A solution of ammonia has a ph of 11.8. What is the concentration of OH- ions in the solution?

Answer:

Explanation:

1. 40.08 + 35.45(2) = 110.98

2. 14.01 + 1.01(5) + 16.00 = 35.06

3.  107.87 + 12.01(2) + 1.01(3) + 16.00(2) = 165.91

4. 137.33(3) + 30.97(2) + 16.00(8) = 601.93

5. 26.98(2) + 16.00(9) + 12.01(3) = 216.06

6. 65.39 + 14.01(2) + 16.00(6) = 189.41

Check me if I'm wrong.

Answer:

5SiO2 + 2CaC2 --> 5Si + 2CaO + 4CO2

4NH3 + 5O2 --> 4NO + 6H2O

Answer:

Unsure there's not enough information to answer

Explanation:

Which of the following is NOT a true statement about gases?

Answer:

Deep partial-thickness wounds

Answer:

I think that the answer is N20:2(14.01)+1(16.06)=44.02g/mol(c) fluorine Di nitrogen monoxide contains how many mom 6.022 x

1023 mol N20

Answer:

6.25

Explanation:

Because 2.5 is half and idk know how to explain but  yeah

Answer:

H2SO4 = 0.3885 mol L-1

Explanation:

We need (i) a stoichiometric equation:

H2SO4 + 2NaOH = NaSO4 +2H2O

1:2

And (ii) equivalent quantities of sodium hydroxide

Moles of NaOH  = 10x [tex]10^{-3}[/tex]L x 0.777mol [tex]L^{-1}[/tex] = 0.00777 mol

So H2SO4  = (0.5 x 0.00777 mol) / 0.001

= 0.3885 mol L-1

Answer:

[tex]V_2=36.84L[/tex]

Explanation:

Hola,

En este caso, podemos usar la ley de Boyle, la cual nos permite analizar el comportamiento volumen-presión en un gas ideal de manera inversamente propocional:

[tex]P_1V_1=P_2V_2[/tex]

Así, dado el volumen y la presión inicial, la cual se convierte a atmósferas (760 torr = 1atm), calculamos el volumen final a 1 atm como se muestra a continuación:

[tex]V_2=\frac{P_1V_1}{P_2}=\frac{700torr*\frac{1atm}{760torr}*40l }{1atm}\\ \\V_2=36.84L[/tex]

Saludos!

Answer:

[tex]V_2=~36.84~Litros[/tex]

Explanation:

En este caso tenemos diferentes valores de volumen y presión para un primer estado:

[tex]V_1=~40~Litros[/tex]

[tex]P_1=~700~torr[/tex]

Y tenemos valores de presión para un segundo estado:

[tex]V_2=~?[/tex]

[tex]P_2=~1~atm[/tex]

Necesitamos una relación entre volumen y presión para poder hallar nuestra incognita ( [tex]V_2[/tex]). Nuestra relación es la ley de Boyle:

[tex]P_1*V_1=P_2*V_2[/tex]

Ahora bien, tenemos una unidad diferente para el presión en [tex]P_2[/tex] (atm), debemos hacer una conversión. Esta conversión puede hacerse si sabemos que 1 atm = 760 torr por lo cual [tex]P_2=760~torr[/tex]

Ahora podemos reemplazar en la ecuación:

[tex]700~torr*40~Litros=760~torr*V_2[/tex]

[tex]V_2=\frac{700~torr*40~Litros}{760~torr}[/tex]

[tex]V_2=~36.84~Litros[/tex]

El volumen sera de 36.84 Litros

Espero que ayude!

Answer:

[tex]n_{Na_2CO_3}=0.28molNa_2CO_3[/tex]

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

[tex]Na_2CO_3(aq)+CaCl_2(aq)\rightarrow CaCO_3(aq)+2NaCl(aq)[/tex]

Hence, given the solution of calcium chloride, we can compute its reacting moles:

[tex]n_{CaCl_2}=0.35\frac{mol}{L}*803.1mL*\frac{1L}{1000mL}= 0.28molCaCl_2[/tex]

Thus, by knowing there is a 1:1 molar ratio between sodium carbonate and calcium chloride, we can easily compute the moles of sodium carbonate needed for a complete precipitation as shown below:

[tex]n_{Na_2CO_3}=0.28molCaCl_2*\frac{1molNa_2CO_3}{1molCaCl_2} \\\\n_{Na_2CO_3}=0.28molNa_2CO_3[/tex]

Best regards.

Answer:

3.01 * 10 ^ 23 atoms of Pt

Explanation:

1 mole of Pt contains 6.02 * 10 ^ 23 atoms of Pt

195.084 g of Pt has  6.02 * 10 ^ 23 atoms of Pt  

97.6 g = .5 moles so  

97.6 g of Pt has 3.01 * 10 ^ 23 atoms of Pt

The 97.6 grams of platinum contains [tex]3.011\times 10^{23}[/tex] atoms.

Given:

The mass of platinum = 97.6 grams

To find:

The number of platinum atoms in 97.6 grams.

Solution:

Mass of platinum = 97.6 g

Moles of platinum =[tex]\frac{97.6g}{195.084 g/mol}=0.500 mol[/tex]

According to the mole concept:

1 mole = Avogadro Number = [tex]N_A=[/tex] [tex]6.022\times 10^{23} atoms/ molecules/ions[/tex]

The number of platinum atoms in 0.500 moles of platinum:

[tex]=0.500\times 6.022\times 10^{23} atoms\\\\=3.011\times 10^{23} atoms[/tex]

The 97.6 grams of platinum contains [tex]3.011\times 10^{23}[/tex] atoms.

Learn more about the mole concept here:

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Answer:

B. release oxygen as a product

Explanation:

Answer:

Water that is present beneath the Earth's surface

Answer:

1. 2.17 dm^3

2. 109.1 dm^3

3. 0.398 atm

Explanation:

1. Considering the equation of the reaction;

Number of moles of chlorine gas in 3.44 g= 3.44/2(35.5)= 0.0485 moles

Since we can see from the equation that

1 mole of chlorine gas yields 2(22.4) dm^3 of HCl

0.0485 moles of chlorine gas yields 0.0485 moles × 2(22.4)dm^3/1= 2.17 dm^3

2. Note that 1 mole of Kr occupies 22.4 dm^3

Therefore 4.87 moles of Kr will occupy 4.87 × 22.4 dm^3/1 = 109.1 dm^3

3. From PV= nRT

n= 0.0485 moles

V= 4.55 L

T= 455 K

P= the unknown

R= 0.082 atm dm^3K-1mol-1

P= nRT/V

P= 0.0485 moles × 0.082 atm dm^3K-1mol-1 × 455/4.55

P= 0.398 atm

Answer:

1) volume of HCl = 2.17 L HCl

2) volume of Kr = 109.09 L

3) Pressure of HCl = 0.796 atm

Explanation:

Step 1: Data given

Mass of Cl2 : 3.44 grams

Molar mass Cl2 = 70.9 g/mol

STP = 1atm and 273 K

Step 2: The balanced equation

H2(g) + Cl2(g) → 2HCl(g)

Step 3: Calculate moles of Cl2

Moles Cl2 = mass/ molar mass Cl2

Moles Cl2 = 3.44 grams / 70.9 g/mol

Moles Cl2 = 0.0485 moles

Step 4: Calculate moles HCl

For 1 mol H2 we need 1 mol Cl2 to produce 2 moles HCl

For 0.0485 moles Cl2 we'll have 2*0.0485 = 0.097 moles HCl

Step 5: Calculate volume of HCl

For 1 mol we have 22.4 L

For 0.097 moles we have 22.4 * 0.097 = 2.17 L HCl

Step 1: Data given

Moles of Kr = 4.87 moles

STP = 1 mol, 1atm and 273 K and 22.4 L

Step 2: Calculate volume at STP

1 mol has a volume of 22.4 L

4.87 moles has a volume of 22.4 L * 4.87 = 109.09 L

Step 1: Data given

Mass of Cl2 : 3.44 grams

Molar mass Cl2 = 70.9 g/mol

Volume = 4.55 L

Temperature = 455 K

Step 2: The balanced equation

H2(g) + Cl2(g) → 2HCl(g)

Step 3: Calculate moles of Cl2

Moles Cl2 = mass/ molar mass Cl2

Moles Cl2 = 3.44 grams / 70.9 g/mol

Moles Cl2 = 0.0485 moles

Step 4: Calculate moles HCl

For 1 mol H2 we need 1 mol Cl2 to produce 2 moles HCl

For 0.0485 moles Cl2 we'll have 2*0.0485 = 0.097 moles HCl

Step 5: Calculate pressure of HCl

p*V = n*R*T

⇒with p = the pressure of HCl = TO BE DETERMINED

⇒with V = the volume = the volume of HCl = 4.55 L

⇒with n = the moles of HCl = 0.097 moles

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 455 K

p = n*R*T / V

p = (0.097 moles * 0.08206L*atm/mol*K * 455 K) / 4.55 L

p = 0.796 atm

Answer:

v = 500 milliliters

Explanation:

[tex]HNO_{3}[/tex]  ⇒  [tex]H^{+} + NO^{3-}[/tex]

[tex]KOH[/tex]  ⇒  [tex]K^{+} + OH^{-}[/tex]

1 [tex]H^{+}[/tex] to 1 [tex]OH^{-}[/tex]

[tex]\frac{0,5}{V} = \frac{0,1}{100} \\\\v * 0,1 = 50\\v = 500 milliliters[/tex]

(d) greenhouse effect

Answer:

B. cloud formation

Explanation:

The event that will most likely occur is cloud formation. This is because Rising Air is the key process in the production of clouds and precipitation. This occurs because the air rises and as it rises it begins to expand, it expands so much so that the temperature of the air begins to decrease and humidity rises  until  cloud droplets begin forming as the excess water vapor condenses on the the air particles.

Answer: constant

Explanation:

Processes like nitrogen fixation, lightning, and the cycle results the nitrogen atmosphere to  remain less constant

Answer:

[tex]V_2=188mL[/tex]

Explanation:

Hello,

In this case, for dilution processes, the initial moles must be the same to the final moles, therefore, only the volumes and molarities change from the beginning to the end of the dilution:

[tex]M_1V_1=M_2V_2[/tex]

In this case, we are asked to compute the new or final volume, so we simply solve for it as shown below:

[tex]V_2=\frac{M_1V_1}{M_2}=\frac{120mL*1.3M}{0.83M}\\ \\V_2=188mL[/tex]

Best regards.

Answer:

Conditions which results in deviating a gas from "ideal" behavior are

1. Low Temperature

2. High Temperature

Explanation:

Ideal gas according to the kinetic model theory states that the conditions that apply are high temperatures where kinetic energy and low pressure is too high and the interactions in between and the container are negligible. Hence, the deviations of ideal gas falls when there is low temperature and high pressure.

Answer:

2.5milligram

Explanation:

Due to Kr-42 the 20mg will diluted to the experinental evluation

Answer:

Yes they do

Explanation:

This is because the light that shines on the pots and pans reflect back considering that they are shinny.

Answer:

Polished shiny surfaces reflect light because they have a even surface.

Explanation:

The polished shiny surfaces being smooth and lustrous, absorb very little amount of light and reflect more.

Pls Brainliest!!

Answer:

Explanation:So if a neutron or two is added or removed from the nucleus, then the ... For example Cl–35 has an atomic mass of 35 u (17 protons and 18 neutrons), while Cl–37 ... Calculate the mass contribution of chlorine–35 to the average relative atomic mass ... Which of the following are isotopes of 3517Cl? 1735Cl. 3517Cl. 3717Cl.

Answer:

Yes is incorrect

Explanation:

not all veins carry blood rich in CO2 , the pulmonary vein carries blood with O2 which means that not all veins carry blood rich in CO2

Answer:

The correct answer is 1.61 L.

Explanation:

Based on the given information, 3.712 grams of Mg reacts with 104.2 ml of 1.385 mol per L HCl at SATP, there is a need to find the amount of hydrogen gas produced in liters.  

The chemical reaction taking place in the given case is,  

Mg + 2HCl = MgCl2 + H2

The reacting moles of each reactants is,  

Moles of Mg = 3.712 g/24.305 g = 0.153 moles

Moles of HCl = 1.385 mol/L * 0.1042 L = 0.144 moles

From the reaction it is clear that Mg and HCl are present in 1:2 molar ratio. Therefore, 0.153 moles of Mg can completely react with 0.306 moles of HCl. However, the moles of HCl obtained in the given case is only 0.144 moles, thus, HCl is a limiting reactant.  

Now the moles of hydrogen produced is,  

n = 0.144 moles of HCl * (1 mole H2/2 mol HCl) = 0.072 moles

Finally to find the liters of hydrogen gas produced, the ideal gas equation is used, that is, PV = nRT

At STAP, the value of T is 273 K and pressure is 1 atm, the value of R is 0.082 atm.L/mol.L. Now putting the values we get,  

PV = nRT

V = nRT/P

V = 0.072 mol * 0.082 atm.L/mol.L*273/ 1 atm

V = 1.61 L

Answer:

1. 2.17 dm3 VOLUME OF HCl IS PRODUCED WHEN 3.44 g OF Cl2 REACT AT STP

2. 4.87 MOLE OF Kr AT STP CONTAINS 109.088 dm3 .

3. THE PRESSURE WHEN 3.44 g OF Cl2 are reacted at 4.55 L AT 455 K IS 0.77 atm

Explanation:

1 Volume of HCl if 3.44 g of Cl2 are reacted at STP?

Equation for the reaction:

H2 + Cl2 ---------> 2HCl

1 mole of Cl2 reacts to form 2 mole of HCl

At STP, 1 mole of a gas is equal to the molar mass of the gas sample

35.5 * 2 g of Cl2 reacts to form 2 mole of HCl

3.44 g of Cl2 will react to form  ( 3.44 * 2 / 71 ) mole of HCl

= 0.0969 mole of HCl

1 mole of HCl = 22.4 dm3

0.0969 mole of HCl = ( 22.4 * 0.0969 / 1)

= 2.17056 dm3

The volume of HCl is 2.17 dm3 when 3.44 g of Cl2 are reacted at STP.

2. What volume does 4.87 mol of Kr have at STP?

1 mole of a substance is 22.4 dm3 of the sample

1 mole of Kr = 22.4 dm3

4.87 mole of  Kr = 4.87 * 22.4

= 109.088 dm3

4.87 mole of Kr at STP contains 109.088 dm3 volume

3. Whta pressure of HCl is generated if 3.44 g of Cl2 are reacted at 4.55 L at 455 K

Using the formula:

PV = nRT

V = 4.55 L

R = 0.082 L atm/ mol K

T = 455 K

m = 3.44 g

n = mass / molar mass

molar mass = ( 1 + 35.5) = 36.5 g/mol

n = 3.44 g / 36.5 g/mol

n = 0.094 mole

P = nRT / V

P = 0.094 * 0.082 * 455 / 4.55

P = 3.50714 / 4.55

P = 0.7708 atm

The pressure of HCl if 3.44 g of Cl2 are reacted at 4.55 L and 455 K is 0.7708 atm.

1. The volume of HCl generated is 2.15 L

2. The volume of 4.87 moles of Kr is 109.088 L

3. The pressure of HCl generated is 0.788 atm

1. Determination of the volume of HCl generated

Mass of Cl₂ = 3.44 g

Molar mass of Cl₂ = 2 × 35.5 = 71 g/mol

Mole = mass / molar mass

Mole of Cl₂ = 3.44 / 71

H₂ + Cl₂ —> 2HCl

From the balanced equation above,

1 mole of Cl₂ reacted to produce 2 moles of HCl.

Therefore,

0.048 mole of Cl₂ will react to produce = 0.048 × 2 = 0.096 mole of HCl

At standard temperature and pressure (STP),

1 mole of HCl = 22.4 L

Therefore,

0.096 mole of HCl = 0.096 × 22.4 = 2.15 L

Thus, the volume of HCl generated at STP is 2.15 L

2. Determination of the volume of 4 moles of Kr at STP

At standard temperature and pressure (STP),

1 mole of Kr = 22.4 L

Therefore,

4.87 moles of Kr = 4.87 × 22.4 = 109.088 L

Thus, 4.87 moles of Kr has a volume of 109.088 L at STP

3. Determination of the pressure of HCl generated.

Number of mole (n) of HCl obtained = 0.096 mole

Volume (V) = 4.55 L

Temperature (T) = 455 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 4.55 = 0.096 × 0.0821 × 455

P × 4.55 = 3.586128

Divide both side by 4.55

P = 3.586128 / 4.55

Thus, the of HCl generated is 0.788 atm

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Answer:

the answer is C Ozone

hope that helps

Answer:

C6H12O6

Explanation:

Just use the table method like I did and compared the molecular mass with the mass of the empirical formula.

Answer:  NaNO3 (Sodium Trioxonitrate (V) )

Explanation:

The equation of the reaction is; HNO3 + NaOH -----> H2O + NaNO3

Answer: its B

Explanation: