Answer:
due to the presence of fee electrons.
Explanation:
these electrons conduct electric current.
Conductivity in metallic solids is due to the presence of free electron. No of the electron will decide the flow of the electric current.
What is the charge?When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.
Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term “neutral” refers to an item that has no net charge.
A valence electron is an electron in the outermost shell. Hence, associated with an atom that can experience the innovation of a chemical bond if the outer shell is not closed.
Conductivity in metallic solids is due to the presence of free electron.
Hence, electron is the correct answer for blank.
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Two simple pendulum of slightly different length , are set off oscillating in step is a time of 20s has elasped , during which time the longer pendulum has completed exactly 10 oscillations .Find the length of each pendulum.
Answer:
Length of longer pendulum = 99.3 cm
Length of shorter pendulum = 82.2 cm
Explanation:
Since the longer pendulum undergoes 10 oscillations in 20 s, its period T = 20 s/10 = 2 s.
From T = 2π√(l/g), the length of the pendulum. l = T²g/4π²
substituting T = 2s and g = 9.8 m/s² we have
l = T²g/4π²
= (2 s)² × 9.8 m/s² ÷ 4π²
= 39.2 m ÷ 4π²
= 0.993 m
= 99.3 cm
Now, for the shorter pendulum to be in step with the longer pendulum, it must have completed some oscillations more than the longer pendulum. Let x be the number of oscillations more in t = 20 s. Let n₁ = number of oscillations of longer pendulum and n₂ = number of oscillations of longer pendulum.
So, n₂ = n₁ + x. Also n₁ = t/T₁ and n₂ = t/T₂ where T₂ = period of shorter pendulum.
t/T₂ = t/T₁ + x
1/T₂ = 1/T₁ + x (1)
Also, the T₂ = t/n₂ = t/(n₁ + x) (2)
From (1) T₂ = T₁/(T₁ + x) (3)
equating (2) and (3) we have
t/(n₁ + x) = T₁/(T₁ + x)
substituting t = 20 s and n₁ = 10 and T₁ = 2s, we have
20 s/(10 + x) = 2/(2 + x)
10/(10 + x) = 1/(2 + x)
(10 + x)/10 = (2 + x)
(10 + x) = 10(2 + x)
10 + x = 20 + 10x
collecting like terms
10x - x = 20 - 10
9x = 10
x = 10/9
x = 1.11
x ≅ 1 oscillation
substituting x into (2)
T₂ = t/n₂ = t/(n₁ + x)
= 20/(10 + 1)
= 20/11
= 1.82 s
Since length l = T²g/4π²
substituting T = 1.82 s and g = 9.8 m/s² we have
l = T²g/4π²
= (1.82 s)² × 9.8 m/s² ÷ 4π²
= 32.46 m ÷ 4π²
= 0.822 m
= 82.2 cm
how many seconds are there in the month of March
Answer:
2,678,400
Explanation:
31 days in March
1 minute has 60 seconds
1 hour has 3600 seconds
24 hours in one day
24 hours has 1440 seconds
24hour have 86,400sec
31×86,400=2,678,400 sec
4) Un péndulo tiene un período de oscilación de 4 seg (T) , realizando su
movimiento desde su posición de equilibrio, si la aplitud del movimiento es de
10 cm y el ángulo de desfase es de 20 grados. Calcular:
La posición en la que se encuentra a los 5 segundos de haber iniciado el
movimiento.
Answer:
x = 1.43 cm
Explanation:
The horizontal displacement of the pendulum can be found using the following equation:
[tex] x(t) = x_{0}*sin(\omega*t + \phi) [/tex]
Where:
x₀: is the initial horizontal displacement = 10 cm
ω: is the angular frequency
t: is the time = 5 s
Φ: is the phase shift = 20° = 20*2π/360 = 0.35 rad
The angular frequency can be calculated using the oscillation perid (T):
[tex] \omega = \frac{2\pi}{T} = \frac{2\pi}{4 s} = 1.57 rad/s [/tex]
The horizontal displacement is:
[tex] x(t) = x_{0}*sin(\omega*t + \phi) = 10 cm*sin(1.57 rad/s*5 s + 0.35 rad) = 1.43 cm [/tex]
Therefore, the displacement of the pendulum at 5 s is 1.43 cm.
I hope it helps you!
An open-pipe resonator has a length of 2.39 m. Calculate the frequency of its third harmonic if the speed of sound is 343 m/s.
80 Hz
115.7 Hz
215.27 Hz
100.1 Hz
Answer:
f = 215.27 Hz
Explanation:
We have,
An open-pipe resonator has a length of 2.39 m.
It is required to find the frequency of its third harmonic if the speed of sound is 343 m/s.
For third harmonic, its length is equal to, [tex]l=\dfrac{3\lambda}{2}[/tex]
So,
[tex]\dfrac{3v}{2f}=2.39[/tex]
f is frequency in its third harmonics
[tex]f=\dfrac{3v}{2\times 2.39}\\\\f=\dfrac{3\times 343}{2\times 2.39}\\\\f=215.27\ Hz[/tex]
So, the frequency of its third harmonic is 215.27 Hz.
Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends toward the normal.
Which statement best describes Cleo’s mistake?
A. Light travels through air and water in angled, scattered paths.
B. Light does not change direction when it moves from air into water.
C. Light slows down when it moves from air into water.
D. Light bends away from the normal when it moves from air into water.
Answer:
light bends away from the normal when it moves from air into water-refraction
Answer: C.) Light slows down when it moves from air into water.
Explanation: i hope this helps :)
20. Threshold braking in the vehicle's braking system
occurs when
a. the brake pedal is pushed, heel on floorboard,
with full foot pressure.
b. the brakes are exerting full braking power,
without traction loss.
C. the driver begins pushing down the brake pedal,
with moderate slowdown.
d. the brakes just begin to take hold with a gradual
slowdown.
a wheel at rest gains an angular momentum of 10.7kgm²/s in 8s. if the moment if inertia of the wheel is 2.2kgm², how many revolutions will be made before the wheel attains an angular velocity of 30rad/s
Answer:
Revolutions made before attaining angular velocity of 30 rad/s:
θ = 3.92 revolutions
Explanation:
Given that:
L(final) = 10.7 kgm²/s
L(initial) = 0
time = 8s
Find Torque:Torque is the rate of change of angular momentum:
[tex]T = \frac{L(final)-L(initial)}{t}\\T = \frac{10.7-0}{8}\\T=1.34 Nm[/tex]
Find Angular Acceleration:We know that
T = Iα
α = T/I
where I = moment of inertia = 2.2kgm²
α = 1.34/2.2
α = 0.61 rad/s²
Find Time 't'
We know that angular equation of motion is:
ω²(final) = ω²(initial) +2αθ
(30 rad/s)² = 0 + 2(0.61 rad/s²)θ
θ = (30 rad/s)²/ 2(0.61 rad/s²)
θ = 24.6 radians
Convert it into revolutions:
θ = 24.6/ 2π
θ = 3.92 revolutions
The diagrams at the right show the path of light as it passes from air into the three solids. What are the possibilities of the solids in A, B and C? Explain.
Answer:
when light falls on denser medium it may be reflected back or enters the medium and if it enters the medium it refracts towards the normal line of the medium.
who proposed the big bang theory
Answer:
is it George Lemaitre?
Explanation:
sorry if i'm not helpful
which temperature is warmer than the freezing point of water
A. 0 F
B. 0 k
C. 1 C
D. 33 K
Answer:
1°C
Explanation:
Water freezes at 0°C, 32°F, and 273°K.
The only temperature warmer than the freezing point is 1°C.
Answer:
A. 0 F
Explanation:
Test approved
A 5000N block is lifted 1000cm. How much work was done?
Answer:
W(mg) = -5000j
Explanation:
Work done by weight force is = - mgh ==>mg = w & 1000cm = 1m ==> -5000 (1)= -5000j
it is what I can calculate for this question
Which statements apply to transverse waves? Check all that apply.
The question is incomplete as it does not have the options which are:
The waves have a trough.
Particles move only small distances.
particles travel the length of the wave, moving in an up-and-down motion.
The waves have a crest.
The energy is transferred perpendicular to the direction of the wave motion.
Answer:
The waves have a trough. Particles move only small distances. The waves have a crest. The energy is transferred perpendicular to the direction of the wave motion.Explanation:
Transverse waves are the waves which can be characterised easily by their oscillation in a perpendicular direction to the path of the wave propagation.
The particle follows the wave nature and moves only to a small distance like ripples in the water and these waves possess the trough, the lower part and the crest the upper part.
These waves can be observed in ripples of the water, in a string of the guitar while playing and the electromagnetic waves.
Thus, the selected options are correct.
a spring is compressed by 0.02m. Calculate the energy stored in the spring if the force constant is 400Nm-1
Answer:
0.08 J
Explanation:
EE = ½ kx²
EE = ½ (400 N/m) (0.02 m)²
EE = 0.08 J
The energy stored in the spring, if the force constant is 400N/m is 0.08 J.
What is spring potential energy?When the spring is compressed, it gets compressed up to its elastic limit. When load is removed from the spring, it regains its shape and obtains equilibrium position. The energy stored in this process is called as spring potential energy.
Given a spring is compressed by 0.02m. The force constant is 400N/m. The energy stored in the spring is given by
SPE = ½ kx²
SPE = ½ (400 N/m) (0.02 m)²
SPE = 0.08 J
Thus, the energy stored in the spring is 0.08 J.
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How does rubbing one object on another create static electricity?
O A. The friction from rubbing creates electrons as a by-product of the
heat.
B. Rubbing removes all electrons from one object.
C. Rubbing causes charging by induction to occur.
u
D. The rubbing moves electrons to the object that holds them more
tightly.
Answer: I think the answer to this question is D.The rubbing moves electrons to the object that holds them more tightly
Explanation:
When one object is rubbed against another, static electricity can be created. This is because the rubbing creates a negative charge that is carried by electrons. ... Similarly, when you rub a balloon on your head it causes opposite static charges to build up both on your hair and the balloon
How much would it cost to operate five incandescent light bulbs for the months of April and May, collectively, given that each bulb is one hundred and fifty Watts, electricity for home use is 0.3AED per kilowatt-hour, and that the light s will be on for three hours per day during this two month period.
please i need an answer fast or my teacher will kill me
Answer:
Total Cost is 41.18 AED
Explanation:
Per day number of hours light bulbs were on=3hours
5 bulbs power consumption = 150Wx5 = 750W
Electricity usage per day = 750 x 3 = 2250Wh = 2.25kWh
April has 30 days and May has 31 days. Therefore totals days = 61days
Total power consumption = 2.25x 61 = 137.25kWh
Total Cost = 137.25x 0.30 = 41.175 AED
in which electric circuit would the voltmeter read 10 volts ?
Given that,
Voltage = 10 volt
Suppose, The three resistance is connected in parallel and each resistance is 12 Ω. find the current in the electric circuit.
We need to calculate the equivalent resistance
Using formula of parallel
[tex]\dfrac{1}{R}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}[/tex]
Put the value into the formula
[tex]\dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}[/tex]
[tex]\dfrac{1}{R}=\dfrac{1}{4}[/tex]
[tex]R=4\ \Omega[/tex]
We need to calculate the current in the circuit
Using ohm's law
[tex]V=IR[/tex]
[tex]I=\dfrac{V}{R}[/tex]
Where, V = voltage
R = resistance
Put the value into the formula
[tex]I=\dfrac{10}{4}[/tex]
[tex]I=2.5\ A[/tex]
Hence, The current in the circuit is 2.5 A
what is the process where dna can change in many ways?
Answer:
process of recombination
Explanation:
this process happens when 2 molecules of DNA exchange pieces of their genetic material with each other
A farm would feel hotter on a sunny summer day than New York City.
True
False
false
hope this help
lf I'm write can you give me a brainlist please
A dog walks 14 meters to the west and then 20 meters back
to the east.
Answer 34
Explanation:
Answer:
The dog moved 6 meters west and 34 meters total
Explanation:
The nucleus of a hydrogen atom is a single proton, which has a radius of about 1.2 × 10-15 m. The single electron in a hydrogen atom orbits the nucleus at a distance of 5.3 × 10-11 m. What is the ratio of the density of the hydrogen nucleus to the density of the complete hydrogen atom?
Answer: 0.86 × 10^14
Explanation:
Given the following :
Radius of proton = 1.2 × 10-15 m
Radius of hydrogen atom = 5.3 × 10-11 m
Density of proton could be calculated thus:
Mass of proton = 1.67 × 10^-27 kg
Using the formula :
(4/3) × pi × r^3
(4/3) × 3.142 × (1.2 × 10^-15)^3 = 7.24 × 10^-45
Density = mass / volume
Density = (1.67 × 10^-27) / ( 7.24 × 10^-45)
= 0.2306 × 10^18
Density of hydrogen atom:
Mass of hydrogen atom= 1.67 × 10^-27 kg
Using the formula :
(4/3) × pi × r^3
(4/3) × 3.142 × (5.3 × 10^-11)^3 = 6.24 × 10^-31
Density = mass / volume
Density = (1.67 × 10^-27) / ( 6.24 × 10^-31)
= 0.2676 × 10^4
Ratio is thus:
Density of proton / density of hydrogen atom
0.2306 × 10^18 / 0.2676 × 10^4 = 0.8617 × 10^14
Which situation involves an object that can be considered to be in free fall?
A) a bungee jumper just before reaching the bottom of a jump.
B) a ball at the top of its motion after being thrown straight up in the air.
C) a helicopter that is hovering above a freeway. D) a meteor traveling through the atmosphere
Answer:
B: Only the ball experiences no resistive force to its state of motion.
If a t-shirt gun can fire t-shirts with an initial speed of 15 m/s, what is the maximum distance (along horizontal, flat ground) a t-shirt can be fired?
Answer:
h = 11.47 m
Explanation:
Initial speed pf the t-shirt gun is 15 m/s
We need to find the maximum distance covered by the t-shirt. It is based on the conservation of energy. The maximum distance covered is given by :
[tex]h=\dfrac{u^2}{2g}\\\\h=\dfrac{(15)^2}{2\times 9.8}\\\\h=11.47\ m[/tex]
So, it will cover a distance of 11.47 m.
Which of the following statements is INCORRECT based on our Ray Model of Light?
Select one or more:
a. Light moves in a circular motion and diffracts when it encounters an obstacle, which is why shadows exist.
b. The ray of light approaching a mirror is the incident ray, and the ray of light that leaves a mirror is the reflected ray.
c. In order to view an object, light rays from that object must enter your eye.
d. The distance from all plane mirrors to any object is equal to the distance from the mirror to the image.
Answer:
a and c
Explanation:
a)light moves in a straight line and distracts when it encounters an obstacle forming a shadow
c)the light rays from that object or also tgose from the image must enter your eye for you to see that image
Suponiendo que la Tierra describe una órbita circular alrededor del Sol, calcula su velocidad de traslación. Dato: la distancia media de la Tierra al Sol es 149 600 000.
Answer:
v = 51.60 m/s
Explanation:
To calculate the velocity of the Earth around the sun you use the following formula, which comes from the universal gravitational Law:
[tex]v=\sqrt{\frac{GM_E}{r}}[/tex]
M_E: Earth's mass = 5.97*10^24 kg
r: distance between the Sun and the Earth = 149 600 000 km =m
G: Cavendish's constant = 6.674×10−11 m3⋅kg−1⋅s−2
You replace the values of G, M_E and r in the equation for v:
[tex]v=\sqrt{\frac{(6.674*10^{-11}m^3/kgs^2)(5.97*10^{24} kg)}{ 1.496*10^{11}m }}\\\\v=51.60\frac{m}{s}[/tex]
hence, the velocity of traslation of the Earth is 51.60 m/s
You spend some time thinking about events that involve matter and energy. Consider balls of different shapes and materials that reach different heights as they bounce off the same floor. What aspects of this event relates to matter? What aspect relates to energy?
Answer:
Matter - The ball itself
Energy - the motion of the ball as they reach different height.
Explanation:
The aspect of the event which relates to matter is the ball itself being described above, this us because, the ball is a physical substance or material which possesses mass and occupies space.
The aspect which relates to energy in the event described above is the motion of the ball when bounced off the floor, changing from potential to kinetic energy depending on the height attained, at any instance, the total energy is the sum of the kinetic and potential energy, however, at maximum height, at rest, Potential energy is maximum with kinetic energy equal zero, at maximum height, kinetic energy then start to increase with height until it reaches it's the maximum height, where the direction changes, at this point kinetic energy turns to zero. Therefore, the motion of the ball and height attained relates to energy.
The interference between the two wave pulses shown above will
result in a wave with an amplitude of
Select one
Answer:
can you make it clear i do not understand.
Explanation:
How does matter affect the way you perceive and use light
Answer:
The relationship between light and matter produces three phenomena, namely:
reflectionabsorption transmission and EmissionExplanation:
Reflection: This happens when matter deflects light in another direction
In everyday use, reflective materials are used on construction apparel, handheld electric torch, headlamp of vehicles etc.
2. Absorption: When matter captures electromagnetic radiation, it converts the energy of photons into internal energy and absorption is said to have taken place.
Light absorption by the chlorophyll in plants for use in production is an example of how humans use light absorption albeit indirectly.
3. Transmission
When matter is transparent or semi-transparent it allows light to pass through. For semi-transparent matter, some of the light is absorbed.
Transmission of light is used predominantly in various kinds of lighting effects for interior decoration and houses.
4. Emission
When matter releases energy as light, it is said to have emitted light.
Examples of everyday emission of light include Light Emitting Diode which is used in remote controls.
Cheers!
find the kinetic energy of 5 litre of a gas at STP given standard pressure is 1.013 into 10 to the power 5 Newton per metre square
Answer:
1.52 kJ
Explanation:
Total kinetic energy in gas K = 3NkT/2 where N = number of molecules, K = Boltzmann constant and T = temperature.
Also from the ideal gas law, PV = NkT
substituting PV into K above
K = 3PV/2 where P = pressure = 1.013 × 10⁵ N/m² and V = volume of gas = 5 litres = 5 dm³ = 5 × 10⁻³ m³
K = 3 × 1.013 × 10⁵ N/m² × 5 × 10⁻³ m³/2
= 1519.5 J
= 1.5195 kJ
≅ 1.52 kJ
It is a way to display to number of ________ for elements. This chart will show the correlation between ______ number and the number of valence electrons
Answer:
Electrons
Atomic number
Explanation:
The question describes a period table which is a chart of the elements.
The Periodic Table of elements shows the arrangement of elements based on their increasing atomic number.
In a neutral atom, the number of electrons will equal the number of protons, so we can easily determine electron number from atomic number. In addition, the position of an element in the periodic table—its column, or group, and row, or period—provides useful information about how those electrons are arranged (electronic configuration) in their different shells.
It is a way to display to number of ____electrons____ for elements. This chart will show the correlation between __atomic____ number and the number of valence electrons
Which of these objects are malleable? Check all that apply.
tin fork and knife from a camping set
antique ceramic vase
steel pole fence post
marble sculpture
glass tabletop
copper coin
Answer:
The tin fork and knife, the copper coin, and the steel fence pole.
Explanation:
Those are both what people would call soft metals so they are malleable to the extent of probably not needing heavy duty equipment. It depends on you description of malleable because the steel fence pole could be malleable with the correct equipment and not snap in half if bent slowly enough.
The definition of malleable: (of a metal or other material) able to be hammered or pressed permanently out of shape without breaking or cracking.
But the glass table, marble sculpture and antique ceramic vase are nowhere near malleable because if you tried bending them they wouldn't bend but would shatter and break into pieces.
The tin fork and knife, the copper coin, and the steel fence pole are malleable, the correct option is A, C, and F.
What are malleable objects?A malleable material is one that can be easily formed into a thin sheet by hammering. The most malleable metal is gold. In contrast, ductility is a solid material's ability to deform under tensile stress.
Metals are malleable because when a force is applied, layers of ions can slide over each other. Metallic bonding allows metal to change shape without breaking.
Gold, iron, aluminum, copper, silver, and lead are examples of malleable metals. Ductility and malleability do not always correlate; for example, gold is both ductile and malleable, whereas lead is only malleable.
Tin fork and knife, copper coin, and steel fence pole are all malleable.
Thus, the correct options are A, C, and F.
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