When a charge moves between
two points that have a potential
difference of +12.0 V, its electric
potential energy increases by
0.418 J. What is the amount
of the charge?
Include the correct sign, + or -
(Unit = C)

When A Charge Moves Betweentwo Points That Have A Potentialdifference Of +12.0 V, Its Electricpotential

Answers

Answer 1

Answer:

+ 0.07 C

Explanation:

From the question given above, the following data were obtained:

Potential difference (V) = 12 V

Energy (E) = 0.418 J

Charge (Q) =?

The energy (E) , potential difference (V) and charge (Q) are related by the following equation:

E = ½QV

With the above formula, we can obtain the charge as follow:

Potential difference (V) = 12 V

Energy (E) = 0.418 J

Charge (Q) =?

E = ½QV

0.418 = ½ × Q × 12

0.418 = Q × 6

Divide both side by 6

Q = 0.418 / 6

Q = + 0.07 C

Answer 2

Answer:

.0348

Explanation:

right on Acellus


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Answers

Answer:

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Answers

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