Where is the potential energy equal to zero?

Answer:

When you blow into a tuba the air vibrates very slowly.​

Explanation:

Tuba is a buzz instrument ie sound is produced in it with the help of lip vibration . It is the lowest pitched musical instrument in the brass family .

Due to absence of resonance in it , it produces music of lowest pitch , So when one blows into it the air column of the instrument vibrates very slowly producing low pitched sound.

Answer:

a) v1f = 0.25 m/s

b) F = 50000N

Explanation:

a) In order to calculate the speed of the player after he fires the puck, you use the conservation of momentum law. Before the puck is in motion and after the total momentum of both player and puck must conserve:

[tex]m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}[/tex]        (1)

m1: mass of the player = 100kg

v1i: initial velocity of the player = 0m/s

v2f: final velocity of the puck = ?

m2: mass of the puck = 0.5kg

v2i: initial velocity of the puck = 0 m/s

v2f: final velocity of the puck = 50 m/s

You replace these values into equation (1) and you solve for v1f (final velocity of player):

[tex]0kgm/s+0kgm/s=(100kg)v_{1f}+(0.5kg)(50m/s)\\\\v_{1f}=-\frac{(0.5kg)(50m/s)}{100kg}\\\\v_{1f}=-0.25\frac{m}{s}[/tex]

The minus sign means that player moves in a opposite direction to the motion of the puck

The velocity of the player after he fires the puck is 0.25 m/s

b) The force needed is given by the change in time , of the momentum of the player, which is given by:

[tex]F=\frac{\Delta p}{\Delta t}=m\frac{\Delta v}{\Delta t}[/tex]

The change on the velocity of the puck is 50m/s, and the time interval is 0.1s.

[tex]F=(100kg)\frac{50m/s}{0.1s}=50000N[/tex]

The force needed to create the needed impulse, to accelerate the puck is 50000N

Answer:

v = 0

Explanation:

It is given that,

Mike ran ten laps around his school's 1/4 mile track in 15 minutes. He finishes his run at the exact same point that he started. We need to find his average velocity. Average velocity is equal to net displacement divided by total time taken.

As he returns exactly at the same point that he started, it means his displacement or the shortest distance covered is equal to 0. As a result, its average velocity is equal to 0.

Answer:

45 W

Explanation:

Power: This can be defined as the rate at which electrical energy is consumed in a circuit. The unit of power is Watt (W).

From the question,

The expression for power is given as,

P = VI.................. Equation 1

Where V = Voltage, I = current.

Given: V = 12 V, I = 3.75 A.

Substitute into equation 1.

P = 12(3.75)

P = 45 W.

Answer:

P = 45 Watt

Explanation:

The electrical power used by an electrical device or the electrical circuit is given by the following formulae:

P = VI

P = I²R

P = V²/R

where,

P = Electrical Power Consumed by the Device

V = The Voltage applied to the circuit or device

R = Resistance of device or circuit

I = Current passing through the device or circuit

We have the following data for our circuit:

V = 12 volts

I = 3.75 A

Therefore, it is clear from the data that we will use the first formula:

P = VI

P = (12 volts)(3.75 A)

P = 45 Watt

Answer:

4

Explanation:

p=m×v

m=2kg

v=2m/s

2×2=4

Answer:

4kgms/1

Explanation:

p=m×v

 =2kg×2m/s

 =4kgms/1

Answer:

a) The severity index (SI) is 3047.749, b) The injured travels 0.345 meters during the collision.

Explanation:

a) The g-multiple of the acceleration, that is, a ratio of the person's acceleration to gravitational acceleration, is:

[tex]a' = \frac{35\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }[/tex]

[tex]a' = 3.569[/tex]

The time taken for the injured to accelerate to final speed is given by this formula under the assumption of constant acceleration:

[tex]v_{f} = v_{o} + a \cdot t[/tex]

Where:

[tex]v_{o}[/tex] - Initial speed, measured in meters per second.

[tex]v_{f}[/tex] - Final speed, measured in meter per second.

[tex]a[/tex] - Acceleration, measured in [tex]\frac{m}{s^{2}}[/tex].

[tex]t[/tex] - Time, measured in seconds.

[tex]t = \frac{v_{f}-v_{o}}{a}[/tex]

[tex]t = \frac{\left(12\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)}{35\,\frac{m}{s^{2}} }[/tex]

[tex]t = 0.095\,s[/tex]

Lastly, the severity index is now determined:

[tex]SI = \frac{a'^{5}}{2\cdot t}[/tex]

[tex]SI = \frac{3.569^{5}}{2\cdot (0.095\,s)}[/tex]

[tex]SI = 3047.749[/tex]

b) The initial and final speed of the injured are [tex]1.944\,\frac{m}{s}[/tex] and [tex]5.278\,\frac{m}{s}[/tex], respectively. The travelled distance can be determined from this equation of motion:

[tex]v_{f}^{2} = v_{o}^{2} + 2\cdot a \cdot \Delta s[/tex]

Where [tex]\Delta s[/tex] is the travelled distance, measured in meters.

[tex]\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex]

[tex]\Delta s = \frac{\left(5.278\,\frac{m}{s} \right)^{2}-\left(1.944\,\frac{m}{s} \right)^{2}}{2\cdot \left(35\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\Delta s = 0.345\,m[/tex].

Answer:

The force exerted by the wood on the bullet is 399.01 N

Explanation:

Given;

mass of bullet, m = 0.0021 kg

initial velocity of the bullet, u = 497 m/s

final velocity of the bullet, v = 0

distance traveled by the bullet, S = 0.65 m

Determine the acceleration of the bullet which is the deceleration.

Apply kinematic equation;

V² = U² + 2aS

0 = 497² - (2 x 0.65)a

0 = 247009 - 1.3a

1.3a = 247009

a = 247009 / 1.3

a = 190006.92 m/s²

Finally, apply Newton's second law of motion to determine the force exerted by the wood on the bullet;

F = ma

F = 0.0021 x 190006.92

F = 399.01 N

Therefore, the force exerted by the wood on the bullet is 399.01 N

Answer:3.21 m

Explanation:

Given

Length of ladder [tex]L=7.9\ m[/tex]

inclination of ladder [tex]\theta =66^{\circ}[/tex]

If x is the  horizontal distance between building and ladder then,

Using trigonometric relation

we get

[tex]\cos \theta =\frac{x}{L}[/tex]

[tex]x=L\cos \theta [/tex]

[tex]x=7.9\times \cos (66)[/tex]

[tex]x=3.21\ m[/tex]

Answer:

Force of gravity, F = 70 N      

Explanation:

It is required to find the force of gravity acting on an object that has a mass of 7 kg. Force of gravity always acts in downward direction.

The force of gravity is equal to the weight of an object. It is given by :

[tex]F=mg[/tex]

g = acceleration due to gravity, for Earth, g = 10 m/s²

So,

[tex]F=7\times 10\\\\F=70\ N[/tex]

So, 70 N of force of acting on an object.

Answer:

1.22m

Explanation:

Since

sinθ  =  refraction-of-the-oil/refraction-of-the-brine =1.27/1.81 = 0.702

θ = [tex]sin^-^1[/tex](0.702)

Hence

Critical angle = θ = 44.58°

tan(θ) = d/1.24

tan(44.58°) = d/1.24

Hence, 0.98 = d/1.24

The distance d = 0.98 x 1.24 = 1.22m

Answer:

P = √( μ / ε ) × πa^2 |Jo|^2 ln {b/a}.

Explanation:

So, we will be making use of the data or parameters given in the question above;

=>" radii a, and b, with b > a, is filled with a uniform dielectric material with permittivity ε and permeability μ0."

=> " A TEM mode is propagated along the line and the peak value of magnetic field when rho = a is B0."

So, we will be making use of the two equations below;

Ë = ( λ/ 2πEP) × P'. --------------------------(1)..

B' = √ μE × ( λ/ 2πEP) × P' --------------(2).

Where equation (1) and (2) represent Gauss' law and magnetic field equation respectively.

Jo = 1/√ μE × λ/2 × π × a.

When we solve for charge per unit length, we have;

λ = 2 × π × Jo × a × √ μE.

The energy flux,s = E' × J'= √μE× |Jo(Z) |^2 × a^2/b^2 { cos^2 kz - wt + Avg Jo} Z'.

Hence, the time. Average power flux = 1/2× √ μE× |Jo(Z) |^2 × a^2/b^2 × Z'.

Therefore, P = ∫z' . <s> da

P = ∫ ∫ 1/2× √ μE× |Jo(Z) |^2 × a^2/b^2 × Z' pd pd p Θ.

(Take limit on the first at second integration as : 2π,0 and b,a).

P = √( μ / ε ) × πa^2 |Jo|^2 ln {b/a}.

Answer:

(a) 1.14 s

(b) 0.87 s

Explanation:

A person moves by the help of frictional force, as a result of gtound reaction. So, the formula for frictional force is:

F = μR

where,

F = frictional force

μ = coefficient of friction

R = Normal Reaction = Weight of Body = W = mg

Therefore,

F = μmg

but, from Newton's 2nd Law of Motion:

F = ma

Comparing both equations, we get:

μmg = ma

a = μg   ---------- equation (1)

Now, to calculate the distance moved by a body, we use 2nd equation of motion:

s = (Vi)(t) + (0.5)at²

using equation (1), we get:

s = (Vi)(t) + (0.5)μgt²

where,

s = distance moved by body

Vi = initial velocity of body

t = time taken to cover the distance

g = acceleration due to gravity

(a)

Vi = 0 m/s

g = 9.8 m/s²

s = 3.2 m

μ = 0.5

t = ?

Therefore,

3.2 m = (0 m/s)(t) + (0.5)(0.5)(9.8 m/s²)t²

t² = 3.2 m/(0.5)(0.5)(9.8 m/s²)

t = √1.30612 s²

t = 1.14 s

(a)

Vi = 0 m/s

g = 9.8 m/s²

s = 3.2 m

μ = 0.5

t = ?

Therefore,

3.2 m = (0 m/s)(t) + (0.5)(0.5)(9.8 m/s²)t²

t² = 3.2 m/(0.5)(0.5)(9.8 m/s²)

t = √1.30612 s²

t = 1.14 s

(a)

Vi = 0 m/s

g = 9.8 m/s²

s = 3.2 m

μ = 0.87

t = ?

Therefore,

3.2 m = (0 m/s)(t) + (0.5)(0.87)(9.8 m/s²)t²

t² = 3.2 m/(0.5)(0.87)(9.8 m/s²)

t = √0.75 s²

t = 0.87 s

Answer:

The correct answer will be "2 m".

Explanation:

As we know,

⇒  [tex]\frac{Mirror's \ size}{Body's \ height} =\frac{1}{2}[/tex]

Now,

⇒  [tex]Size \ of \ a \ mirror = \frac{n}{2}[/tex]

Then,

⇒  [tex]Size \ of \ mirror = \frac{4}{2}[/tex]

⇒                            [tex]=2 \ meter[/tex]

Answer:

The answer is angle 2.

Explanation:

Angle 2 is the Reflected Ray of angle 1.

Angle 3 is the Refracted angle.

Angle 2 is the angle of reflection. the light incident will bounce to the opposite end after striking is called the reflection.

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

In the reflection, the light incident will bounce to the opposite end after striking. Angle 2 satisfies the properties of the reflection.

Hence angle 2 is the angle of reflection.

To learn more about the law of reflection refer to the link;

brainly.com/question/12029226

Answer:

The Formula Is F = m * a And It's Units Is (kg)(m/s2)

Explanation:

Answer:

y(x,t)=-0.395m

Explanation:

The wave function modeling waves are:

[tex]y_1(x,t)[/tex]= (0.4 m)sin[(3 [tex]m^-^1[/tex])x + (2 [tex]s^-^1[/tex])t]

[tex]y_2(x,t)[/tex]=(0.8 m)sin[(6  [tex]m^-^1[/tex])x − (5 [tex]s^-^1[/tex])t]

The principle of superposition can be defined as the resultant of [tex]y_1[/tex] and [tex]y_2[/tex] is equal to their algebraic sum

[tex]y(x,t)=y_1(x,t)+y_2(x,t)[/tex]

y(x,t)= (0.4 m)sin[(3 [tex]m^-^1[/tex])x + (2 [tex]s^-^1[/tex])t] + (0.8 m)sin[(6  [tex]m^-^1[/tex])x − (5 [tex]s^-^1[/tex])t]

Substitute 0.9m for x and 0.4s for t as required  

y(x,t)= (0.4 )sin[(3 [tex]m^-^1[/tex])(0.9) + (2 [tex]s^-^1[/tex])(0.4)] + (0.8 m)sin[(6  [tex]m^-^1[/tex])(0.9)− (5 [tex]s^-^1[/tex])(0.4)]

y(x,t)= -0.14 - 0.255

y(x,t)=-0.395m

The vertical displacement of the resultant wave formed by the interference of the two waves is -0.395m

Two sinusoidal waves are given such that:

y₁(x, t) = (0.4 m)sin[(3 m⁻¹)x + (2s⁻¹)t]  and

y₂(x, t) = (0.8 m)sin[(6 m⁻¹)x − (5s⁻¹)t]

The superposition of the two waves gives the outcome of the interference at x = 0.9 m and t = 0.4 s.

y(x,t) = y₁(x, t) +  y₂(x, t)

y(0.9,0.4) = y₁(0.9, 0.4) +  y₂(0.9, 0.4)

y(0.9,0.4) = (0.4 m)sin[(3 m⁻¹)0.9 + (2s⁻¹)0.4] + (0.8 m)sin[(6 m⁻¹)0.9 − (5s⁻¹)0.4]

y(0.9,0.4) = -0.395m

Learn more about interference:

https://brainly.com/question/16098226?referrer=searchResults

Answer:

Explanation:

There is no acceleration in vertical direction

Fn = mg + Fp sin 35

Frictional force = 99.7 N

Net force in forward direction = Fp cos 35 - 99.7

= 168 cos 35 - 99.7

= 137.61-99.7

= 37.91 N

net acceleration of chair = net force / mass

= 37.91 / 50

= .7582 m / s² .

positive

Because adding electrons makes an object to be negative and removing makes it to be positive

Answer:

The time take is  [tex]t = 1.3964 \ days[/tex]

Explanation:

From the question we are told that

    The decay constant is  [tex]\lambda = 0.16[/tex]

     The percentage fall is  [tex]c = 0.80[/tex]

The equation for radioactive decay is mathematically represented as

               [tex]N(t) = N_o * e^{- \lambda t }[/tex]

Where is [tex]N(t)[/tex] is the new amount of the new the isotope while [tex]N_o[/tex] is the original

At initial  [tex]N_o = 100[/tex]%  = 1

At [tex]N(t ) = 80[/tex]%  = 0.80  

       [tex]0.80 = 1 * e^{- 0.16 t }[/tex]

=>     [tex]-0.223 = -0.16 t[/tex]

=>     [tex]t = 1.3964 \ days[/tex]

Answer:

t = 1.4 days

Explanation:

The law of radioactive decay gives the amount of radioactive substance, left after a certain amount of time has passed. The formula of law of radioactive decay is given as follows:

N = N₀ (e)^-λt

where,

λ = decay constant = 0.16

N₀ = Initial Amount of the Substance

N = The Amount of Substance Left after Decay = 80% of N₀ = 0.8 N₀

t = Time Required by the Substance to decay to final value = ?

Substituting these values in the law of radioactive decay formula, we get:

0.8 N₀ = N₀ (e)^-0.16 t

0.8 = (e)^-0.16 t

ln (0.8) = -0.16 t

t = - 0.2231/-0.16

t = 1.4 days

Answer:Sound travel faster in warm room.

Explanation:The speed of sound depends on the temperature of the medium. Mathematically, the relation between the speed of the sound and the temperature is give by:v=

is the ratio of the specific heats

R is the gas constant

T is the temperature of the medium

We know that the temperature of the warm room is more as compared to the cold room.

So, it is clear that the sound travel faster in a warm room. The particles move faster when the temperature is high.            

Explanation:

The negative value of the packing fraction indicates that the actual isotopic mass is less the mass number.

Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

[tex]F_c=m\frac{v^2}{r}[/tex]  (1)

m: mass object = 2.3 kg

r: radius of the circular orbit = 0.034 m

v: tangential speed of the object

However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

[tex]K=\frac{1}{2}mv^2[/tex]

You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:

[tex]v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}[/tex]

you replace this value of v in the equation (1). Also, you replace the values of r and m:

[tex]F_c=(2.3kg)(\frac{11.3m^2/s^2}{0.034})=764.41N[/tex]

hence, the tension in the string must be T =  Fc = 764.41 N

Answer:

the time taken for the ball to hit the ground is 0.424 s

Explanation:

Given;

velocity of the ball, u = 5 m/s

height of the house which the ball was kicked, h = 3m

Apply kinematic equation;

h = ut + ¹/₂gt²

where;

h is height above ground

u is velocity

g is acceleration due to gravity

t is the time taken for the ball to hit the ground

Substitute the given values and solve for t

3 = 5t + ¹/₂(9.8)t²

3 = 5t + 4.9t²

4.9t² + 5t -3 = 0

a = 4.9, b = 5, c = -3

Solve for t using formula method

[tex]t = \frac{-5 +/-\sqrt{5^2-4(4.9*-3)}}{2(4.9)} = \frac{-5+/-(9.154)}{9.8} \\\\t = \frac{-5+9.154}{9.8} \ or \ \frac{-5-9.154}{9.8} \\\\t = \frac{4.154}{9.8} \ or \ \frac{-14.154}{9.8} \\\\t = 0.424 \ sec \ or -1.444 \ sec\\\\Thus, t = 0.424 \ sec[/tex]

Answer:

4. the time going up is equal to the time coming down the acceleration is directly proportional to the velocity.

Explanation:

1. FALSE

The acceleration at the top point is equal to the acceleration due to gravity (9.8 m/s²). It is the velocity of the stone that becomes zero for a moment, at the top point.

2. FALSE

The acceleration of the body in a free fall motion always remains constant, and its value is equal to the acceleration due to gravity (9.8 m/s²)

3. FALSE

The velocity and acceleration point in opposite direction, during upward motion only (Velocity points up and acceleration points down). But they point in same direction during the downward motion (Both velocity and acceleration point down).

4. TRUE

Since, there is no air friction. Therefore, the acceleration for both upward an downward motion will be constant, without any opposing force. Hence, the time taken by the stone to go up will be equal to time taken by the stone to come down.

Answer:

Explanation:

Let the required depth be d .

Sound will first travel trough 480 m deep lake . Then it will enter granite layer .   Sound travelling through granite will reach oil level , get reflected and come back to the surface of lake as echo . Total time taken by sound to travel total distance  is .93 s

Total distance = 2d + 2 x 480 m

= 2d + 960 m

speed of sound in granite is given as 6000 m / s and speed through water is 1480 m /s

total time taken

= 2d / 6000 + 960 / 1480 = .93

2d / 6000 + .6486 = .93

2d / 6000 = .2814

d= 844.2 m

Answer:

θ = 39.7º

Explanation:

In this exercise we must use Newton's second law for the sphere, at the equilibrium point we write the equations in each exercise; we will assume that plate 1 is on the left

Y Axis

       [tex]T_{y}[/tex] -W = 0

       [tex]T_{y}[/tex] = W

X axis

         -[tex]F_{e1}[/tex] - F_{e2} + Tₓ = 0

let's use trigonometry to find the components of the tension, we measure the angle with respect to the vertical

         sin θ = Tₓ / T

         cos θ = T_{y} / t

         Tₓ = T sin θ

         T_{y} = T cos θ

let's use gauss's law to find the electric field of each leaf; We define a Gaussian surface formed by a cylinder, so the component of the field perpendicular to the base of the cylinder is the one with electric flow.

         F = ∫ E. dA = [tex]q_{int}[/tex] / ε₀

  in this case the scalar product is reduced to the algebraic product, the flow is towards both sides of the plate

        F = 2E A = q_{int} / ε₀

let's use the concept of surface charge density

        σ = q_{int} / A

we substitute

        2E A = σ A /ε₀

          E = σ / 2ε₀

this is the field created by each plate. The electric force is

        [tex]F_{e}[/tex] = q E

for plate 1 with σ₁ = -30 10⁻⁶ C / m²

         F_{e1}  = q σ₁ /2ε₀

for plate 2 with s2 = ab 10⁻⁶ C / m², for the calculations a value of this charge density is needed, suppose s2 = 10 10⁻⁶ C / m²

          F_{e2} = q σ₂ /2ε₀

we substitute and write the system of equations

           T cos θ = mg

          - q σ₁ / 2ε₀  - q σ₂ /2ε₀  + T sinθ = 0

we introduce t in the second equations

          - q /2 ε₀  (σ₁ + σ₂) + (mg / cos θ) sin θ = 0

          mg tan θ = q /2ε₀   (σ₁ + σ₂)

          θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)

data indicates the mass of 0.25 g = 0.25 10⁻³ kg

give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²

let's calculate

         θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2  8.85 10⁻¹² 0.25 10⁻³ 9.8))

         θ = tan⁻¹ 8.3 10⁻¹)

         θ = 39.7º

Answer:

The frequency is [tex]f = 165 Hz[/tex]

Explanation:

From the question we are told that

       The position of zero intensity is  [tex]L = 0.5 \ m[/tex] from the center

 Now the  wavelength of the sound is mathematical represented as

        [tex]\lambda = 4 L[/tex]

        [tex]\lambda = 4 * 0.5[/tex]

       [tex]\lambda = 2 \ m[/tex]

Now the frequency of the sound is mathematically represented as

      [tex]f = \frac{v}{\lambda}[/tex]

 substituting values

      [tex]f = \frac{330}{ 2}[/tex]

     [tex]f = 165 Hz[/tex]

Answer:

Explanation:

We shall apply the law of conservation of momentum to calculate the momentum and the speed of daughter nucleus .

Since the velocity of electron is very high we shall apply relativistic formula to calculate its momentum .

= [tex]\frac{mv}{\sqrt{1-(\frac{v}{c})^2 } }[/tex]

[tex]= \frac{9.11 \times 10^{-31}\times 5\times 10^7}{\sqrt{1-(\frac{5\times10^7}{3\times 10^8})^2 } }[/tex]

45.55 x 10⁻²⁴ x 1.176

= 53.58 x 10⁻²⁴ .

momentum of neutrino = 8 x 10⁻²⁴ . They are perpendicular to each other so total momentum

= √ [( 53.58 x 10⁻²⁴ )²+(8 x 10⁻²⁴)²]

= 54.17 x 10⁻²⁴

Hence the momentum of recoiled daughter nucleus will be same but in opposite direction

velocity of recoil = momentum / mass

= 54.17 x 10⁻²⁴ / 2.34 x 10⁻²⁶

= 23.15 x 10² m /s

Answer: The normal of the plane must be parallel to the electric field vector.

Explanation:

the normal to the surface is defined as a versor that is perpendicular to the plane.

Now, if the angle between this normal and the line of the field is θ, we have that the flux can be written as:

Φ = E*A*cos(θ)

Where E is the field, A is the area and θ is the angle already defined.

Now, this maximizes when θ = 0.

This means that the normal of the surface must be parallel to the electric field