A. The mean selling price (in $ thousands) of the homes was computed earlier to be $357. 0, with a standard deviation of $160. 7. Use the normal distribution to estimate the percentage of homes selling for more than $500. 0. Compare this to the actual results. Is price normally distributed? Try another test. If price is normally distributed, how many homes should have a price greater than the mean? Compare this to the actual number of homes. Construct a frequency distribution of price. What do you observe?



b. The mean days on the market is 30 with a standard deviation of 10 days. Use the normal distribution to estimate the number of homes on the market more than 24 days. Compare this to the actual results. Try another test. If days on the market is normally distributed, how many homes should be on the market more than the mean number of days? Compare this to the actual number of homes. Does the normal distribution yield a good approximation of the actual results? Create a frequency distribution of days on the market. What do you observe?

Event A' has a probability of 50% (25% for freshmen + 25% for seniors).

To determine Event A', we need to first identify what Event A represents. Event A is the probability that a student is a sophomore or junior. Since students have equal probabilities of being freshmen, sophomores, juniors, or seniors, the probability of Event A is 50% (25% for sophomores + 25% for juniors).
Event A' is the complement of Event A, which means it includes the other two grade levels not included in Event A, in this case, freshmen and seniors. Therefore, Event A' is the probability that a student is a freshman or a senior. Since students have equal probabilities of being in each grade level, Event A' also has a probability of 50% (25% for freshmen + 25% for seniors).

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the price of one apple after solving the simultaneous equations is $1.45.

Let's denote the price of one apple by "a" and the price of one banana by "b". We can then set up a system of two equations to represent the given information:

4a + 9b = 12.70 (equation 1)
8a + 11b = 17.70 (equation 2)

To solve for the price of one apple, we want to isolate "a" in one of the equations. One way to do this is to multiply equation 1 by 8 and equation 2 by -4, which will allow us to eliminate "b" when we add the two equations together:

(8)(4a + 9b) = (8)(12.70) --> 32a + 72b = 101.60 (equation 3)
(-4)(8a + 11b) = (-4)(17.70) --> -32a - 44b = -70.80 (equation 4)

Adding equations 3 and 4 gives:

28b = 30.80

Solving for "b" yields:

b = 1.10

Substituting this value of "b" into equation 1 gives:

4a + 9(1.10) = 12.70

Solving for "a" yields:

a = 1.45

Therefore, the price of one apple is $1.45.

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The mover is communicating that the weight of the table and 4 chairs combined, represented as t+4C, is greater than or equal to 100 pounds.

The expression t+4C represents the total weight of the table and 4 chairs. The mover's invoice states that this total weight is greater than or equal to 100 pounds, which means that the combined weight of the table and chairs is at least 100 pounds. Therefore, the correct answer is D, "The table and 4 chairs weigh at least 100 pounds."

To solve this mathematically, we can use algebraic inequalities. The inequality t+4C >_ 100 can be rearranged as t >_ 100-4C. This means that the weight of the table t must be greater than or equal to 100 minus four times the weight of a single chair C.

If each chair weighs less than 25 pounds, then the total weight of the table and 4 chairs combined will be at least 100 pounds. So D is correct answer.

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To find the probability that the point lies in the shaded region of the circle, we need to compare the area of the shaded region to the total area of the circle. Let's say the radius of the circle is r.

The area of the shaded region can be found by subtracting the area of the unshaded region from the total area of the circle. The unshaded region is a square with side length equal to the radius of the circle. Therefore, its area is r^2. The total area of the circle is πr^2. So the area of the shaded region is:
πr^2 - r^2 = r^2(π - 1)

Now, if we choose a point at random from the circle, any point has an equal chance of being chosen. So the probability of choosing a point in the shaded region is equal to the area of the shaded region divided by the total area of the circle:

P(shaded) = (r^2(π - 1))/πr^2 = π - 1

Therefore, the probability of choosing a point in the shaded region of the circle is π - 1.

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The measure of the radius of the hexagon rounded to the nearest inch is 14 inches.

The problem presents a hexagon with a central angle of 60º, and the task is to calculate its radius. To do so, we can use the trigonometric relationship between the radius, apothem, and an angle. The apothem is a line segment from the center of a polygon perpendicular to one of its sides. For a regular hexagon, the apothem length is equal to the radius, which we want to find.

The trigonometric relationship for this case is cos(30) = a/c, where a is the apothem and c is the radius. By rearranging the equation to solve for c, we get c = a/cos(30).

Substituting the value of 12 inches for the apothem, we get c = 12/cos(30). Using a calculator, we can find that cos(30) = 0.866, so c = 12/0.866 = 13.855 inches.

To round to the nearest whole number, we get c = 14 inches.

Correct Question :

A regular hexagon is shown. What is the measure of the radius, c, rounded to the nearest inch? use the appropriate trigonometric ratio to solve. 6 in. 10 in. 14 in. 24 in.

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The correct option is the first one, and the domain is the set of real numbers except for x = -6.

The inverse will be a function such that when we take the composition we get the identity, then we can write:

[tex]f(g(x)) = \frac{1}{g(x) - 4} - 6 = x[/tex]

We need to solve that for g(x), we will get:

[tex]\frac{1}{g(x) - 4} - 6 = x\\\\\frac{1}{g(x) - 4} = x +6\\\\g(x) - 4 = \frac{1}{x + 6} \\g(x) = \frac{1}{x + 6} + 4[/tex]

That is the inverse function, and notice that if x = -6 the denominator becomes zero, so that value is not in the domain.

Then the correct option is the first one.

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The width of the rectangle is approximately 5.39 meters.

Let's denote the width of the rectangle by x. According to the problem, the length of the rectangle is 4 meters more than the width, which means that the length can be represented as x+4.

The formula for the area of a rectangle is A = length x width. In this case, we know that the area of the rectangle is 77 square meters, so we can set up the following equation:

77 = (x+4)x

Expanding the brackets, we get:

77 = x² + 4x

Rearranging this equation into standard quadratic form, we get:

x² + 4x - 77 = 0

To solve for x, we can use the quadratic formula:

[tex]x = \frac{(-b ± sqrt(b^2 - 4ac))}{ 2a}[/tex]

Plugging in the values for a, b, and c, we get:

[tex]x = \frac{(-4 ± sqrt(4^2 - 4(1)(-77)))}{ 2(1)}[/tex]

Simplifying this expression, we get:

[tex]x = \frac{(-4 ± sqrt(336)} { 2}[/tex]

[tex]x = \frac{(-4 ± 4sqrt(21))}{ 2}[/tex]

x = -2 ± 2[tex]\sqrt{(21)}[/tex]

Since the width of a rectangle cannot be negative, we discard the negative solution and get:

x = -2 ± 2[tex]\sqrt{(21)}[/tex]

Therefore, the width of the rectangle is approximately 5.39 meters (rounded to two decimal places).

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In order to find the probability of a student playing on the football team given that they play in the band, we'll use conditional probability.

The formula for conditional probability is P(A|B) = P(A and B) / P(B).

In this case, A represents playing on the football team, and B represents playing in the band.

Given:
P(B) = 0.15 (probability of playing in the band)
P(A and B) = 0.03 (probability of playing in the band and on the football team)

Now we can apply the formula:

P(A|B) = P(A and B) / P(B) = 0.03 / 0.15 = 0.2

So, the probability that a student at Kennedy High School plays on the football team given that they play in the band is 0.2 or 20%.

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Answer:

Slope= -1/3

Step-by-step explanation:

The slope is found using (y₂ - y₁) / (x₂ - x₁)

(y₂ - y₁)

So let's do the numerator first with the y. -52-(-32). The two negative signs  make 32 positive so -52 + 32= -20

(x₂ - x₁)

Now the denominator, x. -10-(-70). Same thing here, the two negative signs  make 70 positive so -10 + 70 = 60

(y₂ - y₁) / (x₂ - x₁)

Now put them together so -20/60 which equals -1/3 which the slope

The area of this irregular polygon is 344.5 square units.

To find the area of an irregular polygon, you can divide it into smaller, simpler shapes.

In this case, we can divide the polygon into a rectangle and a right triangle.

The rectangle has a height of 4 and a width of 13, so its area is 4 x 13 = 52 square units.

The right triangle has a base of 13 and a height of (110 - 4 x 13) / 2 = 45, since the total height of the polygon is 110.

Therefore, the area of the right triangle is (1/2) x base x height = (1/2) x 13 x 45 = 292.5 square units.

Adding the areas of the rectangle and the triangle, we get a total area of 52 + 292.5 = 344.5 square units.

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Answer:

18 feet

Step-by-step explanation:

multiply 5 1/3 yards by 3 to find the measurement in feet.

16/3 x 3 = 16

16 + 2 = 18

Helping in the name of Jesus.

a. FA5.6₁₆ = 15x16² + 10x16 + 5 + 6/16 = 4005.375₁₀

b. 725.38₁₀ remains the same in decimal form

c. 3F4.8₁₆ = 3x16² + 15x16 + 4 + 8/16 = 1012.5₁₀

d. 73.25₈ = 7x8 + 3 + 2/8 = 59.3125₁₀

e. FF.F0₁₆ = 15x16 + 15 + 15/16 + 0/256 = 255.9375₁₀

Decimal form is a way of representing numbers using the base 10 number system. In this system, there are 10 digits from 0 to 9 that are used to represent all possible numbers. Each digit in a decimal number has a place value that is determined by its position. The rightmost digit represents units, the next digit to the left represents tens, and so on, with each successive digit representing higher powers of 10.

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The old coordinates are;

W (3, 14)

Y (12, 14)

X (6, 11)

While the new coordinates for the reflected triangle are:

W'' (3, -14)

X'' (6, -11)

Y'' (12, -14).

See the attached image.

A reflection is referred to as a flip in geometry. A reflection is the shape's mirror image. The line of reflection is formed when an image reflects through a line.

A figure is said to mirror another figure when every point in one figure is equidistant from every point in another figure.

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Step-by-step explanation:

there is no explanation about x so wierd

The limit of (sin(9x))/x as x approaches 0 is equal to 9.

To evaluate this limit analytically, we can use L'Hopital's Rule.

Taking the derivative of the numerator and denominator with respect to x, we get:lim (sin(9x))/x = lim (9cos(9x))/1as x approaches 0.

Substituting x = 0, we get:lim (sin(9x))/x = 9cos(0)/1 = 9Therefore, the limit of (sin(9x))/x as x approaches 0 is equal to 9.

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

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The possible propagated error in computing the area of the square is between 19/32 and 21/32 square inches.

(a) Let A be the area of the square tile. The differential of A with respect to the side length x is dA/dx = 2x.

dA ≈ (dA/dx)dx

At the lower end of the possible range for x, we have:

x = 9 31/32 inches

dx = 1/32 inch

dA = (2x)(dx) = (2(9 31/32))(1/32) = 19/32 square inches

At the upper end of the possible range for x, we have:

x = 10 1/32 inches

dx = 1/32 inch

dA = (2x)(dx) = (2(10 1/32))(1/32) = 21/32 square inches

Therefore, the possible propagated error in computing the area of the square is between 19/32 and 21/32 square inches.

(b) The percent error in computing the area of the square is given by:

(percent error) = (error / actual value) x 100

(percent error) = [(21/32 - 100) / 100] x 100% = -79/1600 x 100% ≈ -4.94%.

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The probability of Henry choosing a Milky Way and then a Snickers is 2/27.

1. First, let's find the total number of candy pieces in Henry's candy jar:
3 Snickers + 1 Reese's + 1 Twix + 2 Milky Ways + 2 Skittles Packs = 9 pieces of candy.

2. Next, we'll calculate the probability of choosing a Milky Way on the first pick:
There are 2 Milky Ways and 9 total pieces of candy, so the probability is 2/9.

3. Since Henry puts the candy back, there are still 9 pieces of candy for the second pick. Now, we'll calculate the probability of choosing a Snickers on the second pick:
There are 3 Snickers and 9 total pieces of candy, so the probability is 3/9 (or 1/3).

4. Finally, we'll multiply the probabilities of each individual event to find the probability of both events occurring together (choosing a Milky Way and then a Snickers):
(2/9) * (1/3) = 2/27

So, the probability of Henry choosing a Milky Way and then a Snickers is 2/27.

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The only option left is −5°F, which is colder than −3°F and thus could be the temperature on her thermometer this morning.

The temperature on Skylar's thermometer is measured using a scale that indicates the degree of hotness or coldness of the atmosphere. In this case, we know that the temperature on her thermometer last night was −3°F. The negative sign indicates that the temperature was below the freezing point of water.

We are asked to determine what the temperature could be on her thermometer this morning. Since we are told that the temperature is colder than −3°F, we can eliminate 0°F and 2°F as possible options, as they are warmer than −3°F.

Similarly, −1°F is only slightly colder than −3°F, so it is unlikely to be the temperature on Skylar's thermometer this morning. Therefore, the only option left is −5°F, which is colder than −3°F and thus could be the temperature on her thermometer this morning.

It is important to note that temperature can have a significant impact on our daily lives. Extreme cold temperatures can cause frostbite, hypothermia, and other health hazards, while hot temperatures can lead to dehydration, heat exhaustion, and heat stroke. It is important to dress appropriately and take necessary precautions when the temperature is too low or too high.

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Answer:

There are three methods used to solve systems of equations: graphing, substitution, and elimination.

Step-by-step explanation:

To evaluate the integral of tan inverse v(x+2) dx, we need to make a substitution. Let u = x + 2, then du/dx = 1 and dx= du. Therefore, the final answer is: ∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - tan inverse v(x+2) / v'(x+2) + C

Substituting this back into the integral, we get:
∫ tan inverse v(x+2) dx = ∫ tan inverse v(u) du
Using the formula from the table of integrals, we have:
∫ tan inverse v(u) du = u tan inverse v(u) - ∫ u / (1 + v(u)^2) du
Substituting back u = x + 2, we get:
∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - ∫ (x+2) / (1 + v(x+2)^2) dx
Now, we can use another substitution, let t = v(x+2), then dt/dx = v'(x+2) and dx = dt / v'(x+2).
Substituting this back into the integral, we get:
∫ (x+2) / (1 + v(x+2)^2) dx = ∫ (x+2) / (1 + t^2) dt / v'(x+2)
Using the formula from the table of integrals, we have:
∫ (x+2) / (1 + t^2) dt = tan inverse t + C
where C is the constant of integration.
Substituting back t = v(x+2), we get:
∫ (x+2) / (1 + v(x+2)^2) dx = tan inverse v(x+2) / v'(x+2) + C
Therefore, the final answer is:
∫ tan inverse v(x+2) dx = (x+2) tan inverse v(x+2) - tan inverse v(x+2) / v'(x+2) + C
where C is the constant of integration.

To evaluate the integral of tan inverse v(x+2) dx using substitution, we'll first make a substitution:
Let u = x+2. Then, du = dx.
Now, we can rewrite the integral as:
∫tan^(-1)(v(u)) du
Next, we'll look up the integral of tan^(-1)(v(u)) in a table of integrals. Unfortunately, there isn't a direct formula for this specific integral. However, we can use integration by parts to proceed further.
Let I = ∫tan^(-1)(v(u)) du. Let's choose:
f(u) = tan^(-1)(v(u)) and df(u) = du,
g'(u) = 1 and dg(u) = u du.
Using integration by parts formula:
I = f(u)g(u) - ∫g(u)df(u)
I = u*tan^(-1)(v(u)) - ∫u(1/(1+v^2(u))) du
Now, we'll need to substitute back x+2 for u:
I = (x+2)*tan^(-1)(v(x+2)) - ∫(x+2)(1/(1+v^2(x+2))) dx
This integral doesn't have a simple closed-form solution, so the final answer will remain in the form shown above.

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Chelsey is correct.

The equation of the tangent line is y = 8

Perimeter of BCDE is 28.28

Chelsey is correct. The tangent line at a point on a circle is perpendicular to the radius at that point.

Therefore, it has the same slope as the radius at the point of tangency.

To find the equation of the tangent line at point B(7,8), find the slope of the radius at B.

The radius at B passes through the center of the circle (7,3) and B(7,8), so its slope is:

m = (8 - 3) / (7 - 7) = undefined

This is because the radius is a vertical line. The slope of the tangent line at B is the negative reciprocal of the slope of the radius at B, which is 0.

The equation of the tangent line is:

y - 8 = 0(x - 7)

y = 8

Part B: To find the perimeter of BCDE, we need to find the length of one of its sides and then multiply by 4. Since the square is inscribed in the circle, its diagonal is equal to the diameter of the circle, which is 10 (twice the radius).

Therefore, the length of one side of the square is:

s = 10/√(2) ≈ 7.07

The perimeter of BCDE is:

4s = 4(7.07) ≈ 28.28

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The factored form of the equation is 1/2(y - √5)

To factor this expression, we need to look for any common factors that can be pulled out of both terms. We can see that both terms contain a factor of 1/2, so we can factor that out:

1/2(y - 5 1/2)

Now we need to see if there are any further factors that we can find. The term inside the parentheses, y - 5 1/2, cannot be factored any further using real numbers. However, we can write the expression as y - √5, which shows that it involves the square root of 5.

So the final factored form of the expression is:

1/2(y - √5)

This means that if we multiply 1/2 by (y - √5), we get back the original expression 1/2y - 5 1/2.

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Answer: 5

Step-by-step explanation:

10 + 7h = 45

-10         -10

     7h = 35

divide by 7 to both sides

        h = 5

The volume of the given sphere having radius of 4 units is 267.94 units³.

Given the radius of the sphere (r) = 4 units

To find the volume of the given sphere, we have to substitute the radius in the below volume formula of the sphere,

the volume of the sphere = 4/3 * π * r³

the volume of the given sphere = 4/3 * 3.14 * (4)³        

[π  is approximately equal to 3.14]

the volume of the given sphere = 267.94 units³

So from the above analysis, we can conclude that the volume of the sphere having 4 units radius is 267.94 units³.

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Given question is not having complete information, the complete question is written below:

What is the volume of the sphere having 4 units radius?

The function that can be used to find the total area is: (x^2 + 25) sq. ft.

A square is a type of quadrilateral which has an equal length of sides. So then its area can be calculated as;

area of a square = length x length

We have from the question that; a square surface that has a side length of x feet. So that;

area of the square surface = length * length

                                            = x * x

                                            = x^2 square feet

But since the contractor always adds 25 square feet to the area, he buys extra paint, then the function required is:

total area = (x^2 + 25) sq. ft.

The function is (x^2 + 25) sq. ft.

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Answer:

----------------------

In order to find the total area, we need to consider both the area of the square surface and the extra paint he always adds.

Find the area of the square surface:

Add the extra 25 square feet of paint:

Combining these steps, the function is:

The perimeter of triangle MKN is 34 units.

Based on the information provided, we have a circle with three points of tangency: A, B, and C. Let's consider the triangle formed by these points: MKN.

We are given that the length of AM is 6 and the length of BK is 4. We need to find the perimeter of triangle MKN.

To find the perimeter, we need to know the lengths of all three sides. However, the length of side AC is not provided.

Without additional information, we cannot determine the lengths of sides MN and KN or calculate the perimeter of triangle MKN.

Therefore, with the given information, we cannot find the perimeter of triangle MKN or provide a numerical answer

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