Answer:
Br2+KI→KBr+I2
Explanation:
heating up a reaction increases the speed of a reaction until the ____
Heating up a reaction increases the speed of a reaction until the enzyme denatures.
What is enzyme denaturation?Enzyme denaturation occurs when a biological protein catalyst does not work anymore due to a high temperature that alters its tridimensional conformation.
This cellular process (denaturation) is well known to be one of the main causes of enzymatic failure.
In conclusion, heating up a reaction increases the speed of a reaction until the enzyme denatures.
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A car's tires are inflated to 2.11 atm at 25c. after driving to the grocery store, the tires are at 2.25 atm. what is the temperature of the air in the tire after the drive?
Answer:
T₂ = 26.7 °C
Explanation:
Because you are dealing with pressure and temperature, you can use Gay-Lussac's Law to find the final answer. The equation looks like this:
P₁ / T₁ = P₂ / T₂
In this form, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You have been given the values for all of the variables but "T₂". Therefore, by plugging these values into the equation, you can simplify to find "T₂".
P₁ = 2.11 atm T₁ = 25 °C
P₂ = 2.25 atm T₂ = ?
P₁ / T₁ = P₂ / T₂ <--- Gay-Lussac's Law equation
(2.11 atm) / (25 °C) = (2.25 atm) / T₂ <--- Plug variables into equation
0.0844 = (2.25 atm) / T₂ <--- Divide 2.11 by 25
(0.0844) x T₂ = 2.25 atm <--- Multiply both sides by T₂
T₂ = 26.7 <--- Divide both sides by 0.0844
Which of the following shows the combustion of a hydrocarbon?
OA. NaOH + HCI → NaCl + H₂O
OB. CO₂ + H₂O → H₂CO3
OC. 2C₂H₂ +502 + 4CO2 + 2H₂O
OD. C₂H4 + Cl₂ ⇒ C₂H4Cl₂
Answer:
C
Explanation:
with combustion you must know that your products must be carbon dioxide and water. I think you copied your question incorrectly.
A is a solution containing 3.5g of HX per dm-³. B is a solution containing 0.050moldm-³ of an hydrous sodium trioxocarbonate (IV) of solution 25cm³ portions of solution B required an average of 26.10cm³ of Solution A for complete neutralization. From this results, calculate
1. The Molar Concentration Of A
2. The Relative Molar Mass Of A
Equation For The Reaction 2HX + Na2CO3 ---> 2NaX + H2O + CO2
Brainliest!!
The Molar Concentration Of A =0.099 .
The Relative Molar Mass Of A = 35.0129 gm
Given,
Mass of HX = 3.5 g
Moles of solution B ([tex]Na_{2} CO_{3}[/tex]) = 0.05 moles
Volume of HX = 26.10 mL
Volume of Solution B = 25 mL
Molecular weight of solution B = 2(atomic weight of Na )+ atomic weight of C + 3(atomic weight of O)
= 2(23) + 12 + 3(16)
=106 gm
Equivalent weight of [tex]Na_{2} CO_{3}[/tex] = molecular weight / 2 = 106 /2 =53 g
Mole = mass / molecular weight
∴0.05 = mass / 106
∴ mass = 5.3 gm [tex]Na_{2} CO_{3}[/tex]
Normality = mass ÷ (equivalent weight × volume of the solution in liter)
= 5.3 ÷( 53 × 0.025)
=4 N
So, by using formula ,
[tex]N_{1} V_{1} =N_{2} V_{2}[/tex]
[tex]N_{1}[/tex] = normality of solution B = 4 N
[tex]V_{1}[/tex] = volume of solution B = 25 mL
[tex]N_{2}[/tex] = normality of solution A = ? N
[tex]V_{2}[/tex] =Volume of solution A = 26.1 mL
∴ 4×25 = [tex]N_{2}[/tex] × 26.1
∴[tex]N_{2}[/tex] = 3.83 N
∴ normality of solution A = 3.83 N
from Formula of the normality we can find the equivalent weight of the A
Normality = mass of HX ÷ (equivalent weight × volume of the solution in liter)
3.83 = 3.5 ÷( equivalent weight × 0.0261)
∴equivalent weight = 35.0129 g
In case of HX the electron transfer is 1 ,so equivalent weight = molecular weight ; which is also termed as relative molar mass in given case.
∴The Relative Molar Mass Of A = 35.0129 g
Molar concentration = mass / molar mass
= 3.5 / 35.0129
= 0.099 mole
∴ The Molar Concentration of A is 0.099 .
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the company calculated that they would produce 4.8 tonnes of magnesium but only 3.2 tonnes was produced calculate the percentage yield
Identify 3 chemicals that produce a potentially dangerous reaction with hydrochloric acid.
What is the answer to this question? I need help!!
Answer:
[tex]\fbox {C}[/tex]
Explanation:
By repeating the experiment with new amounts of each reactant, this conflict can be resolved as we can see the effect of a reactant on the final amount of product formed.
Considering the temperature vs. time graph below, how does the temperature at the beginning of a change of state
compare with the temperature at the end of the change?
Temperature vs. Time
140
120
100
80
60
Time (min) →
4
The temperature is always lower.
The temperature is always the same.
The temperature is usually lower.
The temperature is usually higher.
Temperature (°C)
The temperature is always the same.
How Temperature manifests in objects ?Assume we have something in solid phase. As we increase the temperature, the particles on the solid increase their kinetic energy, thus, the particles move more.
This causes that the volume of the object increases (for example when we heat up a metal and it dilates) and this keeps happening until we reach a critical point, when we are near a change of phase.
At this point the energy given is not used to increase the temperature of the object, but is used to "break" bonds in such a way that the particles are more free than before.
When all these bonds are "broken" the change of phase is completed, and in the case of the solid, we go from solid phase to liquid phase.
So, the temperature is always the same at the beginning of a change of state compare with the temperature at the end of the change
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What is the mass of a 7.426-mole sample of sodium hydroxide (NaOH molar mass = 40.0 g/mol)?
Select one:
5.360 g
40.00 g
179.1g
297.0 g
[tex](40.0)(7.426)=\boxed{297.0 \text{ g (to 4 sf)}}[/tex]
A year has 365 day and a day has 24 hours. if an hour has 60 minutes and a minute has 60 seconds how many seconds are in a year
Answer:
31536000
Explanation:
There are 31536000 seconds in a day.
60s x 60min x 24hrs x 365 days = 31536000sec
How many moles of propane
react when 294 g of CO2 form?
C3H8 +502 3CO2 + 4H₂O
?] mol C3H8
the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?
The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
Position of 18o-labeled methanol in the products
The 18O label will appear at position b in the product as indicated in the image.
This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).
While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.
Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.
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Ammonia gas occupies a volume of 450. mL at a pressure of 720. mm Hg. What volume will it occupy at standard pressure?
Show your work Please!!!!
If you added the same amount of sugar to the same amount of water and boiled it, what would the boiling point be?
Answer:
Adding sugar to water will raise the boiling point and decrease the freezing point of water.
Explanation:
Hope this helps!
If same amount of sugar added to the same amount of water and boiled it then boiling point increases.
When sugar added to water it become solution.
Example: If water boils at 100°C then solution with 80% sugar in 20% of water boils at 112°C.
Why boiling point of solution of sugar and water is higher then boiling point of water?Since, sugar is non-volatile solute. So, when we boil the solution of sugar in water then water boils easily in low temperature but more high temperature is required to boil sugar.
What is non-volatile solute?The solute which has higher vapor pressure as compare to solution in which it dissolve is called non-volatile solute.
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Consider the compound calcium nitrate, Ca(NO3)2. Which statements are true about this compound? Check all that apply. There are two atoms of oxygen. There are six atoms of oxygen. There are two nitrogen atoms. There are two calcium atoms.
Calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.
Ca(NO₃)₂
Calcium nitrate is a compound consisting of calcium, nitrogen and oxygen compoundsIt is an inorganic compoundIt is water-absorbent and absorbs moisture from airCalcium nitrate has two forms, hydrous and anhydrousBoth forms are colourless and odourlessThe reaction to form Calcium nitrate is Ca + 2NO₃ -----> Ca(NO₃)₂The number of oxygen atoms is: 2x3 = 6The number of nitrogen atoms is: 2x1= 1There is 1 calcium atomThus, calcium nitrate is made up of 6 oxygen atoms, 2 nitrogen atoms and one calcium atom.
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Answer:
B)There are six atoms of oxygen.
C)There are two nitrogen atoms.
Explanation:
edge 2023
A thermodynamically-controlled process describes a reaction that ________.
A thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.
What is a thermodynamically-controlled process?A thermodynamically-controlled process is a reaction in which the ratio of the product formed is determined by the relative stability of the products.
Thermodynamic control ensures that the most stable or more stable of two products is formed.
Therefore, a thermodynamically-controlled process describes a reaction that the most stable or more stable of two products is formed.
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The 9.6 g object displaced
3.2 mL of water.
What is its density in g/mL?
density=[?] g/mL
Answer: 3
Explanation:
Density is mass/volume divide the mass 9.6 by the volume of 3.2
[tex]\frac{9.6}{3.2} =3[/tex]
The density of the object displaced in water is equal to 3 g/ml.
What is the density?The density of a substance can be described as the substance's mass per unit of its volume. The symbol is generally used to represent density ρ and the letter D can be used.
The mathematical formula of the density of a material can be represented as shown below:
Density = Mass/volume
ρ = m/V
The density of a material varies with pressure as well as temperature. There is a small variation in the density of the solids and liquids but much larger for gases. Increasing the pressure of the substance decreases the volume and thus increases its density.
As the object displaced water of volume of 3.2 ml.
Therefore, the volume of the object, V = 3.2 ml
The mass of the object, m = 9.6 g
The density of the object placed in water can be calculated as:
Density of object = 9.6/3.2 = 3 g/ml
Therefore, the density of the object is 3 g/ml.
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Which would be a good use for an organic substance? Check all that apply. A. Electrical conductors B. Waterproof coatings C. Fuels such as gasoline D. Microchips E. Plastic storage containers
Answer:
B. waterproof coatingExplanation:
please mark me brainlistSpecialized periodicals in which scientists publish the results of their works are called
Specialized periodicals in which scientists publish the results of their works are called scientific journals.
In educational publishing, a scientific journal is a periodical book intended to similarly the progress of technology, typically by way of reporting new studies.
Journal articles may include original research, re-analyses of studies, opinions of literature in a selected place, proposals of new but untested theories, or opinion pieces.
These scientific journals include the following.
original articles, case reports, technical notes, pictorial essays, reviews, commentaries editorials.Learn more about scientific journals here https://brainly.com/question/14443228
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What is the volume of 0.24 mol oxygen (02) gas at 345 k and a pressure of 0.75
9.06 L is the volume of 0.24 mol oxygen (02) gas at 345 k and a pressure of 0.75.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
We know that the ideal gas equation relates the pressure, volume, temperature, and moles of gases as:
PV =nRT
This is a combined gas law based on other gas law like Boyle's law, Charle's law, Avagadro's law, Gay Lussac's law
P = pressure = 0.75 atm
V = volume = ?
n = moles = 0.24 mol
R = 0.0821 L atm / molK [gas constant]
T = temperature = 345 K
Putting the values
Volume =[tex]\frac{nRT}{ P}[/tex]
Volume = 0.24 X 0.0821 X 345 / 0.75
= 9.06 L
Hence, 9.06 L is the volume of 0.24 mol oxygen (02) gas at 345 k and a pressure of 0.75.
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Calculate the molecular mass of Al2(SO4)3(Molecular mass of Al=27, S=32, O=16) Pls fast
Al₂(SO₄)₃
= 2.Al+3.S+12.O
= 2.27 + 3.32+12.16
= 54+96+192
=342 g/mol
What is the pH of a solution with a
POH of 8.35?
Answer: The pH of the solution is 5.65
Explanation:
The relationship between the pH and the pOH is that [tex]pH+pOH=14[/tex].
Given this, we can plug in the pOH and subtract that from 14.
[tex]14-pOH=pH\\14-8.35=5.65[/tex]
I hope this helped! Pls give brainliest!! :)
Answer:
Give the man above me brainliest
Consider the reaction below.
2Al2O3 --> 4Al + 3O2
How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?
(a) 17.7 mol
(b) 19.9 mol
(c) 39.8 mol
(d) 53.0 mol
Answer:
(b) 19.9 moles
Explanation:
To convert from moles Al to moles O₂, you need to multiply the given value by the mole-to-mole ratio of each component. This ratio is constructed via the coefficients in the balanced reaction. The desired unit (moles O₂) should be placed in the numerator to allow for the cancellation of units.
2 Al₂O₃ ----> 4 Al + 3 O₂
^ ^
26.5 moles Al 3 moles O₂
--------------------- x ---------------------- = 19.9 moles O₂
4 moles Al
7.0 mol Mn reacts with 5.0 mol
O2 according to the equation below:
2Mn + O₂ → 2MnO
How many moles of MnO form from
5.0 mol Mn?
? ] mol MnO
Round your answer to the tenths place.
Answer:
5.0 mol
Explanation:
From the coefficients of the equation, we know that for every 2 moles of Mn consumed, 2 moles of MnO are produced.
Thus, the number of moles of Mn consumed is equal to the number of moles of MnO produced, and thus the answer is 5.0 mol.
The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.
What is a limiting reagent?In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.
In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.
Thus, the moles of oxygen consumed by 7 moles of Mn is:
2 moles Mn = 1 mole O₂
7 moles Mn = 3.5 moles O₂
The available moles of O₂ = 5 mol.
The remaining moles of O₂ = 5-3.5 moles
The remaining moles of O₂ = 1.5 moles
The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.
The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂
1 mole O₂ = 2 moles MnO
1.5 moles O₂ = 2 * 1.5 moles MnO
1.5 moles O₂ = 3 moles MnO
Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.
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Given the balanced equation representing a
reaction:
2NO+ O₂ → 2NO₂ + energy
1. The mole ratio of NO to NO₂ is
(1) 1 to 1
(2) 2 to 1
(3) 3 to 2
(4) 5 to 2
Answer: it would be a 1 to 1 ratio
Explanation: originally it would be 2 to 2 but you have to reduce
Consider these two electron configurations for neutral atoms L and M.
L-1s²2s²2p^6 3s²
M-1s²2s²2p^6 3s¹3p¹
What is the atomic number of L?
Calculate electrons
1s²2s²2p⁶3s²[Ne]3s²Total electrons=10+2=12
The element is Magnesium with symbol Mg as atomic no is 12
Additional:-
M:-
1s²2s²2p⁶3s¹3p¹Excited state of magnesium
A container with oxygen, xenon and helium has a total pressure of 1436.4kPa. If the pressure of the helium is 348.1kPa and the pressure of the oxygen is 516.8kPa, what is the pressure (kPa) of the xenon?
The partial pressure of xenon is 571.5 KPa if the total pressure is 1436.4kPa.
What is partial pressure?The pressure exerted by a (specified) component in a mixture of gases.
According to Dalton's law of partial pressure, the net pressure of a gaseous mixture is always equal to the sum of the partial pressures of individual gases.
Now we are given that the total pressure is 1436.4kPa
The partial pressure of helium is 348.1kPa
The partial pressure of oxygen is 516.8kPa
Partial Pressure of xenon?
Using dalton's law;
1436.4kPa = 348.1kPa + 516.8kPa + partial pressure of xenon
The partial pressure of xenon is 571.5 KPa.
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What mass of ammonium nitrate
is needed to dissolve in 995 g of
water to make a 1.50 m solution?
Answer:
=> 119.4597 g
Explanation:
From our question, we have been provided with the molarity of the resultant solution.
We know that, molarity of a solution is contained in 1 L or 1000 cm³ of solution.
Hence we have 1.50 moles in 1000 cm³.
Also, we know that, 1 cm³ equivalent to 1 g for water.
Thus, from our question we have 995 cm³ of water.
Lets now solve our problem;
1.5 moles are contained in 1000 cm³
x moles are contained in 995 cm³
Cross multiply
[tex]x \: moles \: = \frac{(995 {cm}^{3} \times 1.5 \: moles )}{(1000 {cm}^{3} )} \\ = \frac{1492.5 \: moles}{1000} \\ = 1.4925 \: moles[/tex]
1.4925 moles of NH4NO3 are required to be dissolved in water.
To find the mass of solute (NH4NO3) we use the formula;
Mass = RFM (Relative Formula Mass) x Number of moles
[tex] = 80.04 \: \frac{g}{mol} \times1.4925 \: mol \\ = 119.4597 \: g [/tex]
Therefore the mass of NH4NO3 needed to be dissolved in 995 g of water is 119.4597 g
Answer:
119.4597
Explanation:
Acellus
Did you write these compounds?
KBr
2 NH₂OH
2HNO3
The missing components of the neutralisation reaction include the following:
KBr KBr 2NH4OHKBr 2NH4OH2HNO2What is neutralisation reaction?Neutralisation reaction is defined as the type of reaction that leads to the formation of salt and water when an acid and a base reacts.
From the reactions given the missing components are replaced as follows:
HBr + KOH --> KBr + H2OH2SO4 + 2NH4OH --> (NH4)2SO4 + 2H2O2HNO3 + Mg(OH)2 --> Mg(NO3)2 + 2H2OLearn more about acids here:
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What volume did a helium-filled balloon have at 18.1 °C and 2.61 atm if its new volume was 59.9 mL at 1.92 atm and 12.5°C?
a. 44.9
b. 63.8
c.43.2
d. 83.0
Answer:
a. V=44.9mL
Explanation:
For a gas undergoing all of these changes, it will be important to combine Boyle's Law and Charles' Law to form the following equation (if it isn't already known):
[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]
Where the Temperatures must be measured in Kelvin.
Recall that to convert Celsius to Kelvin, one must add 273 or use the equation [tex]T_C+273=T_K[/tex].
Thus, [tex]T_1=(18.1+273)[K]=291.1[K][/tex] and [tex]T_2=(12.5+273)[K]=285.5[K][/tex]
To solve for the requested quantity, note that all of the other units match between beginning and end, so we substitute and solve:
[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]
[tex]\dfrac{(2.61[atm])V_1}{(291.1[K])}=\dfrac{(1.92[atm])(59.9[mL])}{(285.5[K])}[/tex]
[tex]\dfrac{(2.61[atm] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})\bold{V_1}}{291.1[K] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}*\dfrac{291.1[K] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}{2.61[atm]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}=\dfrac{(1.92[atm]\!\!\!\!\!\!\!\!\!\!\!{--})(59.9[mL])}{285.5[K\!\!\!\!\!{-}]}*\dfrac{291.1[K\!\!\!\!\!{-}]}{2.61[atm]\!\!\!\!\!\!\!\!\!\!\!{--}}[/tex]
[tex]V_1=44.928677576[mL][/tex]
Accounting for significant digits, [tex]V_1=44.9[mL][/tex]
