Write a program that computes and display the n! for any n in the range1...100​

Answer:

Single use i think

Explanation:

Answer: im pretty sure on a network.

Explanation:

Answer:

Procter and Gamble is an organization that uses supercomputing.

Explanation:

Supercomputing refers to the use of high-performance computers in the development and production of items. Procter and Gamble is a company known for the production of many household items and personal care products. Uses and advantages of supercomputing to this company include;

1. Testing virtual prototypes of substances used in production: This is a faster way of developing products that are sustainable because many prototypes can be examined with the help of computers and the best chosen for production.

2. Developing unique designs of products: Supercomputers allow for the development of high-quality designs which include the internal and external designs of products.

3. Simulation of many molecules: Molecules such as those involved in the production of surfactants can be analyzed to understand how they work with the aid of supercomputers.

4. Computational fluid dynamics: This helps the scientists to understand how fluid works using numerical analysis and the structure of compounds.

The designs and products obtained through supercomputing are a source of competitive advantage because the company can make high-quality and unique products that appeal to customers and meet the latest trends. This would increase their marketability and give them an advantage over companies that do not have access to these computers.

Reference:   The Department of Energy. (2009) High-Performance Computing Case Study. Procter & Gamble's Story of Suds, Soaps, Simulations, and Supercomputers

Answer:

Here is the function:

def NumberOfSongs(word):  # function definition    

   count=0  #count the occurrence of word in song

   for song in lyrics['Lyrics']:  #iterates through song lyrics

       if word in str(song):  #if word is in the song

           count=count+1  #adds 1 to the count

   if count!=0:  #if word occurs in the songs

       return f'{str(count)} songs were found to contain {word} in this dataset'  #display the count of the word in the song

   else:  #if word does not appear in any song

       return f'No songs were found to contain the words:{word}'  #returns this message if no songs were found with given word

print(NumberOfSongs('like')) #calls method with the word like given as parameter to it

Explanation:

You can add the csv file this way:

import pandas as pd

lyrics = pd.read_csv("lyrics.csv", encoding="cp1252")

Now you can use the NumberOfSongs method which iterates through the Lyrics of lyrics.csv and find if any of the songs in the file contains the specified word.

The screenshot of program along with its output is attached. Since the file was not provided i have created a csv file. You can add your own file instead of lyrics.csv

Answer: Did you ever think of a mirror?

Explanation: Not trying to be rude about it.

Answer:

Slower

Explanation:

Answer:

me

Explanation:

yea not me

Explanation:

Answer:

Written in Python

def count_down_from(n):

    for i in range(n,-1,-1):

         print(i)

Explanation:

This line defines the function

def count_down_from(n):

This line iterates from n to 0

    for i in range(n,-1,-1):

This line prints the countdown

         print(i)

Answer:

c. StringBuilder

Explanation:

An alternative to the String class would be the StringBuilder Class. This class uses Strings as objects and allows you to mix and match different strings as well as adding, removing, implementing,  and modifying strings themselves as though they were similar to an array. Unlike the string class StringBuilder allows you to modify and work with a combination of strings in the same piece of data as opposed to having various objects and copying pieces which would take up more memory.

You want to look up colleges but exclude private schools. Including punctuation, The type is private -college. The correct option is c.

The institutions for higher studies are those institutions that provide education after schooling. They are colleges and universities. Universities, colleges, and professional schools that offer training in subjects like law, theology, medicine, business, music, and art are all considered higher education institutions.

Junior colleges, institutes of technology, and schools for future teachers are also considered to be part of higher education. There are different types of colleges, like government colleges and private colleges. Private colleges are those which are funded by private institutions.

Therefore, the correct option is c. private -college.

To learn more about excluding, refer to the link:

https://brainly.com/question/27246973

#SPJ2

In python:

age = float(input("How old are you? "))

weight = float(input("How much do you weigh? "))

heart_rate = float(input("What's your heart rate? "))

time = float(input("What's the time? "))

print("The calories burned for men is {}, and the calories burned for women is {}.".format(

   ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * (time / 4.184),

   ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022) * (time / 4.184)))

This is the program.

When you enter 49 155 148 60, the output is:

The calories burned for men is 489.77724665391963, and the calories burned for women is 580.939531548757.

Round to whatever you desire.

The programming language is not stated. So, I will answer this question using Python programming language.

The program requires a sequence control structure, because it does not make use of conditions and iterations.

The program in python is as follows, where comments (in italics) are used to explain each line.

#This gets input for age, in years

age = int(input("Age (years): "))

#This gets input for weight, in pounds

weight = int(input("Weight (pounds): "))

#This gets input for heart rate, in beats per minutes

heart_rate = int(input("Heart Rate (beats per minutes): "))

#This gets input for time, in minutes

time = int(input("Time (Minutes) : "))

#This calculates the calories burnt for men

Men = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184

#This calculates the calories burnt for women

Women = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184

#This prints the calories burnt for men

print("Men:", Men)

#This prints the calories burnt for women

print("Women:", Women)

At the end of the program, the program outputs the amount of calories burnt for men and women.

See attachment for sample run

Read more about Python programs at:

https://brainly.com/question/22841107

Answer:

Written in Python:

import re

name = input("Name: ")

print(re.sub("[ ]", ", ", name))

Explanation:

This line imports the regular expression library

import re

This line prompts user for input

name = input("Name: ")

This line replace the space with comma and prints the output

print(re.sub("[ ]", ", ", name))

Answer:

The mailman would sometimes take a different path to deliver each letter to your home.

Explanation:

Options:

The mailman would sometimes take a different path to deliver each letter to your home.

Letters would be written on the outside of envelopes for all to read instead of letters put inside envelopes.

Routers work in different ways and they take the fastest route no matter what is the direction they have to take, so they travel to several servers trying to find the fastest path to their destination, it changes almost everytime because of the use of servers and the conection speed of the different routes they can connect to, so that would be the option.

In python:

i = 1

lst1 = ([])

lst2 = ([])

while i <= 5:

   person1 = int(input("Enter the salary individual 1 got in year {}".format(i)))

   person2 = int(input("Enter the salary individual 1 got in year {}".format(i)))

   lst1.append(person1)

   lst2.append(person2)

   i += 1

if sum(lst1) > sum(lst2):

   print("Individual 1 has the highest salary")

else:

   print("Individual 2 has the highest salary")

This works correctly if the two individuals do not end up with the same salary overall.

Answer:

Earned value is a measure which is used on projects to determine the value of work which has been completed to date, in order to understand how the project is performing on a cost and schedule basis. At the beginning of a project, a project manager or company will determine their budget at completion (BAC) or planned value (PV).

Explanation:

Answer:

Written in C++

int sum(int arr[], int size) {

 int total = 0;      

 if(size>=3)  {

  for (int i = 0; i < size; ++i) {

     if(i%3 == 0)      {

     total += arr[i];    

     }

  }

 }

  return total;

}

Explanation:

This line defines the function

int sum(int arr[], int size) {

This line initializes sum to 0

 int total = 0;      

This line checks if size is at least 3

 if(size>=3)  {

This loop iterates through the array

  for (int i = 0; i < size; ++i) {

The following adds multiples of 3

     if(i%3 == 0)      {

     total += arr[i];    

     }

  }

 }

This returns the calculated sum

  return total;

}

See attachment for full program

Answer:

what :)

Explanation:

Answer:

All functions were written in python

addUpSquaresAndCubes Function

def addUpSquaresAndCubes(N):

    squares = 0

    cubes = 0

    for i in range(1, N+1):

         squares = squares + i**2

         cubes = cubes + i**3

    return(squares, cubes)

sumOfSquares Function

def sumOfSquares(N):

    squares = 0

    for i in range(1, N+1):

         squares = squares + i**2

    return squares

sumOfCubes Function

def sumOfCubes(N):

    cubes = 0

    for i in range(1, N+1):

         cubes = cubes + i**3

    return cubes

Explanation:

Explaining the addUpSquaresAndCubes Function

This line defines the function

def addUpSquaresAndCubes(N):

The next two lines initializes squares and cubes to 0

    squares = 0

    cubes = 0

The following iteration adds up the squares and cubes from 1 to user input

    for i in range(1, N+1):

         squares = squares + i**2

         cubes = cubes + i**3

This line returns the calculated squares and cubes

    return(squares, cubes)

The functions sumOfSquares and sumOfCubes are extract of the addUpSquaresAndCubes.

Hence, the same explanation (above) applies to both functions

the answer is:

c. which methods of solving problems and interacting with others he favors.

Answer:

C

Explanation:

Answer:

What?

Explanation:

Answer:

Webmail

Explanation:

Got it right on a test

Answer:

c.a system that start with a process, them output resources in the input

Answer:

a

Explanation:

Yes, true.

Shortest Remaining Time First, also popularly referred to by the acronym SRTF, is a type of scheduling algorithm, used in operating systems. Other times it's not called by its name nor its acronym, it is called the preemptive version of SJF scheduling algorithm. The SJF scheduling algorithm is another type of scheduling algorithm.

The Shortest Remaining Time First has been touted by many to be faster than the SJF

The answer to the question which asks if the Shortest Remaining Time First is the best preemptive scheduling algorithm that can be implemented in an Operating System is:

This refers to the type of scheduling algorithm which is used to schedule tasks that would be executed in the processing unit in an Operating System based on the shortest time taken to execute the task.

With this in mind, we can see that this is the best preemptive scheduling algorithm that can be implemented in an Operating System because it makes task execution faster.

Read more about scheduling algorithm here:
https://brainly.com/question/15191620

Answer:

#include <iostream>

#iclude <iomanip>

#include <algorithm>

using namespace std;

int main(){

int num1, num2, num3,

int sum, maxDrop, minDrop = 0;

float avg;

string end = "\n";

cout << " Enter the leaf drop for September: ";

cin >> num1 >> endl = end;

cout << "Enter the leaf drop for October: ";

cin >> num2 >> endl = end;

cout << "Enter the leaf drop for November: ";

cin >> num3 >> endl = end;

int numbers[3] = {num1, num2, num3} ;

string month[3] = { "September", "October", "November"}

for ( int i =0; i < 3; i++) {

 if (numbers[i] < 0) {

   cout << "Error: all leaf counts must be at least zero\n";

   cout << "End of Maple Marvels\n";

   cout << "Welcome to Maple Marvels";

   break;

 } else if (number[i] >= 0 ) {

     sum += number[i] ;

   }

}

for (int i = 0; i < 3; i++){

 cout << month[i] << " leaf drop: " << numbers[i] << endl = end;

}

cout << "Total drop: " << sum << endl = end;

cout << setprecision(3) << fixed;

cout << "Average drop: " << sum / 3<< endl = end;

maxDrop = max( num1, num2, num3);

minDrop = min(num1, num2, num3);

int n = sizeof(numbers)/sizeof(numbers[0]);

auto itr = find(number, number + n, maxDrop);

cout << "Highest drop: "<< month[ distance(numbers, itr) ] << endl = end;

auto itr1 = find(number, number + n, minDrop);

cout << "Lowest drop: " << month[ distance(numbers, itr1) ] << endl = end;

cout << "End of Maple Marvels";

Explanation:

The C++ soucre code above receives three integer user input and calculates the total number, average, minimum and maximum number of leaf drop per month, if the input isn't less than zero.

Answer:

Written in Python

num = int(input("Items: "))

myitems = []

total = 0

for i in range(0, num):

     item = int(input("Number: "))

     myitems.append(item)

     total = total + item

average = total/num

print("Average: "+str(average))

count = 0

for i in range(0,num):

     if myitems[i] > average:

           count = count+1

print("There are "+str(count)+" items greater than average")

Explanation:

This prompts user for number of items

num = int(input("Items: "))

This creates an empty list

myitems = []

This initializes total to 0

total = 0

The following iteration gets user input for each item and also calculates the total

for i in range(0, num):

     item = int(input("Number: "))

     myitems.append(item)

     total = total + item

This calculates the average

average = total/num

This prints the average

print("Average: "+str(average))

This initializes count to 0

count = 0

The following iteration counts items greater than average

for i in range(0,num):

     if myitems[i] > average:

           count = count+1

This prints the count of items greater than average

print("There are "+str(count)+" items greater than average")

Answer:

text box

Explanation:

on edge 2020

Answer:

A- text box

Explanation: ;)

Answer:

Answers are given by the users, so reliable information varies. Usually, you can find if it is reliable by checking other websites to see if the information matches up with other reliable websites.

Explanation:

Answer:

Replace

/* Your solution goes here */

with

sumExtra = 0;

for (i =0; i<NUM_VALS;i++){

if(testGrades[i]>100){

sumExtra = sumExtra - testGrades[i] + 100;

}

}

Explanation:

This line initializes sumExtra to 0

sumExtra = 0;

The following is a loop from 0 to 3

for (i =0; i<NUM_VALS;i++){

The following if condition checks if current array element is greater than 100

if(testGrades[i]>100)

{

This line calculates the extra credit

sumExtra = sumExtra - testGrades[i] + 100;

}

}

See attachment for complete question

Answer:

logging off one of the computers, and then logging back on

Answer:

the last one:

logging off one of the computers, and then logging back on

Explanation:

if something goes wrong on an electronic device you can reboot it and it should eventually work.

have a nice day

In python:

numA = [4, 1, 6, 10, 2, 3, 7, 9, 11, 12, 5, 8]

numB = [2, 12, 10, 11, 1, 3, 7, 9, 4, 8, 5, 6]

while True:

   i = 0

   userChoice = input("Adding or Multiplying? (a/m) ")

   if userChoice == "a":

       while i < len(numA):

           answer = int(input("What is {} + {} ".format(numA[i],numB[i])))

           if answer == numA[i] + numB[i]:

               print("Correct!")

           else:

               print("That's incorrect. The right answer is {}".format(numA[i] + numB[i]))

           i += 1

   elif userChoice == "m":

       while i < len(numA):

           answer = int(input("What is {} * {} ".format(numA[i], numB[i])))

           if answer == numA[i] * numB[i]:

               print("Correct!")

           else:

               print("that's incorrect. The right answer is {}".format(numA[i] * numB[i]))

           i += 1

The program will give them a choice of practicing adding or multiplying is true.

Computer program is defined as a series of instructions written in a programming language that a computer may follow. Computers can obey a set of instructions created through coding.  Programmers can create programs, including websites and apps, by coding.

Python says:

numA = [4, 1, 6, 10, 2, 3, 7, 9, 11, 12, 5, 8]

numB = [2, 12, 10, 11, 1, 3, 7, 9, 4, 8, 5, 6]

though True:

I = 0

input("Adding or Multiplying? (a/m)") userChoice

when userChoice equals "a"

even when I = len(numA):

What is input("What is + ".format(numA[i],numB[i]))? answer = int

if response == numA[i] + numB[i]:

print("Correct! ")

else:

print( "That is untrue. The appropriate response is "Formatted as (numA[i] + numB[i])

I += 1

if userChoice == "m," then

even when I = len(numA):

answer = int("What is *? ".format(numA[i], numB[i]))

if the response equals numA[i] + numB[i]:

print("Correct! ")

else

print( "that is untrue. The appropriate response is ".format(numB * numA[i]

I += 1

Thus, the program will give them a choice of practicing adding or multiplying is true.

To learn more about program, refer to the link below:

https://brainly.com/question/11023419

#SPJ3