Write the equation for the line in slope-intercept form.

The mathematical ideas that are involved in the cannonball are quadratic functions and parabolas

When the cannonball is launched, it would follow a parabolic path.

Parabolas are represented by quadratic functions.

Hence, the mathematical ideas/concepts are involved are quadratic functions and parabolas

The quantities that can be measured are:

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Answer: n > 2.5 or n < -2.5

Step-by-step explanation:

Let's solve your inequality step-by-step.

1. Solve Absolute Value.

|n| > 2.5

We know either n > 2.5 or n < -2.5

n > 2.5 (Possibility 1)

n < -2.5 (Possibility 2)

Your answer is n > 2.5 or n < -2.5

Answer: Mean is 12

Step-by-step explanation: Mean is adding it all up and then dividing, 12 + 13 + 11 + 11 + 13 is 60

Divide 60 by the amount of numbers, 5

60 divided by 5 is 12

                 [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}}\rule{50}{1}[/tex]

            Five children are the following ages:-

   - What is their mean age?

        [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer \& how to solve:-}}}\rule{50}{1}[/tex]

In order to find the mean of a set of data, we need to add all the numbers in that set, as follows:-

[tex]\Large\text{12+13+11+11+13}[/tex]

    [tex]\bigstar[/tex] On simplification,

[tex]\Large\textit{60}[/tex]

However, that's not our final step; we also need to divide by how many numbers there are (in this case, we have 5, so we divide by 5, as follows:-

                       [tex]\Large\textsf{60:5}[/tex]

[tex]\bigstar[/tex] As a result, the mean of the children's ages is as follows:-

      [tex]\Large\textit{Mean=12}[/tex]

         [tex]\rule{50}{1}\smile\smile\smile\smile\smile\rule{50}{1}[/tex]

Work Shown:

q = 1 - p

q = 1 - 0.5

q = 0.5

Step-by-step explanation:

[tex]3(x + 2) = 2(2 - x) \\ 3x + 6 = 4 - 2x \\ 3x + 2x + 6 = 4 - 2x + 2x \\ 5x + 6 = 4 \\ 5x + 6 - 4 = 4 - 4\\ 5x = 2 \\ x \frac{2}{5} = 0.4[/tex]

Answer:

32 yd.

Step-by-step explanation:

63 / 7 is 9. 9+7+9+7 is 32.

Answer:

1. 2 + 3

2. -4 - 8

3. -4 + 8

4. -2 × 2

5. 24 ÷ 2

6. 3 - 8

7. 1 × 7

8. -7 ÷ -1

9. 36 ÷ 4

10. 3 × -3

you're welcome

Part A: Kennedy's expression is incorrect because 0.07 is 7 percent, not 70.

Part B: The correct expression would be 0.7 * 20, which equals 14

Answer:

35 area of shaded regions

Answer:

It llooks like its missing some information. I don't think I can find the triangle areas without another angle measure or line length.

Step-by-step explanation:

Answer:

$2.4

Step-by-step explanation:

85.9-55=30.9

30.9-30=0.9

0.9+1.5=2.4

Answer:

a) m∠6 = 55 and m∠8= 55 - 20 --> m∠8= 35     x = 55

b) m∠7 = 40 and m∠9 = 140                                x = 40

c) m∠8 = 46 and m∠7 = 46                                  x = 18

d) m∠6 = 63 and m∠7 = 27                                  x = 9

(just like the note says at the top each one is a different problem hence the different answer or each angle even if its the same one)

Step-by-step explanation:

I've attached my work

Sorry it took so long

Please give me feedback on my repsomse by commenting,

any way i can improve showing my work?

Hope it helps, let me know if you have questions !

Have a nice rest of your day :)

Answer:

PLEASE HELP 80 PTS.

Step-by-step explanation:

The data set which contains an outlier from the given answer choices is; Choice D; {16, 42, 45, 45, 46, 48}.

An outlier in a set of data values is a data value which differs significantly from other data points and hence, tends to affect the mean of such set of data values significantly.

On this note, choice D is the set of data values which contains an outlier.

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Answer:

it's a non-function

Answer:

6

Step-by-step explanation:

42=--24+8k+6k-18

42=-24+14k-18

42=-42+14k

14k=-42-42

-14k=-84

k=84/14

K=6.

Hey there!

42 = -8(3 - k) + 6(k - 3)

-8(3 - k) + 6(k - 3) = 42

-8(3 - 1k) + 6(1k - 3) = 42

-8(3) - 8(-1k) + 6(1k) + 6(-3) = 42

-24 + 8k + 6k - 18 = 42

COMBINE the LIKE TERMS

(8k + 6k) + (-24 - 18) = 42

8k + 6k - 24 - 18 = 42

14k - 42 = 42

ADD 42 to BOTH SIDES

14k - 42 + 42 = 42 + 42

SIMPLIFY IT!

14k = 42 + 42

14k = 84

DIVIDE 14 to BOTH SIDES

14k/14 = 84/14

SIMPLIFY IT!
k = 84/14

k = 6

Therefore, the answer is: k = 6

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

Step-by-step explanation:

Answer:  Alternate interior angles

Step-by-step explanation:

Let's take this fun problem step-by-step:

Let's first analyze the triangle:  ΔBRE

  ∠B + ∠E + ∠R = 180

  45 + 35 + ∠R = 180

    ∠R = 100   ⇒ ∠BRE = 100 degrees

Now let's analyze ΔAQD

 ∠A + ∠Q + ∠D = 180

 30 + ∠Q + 50 = 180

    ∠Q = 100 degrees ⇒ ∠AQD = 180 degrees

Now let's consider another fact:

           ⇒ meaning that ∠AQD + ∠RQC = 180 degrees

              ⇒ ∠RQC = 180 degrees - ∠AQD = 180 - 100 = 80 degrees

            ⇒ meaning that ∠BRE + ∠BRC = 180 degrees

                ⇔ ∠BRC = 180 degrees - ∠BRE = 180 - 100 = 80 degrees

Now let's consider ΔQRC:

  ∠BRC + ∠RQC + ∠QCR = 180 degrees

   80 + 80 + x = 180

         x = 20 degrees

Answer: 20 degrees

Hope that helps!

Next three terms after 27 are 36, 45 and 54.

Answer:

b.  h = 2A/b.

Step-by-step explanation:

A = 1/2 bh

Multiply through by 2:

2A = bh

Divide both sides by b:

h = 2A/b.

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -8 + 4}{2}~~~ ,~~~ \cfrac{ 6 -2}{2} \right)\implies \left( \cfrac{-4}{2}~~,~~\cfrac{4}{2} \right)\implies (-2~~,~~2)[/tex]

Answer:

its b i think maybe i might be wrong

Step-by-step explanation:

have a nice day :)

Answer:

340 cm^2

Step-by-step explanation:

Given:

Figure

To Find:

Area of the shaded region

Solution:

Area of shaded region:

[tex] \rm= Area \: of \: trapezium \: ABCD - Area \: of \: Trapezium \: EHGF[/tex]

We know that,

[tex] \rm \: Trapezium = 1/2 × (a+b)×h \: \: \: sq. units [/tex]

So,

[tex] \rm = 1/2 × (a+b)×h \: \: \: - 1/2 × (a+b)×h [/tex]

Trapezium ABCD:

According to the formula,

Trapezium EHGF:

Substitute:

[tex] \tt= \cfrac{1}{2} (40 + 24) \times 25 - \cfrac{1}{2} (30 + 16) \times \: 20[/tex]

[tex]\tt= \cfrac{1}{2} (64) \times 25 - \cfrac{1}{2} (46) \times \: 20[/tex]

[tex]\tt = \cfrac{1}{2} \times 1600 - \cfrac{1}{2} \times 920[/tex]

[tex] \tt \: = 800 - 460[/tex]

[tex] \rm = 340 \: cm {}^{2} \: or \: sq. \: cm[/tex]

Thus, the area of the shaded region will be 340 cm^2 .

Answer:

=0.291

Step-by-step explanation:

number of residents who have completed some college =5372

number of residents who has completed college and age group 20-29years=1563

1563/5372

=0.29095

The statement that describes how accurate he can expect his prediction to be his prediction will probably be very different than the actual value.

Correlation is a statistical measure used to measure the relationship that exists between two variables. Negative correlation is when two variables move in different direction. If one variable increases, the other variable decreases. When two variables have a negative correlation, there is a negative sign in front of the number.

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Answer:

His prediction will probably be very close to the actual value.

Step-by-step explanation:

Other answer is wrong. I got it right.

Answer:

change 290 grams to pounds= 0.639 pounds

change 87 grams to ounces= 3.069 ounces

change 1,038 mph to feet per second= 1522.4 feet per second

change 65 miles per hour to kilometers per hour

= 104.607 kilometers per hour

Hope this helps.

Step-by-step explanation:

"properly" is very vague.

as your can imagine, particularly in math, where many things are commutative or have other degrees of freedom what do when in what sequence, you will find particularly for the little techniques many different approaches. and most of them are correct.

particularly today I keep scratching my head about what i think is immensely complicated but teachers swear they are helping the students.

anyway, this is how I do divisions by using an example :

73496 ÷ 17

the "window" I use to look at the first number is a long as the second number. in this case 2 digits.

step 1a :

as mentioned, we look at the 2 left most digits (73) and see how often 17 fits inside that as a whole :

73 ÷ 17 = 4

4×17 = 68, so we have a remainder of 73-68 = 5.

I write it like this :

73|496 ÷ 17 = 4

05 (4×7 = 28 and 5 is then 33, carry over 3,

4×1 = 4 plus carry 3 = 7, 0 difference)

step 1b :

pull the next position down

734|96 ÷ 17 = 4

054

step 2a :

we look at the bottom number and divide this by 17.

54 ÷ 17 = 3 and a remainder of 3.

734|96 ÷ 17 = 43

054

03 (3×7 = 21 and 3 is then 24, carry over 2,

3×1 = 3 plus carry 2 = 5, 0 difference)

step 2b :

pull the next position down

7349|6 ÷ 17 = 43

054

039

step 3a :

we look at the bottom number and divide this by 17.

39 ÷ 17 = 2 and a remainder of 5.

734|96 ÷ 17 = 432

054

039

05 (2×7 = 14 and 5 is then 19, carry over 1,

2×1 = 2 plus carry 1 = 3, 0 difference)

step 3b :

pull the next position down

73496| ÷ 17 = 432

054

039

056

step 4a :

we look at the bottom number and divide this by 17.

56 ÷ 17 = 3 and a remainder of 5.

73496| ÷ 17 = 4323

054

039

056

05 (3×7 = 21 and 5 is then 26, carry over 2,

3×1 = 3 plus carry 2 = 5, 0 difference)

step 4b :

pull the next position down. but we have reached the last position before the decimal point. from that moment on we create result numbers after the decimal point.

and because the left number did not have any explicit digits after the decimal point, all the numbers we are pulling down now are 0.

73496.0| ÷ 17 = 4323.

054

039

056

050

step 5a :

we look at the bottom number and divide this by 17.

50 ÷ 17 = 2 and a remainder of 16.

73496.0| ÷ 17 = 4323.2

054

039

056

050

16 (2×7 = 14 and 6 is then 20, carry over 2,

2×1 = 2 plus carry 2 = 4, 1 difference)

step 5b :

pull the next position down. because the left number did not have any explicit digits after the decimal point, all the numbers we are pulling down now are 0.

73496.00| ÷ 17 = 4323.2

054

039

056

050

160

step 6a :

we look at the bottom number and divide this by 17.

160 ÷ 17 = 9 and a remainder of 7.

73496.00| ÷ 17 = 4323.29

054

039

056

050

160

07 (2×7 = 14 and 6 is then 20, carry over 2,

2×1 = 2 plus carry 2 = 4, 1 difference)

step 6b :

pull the next position down. because the left number did not have any explicit digits after the decimal point, all the numbers we are pulling down now are 0.

73496.000| ÷ 17 = 4323.29

054

039

056

050

160

070

step 7a :

we look at the bottom number and divide this by 17.

70 ÷ 17 = 4 and a remainder of 2.

73496.00| ÷ 17 = 4323.294

054

039

056

050

160

070

02 (4×7 = 28 and 2 is then 30, carry over 3,

4×1 = 4 plus carry 3 = 7, 0 difference)

step 7b :

pull the next position down. because the left number did not have any explicit digits after the decimal point, all the numbers we are pulling down now are 0.

73496.0000| ÷ 17 = 4323.294

054

039

056

050

160

070

020

and so on ...

Answer:

A 6000

Step-by-step explanation:

15x20 = 300

300 x 10

since theres two rectangles with the same side lengths

3000 x 2

6000

Answer:

A 6000 cm^3

Step-by-step explanation:

Bottom rectangular prism volume =   15 x 20 x 10 = 3000 cm^3

Top prism =   10 x 20 x 15  = 3000 cm^3

Summed = 6000 cm^3

The total distance of the putts in yards, feets and inches be 8 yd 0 ft 6 inches or 8 yd 0.5 ft 0 inches

The conversion between different units of measurement for the same quantity, typically through multiplicative conversion factors.

As,

1 yard = 3 foot,

1 feet = 12 inches.

Now the lengths are given 15ft 4 in and 9 ft 2 in.

So, the total distance of the putts be,

=15 ft 4 in + 9 ft 2 in

=  24 ft 6 inches

= 8 yd 0 ft 6 inches or 8 yd 0.5 ft 0 inches

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Answer:

[tex]\frac{12}{\sqrt{10} +\sqrt{7} +\sqrt{3} }=\frac{6\sqrt{147} +6\sqrt{63}-6\sqrt{210} }{21 }[/tex]

Step-by-step explanation:

[tex]\frac{12}{\sqrt{10} +\sqrt{7} +\sqrt{3} }[/tex]

[tex]=\frac{12\left( \sqrt{10} -\left( \sqrt{7} +\sqrt{3} \right) \right) }{(\sqrt{10}+(\sqrt{7} +\sqrt{3 } ))( \sqrt{10} -( \sqrt{7} +\sqrt{3}))}[/tex]

[tex]=\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{\sqrt{10^2} -(\sqrt{7} +\sqrt{3})^2}[/tex]

[tex]\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{10-(10+2\sqrt{21} )} }[/tex]

[tex]=\frac{12\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{-2\sqrt{21} }[/tex]

[tex]=\frac{-6\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{\sqrt{21} }[/tex]

[tex]=\frac{-6\left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{\sqrt{21} } \times\frac{\sqrt{21} }{\sqrt{21} }[/tex]

[tex]=\frac{-6\sqrt{21} \left( \sqrt{10} -\sqrt{7} -\sqrt{3} \right) }{21 }[/tex]

[tex]=\frac{-6\sqrt{210} +6\sqrt{147} +6\sqrt{63} }{21 }[/tex]

[tex]=\frac{6\sqrt{147} +6\sqrt{63}-6\sqrt{210} }{21 }[/tex]

Remark:

You can simplify moreover if you want to.