Which type of force causes an object to stop sliding along a surface?
A. Compression
B. Tension
C. Electric
D. Friction

Answer:

Given,

Mass, m = 2kg

Height or distance, s = 20m

Initial velocity, u = 0m/s

Acceleration due to gravity, g = 10m/s (It is 9.8m/s but can be assumed 10m/s for simplifying calculations)

(Because the object is is just dropped)

Final velocity, v = ?

Solution

v^2 = u^2 + 2as (u^2 means u raised to power 2)

=> v^2 = 0^2 + 2*10*20

=> v^2 = 400

=> v = 20

Thus the velocity just before the body strikes the ground will be 20m/s.

Answer:

I ATE APPLE PIE YESTERDAY

Explanation:

Answer:

The train is traveling 18 meters per second.

Explanation:

540/30 = 18

To check your answer do 18 * 30 and it equals 540

Answer:

Ice is the solid state of water, a normally liquid substance that freezes to the solid state at temperatures of 0 °C (32 °F) or lower and expands to the gaseous state at temperatures of 100 °C (212 °F) or higher.

Explanation:

Answer:

[tex]H_t= 725.8[/tex]

Explanation:

From the question we are told that:

Acceleration of Dr Evil [tex]a=7.0m/s^2[/tex]

Struggle time [tex]t=11s[/tex]

Generally the Newton's equation for Height traveled is mathematically given by

 [tex]s = ut +\frac{1}{2} at2[/tex]

 [tex]s = 7*121/2[/tex]

 [tex]s= 423.25[/tex]

Generally the Newton's equation for Velocity at given time is mathematically given by

[tex]v= u+at \\ v= 0+7*11[/tex]

[tex]v= 77 m/s[/tex]

Generally the Newton's equation for Total Height [tex]H_t[/tex] is mathematically given by

[tex]v^2= u2+2as\\ v^2=772+2x(-9.8)s \\ s = 5929/19.6[/tex]

[tex]s=302.5m[/tex]

Therefore the total height is given as

[tex]H_t=423.3+302.5[/tex]

[tex]H_t= 725.8[/tex]

Answer:

220.7

Explanation:

distance traveled is 1.5*5=7.5m

PE gain is MGH=3*9.81*7.5=220.7

Answer:

I cheated on

Spanish

ELA

history

Explanation:

Answer:

thx

Explanation:

The magnitude of the angular acceleration of the pendulum at the moment of release is; α = 18.45 rad/s²

We are given;

Mass of rod; m = 1 kg

Length of rod; L = 49.8 cm = 0.498 m

Mass of Disk; M = 4 kg

Radius of disk; r = 24.9 cm = 0.249 m

Let us first calculate the torque acting from the formula;

τ = mg(L/2) + MgL

Thus;

τ = (1 × 9.8 × (0.498/2)) + (4 × 9.8 × 0.498)

τ = 21.96 N.m

Using parallel axis theorem, we can find the moment of inertia about the given axis as;

I = (mL²/3) + ½MR² + ML²

Plugging in the relevant values gives;

I = (1 * 0.498²/3) + ½(4 * 0.249²) + (4 * 0.498²)

I = 1.19 kg.m²

The angular acceleration is given by the formula;

α = I/τ

α = 21.96/1.19

α = 18.45 rad/s²

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Answer:

1st speed 2.velocity 3.speed4.velocity5.velocity6.speed

[tex]\\ \sf\longmapsto Work\:done=Force(Displacement)[/tex]

[tex]\\ \sf\longmapsto Force=\dfrac{Work\:done}{Displacement}[/tex]

[tex]\\ \sf\longmapsto Force=\dfrac{45}{5}[/tex]

[tex]\\ \sf\longmapsto Force=9N[/tex]

Given values:

Work done,

Displacement,

We know that,

→ [tex]Work \ done = Force\times Displacement[/tex]

or,

→ [tex]Force = \frac{Work \ done}{Displacement}[/tex]

By putting the values, we get

             [tex]= \frac{45}{5}[/tex]

             [tex]= 9 \ N[/tex]

Thus the response above is right.  

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Answer:

put it in a volcano

Explanation:

Answer:

d. R

Explanation:

There are 4 main types of blood – A, B, AB and O.

Blood is the most important component of our life. It is a fluid connective tissue which consists of plasma, blood cells and platelets. It circulates throughout the body and delivers oxygen. Among the given options R is not a blood type. The correct option is D.

It was Karl Landsteiner who discovered the ABO blood group system. There are 4 main blood groups,  they are A, B, AB and O. Your blood group is determined by the genes you inherit from your parents. Each blood group may be either RhD positive or RhD negative.

Blood group A has antigens on the red blood cells with anti-B antibodies in the plasma. Blood group B has B antigens with anti-A antibodies in the plasma. The blood group O has no antigens but both antibodies are present whereas AB has no antibodies.

Group O is the universal donor and AB is universal recepient.

Thus the correct option is D.

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Answer:

A fundamental theory that provides a description of the physical properties of nature at the scale of atoms and subatomic particles.

Explanation:

Answer:

the distance is 315.3696 m

Explanation:

The computation of the distance is given below:

Given that

Sound intensity = 1.67 × 10^-6 W/m^2

And, the distance = 233 m

Now as we know that

Power = Intensity × surface area

1.67 × 10^-6 × 4π(233)^2 = 1.67 × 10^-6 ÷ 2× 4π × d^2

d^2 = 2 × (223)^2

= √2 × 223

= 315.3696 m

Hence, the distance is 315.3696 m

Answer:

B. As gravity increases weight increases and as gravity decreases weight decreases

Explanation:

Option B is the correct answer.

From the information given, we can deduce that as the gravity increases, the weight also increases and as the gravity decreases, the weight decreases as well.

This is true from the  given table. On earth, the gravity of the man was 9.8m/s² and his weight 588N. But get to space, moon precisely, the gravity reduced to 1.62m/s². Then we discover that such decrease in his gravity also led to the sharp decrease in the weight. The weight decreased from 588N on earth to 96N on the moon.

This actually reveals that weight and gravity are related in a way. Weight of an object is known to be the force of gravity on the object. The weight actually vary as a result of varying gravity.

Answer: b

since the pull of gravity on the moon is less we weigh less.

Answer:

Fs = 17.66 N

Explanation:

The force of static friction is given by the following formula:

[tex]F_s = \mu R = \mu W\\[/tex]

where,

Fs = The force of static friction = ?

μ = coefficient of static friction = 0.9

W = weight of sneakers = mg

m = mass of sneakers = 2 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]F_s = \mu mg\\F_s = (0.9)(2\ kg)(9.81\ m/s^2)\\[/tex]

Fs = 17.66 N

The entire park area is considered to be a semi-arid desert, but distinct habitats are located at different elevations along the 8,000-foot elevation gradient. Near the Colorado River, riparian vegetation and sandy beaches prevail.

Answer:

92.7 km

Explanation:

Since the magnetic field due to a solenoid is given by B = μ₀Ni/L where  μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid, L = length of cardboard tube = 58 cm = 0.58 m, , i = current in wire = 2.5 A and l = length of wire.

So, N = BL/μ₀i

Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T

So, substituting the variables into the equation, we have

N = BL/μ₀i

N = 0.2 T × 0.58 m/(4π × 10⁻⁷ H/m × 2.5 A)

N = 1.16 Tm/(31.416 × 10⁻⁷ HA/m)

N = 0.0369 × 10⁷ turns

N = 0.0369 × 10⁷ turns

N = 3.69 × 10⁵ turns

length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m

So, l = NC

= NπD

= πND

= π × 3.69 × 10⁵ turns × 0.08 m

= 0.9274 × 10⁵ m = 9.274 × 10⁴ m

= 92.74 × 10³ m

= 92.74 km

≅ 92.7 km

The total legnth of the wire to built a solenoid will be  92.7 km

A solenoid is a electromagnet in which the wires are wounded on the outer surface of the soft iron and then the current is passed so due to flow of the current the magnetic field generated around the wire.

Since the magnetic field due to a solenoid is given by

B = μ₀Ni/L

where

μ₀ = permeability of free space = 4π × 10⁻⁷ H/m,

N = number of turns of solenoid,

L = length of cardboard tube = 58 cm = 0.58 m, ,

i = current in wire = 2.5 A and

l = length of wire.

Since B = 2.0 kG = 2.0 × 10³ G = 2.0 × 10³ × 10⁻⁴ T = 2.0 × 10⁻¹ T = 0.2 T

So, substituting the variables into the equation, we have

[tex]N=\dfrac{BL}{\mu_oI}[/tex]

[tex]N=\dfrac{0.2\times 0.58}{4\pi\times 10^{-7} \times 2.5}[/tex]

[tex]N=\dfrac{1.16}{31.416\times 10^{-7}}[/tex]

N = 0.0369 × 10⁷ turns

N = 0.0369 × 10⁷ turns

N = 3.69 × 10⁵ turns

length of wire l = NC where N = number of turns and C = circumference of tube = πD where D = diameter of tube = 8.0 cm = 0.08 m

So, l = NC

= NπD

= πND

= π × 3.69 × 10⁵ turns × 0.08 m

= 0.9274 × 10⁵ m = 9.274 × 10⁴ m

= 92.74 × 10³ m

= 92.74 km

≅ 92.7 km

Hence the total legnth of the wire to built a solenoid will be  92.7 km

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Volumes can be transfered to liters only when their measurement units are dm³. a) Which means that: 0.45m³=450dm³ you move the decimal place three places to the right because m³ is larger measurement unit than dm³. 375 cm³ = 0.375 dm³; 75cl = 0.75l because of the prefix centi. 0.6dm³ = 0.6 dm³

So it will be 450l; 0.375l; 0.75l; 0.6l

b) 450l>0.75l>0.6l>0.375l

0.45m³>75cl>0.6dm³>375cm³

I hope i didn't make a mistake, but it would be good if somebody else answered too, so you can compare the answers and see if i made a mistake

The given volumes in liter will be 450 L, 0.375 L, 0.75 L, 0.6 L and the arrangement in descending order will be 450 L > 0.75 L > 0.6 L > 0.37 L .

Every three-dimensional item takes up space in some way. The volume of this area is what is used to describe it. The area covered within an entity's three-dimensional bounds is referred to as its volume. The object's size is another name for it.

As per the given information in the question,

a.

The given volume in a meter cube is 0.45.

Unit conversion:

1 m³ = 1000 L

So, 0.45 m³ = 0.45 × 1000

= 450 L

The given volume in a centimeter cube is 375.

Unit conversion:

1 cm³ = 0.001 L

375 cm³ = 0.001 × 375

= 0.375 L.

The given volume in a centiliter cube is 75.

Unit conversion:

1 cl³ = 0.01 L

75 cl³ = 75 × 100

= 0.75 L

The given volume in the decimeter cube is 0.6.

1 dm³ = 1 L

0.6 dm³  = 0.6 L

b.

So, the volumes in descending order will be,

450 L > 0.75 L > 0.6 L > 0.37 L or,

0.45 m³ > 75 cl³ > 0.6 dm³ > 375 cm³

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Answer:

koh

Explanation:

it is a basic substance that reacts with the lipids on your fingers, as soon as you touch it, to form soap

Complete question

To reduce the drag coefficient and thus to improve the fuel efficiency, the frontal area of a car is to be reduced. Determine the amount of fuel and money saved per year as a result of reducing the frontal area from 18 to 14 ft2. Assume the car is driven 12,000 mi a year at an average speed of 55 mi/h. Take the density and price of gasoline to be 50 lbm/ft3 and $3.10/gal, respectively; the density of air to be 0.075 lbm/ft3, the heating value of gasoline to be 20,000 Btu/lbm; and the overall efficiency of the engine to be 30 percent. Take the drag coefficient as CD=0.3 for a passenger car.

Answer:

22.22%

$57

Explanation:

From the question we are told that

Initial area of frontal area [tex]a_1=18ft^2[/tex]

Final area of frontal area [tex]a_2=14ft^2[/tex]

Distance covered a year [tex]D=12000mile[/tex]

Average speed a year [tex]V_{avg}=55mile/h[/tex]

Density [tex]\rho=50 lbm/ft3[/tex]

Price [tex]P= $3.10/gal[/tex]

Density of air [tex]\rho_{air} 0.075 lbm/ft3[/tex]

Heating value of gasoline [tex]Q=20,000 Btu/lbm[/tex]

Efficiency [tex]\eta=30\%[/tex]

Drag coefficient [tex]CD=0.3[/tex]

[tex]\triangle A=18-14ft^2=4ft^2[/tex]

Generally the equation for drag force [tex]C_D[/tex] is mathematically given as

[tex]F_D=\frac{C_DAPV^2}{2}[/tex]

[tex]F_D=\frac{0.3*18*0.075*(80.685^2)*A}{2}[/tex]

[tex]F_D=73.24Alb[/tex]

where [tex]v=55mil/h*1.467=80.685ft/s[/tex]

Generally the equation for work done W is mathematically given as[tex]W=F_D*L[/tex]

where [tex]L=12000mile*5280[/tex]

[tex]L=63360000[/tex]

[tex]W=73.24A*63360000[/tex]

[tex]W=4.6*10^9A[/tex]

Generally the equation for overall efficiency [tex]\eta[/tex] is mathematically given as

where

[tex]W_{req}=required\ gasoline\ power\ efficiency[/tex]

[tex]\eta=\frac{W}{W_{req}}[/tex]

[tex]W_{req}=\frac{W}{\eta}[/tex]

[tex]W_{req}=\frac{4.6*10^9}{0.3}[/tex]

[tex]W_{req}=1.55*10^{10}A[/tex]

Generally the equation for reduction fee with change in frontal area [tex]\triangle M[/tex] is mathematically given as

[tex]\triangle M =\triangle Vgasoline*cost[/tex]

Where

[tex]\triangle Vgasoline= volume\ reduction\ of\ gasoline[/tex]

[tex]\triangle Vgasoline=\frac{E_{req}}{H*P}[/tex]

[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]

if

[tex]20000btu/ibm=20000*778.169*32.2(1bm.ft^2/s)[/tex]

[tex]\triangle Vgasoline=\frac{1.55*10^{10}A}{20000*778.169*32.2*50}[/tex]

[tex]\triangle Vgasoline=0.61859A[/tex]

Therefore

[tex]\triangle M =0.61859A*3.10[/tex]

if [tex]1ft^2=7.48gal[/tex]

[tex]\triangle M =0.61859(4)*3.10*7.48[/tex]

[tex]\triangle M = \$ 57.671[/tex]

Generally the equation for reduction of fuel [tex]F_r[/tex]is mathematically given as

[tex]F_r=\frac{\triangle A}{\triangle i}*100[/tex]

where

[tex]\triangle i=18ft^2[/tex]

[tex]F_r=\frac{4}{18}*100[/tex]

Fuel reduction price by reducing front area is 22.22%

Money saved per year is $57

Answer:

The answer is "0.91238 and 744.8"

Explanation:

In this scenario it is easier to take a person to the water-pool than to transport the people in the air, as the person's strength is increased by water upwards:

[tex]f_b \to m \to mg =person \\\\F_B \ in\ air = v\ & air\ g \\\\[/tex]

               [tex]=0.076 \times 1.225 \times 9.8 \\\\ =0.91238 \ N\\\\[/tex]

[tex]F_B \ in \ water = v \& water \ g \\\\[/tex]

                    [tex]=0.076 \times 1000 \times 9.8\\\\= 744.8 \ N\\[/tex]

Answer:

Explanation:

The answer is C  i think

a. 75 kg, The mass of an object is the amount of matter that constitutes that object and is independent of the acceleration of gravity and is constant under any circumstances.

_________________________________

b. Weight = mass × gravity acceleration

♡ On the Earth : Weight = 75 × 10

Weight = 750 N

♡ On the Venus : Weight = 75 × 8.87

Weight = 665.25 N

A). force

hope it helps and your day will be full of happiness

Answer: D. The object would have an acceleration of 6 m/s/s to the right.

Explanation:

I got it right on USA test prep