Which of the following is not true about taxes? A. Mandatory sum of money by government so that it can operate B. Due on April 15th C. largely collected to support private businesses D. Collected by the Internal Revenue Service (IRS)

Answer:

The charge pass through your hair dryer is 3000 C.

Explanation:

Given that,

Power = 1200 W

Voltage = 120 V

Flow time = 5 min

We need to calculate the current

Using formula of power

[tex]P=VI[/tex]

[tex]I=\dfrac{P}{V}[/tex]

Put the value into the formula

[tex]I=\dfrac{1200}{120}[/tex]

[tex]I=10\ A[/tex]

We need to calculate the charge pass through your hair dryer

Using formula of current

[tex]I=\dfrac{Q}{t}[/tex]

[tex]Q=It[/tex]

Put the value into the formula

[tex]Q=10\times5\times60[/tex]

[tex]Q=3000\ C[/tex]

Hence, The charge pass through your hair dryer is 3000 C.

Answer:

False

Explanation:

The cryosphere is all the part of the earth where water is in solid form. Where wind interacts with rocks, it is an example of atmosphere - geosphere interaction.

Answer:

   a = 4.0 m / s²,     so the result of the exercise is correct

Explanation:

This is an exercise on Newton's Second Law

               F = m a

we create a reference system with the horizontal x axis and the vertical y axis

Axis y

             N -W = 0

X axis

              F -fr = m a

give us the applied force F = 40 N, the value of the friction outside fr = 24 N

               a = (F - fr) / m

let's calculate

              a = (40 - 24) / 4

              a = 4.0 m / s²

so the result of the exercise is correct

Answer:

Airplane X has more gravitational potential energy than Airplane W

Explanation:

Gravitational potential energy is defined as "the energy acquired by an object due to its positional change in presence of gravitational force."

That being said, gravitational potential energy depends on the height of an object above the ground. It also depends on the mass of the object and even further, the amount of gravitational force that is applied.

And if we take a look at the question again, we'd agree that the two airplanes are flying at different heights, this means their gravitational potential energy will be different. And as such, Airplane X has more gravitational potential energy than Airplane W

Answer:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

Since electromagnetic waves do not require a medium to pass through, they are faster in matter that has fewer particles. ... ~ Sound cannot travel in a vacuum because mechanical waves, such as sound waves, require a medium to propagate through.

Answer:

lithium

Explanation:

I took physical science 2 years ago and passed with an A

Answer:

10389.6 J

Explanation:

Power is the rate of doing work with respect to time, its S.I unit is in watts but it can also be expressed in J/s. Power is calculated using the formula:

[tex]Power=\frac{energy}{time}[/tex]

Power is also the rate at which energy is used per second.

Energy is the capacity to do work and it is measured in joules (J).

Power = current × voltage = 7.4 A × 3 V = 22.2 W

[tex]Energy=power*time\\\\time=7.8\ min=7.8*60\ s=468\ s\\\\Energy=22.2*468\\\\Energy=10389.6\ J[/tex]

Answer:

The  density is  [tex]\rho_{block} =  356 \ kg/m^3 [/tex]

Explanation:

From the question we are told that

   The proportion of the plastic under water is  p =  0.356

Generally at equilibrium the buoyant force is equal to the weight of the block i.e

         [tex]B =  mg[/tex]

Generally the Buoyant force is mathematically represented as

          [tex]B  =  \rho  *  V *  g[/tex]

Here [tex]\rho[/tex] density of the water with value

[tex]\rho =  1000 kg/m^3[/tex] ,

V is the volume of water displaced by the block which is [tex] p * V_{block [/tex] ,  

So

    [tex]1000 *  0.356 V_{block}  *  g  =  m *  g[/tex]

Here m is the mass of the block which is mathematically represented  as

        [tex]m  =  \rho_{block}  *  V_{block}[/tex]

So

         [tex]1000 *  0.356 V_{block}  *  g  =   \rho_{block}  *  V_{block}*  g[/tex]

         [tex]1000 *  0.356 V_{block}  =   \rho_{block}  *  V_{block}*  g[/tex]

       =>    [tex]\rho_{block} =  1000 *  0.356[/tex]

      =>    [tex]\rho_{block} =  356 \ kg/m^3 [/tex]

Answer:

C. student viewed the ruler from a different angle

Explanation:

It is the problem of viewing the scale from different sides or angles. If we assume the actual length of the stick to be 22 cm. Then the first student measured the length by reading the values from 1 cm towards 22 cm on the scale. While, the second student measured the length of the stick by reading the values from the other side or the other angle of the scale, that is, from 30 cm mark towards 1 cm. And in that case the the length of the 22 cm long stick will appear  as:

30 cm - 22 cm = 8 cm

Therefore, the second student read 8 cm on scale. So, the correct option is:

C. student viewed the ruler from a different angle

Answer:

Explanation:

Displacement is the shortest distance or path between two points.

1) Displacement = √(36² + 45²) = 57.63 miles

2) Displacement = √(100² + 500²) = 509.9 meters

3) Displacement = √(60² + 40²) = 72.11 miles

4) Displacement = √(700² + 500²) = 860.23 miles

5) Displacement = 300 - 300 = 0 miles

6) Displacement = 200 + 100 = 300 miles

7) Displacement = √(650² + 650²) = 919.24 miles

8) Yes, since a distance is moved in a direction

Answer:

C

Explanation:

only if there is a net force of zero, the body will not move

some people may say B but that is wrong because maybe one force is greater than the other so the object would still move even though the forces are in opposite directions and parallel

Answer:

when the electron transferred permanently to another atom

Answer:

Explanation:

Formula for calculating normal force is expressed as:

[tex]F = ma\\since \ a = \frac{v^2}{r} \\F = \frac{mv^2}{r}[/tex]

m is the mass of the body = 50kg

v is the velocity of the Ferris wheel = 8m/s

r is the radius of the Ferris wheel

Substitute into the formula:

[tex]F = \frac{50 \times 8}{10}\\ F = \frac{400}{10}\\ F = 40N\\[/tex]

Hence the normal force of the seat is 40N

Answer:

3 in the back so it can shove it off the sand bar

Explanation:

Answer:

this depends on religion

Explanation:

some people believe in the big bang and some people believe in Jesus Christ and other gods.

big bang- Gravity

God- spoke

Answer:

V = 331.59m/s

Explanation:

First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.

S = ut + 1/2at²

Given height of the cliff S = 80m

initial velocity u = 0m/s²

a = g = 9.81m/s²

Substitute

80 = 0+1/2(9.81)t²

80 = 4.905t²

t² = 80/4.905

t² = 16.31

t = √16.31

t = 4.04s

Next is to get the vertical velocity

Vy = u + gt

Vy = 0+(9.81)(4.04)

Vy = 39.6324

Also calculate the horizontal velocity

Vx = 1330/4.04

Vx = 329.21m/s

Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.

V² = Vx²+Vy²

V² = 329.21²+39.63²

V² = 329.21²+39.63²

V² = 108,379.2241+1,570.5369

V² = 109,949.761

V = √ 109,949.761

V = 331.59m/s

Hence the speed of the shell as it hits the ground is 331.59m/s

Answer:

μk = 0.58

Explanation:

       [tex]F_{apph} = F_{app} * sin\theta = 126 N * sin 25 = 53.3 N[/tex]

       ⇒  [tex]F_{n} = - F_{apph} = -53.3 N[/tex]

       [tex]F_{g} = m_{b} * g = 8.5 Kg * (-9.8 m/s2) = -83.3 N[/tex]

       [tex]F_{appv} = F_{app}* cos\theta = 126 N * cos 25 = 114.2 N[/tex]

      [tex]F_{ff} = \mu_{k}* F_{n} =\mu_{k} * (-53.3 N)[/tex]

        μk = 0.58

Answer: 549.9 km

Explanation: 84.6km every hour so 84.6*6.5= 549.9

Answer:

4 bobux

Explanation:

one bobux

two bobux

three bobux

four bobux

Answer:

A. Loses PE and gains KE

Explanation:

Statement is incomplete. Complete statement of problem is:

1. An object from a certain height falls freely. Which of the following happens to PE  and KE when the object is half on its way down?

A. Loses PE and gains KE

B. Gains PE and loses KE

C. Loses both PE and KE

D. Gains both PE and KE​

If we neglect the effects of any conservative force, the application of the Principle of Energy Conservation is reduced to a sum of gravitational potential ([tex]U_{g}[/tex]) and translational kinetic energies, measured in joules. That is:

[tex]U_{g,1}+K_{1} =U_{g,2}+K_{2}[/tex] (Eq. 1)

Let assume that an object falls from a height [tex]h[/tex] with a speed of zero. By definitions of gravitational potential and translational kinetic energies the previous is expanded. If final height is the half of initial value, then:

[tex]m\cdot g\cdot h = 0.5\cdot m\cdot g\cdot h +K_{2}[/tex] (Eq. 1b)

[tex]K_{2} = 0.5\cdot m\cdot g\cdot h[/tex]

[tex]K_{2} = 0.5\cdot U_{g,1}[/tex]

In a nutshell, translational kinetic energy is increased at the expense of diminishing gravitational potential energy. The correct answer is A.

Complete question:

use the hubble's law to determine the distance to a quasar receding at 75% the speed of light. The speed of light is 300,000 km/sec. assume Hubble's constant is 2.2 x 10⁻⁵ km/s/Lyr

Answer:

The distance to the quasar is 1.02 x 10¹⁰ Lyr

Explanation:

Given;

speed of light, v = 300, 000 km/sec

Hubble's constant, H₀ = 2.2 x 10⁻⁵ km/s/Lyr

percentage of the quasar recession = 75% of speed of light

Hubble's Law is given by;

[tex]v =H_od\\\\d = \frac{v}{H_o}\\\\d= \frac{(0.75*300,000)}{2.2*10^{-5}}.Lyr\\\\d = 1.02*10^{10} \ Lyr[/tex]

Therefore, the distance to the quasar is 1.02 x 10¹⁰ Lyr

I think it is D. Force

Answer:

Explanation:

Do you mean tire tracks?

If you do then the tracks show that there must have been a lot of heat involved. When the tires skid, the friction produced must be awfully hot to stop and 800 kg vehical (which is pretty small). The tire tracks that you see are bits of melted rubber taken from the tire.

Force is involved, but heat is the better answer.

gravity is necessary for friction to take place. If you were out in space, you could not get enough friction to leave tire tracks. (Force is awfully small).

Lubrication is there to give you a 4th choice. The exact opposite is what takes place. Lubrication reduces friction.

Answer:

4m/s^2 ( A)

Explanation:

The solution is in the attached file

Answer:

luster

Explanation:

Answer:

C

Explanation:

It seems right.

answer

Think of it this way. Osmosis occurs when water flows to a different side given its a membrane or not. This is because it flows to a less dense area to reach equilibrium between the two sides. Heat is very similar. It will try to spread to places where there is not as much heat. Keeping the laws of heat travels up, the heat from the coils will reach the ends. We call this "Thermal Equilibrium"

Answer:

The force is [tex]F_b =  216 \  N [/tex]

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  [tex]k = 20 \ N/ m[/tex]

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      [tex]W =  m *  g[/tex]

=>   [tex]W =  80 *  9.8 [/tex]

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      [tex]F  =  k  *  x[/tex]

=>     [tex]F  =  20   * 50 [/tex]

=>     [tex]F  =  1000 \  N [/tex]

The force to be applied by the bear is

    [tex]F_b =  F -  W[/tex]

=>    [tex]F_b =  100 -  784[/tex]

=>  [tex]F_b =  216 \  N [/tex]

Explanation:

The question is incomplete. Here is the complete question.

A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 98 m and acquired a velocity of  30m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to...

Given

initial velocity of rocket u = 0m/s

final velocity of rocket = 30m/s

Height reached by the rocket = 98m

Required

upward acceleration of the rocket

Using the equation of motion below to get the acceleration a:

[tex]v^2 = u^2+2as\\30^2 = 0^2 + 2(a)(98)\\900 = 196a\\a = \frac{900}{196}\\a = 4.59m/s^2[/tex]

Hence  upward acceleration of the rocket during the burn phase is closest to 5m/s²

Note that the velocity used in calculation was assumed.

Answer:

[tex]\mu_{s} = 3.071[/tex]

This result represents an absurd, not plausible, as coefficient of frictions from materials have values between 0 and 1.

Explanation:

From Second Newton's Law we understand that centripetal acceleration experimented by motocyclist is due to force derived from static friction. And normal force of the ground on motocyclist equals weight of motocyclist due to the flatness of circular turn. The equations of equilibrium of the motocyclist is:

[tex]\Sigma F_{x} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (Eq. 1)

[tex]\Sigma F_{y} = N-m\cdot g = 0[/tex] (Eq. 2)

Where:

[tex]\mu_{s}[/tex] - Static coefficient of friction, dimensionless.

[tex]N[/tex] - Normal force, measured in newtons.

[tex]m[/tex] - Mass of the motocyclist, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Speed of the motorcyclist, measured in meters per second.

[tex]R[/tex] - Radius of the circular turn, measured in meters.

The static coefficient of friction is cleared in (Eq. 1):

[tex]\mu_{s} = \frac{m\cdot v^{2}}{N\cdot R}[/tex]

From (Eq. 2) we get that normai force is:

[tex]N = m\cdot g[/tex]

And we expand the resulting expression in (Eq. 1):

[tex]\mu_{s} = \frac{m\cdot v^{2}}{m\cdot g\cdot R}[/tex]

[tex]\mu_{s} = \frac{v^{2}}{g\cdot R}[/tex] (Eq. 3)

If we know that [tex]v = 30.556\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 31\,m[/tex], the expected static coefficient of friction is:

[tex]\mu_{s} = \frac{\left(30.556\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (31\,m)}[/tex]

[tex]\mu_{s} = 3.071[/tex]

This result represents an absurd, not plausible, as coefficient of frictions from materials have values between 0 and 1.

The final displacement of the duck would be 11.18 meters in NW, therefore the correct answer is option B.

Displacement describes this shift in location.

As given in the problem Donald Duck Matthews wanted to show up all his friends with the newfound dancing skills he left his house to go to dressers house 20 m north from where he was he's so dresser his moves went off to the next place and next stop was 10 m west at choirboys house luckily he saw Eddie there too.

After showing off his skills again he was satisfied, but he still had to show one last person up. His brother was 15 m South.

His final position would be 5 meters north and 10 meters west.

The displacement of the Duck = √( 10² + 5²)

                                                   = 11.18 meters in NW

Thus, the final displacement of the duck would be 11.18 meters in NW.

To learn more about displacement here, refer to the link;

brainly.com/question/10919017

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