1 ) If the supplement of an angle is 30 degrees more than the measure of the angle, what is the measure of the angle?

2) If the supplement of an angle is 12 degrees less than twice the measure of the angle, what is the measure of the angle?

The value of the expression 11C7 is 330. This can be calculated using the formula for combinations, which is nCr = n!/r!(n-r)!, where n is the total number of objects and r is the number of objects being selected. So, the correct answer is A).

To calculate the value of the expression 11C7, we need to use the formula for combinations or binomial coefficients, which is

nCr = n! / (r! * (n-r)!)

where n is the total number of items, r is the number of items to be chosen, and ! denotes the factorial operation (the product of all positive integers up to n).

In this case, we have

n = 11 and r = 7

So, we can substitute these values into the formula

11C7 = 11! / (7! * (11-7)!)

= 11! / (7! * 4!)

= (11 * 10 * 9 * 8 * 7 * 6 * 5) / (4 * 3 * 2 * 1)

= 330

Therefore, the value of the expression 11C7 is 330. So, the correct answer is A).

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--The given question is incomplete, the complete question is given

"Pls respond quick | what is the value of the expression? ₁₁C₇

a)330

b)1,663,200

c)5040

d)7920"--

We may use the identity (a + b)³ = a³ + 3a²b + 3ab² + b³ to get 970299, 1061208, and 992016008 for (i), (ii), and (iii), respectively.

Using the identity (a + b)³ = a³ + 3a²b + 3ab² + b³ allows us to expand and simplify the expressions by distributing and collecting like terms. Any integer's cubes can be calculated using this method.

(i) Using the identity, we can write 99 as 100 - 1 and get:

= (99)³

= (100 - 1)³

= 100³ - 3(100²)(1) + 3(100)(1²) - 1³

= 970299

(ii) We can denote 102 as 100 + 2 and use the identity to obtain:

= (102)³

= (100 + 2)³

= 100³ + 3(100²)(2) + 3(100)(2²) + 2³

= 1061208

(iii) Using the identity, we may write 998 as 1000 - 2 and get:

= (998)³

= (1000 - 2)³

= 1000³ - 3(1000²)(2) + 3(1000)(2²) - 2³

= 992016008

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The step which include the mistake is step 5.

The correct answer choice is option D.

[tex] \frac{1 + {3}^{2} }{5} + | - 10| \div 2[/tex]

Step 1:

[tex] = \frac{1 + {3}^{2} }{5} + 10 \div 2[/tex]

Step 2:

[tex] = \frac{1 + 9 }{5} + 10 \div 2[/tex]

Step 3:

[tex] = \frac{10}{5} + 10 \div 2[/tex]

Step 4:

[tex] = 2 + 10 \div 2[/tex]

Step 5:

[tex] = 12 \div 2[/tex]

Step 6:

[tex] = 6[/tex]

The step which include the mistake is step 5; because it didn't follow the rule of PEMDAS

P = parenthesis

E = exponents

M = Multiplication

D = Division

A = addition

S = subtraction

Therefore,

It should be;

[tex] = 2 + 5[/tex]

[tex] = 7[/tex]

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The parametric equations to plot points. The sixth point is (0, 1).

The parametric equations given are:

x = sin t

y = 1 − cos t

To plot points for these equations, we can choose some values of t and substitute them in the equations to get the corresponding values of x and y. Here are some points we can plot:

When t = 0, x = sin 0 = 0 and y = 1 − cos 0 = 1.

So the first point is (0, 1).

When t = π/4, x = sin (π/4) = √2/2 and y = 1 − cos (π/4) = 1 − √2/2.

So the second point is (√2/2, 1 − √2/2).

When t = π/2, x = sin (π/2) = 1 and y = 1 − cos (π/2) = 0.

So the third point is (1, 0).

When t = π, x = sin π = 0 and y = 1 − cos π = 2.

So the fourth point is (0, 2).

When t = 3π/2, x = sin (3π/2) = −1 and y = 1 − cos (3π/2) = 0.

So the fifth point is (−1, 0).

When t = 2π, x = sin 2π = 0 and y = 1 − cos 2π = 1.

So the sixth point is (0, 1).

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The population density of the fish is 0.0061sharks/m²

Population density is a measurement of population per unit land area. Therefore the population density can be expressed as;

population density = population/ area

The number of fish in the tank is 3

The area of the tank is given as!

A = 2πr( r+h)

h = 3meters

r = d/2 = 15/2 = 7.5

A = 2 × 3.14 × 7.5(7.5+3)

A = 47.1( 10.5)

A = 494.55 m²

Therefore population density = 3/494.55

= 0.0061sharks/m²

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3/4 + (1/3 divided by 1/6) - (-1/2) when simplified give 3 1/4

How to determine this

3/4 + (1/3 divided by 1/6) - (-1/2)

3/4 + (1/3 ÷ 1/6) - (-1/2)

Using the rule of BODMAS

Whee B = Bracket

O = Order

D = Division

M = Multiplication

A = Addition

S = Subtraction

By removing the bracket

3/4 + 1/3 ÷ 1/6 + 1/2

By dividing

3/4 + 1/3 * 6/1 + 1/2

3/4 + 6/3 + 1/2

3/4 +2 + 1/2

By finding the LCM

The LCM is lowest common factor of the denominator which is 4

= [tex]\frac{3+8+2}{4}[/tex]

= 13/4

= 3 1/4

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If combine harvester able to cut a 2450 square meters field in 5 hours and other one can do the same job in 7 hours then the area that the two combines cut in 9 hours is equals to the 7,560 square meters.

We have two harvester which can cut a area into different time.

The time taken by first harvester cuts into 2450 square meters field =5 hours.

The time taken by second harvester cuts into 2450 square meters field = 7 hours.

We have to determine the area can the two combines cut in 9 hours.

Here, total work = 2450 square meters

Work ability or efficiency of first harvester = 2450/5 = 490

Work efficiency of second harvester

= 2450/7= 350

Efficiency of both harvester in combine

= 350 + 490 = 840

So, area they cut into 9 hours = 840 × 9

=7560 square meters

Hence, required area is 7,560 square meters.

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Answer:

67. 50

Step-by-step explanation:

15x4.50= 67.5

The height of the ice block must be 10 inches, the length and width could be any combination of dimensions that multiply together to equal 48 square inches.

The overall number of cube units that the cube totally occupies is the definition of a cube's volume. Volume is simply the total amount of space an object takes up. The cube's volume can be calculated using the formula a3 where an is the cube's edge.

given,

To check if the height of the ice block must be 10 inches to have a volume of 480 cubic inches, we can use the formula for the volume of a rectangular solid:

V = l * w * h

where l represents the length, w represents the measurement of width, while h is the peak, and V is the volume.

Since the volume is given as 480 cubic inches, and the height is specified as 10 inches, we can write:

480 = l * w * 10

Dividing both sides by 10, we get:

48 = l * w

This means that the product of the length and width must be equal to 48 square inches in order for the block of ice to have a volume of 480 cubic inches with a height of 10 inches.

There are many possible dimensions that satisfy this condition. For example, the block of ice could have dimensions of 8 inches by 6 inches by 10 inches, or 12 inches by 4 inches by 10 inches, or 16 inches by 3 inches by 10 inches, and so on.

Therefore, while the height of the ice block must be 10 inches, the length and width could be any combination of dimensions that multiply together to equal 48 square inches.

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The critical point x = 0 does not yield a local minimum or maximum. The function is always decreasing.

To find the critical points and intervals for the function y = x^3 / (x^2 + 1), we'll first find the derivative using the Quotient Rule:

y'(x) = [(x^2 + 1)(3x^2) - x^3(2x)] / (x^2 + 1)^2

y'(x) = (3x^4 + 3x^2 - 2x^4) / (x^2 + 1)^2

y'(x) = (x^2 - 2x^2) / (x^2 + 1)^2

Now, we'll find the critical points by setting the derivative equal to zero:

0 = (x^2 - 2x^2) / (x^2 + 1)^2

0 = x^2(1 - 2) / (x^2 + 1)^2

0 = -x^2 / (x^2 + 1)^2

This equation is equal to zero only when x = 0. So, the critical point is x = 0.

Next, we'll use the First Derivative Test to determine if the critical point yields a local min or max. To do this, we'll evaluate the sign of y'(x) to the left and right of x = 0.

1. Left of x = 0 (for example, x = -1):
y'(-1) = (-1)^2(1 - 2) / (-1^2 + 1)^2 = -1 / 1^2 = -1 (negative)

2. Right of x = 0 (for example, x = 1):
y'(1) = (1)^2(1 - 2) / (1^2 + 1)^2 = -1 / 2^2 = -1/4 (negative)

Since the derivative is negative on both sides of the critical point, the function is decreasing for all x. Thus, the critical point x = 0 does not yield a local minimum or maximum. The function is always decreasing.

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(I) The new selling price per kilogram of the tomatoes is 0.4576.

(II) The percentage profit on the whole transaction is 24.77% if she threw away 5kg of bad tomatoes.

The new selling price is calculated as follows;

The cost per kilogram of the tomatoes is;

Cost per kg = Total cost / Total weight

Cost per kg = 52 / 130

Cost per kg = 0.4

Selling price per kg = Cost per kg + (Profit percentage x Cost per kg)

Selling price per kg = 0.4 + (0.3 x 0.4)

Selling price per kg = 0.52

The new selling price per kilogram is:

= Selling price per kg - (Reduction percentage x Selling price per kg)

= 0.52 - (0.12 x 0.52)

= 0.4576

The total revenue from selling the tomatoes is calculated as;

The woman sold half of the 130kg of tomatoes, = 130 / 2 = 65kg

Revenue = (amount sold x selling price per kg) + (amount left x new selling price per kg)

Revenue = (65 x 0.52) + (65 x 0.4576)

Revenue = 33.8 + 29.68

Revenue = 63.48

New total cost = Total cost / Total weight x (Total weight - Bad tomatoes)

New total cost = 0.4 x (130 - 5)

New total cost = 50.6

The profit on the whole transaction  is calculated as;

Profit = Total revenue - New total cost

Profit = 63.48 - 50.6

Profit = 12.88

The profit percentage on the whole transaction is calculated as;

Profit percentage = (Profit / Total cost) x 100%

Profit percentage = (12.88 / 52) x 100%

Profit percentage = 24.77%

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If a data set is normally distributed with a mean of 27 and a standard deviation of 3. 5, the z-score for a value of 25 is -0.57.

To find the z-score for a value of 25 in a normally distributed data set with a mean of 27 and a standard deviation of 3.5, we use the formula:

z = (x - μ) / σ

where:
x = the given value (25)
μ = the mean (27)
σ = the standard deviation (3.5)

Plugging in the values, we get:

z = (25 - 27) / 3.5
z = -0.57

Rounding to the nearest hundredth, the z-score for a value of 25 is -0.57.

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The correct statement that interprets the function M(t) is:

B) The total municipal debt in llinois was $43.38 billion in 2000 and increases about 5.2% each year.

According to the question the function M(t) =41.24(1.052)^t represents the total municipal debt for the state of llinois in billions of dollars, where t is the number of years since 2000.

The incorrect options are:

Option A is incorrect as the function does not represent an increase of 1.052% each year, but rather an increase of 5.2% each year (since 1.052=1+0.052)

Option C is also incorrect because it suggests an increase of 105.2% each year, which is not possible.

Option D is also incorrect because it states that the total municipal debt was $41.24 billion in 2000, and increases about 5.2% each year.

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The sequence (n){(1-2)/(3^n+1) + 3} is bounded and decreasing. The GLB is 3 and the LUB is 1.

To determine the boundedness and monotonicity of the sequence, we can look at the limit as n approaches infinity.

Taking the limit of the sequence, we have:

lim(n→∞) [(1-2)/(3^n+1) + 3] = 3

This means that the sequence approaches a finite value as n gets larger, so the sequence is bounded.

Next, to check the monotonicity of the sequence, we can take the first derivative of the sequence with respect to n:

d/dn [(1-2)/(3^n+1) + 3] = [(2-1)(-ln3)(3^n+1)]/[(3^n+1)^2]

Simplifying, we get:

d/dn [(1-2)/(3^n+1) + 3] = (-ln3)/(3^n+1)^2

Since the derivative is negative for all n, the sequence is decreasing.

To find the GLB and LUB, we can use the fact that the sequence is decreasing and bounded. Since the sequence approaches 3 as n approaches infinity, 3 is the lower bound.

To find the upper bound, we can use the fact that the sequence is decreasing and start with the second term, which is 2. Therefore, the upper bound is 2. Since 1 < 2, we can conclude that the LUB is 1.

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Answer:

19/2

Step-by-step explanation:

133 = 7 × 19

14 = 7 × 2

133/14 = 19/2

Hence Simplified

PJ's design is best described as a randomized controlled trial (RCT), which is a type of experimental study that randomly assigns participants to a control group or an intervention group.

In this case, the control group did not receive the soft music during high stakes science testing, while the intervention group did. By administering both a pretest and a posttest, PJ was able to measure any differences in performance between the two groups. The use of randomization helps to ensure that any differences observed between the groups can be attributed to the intervention (soft music) rather than to other factors that may have influenced the results. Overall, PJ's RCT design is a rigorous way to test the effects of a specific intervention on a particular outcome.

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Answer:

The expression 625y^2 + 400y - 36 + 20z - z^2 can be rearranged and simplified as follows:

625y^2 + 400y - 36 + 20z - z^2

= (25y)^2 + 2(25y)(8) + 8^2 - 8^2 - 36 + 20z - z^2 (adding and subtracting (25y)(8) and 8^2 inside the parentheses)

= (25y + 8)^2 - (8^2 + 36) + 20z - z^2 (expanding the squared term and simplifying)

= (25y + 8)^2 - 100 + 20z - z^2 (simplifying)

Therefore, the simplified form of the expression is:

(25y + 8)^2 - 100 + 20z - z^2.

Note that this expression can also be written as:

(5y + 2)^2(5y - 12)^2 - (z - 10)(z + 10),

Using the difference of squares factorization. However, this is not necessarily simpler than the previous form, and it depends on the context and the purpose of the expression.

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The solution to the composite function (f + g)(x) is: 8x + 7

Composite functions are said to occur when the output of one function is used as the input of another. If we have a function f and another function g, it means that the function fg(x), said as “ f of g of x”, is the composition of the two functions.

Now, we are given two functions as:

f(x) = x + 3

g(x) = 7x + 4

Thus, we can say that:

(f + g)(x) = f(x) + g(x)

= x + 3 + 7x + 4

= 8x + 7

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The correct answer is option (d) (x, y) → (x + 1/3, y + 1/3).

The dilation is a type of transformation that changes the size of the object, but not the shape. It can be represented by a rule in which each point of the original object is multiplied or divided by a constant factor. In this case, since the center of dilation is the origin, we can find the constant factor by dividing the coordinates of the corresponding points of the two rectangles.

Let's take the point Q(x, y) in rectangle QRST and its corresponding point Q'(x', y') in rectangle Q'R'S'T'. Since the dilation is centered at the origin, we have:

x' = k * x

y' = k * y

where k is the constant factor of dilation. We can find k by dividing the corresponding sides of the rectangles. For example, the length of QR is 4 units, and the length of Q'R' is 4/3 units. Therefore, k = 4/3.

Using this value of k, we can find the coordinates of any point in rectangle QRST that corresponds to a point in rectangle Q'R'S'T'. For example, point R(6, 2) in rectangle QRST corresponds to point R'(6 + 1/3, 2 + 1/3) = (20/3, 7/3) in rectangle Q'R'S'T'.

Hence, the correct answer is (x, y) → (x + 1/3, y + 1/3).

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The 95% confidence interval is: b) -1.38 to d) 3.44.

The value of the sample mean difference is 1.74, which falls:

b) within.

Here, we have to determine the 95% confidence interval for the difference of sample means and complete the statements, we need to use the sample mean difference provided and the confidence interval limits given as options.

We'll compare the sample mean difference to the interval to see if it falls within or outside the interval.

Given that the sample mean difference is 1.74, let's analyze the options:

Options for the confidence interval limits:

Lower limit options:

a) -1.26

b) -1.38

c) -3.48

d) -3.44

Upper limit options:

a) 1.26

b) 3.48

c) 1.38

d) 3.44

Since the sample mean difference is 1.74, we need to check if it falls within the interval formed by the lower and upper limits.

Looking at the options for the lower limit, the closest value to 1.74 is -1.38, and the closest value to the upper limit is 3.44.

So, the 95% confidence interval would be:

-1.38 to 3.44

Now, completing the statements:

The 95% confidence interval is: b) -1.38 to d) 3.44

The value of the sample mean difference is 1.74, which falls:

b) within

So, the completed statements are:

The 95% confidence interval is -1.38 to 3.44.

The value of the sample mean difference is 1.74, which falls within the 95% confidence interval.

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Answer:

y = 2x + 14

Step-by-step explanation:

y = mx + b to write the equation, we need 2 things: the slope and the y-intercept

y = ___x + ____

Slope:

Change in y over the change in x.  We find the change by subtracting.   The y values are 6 and -2.  The x values are -4 and -8

[tex]\frac{6- (-2)}{-4 -(-8)}[/tex] = [tex]\frac{6+2}{-4+8}[/tex] = [tex]\frac{8}4}[/tex] = 2

The slope is 2.

y-intercept:

Use either of the points given and the slope 2 to find the y-intercept.  I am going to use the points(-4,6).  I will use -4 for x and 6 for y given from the point

y = mx + b

6 = 2(-4) + b

6 = -8 + b  Add 8 to both sides

14 = b

The y-intercept is 14.

y = 2x + 14

Helping in the name of Jesus.

The first step in solving the equation is to isolate the radical term, and the second step is to eliminate the radical by raising both sides to the power of 3. Solving this equation for x initially yields x = 0, x = 2, and x = -2. Checking the solutions shows that it is not a real solution.

The first step in solving the equation (4x)[tex]^{1/3}[/tex] - x = 0 is to isolate the radical term by adding x to both sides of the equation. This gives us

(4x)[tex]^{1/3}[/tex]= x.
The second step is to raise both sides of the equation to the power of 3, which eliminates the radical. This results in 4x = x³.

Solving this equation for x initially yields x = 0, x = 2, and x = -2.
Checking the solutions shows that only x = 2 is a valid solution, as plugging it back into the original equation yields (4*2)[tex]^{1/3}[/tex] - 2 = 0. However, plugging in x = 0 results in a division by zero, and plugging in x = -2 yields a negative number under the radical, which is not a real solution.

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The null hypothesis (H0) for this situation would be that there is no difference in the proportion of male and female students with an overall GPA of 3.5 or higher.

The alternative hypothesis (Ha) would be that there is a difference in the proportion of male and female students with an overall GPA of 3.5 or higher.

Formally, we can write the hypotheses as:

H0: p_male = p_female (where p_male represents the proportion of male students with an overall GPA of 3.5 or higher, and p_female represents the proportion of female students with an overall GPA of 3.5 or higher)

Ha: p_male ≠ p_female

The president of the university can test these hypotheses using a hypothesis test for the difference in proportions. She can calculate the test statistic using the sample proportions and sample sizes for male and female students, and then compare it to the appropriate critical value or p-value based on the desired level of significance.

If the test results provide strong evidence against the null hypothesis, she can reject it and conclude that there is a statistically significant difference in the proportion of male and female students with an overall GPA of 3.5 or higher. If the test results do not provide enough evidence to reject the null hypothesis, she can fail to reject it and conclude that there is not enough evidence to suggest a difference in grades between males and females.

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To verify that the function f(x) = -4x^2 + 12x - 4ln x attains an absolute maximum and absolute minimum on [1/2,2], we can use the Extreme Value Theorem.

First, we need to check if the function is continuous on the interval [1/2,2] and differentiable on the open interval (1/2,2).

The function is continuous on [1/2,2] because it is a polynomial and the natural logarithm function is continuous on its domain.

To check if it is differentiable on (1/2,2), we need to take the derivative:

f'(x) = -8x + 12 - 4/x

This is defined and continuous on the open interval (1/2,2).

Now we can find the critical points by setting f'(x) = 0:

-8x + 12 - 4/x = 0

Multiplying both sides by x and rearranging, we get:

-8x^2 + 12x - 4 = 0

Dividing by -4, we get:

2x^2 - 3x + 1 = 0

This factors as (2x - 1)(x - 1) = 0, so the critical points are x = 1/2 and x = 1.

We also need to check the endpoints of the interval:

f(1/2) = -4(1/4) + 6 - 4ln(1/2) = 2 - 4ln(1/2)

f(2) = -4(4) + 12(2) - 4ln(2) = 8 - 4ln(2)

Now we can compare the function values at the critical points and endpoints to find the absolute maximum and minimum:

f(1/2) = 2 - 4ln(1/2) ≈ 5.39

f(1) = -4(1) + 12(1) - 4ln(1) = 8

f(2) = 8 - 4ln(2) ≈ 0.31

So the absolute maximum value is 8, which occurs at x = 1, and the absolute minimum value is 0.31, which occurs at x = 2.

Therefore, the function f(x) = -4x^2 + 12x - 4ln x attains an absolute maximum and absolute minimum on [1/2,2], and the absolute maximum value is 8 and the absolute minimum value is 0.31.
To verify that the function f(x) = -4x^2 + 12x - 4ln(x) attains an absolute maximum and minimum on the interval [1/2, 2], we will first find its critical points by taking the first derivative and setting it to zero, and then evaluate the function at the critical points and endpoints.

The first derivative of f(x) is:

f'(x) = -8x + 12 - 4/x

Setting f'(x) to zero, we have:

-8x + 12 - 4/x = 0

Multiplying by x to remove the fraction, we get:

-8x^2 + 12x - 4 = 0

Dividing by -4, we have:

2x^2 - 3x + 1 = 0

Factoring, we get:

(x-1)(2x-1) = 0

This gives us the critical points x = 1 and x = 1/2.

Now, we evaluate f(x) at the critical points and endpoints:

f(1/2) = -4(1/2)^2 + 12(1/2) - 4ln(1/2)
f(1) = -4(1)^2 + 12(1) - 4ln(1)
f(2) = -4(2)^2 + 12(2) - 4ln(2)

Calculating these values, we get:

f(1/2) ≈ 5.386
f(1) = 4
f(2) ≈ -4

The absolute maximum value is ≈ 5.386 at x = 1/2, and the absolute minimum value is ≈ -4 at x = 2.

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By using completing the square, the equation can be rewritten as (x + (-11/4))² = 9/16.

In Mathematics and Geometry, the standard form of a quadratic equation is represented by the following equation;

ax² + bx + c = 0

Next, we would solve the given quadratic equation by using the completing the square method;

2x² - 11x + 14 = 0

By dividing all through by 2, we have:

x² - 11x/2 + 7 = 0

x² - 11x/2 = -7

In order to complete the square, we would have to add (half the coefficient of the x-term)² to both sides of the quadratic equation as follows:

x² - 11x/2 + (-11/4)² = -7 + (-11/4)²

x² - 11x/2 - 121/16 = 9/16

(x - 11/4)² = 9/16.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

-5 and 7

Step-by-step explanation

lets try putting -5 and 7

-5 +7=2

and the difference is 8

i am not smart sorry

Carl pays his broker a total of $200 in fees for the 40 trades he made during the year.

To calculate how much Carl pays his broker, we need to first determine how many trades he made in a year. Looking at the table, we can see that Carl made a total of 40 trades - 20 buys and 20 sells. Since each trade incurs a $5 charge, we can multiply the number of trades by the cost per trade to get the total amount paid to the broker.

40 trades x $5 per trade = $200 paid to the broker in a year

It's important to note that transaction costs can have a significant impact on investment returns, especially for small accounts, so it's important to consider these costs when making investment decisions. Some brokers may offer lower transaction fees or other incentives to attract clients, so it's worth shopping around and comparing fees before choosing a broker. Additionally, it may be more cost-effective to use a robo-advisor or invest in index funds or exchange-traded funds (ETFs) that have lower fees compared to actively managed funds.

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Answer:

Step-by-step explanation:

The total balance of the two investment accounts at the end of ten years will be $16,564.08. To calculate the total balance of the two accounts at the end of ten years,

we need to use the formulas for simple interest and compound interest.

For Account I, the simple interest formula is:

I = Prt

where I is the interest earned, P is the principal (the amount deposited), r is the annual interest rate as a decimal, and t is the time in years.

Plugging in the values for Account I, we get:

I = (3500)(0.065)(10) = $2,275

So, after ten years, the balance in Account I will be:

B1 = P + I = 3500 + 2275 = $5,775

For Account II, the compound interest formula is:

A = P(1 + r/n)^(nt)

where A is the balance at the end of the time period, P is the principal, r is the annual interest rate as a decimal, n is the number of times the interest is compounded per year, and t is the time in years.

Plugging in the values for Account II, we get:

A = 5900(1 + 0.06/1)^(1*10) = $10,789.08

So, after ten years, the balance in Account II will be $10,789.08.

Therefore, the total balance of the two accounts at the end of ten years will be:

Total balance = Balance in Account I + Balance in Account II

= $5,775 + $10,789.08

= $16,564.08

In summary, by using the formulas for simple interest and compound interest, we can calculate that the total balance of the two investment accounts at the end of ten years will be $16,564.08.

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Answer:

25

Step-by-step explanation:

all three angles of a triangle equal to 180º. 135+20=155

180-155=25

this is how u get ur answer

135° + 20° = 155°

Since the angles must have a sum of 180°, we subtract 155° from 180°, which would equal 25°.

To confirm: 135° + 20° + 25° = 180°

The length of the fourth swing is 25.6 inches. The sequence is arithmetic or geometric.

The length of the arc through which a pendulum swings is 50 inches. To determine whether the sequence is arithmetic or geometric, and to find the length of the fourth swing, we will analyze the given information.

The length of the first swing is 50 inches. Each successive swing is 80% of the preceding swing. This means that to find the length of the next swing, we multiply the length of the current swing by 80% (or 0.8).

Since we are multiplying by a constant factor (0.8) to find the next term in the sequence, this is a geometric sequence, not an arithmetic sequence.

Now, let's find the length of the fourth swing.

1st swing: 50 inches
2nd swing: 50 * 0.8 = 40 inches
3rd swing: 40 * 0.8 = 32 inches
4th swing: 32 * 0.8 = 25.6 inches

The length of the fourth swing is 25.6 inches.

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