When a coordinate grid is superimposed on a map of lanesville the middle school is located at (15,13) and the librart is located at (27,9). If each unit represents 1 mile how many miles apart are the middle school in the liebrary round your answer to the nearest 10th

Answer:

4.5 miles

Step-by-step explanation:

Given

[tex]Middle\ School = (15,13)[/tex]

[tex]Library = (27,9)[/tex]

To solve this, we simply solve for the distance (D) between both points.

[tex]D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

Where:

[tex](x_1,y_1) = (15,13)[/tex]

[tex](x_2,y_2) = (27,9)[/tex]

[tex]D = \sqrt{(27 - 25)^2 + (9 - 13)^2}[/tex]

[tex]D = \sqrt{(2)^2 + (-4)^2}[/tex]

[tex]D = \sqrt{4 + 16}[/tex]

[tex]D = \sqrt{20}[/tex]

[tex]D=4.472135955[/tex]

[tex]D=4.5[/tex] --- approximated

Since each unit is 1 mile. The distance is 4.5 miles

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