Answer:
The electric field at that point is [tex]E = 66.66 \Delta V[/tex]
Explanation:
From the question we are told that
The distance is [tex]d = 1.5 cm = \frac{1.5}{100} = 0.015 \ m[/tex]
Generally the electric field at this region is mathematically represented as
[tex]E = \frac{\Delta V }{d}[/tex]
So [tex]\Delta V[/tex] is the electric potential difference between the electrods
So the equation becomes
[tex]E = \frac{\Delta V }{0.015}[/tex]
[tex]E = 66.66 \Delta V[/tex]
When the value of potential difference from the manual is substituted for
[tex]\Delta V[/tex] is substituted the we would arrive at the value of E but these is not available([tex]\Delta V[/tex]) i will leave the solution in terms of [tex]\Delta V[/tex]
A bird is about 6.5 in. long, with a thin, dark bill and a wide, white wing stripe. If the bird can fly 88 mi with the wind in the same time it can fly 72 mi against the wind when the wind speed is 2 mph, what is the rate of the bird in still air?
Answer:
20.0 mph
Explanation:
Let x represent the speed in still air, and t represent the time of flight;
Speed of wind = 2 mph
When flying with the wind, it's Speed is;
x + 2
When flying against wind, it's speed is;
x - 2
distance = speed × time;
When flying with the wind, distance is;
(x+2)t = 88 .....1
When flying against wind, distance is;
(x-2)t = 72 .......2
Solving the simultaneous equation;
Divide equation 1 by 2
(x+2)t/(x-2)t = 88/72
(x+2)/(x-2) = 1.222
x+2 = 1.222(x-2)
x+2 = 1.222x - 2.444
x(1.222-1) = 2+2.444
x(0.222) = 4.444
x = 4.444/0.222
x = 20.0 mph
the rate of the bird in still air is 20.0 mph
what happens at night- describing air circulation
Answer:
The environment is warmed by the light throughout the day, such that the temperature increases. The weather is decreasing and the temperature decreases in the night as the sun falls. There was a misunderstanding. Thanks to the density, the atmosphere becomes densest on the earth. The air becomes colder and colder when you move up.
Explanation:
Answer is above
Hope this helps.
During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electromagnetic wave. During normal beating of the heart, the maximum value of the oscillating potential difference across 0.305 m of a person’s chest is 3.95 mV. This oscillating potential difference produces a 0.75-Hz electromagnetic wave.
What is the maximum electric field created?
Answer:
E = 0.0130 V/m.
Explanation:
The electric field is related to the potential difference as follows:
[tex] E = \frac{\Delta V}{d} [/tex]
Where:
E: is electric field
ΔV: is the potential difference = 3.95 mV
d: is the distance of a person's chest = 0.305 m
Then, the electric field is:
[tex]E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m[/tex]
Therefore, the maximum electric field created is 0.0130 V/m.
I hope it helps you!
A seesaw consisting of a uniform board of mass M and length L, supports at rest a father and daughter with masses "mf " and "md", respectively.
The support ( called the fulcrum ) is under the centre of gravity of the board , the father is the distance "d" from the center and the daughter is a distance "L/2" from the center.
A) determine the magnitude of the upward force "n" exerted by the support on the board ?
B) determine where the father should sit to balance the system at rest ?
Answer:
A) N = (M + mf + md) g
B) d = md L / (2 mf)
Explanation:
Draw a free body diagram. There are four forces acting on the board.
Weight force M g pulling down at the center of the board.
Normal force N pushing up at the center of the board.
Weight force mf g pulling down a distance d from the center.
Weight force md g pulling down at the end of the board.
Sum of forces in the y direction:
∑F = ma
N − M g − mf g − md g = 0
N = (M + mf + md) g
Sum of moments about the center of the board:
∑τ = Iα
md (L/2) − mf d = 0
d = md L / (2 mf)
The magnitude of the upward force n exerted by the support on the board will be the same with the magnitude of the weight of the seesaw. Which is
W = 9.8M Newton
The father should sit at L/4 at the other end in order to balance the system at rest
Since the seesaw is of a uniform board, the center of gravity will act at the center. If it is of length L, the support called the fulcrum will be positioned at L/2.
If the daughter is a distance L/2 from the center, Then, she must be positioned at L/4 from the one edge of the board.
A. The magnitude of the upward force n exerted by the support on the board will be the same with the magnitude of the weight of the seesaw. Which is
W = mg
W = 9.8M Newton
The weight of both the father and the daughter will act downward. so, they will not be included.
The father should sit at L/4 at the other end in order to balance the system at rest
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consider a 38 degree F object placed in 68 F room write a differential equation for T thetemperature of the object at time t using k>0 for the constant of proportionality and write your equation in terms of T k and t
Answer:
dY/dt = k(Y - Ys).
Explanation:
Okay, this question based on the law known as the Newton's law of cooling. According to Newton's law of cooling, when an object is placed into a specific or particular environment, the object's temperature will definitely be lower than the temperature of the surrounding or the environment.
So, we are given that the temperature of the object = 38 degree F = Y(o) of the object and the temperature of the environment = 68 degree F = Ys
Hence, dY/dt = k(Y - Ys).
dY/ (Y - Ys) =kdt.
A uniform stationary ladder of length L = 2.7 m and mass M = 14 kg leans against a smooth vertical wall, while its bottom legs rest on a rough horizontal floor. The coefficient of static friction between floor and ladder is μ = 0.39. The ladder makes an angle θ = 55∘ with respect to the floor. A painter of mass 8M stands on the ladder a distance d from its base.(a) Find the magnitude of the normal force N, in newtons, exerted by the floor on the ladder.(b) Find an expression for the magnitude of the normal force NW exerted by the wall on the ladder.(c) What is the largest distance up the ladder (d) max, in meters, that the painter can stand without the ladder slipping?
Answer:
A) 1236 N
B) Nw = µ_s•N
C) d_max = 1.525 m
Explanation:
From the question, "smooth vertical wall" means that there is no friction there and thus the only vertical forces are the weights of the ladder and painter and the normal force at the floor.
a) Mass of ladder = 14 kg
Mass of painter = 8M = 8 * 14 = 112 kg
Thus, magnitude of normal force is;
N = total mass x acceleration due to gravity = (14 + 112)9.8
N = 1236 N
(b) Sum of the moments about the base of the ladder:
ΣH = 0
Nw - µ_s•N = 0
Nw = µ_s•N
c) Since they are the only two horizontal forces in play, we know that
Nw = Ff where Ff is the friction force at the floor.
Ff = µ_s*N = 0.39 × 1236
Ff = 482.04 N
So, to find maximum distance painter can stand without slipping, we'll use the formula ;
Nw(Lsinθ) = (Mgcosθ)(L/2) + (8Mgcosθ * d_max)
Plugging in the relevant values, we have;
482.04(2.7*sin55) = ((14 × 9.8cos55)*(2.7/2)) + (8*14*9.8cos55 * d_max)
1066.133 = 106.238 + 629.5575*d_max
629.5575*d_max = 1066.133 - 106.238
629.5575*d_max = 959.895
d_max = 959.895/629.5575
d_max = 1.525 m
A) The magnitude of the normal force is 1236 N
B) expression for the magnitude of the normal force Nw = µ_s•N
C) The largest distance up the ladder (d) max, d_max = 1.525 m
What is friction?The friction is defined as when any object slides on a surface then the force in opposite direction of the external applied force is generated which restrict the motion of the object is called as the friction force.
From the question, "smooth vertical wall" means that there is no friction there and thus the only vertical forces are the weights of the ladder and painter and the normal force at the floor.
a) Mass of ladder = 14 kg
Mass of painter = 8M = 8 * 14 = 112 kg
Thus, the magnitude of normal force is;
N = total mass x acceleration due to gravity = (14 + 112)9.8
N = 1236 N
(b) Sum of the moments about the base of the ladder:
ΣH = 0
Nw - µ_s•N = 0
Nw = µ_s•N
c) Since they are the only two horizontal forces in play, we know that
Nw = Ff where Ff is the friction force at the floor.
Ff = µ_s*N = 0.39 × 1236
Ff = 482.04 N
So, to find maximum distance painter can stand without slipping, we'll use the formula ;
[tex]N_{w}(Lsin\theta) = (Mgcos\theta)(\dfrac{L}{2}) + (8Mgcos\theta \times d_{max)[/tex]
Plugging in the relevant values, we have;
[tex]482.04(2.7\times sin55) = ((14 \times 9.8cos55)\times (\dfrac{2.7}{2})) + (8\times 14\times 9.8cos55 \times d_{max)[/tex]
[tex]1066.133 = 106.238 + 629.5575\times d_{max[/tex]
[tex]629.5575\times d_{max} = 1066.133 - 106.238[/tex]
[tex]d_{max} = \dfrac{959.895}{629.5575}[/tex]
d_max = 1.525 m
Thus, the magnitude of the normal force is 1236 N and an expression for the magnitude of the normal force Nw = µ_s•N . The largest distance up the ladder (d) max, d_max = 1.525 m
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A block-and-tackle pulley hoist is suspended in a warehouse by ropes of lengths 2 m and 3 m. The hoist weighs 350 N. The ropes, fastened at different heights, make angles of 50° and 38° with the horizontal. Find the tension in each rope and the magnitude of each tension.
Answer:
276 N and 225 N
Explanation:
Draw a free body diagram. There are three forces on the hoist:
Weight force 350 N pulling down,
Tension force T₁ pulling up and left 50° from the horizontal,
Tension force T₂ pulling up and right 38° from the horizontal.
Sum of forces in the x direction:
∑F = ma
T₂ cos 38° − T₁ cos 50° = 0
T₂ cos 38° = T₁ cos 50°
T₂ = T₁ cos 50° / cos 38°
Sum of forces in the y direction:
∑F = ma
T₂ sin 38° + T₁ sin 50° − 350 = 0
T₂ sin 38° + T₁ sin 50° = 350
Substitute:
(T₁ cos 50° / cos 38°) sin 38° + T₁ sin 50° = 350
T₁ cos 50° tan 38° + T₁ sin 50° = 350
T₁ (cos 50° tan 38° + sin 50°) = 350
T₁ = 350 / (cos 50° tan 38° + sin 50°)
T₁ = 276 N
T₂ = T₁ cos 50° / cos 38°
T₂ = 225 N
The heating element in an electric kettle is rated as 2.0 kW. If the water in the kettle is at 100.0 °C, what volume of water will be converted into steam in one minute? The specific latent heat of vaporization of the water is 2,257,000 J/kg and the
3 density of water is 1,000 kg/m .
Answer:
The volume is [tex]V =5.32 *10^{-5} \ m^3[/tex]
Explanation:
From the question we are told that
The power of the heating element is [tex]P = 2.0 kW = 2.0 *10^3 \ W[/tex]
The temperature of the water in the kettle is [tex]T _w = 100^oC[/tex]
The time to convert water to steam is t = 1 minute = 60 sec
The specific latent heat of vaporization is [tex]H_v = \ 2,257,000 J/kg[/tex]
The density of water is [tex]\rho_w = 1000\ kg/m^3[/tex]
The power of the heating element is mathematically represented as
[tex]P = \frac{E}{t}[/tex]
Where E Energy generated by the heating element in term of heat
[tex]E = Pt[/tex]
substituting values
[tex]E = 2.0 *10^{3} * 60[/tex]
[tex]E = 120000 J[/tex]
Now
The latent heat of vaporization is mathematically represented as
[tex]H_v = \frac{E}{m}[/tex]
Where m is the mass of water converted to steam
So
[tex]m = \frac{E}{H_v}[/tex]
substituting values
[tex]m = \frac{120000}{2257000}[/tex]
[tex]m = 0.0532\ kg[/tex]
The volume of water converted to steam is mathematically evaluated as
[tex]V = \frac{m }{\rho_w}[/tex]
substituting values
[tex]V = \frac{0.0532}{1000}[/tex]
[tex]V =5.32 *10^{-5} \ m^3[/tex]
adeen says that you can increase the resistance of a copper wire by hammering the wire to make it narrower and longer. Arnell says that you can increase its resistance by heating the wire. Which one, if either, is correct, and why
Answer:
Both of Arnell and Adeen are right.
Explanation:
For Adeen, hammering the wire makes it flat, effectively reducing the cross sectional area, and increasing the length of the wire. Recall that the resistivity of a metal conductor increases with length and decreases with cross sectional area. From this, we can see that the resistance of the wire will increase due to the hammering. This means Adeen is correct.
For Arnell, heating a metal causes the atoms along with their electrons to vibrate in a random manner. These random motions is not organised and can be in any direction. For electricity to flow smoothly, the electrons must travel in the same direction in an orderly fashion. The randomly vibrating atoms will continuously bump into the flowing electron, resisting the smooth motion of the electrons. This collisions results in an additional resistance, hence, the resistance is increased. This means Arnell is correct.
Now suppose that the Earth had the same mass and radius as it currently does, but all of the mass was concentrated into a thin (1 ft. thick) hollow spherical shell below your feet. Also suppose there was a small hole in the shell, just big enough four you to fit through. Compare the force of gravity on you outside the shell to the force of gravity if you stepped inside the shell.
Answer:
The force of gravity at the shell will be extremely great on me due to the huge mass collapsed into the small radius.
At the center of the shell, the gravitational forces all around should cancel out, giving me a feeling of weightlessness; which will be a lesser force compared to that felt while standing on the shell.
Explanation:
For the collapsed earth:
mass = 5.972 × 10^24 kg
radius = 1 ft
according to Newton's gravitation law, the force of gravity due to two body with mass is given as
Fg = GMm/[tex]R^{2}[/tex]
Where Fg is the gravitational force between the two bodies.
G is the gravitational constant
M is the mass of the earth
m is my own mass
R is the distance between me and the center of the earths in each case
For the case where I stand on the shell:
radius R will be 1 ft
Fg = GMm/[tex]1^{2}[/tex]
Fg = GMm
For the case where I stand stand inside the shell, lets say I'm positioned at the center of the shell. The force of gravity due to my mass will be balanced out by all other masses around due to the shell of the hollow earth. This cancelling will produce a weightless feeling on me.
A small block is released from rest at the top of a frictionless incline. The distance from the top of the incline to the bottom, measured along the incline, is 3.40 m. The vertical distance from the top of the incline to the bottom is 1.09 m. If g
Complete Question
A small block is released from rest at the top of a frictionless incline. The distance from the top of the incline to the bottom, measured along the incline, is 3.40 m. The vertical distance from the top of the incline to the bottom is 1.09 m. If [tex]g=9.8 \ m/s^2[/tex] , what is the acceleration of the block as it slides down the incline plane
Answer:
The acceleration is [tex]a = 3.142 m/s^2[/tex]
Explanation:
From the question we are told that
The distance from top to bottom of the inclined plane measured along the incline is [tex]d = 3.40 \ m[/tex]
The distance from top to bottom of the inclined plane measured along the vertical axis is
[tex]D = 1.90 \ m[/tex]
According to the SOHCAHTOA rule
[tex]sin \theta = \frac{D}{d}[/tex]
=> [tex]\theta = sin ^{-1} [\frac{D}{d} ][/tex]
substituting values
=> [tex]\theta = sin ^{-1} [\frac{1.09}{3.40} ][/tex]
[tex]\theta = 18.699^o[/tex]T
The acceleration of a block on a frictionless inclined plane is mathematically represented as
[tex]a = gsin \theta[/tex]
substituting values
[tex]a = 9.8 * sin(18.699)[/tex]
[tex]a = 3.142 m/s^2[/tex]
Assume the earth to be a nonrotating sphere with mass MEME and radius RERE. If an astronaut weights WW on the ground, what is his weight when he is 2RE2RE above the surface of the earth
Answer:
The weight at a distance 2 RE from surface of earth is W/9
Explanation:
For the value of acceleration due to gravity (g), we have a formula, that is:
g = (G)(ME)/(RE)² ----- equation (1)
where,
G = Gravitational Constant
ME = Mass of Earth
RE = Radius of Earth
g = Acceleration due to gravity on surface of earth = 9.8 ms²
When the person goes 2RE, distance above earth's surface. Then the total distance from center of earth becomes: 2RE + RE = 3RE.
Therefore, equation (1) becomes:
gh = (G)(ME)/(3RE)²
where,
gh = acceleration due to gravity at height
gh = (G)(ME)/(RE)²9
using equation (1), we get:
gh = g/9
Now, he weight is given by formula:
W = mg ------- equation (2)
At height 2RE
Wh = (m)(gh)
where,
Wh = Weight at height = ?
m = mass of astronaut
Therefore, using vale of gh, we get:
Wh = mg/9
Using equation (2), we get:
Wh = W/9
A spring of negligible mass and force constant k = 410 N/m is hung vertically, and a 0.200 kg pan is suspended from its lower end. A butcher drops a 2.5 kg steak onto the pan from a height of 0.50 m. The steak makes a totally inelastic collision with the pan and sets the system into vertical SHM
1. What is the speed of the pan and steak immediately after the collision?
2. What is the amplitude of the subsequent motion?
3. What is the period of that motion?
Answer:
1) 2.9m/s
2)0.235cm
3)0.509s
Explanation:
1. moments are conserved, when the steak hits the pan:
velocity 'v' of the steak:
v = √(2gh) = √(2*9.81*0.5) = 3.13 m/s
velocity pan + steak is
v =[tex]m_1v_1/(m_1+m_2)[/tex]= 2.5*3.13/(2.7) = 2.9 m/s
2.initial kinetic energy of pan + steak = spring energy
1/2 mv² = 1/2 kA²
where, A = amplitude
2.7 x 2.9² = 410 x A²
A²=22.707/410
A = 0.235 cm
3. T = 2π√(m/k) = 2π√(2.7/410) = 0.509 s
Therefore, the period of that motion is 0.509s
1) The speed of the pan and steak immediately after the collision is 2.9m/s
2) The amplitude of the subsequent motion is 0.235cm.
3) The period of that motion is 0.509s.
Calculation of the speed, amplitude, and the period:1.
Since
v = √(2gh) = √(2*9.81*0.5) = 3.13 m/s
Also,
v == 2.5*3.13/(2.7)
= 2.9 m/s
2.
Now
initial kinetic energy of pan + steak = spring energy
So,
1/2 mv² = 1/2 kA²
Here,
A = amplitude
2.7 x 2.9² = 410 x A²
A²=22.707/410
A = 0.235 cm
3.
Now
T = 2π√(m/k)
= 2π√(2.7/410)
= 0.509 s
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What is unique about visible
light in the electromagnetic
spectrum?
Answer:
The visible light spectrum is the segment of the electromagnetic spectrum that the human eye can view. More simply, this range of wavelengths is called visible light. Typically, the human eye can detect wavelengths from 380 to 700 nanometers.
Explanation:
Answer:
Visible light, which travels at a dizzying 186,282 miles per second through space, is just one part of light's broad spectrum, which encompasses all electromagnetic radiation. We can detect visible light because of cone-shaped cells in our eyes that are sensitive to the wavelengths of some forms of light
Explanation:
Suppose a low-frequency sound source is placed to the right of a person, whose ears are approximately 13 cm apart, and the speed of sound generated is 340 m/s. How long (in s) is the interval between when the sound arrives at the right ear and the sound arrives at the left ear
Answer:
The time taken by the sound is [tex]3.82\times 10^{-4}\ s[/tex]
Explanation:
We have,
A low-frequency sound source is placed to the right of a person, whose ears are approximately 13 cm apart, and the speed of sound generated is 340 m/s.
It is required to find the time taken by the sound when the sound arrives at the right ear and the sound arrives at the left ear. Let t is the time taken. It can be calculated as :
[tex]v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{0.13}{340}\\\\t=3.82\times 10^{-4}\ s[/tex]
So, the time taken by the sound is [tex]3.82\times 10^{-4}\ s[/tex]
momentum is closely related to
Answer:
Momentum is mainly related to forces
Find the truth table for the circuit shown. Explain the working principle for all the inputs, briefly. Explain why D1 is used in the network.
Answer:
see below for the truth table
Explanation:
Truth Table
As we will see from the description of operation, any input low causes the output to be high. This is the logic of a NAND gate. The truth table is attached.
Working Principle
Pulling any of A, B, or C low will saturate transistor Q1, depriving Q2 of any base current, cutting it off. Then Q5 is also deprived of base current and is cut off. Meanwhile, the current through R2 supplies base current to Q4, allowing it to pull the output high.
If all of A, B, and C are high (or open), base current is supplied to Q2 through the base-collector junction of Q1. Then Q2 saturates, supplying base current to Q3. Diode D1 ensures that the voltage across Q2 will be insufficient to supply any base current to Q4, so it stays cut off.
The motor on a helicopter turns at an angular speed of 6.2 x 102 revolutions per minute. (a) Express this angular speed in radians per second.
(b) If the rotor has a radius of 3.0 m, what arc length (linear displacement) tip of the blade trace out in 2.0 x 102 s?
Answer:
64.93 rad/s38.956 kmExplanation:
(a)
[tex]\dfrac{6.2\cdot 10^2\,\text{rev}}{60\,\text{s}}\times\dfrac{2\pi\,\text{rad}}{\text{rev}}=\dfrac{62\pi\,\text{rad}}{3\,\text{s}}\approx\boxed{64.93\,\text{rad/s}}[/tex]
__
(b)
[tex]d=r\theta=(3.0\,\text{m})(2.0\cdot 10^2\,\text{s})\left(\dfrac{62\pi\,\text{rad}}{3\,\text{s}}\right)=124\pi\cdot 10^2\,\text{m}=\boxed{38\,956\,\text{m}}[/tex]
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 3.5 s for the boat to travel from its highest point to its lowest, a total distance of 0.69 m. The fisherman sees that the wave crests are spaced 6.6 m apart. Part A How fast are the waves traveling
Answer:
v= 0.94 m/s
Explanation:
In order to calculate the speed of the waves, you use the following formula for the speed of the waves:
[tex]v=\lambda f[/tex] (1)
v: speed of the wave
λ: wavelength of the wave
f: frequency of the wave
The frequency is calculated by using the information about the time that boat takes to travel from its highest point to its lowest point. This time is a half of a period:
[tex]\frac{T}{2}=3.5s\\\\T=7.0s[/tex]
Then, the frequency is:
[tex]f=\frac{1}{T}=\frac{1}{7s}=0.142Hz[/tex]
The wavelength of the wave is the distance between crests of the wave
[tex]\lambda=6.6m[/tex]
With the values of the frequency and the wavelength, you can find the speed of the wave by using the equation (1):
[tex]v=(6.6m)(0.142Hz)=0.94\frac{m}{s}[/tex]
The speed of the wave is 0.94m/s
A current cannot produce a magnetic field. *
True or false
Answer:
False
Explanation:
False, as a magnetic field is generated whenever current travels through a conductor.
An electromagnet consists of a coil of wire wrapped around a bar of iron. The coil and iron bar get magnetized when electric current flows through the wire. An electromagnet also has north and south magnetic poles. The magnetic field is strongest at either pole of the magnet.
A toy car's movements is measured using photogates.
Answer:
a) the velocity increases then decreases.
You are on an interstellar mission from the Earth to the 8.7 light-years distant star Sirius. Your spaceship can travel with 70% the speed of light and has a cylindrical shape with a diameter of 6 m at the front surface and a length of 25 m. You have to cross the interstellar medium with an approximated density of 1 hydrogen atom/m3.
(a) Calculate the time it takes your spaceship to reach Sirius.
(b) Determine the mass of interstellar gas that collides with your spaceship during the mission.
Note: Use 1.673 ×10−27 kg as proton mass.
Answer:
Explanation:
TJVFKBFVN
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. If the plane is traveling horizontally with a speed of 250 km/hr (69.4 m/s) how far in advance of the recipients (horizontal distance) must the goods be dropped
Answer:
481 m
Explanation:
To fall 235 m, the time required is
t = √(2H/g)
t= √(2[tex]\times[/tex]235/9.8)
t=6.92 seconds.
The supplies will travel forward
6.92 [tex]\times[/tex] 69.4 ≈ 481 m
Therefore, the goods must be dropped 481 m in advance of the recipients.
Two large parallel conducting plates separated by 6 cm carry equal and opposite surface charge densities such that the electric field between them is uniform. The difference in potential between the plates is 400 V. An electron is released from rest at the negatively charged plate.
(a) What is the magnitude of the electric field between the plates?
(b) Which plate is at the higher potential?
1. The negatively charged plate
2. the positively charged plat
Answer:
a. 6666.67 V/m
b. 2. the positively charged plat
Explanation:
a. The computation of the magnitude of the electric field between the plates is shown below:
As we know that
[tex]E = \frac{V}{d}[/tex]
[tex]= \frac{400 V}{0.06 m}[/tex]
= 6666.67 V/m
hence, the magnitude of the electric field is 6666.67 V/m
b. Based on this the higher potential is positively charged plate as the flow of the current goes from positive to negative and it is inverse in case of th electron
We simply applied the above formula
A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?
A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?
If the distance from the source is doubled. The amplitude of the magnetic field is smaller 4 times.
The sun generates both mechanical and electromagnetic waves. Which statement about those waves is true?
ОА
The mechanical waves reach Earth, while the electromagnetic waves do not.
ОВ.
The electromagnetic waves reach Earth, while the mechanical waves do not.
Ос. Both the mechanical waves and the electromagnetic waves reach Earth.
OD. Neither the mechanical waves nor the electromagnetic waves reach Earth.
Answer:
B: The electromagnetic waves reach earth, while the mechanical waves do not.
correct Answer:
The electromagnetic waves reach Earth, while the mechanical waves do not
What structures can be found in the axial region of the body?
Answer:
The axial region of the body consists of the bones of the head, trunk of a vertebrate, skull, vertebral column, and thoracic cage. The human skeleton consists of 80 bones.
Explanation:
The axial region of the body consists of the bones of the head, trunk of a vertebrate, skull, vertebral column, and thoracic cage. The human skeleton consists of 80 bones.
It is composed of the following six parts:
1. Skull (22 bones)
2. Ossicles of the middle ear
3. Hyoid bone
4. Rib cage
5. Sternum
6. Vertebral column
The axial region of the body forms the vertical axis of the body as the axial skeleton supports the head, neck, back, and chest.
Two bars are conducting heat from a region of higher temperature to one of lower temperature. The bars have identical lengths and cross-sectional areas, but are made from different materials. In the drawing they are placed in "parallel" between the two temperature regions arrangement A, while they are placed end-to-end in arrangement B. In which arrangement is the heat conducted the greatest?
A) Arrangement A
B) The heat conducted is the same in both arrangements.
C) Arrangement B
D) It is not possible to determine which arrangement conducts more heat
Answer:
A) Arrangement A
Explanation:
The rate of heat conduction is given by Fourier's Law of Heat Conduction. It is given as follows:
Q = KAΔT/L
where,
Q = Rate of Heat Transfer or Conduction
K = Thermal Conductivity
A = Cross-Sectional Area
ΔT = Difference in Temperature
L = Thickness
So, it is clear from the formula that for a constant temperature difference and value of thermal conductivity, the rate of heat transfer is directly proportional to the cross-sectional area and it is inversely proportional to the thickness.
Therefore, the arrangement with larger cross-sectional area and smaller thickness will be the one with the greatest heat transfer rate and as a result greatest heat shall be conducted through that arrangement.
It is clear that the parallel arrangement that is arrangement A, has higher cross-sectional area and smaller thickness. Therefore, the correct option is:
A) Arrangement A
how you would teach the habit to your students.
Answer:
Probably just enforcing it little by little. (If you mean a habit. If you mean a certain topic it's different.)
Explanation:
If you are trying to teach your students a habit-
Try to correct them everytime they don't follow it. Expect them to do so and give a reward when they earn it.
If you mean a certain topic-
Make a slideshow or a presentation with an interactive game. Making it not boring and having them more attentive.
I gave a more general answer, so if you would like to go deeper into the subject I would be more happy to.
(If this helped, please let me know. If you have any questions do not be afriad to ask!)
A An ____ occurs when a very low resistance circuit is formed and can easily start a fire.
parallel circuit
series circuit
short circuit
voltage divider
Question 9 (4 points)
Which device measures the current in a circuit?
Answer:
1- Short circuit
2- ammeter
