Coulomb is the unit of which quantity?

Answers

Answer 1

Answer:

electric charge

Answer 2

Answer:

Electric charge.

Explanation:

Coulomb, unit of electric charge in the metre - kilogram - second - ampere system, the basis of the SI system of physical units. It is abbreviated as C. The coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.


Related Questions



PLEASE HELP!!!


Thunder is a sound wave created

by a lightning strike. If it travels at

343 m/s, how much time does it

take to travel a mile (1610 m)?

(Unit = s)

Answers

Answer:

t = 9.38 s

Explanation:

Given that,

The speed of the sound wave, v = 343 m/s

Distance, d = 1610 m

We need to find the time taken to travel a mile. The distance traveled by the sound is 2d. Using the formula for speed,

[tex]v=\dfrac{2d}{t}[/tex]

t is the time taken to travel a mile

So,

[tex]t=\dfrac{2d}{v}\\\\t=\dfrac{2\times 1610}{343}\\\\t=9.38\ s[/tex]

So, it will take 9.38 seconds.

Answer:

4.69s

Explanation:

The formula to find time is time = distance / velocity

Plug the numbers into the formula

So

1610 / 343

= 4.69s

A 70 ft rope hangs from a helicopter above this room. The rope has a mass per unit length of 2 lb/ft. In order to be rescued from this exam the helicopter must pull you up and out of the room to safety. Assume that you weigh 120 lbs. How much work will it take get you safely away from this test

Answers

Answer:

The work done to get you safely away from the test is  2.47 X 10⁴ J.

Explanation:

Given;

length of the rope, L = 70 ft

mass per unit length of the rope, μ = 2 lb/ft

your mass, W = 120 lbs

mass of the 70 ft rope  = 2 lb/ft x 70 ft

                                         = 140 lbs.

Total mass to be pulled to the helicopter, M = 120 lbs  + 140 lbs  

                                                                       = 260 lbs

The work done is calculated from work-energy theorem as follows;

W = Mgh

where;

g is acceleration due gravity = 32.17 ft/s²

h is height the total mass is raised = length of the rope = 70 ft

W = 260 Lb x 32.17 ft/s²  x 70 ft

W = 585494 lb.ft²/s²

1 lb.ft²/s² = 0.0421 J

W = 585494 lb.ft²/s²  = 2.47 X 10⁴ J.

Therefore, the work done to get you safely away from the test is  2.47 X 10⁴ J.

The gravitational strength at the poles is greater than the gravitational strength at the equator. What will happen to an object when it moves from the poles to the equator? Group of answer choices A. Its mass will increase. B. Its mass will decrease. C. Its weight will increase. D. Its weight will decrease.

Answers

Answer:

C

Explanation:

Because this same question was on my test last week and I got it correct

How to explain third law when a boat is moving away from a paddock when a women’s feet is on the paddock and the boat

Answers

Answer:

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When the man jumps from a boat, he applies force on the boat due to which boat moves backward. An equal force is exerted by the boat on the man which helps the man to jump out of the boat.

2 points
13. The law of conservation of mass can be demonstrated by a chemical
reaction. Which of the following models of a chemical reaction best
represents the law of conservation of mass?
A
C
B
D.
8
8.
a.
Ο Ο Ο Ο

Answers

Answer:

A

Explanation:

the mass in the option a is conserved of two elements

Identify equivalent terms for stored energy and energy of motion.
a. Stored energy is potential energy, and energy of motion is kinetic energy.
b. Energy of motion is potential energy, and stored energy is kinetic energy.
c. Stored energy is the potential as well as the kinetic energy of the system.
d. Energy of motion is the potential as well as the kinetic energy of the system.

Answers

Answer:

a. Stored energy is potential energy, and energy of motion is kinetic energy

Explanation:

The correct option is - a. Stored energy is potential energy, and energy of motion is kinetic energy.

Reason -

Potential energy is stored energy, whereas kinetic energy is the energy of moving things.

Kinetic energy is energy possessed by an object in motion.The energy associated with position is called potential energy .

Can you help me please here is the picture DUE NOW PLEASE.

Answers

they are formed when hot

it's dependent on the rate of cooling of the melt, slow cooling allows large crystals to form, fast cooling yields small crystals. They cool too quickly to form crystals.

Hope this helps! <3 :3


Which letter on the map represents the
Southern Ocean

Answers

Answer:

B cus is in the south but that pfp tho

I need help with 6 and 7 please help?

Answers

Answer:

6-a .   7-c

Explanation:

6-a and 7-c I think that’s the answer

10. A 50 kg bicyclist on a 10 kg bicycle speeds up from 5.0 m/s to 10 m/s.
(a) What was the total kinetic energy before accelerating? Full working out​

Answers

Answer:

T.K.E = 750 Joules.

Explanation:

Given the following data;

Initial velocity, u = 5m/s

Final velocity, v = 10m/s

Mass of bicyclist = 50kg

Mass of bicycle = 10kg

Total mass, Tm = 50 + 10 = 60kg

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}mv^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

m represents mass measured in kilograms.

v represents velocity measured in metres per seconds square.

To find the total kinetic energy before accelerating simply means the kinetic energy due to the initial velocity and total mass;

[tex] T.K.E = \frac{1}{2}T_{m}U^{2}[/tex]

Substituting into the equation, we have;

[tex] T.K.E = \frac{1}{2}*60*5^{2}[/tex]

[tex] T.K.E = 30*25 [/tex]

T.K.E = 750 Joules.

Which phrase best completes the diagram?

Role of the Federal Reserve in the U.S. economy:

Sets interest rates➡️?➡️Loans money to other banks

A. Approves the federal budget.
B. Votes on coporate regulations.
C. Sets the consumer price index.
D. Makes rules for other banks.

Correct answer is:

D. Makes rules for other banks.​

Answers

Answer:

B

Explanation:

i think

Answer:

D. makes rules for other banks

Explanation:


Maurice is playing some of the arcades at the county fair. At one booth he throws a 1.2-kg ball forward with a velocity of 15 m/s and hits a 0.5-kg can
at rest. The ball continues forward at 9 m/s. What is the new velocity of the can, in m/s? (Round your answer to one decimal place if necessary.)

Answers

Answer:

9.6

Hope this helps.

A barrel contains 285 kg of water.
What is the volume of the water?
(Unit = m^3)

Answers

Answer:

285 Litre ( 1kg of water occupies 1 Litre )

which is identical to 285 dm^3 ie 285 cubes of length 10 cm

and as there are 10 of these linearly in 1 m then there are 10^3 = 1000 dm^3 in each m^3

giving a volume of 0.285 m^3

Of course if you KNEW that 1m^3 of water has a mass of 1000 kg then you would simply have said that the volume was 285/1000 m^3

The volume of the water will be  0.285 [tex]m^{3}[/tex]

What is volume ?

A volume is simply defined as the amount of space occupied by any three-dimensional solid. These solids can be a cube, a cuboid, a cone, a cylinder or a sphere. Different shapes have different volumes. Volume is the measure of the capacity that an object holds.

A method in which the value of the unit (one) quantity is first obtained to find the value of any required quantity is called the unitary method. So , by finding the value volume of 1 kg water , we can find the volume of 285 kg water by simply multiplying it with the volume of 1kg water using unitary method

using unitary method

1000 kg of mass have volume of = 1[tex]m^{3}[/tex]

then , the volume of 1kg  will be = 1 / 1000  [tex]m^{3}[/tex]  

The volume of 285 kg will be =  (1 / 1000) * 285 = 0.285 [tex]m^{3}[/tex]

Hence if a barrel contains 285 kg of water, then the volume of the water will be  0.285 [tex]m^{3}[/tex]

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1. An astronaut is getting ready to explore. If his mass is 60 kg, what is his weight
on Earth?

Answers

60*2.2=132lbs ...........

In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal different information. You will use the both momentum principle and the energy principle in this problem.
A satellite of mass 3500 kg orbits the Earth in a circular orbit of radius of 7.3 106 m (this is above the Earth's atmosphere).The mass of the Earth is 6.0 1024 kg.
What is the magnitude of the gravitational force on the satellite due to the earth?
F= ________N
Using the momentum principle, find the speed of the satellite in orbit. (HINT: Think about the components of (dp^^\->)\/(dt) parallel and perpendicular to p^^\->.)
v = ________ m/s
Using the energy principle, find the minimum amount of work needed to move the satellite from this orbit to a location very far away from the Earth. (You can think of this energy as being supplied by work due to something outside of the system of the Earth and the satellite.)
work= ________J

Answers

Answer:

A) F_g = 26284.48 N

B) v = 7404.18 m/s

C) E = 19.19 × 10^(10) J

Explanation:

We are given;

Mass of satellite; m = 3500 kg

Mass of the earth; M = 6 x 10²⁴ Kg

Earth circular orbit radius; R = 7.3 x 10⁶ m

A) Formula for the gravitational force is;

F_g = GmM/r²

Where G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Plugging in the relevant values, we have;

F_g = (6.67 × 10^(-11) × 3500 × 6 x 10²⁴)/(7.3 x 10⁶)²

F_g = 26284.48 N

B) From the momentum principle, we have that the gravitational force is equal to the centripetal force.

Thus;

GmM/r² = mv²/r

Making v th subject, we have;

v = √(GM/r)

Plugging in the relevant values;

v = √(6.67 × 10^(-11) × 6 x 10²⁴)/(7.3 x 10⁶))

v = 7404.18 m/s

C) From the energy principle, the minimum amount of work is given by;

E = (GmM/r) - ½mv²

Plugging in the relevant values;

E = [(6.67 × 10^(-11) × 3500 × 6 × 10²⁴)/(7.3 x 10⁶)] - (½ × 3500 × 7404.18)

E = 19.19 × 10^(10) J

The force of friction depends upon​

Answers

Answer:

ask internet?

Explanation:

easy .....

..

Friction depends partly on the smoothness of the contacting surfaces, a greater force being needed to move two surfaces past one another if they are rough than if they are smooth.
Therefore, friction depends on the smoothness or roughness of the two surfaces which are in contact.

A sound having a frequency of 299 Hz travels through air at 332 m/s.
What is the wavelength of the sound? Answer in units of m.

Answers

Answer:

1.11 m.

Explanation:

Why?

The speed for a wave is done by the equation:   v = f * w. Because the frecuency tells us about how many cycles the wave makes each time, but for each cycle the wave runs certain distance, given for the wavelenght. If you isolate the letter w you get the value just doing a ratio.

v = speed

f = frecuency

w = wavelenght

w = v / f

A car starting from rest is accelerated uniformly to a velocity of 100.8km/h. Convert this to metre per secondphy​

Answers

Explanation:

100.8 km/h × (1000 m/km) × (1 h / 3600 s) = 28 m/s

Answer:

28 m/s

Explanation:

100.8km/hr * 1hr/3600sec* 1000m/km= 100.8*1000/3600 m/s

[1 mark]
29. A ball rolls at a constant speed of 3.0 m/s for 8.0 seconds. How far does it roll in this time!
A. 2.7 m
B. 3.0 m
C. 8.0 m
D. 24.0 m

Please help me

Answers

Answer:

D. 24.0m

Explanation:

formula

S=d/t

s=speed

d=distance

t=time

s=3.0m/s

d=x

t=8.0s

s=d/t

d=s*t

d=3.0*8.0

d=24.0m

s=? u=3 a=0 t=8

S=ut+1/2a(t^2)
s=3(8) + 0
s=24m

Answer is D)24m

Rank the following circuits in order from highest to lowest values of the current in the circuit.

i. a 1.4-Ω resistor connected to a 1.5-V battery that has an internal resistance of 0.10 Ω;
ii. a 1.8-Ω resistor connected to a 4.0-V battery that has a terminal voltage of 3.6 V but an unknown internal resistance;
iii. an unknown resistor connected to a 12.0-V battery that has an internal resistance of 0.20 Ω and a terminal voltage of 11.0 V.

a. (i), (iii), (ii)
b. (iii), (i), (ii)
c. (ii), (iii), (i)
d. (i), (ii), (iii)
e. (iii), (ii), (i)
f. (ii), (i), (iii)

Answers

Answer:

e)

Explanation:

Let's get first the values of the currents for the three cases.

i)

The battery forms a series circuit with its internal resistance and the 1.4 Ω resistor. Since the current is the same at any point of the circuit, and the sum of all voltages along a closed circuit must be zero, we can apply Ohm's Law in each resistor, as follows:

        [tex]V = I*r_{i} + I*R_{1} (1)[/tex]

Replacing V, ri and R₁ by their values, we can solve for the current I as follows:

      [tex]I_{i} = \frac{V}{r_{int} + R_{i}} = \frac{1.5V}{0.1 \Omega + 1.4 \Omega} = 1.0 A (2)[/tex]

ii)

Since the voltage of the battery is 4.0 V (open circuit voltage), and it falls to 3.6 V when is connected to a 1.8Ω resistor, this means that the voltage through the resistor must be 3.6 V, due to the sum of all voltages along a closed circuit must be zero.So, we can find the current through the circuit, applying Ohm's Law to the 1.8Ω resistor, as follows:

       [tex]I_{ii} =\frac{V_{term} }{R_{ii} } =\frac{3.6V}{1.8 \Omega} = 2.0 A (3)[/tex]

iii)

Since the 12.0 V battery has a terminal voltage of 11.0 , this means that the voltage through the internal resistance of 0.2 Ω, must be 1.0 V.So we can find the current Iiii, applying Ohm's Law to the internal resistance value, as follows:

      [tex]I_{iii} =\frac{V-V_{term}}{r_{int} } =\frac{12.0 V- 11.0 V}{0.2 \Omega} =\frac{1.0V}{0.2\Omega} = 5.0 A (4)[/tex]

So, the highest current is the Iiii, followed by Iii and Ii, which is stated by e).

the moon's mass is ____?

Answers

Answer:

i hope this is helpful

Explanation:

7.34767309 × 1022 kilograms

Answer:

Hellooo

7.35 x 1022 kg

The moon's mass is 7.35 x 1022 kg, about 1.2 percent of Earth's mass. Put another way, Earth weighs 81 times more than the moon.

Explanation:

thanks

A cylindrical tank with radius 3 m is being filled with water at a rate of 2 m3/min. How fast is the height of the water increasing (in m/min)

Answers

Answer:

.0707 m / min

Explanation:

The computation is shown below:

= Flow of the volume ÷ crossectional area

A = π × r^2

= 9 π

= 28.27 m^2

so, the fast of the height of the water rise is

=(2 m^3 / min) ÷ 28.27 m^2

= .0707 m / min

Rupert is investigating the properties of a light (effectively massless) spring. He has attached one end of the spring to a fixed horizontal rod and allowed the spring to hang vertically. The free end of the spring has a small hook to which Rupert can attach various masses. An Experiment to Determine the Spring Constant Part A Rupert finds that if he attaches a 470.0 gram mass to the hook, and then very slowly lowers the mass with his hand until the force on the mass by the spring is as large as the weight of the mass, that the spring stretches by 36.0 cm . What is the spring constant of Rupert's spring

Answers

Answer:

Explanation:

For equilibrium ,

weight of mass 470 gram = restoring force in spring

If x be extension in spring and k be spring constant

restoring force = kx

weight of mass = kx

.47 x 9.8 = k x .36

k = 12.8 N /m.

A water park has a slide that finishes with the rider flying horizontally of the bottom of the slide. The slide is designed to end 1.5 m above the water level, and the average rider is estimated to leave the bottom of the slide at 25 m/s. How far Horizontally will the rider travel from the bottom of the slide before hitting the water?

Answers

Answer:

25 m/s * √(1.5 m/g) ≈ 9.78 m

Explanation:

When effects of air resistance is neglected, the motion can be modeled as

x(t) =  25 m/s * t

y(t) = 1.5 m - g * t²

based on a coordinate system where the x axis is on the water level (modeled as a plane), y axis being parallel to the gravitational force and the point of origin sitting at the point on the water surface directly below the exit of the slide. The x value is the horizontal travel we’re interested in. Time t begins at the exit of the slide by this rider. g is the gravitational acceleration.

At the time when the rider hits water, we know y = 0.

0 = 1.5 m - g * t² ⇔ t = ±√(1.5 m/g)

Since we are only interested in the non-negative (not past) time range, it’s t = √(1.5 m/g)

The horizontal travel is thus:

x(√(1.5 m/g)) = 25 m/s * √(1.5 m/g) ≈ 25 * √(1.5/9.81) m ≈ 9.78 m

studyhero A violin string has a length, from the bridge to the end of the fingerboard, of 50 cm. That section of the string has a mass of only 2 g. When the violinist plays an open string (the full length) a 440 Hz A-note is heard. Determine the length of the string needed to play a 528 Hz note without adjusting the tension in the string. This is accomplished by pressing on the fingerboard at the appropriate location.

Answers

Answer:

= 0.517 m

Explanation:

This is a resonance exercise where the ends of the string are fixed, therefore it has a node of them, the fundamental (longest) wavelength created has the form

                λ = 2L

wave speed is related to wavelength and frequency

               v = λ f

               v = 2L f

let's calculate

                v = 2 0.50 440

                v = 440 m / s

since they indicate that the tension of the string does not change and the linear density of the string is constant, the speed of the wave also remains constant

               f =[tex]\frac{v}{2L}[/tex]

let's find the length for the new resonance frequency

               L = [tex]\ \frac{v}{2f}[/tex]

let's calculate

               L = [tex]\frac{440}{2 \ 528}[/tex]

               L = 0.5166 m

27. The electric field around a positive charge is shown in the diagram. Describe the nature of these lines. Please use 2 content related sentences

Answers

Answer:

Once we place a positive test at a point close to the sphere, we find that an electrostatic force is applied to the outside of the sphere. Therefore, at any point around the sphere, the electric field vector is radially outward.

A child swings with a small amplitude on a playground with a 2.5m long chain.
a) what is the period of the child’s motion
b) what is the frequency of vibration

Answers

a) T=2*pi(L/g)^1/2
T=2*3.14(2.5/9.81)^1/2
T=3.171s
b) T=1/f
f=1/3.171
f=0.315Hz

a. The period of the child's motion is 3.171 seconds.

b. The frequency of the vibration is 0.315 Hz.

Calculation of the period & frequency:

Since A child swings with a small amplitude on a playground with a 2.5m long chain.

a. So here the time period should be

[tex]2\times \ pi(L/g)^{1/2}\\\\2\times 3.14(2.5/9.81)^{1/2}[/tex]

T=3.171s

b) Now the frequency is

[tex]T=1\div f\\\\f=1\div 3.171[/tex]

f=0.315Hz

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Evidence supporting the humanistic perspective is easily measured. True or false?

Answers

Answer:

False

Explanation:

I believe it's false.

Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.

What is an Evidence?

Evidence is defined as an object or information introduced to make the existence of a fact more or less probable that of testimony, document, photograph, video, voice recording, DNA test, or other tangible objects. can take form.

Evidence is used to prove an argument made by individuals or groups that believe something is true or a fact that can be used to refute or disprove a fact or argument that people disagree with, or considered false.

Thus, Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.

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what is agrculture and it means​

Answers

Answer:

Agriculture is the science, the practice of cultivating the soil, art, producing crops, raising livestock, and in varying degrees the preparation and marketing of the resulting products cleared the land to use for agriculture.

Explanation:

This is what I found during my research and I hope this helps. Correct me if I am incorrect! Have a good one.

≧◉◡◉≦

g The international space station has an orbital period of 93 minutes at an altitude (above Earth's surface) of 410 km. A geosynchronous satellite has an orbital period of 24 hours. The radius of Earth is 6400 km. Use Kepler's 3rd Law to compare these two and find the orbital altitude of the geosynchronous satellite.

Answers

Answer:

r = 4.21 10⁷ m

Explanation:

Kepler's third law It is an application of Newton's second law where the forces of the gravitational force, obtaining

            T² = ([tex]\frac{4\pi }{G M_s}[/tex] ) r³             (1)

           

in this case the period of the season is

            T₁ = 93 min (60 s / 1 min) = 5580 s

            r₁ = 410 + 6370 = 6780 km

            r₁ = 6.780 10⁶ m

for the satellite

           T₂ = 24 h (3600 s / 1h) = 86 400 s

if we substitute in equation 1

            T² = K r³

            K = T₁²/r₁³

            K = [tex]\frac{ 5580^2}{ (6.780 10^6)^2}[/tex]

            K = 9.99 10⁻¹⁴ s² / m³

we can replace the satellite values

            r³ = T² / K

            r³ = 86400² / 9.99 10⁻¹⁴

            r = ∛(7.4724 10²²)

            r = 4.21 10⁷ m

this distance is from the center of the earth

The orbital altitude of the geosynchronous satellite is mathematically given as

r = 4.21 10⁷ m

What is the orbital altitude of the geosynchronous satellite?

Question Parameters:

Generally, the equation for the Gravitational force   is mathematically given as

 T^2 =[tex]\frac{4\pi }{G M_s} * r^3[/tex]

Therefore

K = T₁^2/r₁^3

K = \frac{ 5580^2}{ (6.780 10^6)^2}

K = 9.99 10^{-14} s^2 / m^3

Since

r^3 = T^2 / K

r^3 = 86400² / 9.99 10^{-14}          

r = 4.21 10⁷ m

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