Which of the following statements is true about two objects in thermal equilibrium

The stages of the baby birth are Dilation, strong contractions, and delivery of the baby and the placenta.

Dilation, intense contractions, and delivery of the baby and placenta are the phases of a baby's birth.

The stages of the birth process are as follows;

1. The first stage includes the latent phase, in which cervical dilation begins (3 to 5 cm) along with mild contractions, and the active phase, in which strong contractions occur along with complete or nearly complete dilation.

2. The second stage is fetus expulsion or delivery, in which the cervix is fully dilated, and the baby is born.

3. The third stage is placenta delivery or expulsion, which occurs as the placenta is delivered.

4. Dilation, intense contractions, and delivery of the baby and placenta are the phases of labor and delivery.

Hence,the stages of the baby birth are Dilation, strong contractions, and delivery of the baby and the placenta.

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Answer:

the answer is -dilation and thinning of the cervix, delivery of the fetus, delivery of the placenta

Explanation:

i took a quiz and got it right

If the trend changed toward traditional (pre-World War II) families, the women’s rights are employment in manufacturing sector.

The war between two countries to take over each other's kingdom using weapons to kill each other.

Before the world war, the army needs armor, weapons, guns and tanks. Their manufacturing is only possible with many workers to work for long hours. If the men are not enough, then women are given opportunities to work with them.

Thus, the women’s rights are employment in manufacturing sector when trend changed traditional families.

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Answer:

532063

Explanation:

If he's shooting 333 arrows per shot and has 177177177 arrows, you need to divide to find the number of arrows he can shoot total, ignoring the decimal since you can't shoot a partial arrow.

177177177/333=532063

Answer:

MOST : E         LEAST :  D

Explanation:

Grav attraction = G m1 m1 / r^2    

        G  and   'r' are the same for all of the pictures, so the one picture with the biggest mass has the MOST attraction     and the  one with the least mass has the least attraction.

The pair with the largest gravitational attraction is the Earth and the Moon.

The pair with the smallest gravitational attraction is the Earth and a grain of sand.

The gravitational force between two masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In other words, the more massive the objects, the stronger the gravitational force between them. The closer the objects are, the stronger the gravitational force between them.

The Earth and the Moon are the most massive objects in the pair. The Earth has a mass of about 5.972 × 10²⁴ kg, and the Moon has a mass of about 7.34 × 10²² kg. The distance between the Earth and the Moon is about 384,400 km.

The grain of sand is much less massive than the Earth or the Moon. The mass of a grain of sand is about 10⁻⁶ kg. The distance between the Earth and a grain of sand is much greater than the distance between the Earth and the Moon.

Therefore, the gravitational attraction between the Earth and the Moon is much stronger than the gravitational attraction between the Earth and a grain of sand.

Here is a table of the gravitational attractions for each pair of masses:

Pair of masses Gravitational attraction

Earth and Moon 1.98 × 10²⁰ N

Earth and a grain of sand 1.0 × 10⁻¹⁷ N

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If the angle between their initial directions was 90 ∘ , their speed after the collision will be 4.35 m/s.

When two moving bodies after colliding stick to each other and move together is called the inelastic collision.

In inelastic collision , momentum is remains conserved.

Initial momentum =Final momentum

m₁u₁ +m₂u₂ = (m₁ +m₂ )v

where, u₁ and u₂ represents initial velocities of two hockey players and v₁ and v₂ shows the final velocities.

m₁ =m₂ =m and u₁ = u₂ =u

Substitute the values from the question, we get

2mu = 2mv

u =v

u = v x cos (θ/2)

u = 6.15 cos(90/2)

u = v = 4.35 m/s

Thus, the speed after collision is 4.35 m/s.

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Answer:

The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is 3.92 m/s.

Explanation:

Let's use Newton's 2nd Law to help solve this problem.

The force acting on the Ferris wheel is the centripetal force, given in the problem: [tex]F_c=115 \ \text{N}[/tex].

The mass "m" is the sum of the man and woman's masses: [tex]85+65= 150 \ \text{kg}[/tex].

The acceleration is the centripetal acceleration of the Ferris wheel: [tex]a_c=\displaystyle \frac{v^2}{r}[/tex].

Let's write an equation and solve for "v", the tangential (linear) acceleration.

The Ferris wheel's tangential velocity is 3.92 m/s.

Answer:

B) Warm radiates to Cool

Explanation:

Radiation transfers thermal energy without need for contact, where areas with higher thermal energy (hot) transfer energy to areas with lower thermal energy (cold)

The charge distribute on the inner surface with the radius r₁ will be zero,In the region r₁<r<r₂  will also zero. While on the outer surface with radius r₂ will be -q.

The total electric flux out of a closed surface is equal to the charge contained divided by the permittivity,

According to Gauss Law. the electric flux in a given area is calculated by multiplying the electric field by the area of the surface projected in a plane perpendicular to the field.

From the Gauss law, it is stated that the field inside the conductor is zero. Charge will lie only on the surface.

(a)The charge distribute on the inner surface with the radius r₁ will be zero.

(b) In the region r₁<r<r₂  will also zero.

(c)The outer surface with radius r₂ charge distribution  will be -q.

Hence, the charge distribute on the inner surface with the radius r₁ will be zero,

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Answer: Hello! I'm Jungkook. Here is your answer.....

A. conductivity

Explanation:

Hope this helps! Anneyong/Bye!

xoxoKookie

Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

 if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

Answer:

A) The stomach breaks down the food and passes it to the small intestine to be digested further.

Explanation:

I am pretty sure it is the first option because there is no way the stuff you eat can be turned into a liquid, it wouldn't make sense for the stomach to pass the digested food from small intestine to large intestine, so it would have to be the first one. A out of all of the options makes more sense and the stomach has to pass the digested food somewhere.

I hope I helped you

Answer:

At least they found him.

Explanation:

The magnitude of the frictional force opposing the applied force is 50 N.

The friction is caused due to the relative motion between two uneven contacting surfaces.

Given is the mass of trunk m = 20kg, kinetic coefficient of friction μ = 0.255.

The normal force acting on the trunk N = mg

N = 20 kg x 9.81m /s²

N = 196.2 Newton

The friction force is

f =μN

f = 0.255 x 196.2

f =50.031 N

Thus, the  magnitude of the frictional force opposing the applied force is approximately 50N.

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Answer:

a) 6.4 x 10^-12 cm^3

b) 17 x 10^-6 mm^2

Explanation

a). The shape is assumed to be spherical The volume = volume of a sphere = \frac{4}{3} \pi r^3

3

4

πr

3

V = \frac{4}{3}*3.142* 1.15^3

3

4

∗3.142∗1.15

3

= 6.3715 μm^3

1 μm^3 = 10^-12 cm^3

6.3715 μm^3 = 6.3715 x 10^-12 cm^3

==> 6.4 x 10^-12 cm^3

Answer:

See below

Explanation:

Volume of a sphere = 4/3 pi r^3

   we are given diameter   r = 1/2 dia = 1.45 u-meter = 1.45 x 10^-4 cm

  4/3  pi (1.45 x 10^-4)^3 = 1.277 x 10^-11   cm^3    = VOLUME

1.45 u-meter = .00145 mm

Surface area = 4 pi r^2 =  4 pi (1.45 x 10^-3 ) ^2 = 2.64 x 10^-5 mm^2

In the velocity vs. time graph, the displacement of the object after 1 second is 3 m.

The displacement of an object is the change in position of the object.

From the graph, the displacement of the object after 1 second is calculated as follows;

x = vt

where;

x = 3 x 1 = 3 m

Thus, in the velocity vs. time graph, the displacement of the object after 1 second is 3 m.

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Answer:

The speed is =15.91ms−1. The time is =6.92s

Explanation:

Answer:

4

Explanation:

We can say the motion of the object is stopped when its velocity is 0. That means we just have to check how many times the line of the graph intersects the x-axis. Hence, we can say that the object of the motion is stopped 4 times.

The angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].

The velocity of a particle when moving in the circular path.

Let speed of the bug with respect to ground is u.

Speed of bag with respect to ring will be

v = u - (- Rω) =

Then, u = v- Rω...............(1)

Angular momentum of ring and bug will remain conserved.

Initial  momentum: L ring + Lbug =0

Final  momentum:  -2m₁ R²ω + m₂uR =0...............(2)

Using equation (1) and (2), the angular velocity expression will be

ω =[m₂v / {(2m₁ +m₂)R}] in positive z direction

Thus, the angular velocity of the ring when the bug is halfway around and the angular velocity of the ring when the bug is back at the pivot is [m₂v / {(2m₁ +m₂)R}].

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Answer:

S = V t + 1/2 g t^2    where the ball has a speed of V and falls for .2 sec

6 = V t + 4.9 * .04 = V * .2 + .2

V = (6 - .2) / .2 = 29 m/s      speed entering area

T = V / g = 29 / 9.8

T = 2.96 sec      time to reach speed V

H = 1/2 g t^2   time to fall a distance H

H = 4.9 * 2.96^2 = 42.9 m      height from which ball was dropped

Check using first equation:

S = 29 * .2 + 4.9 + .2^2 = 6 m

∑F=m.a = m.(Δv/Δt)

∑F=2.16 x (27-0/10)

∑F=5.832 N

Answer:

When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon)

A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by. E=hf=hcλ(energy of a photon) E = h f = h c λ (energy of a photon) , where E is the energy of a single photon and c is the speed of light.

Hello!

We can use the following equation for magnetic force on a moving particle:

[tex]F_B = qv \times B[/tex]

[tex]F_B[/tex] = Magnetic Force (? N)

q = Charge of particle (1.28 × 10⁻⁵C)
v =velocity of particle (5.63× 10⁷m/s)

B = Strength of magnetic field (8.91 × 10⁻⁴T)

This is a cross-product, so the magnetic force depends on the SINE of the angle between the particle's velocity vector and the magnetic field vector.

Since the charge is moving PERPENDICULAR to the field, the angle between the velocity and magnetic field is 90°. The sine of 90° = 1, so we can simplify the equation to:

[tex]F_B = qvB(1) = qvB\\[/tex]

Plug in the values and solve.

[tex]F_B = (1.28*10^{-5})(5.63*10^7)(8.91*10^{-4}) = \boxed{\text{A. } 0.6421 N}[/tex]

Answer:

-10/3

Explanation:

the slope of the graph is negative,  the velocity is slowing.  so we know the positive answers are not correct.   next we just need to figure out how much of a slope the line has.   it's  down 10 and over 3... soo

-10/3 looks good ..     the format for the fraction is  rise / run .  in this case rise is negative, but other wise it's the same.