‼️‼️‼️‼️WILL MARK BRAINLIEST‼️‼️‼️‼️

WILL MARK BRAINLIEST

Answers

Answer 1

Answer:

S = 2π(14^2) + 2π(14)(154)

= 2π(196) + 2π(2,156)

= 4,704π = 14,778.1 ft^2

Using 3.14 for π:

S = 4,704(3.14) = 14,770.6 ft^2


Related Questions

Find the principal needed now to get the given amount; that is, find the present value. To get $4000 after 2 1/4 years at 9% compounded daily The present value of $4000 is $? (Round to the nearest cent as needed.)​

Answers

Step-by-step explanation:

Compounding formula

FV = PV ( 1 + i )^n      FV = Future value (4000)       PV = present value

                      i = decimal interest per PERIOD = .09/365

                      n = periods = 2 1/4 yrs * 365 days/yr = 821.25 periods

4000 = PV ( 1 + .09/365)^821.25

Solve for PV = $ 3266.83

                                     

A small country emits 80,000 kilotons of carbon dioxide per year. In a recent global agreement, the country agreed to cut its carbon emissions by 2.5% per year for the next 7 years. In the first year of the agreement, the country will keep its emissions at 80,000 kilotons and the emissions will decrease 2.5% in each successive year. How many total kilotons of carbon dioxide would the country emit over the course of the 7 year period, to the nearest whole number?

Answers

Using an exponential function and integration, it is found that over the entire 11 year period, the country will emit 763,968 kilotons of carbon dioxide.

Exponential function:

A decaying exponential function is modeled by:

⇒ A (t) = A (0) (1 - r)ⁿ

In which:

A(0) is the initial value.

r is the decay rate, as a decimal.

In this problem:

In the first year, the country emits 80,000 kilotons, hence . A (0) = 8000

Emissions will decrease 2.5% in each successive year, hence r = 0.026

Then, the equation for the amount emitted each year is:

⇒ A (t) = A (0) (1 - r)ⁿ

⇒ A (t) = 80000 (1 - 0.025)ⁿ

⇒ A (t) = 80,000 (0.975)ⁿ

The total amount emitted over the course of the 11 year period is:

T = ∫ 0 to 11 ( A (t) ) dt

Hence:

T = ∫ 0 to 11 ( 80000 (0.974)ⁿ ) dt

Applying the Fundamental Theorem of Calculus:

T = 763,968 kilotons

Hence, Over the entire 11 year period, the country will emit 763,968 kilotons of carbon dioxide.

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What is the equation of a parabola with a vertical axis, vertex (h, k), and directrix y = k – p, where p is a nonzero real number? How can the equation be simplified if the vertex is at the origin?

Answers

Note that equation of a parabola with a vertical axis, vertex (h, k), and directrix y = k – p, where p is a nonzero real number is (y-k)² = 4p(x-h).

How can the equation be simplified if the vertex is at the origin?

The equation of a parabola with a vertical axis, vertex (h, k), and directrix y = k – p, where p is a nonzero real number, is:

(y - k)²   = 4p( x -  h)

If the vertex is at the origin (h = 0, k = 0 ), the equation an be simplified to....

y² = 4px

where p is still a nonzero real number.

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PLEASE SOMEONE !! 15 POINTS!!!

Answers

Answer:

The answer is -5

Step-by-step explanation:

Each number moves down 5 as it moves to the right 1. Right is positive, and down is negative. -5 divided by 1 is -5.

Solve for x. Round to the nearest tenth, if necessary.

Answers

Answer:

160

Step-by-step explanation:

The cosine is equal to the adjacent side divided by the hypotenuse (adj/hyp)

Adjacent = 80

Hypotenuse = x

therefore, cos(60) = 80/x

1/2 = 80/x

x = 80 x 2 = 160

Enter your answer by filling in the boxes.

Answers

The correct statement regarding the end behavior of the function is given as follows:

As x -> -∞, f(x) -> +∞.As x -> +∞, f(x) -> +∞.

What is the end behavior of a function?

The end behavior of a function refers to how the function behaves as the input variable approaches positive or negative infinity.

The function in this problem is given as follows:

f(x) = 2(x - 4)² + 3.

We have the square of a number, which is always positive, hence the function goes to positive infinity when the input goes to negative infinity/positive infinity.

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What is the value of X? (Thx for any help!)

Answers

Answer:

x=109 y=100

Step-by-step explanation:

Answer:

x=100

y=109

Step-by-step explanation:

For any quadrilateral (4-sided shape) inscribed in a circle (all 4 vertices of the quadrilateral are on the edge of the circle),  there is a special relationship between certain pairs of angles within the quadrilateral.


Specifically, opposite angles (angles across from each other) must sum (add) to 180 degrees.

The angle measuring 80 degrees is opposite the angle measuring x degrees, so x + 80 = 180, implying x = 100.

In this case, the angle measuring 71 degrees is opposite the angle measuring y degrees.  So, 71 + y = 180, which implies y = 109.

I-Ready
What is the distance between point P and point Q?

Answers

Answer: The distance between Point P and Point Q is 11 units.
Explanation: Point P’s coordinates are (-5,7) and Point Q’s coordinates are (6,7). Since the y-coordinates of both points are 7, you can simply ignore them. Now for -5 and 6, you would have to add them together for the distance since one is a negative value and the other is a positive value. Remember, distance is always positive. So when you add, -5 turns into 5. (6 units + 5 units = 11 units). Therefore, the distance is 11 units. Hope that helps!

The distance between Town P and Town Q is 237.5 Km. At 11.30 a.m a van travels from
Town P to Town Q at an average speed of 35 km/h. At the same time, a car travels from
Town Q to Town P along the same route at an average speed of 60 km/h.
a)At what time will the vehicles meet on the way?

b) How far will each vehicle have travelled when they meet?

Answers

Answer:

So when the two vehicles meet, the van has travelled 87.5 km and the car has travelled 150 km.

Step-by-step explanation:

(a) Let's call the time it takes for the two vehicles to meet "t". We know that the distance between the two towns is 237.5 km, and the combined speed of the two vehicles is 35 km/h + 60 km/h = 95 km/h. Using the formula distance = speed × time:

237.5 = 95t

Solving for t:

t = 237.5/95

t ≈ 2.5 hours

So the two vehicles will meet on the way 2.5 hours after 11.30 a.m., which is at 2.00 p.m.

(b) To find how far each vehicle has traveled when they meet, we can use the formula distance = speed × time again. The van travels at 35 km/h for 2.5 hours, so it travels:

distance = speed × time = 35 km/h × 2.5 hours = 87.5 km

The car travels at 60 km/h for 2.5 hours, so it travels:

distance = speed × time = 60 km/h × 2.5 hours = 150 km

So when the two vehicles meet, the van has traveled 87.5 km and the car has traveled 150 km.

100 POINTS!!!

Question


Answers

Answer:

A) Sequence 2: 15,13,11,9,7

A) Ordered pairs (12,15), (16,13), (19,11), (22,9), (25,7)

B)  Sequence 1: 1,5,17,53,161

B) Sequence 2: 6,15,33,69,141

B) Ordered pairs (1,6), (5,15), (17,33), (53, 69) (161,141)

Step-by-step explanation:

Helping in the name of Jesus.

Answer:

A) Sequence 2: 15,13,11,9,7

A) Ordered pairs (12,15), (16,13), (19,11), (22,9), (25,7)

B)  Sequence 1: 1,5,17,53,161

B) Sequence 2: 6,15,33,69,141

B) Ordered pairs (1,6), (5,15), (17,33), (53, 69) (161,141)

Step-by-step explanation:

Helping in the name of typing.

Mrs. Hopkins gives her students a math quiz every 8 and a science quiz every 6 days. If she gives math and science quizzes today, how many days will it be before both quizzes are given on the same day again?

Answers

Therefore , the solution of the given problem of unitary method comes out to be once more administer maths and science quizzes on the same day.

Definition of a unitary method.

The well-known minimalist approach, current variables, and any crucial elements from the initial Diocesan tailored query can all be used to accomplish the work. In response, you can be granted another chance to utilise the item. If not, important impacts on our understanding of algorithms will vanish.

Here,

List the multiples of each integer until we discover a common multiple as one method to determine the least common multiple:

=> 8, 16, 24, 32, 40, 48, 56, 64, 72, and 80 are all multiples of 8.

=> 6, 12, 18, 24, 30, 36, 42, 48, 54, and 60 are multiples of 6.

As an alternative, we can use the prime factorization technique to identify the smallest common multiple:

=> 8's prime factors are 2 x 2 x 2

=> 6's prime factors are 2 x 3

=> 2 x 2 x 2 x 3 = 24

We can see that 24 is the smallest common multiple once more, and in 24 days,

Mrs Hopkins will once more administer maths and science quizzes on the same day.

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the slope between the points -3, 0 and 0, -1 ?

Answers

Answer:

Step-by-step explanation:

m = [tex]\frac{y2-y1}{x2-x1}[/tex]

m = [tex]\frac{-1-0}{0+3}[/tex]

m = [tex]\frac{-1}{3}[/tex]

Answer: -[tex]\frac{1}{3}[/tex]

On Low Budget Airlines, the maximum weight of the luggage a passenger can bring without charge is 50 pounds. Mary Ellen has decided to weigh each item as she packs her bag. Use rounding to the nearest one pound to estimate the weight of her luggage.
The estimated weight is pounds.

Answers

Answer: 50 pounds

Step-by-step explanation:

The maximum weight of the luggage a passenger can bring without charge is 50 pounds.

Mary Ellen has decided to weigh each item as she packs her bag.

weight of Suitcase = 3.65 lbs

weight of clothing = 4.35 lbs

weight of shoes = 8.67 lbs

weight of toiletries = 11.35 lbs

weight of extras = 21.63 lbs

Now we will add the weights of each items

Total weight = 3.65 + 4.35 + 8.67 + 11.35 + 21.63 = 49.65

Rounding to the nearest to the one pound will be = 50 lbs

(Since 0.65 is greater than 0.5 so by rounding off 0.65 will become 1.)

Therefore the estimated weight is 50 pounds.

Suppose that the functions q and r are defined as follows.

Answers

Answer:

Step-by-step explanation:

Given:

q(x) = -3x+4

r(x) = -4x

(r₀q)(4)   =>    r(q(4))     solve for q(4) first

q(4) = -3(4)+4       > substitute 4 in for x

q(4) = -12 +4

q(4) = -8           > now substitute this into r(q(4))

r(-8) = -4(-8)     > substitute -8 in for x

r(-8) = 32

(r₀q)(4) = 32

(q₀r)(4)   => q(r(4))    solve for r(4) first

r(4) = -4(4)        > substitute 4 for x

r(4) =-16            > substitute this into q(x)

q(-16) = -3(-16)+4

q(-16) = 48 +4

q(-16) = 52

(q₀r)(4) = 52


Suppose a normal distribution has a mean of 34 and a standard deviation of
2. What is the probability that a data value is between 30 and 36? Round your
answer to the nearest tenth of a percent.

Answers

Answer:

it’s 86.6%

Step-by-step explanation:

could be wrong

Construct a 90 ​% confidence interval of the population proportion using the given information.
x = 105 n =150

Answers

The 90% confidence interval based on the data provided will be (0.6152, 0.7848)

How to calculate the confidence interval

It should be noted that standard error = ✓[(p * q) / n]

p = population proportion

q = 1 - p

n = sample size

sample proportion = x / n = 105 / 150 = 0.7

standard error = ✓(p * q) / n] = sqrt[(0.7 * 0.3) / 150] = 0.0516

margin of error = 1.645 * 0.0516 = 0.0848

Confidence interval = sample proportion ± margin of error

                 = 0.7 ± 0.0848

                 = (0.6152, 0.7848)

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. Suppose that the following represents the graph of the function f(x).
N
a. (5 points) Determine the x intercepts and give a number line for the function
f(x). Are there any horizontal or vertical asymptotes?
b. (5 points) Give a number line for f'(x) and classify any local maxima or minima.
c. (5 points) Give a number line for f"(x) and list any points of inflection.

Answers

The x intercepts are (-2, 0), (2, 0) and (3, 0) and it has vertical asymptotes at x = 4 and x = -4

Determining the x intercepts

The x intercepts are the points where the graph intersect with x-axis

In this case, the points are (-2, 0), (2, 0) and (3, 0)

So, the x intercepts are (-2, 0), (2, 0) and (3, 0)

Are there any horizontal or vertical asymptotes?

The graph has no horizontal asymptotes

However, it has vertical asymptotes at x = 4 and x = -4

The local maxima or minima

From the graph, the local maxima or minima are

Minima (3, -1) and Maxima (-1, 12)

The point of inflection

This is the points where the graph changes it concave-ness

From the graph, we have the point to be (1, 13/2)

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I need some assistance with this ? Please

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Answer:

I am sorry this is just so new for me like what even is an "imaginary" solution, i am in 6th grade wth

Select all true statements about the graph that represents y=2x(x−11) .

Answers

The correct answers for the quadratic equation are:

x-intercepts or roots of the parabola are (0, 0) and (11, 0)ordinate of the vertex is x = 5.5What are the Properties of a quadratic equation?

Roots of a quadratic equation are the points where y = 0.

Abscissa of a quadratic equation are the points where x = 0.

If the equation of a quadratic equation is in the vertex form,

         y = a(x - h)² + k

         Vertex of the U-shaped curve will be (h, k)

Given in the question, where the equation of the u-shaped curve is
y = 2x(x - 11)

Convert the equation in the vertex form,

y = 2x² - 22x

y = 2(x² - 11x)

y = 2 *  (x² - 2 ( 5.5x) + (5.5)² - (5.5)²)

y = 2[(x - 5.5)² - 30.25]

y = 2(x - 5.5)² - 60.5

Hence, the vertex of the U-shaped curve will be (5.5, -60.5).

For x-intercepts,

Substitute y = 0,

0 = 2x(x - 11)

⇒ x = 0, 11

   Therefore, roots of the parabola will be (0, 0) and (11, 0).

and the  ordinate of the vertex is x = 5.5

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Twenty middle-aged men with glucose readings between 90 milligrams per deciliter and 120 milligrams per deciliter of blood were selected randomly from the population of similar male patients at a large local hospital. Ten of the 20 men were assigned randomly to group A and received a placebo. The other 10 men were assigned to group B and received a new glucose drug. After two months, posttreatment glucose readings were taken for all 20 men and were compared with pretreatment readings. The reduction in glucose level (Pretreatment reading − Posttreatment reading) for each man in the study is shown here.

Group A (placebo) reduction (in milligrams per deciliter): 12, 8, 17, 7, 20, 2, 5, 9, 12, 6

Group B (glucose drug) reduction (in milligrams per deciliter): 29, 31, 13, 19, 21, 5, 24, 12, 8, 21

Create and interpret a 98% confidence interval for the difference in the placebo and the new drug. (10 points)

Answers

A: The data provides convincing evidence, at α=0.02 level, that the glucose drug is effective in reducing mean glucose level.

B: The 98% confidence interval for the difference in mean reduction of glucose level between placebo and drug groups is 3.5 to 13.7 mg/dL, supporting the effectiveness of the glucose drug

A: To test whether the glucose drug is effective in producing a reduction in mean glucose level, we will use a two-sample t-test with equal variances assuming normality of the differences.

Let μA be the true mean reduction in glucose level for the placebo group and μB be the true mean reduction in glucose level for the glucose drug group. The null hypothesis is H0: μA - μB = 0, and the alternative hypothesis is Ha: μA - μB < 0

Using the given data, the sample mean reduction for the placebo group is 9.7 mg/dL and for the glucose drug group is 18.3 mg/dL. The pooled sample standard deviation is 8.064 mg/dL, and the t-statistic is calculated to be:

t = (xB - xA) / (sP × √(1/nA + 1/nB))

= (18.3 - 9.7) / (8.064 × √(1/10 + 1/10))

= 2.551

where xA and xB are the sample means, sP is the pooled sample standard deviation, and nA and nB are the sample sizes.

B: To create a 98% confidence interval for the difference in the placebo and the new drug, we will use the formula:

CI = (xB - xA) ± tα/2,sP × √(1/nA + 1/nB)

where xA and xB are the sample means, sP is the pooled sample standard deviation, nA and nB are the sample sizes, and tα/2,sP is the t-value corresponding to a 98% confidence level with 18 degrees of freedom.

Using the values from Part A, we have:

CI = (18.3 - 9.7) ± 2.101 × 8.064 × √(1/10 + 1/10)

= 8.6 ± 5.103

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The correct question is:

Twenty middle-aged men with glucose readings between 90 milligrams per deciliter and 120 milligrams per deciliter of blood were selected randomly from the population of similar male patients at a large local hospital. Ten of the 20 men were assigned randomly to group A and received a placebo. The other 10 men were assigned to group B and received a new glucose drug. After two months, posttreatment glucose readings were taken for all 20 men and were compared with pretreatment readings. The reduction in glucose level (Pretreatment reading − Posttreatment reading) for each man in the study is shown here.

Group A (placebo) reduction (in milligrams per deciliter): 12, 8, 17, 7, 20, 2, 5, 9, 12, 6

Group B (glucose drug) reduction (in milligrams per deciliter): 29, 31, 13, 19, 21, 5, 24, 12, 8, 21

Part A: Do the data provide convincing evidence, at the α = 0.02 level, that the glucose drug is effective in producing a reduction in mean glucose level?

Part B: Create and interpret a 98% confidence interval for the difference in the placebo and the new drug.

Which of the following pairs consists of equivalent fractions? 3/9 and 5/15 ,12/20 and 20/25,5/6 and 6/5,6/12 and3/4

Answers

Answer:

[tex]The[/tex] [tex]Answer[/tex] [tex]Is:[/tex] [tex]\frac{3}{9}[/tex] [tex]&[/tex]& [tex]\frac{5}{15}[/tex]

Step-by-step explanation:

Divide by 4 , 2nd fraction Divide by 5:

3/4 ≠ 4/5

5/6 ≠ 6/5 We can already see it.

Divide by 3. . .

2/4 ≠ 3/4

Divide by 3 , 2nd fraction Divide by 5:

1/3 = 1/3 [tex]Perfect![/tex]

The answer is, [tex]\frac{3}{9}[/tex] & [tex]\frac{5}{15}[/tex]

Natasha is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 20 inches × 15 1 4 inches. She needs to cut another rectangle that is 10 1 2 inches by 10 1 4 inches. How many total square inches of construction paper does Natasha need for her project? Mixed number

Answers

To find the total area of construction paper needed for the project, we need to find the area of each rectangle and then add them together.

The area of the first rectangle is:

20 inches × 15 1/4 inches = 20 × (60/4 + 1/4) = 20 × 61/4 = 20 × 15.25 = 305 square inches

The area of the second rectangle is:

10 1/2 inches × 10 1/4 inches = (10 × 2 + 1/2) × (40/4 + 1/4) = 21 × 41/4 = 21 × 10.25 = 215.25 square inches

Therefore, the total area of construction paper needed for the project is:

305 + 215.25 = 520.25 square inches

So, Natasha needs 520 1/4 square inches of construction paper for her project.

Solve for x. Round to the nearest tenth, if necessary.

Answers

The calculated value of x in the right triangle is 8.7

Calculating the value of x in the right triangle

From the question, we have the following parameters that can be used in our computation:

The right triangle

The value of x in the right triangle can be calculated using the following sine ratio

sin(75) = x/9

Cross multiply the equation

So, we have

x = 9 * sin(75)

Evaluate the products

x = 8.7

Hence, the value of x in the right triangle is 8.7

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Find the surface area of the triangular prism. A triangular prism. The base is a right triangle with base and height 4 millimeters, and the third side 5.7 millimeters. The height of the prism is 3 millimeters.

Answers

The surface area of the triangular prism is approximately 44.29 square millimeters.

What is surface area?

Surface area is the total area that the surface of a three-dimensional object covers. It is a measure of the amount of space that the surface of an object occupies. Surface area is usually measured in square units such as square meters, square centimeters, square inches, or square feet.

What is the area?

The total space occupied by a flat (2-D) surface or the shape of an object is defined as its area.

The area of a plane figure is the space enclosed by its boundary.

According to the given information:

To find the surface area of a triangular prism, we need to add up the area of all the faces. A triangular prism has three rectangular faces and two triangular faces.

Let's start by finding the area of the triangular faces. The base of the triangular prism is a right triangle with base 4 millimeters, height 4 millimeters, and hypotenuse 5.7 millimeters. We can use the Pythagorean theorem to find the missing side:

[tex]a^2 + b^2 = c^2\\4^2 + 4^2 = 5.7^2[/tex]

16 + 16 = 32.49

32 = 32.49 - 0.49

32 = 32

So the missing side has length [tex]\sqrt{(5.7^2 - 4^2)} =3.69 millimeters.[/tex] This is the base of each triangular face.

The height of the triangular prism is 3 millimeters, so the height of each triangular face is also 3 millimeters.

The area of each triangular face is:

(1/2) × base × height

= (1/2) × 3.69 × 3

≈ 5.54 square millimeters

So the total area of the two triangular faces is:

2 × 5.54= 11.08 square millimeters

Now let's find the area of each rectangular face. The length of each rectangular face is the same as the base of the triangular face, which is 3.69 millimeters. The width of each rectangular face is the height of the triangular prism, which is 3 millimeters.

The area of each rectangular face is:

length × width

= 3.69 × 3

≈ 11.07 square millimeters

So the total area of the three rectangular faces is:

3 × 11.07

= 33.21 square millimeters

To find the surface area of the triangular prism, we add up the area of all five faces:

11.08 + 33.21

= 44.29 square millimeters

Therefore, the surface area of the triangular prism is approximately 44.29 square millimeters.

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Please if you know the answer put the steps on thank you.

Answers

Answer:

1. # of people who predicted they would pass = 30

2. # of people who predicted they would fail = 20

3. # of people who predicted they would pass and actually passed = 27

4. # of people who predicted they would pass and actually failed = 3

5. # of people who predicted they would fail and actually passed = 11

6. # of people who predicted they would fail and actually failed = 9

Step-by-step explanation:

1. # of people who predicted they would

The total number of people who took the test is 50.The number of people who predicted they would pass is 30.The number of people who predicted they would fail is 20 (since 50 - 30 = 20)Let x be the number of people who predicted fail and actually passed the test. Since three times as many people who passed predicted pass than predicted fail, we know that 3x is the number of people who predicted pass and actually passed the test. Therefore, the total number of people who passed the test is x + 3x = 4x, and we know that 36 people passed the test, so 4x = 36, and x = 9.Since x is the number of people who predicted fail and actually passed the test, then the number of people who predicted fail and actually failed the test is 20 - x = 20 - 9 = 11.The number of people who predicted pass and actually passed the test is 3x = 3(9) = 27.The number of people who predicted pass and actually failed the test is 30 - 27 = 3.

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A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took
13.5
m
2
13.5 m
2
13, point, 5, start text, space, m, end text, squared of material to build the cube.
What is the volume inside the giant sugar cube?
Give an exact answer (do not round).

Answers

The volume of the inside of the giant sugar cube would be = 3.375cm³

How to calculate the volume of a cube using the given surface area?

To calculate the volume of a cube, the side length should first be determined from the surface area given.

But the formula for surface area of a cube = 6a²

That is;

surface area = 13.5cm²

a = ?

13.5 = 6(a)²

13.5/6 = a²

a = √13.5/6

= √2.25

= 1.5cm

Therefore the volume of the cube = a³

= 1.5³

= 3.375cm³

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Complete question:

A candy store called "Sugar" built a giant hollow sugar cube out of wood to hang above the entrance to their store. It took 13.5m² of material to build the cube. What is the volume inside the giant sugar cube? Give an exact answer (do not round).

How to solve -10(x-1.7)=-3 by expanding first

Answers

To solve the equation -10(x-1.7)=-3 by expanding first, we need to apply the distributive property of multiplication.

Expanding -10(x-1.7), we get

-10x + 17 = -3

Now we can solve for x by isolating the variable on one side of the equation. To do this, we'll add 10x to both sides of the equation

-10x + 17 + 10x = -3 + 10x

Simplifying, we get

17 = 10x - 3

Next, we add 3 to both sides of the equation

17 + 3 = 10x - 3 + 3

Simplifying, we get

20 = 10x

Finally, we divide both sides of the equation by 10 to isolate x

20/10 = 10x/10

Simplifying, we get

2 = x

Therefore, the solution to the equation -10(x-1.7)=-3 by expanding first is x = 2.

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I know how to use the explicit formula to find a_1, but having a_n-1 being multiplied by 2 has thrown me for a loop. I am not sure how to fit it into the formula.

Answers

The first four elements of the sequence are:

a11 = 5350

a12 = 10702

a13 = 21406

a14 = 42814

How to calculate the sequence

Starting with a11 = 5350, we can use the recursive formula to find a12:

a12 = 2a11 + 2 = 25350 + 2 = 10702

a13 = 2a12 + 2 = 210702 + 2 = 21406

a14 = 2a13 + 2 = 221406 + 2 = 42814

Therefore, the first four elements of the sequence are:

a11 = 5350

a12 = 10702

a13 = 21406

a14 = 42814

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pleaseeeee i need helppp in this

Answers

The resulting matrix formed by performing R2 -> 4R1 + R2 on M is given as follows:

[tex]M = \left[\begin{array}{ccc}-4&3&1\\-18&9&8\end{array}\right][/tex]

How to do the row operation?

The matrix in the context of this problem is defined as follows:

[tex]M = \left[\begin{array}{ccc}-4&3&1\\-2&-3&r\end{array}\right][/tex]

The rows of the matrix are given as follows:

R1: -4, 3 and 1.R2: -2, -3 and 4.

Hence the row 2 of the resulting matrix has the elements given as follows:

Column 1: 4 x -4 - 2 = -18.Column 2: 4 x 3 - 3 = 9.Column 3: 4 x 1 + 4 = 8.

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Solve for the missing angle measurements for angles a, b, c, and d

Answers

Note that the angle measurements are given as follows:

A = 145° (Sum of angles on a straight line.

B = 35° Opposite angles

C = 145° Opposite angels

D) = 35° supplementary angels.

What is the explanation of the above statements?

a) Note that Sum of angles on a straight line=180° and are therefore supplementary

b) All opposite angle are equal, since ∠b is opposite to 35°, then ∠b = 35°

c) 145° is also opposite to ∠c

d) when two angles are supplementary, it means that they sum up to 180°

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Full Question:

Solve for the missing angle measurements for angles a, b, c, and d
See the attached imge

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