which has more KE, a 2 g bee flying at 1 m/s, or a 1 g wasp flying at 2 m/s

Answers

Answer 1

Answer:

the 1 gram wasp

Explanation:

To start off with this problem, write down every piece of information and do neccessary conversions.

mass of bee = 2 grams = 0.002 kg

speed of bee = 1 m/s

mass of wasp = 1 gram = 0.001 kg

speed of wasp = 2 m/s

now, we will use the kinetic energy formula and compare the answers

KE BEE = 0.5 (0.002 kg)(1 m/s)^2 = 0.001 Joules

KE WASP = 0.5(0.001 kg)(2 m/s)^2 = 0.002 Joules

0.002 J > 0.001 J


Related Questions

The glucometer applies a potential difference of 0.90 volts across a blood sample. The glucose concentration of the blood sample is 0.98 grams/litre. Determine the current in the blood sample. ​

Answers

The amount of current in the blood sample is determined as 0.12 A.

Current in the blood

The current in the blood is calculated by applying Ohm's law as shown below;

V = IR

where;

V is voltageI is currentR is resistance

From resistivity chart corresponding to 0.98 g/L, resistance, R = 7.4

I = V/R

I = 0.9 /7.4

I = 0.12 A

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A teacher wants to demonstrate that the radioactive source emits alpha beta and gamma radiation. Describe a method the teacher could use (IMPORTANT REPLAY ASAP) I will give Brainly

Answers

By using an electric field, it is feasible to differentiate between these different forms of radiation.

What is a radioactive source?

A source that emits radiation like gamma, beta, and alpha rays is said to be radioactive. Using an electric field, we can discriminate between these different forms of radiation.

The field does not deflate the gamma rays, but it does deflate the alpha and beta rays, with the alpha being deflated to the field's negative portion and the beta to its positive part.

Hence, by using an electric field, it is feasible to differentiate between these different forms of radiation.

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A uniform plate of height 1.870 m is cut in the form of a parabolic section.
The lower boundary of the plate is defined by: y = 0.500[tex]x^{2}[/tex]. Find the distance from the rounded tip of the plate to the center of mass.

Answers

The distance from the rounded tip of the plate to the center of mass is 1.87 m.

What is center of mass?

The center of mass is a point inside or outside the mass where all of the mass is concentrated.

The y-coordinate of the centroid is given by the ratio of two definite integrals;

Yc = ∫ydm/∫dm,

where dm is a density function

For the uniform plate, δ does not change with position in the plate.

Yc = ∫yδdA/∫δdA

Yc = ∫ydA/∫dA.

dA is a horizontal slice of the plate with dimensions xdy.

Solving the parabola for x,

y = 0.5x²

x = ± √(y/0.50), where the negative value corresponds to the left half of the parabola and the positive to the right half.

dA = (√(y/0.50)

     = √(y/0.50))dy

     = 2(√(y/0.50))dy

The limits of integration are from zero to 1.870, the top of the plate.

∫ydA = ∫2y√(y/0.50)dy = 7.232 m³

∫dA = ∫2√(y/0.50)dy = 3.868 m²

∫ydA/∫dA =  7.232 m³/3.868 m²

∫ydA/∫dA =  1.869700 m

∫ydA/∫dA =   1.87 m

Thus, the distance from the rounded tip of the plate to the center of mass is 1.87 m.

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What is the force of gravity in water​

Answers

There is a gravitational force because the special water has mass.
Objects with mass have a gravitational interaction with the Earth.
The magnitude of this gravitational force is equal to the mass (in kilograms) multiplied by the local gravitational field (g = 9.8 N/kg).

Select. The star cycle that is accurate

Answers

One stellar-mass star, red giants, white dwarfs, or planetary nebulae will make up the correct star cycle. Option C is correct.

What is the solar system?

The satellites of the planet, countless comets, asteroids, and meteoroids, as well as the interplanetary medium, make up the solar system.

The complete question is;

"Choose the correct star life cycle.

A. Supernova, star as well as red giant, the nebula is incorrect.

B. Nebula, white dwarf, planetary nebula That is incorrect.

C. Planetary nebula, red giant, white dwarf, and star with a single stellar mass That is true!

D. Nebula, a star of one stellar mass, is not correct. It is correct if the star had four or more stellar masses."

Star of one stellar mass, red giant, white dwarf, and planetary nebula make up the proper life cycle.

Hence option C is correct.

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Question 2 of 25
What is the term for a pair of forces described by Newton's third law?

A.
Normal-friction pair

B.
Action-reaction pair

C.
Kinetic-static pair

D.
Inertia-movement pair

Answers

The term for a pair of forces described by Newton's third law is action-reaction pair. Details about Newton's law can be found below.

What does Newton's third law state?

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

This law proposed that when an object 1 acts on object 2 with a force of a particular magnitude, object 2 also acts on object 1 with an opposite force of same magnitude.

Therefore, it can be said that the term for a pair of forces described by Newton's third law is action-reaction pair.

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Need help with this question!

Answers

Answer:(note that values will be on top in small)

cobalt :- 60Co

potassium :- 40K

neon :- 24Ne

lead :- 208Pb

A 545 N sled is pulled a distance of 385 m. The task is done by pulling on a rope with a force of 1225 N at an angle of 19° with the horizontal. How much work is done in pulling the sled? What is the acceleration in the x direction, assuming that friction is negligible? Assuming the sled started at rest, how long does it take to pull the sled 185 m?

Answers

The work done in pulling the sled is 445,930.2 Joules.

The acceleration in the x direction, assuming that friction is negligible, is  20.85 m/s².

Time taken to pull the sled 185 m is 4.21s.

What is work done?

Work done is equal to product of force applied and distance moved.

Given is a 545 N sled is pulled a distance of 385 m. The task is done by pulling on a rope with a force of 1225 N at an angle of 19° with the horizontal.

Work = Force x Distance x cos(angle)

W= 1225 x 385 x cos 19°

W = 445,930.2 Joules

Thus, the  work done in pulling the sled is 445,930.2 Joules

From the Newton's second law of motion, we have'

F = ma

acceleration, a = 1225cos19° / ( 545 /9.81)

a = 20.85 m/s²

Thus, the acceleration in the x direction is  20.85 m/s²

Using the second equation of motion, we get

s = ut+ 1/2 at²

Substitute the values, we have

185 m = 0 +1/2 x 20.85 x t²

t = 4.21 s

Thus, the time taken to pull the sled 185 is 4.21s.

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Lucia wants to change the motion map shown so that it’s shows uniform circular motion. What change should Lucia make ?

Answers

Answer:

The last one - each  vector pointing towards the center of the circle must be the same length for uniform circular motion

What is the frequency of light with a wavelength of 2.10 × 10-7 m?

Answers

Answer:

V = ?

C = 3 × 10^8

wavelength = 2.10 × 10^-7

wavelength = C/V

V = C/wavelength

V = 3 × 10^8/2.10 × 10^-7

V = 1.43 × 10^ 15

A pendulum swings to and fro every 2.0 s. The period of the swing is.
O 2 Hz
2 s
O 0.5 s
O 0.5 Hz

Answers

Answer:

Explanation:

Solution

In physics, a period is a measurement of time. The answer must be either B or C. It is a direct measurement of time, not its reciprocal. So the answer is B. A and D is a measurement of the actual cycle that it takes before the motion begins to repeat itself.

Answer

B

The heat capacity of nickel is 0.444 J/(g · °C). Calculate the amount of heat needed to raise the temperature of 18 g of nickel from 20 °C to 66 °C. Now imagine those same joules were used instead to accelerate the same mass of nickel from rest. What would be the final speed, in m/s?
Hints:
The formula for kinetic energy is: Ek=1/2 mv^2
For joules needed for heating, use the mass in grams, but for kinetic energy, convert the mass to kilograms.
Round your answer to the nearest whole number.

Answers

The final speed of the nickel at the given quantity of heat is determined as 202.1  m/s.

Final speed of the nickel

Apply the principle of conservation of energy.

Q = mcΔθ

Q = (18)(0.444)(66 - 20)

Q = 367.63 J

Q = K.E = ¹/₂mv²

2K.E = mv²

v = √(2K.E/m)

where;

v is the final speed

v = √(2 x 367.63)/(0.018))

v = 202.1 m/s

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Need help with this question

Answers

Answer:

1. 92, 138, 92

2. 7, 7, 7

3. 17, 18, 17

4. 29, 34, 29

Explanation:

the number on the bottom is always going to be the atomic number, or the number of protons.

the number on the top is going to be the atomic mass number, which is the sum of the number of protons and neutrons.

there is always going to be the same number of electrons as protons, because that was the overall charge of each atom is 0.

for example, for the first one:

there are 92 protons

there are 230 - 92 = 138 neutrons

there are 92 electrons

The following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t₁=2sec and t₂=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
will give brilliance ​

Answers

A. The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 4 i m/s.

B. The velocity and acceleration at any time t is  4t i +1 j and 4i.

C. The average acceleration in the time interval given in part (a) is 4

What is acceleration?

Acceleration can be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

Given the following equation shows the position of a particle in time t, x=at² i + bt j

where t is in second and x is in meter. a=2m/s², b=1m/s.

A. Velocity is time rate of change of displacement.

V = dx/dt

V = d/dt (2t² i + 1t j)

V = 4t i +1 j

Velocity in time interval,

At  t₁=2sec , V₂= 4x2 i + 1 j = 8 i + 1 j

At  t₂=3sec, V₃ = 4x3 i + 1 j = 12 i + 1 j

Average velocity in time interval t₁=2sec and t₂=3sec is

, V₃ - V₂ = (12 i + 1 j) - ( 8 i + 1 j )

Average velocity =  4 i

B. Velocity at time t, is

V(t) = V = 4t i +1 j

Acceleration a = dV/dt

a(t) = d/dt (4t i +1 j)

a(t) = 4 i +0 j

C. Average acceleration in time interval t₁=2sec and t₂=3sec is

a = 4 m/s²

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A hydrogen bond forms by the electrostatic interaction of opposite charges in two molecules. If
the bond length is 2x10 -10 m and the magnitude of the charges involved is
approximately 1.60x10 -20C, what is the force between the molecules involved in the bond?

Answers

The force between the molecules involved in the bond is 6. 426 *10^-11 Newton

How to determine the force

Using the formula:

F = K[q1 x q2]/D^2

where K is coulombs constant =9 *10 ^9 Nm^2/C^2.

q1  and q2 = charges  =  1.60x10 -20C

d = distance between the charges = 2x10 -10 m

Substitute the values into the formula

F =  [tex]9 * 10^9\frac{ 1.60*10^ -20 * 1.60 *10^ -20}{2x10^ -10^{2} }[/tex]

F = [tex]9 *10^9\frac{2. 856* 10^-40}{4* 10^-20}[/tex]

F = [tex]9* 10^9 * 7. 14* 10^-21[/tex]

F = [tex]6. 426 * 10^-11[/tex] Newton

Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton

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A person who falls between introversion and extroversion is

Answers

Answer:

the answer is ambivert have a good fourth of July

Answer:

i believe the answer is ambivert

what type of energy does a pv cell create ?

Answers

Answer:  Solar Photovoltaic (PV) cells generate electricity by absorbing sunlight and using that light energy to create an electrical current. There are many PV cells within a single solar panel, and the current created by all of the cells together adds up to enough electricity to help power your school, home and businesses.

                              --Cited from Solar Schools

I’m not exactly sure but I hope some one can answer it

A body moves in an x-y plane with a velocity vm/s. The component of v are Vx=5m/s, Vy=7m/s along x and y axis respectively. What is the magnitude and direction of the velocity

Answers

the answer is in the picture ok

good luck don't worry it's a correct

#carry on learning

i need help with lab

Answers

(a) The equilibrant C for force of vector A and B is 3.43 N.

(b) The equilibrant C for fx of vector A and B is 2.1 N.

(c) The equilibrant  C, for fy of vector A and B is 2.12 N.

What is equilibrant force?

An equilibrant force is a single force that will bring other bodies into equilibrium.

From configuration 1:

Vector A: mass = 0.2 kg, θ = 20⁰

Vector B: mass = 0.15 kg, θ = 80⁰

Fx = mg cosθ

Fy = mg sinθ

where;

m is mass g is acceleration due to gravity

Vector A

Force of A due to its weight

F(A) = mg

F(A) = 0.2 x 9.8 = 1.96 N

Fx = (0.2 x 9.8) cos(20) = 1.84 N

Fy = (0.2 x 9.8) sin(20) = 0.67 N

Resultant force

R = √(0.67² + 1.84²)

R = 1.96 N

Vector B

Force of B due to its weight

F(B) = mg

F(B) = 0.15 x 9.8

F(B) = 1.47 N

Fx = (0.15 x 9.8) cos(80) = 0.26 N

Fy = (0.15 x 9.8) sin(80) = 1.45 N

Resultant force

R = √(0.26² + 1.45²)

R= 1.47 N

Equilibrant  C of vector A and B

Equilibrant force:

Force, C = 1.96 N + 1.47 N

Force, C = 3.43 N

Equilibrant FX:

Fx, C = Fx(A) + Fx(B)

Fx, C = 1.84 N + 0.26 N = 2.1 N

Equilibrant FY:

Fy, C = Fy(A) + Fy(B)

Fy, C =0.67 N + 1.45 N = 2.12 N

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. Two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as u(r) = − Gm R1 −r − Gm R2 −r . This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets. (a) Draw a graph of u as a function of position (r) along the line between the two planets. (b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2. What is the minimum speed v which will permit the projectile to reach station Beta?

Answers

(a) A graph of u as a function of position (r) along the line between the two planets is attached below.

(b) The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

What is gravitational potential energy?

If an object is lifted, work is done against gravitational force. The object gains energy.

Given are two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as

u(r) = − (Gm /R1 −r) − (Gm / R2 −r) .

This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets

(a) A graph of u (r)  versus position (r) along the line between the two planets is attached in answer.

(b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.

The range of the projectile is given by R =  v²sin2θ / g

g = gravitational acceleration of Earth

If g = g(p) for planet , range  R =  v²sin2θ / g(p)..................(1)

The gravitational force of attraction = weight force

Gm² /d² = m g(p)

g(p) = Gm/d².........................(2)

For R = d/3, from equation (1), we have

d/3 =  v²sin2θ / g(p)

Plug the expression for g(p) , we get

v = √ [Gm/3dsin2θ ]

For velocity to be minimum, sin2θ =1

So, the minimum velocity will be

v = √ [Gm/3d]

Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

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What is the acceleration of Karla's I Phone being thrown from Mr. Higley's classroom at 0m/s if it hits the wall 1.2 seconds later going 35 m/s?

Answers

The acceleration of Karla's I IPhone being thrown from Mr. Higley's classroom at 0 m/s will be 29.16 m/s²

What is acceleration?

The rate of velocity change concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.

The given data in the problem is given by ;

u is the initial speed =  0 m/sec

v is the final speed= 35  m/sec

t is the time interval= 1.2 second

a is the acceleration=? m/sec²

The formula for acceleration is;

[tex]\rm a=\frac{v-u}{t} \\\\ a= \frac{35-0}{1.2} \\\\ a= 29.16 \ m./s^2[/tex]

Hence, the acceleration of Karla's iPhone being thrown from Mr. Higley's classroom at 0 m/s will be 29.16 m/s²

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Water flows with a volume flow rate of 1.44 m³/s in a pipe. Find the water speed where the pipe radius is 0.430 m.

Answers

Answer:

0.6192

Explanation:

1.44 x 0.430=0.6192

A 0.15-kilogram baseball moving at 43 meters per second was stopped by the catcher’s glove in 0.050 seconds. What was the average force exerted on the ball by the glove? Round your answer to two significant figures.

Answers

The average force exerted on the ball by the glove will be 129 N.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Mass,(m)=0.15-kilogram

Initial speed,u=43 meters per second

Time period,t= 0.050 seconds

Average force exerted,F=?

The average force exerted on the ball by the glove is;

[tex]\rm F = m\frac{v-u}{t} \\\\ F=0.15( \frac{43-0}{0.050} )\\\\ F=129 N[/tex]

Hence, the average force exerted on the ball by the glove will be 129 N.

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A resistor has a resistance of 8.2 kΩ. If a voltage of 15.9 V were placed across it, what would be the current, in mA? Give the answer to two decimal places; don't worry if the computer adds zeroes.

Answers

The value of the electric current for the given conditions willl be  1939.02 A.

What is ohm’s law?

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

Ohm's law claims that the voltage across a conductor is direct to the current flowing through it. This current-voltage connection may be expressed mathematically as,

V=IR

15.9 V = I × 8.2 × 10³ Ω

I = 1939.02 A

Hence, the value of the electric current for the given conditions willl be  1939.02 A.

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The road from city A to city B is described by a car with Vm 40 km / h. When the car turns (from B to A) the average speed is 60 km / h. Find the average round trip speed.​

Answers

Answer:

i think the answer is 20.......

Why is it important to remember "association, not
causation" when discussing correlations?

Answers

It is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.

What is the value of associations in science?

The associations among variables have a fundamental value in science because they can determine how such variables behave in hypothetical situations.

Moreover, correlation only indicates a type of association between variables and therefore it is less informative.

In conclusion, it is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.

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The value of acceleration due to gravity (g) on a point 10,000 kilometers above sea level is about 1.49 meters/second2. How much will an object, which weighs 98 newtons on the surface of Earth, weigh on this point? The value of acceleration due to gravity on Earth is 9.8 meters/second2.

Answers

An object, which weighs 98 N on the surface of Earth, weigh on this point is 2.23 x 10²⁴ kg.

What is gravity?

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given, the Earth has the acceleration due to gravity, g =  9.81 m/s².

Force of gravity W = mass x acceleration due to gravity

98N = m x 9.8m/s²

m = 10 kg

The value of acceleration due to gravity (g) on a point 10,000 km above sea level is about 1.49 m/s².

The acceleration due to gravity and mass is related as

g = GM/R²

where G = gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg² and R is the distance between two masses.

Substituting the values, we get

1.49 m/s² =  6.67 x 10⁻¹¹ N.m²/kg² x M/ (10000 x 10³ m)²

M = 2.23 x 10²⁴ kg

Therefore, an object will weigh on this point is 2.23 x 10²⁴ kg

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Two force of 20N and 40N act at a
Point and the angle between them is 50 degrees.
Find the resultant force
Find the direction using sine rule

Answers

R=√20²+40²+2.20.40 cos 50

R=55 N

R/sin β = F/sin α

55/sin 50 = 40/sin α

α = 33°


It is important that a frame of reference

Answers

Answer:

enable us to take in a wide variety of information, and process it based on our past experience and values.

Explanation:

Two identical 3.0-kg cubes are placed on a horizontal surface in
contact with one another. The cubes are lined up from left to
right and a force F₁ is applied to the left side of the left cube
causing both cubes to move at a constant speed v. If the
coefficient of kinetic friction between the cubes and the
surface is 0.3, what is the magnitude of the force exerted by the
left cube on the right cube?
(3

Answers

The magnitude of the force exerted by the left cube on the right cube is 17.64N.

What is frictional force?

When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.

Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.

From the equilibrium of forces in vertical direction

Normal force N= 2m x g

friction force f = μN =μ(2m)g

From the equilibrium of forces in horizontal direction

F₁ =ma =0

using Newton's third law of motion, we get

F₁  - f =0

F₁  =f = μ(2m)g

Put the values, we get

F₁  = 17.64N

Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.

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Trust fund overages or shortages are serious violations of the law, which can result in loss of license, even if the discrepancy is caught and corrected. Which statement is correct regarding trust fund liability? if x+X+1=0 then what is the value of x + x + x Write a short note on any one thing about the poem that you like most. You may choose words, phrases or lines from the poem to support your description. The numbers of suitcases loaded onto various airplanes are an example of which type of data? What is the quotient in scientific notation? Communication processes such as face-to-face conversations, telephone conversations, and meetings in which all communicators are present at the same time are referred to as __________ communication. Translate the following statements into algebraic expressions.One-half of the sum of 8 and x. Assuming no air resistance, how long would ittake a skydiver to fall 180 feet? (Estimateyour answer to one decimal place. Hint: Use theequation d = 16+) For many years, these Cycladic figures were thought to have beenA.central to religious beliefs focusing on a mother goddess.B.used as currency.C.mostly displayed in an upright position.D.carved from wood, with metal inlays. the nurse is reviewing pressurized metered-dose inhaler (pmdi) instructions with a client. which statement by the client indicates the need for further instruction? Suppose that the lifetimes of tires of a certain brand are normally distributed with a mean of 74000 miles and a standard deviation of miles. these tires come with a -mile warranty. the manufacturer of the tires can adjust during the production process, but the adjustment of is quite costly. the manufacturer wants to set once and for all so that only of the tires will fail before warranty expires. find the standard deviation to be set. carry your intermediate computations to at least four decimal places. round your answer to at least one decimal place. A 808 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 632 kg. The two cars lock up and slide together with a speed of 15.0 km/h. What was the speed of the first car just before the collision? [tex]4x {}^{2} + 20x + 25[/tex]using appropriate identity factories the following First conditionalWrite first conditional sentences using the prompts.1 I not study/I do badly in the examIf______________________________6 my parents say yes/I stay with you this weekendIf_____________________________ Given circle with radius of 5cm.Find out(a) diameter(b) perimeter(c) area How do you think you might have reacted to Lincolns speech if you had been alive when he delivered it? What is the result of adding the system of equations? Equation 1: 2x + y = 4 Equation 2: 3x - y = 6 A) 5x = 10 B) x = 5 C) x = 10 Muckraking journalistsO exposed corruption and bad business practiceO touted benefits of laissez faire economicsO supported big businessO supported war with Europe which rocks are found in layers and often contain fossils Find the value of x.