The speed of sound waves in air at room temperature T=20° is 344.035 m/s.
The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is 17.20 m to 0.0172 m.
What is wavelength?The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
Wavelength λ = c/f
where c is the speed of sound wave.
Given the room temperature T = 20 +273 = 293K
The velocity of sound wave is given by
v = √(γRT/m)
where γ =1.4 , m = 28.8×10⁻³ kg/mol R = 8.31 J/K.mol
Substituting the values, we get
v = 344.035 m/s
Thus, the speed of sound wave is 344.035 m/s
The human ear can hear frequencies in the range of 20 – 20,000Hz.
The wavelength corresponding to 20Hz is
λ = c/f
λ = 344.035 /20
λ = 17.20 m
The wavelength corresponding to 20,000Hz is
λ = 344.035 /20000
λ = 0.0172 m
Thus, the range of wavelength is 17.20 m to 0.0172 m sensitive to human ear.
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A circular wheel of mass 50 kg and radius 200 mm is rotating at 300 r.p.m. Find its kinetic energy.
Tennis balls experience a large drag force. A tennis ball is hit so that it goes up and then comes back straight down.
A tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.
How object move upward and downward?We know that objects move upward due to application of force on it while on the other hand, object comes to the ground because of the attraction of earth which we called gravity.
So we can conclude that a tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.
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Estimate the gravitational force of attraction between two people sitting side by side on a park bench. How does this force compare with the gravitational force exerted on each of them by the Earth
Weight is compared with the gravitational force exerted on each of them by the Earth.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The gravitational force is balanced by weight;
[tex]\rm F = W \\\\ G\frac{mM}{r^2} =mg[/tex]
Hence, weight is compared with the gravitational force exerted on each of them by the Earth.
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An elevator is moving in an upwards direction. The free body diagram for the forces acting on the elevator during this time is: The motion of the elevator can best be described as:
The motion of the elevator can best be described as motion against gravity with negative acceleration.
What is motion?Motion refers to a change in position of an object when it moves from one point another along a reference frame.
An object moving in a downward direction is moving in a positive direction and its velocity increases relative to the earth since gravity acts downwards.
An object moving in a upward direction is moving in a negative direction and its velocity decreases relative to the earth since gravity acts downwards.
Therefore, the motion of the elevator can best be described as motion against gravity with negative acceleration.
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Particles q1, q2, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C,
and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.250 m. What is the net force on q2?
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
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a. The potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J. Find by how much is the spring is compressed.
b. A 0.010 kg dart is fired straight up. Find the vertical distance the dart travels from its position when the spring is compressed to its highest position.
c. The same dart is now fired horizontally from a height of 4.70 m. The dart remains in contact until the spring reaches its equilibrium position. Find the horizontal velocity of the dart at that time.
d. Find the horizontal distance from the equilibrium position at which the dart hits the ground.
a. The spring is compressed by 0.174 m.
b. The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.
c. The horizontal velocity of the dart at that time is 13.74 m/s.
d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.
What is potential energy?The energy by virtue of its position is called the potential energy.
a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.
PE of spring = 1/2 kx²
Put the values, we get
P.E = 0.940 = 1/2 x 62 x²
x = 0.174 m
Thus, the spring is compressed by 0.174 m.
b. Given is a 0.010 kg dart is fired straight up.
The vertical height is find out by
0.940 J = (0.010 kg) (9.8 m/s²) h
h = 9.6 m
Thus, the vertical distance the dart travels from its position is 9.6 m
c. From the conservation of energy principle, total mechanical energy is conserved.
1/2 mv² =mgh
v = √2gh
Plug the values, we get
v = √2 x 9.8x 9.6
v = 13.74 m/s
Thus, the horizontal velocity is 13.74 m/s.
d. Time that dart spends in air, t = √2h/g
t = √(2x9.6)/9.81
t = 1.4 s
The horizontal distance from the equilibrium position at which the dart hits the ground.
Horizontal distance = (Velocity on x direction) x time
Horizontal distance = 13.74 m/s x 1.4s
Horizontal distance = 19.236 m
Thus, the horizontal distance is 19.236 m.
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A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
Answer:
Explanation:
Force:
⇒ Mass × Acceleration
Work Done:
⇒ Force × Distance
Calculations:
⇒ Force = 0.0083 × 7000 N
⇒ Work done = 0.0083 × 7000 × 5.8 × 10^4 Joules
Wavelength is determined by dividing a wave's speed by its frequency. If a wave has a frequency of 1 hertz and a speed of 20 m/s, what is its wavelength?
Select one:
a. 80 m
b. 5 m
c. 0.05 m
d. 20 m
Answer:
D. 20m
Explanation:
this answer is 20 m.
wavelength = velocity / frequency
Kim is ice-skating going 4.6 m/s. What is her velocity after 10 seconds ?
This is a uniform rectilinear motion (MRU) exercise.
To start solving this exercise, we obtain the following data:
Data:v = 4.6 m/sd = ¿?t = 10 secTo calculate distance, speed is multiplied by time.
We apply the following formula: d = v * t.
We substitute the data in the formula: the speed is equal to 4.6 m/s, the time is equal to 10 s, which is left as follows:
[tex]\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }[/tex]
[tex]\bf{d=46 \ m}[/tex]
Therefore, the speed at 10 seconds is 46 meters.
[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
A small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then drops down to a horizontal surface and bounces elastically back up as shown.
The picture is to scale. It shows the position of the mass at equal time intervals starting from rest at T. The height of the mass at X is the same as at V. Click here to view the motion of the mass m.
(options are: less than, greater than, equal to)
• The speed change between T and S is (blank) between S and R.
• The speed of m at X is (blank) that at Q.
• The size of the total force on m at P is (blank) at U.
• The mechanical energy of m at P is (blank) that at V.
• The size of the total force on m at S is (blank) at P.
• The velocity of m at X is (blank) that at V.
• The speed change between T and S is greater between S and R.
• The speed of m at X is greater that at Q.
• The size of the total force on m at P is less at U.
• The mechanical energy of m at P is equal to that at V.
• The size of the total force on m at S is greater at P.
• The velocity of m at X is equal to that at V.
What is mechanical energy?The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
Given is a small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then drops down to a horizontal surface and bounces elastically back up as shown.
The picture shows the position of the mass at equal time intervals starting from rest at T. The height of the mass at X is the same as at V.
Between T to S and S to R, the mass is under constant acceleration. Time taken to move from T to S is greater than S to R. Thus, the speed change between T and S is greater than between S and R.
At Q, there is only a horizontal velocity component, but at X. the speed will be greater and has both vertical and horizontal component. Thus, the speed of m at X is greater than that at Q.
Force is given as the rate of change of momentum with time. At U, change in momentum is large compared to P. Thus, the size of the total force on m at P is less at U.
There is no friction acting on the system. So the energy remains conserved. Mechanical energy at P = V.
The force on mass m at S is only the gravity force. The remaining forces are cancelled by the normal force. Thus, size of the total force on m at S is greater at P.
The energy is conserved at each point of motion of mass. If X and V are at same height, they have same potential energy and so their kinetic energy. Thus, velocity of m at X is equal to that at V.
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A car moves with the speed of 40km/hr for the first half distance and 60km/hr for second half distance.find average speed of car?
Answer:
50km/h
Explanation:
average = (a + b) / 2
average = (60 + 40) / 2
average = 50
PLEASE HELP!! 50 points. The answer is not 2.6 m/s.
Answer:
A
Explanation:
5.2mm/s
hope this helps
state how the centripetal force is provided in a c held on a playground roundabout
The centripetal force is obtained by its formulas is,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
What is centripetal acceleration?The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.
The formula for the centripetal force is ;
[tex]\rm F_C= \frac{mv^2}{r}[/tex]
Where,
r is the radius
v is the linear speed
m is the mass of an object
Hence, the centripetal force obtained by its formulas as,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
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what’s better csp or pv ?
Answer:
CSP
Explanation:
CSP systems store energy through Thermal Energy Storage technologies (TES), so power can be used when there isn't enough sunlight. PV systems, however, can't store thermal energy because they use direct sunlight, rather than heat. For this reason, CSP systems are better for energy storage and efficiency.
A car traveling at 120km/h towards west makes a right turn and travel north without changing its speed .120km/h120km/h.Using a vector diagram.Finding the magnitude and direction of the resultant velocity of the car
The magnitude and direction of the resultant velocity of the car will be 169.70 km/h and 45°.
What is a vector?The quantity which has magnitude, direction and follows the law of vector addition is called a vector.
A car traveling at 120 km/h towards west makes a right turn and travel north without changing its speed.
Then the magnitude (R) will be
R² = 120² + 120²
R² = 28800
R = 169.70 km / h
Then the direction of the resultant velocity will be
tan θ = 120 / 120
tan θ = 1
tan θ = tan 45°
θ = 45°
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A 50 N force is applied to the free end of a spiral spring of force constant, 100 Nm
Calculate the work done by the force to stretch the spring.
The work done by the force to stretch the spring is determined as 12.5 J.
Work done by the forceThe work done by the force to stretch the spring is calculated as follows;
W = ¹/₂Fx
F = kx
W = ¹/₂F(F/k)
W = ¹/₂F²/k
W = ¹/₂ x (50²)/100
W = 12.5 J
Thus, the work done by the force to stretch the spring is determined as 12.5 J.
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Consider an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
1.What is the electric flux through the cylinder due to this infinite line of charge?
2.What is the flux through the cylinder if its radius is increased to r= 0.600 m ?
3.What is the flux through the cylinder if its length is increased to l= 0.990 m ?
The electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C
Given an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
Solve for the electric flux through the cylinder due to this infinte line:
As below equation mentions, the electric flux for a uniform electric filed is given by:
Фₓ = EA cosΦ
Φₓ = λLcosΦ)/ε
Φₓ = (3 x 10^(-6) x 0.4 x cos0)/(8.854 x 10^(-12))
Φₓ = 1.355 x 10^(5) Nm²/C
Hence the electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C
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Put the steps of the scientific method in order.
A. Question -> Research -> Hypothesis -> Experiment -> Analysis -> Conclusion
B. Research -> Hypothesis -> Experiment ->Question -> Conclusion -> Analysis
C. Research -> Question -> Hypothesis -> Experiment -> Analysis -> Conclusion
D. Hypothesis -> Experiment -> Conclusion -> Question -> Research -> Analysis
Answer:
c
Explanation:
Answer:
c
Explanation:
im smart
A squirrel sitting on the ground starts to run with an acceleration of 5.1 m/s².
How fast is the squirrel going after 0.25 seconds?
O A. 20.4m/s
OB. 0.49 m/s
OC. 3.1 m/s
OD. 1.28 m/s
Answer:
0.159
Explanation:
the formula to find its is 1÷2*gt^2
Answer:
D
Explanation:
v= a t
= 5.1 * .25 = 1.275 m/s
In which device is chemical energy transformed into electrical energy?
Answer:
A Rechargeable Battery
Explanation:
That is roughly what happens when a secondary cell is recharged (rechargeable battery.) Electric current transforms one chemical species with a lower energy level into another with a higher energy level. When the battery is loaded, this energy can be released. Strictly speaking, no conversion occurs: chemical energy is electrical energy! The energy of electrons in any particular substance, such as metal, are due to electron interactions with the nuclei in the substance and with each other. Electrons, in particular, occupy certain energy levels in metals. Because each metal has a distinct highest occupied energy level, electrons can alter their energies by traveling from one metal to another. An electrical current is made up of this movement!
The frequency of a waveform is found by determining the...
Select one:
a. number of crests passing a point in a given time.
b. distance from a wave's midpoint to its crest.
c. distance between two moving low points of the wave.
d. distance between a crest and a trough.
By counting the number of crests that pass a point in a specific amount of time, one may determine the frequency of a waveform. Option a is correct.
What is the frequency of the sound?A sound pressure wave's frequency, also known as pitch, is the number of times it repeats itself every second.
The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.
The frequency of a waveform is found by determining the number of crests passing a point in a given time.
Hence option a is correct.
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how do I calculate equilibrant and fx and fy. I don't understand what they are asking
(a) The equilibrant C for force of vector A and B is 3.43 N.
(b) The equilibrant C for fx of vector A and B is 2.1 N.
(c) The equilibrant C, for fy of vector A and B is 2.12 N.
What is equilibrant force?An equilibrant force is a single force that will bring other bodies into equilibrium.
From configuration 1:Vector A: mass = 0.2 kg, θ = 20⁰
Vector B: mass = 0.15 kg, θ = 80⁰
Fx = mg cosθ
Fy = mg sinθ
where;
m is mass g is acceleration due to gravityVector AForce of A due to its weight
F(A) = mg
F(A) = 0.2 x 9.8 = 1.96 N
Fx = (0.2 x 9.8) cos(20) = 1.84 N
Fy = (0.2 x 9.8) sin(20) = 0.67 N
Resultant forceR = √(0.67² + 1.84²)
R = 1.96 N
Vector BForce of B due to its weight
F(B) = mg
F(B) = 0.15 x 9.8
F(B) = 1.47 N
Fx = (0.15 x 9.8) cos(80) = 0.26 N
Fy = (0.15 x 9.8) sin(80) = 1.45 N
Resultant forceR = √(0.26² + 1.45²)
R= 1.47 N
Equilibrant C of vector A and BEquilibrant force:
Force, C = 1.96 N + 1.47 N
Force, C = 3.43 N
Equilibrant FX:
Fx, C = Fx(A) + Fx(B)
Fx, C = 1.84 N + 0.26 N = 2.1 N
Equilibrant FY:
Fy, C = Fy(A) + Fy(B)
Fy, C =0.67 N + 1.45 N = 2.12 N
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when energy is transferred from one part of a system to another, some of the energy is lost during the transfer and cannot be used as it was intended. Which two sentences describes examples of this?
Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.
What is the law of conservation of energy?According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.
Energy cannot be created nor destroyed and can be transferred from one form to the other form.
The complete question is
"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.
Which two statements provide examples?
A. Friction between a car's tires and the road produces heat.
B. Sunlight strikes a solar panel, generating electricity.
c. Stereo speakers emit a sound when powered by electrical energy,
D. Wind moves a turbine, generating electricity.
I E. Power lines heat up as electricity flows through them."
Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.
Hence, sentences A and D describe examples of energy transformation.
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yhisriyftt
carzy and want one g come 6x 10-1'coulomb or one unit. The ratio, mass for each of the particle is 9.58 x 10" per gram. Hence, the mass
Answer asap for brainlist
They use less wire, A
A railroad cart with a mass of m1 = 11.6 t is at rest at the top of an h = 10.9 m high hump yard hill.
After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m2 = 23.2 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.
What is the law of conservation of momentum?According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Unit conversion:
1 metric tons = 1000 kg
Given data;
m₁= 11.6 metric ton =11600 kg
m₂ = 23.2 metric ton = 23200 kg
Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.
Considering energy conservation;
[tex]\rm m_1 g h = \frac{1}{2} m_1 \times u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2 \times 9.8 \times 10.6 \\\\ u = 207.972 \ m/s[/tex]
From the conservation of momentum principle;
[tex]\rm m_1 \times u = (m_1 + m_2) v\\\\ 11600 \times 207.972 = (11600 + 23200) \times v \\\\ v = 69.3 \ m/s[/tex]
Hence, the final common speed of the two carts will be 69.3 m/sec.
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If the mass of the falling object is 60kg. Calculate force. [Take g=10m/s2]
Calculate the frequency of the wave shown below.
Frequency = Speed/Wavelength (λ)
Select one:
a. 4 hertz
b. 3 hertz
c. 2 hertz
d. 1 hertz
[tex] \color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}[/tex]
[tex] \: \: [/tex]
Given :
Wavelength ( λ ) = 2 m[tex] \: \: [/tex]
Speed = 4 m/s[tex] \: \: [/tex]
We, have to find frequency :
[tex] \: [/tex]
[tex] \large \tt \: Frequency = \frac{Speed}{Wavelength ( \: λ \: )} [/tex][tex] \: \: [/tex]
[tex]\large \tt \: Frequency = \frac{4}{2} [/tex][tex] \: \: [/tex]
[tex]\large \tt \: Frequency = \cancel \frac{4}{2} [/tex][tex] \: \: [/tex]
[tex] \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}[/tex][tex] \: \: [/tex]
Hope Helps!
Why is a valve placed before the rotameter?
a.To measure the flow of liquid entering the extraction bed
b.To regulate the flow of fluid leaving the extraction bed
c.To regulate the flow of liquid entering the extraction bed
d.None of the above.
A valve placed is before the rotameter to regulate the flow of liquid entering the extraction bed. The correct option is c.
What is control valve?Control valves are generally used to maintain a flow as close as possible to the desired value.
Valves positioned before the rotameter for throttling purposes. A control valve will regulates the rate of fluid flow. Control valves control typically flow rate, pressure, and temperature.
Thus, the correct option is c.
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In the image below, a worker is pushing a crate with a mass of 10 kg up a
ramp at a constant rate. Ignoring friction, how much force must the worker
apply so that the crate continues to move at the same speed? (Recall that g =
9.8 m/s²)
A. 25.6 N
B. 67.5 N
C. 16.2 N
D. 49.0 N
Answer:
D. 49N
Explanation:
Because there is no acceleration the sum of the forces in the x-direction is zero. Your weight force is mass x gravity which is 98N. The x-component of which is sin(30). 98sin30 = 49N in the negative x-direction. -49N + The force applied by the worker must equal zero. So, the force applied by the worker must be 49N.
