Answer:
Assist in the movement of food and waste through the digestive system
can someone help with this please. i will give brainliest
Answer:
Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light.
The electromagnetic radiations consist of radio waves, microwaves, infrared ,Visible , ultraviolet, X rays and gamma rays arranged in order of increasing frequency and decreasing wavelengths.
The visible reagion contains Violet , Indigo , Blue , Green , Yellow , Orange and Red in order of increasimg wavelength and decreasing frequency.
3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases by 19.21°C. Calculate ∆H, in kJ/mol, for the dissolution of the unknown solid. (The specific heat of the solution is 4.184 J/g･°C and the density of the solution is 1.20 g/mL).
What is the purpose of striking a match the side of the match
Answer:
The ridges on the side of the match and the match tip rub against each other which makes friction and that friction creates a spark and the match lights up.
Explanation:
At what temperature will 1.50 moles of nitrogen exert a pressure of 1.072 atm in a 20.0 L cylinder?
238 K
0.00574 K
337 K
174 K
Answer:
174 K
Explanation:
To answer this question we will use the PV=nRT formula, where:
P = 1.072 atmV = 20.0 Ln = 1.50 molR = 0.082atm·L·mol⁻¹·K⁻¹T = ?We input the data given by the problem:
1.072 atm * 20.0 L = 1.50 mol * 0.082atm·L·mol⁻¹·K⁻¹ * TAnd solve for T:
T = 174 KMeaning the correct answer is the fourth option, 174 K.
Take your time please.
Answer:
1. Observing
2. Classifying
3. Predicting
4. Making a hypothesis
5. Experimenting
6. Measuring
7. Communicating
8. Making an inference
9. Constant
10. Interpreting data
Explanation:
Hope this helps!!
hope it is helpful to you
A solution containing 1.50 mM ethanol and 2.40 mM methanol gave peak areas of 1487 and 3544, respectively. Subsequently, 2.00 mL of 3.2 mM methanol was added to a 7.00 mL unknown ethanol and diluted to 10.00 mL. The final solution gave peak areas of 6235 and 4487 for ethanol and methanol, respectively. Calculate the concentration of ethanol in the original unknown.
Answer:
8.99mM is the concentration of ethanol in the original unknown.
Explanation:
In chromatography, the peak areas of compounds are proportional to its concentration. The ratio of Area/Concentration for ethanol and methanol is:
Ethanol = 1487 / 1.50mM = 991,33 mM⁻¹
Methanol = 3544 / 2.40mM = 1476.67mM⁻¹
The concentration of ethanol in the diluted solution is:
6235 / 991.33mM⁻¹ = 6.29mM
The original solution was diluted from 7mL to 10mL, the concentration of the original solution is:
6.29mM * (10mL / 7mL) =
8.99mMPlz help Need Answer Quick
Answer:
The correct answer is - [tex]\frac{P}{4}[/tex].
Explanation:
By the ideal gas equation is PV=nRT, the relation between pressure and volume can be drive if the temperature remains constant:
At constant temperature, for a fixed amount of gas, P∝
so the pressure is inversely proportional to volume. Therefore, if the volume is increased in this condition the pressure will decrease in the same manner and A decrease in the volume will lead to an increase in pressure.
Volume increased here = four times = 4V
pressure is P will decrease four times = P/4
Methane is combusted with Oxygen to produce Carbon Dioxide and Water. How many grams of oxygen are required to react with 55 grams of
Methane?
A.55 g
B.110 g
C.165 g
D.220 g
What is the phase label on CI?
A. aq
B.
C. e
D. g
E. s
Answer:
Pubic hair smells bad
Explanation:
what is the difference between zinc and magnesium
A beach ball and a bowling ball were sitting on a shelf. Someone bumped the shelf and the bowling ball and beach ball rolled off
the shelf at the same time. They both hit the ground at the same
time and had the same speed.
Which of these statements correctly compares the kinetic energy
of the two objects just before they hit the ground?
A The bowling ball had more kinetic energy because it
had less potential energy when it was on the shelf.
B The bowling ball had more kinetic energy because it
has more mass.
C Both balls had the same kinetic energy because they
had the same speed.
D Both balls had the same kinetic energy because they had the same potential energy when they were on the
shelf.
Answer: i think its b
Explanation:
PLEASE ANSWER True or False: When adding reactions together to get a desired reaction you must also add their enthalpies to get the enthalpy of that desired reaction.
Answer:
true
Explanation:
The process of shedding an outgrown exoskeleton.
Answer:
Mouthing is the answer to your question
A 9.56 sample of CuS is found to contain 6.35 g of copper what is the percent by mass of the copy and sulfur in this compound? (show your work)
Answer:
%Cu = 66.4%
%S = 33.6%
Explanation:
Step 1: Given data
Mass of CuS: 9.56 gMass of Cu: 6.35 gStep 2: Calculate the mass of S
The mass of CuS is equal to the sum of the masses of Cu and S.
mCuS = mCu + mS
mS = mCuS - mCu
mS = 9.56 g - 6.35 g = 3.21 g
Step 3: Calculate the percent by mass of each element
We will use the following expression.
%Element = mElement / mCompound × 100%
%Cu = mCu / mCuS × 100% = 6.35 g / 9.56 g × 100% = 66.4%
%S = mS / mCuS × 100% = 3.21 g / 9.56 g × 100% = 33.6%
Air movement can affect how quickly evaporation occurs.
O True
O False
6. The drawing shows Samir riding his mountain bike.
i) Draw a circle around the places on the drawing where there
should be a lot of friction.
ii) Explain why there should be a lot of friction in these places.
Answer:
You Need To Upload The Photo Then I Will Help You :)
Explanation:
It is device used to measure thee temperature of food/fish
label the sun. which layer of the sun is #4?
Answer:
is D I guess; photosphere
aluminium containers are used to store and transport nitric acid(HNO3) but not NAOH why?
Answer:
(i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.
Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches.
Use the References to access important values if needed for this question.
Match the gas sample on the left with a description on the right.
You may use the same answer more than once.
Clear All
0.115 moles of Xe in a 4.87 L container at a temperature of 446K
0.599 moles of Xe in a 5.78 L container at a temperature of 306K
0.444 moles of Xe in a 2.39 L container at a temperature of 408K
0.556 moles of Xe in a 2.11 L container at a temperature of 446K
has the highest average molecular speed
has the lowest average molecular speed
has an average molecular speed between the highest and the lowest
Answer:
Container 2 has the lowest average molecular speed
Container 4 has the highest average molecular speed
Explanation:
Step 1: Data given
Atomic mass of Xe = 131.29 g/mol
Container 1: Number of moles Xe = 0.115 moles; volume = 4.87 L; temperature= 446K
Container 2: Number of moles Xe = 0.599 moles; Volume = 5.78 L; temperature= 306K
Container 3: Number of moles Xe = 0.444 moles; Volume = 2.39L; Temperature = 408K
Container 4: Number of moles Xe = 0.556 moles; Volume=2.11L; Temperature =446K
Step 2: Calculate average molecular speed
Average molecular speed V = √(8RT/πM)
→With R = he gas constant expressed in units of J/mol-K
→with T = the temperature in Kelvin
→with M = the molar mass of the gas
Average molecular speed depends on T and M
Since it's all Xenon, M is the samefor the 4 containers
Container 1:
V1 = √(8*8.314*446K/π*131.29)
V1 = 8.48
has an average molecular speed between the highest and the lowest
V2= √(8*8.314*306K/π*131.29)
V2= 7.03
has the lowest average molecular speed
V3 = √(8*8.314*408K/π*131.29)
V3 = 8.11
has an average molecular speed between the highest and the lowest
V4 = √(8*8.314*446K/π*131.29)
V4 = 8.48
Since the volume is smaller than in container 1 the average molecular speed will be a higher
has the highest average molecular speed
Pick the answer that correctly spells a layer of the atmosphere.
A. Mesosphere
B. Thermsphere
C. Mezosphere
D. Tropshere
E. Thermoshere
The correct answer is option A; Mesosphere
The mesosphere is defined as the part atmosphere found above the stratosphere but below the thermosphere.
In this layer of the atmosphere, temperature decreases with height. It covers about 50 to 85 km above the earth.
Mesosphere is the only layer of the atmosphere that was correctly spelt among the options.
Learn more: https://brainly.com/question/12117482
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. The concentration of acetic acid in the sample was ________ M. A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. The concentration of acetic acid in the sample was ________ M. 0.175 0.119 0.365 0.263 none of the above
Answer:
= 0.2625M ≅ 0.26M (2 sig figs)
Explanation:
HOAc + NaOH => NaOAc + H₂O
25ml (Molarity of HOAc) =\ 37.5ml(0.175M NaOH)
Molarity of HOAc = 37.5ml(0.175M NaOH)/25ml
= 0.2625M ≅ 0.26M (2 sig figs)
What is the maximum number of bonds that can occur between two atoms?
One
Two
Three
Four
Five
it can occur 5 atoms
Explanation:
that is base on my study
Which is NOT a goal of the United Nations?
A. Maintain World Peace
B. Fight
C. Discuss Issues
D. Cooperation
Answer:
B.Fight...............
Is this statement true or false?
Gymnosperms reproduce using seeds, but angiosperms do not.
Answer:
FALSE!
Explanation:
Gymnosperms do use seeds but are exposed like the pine cones of pines. Angiosperms still have seeds, however, they flower or fruit.
Answer:
False
Explanation:
What is the vapor pressure of CH3COOH and 90*C?
Answer:
40.kPa hope this helps....
electronic configuration [Ne]3s2 3p6
How many MOLECULES are in 50.0 grams of lithium phosphate
Answer:
115.794361
Explanation:
this is the answer please mark me as brainleist
Answer:
115.794361
Explanation:
that would be the correct answer
What is the chemical name for OBr2?
Answer:
The answer is oxygen difluoride
Explanation:
Hope this helped Mark BRAINLEST!!!!
In the given question, the chemical name for [tex]\rm OBr_2[/tex] is oxygen dibromide.
A chemical name is a unique name given to a chemical compound that accurately describes its chemical composition.
The suffix "di-" means two, and "bromo" refers to the presence of two bromine atoms in the compound. The prefix"-oxygen" indicates that the compound contains oxygen.
Therefore, oxygen dibromide is the chemical name for [tex]\rm OBr_2[/tex]. It is a covalent compound and has oxygen as a central atom.
Learn more about chemical name here:
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What is the mass of 5.55 moles of carbon monoxide
Answer:
[tex]\boxed {\boxed {\sf 155 \ g\ CO}}[/tex]
Explanation:
To convert from moles to mass, the molar mass must be used.
First, write the chemical formula for carbon monoxide. Since the carbon (C) comes first without a prefix, there is 1 carbon atom. The prefix mono- before oxide means 1, so there is also 1 oxygen (O) atom. The formula is CO.
Next, look up their molar masses on the Periodic Table.
C: 12.011 g/mol O: 15.999 g/molSince there is 1 atom of each, the molar masses can be added.
CO: 12.011 g/mol + 15.999 g/mol = 28.01 g/molUse this molar mass as a ratio.
[tex]\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]
Multiply by the given number of moles:5.55
[tex]5.55 \ mol \ CO *\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]
The moles of carbon monoxide cancel.
[tex]5.55 * \frac {28.01 \ g \ CO} {1 }[/tex]
Multiply.
[tex]155.4555 \ g \ CO[/tex]
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, it is the ones place. The 4 in the tenths place tells us to leave the 5.
[tex]155 \ g\ CO[/tex]
5.55 moles of carbon monoxide is about 155 grams.
