which question is the student most likely trying to answer?

Explanation:

A covalent bond can be thought of as a 'shared pair' of electrons, so there are 2 electrons in each bond. That means that a double bond will have 4 electrons in the space between the bonded nuclei, and a triple bond will have 6.

Answer:

ijcQwertyjkllmnnbbvcxzssssdttyyjnnnvvcxyj

Question 1 :

V1/T1 = V2/T2

3.0L/273K = V2/373K

To get the value of Z, cross multiply

3.0L x 373K = 273K x V2

1119 = 273V2

Divide both sides by 273

1119/273 = 273V2/273

4.10L = V2

The new volume is 4.10 liters

Question 2 :

P1/T1 = P2 /T2

P1 = 880 kPA= 880 *10^3 Pa

T1 = 250 K

T2 = 303 K

P2 =?

Substituting for P2

P2 = P1 T2/ T1

P2 = 880 kPa * 303 / 250

P2 = 266,640 kPa/ 250

P2 = 1066.56 kPa.

The new pressure of the gas is 1066.56 kPa

Question 3 :

Given that:

Volume of gas V = 4.80L

(since 1 liter = 1dm3

4.80L = 4.80dm3)

Temperature T = 62°C

Convert Celsius to Kelvin

(62°C + 273 = 335K)

Pressure P = 2.9 atm

Number of moles of gas N = ?

Apply ideal gas equation

pV = nRT

2.9atm x 4.8dm3 = n x (0.0082 atm dm3 K-1 mol-1 x 335K)

13.92 atm dm3 = nx 2.747 atm dm3 mol-1

n = 13.92/2.747

n = 5.08 moles

There are 5.08 moles of gas contained in the sample

Question 4 :

Volume of gas V = 3.47L

(since 1 liter = 1dm3

3.47L = 3.47dm3)

Temperature T = 85.0°C

Convert Celsius to Kelvin

(85.0°C + 273 = 358K)

Pressure P = ?

Number of moles of gas N = 0.100 mole

Apply ideal gas equation

pV = nRT

p x 3.47dm3 = 0.10 x (0.0082 atm dm3 K-1 mol-1 x 358K)

p x 3.47dm3 = 0.29 atm dm3

p = (0.29 atm dm3 / 3.47 dm3)

p = 0.085 atm

If 1 atm = 760 mm Hg

0.085atm = 0.085 x 760

= 64.6 mm Hg

The pressure of the gas is 64.6 mm hg

Answer:

400x

Explanation:

magnification=magnification of objective lens*magnification of eyepiece lens

m=40*10

m=400x

Answer:

a charge on a solar battery cell

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Lens and Ray Optics.

We must understand the Concept that,

1.) When a beam of parallel light pass through a Convex lens, all the rays get deviated and converges to a special point at the axis that is a Focus.

2.) When a beam of light passes through the Concave lens,the light beams diverge from one another forming a virtual focus in the primary side of lens,

Hence the above given diagram beam rays are diverging, it is a CONCAVE LENS

answer is C.) Concave lens

Answer:

1.73 Molar

Explanation:

The formula is Molarity=moles of solute/liters of solution, which can be written in whatever way you prefer, and examples include: M=N/V or M=mol/L.

M=N/V

M= [tex]\frac{5.63}{3.25}[/tex]

Divide 5.63 by 3.25. When you calculate this, you get 1.73, therefore your answer is 1.73 molar.

Answer:

It wouldn't let me post it for some reason. Its all in the picture.

:)

Answer:

''The relationship between air pressure, air density, or altitude? As altitude increases, pressure increases. As altitude increases, air density increases. Air pressure and density are lowest at sea level.''

Explanation:

Answer:

isn't that evaporation if not you can just delete my answer-

Explanation:

Answer:

open system

Explanation:

An open system is a system in which both energy and matter are exchanged with the surroundings.

Answer:

4. 264.6J

5. 37.5J

6. 96J

7. 55Watts

8. 77.14m

9. 6s

10. 750Watts

Explanation:

4). Mechanical energy (potential energy) = mass (m) × acceleration due to gravity (g) × height (h)

m = 3kg, h = 9m, g = 9.8m/s²

P.E = 3 × 9 × 9.8

= 264.6J

5). Kinetic energy (K.E) = 1/2 × m × v²

Where;

m = mass (kg) = 3kg

v = velocity (m/s) = 5m/s

K.E = 1/2 × 3 × 5²

K.E = 1/2 × 3 × 25

K.E = 1/2 × 75

K.E = 37.5J

6). Work done (J) = Force (N) × distance (m)

Force = 12N, distance = 8m

Work done = 12 × 8

= 96J

7). Power = work done (J) ÷ time (s)

Work done = 550J, time = 10s

Power = 550/10

= 55Watts.

8). Work done = force (F) × distance (m)

Work done = 540J, force = 7N, distance = ?

540 = 7 × d

540 = 7d

d = 540/7

d = 77.14m

9). Power = work done (J) ÷ time (s)

Work done = 300J, time = ?, Power = 50Watts.

50 = 300/t

50t = 300

t = 300/50

t = 6seconds.

10). Power = work done (J) ÷ time (s)

This means that;

Power = force × distance / time

Force = 300N, distance = 5m, time = 2s

Power = 300 × 5 ÷ 2

Power = 1500 ÷ 2

Power = 750Watts

Answer:

0.1389mol

Explanation:

no of mol of Al in 7.5g=7.5g/27gmol^-1

=75/270mol

according to tge chemical equation

2mol of Al:1 mol of Al2S3

1mol of Al:0.5mol of Al2S3

therefore 75/270 mol of Al : 0.5*75/270 mol of Al2S3

=0.1389mol

Answer:

A!!!!!!!!

Explanation:

Answer:

3532.8

Explanation:

Answer:

The 2 types of behavioral adaptation are migration, and hibernation. Explanation: Adaptation of animal is the fitness towards its environment.

Explanation:

Answer:

Carbon, helium, and sodium are monoatomic elements.

Hydrogen, iodine, and oxygen are diatomic elements.

Explanation:

Answer:

Oh so so sorry about that. and thanks for caring for us. anyway we are good wbu

Explanation:

im good. i just ate applesauce lol :)

Answer:

There will not be effect on the gas

Explanation:

I'm sure that it's correct answer

Answer and Explanation:

D I believe..

Answer: The saltiest locations in the ocean are the regions where evaporation is highest or in large bodies of water where there is no outlet into the ocean. The saltiest ocean water is in the Red Sea and in the Persian Gulf region (around 40‰) due to very high evaporation and little fresh water inflow.

Explanation: Sea water salinity is expressed as a ratio of salt (in grams) to liter of water. In sea water there is typically close to 35 grams of dissolved salts in each liter. It is written as 35‰ The normal range of ocean salinity ranges between 33-37 grams per liter (33‰ - 37‰).But as in weather, where there are areas of high and low pressure, there are areas of high and low salinity. Of the five ocean basins, the Atlantic Ocean is the saltiest. On average, there is a distinct decrease of salinity near the equator and at both poles, although for different reasons.Near the equator, the tropics receive the most rain on a consistent basis. As a result, the fresh water falling into the ocean helps decrease the salinity of the surface water in that region. As one move toward the poles, the region of rain decreases and with less rain and more sunshine, evaporation increases.Fresh water, in the form of water vapor, moves from the ocean to the atmosphere through evaporation causing the higher salinity. Toward the poles, fresh water from melting ice decreases the surface salinity once again. Water has a unique property. As the temperature decreases to 40°F (4°C) the molecules slow, water contracts and the density increases. Below 40°F (4°C) the molecules begin to bond to each other and as they do, the water begins to expand again, decreasing the density. At 32°F (0°C) all molecules are locked into a crystalline structure with a resulting nine percent expansion in size. This expansion, and corresponding decrease in density, is the reason ice floats. The amount of salt in sea water also determines the temperature at which sea water freezes. Adding salt to water lowers the freezing temperature. Water with a salinity of 17‰ freezes at about 30°F (-1°C) and 35‰ water freezes at about 28.5°F (-2°C). Yet, despite the saltiness of the ocean, sea ice contains very little salt, about a tenth of the amount of salt that sea water has. This is because ice will not incorporate sea salt into its crystal structure. Therefore, sea ice is actually drinkable. The temperature and salinity of the sea water also help determine its density. As the temperature of sea water decreases the density also increases. Also, as the salt content of sea water increases, so does its density. This makes the density of sea water, unlike fresh water, below the freezing point. So, in situations of sea ice formation, the salinity, and therefore the density of the underlying water continues to increase well after an area is iced over.

In the "Average Salinity" map (below), it shows the lowest salinity in the polar regions. Bear in mind, this image depicts surface salinity only. The surface salinity is lower in the polar regions than in the tropical regions due to melting each summer. However, each winter below the ocean surface, the increased salinity in the water due to ice formation, causes the water below the ice to sink and that sinking motion governs the motion of the ocean's deep-water currents.

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

[tex] V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3} [/tex]

[tex] V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3} [/tex]

The total volume is given by:

[tex] V_{T} = V_{o} - V_{i} [/tex]

Where:

[tex] V_{i} [/tex]: is the inner volume

[tex]r_{i}[/tex]: is the inner radius = 1.25/2 = 0.625 m

[tex] V_{o} [/tex]: is the outer volume

[tex]r_{o}[/tex]: is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

[tex] V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3} [/tex]

Now, by using the density we can find the mass of the Igloo:

[tex] m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g [/tex]

Finally, the value (V) of the antiquity is:

[tex] V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6} [/tex]  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

Answer:

Carbon dioxide and water.

Explanation:

If there isn't carbon dioxide, photosynthesis wouldn't happen as carbon dioxide is needed to transfer into the plant and after that the oxygen travels into the surroundings from the plant. There isn't any water, the plant wouldn't be able to make food called glucose.

Answer:

6.39 × 10^23 kg (0.107 M⊕)

Explanation:

Answer:

A number is right I think

Answer:

A.

beryllium fluoride

I hope it is helpful...