ANALYZE In Europe, fuel economy is measured in liters per 100 kilometers. On a 2500 km road trip a car used 150 liters of fuel. The car used an average of how many liters per 100 km?

Answer:

The three equivalent equations are x+1=4, -5+x=-2, and 2+x=5. The x equals 3.

Step-by-step explanation:

The solution is correct, as both sides of the equation are equal.

To find out how much money Rachel had before she went grocery shopping, we can create an equation using a variable.

Let x represent the amount of money Rachel had before grocery shopping.

The equation for the situation would be: x - $68 = $23

Now, let's solve for x:
Step 1: Add $68 to both sides of the equation:
x = $23 + $68

Step 2: Calculate the sum:
x = $91

So, Rachel had $91 before she went grocery shopping.

To prove the solution is correct, we can plug the value of x back into the equation:
$91 - $68 = $23
$23 = $23

Hence, both are equal.

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It would take approximately 95 minutes for the wick to have 74 mm remaining.

1) Finding the slope (mm per minute):
The wick was initially 150 mm in length and reduced to 110 mm after 50 minutes. To find the slope, we use the formula:

Slope = (change in length) / (change in time)

Slope = (110 mm - 150 mm) / (50 minutes - 0 minutes)
Slope = (-40 mm) / (50 minutes)
Slope = -0.8 mm/minute

2) Constructing the linear equation:
We now have the slope (-0.8) and the initial length (150 mm) to create a linear equation:

Length (L) = initial length + slope × time (t)
L = 150 - 0.8t

3) Predicting the time to have 74 mm remaining:
To find the time, plug in 74 mm for the length (L) in the equation and solve for t:

74 = 150 - 0.8t
76 = 0.8t
t = 95 minutes

So, it would take approximately 95 minutes for the wick to have 74 mm remaining.

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The number of unique rhombuses that can be constructed using this information is three.

When given a 40° angle and an 8 cm line segment, we can construct three distinct rhombuses. A rhombus is a quadrilateral with all sides of equal length, and opposite angles are congruent.

In this scenario, the given 40° angle determines the orientation of the rhombus, while the 8 cm line segment determines its side length. By connecting the endpoints of the line segment with congruent opposite angles, we can create three different rhombuses.

Each rhombus formed will possess an angle measure of 40° and a side length of 8 cm. However, these rhombuses will vary in terms of their overall shape and orientation. Each one represents a unique configuration that satisfies the given angle and side length criteria.

Therefore, the correct answer is that three distinct rhombuses can be constructed using the given information.

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A relative frequency of 0.56 means that out of the total number of observations in a given sample or population, 56% of those observations belong to a particular category or have a certain characteristic.

In other words, it is the proportion or fraction of the observations that fall into that particular category or have that characteristic, relative to the total number of observations. For example, if we had a sample of 100 people and 56 of them had brown hair, then the relative frequency of brown hair would be 0.56 or 56%.

To calculate relative frequency, you divide the frequency of a specific event or category by the total number of observations. In this case, the specific event or category occurs 56% as often as the total events or categories observed.

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To approximate √125.04 using linear approximation, first find the linearization of f(x) = ³√x at x = 125. Then use the point-slope form of the equation to find the equation of the tangent line and plug in x = 125.04 to get the approximation.

To approximate √125.04 using linear approximation and the function f(x) = ³√x, first find the linearization of f(x) at x = 125 in the form y = mx + b. Calculate f(125) and f'(x).Calculate f'(125): Use the point-slope form of the equation
1: Calculate f(125) and f'(x).
f(125) = ³√125 = 5
f'(x) = (1/3)x^(-2/3)
2: Calculate f'(125).
f'(125) = (1/3)(125)^(-2/3) = 1/15
3: Use the point-slope form of the equation y - y1 = m(x - x1) to find the equation of the tangent line.
y - 5 = (1/15)(x - 125)
4: Rearrange to find y in terms of x.
y = (1/15)(x - 125) + 5
5: Determine the values of m and b.
m = 1/15
b = (1/15)(-125) + 5
6: Plug in x = 125.04 to approximate √125.04.
²√125.04 ≈ (1/15)(125.04 - 125) + 5
The linearization of f(x) at x = 125 is y = (1/15)x + b, with m = 1/15 and b = (1/15)(-125) + 5. Using these values, the approximation of √125.04 is (1/15)(125.04 - 125) + 5.

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The type 1 error in this scenario would be rejecting the null hypothesis that the mean level of fluoride in children's drinking water is less than 1.2 ppm, when in reality it is true.

The EPA claims that fluoride in children's drinking water should have a mean level of less than 1.2 ppm to reduce the number of dental cavities. A type 1 error occurs when we reject the null hypothesis when it is actually true. In this case, the null hypothesis (H0) would be that the mean fluoride level is less than or equal to 1.2 ppm, and the alternative hypothesis (H1) would be that the mean fluoride level is greater than 1.2 ppm.

A type 1 error would occur if we incorrectly conclude that the mean fluoride level is greater than 1.2 ppm when, in reality, it is less than or equal to 1.2 ppm. This could lead to unnecessary actions being taken to reduce fluoride levels when they are already at an acceptable level.

In other words, falsely concluding that the mean level of fluoride in the water is above 1.2 ppm and therefore causing harm to the children's dental health by not reducing the number of dental cavities.

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Answer:

To calculate Shannon's new net worth after paying off her credit card, we need to subtract the credit card balance from her total liabilities, and then subtract the result from her net worth:

New liabilities = $15,997 - $7,698 = $8,299

New net worth = $872.17 - $8,299 = -$7,426.83

Based on these calculations, Shannon's new net worth would be -$7,426.83 after paying off her credit card. This indicates that her liabilities still exceed her assets, and she would need to continue working towards reducing her debt and increasing her net worth over time.

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Solids can be "unfolded" to form different net arrangements is a true statement.

A net refers to a flat, two-dimensional shape that can be transformed or manipulated to form a three-dimensional object. A solid has the potential to create a variety of nets through various unfolding methods.

The term "net" for a solid refers to a flat shape that can be folded to form the solid object. it is possible to manipulate a three-dimensional object in various manners in order to produce distinct two-dimensional patterns. One can create various nets by cutting different edges of a cube and arranging the resultant faces.

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a. y/x = 40/1, 76/2, 112/3, 148/4 does not represent a proportional relationship. . y/x = 48/2, 96/3, 144/4, 192/5 does not represent a proportional relationship. c. y/x = 18/1, 54/3, 90/5, 126/7  represents a proportional relationship.

A proportional relationship means that the ratio of y to x is constant throughout the table. Let's check each table:

a. y/x = 40/1, 76/2, 112/3, 148/4

If we simplify the fractions, we get y/x = 40, 38, 37.33, 37. This is not a constant ratio, so this table does not represent a proportional relationship.

b. y/x = 48/2, 96/3, 144/4, 192/5

If we simplify the fractions, we get y/x = 24, 32, 36, 38.4. This is not a constant ratio, so this table does not represent a proportional relationship.

c. y/x = 18/1, 54/3, 90/5, 126/7

If we simplify the fractions, we get y/x = 18, 18, 18, 18. This is a constant ratio, so this table represents a proportional relationship.

d. y/x = 24/1, 21/2, 18/3, 15/4

If we simplify the fractions, we get y/x = 24, 10.5, 6, 3.75. This is not a constant ratio, so this table does not represent a proportional relationship.

Therefore, the table that represents a proportional relationship is c. y/x = 18/1, 54/3, 90/5, 126/7.

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a. By central limit theorem, P(XB- XA >= 0. 2) is approximately 0.0228 under the condition that μA=μB.

b. Yes, we can conclude that the observed difference in sample means does provide evidence that the two population means for the two machines are different.

a. Using the central limit theorem, we know that the sampling distribution of the difference in means (XB - XA) is approximately normal with mean (μB - μA) and standard deviation (σ/√n), where σ is the population standard deviation (σ=1 ounce) and n is the sample size (n=36 for both machines).

So, P(XB - XA >= 0.2) can be calculated by standardizing the difference in means:

Z = (XB - XA - (μB - μA)) / (σ/√n)
Z = (4.7 - 4.5 - 0) / (1/√36)
Z = 2

Looking up the probability of Z being greater than or equal to 2 in a standard normal distribution table, we find P(Z >= 2) = 0.0228.

Therefore, P(XB - XA >= 0.2) is approximately 0.0228 under the condition that μA=μB.

b. The difference in sample means (XB - XA = 0.2) is relatively small compared to the population standard deviation (σ=1 ounce). However, the calculated probability in part a (0.0228) suggests that the observed difference in sample means is statistically significant at a significance level of 0.05 (since P(XB - XA >= 0.2) < 0.05).

Therefore, we can conclude that the observed difference in sample means does provide evidence that the two population means for the two machines are different. However, further testing or analysis may be necessary to confirm this conclusion.

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The volume of the cylinder is approximately 1024π cubic meters.

We are given the base area of the cylinder as 64π square meters, which means that the radius of the cylinder is 8 meters (since the area of a circle is given by πr^2). We are also given that the height of the cylinder is twice the radius, which means that the height is 16 meters.

The volume of a cylinder is given by the formula V = πr^2h, where r is the radius and h is the height. Substituting the given values, we get V = π(8^2)(16) = 1024π cubic meters. Therefore, the volume of the cylinder is approximately 1024π cubic meters.

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Answer:

[tex]3217.0 m ^{3}[/tex]

Step-by-step explanation:

The simplified ratios are:  1:6  &  3:25

To simplify the first ratio, we need to convert the units so they are the same. We can either convert 500g to kilograms or 3kg to grams. Let's convert 3kg to grams since it will be easier to compare with 500g.

3 kg = 3000g

Now the ratio becomes:

500g : 3000g

We can simplify this ratio by dividing both sides by 500:

500g/500 = 1 and 3000g/500 = 6

So the simplified ratio is:

1 : 6

For the second ratio, we need to convert either 12cm to meters or 1m to centimeters. Let's convert 1m to centimeters since it will be easier to compare with 12cm.

1m = 100cm

Now the ratio becomes:

12cm : 100cm

We can simplify this ratio by dividing both sides by 4:

12cm/4 = 3 and 100cm/4 = 25

So the simplified ratio is:

3 : 25

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The derivative of the function f(x) = 2 \sqrt(x) / (8x² + 3x - 9) evaluated at x = 4.

To find f'(x), we need to differentiate the given function f(x) using the power rule and the chain rule of differentiation.

First, we can rewrite the function f(x) as:

f(x) = 2x^{1/2} / (8x² + 3x - 9)

Next, we can differentiate f(x) with respect to x:

f'(x) = d/dx [2x^{1/2} / (8x² + 3x - 9)]

Using the quotient rule of differentiation, we have:

f'(x) = [ (8x² + 3x - 9) d/dx [2x^{1/2}] - 2x^{1/2} d/dx [8x² + 3x - 9] ] / (8x² + 3x - 9)²

Applying the power rule of differentiation, we have:

f'(x) = [ (8x² + 3x - 9)(1/2) - 2x{1/2}(16x + 3) ] / (8x² + 3x - 9)²

Now we can evaluate f'(x) at x = 4 by substituting x = 4 into the expression for f'(x):

f'(4) = [ (8(4)² + 3(4) - 9)(1/2) - 2(4)^(1/2)(16(4) + 3) ] / (8(4)² + 3(4) - 9)²

f'(4) = [ (128 + 12 - 9)(1/2) - 2(4)^(1/2)(67) ] / (128 + 12 - 9)^2

f'(4) = [ 131^(1/2) - 2(4)^(1/2)(67) ] / 12167

Therefore, f'(4) = [ 131^(1/2) - 134(2)^(1/2) ] / 12167.

This is the value of the derivative of f(x) at x = 4.

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hope this helps you

We find that the maximum possible number of animals is 37, with 17 white mice and 20 rabbits.

Let's use the following variables:

x be the number of white mice

Let y be the number of rabbits

Based on the given information, we can create the following system of linear inequalities:

10x + 12y ≤ 420 (maximum time available in environment I)

25x + 15y ≤ 600 (maximum time available in environment II)

We also have the constraints that x and y must be non-negative integers.

To solve this problem, we can use a graphing approach. We can graph each inequality on the same coordinate plane and shade the region that satisfies all the constraints. The feasible region will be the region that is shaded.

However, since x and y must be integers, we need to find the corner points of the feasible region and test each one to see which one gives us the maximum value of x + y.

To find the corner points, we can solve each inequality for one variable and then substitute into the other inequality:

For the first inequality: 12y ≤ 420 - 10x, so y ≤ (420 - 10x)/12

For the second inequality: 15y ≤ 600 - 25x, so y ≤ (600 - 25x)/15

Since y must be a non-negative integer, we can use the floor function to round down to the nearest integer:

For the first inequality: y ≤ ⌊(420 - 10x)/12⌋

For the second inequality: y ≤ ⌊(600 - 25x)/15⌋

We can then plot these two expressions on the same graph and find the points where they intersect. We can then test each point to see if it satisfies all the constraints and if it gives us the maximum value of x + y.

After doing all the calculations, we find that the maximum possible number of animals is 37, with 17 white mice and 20 rabbits.

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The dot plot that most accurately displays Miss Little's class data is illustrated below.

To create a dot plot, we first need to determine the range of the data, which is the difference between the highest and lowest values. In this case, the range is from 8 to 16. We then draw a number line that spans the range, and mark each data point along the line with a dot.

Let's take a look at the first data set: 13, 14, 9, 12, 16, 11, and 10. The range is from 9 to 16, so we draw a number line from 9 to 16. We then mark each data point with a dot above its corresponding value on the number line. So, there will be one dot above 13, one dot above 14, two dots above 9, one dot above 12, one dot above 16, one dot above 11, and one dot above 10.

We repeat this process for the second data set: 9, 8, 10, 10, 11, 15, and 10. The range is from 8 to 15, so we draw a number line from 8 to 15. We then mark each data point with a dot above its corresponding value on the number line. So, there will be one dot above 9, one dot above 8, three dots above 10, one dot above 11, one dot above 15, and zero dots above 14.

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Complete Question:

Miss. Little wants to know how many pairs of shoes each of her students owns. She decides to ask each of her students to write the number of pairs of shoes that he or she owns. This data is displayed in the provided chart. Plot the dot plot that most accurately displays Miss Little's class data.

13 14 9 12 16 11 10

9 8 10 10 11 15 10

The cost for an adult is reduced by approximately 26.33% to $22.10.

The original cost for an adult ticket (X) = $30

The reduced cost for an adult ticket = $22.10

We need to find the percentage decrease (p) from the original cost to the reduced cost:

p = ((Original cost - Reduced cost) / Original cost) * 100

p = (($30 - $22.10) / $30) * 100

p = ($7.90 / $30) * 100

p ≈ 26.33 %

The fee for an adult has notably decreased by approximately 26.33%, now costing a mere $22.10.

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In May, the cost for a child is not changed. The cost for an adult is reduced by p % to $22.10. If the original cost of an adult ticket is $X, (i) calculate p, given that the original cost for an adult ticket is $30.

Answer:

a.x=100 equation: 540=(125·2)+90+(2x)

b. x=3 equation: 6x+18=2x+30

Step-by-step explanation:

a. We know that the interior angles of a pentagon have to equal 540 degrees.

So:

540=125+125+90 (hence the square) + x + x

simplify:

540=340+2x

simplify:

200=2x

x=100

b. Using the alternate exterior angles theorem we can say:
6x+18=2x+30

simplify:

4x+18=30

4x=12

x=3

Answer:

---------------------------------

5) Use the combination formula:

In this case, n = 15 (total students) and r = 5 (students in a group).

Substitute and calculate:

The teacher can combine the students in 3003 ways for the first group.

6) After the first group of five is selected, there are 10 students remaining.

Again use the combination formula, with n = 10 and r = 5:

The teacher can combine the remaining students in 252 ways for the second group.

Entry debits the Depreciation Expense account for $7,000 and credits the Accumulated Depreciation account for the same amount, reflecting the decrease in the value of the machine over time.

To calculate  deprecation using the straight- line  system, we need to abate the residual value from the  original cost of the machine and  also divide the result by the estimated useful life. Using the given values, we have  

Cost of machine = $ 39,000

Residual value = $ 4,000  

Depreciable cost = $ 35,000($ 39,000-$ 4,000)

Estimated useful life =  5 times  

To calculate the periodic  deprecation  expenditure, we divide the depreciable cost by the estimated useful life  

Periodic  deprecation  expenditure = $ 7,000($ 35,000 ÷ 5)

Depreciation Expense $7,000

Accumulated Depreciation $7,000

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The journal entry is as given in figure:

The shape of the distribution in the histogram can tell us about the distribution of weights of fish caught by the fisherman.

Looking at the given data set, we can see that the weights of the fish caught vary from as low as 2 pounds to as high as 15 pounds. The histogram of this data set can help us to  fantasize the distribution of these weights.   Grounded on the shape of the histogram, we can see that the distribution is  kindly slanted to the right, with a long tail extending towards the advanced end of the weights.

This suggests that there were  further fish caught that counted  lower than the mean weight of the catch, with smaller fish caught that counted  further than the mean weight. also, the presence of a many outliers(  similar as the fish that counted 15 pounds) suggests that there may have been some larger or unusual fish caught on the trip.

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The area of the triangle is 6 square units.

Once you have the points they make a 3-4-5 triangle.

The two legs are 3 and 4, so the hypotenuse has to be 5.

Or you could use the Pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5

then find area

A=1/2bh

1/2(3*4)

6

Thus, the area of the triangle is 6 square units.

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The rate at which the cost of production is changing is 1000 hundred dollars per day or $100,000 per day.

To find the rate at which the cost of production is changing, we'll use the given cost function C = 50x + 1000, and the information that production is growing at a rate of 20 cases per day when x = 50 cases.

First, differentiate the cost function with respect to x to get the rate of change of the cost with respect to the number of cases produced (dC/dx):

dC/dx = 50

The derivative, 50, tells us that the cost increases by 50 hundred dollars for each additional case produced.

Now, we're given that dx/dt = 20 cases per day when x = 50 cases. To find dC/dt, the rate at which the cost of production is changing, multiply the rate of change of the cost with respect to the number of cases (dC/dx) by the rate of change of the number of cases with respect to time (dx/dt):

[tex]dC/dt = (dC/dx) × (dx/dt) = 50 × 20[/tex]

dC/dt = 1000

So, the rate at which the cost of production is changing is 1000 hundred dollars per day or $100,000 per day.

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No, the relation r is not a partial order relation.

To prove this, we need to show that r is not reflexive, not antisymmetric, or not transitive.

Since r fails to satisfy the antisymmetric property, it is not a partial order relation.

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The partial derivative of z with respect to x is 5xy + 5xz, and the partial derivative of z with respect to y is 5xz + 5yz.

To find the partial derivatives of z with respect to x and y, we use the chain rule. The chain rule allows us to find the rate of change of a function with respect to one of its independent variables while holding all other independent variables constant.

Using the chain rule, we can find the partial derivatives of z with respect to x and y as follows:

∂z/∂x = 5(yz) + 5x(1)(z)

∂z/∂x = 5xy + 5xz

∂z/∂y = 5(xz) + 5y(1)(z)

∂z/∂y = 5xz + 5yz

Therefore, the partial derivative of z with respect to x is 5xy + 5xz, and the partial derivative of z with respect to y is 5xz + 5yz.

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Answer:

The answer for x is 2

z is 100°

Step-by-step explanation:

80=6x+68

6x=80-68

6x=12

divide both sides by 6

6x/6=12/6

x=2

z=?(empty space)

?(empty space)=z

80+z+z+6x+68=360

Note:6x+68=80

80+80+2z=360

160+2z=360

2z=360-160

2z=200

divide both sides by 2

2z/2=200/2

z=100°

The hypothesis test suggests that there is not enough evidence to reject the claim made by the social media company that over 1 million people log onto their app daily, as the  t-value (-1.732) is less than the critical value (-2.429).

Null hypothesis, The true mean number of people who log onto the app daily is equal to or less than 1 million.

Alternative hypothesis, The true mean number of people who log onto the app daily is greater than 1 million.

Level of significance = 1%

We can use a one-sample t-test to test the hypothesis.

t = (X - μ) / (s / √n)

where X is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.

Substituting the values, we get

t = (998,946 - 1,000,000) / (23,876 / √65)

t = -1.732

Using a t-distribution table with 64 degrees of freedom and a one-tailed test at a 1% level of significance, the critical value is 2.429.

Since the calculated t-value (-1.732) is less than the critical value (-2.429), we fail to reject the null hypothesis. There is not enough evidence to support the claim that more than 1 million people log onto the app daily.

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About 125 students play a sport and about 65 students are in the play.

To find the number of students who play a sport and those who are in the play, we need to use the given percentages and round the answers to the nearest whole.
Find the number of students who play a sport:
Multiply the total number of students (145) by the percentage of students who play a sport (86%).
145 × 0.86 = 124.7
Round the answer to the nearest whole number:
Approximately 125 students play a sport.
Find the number of students who are in the play:
Multiply the total number of students (145) by the percentage of students who are in the play (45%).
145 × 0.45 = 65.25
Round the answer to the nearest whole number:
Approximately 65 students are in the play.

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