[tex]t_p[/tex]²/d² = 1 - [tex]\frac{v^2}{c^2}[/tex]

v²[tex]t_p[/tex]²/d² +  [tex]\frac{v^2}{c^2}[/tex] = 1

v²( [tex]t_p[/tex]²/d² +  [tex]\frac{1}{c^2}[/tex] ) = 1

v²( ([tex]t_p[/tex]²c² + d²)/d²c² ) = 1

∴

v² = (d²c²) / ([tex]t_p[/tex]²c² + d²)

v = √[ (d²c²) / ([tex]t_p[/tex]²c² + d²) ]

v = (dc) / √([tex]t_p[/tex]²c² + d²)

so we substitute

v = (0.107 m × c) / √( (256.2 × 10⁻¹² s)²(2.99 × 10⁸ m/s)² + (0.107 m )²)

v = 0.107c / √( 0.00586814 + 0.011449 )

v = 0.107c / √( 0.01731714 )

v = 0.107c / 0.1315946

v = 0.81c

Therefore, the average speed of the particles in terms of the speed of light is 0.81c

Answer:

D. Freezing?

Explanation:

Get water, put it in the freezer, turns into ice after a few hours.

Answer:

[tex]\theta_c = 36.78^o[/tex]

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]

[tex]\theta_c = 36.78^o[/tex]

Answer:

Air exerts forces on falling objects near earth's surface

Explanation:

Falling objects are typically subject to air resistance which prevents the force of gravity on the object

Answer:

The ratio of the new volume to the old volume is 8 to 1.

Explanation:

Let's first list what we know:

Since the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.

The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.

Now, let's solve for the volume of the new cube:

[tex]V = s^3[/tex]

[tex]V = 8^3[/tex]

[tex]V = 512[/tex]

The volume of the new cube is 512 [tex]m^3[/tex].

The ratio of the new volume to the old volume is 512 : 64.

Let's simplify the ratio:

512 : 64

8 : 1

The ratio of the new volume to the old volume is 8 to 1.

P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)

The direction of the magnetic field in the center of the coil point towards the up. So, the correct option is D.

Right-hand grip rule states that, if you are holding a current carrying conductor with your right hand, such that the curled fingers point towards the direction of current flowing through the conductor, then the thumb will point towards the direction of the magnetic field.

Here,

From the current carrying conductor given,

The current is flowing through the conductor in a direction from left to right or it can be said as, the current is flowing in a clockwise direction.

So, we can apply the right-hand grip rule in this conductor.

According to the right-hand grip rule, stretch the thumb of the right hand and point it towards the direction of flow of current in the conductor. Then the remaining curled fingers will be pointed upwards in the conductor.

Hence,

The direction of the magnetic field in the center of the coil point towards the up.

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